Answer:
-3.2m
Explanation:
To find the distance of the 25N weight from the pivot, we can use the concept of moments. The moment of a force is the product of the force and the perpendicular distance from the pivot to the line of action of the force.
The total moment about the pivot due to the weights on side A is:
Moment_A = (10N * 4m) + (30N * 2m) = 80Nm
The moment of the 25N weight on side B must be equal and opposite to the total moment of the weights on side A, so we can set up the following equation:
Moment_B = -80Nm
We can solve for the distance of the 25N weight from the pivot by rearranging the equation to solve for x:
x = Moment_B / 25N = -80Nm / 25N = -3.2m
So the distance of the 25N weight from the pivot is -3.2m. This means that the weight is 3.2m to the left of the pivot, since the pivot is taken as the origin for the purpose of calculating moments.
Plz help me !!!!!!!!!!
Answer:
A. These vibrations can travel through solids, liquids, and gases, but not through empty space.
CAN SOMEONE PLEASE ANSWER THESE 4 QUESTIONS I WILL NEED IT IN A FEW HOURS , YOU WILL GET BRAINLIEST!!
1.) Compare reflection and refraction. How are they similar and how are they different?
2.) In your own words, describe how ray diagrams can be used to describe if light rays are being reflected or refracted.
3.) What is the formula for the Law of Reflection? Define the variables and explain what it tells us about the motion of light.
4.) What is the formula for Snell's? Define the variables and explain what it tells us about the motion of light.
Answer:
1.)Reflection is the act of light reflecting back when it hits a medium on a plane. Refraction is the process by which light shifts its path as it travels through a material, causing the light to bend. Thus, this is the key difference between reflection and refraction. This phenomenon usually occurs in mirrors.
2.)ray diagrams are a visual representation of the propagation of light. They can help us to understand and visualise multiple situations, such as light being reflected off of a mirror or changing its direction while moving through a lens.
3.)Reflection: The process of sending back the light rays which fall on polished surface is called reflection of light.
Laws of reflection:
(i) The angle of reflection is always equal to the angle of incidence.
(ii) The incident rays, reflected rays and the normal, all lie in the same plane.
4.)Snell’s law formula is expressed as: μ= sin i/sin r
, where i is the angle of refraction, r is the angle of refraction and μ is known as the refractive index of the second medium with respect to the first medium.
Mercury thermometer is not suitable to measure the temperature of very cold place. Why?
The use of a mercury thermometer is not suitable for the purpose of determining the temperature of extremely cold ice because at such low temperatures, mercury transforms into a translucent state, making it impossible to read.
Another reasons why mercury thermometer is not suitable to measure the temperature of the very cold place are:
Since mercury freezes at a temperature of -38.83 degrees Celsius, a mercury thermometer will not work in extremely cold temperatures. We are unable to use a thermometer that contains mercury at low temperatures because the glass could shatter at those temperatures.The body whose temperature we are measuring with the thermometer does not radiate heat in the opposite direction.When exposed to low temperatures, mercury takes on a transparent appearance, making it more challenging to obtain accurate readings.To learn more about mercury thermometer, click here:
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Because of the Doppler effect, a light- or sound-emitting object moving toward you has a ________ compared to a stationary object.
Because of the Doppler effect, a light- or sound-emitting object moving toward you has a lower amplitude compared to a stationary object.
The Doppler effect is generally defined as the shift in wave frequency (whether it be sound or light) caused by relative motion between the wave source and the observer. Every time a source wave moves in reference to the observer, this effect can be seen.
The Doppler effect allows astronomers to determine the frequency of light waves as an object moves in relation to the observer. As it approaches you, the frequency decreases and the item exhibits a blueshift. A redshift indicates that an item is travelling away from us.
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Wilbur ran 1-kilometer. Then he ran 500 meters. How many meters did Wilbur run all together?
A) 15,000
B) 1,500
C) 1000
D) 150
A 0.480 kg mass suspended from a spring oscillates with a period of 1.50 s. How much mass must be added to the object to change the period to 2.05 s
The mass added to the object to change the period to 2.05 s is 0.42 kg
What is the time period of an oscillation?
The time taken for an oscillating particle to complete one cycle of oscillation is known as the Period of oscillating particle.
Given :
A 0.480-kg mass suspended from a spring oscillates with a period of 1.50 s.
The formula of the time period is given by:
[tex]T=2\pi \sqrt{m/K}[/tex] ------(1)
where m is the mass and K is the spring constant.
The new time period is given by:
[tex]T'=2\pi \sqrt{m^{'} /K[/tex]-----(2)
where m' is the total mass after the addition and K is the spring constant.
Dividing equation (1) by equation (2).
[tex]T/T'=\sqrt{m/m'}[/tex]
Now, substitute the known terms in the above expression.
[tex]\frac{1.50}{2.05} =\sqrt{0.480/m'}[/tex]
[tex]m'=\frac{0.480}{0.5329}[/tex]
[tex]m'=0.9[/tex] kg
Now, the mass added to the object to change the period to 2.05 s is given by:
m" = 0.9 - 0.480
m" = 0.42 Kg
Thus, 0.42kg of mass must be added to the object to change the period to 2.05s.
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If the refractive index from air to water, nw = 1.3 and the velocity of light in the air is
3 x 108 m/s, what is the velocity of light in water?
Answer:
[tex]n _{w} = \frac{c}{v} \\ 1.3 = \frac{3 \times {10}^{8} }{v} \\ v = \frac{3 \times {10}^{8} }{1.3} \\ v = 2 \times {10}^{8} \: m {s}^{ - 1} [/tex]
What details can you add to your model of sound? model being a slinky
Answer:
I really hope this helps
Explanation:
A net force of 10 newtons accelerates an object at 5.0 meters per second^2. What net force would be required to accelerate the same object at 1.0 meters per second^2
The proper answer is that a force of 16 N net would be needed to accelerate the same item at 1.0 m/s2.
How is the net force needed to accelerate calculated?Newton's second law of motion condenses these relationships. The answer to the acceleration equation above can be written as Net Force = Mass Acceleration, or F = m a.
You know that force(F) & acceleration(a) are connected through mass(m),
F=ma
Here you have:
10 = 5 m
so, m = 10/5 = 2 Kg
Then if you have a = 8 m/s^2
you get:
F=2×8=16 N
Force = 16N
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Runner A is initially 2.0 mi west of a flagpole and is running with a constant velocity of 8.0 mi/h due east. Runner B is initially 9.0 mi east of the flagpole and is running with a constant velocity of 4.0 mi/h due west. How far are the runners from the flagpole when they meet?
The definition of constant velocity is the speed of a moving object that doesn't change over time. The system travelling at a constant speed is subject to zero net acceleration.
What distinguishes instantaneous velocity from average velocity?In contrast to instantaneous velocity, which is determined by slope of tangent line, average speed is defined as the shift in location (or displacement) during the course of transit.
Which of the four main claims about how a body can accelerate even when it has no velocity is untrue?Speed is the measure of velocity in magnitude. As a result, it is impossible to have two objects moving at the same velocity. The right response is therefore option A.
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Y’all which ones is incorrect (if there wrong plz tell me what to circle right then) thanks :3
WILL MARK BRAINLIEST FOR THIS :D
After seeing the fur rubbed with the rod attract the neutral paper, imagine you had an instrument that lets you zoom in enough to see what the paper and rod are made of. Draw a model that shows what happens to the neutral paper to cause it to move towards the charged rod. Make sure to label everything in your model
Seeing the fur rubbed with the rod attracts neutral paper, this happens because the friction of the rod with the rubbed can produce a static electric force. It is this static electric force that causes the pieces of paper to be attracted and rod up.
If the rod or ruler has been rubbed into the hair, then brought closer to the paper, then the paper will lift and stick. Indeed, this can happen due to the presence of an electric charge. When you rub a plastic ruler over your hair, it becomes electrically charged, causing the paper to pull and stick.
The electric charge consists of two types of charge, namely negative charge, and positive charge. However, some objects have an equal amount of negative charge and positive charge. Objects that have the same amount of positive and negative charges are called neutral objects. Initially, a plastic ruler is also an electrically neutral object.
When you rub the ruler against dry hair, it gets an electric charge, because of that electric charge the plastic ruler can exert a force on the paper and pull it closer.
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How much of the world's energy is hydroelectric?
According to the United Nations Environment Programme, hydropower accounted for 16.6% of global electricity generation in 2018.
This is equivalent to a total installed capacity of 706 GW, making it the second largest energy source after thermal sources.
Hydropower is a renewable energy source and is often seen as a more sustainable alternative to thermal sources, as it does not release any greenhouse gases into the atmosphere. Additionally, hydropower is a reliable source of energy, and can be used to meet peak energy demand.
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Calculate the rotational kinetic energy of a 12-kg motorcycle wheel if its angular velocity is 120 rad/s and its inner radius is 0.280 m and outer radius 0.330 m.
According to the question the rotational kinetic energy of a 12-kg motorcycle wheel is 809.14 J
What does rotational kinetic energy?The SI unit for rotational kinetic energy is the joule (J). The rotating kinetic energy formula has a similar structure to a translational kinetic energy equation. Kinetic energy is created by spinning objects around an axis. This type of energy is influenced by the object's mass, weight, and center of mass angle with respect to the axis.
Given data -
Mass = 12-kg
Angular velocity (ω) -120rad/s
inner radius = 0.280 m
outer radius = 0.330 m.
By using the formula
I = ½*M (r1² + r2²)
I = ½ *(12) * (0.2802 + 0.3302)
I = 1.1238 Kgm2
K.E = ½*Iω2
K.E = ½ * (1.1238)*(120)2
K.E = 809.14 J
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A 2kg block is initially at rest on a horizontal frictionless table. A force of 15N is then exerted on the block at an angle of 37° below the horizontal. The change in kinetic energy after moving 3m is?
Answer:
Approximately [tex]36\; {\rm J}[/tex].
Explanation:
Under the assumption, there is no friction to hinder the motion of the block. As a result, the increase in the kinetic energy of the block would be equal to the external work done on the block.
Let [tex]F[/tex] denote this magnitude of this force, let [tex]s[/tex] denote the magnitude displacement, and let [tex]\theta[/tex] denote the angle between this force and displacement. To find the work that this force has done on the block, use the formula:
[tex]\begin{aligned}(\text{work}) &= F\, s\, \cos(\theta)\end{aligned}[/tex].
For example, since the block in this question is moving along a horizontal table, displacement of the block would be in the horizontal direction. It is given that the angle between this force and the horizontal direction is [tex]37^{\circ}[/tex]. Thus, the angle between the force and the displacement would be [tex]\theta = 37^{\circ}[/tex].
Magnitude of this force is [tex]F = 15\; {\rm N}[/tex], while magnitude of displacement is [tex]s = 3\; {\rm m}[/tex]. The work done on this block would be:
[tex]\begin{aligned}(\text{work}) &= F\, s\, \cos(\theta) \\ &= (15\; {\rm N})\, (3\; {\rm m})\, \cos(37^{\circ}) \\ &\approx 36\; {\rm N\cdot m} = 36\; {\rm J}\end{aligned}[/tex].
Hence, the kinetic energy of this block would increase by [tex]36\; {\rm J}[/tex].
a typical gps satellites orbit at an altitude of 2.0 x10^7 m. find (a) the orbital period, and (b) the orbital speed of such a satellite
the orbital period is 7200sec or 2hours and orbital speed is 7,27m/s
(a) The orbital period of a satellite is the time it takes for the satellite to make one full orbit around the Earth. To calculate the orbital period, we can use the equation: T = 2 * pi * (a^3/GM)^(1/2) where T is the orbital period, a is the semi-major axis of the orbit (which is equal to the altitude of the satellite), pi is approximately 3.14, G is the gravitational constant (approximately 6.67 x 10^-11 m^3/kgs^2), and M is the mass of the Earth (approximately 5.98 x 10^24 kg).Plugging in the given altitude of 2.0 x 10^7 m for a and the known values for pi, G, and M, we get:
T = 2 * pi * (2.0 x 10^7 m)^3/ (6.67 x 10^-11 m^3/kgs^2 * 5.98 x 10^24 kg)^(1/2)
Simplifying, we get:
T = 2 * pi * (8.0 x 10^21 m^3/ (4.03 x 10^34 kg*m^3/s^2))^(1/2)
T = 2 * pi * (1.98 x 10^13 s^2/kg)^(1/2)
T = 7200 sec (or 2 hours)
(b) The orbital speed is the distance traveled by the satellite in one hour. We can calculate the orbital speed using the equation v = 2πa/T
Plugging in the values of a and T we get :
v = 2π (2.0 x 10^7 m) / 7200 sec
v = 7,27 m/s
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How do scientists collect evidence about Earth's climate?
"Scientific evidence for warming of the climate system is unequivocal."
What evidence can be used to study the Earth's past climate?Organisms such as diatoms, forams, and coral) can obey useful climate proxies. Other proxies involve ice cores climate, tree rings, and sediment cores. Chemical deputy records include isotope ratios, elemental examination, biomarkers, and biogenic silica.
Climate analyzers use every possible direct and indirect compilation to study the full history of Earth's climate, ice cores drawn from Greenland, Antarctica, and tropical mountain glaciers appear that Earth's climate greets to changes in greenhouse gas levels.
So we can conclude that Climate change is most usually measured using the average surface temperature of the planet.
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A certain light truck can go around a flat curve having a radius of 150 m with a maximum speed of 34.5 m/s. With what maximum speed can it go around a curve having a radius of 60.0 m
With 20.23 ms⁻¹, maximum speed can it go around a curve having a radius of 60.0 m
What's the maximum speed?The highest rate of speed a person can reach is called maximum speed. When athletes alter the magnitude (how quickly they are moving) or direction (or both) of their motion, or both, their acceleration changes as well since acceleration is related to velocity, which has both a magnitude and a direction connected with it.
ac max = V² max / R ....(1)
Inserting given values we get
ac, max = (34.5)² / 150 = 7.935 ms⁻²
For a changed radius of the curve of 60.0 m, the maximum safe speed from (1) becomes
Unew, max= √ac, max R new
Unew, max = √6.826 x 60
Unew, max 1 = 20.23 ms⁻¹, rounded to one decimal place.
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Classify the phase-change scenarios according to the direction of the heat flow in each case. No net transfer of heat occurs Heat is transferred from the water to the surroundings Heat is transferred to the water from the surroundings
When working through these problems, think about the heat in terms of movement of the molecules of water.
Heat is transferred from the water to the surroundings --- water molecules slowing down.
Heat is transferred to the water from the surroundings --- water molecules heating up.
a cloud of steam condenses into liquid water - Heat is transferred from the water to the surroundings. Steam has more molecules moving around than liquid water. Therefore the molecules had to slow down, thereby transferring heat to the surroundings.a block of ice sublimates into water vapor - Heat is transferred to the water from the surroundings --- water molecules are heating upa block of ice melts - Heat is transferred to the water from the surroundings. The water molecules are basically not moving. Therefore heat has to be introduced to the molecules, which causes the melting.a puddle of water evaporates - Heat is transferred to the water from the surroundings. The water molecules are moving in the liquid state. However, when more heat is introduced to the liquid, the molecules move more rapidly and evaporate.a puddle of water freezes into ice - Heat is transferred from the water to the surroundings --- water molecules slowing down as they go from a liquid state to a solid state. ABOUT HEAT TRANSFERHeat transfer is the transfer of energy due to the difference of temperature between two different places. The main discussion in heat transfer is how the energy in heat can move places and the rate of transfer under certain conditions. Heat transfer includes the processes of inflow and outflow of heat. In industrial processes, heat transfer is used to achieve the required temperature in the industrial process and maintain the required temperature throughout the process.
Heat transfer from one object to another can occur by conduction, convection, and radiation. The determinant of heat transfer is the temperature difference. The direction of heat transfer starts from a medium with a high temperature to a medium with a lower temperature. Heat transfer can occur with a single process or multiple processes.
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Una atracción de feria consiste en lanzar un trineo de 2 kg por una rampa ascendente que forma un ángulo de 30º con la horizontal. Si el coeficiente de rozamiento es 0,15 ¿con qué velocidad hay que lanzar el trineo para que ascienda 4 m por la rampa?
Answer:
La velocidad con la que se debe lanzar el trineo es aproximadamente 9.96 m/s
Explanation:
La masa del trineo, m = 2 kg
El ángulo de inclinación del trineo, θ = 30 °
El coeficiente de fricción, μ = 0,15
La altura a la que debe ascender el trineo, h = 4 m
La reacción normal del trineo en la rampa, N = m · g · cos (θ)
La fuerza de fricción [tex]F_f[/tex] = N × μ
Dónde;
g = Th aceleración debida a la gravedad ≈ 9.81 m/s²
∴ [tex]F_f[/tex] = 0.15 × 2 kg × 9.81 m/s² × cos (30°) ≈ 2.55 N
La longitud de la rampa que se mueve el trineo, l = h/(sin(θ))
∴ l = 4/(sin(30°)) = 8
La longitud de la rampa que se mueve el trineo, l = 8 m
El trabajo realizado sobre la fricción, [tex]W_f[/tex] = [tex]F_f[/tex] × l
[tex]W_f[/tex] = 2.55 × 8 ≈ 20.4
El trabajo realizado sobre la fricción, [tex]W_f[/tex] ≈ 20.4 Julios
El trabajo realizado para levantar el trineo a 4 metros de altura, P.E. = m·g·h
∴ P.E. = 2 kg × 9.81 m/s² × 4 m ≈ 78.48 Joules
El trabajo realizado para levantar el trineo a 4 metros de altura, P.E. ≈ 78.48 Joules
El trabajo total requerido para levantar el trineo 4 metros por la rampa, [tex]W_t[/tex] = [tex]W_f[/tex] + P.E.
[tex]W_t[/tex] = 20.4 J + 78.84 J ≈ 99.24 J
Energía cinética, K.E. = 1/2 × m × v²
La energía cinética necesaria para mover el trineo por la rampa, K.E. se da de la siguiente manera;
K.E. = 1/2 × 2 kg × v² ≈ 99.24 J
∴ v² ≈ 99.24 J/(1/2 × 2 kg)
La velocidad con la que se debe lanzar el trineo para que ascienda 4 metros por la rampa, v ≈ 9.96 m/s
Trends are easier to detect when the signal-to-noise ratio is low.
a True
b False
Answer:
I think it's b. False
Explanation:
How do you find the acceleration of a ball rolling down a slope?
The ball accelerates at a constant rate as it moves down the slope because of the constant gravitational force acting on it in a major portion and the rolling tangential force on the object is acting in the smaller form.
Rolling motion of any object occurs when the object starts sliding in a different methods from the other objects such as when the objects starts to roll from the ramp or any other sloppy surface and it rolls down due to the gravitational force and with many other forces such as the rolling tangential force. many forces are acting on the object at the same moment and we are just seeing the gravitational force which is playing a major portion. Hence by this information we can consider that the ball accelerates at a constant rate as it moves down the slope because of the constant gravitational force acting on it in a major portion and the rolling tangential force on the object is acting in the smaller form.
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You can tell from reading this passage that -
the narrator will definitely find a diamond at the Crater of Diamonds State Park.
diamonds are rare, valuable gems.
garnet is as valuable as a diamond.
semi-precious stones are ugly.
Answer: B or "diamonds are rare,valuable gems".
Explanation:
since the link does not show very much, I don't know if A is correct or not. D is incorrect because that is an opinion. C is incorrect.
he period of a wave is equal to the time it takes for one wavelength to pass by a fixed point. You stand on a pier watching water waves and see 10 wavelengths pass by in a time of 40 seconds. a. What is the period of the water waves?b. What is the frequency of the water waves?c. If the wavelength is 3 meters, what is the wave speed?
The period of water waves is 4 seconds. The frequency of water waves is 0.25 Hz. The wave speed is 0.75 m/s.
What is a period of waves and frequency?
Period of waves or wave period represents the time taken by the wave to complete one cycle. It is also defined as the time is taken for two successive crests or troughs (one wavelength) to pass through the specific point.
The wave period is measured in seconds. Hence, its unit is seconds (s). The period of a wave is the ratio of the wavelength and velocity. The wave period is inversely proportional to the frequency.
Frequency is defined as the number of waves passes through the medium in a given time. Frequency equals the number of cycles per second. The unit of frequency is hertz (Hz).
Frequency is inversely proportional to the wave period. If the frequency increases, the wave period decrease, and the wave period increases by decreasing the wave period.
The wave speed equals the product of wavelength and frequency. Wave speed is defined as the distance of wave travels in a given time. The unit of wave seed is m/s.
From the givens,
time = 40 seconds, wavelength = 10m
Wave period = time/wavelength
= 40/10
Wave period = 4 seconds.
Frequency = 1 / wave period
= 1 / 4
Frequency = 0.25 Hz.
Wave speed = wavelength × frequency
= 3×0.25
= 0.75 m/s
Wave speed = 0.75 m/s.
Hence, the wave period is 4s, the frequency is 0.25 Hz, and the wave speed is 0.75 m/s.
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The direction of the velocity of the planet is _______________________ (alwaysThe direction of the velocity of the planet is _______________________ (always, seldom, never) perpendicular to the net force acting upon the planet., seldom, never) perpendicular to the net force acting upon the planet.
According to the satellites' orbits and the speed at which they move, it either happens frequently or always.
As we begin to examine satellite orbits, we find that a circular orbit places the satellite always perpendicular to the object's net force and speed.
The orbit is stretched, just like in elliptical orbits. This informs us that the orbit has four points. As a result, the satellite rarely faces the satellite's net force in a perpendicular direction.
Rarely and always for elliptical orbits. According to the satellites' orbits and the speed at which they move, it either happens frequently or always.
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X-rays with wavelengths of 0.95 nm are detected at a scattering angle of straight theta in a Compton-scattering experiment, as shown in the drawing. What is the scattering angle straight theta if the energy of the scattered photon is 5.111 keV. (For accuracy, use h = 6.626 x 10-34 J·s and c = 2.998 x 108 m/s.)
Answer:
The scattering angle is 0.80
Explanation:
As we know
Wave length = h/mc (1-cos α) --1
W = mc^2
m = E/c^2
Substituting this in equation 1 we get
Wavelength = hc/E (1-cos α)
Substituting the given values, we get -
0.95*10^-9 = [(6.626 *10^-34 * 2.998 *10^8)/5.111*1000*1.6*10^-19} (1-cos α)
(1-cos α) = 1.14 *10^-10
cos α = 1- 1.14 *10^-10
α = 0.80
At an outdoor physies demonstration, a delay of 0.50 second was observed between the time sound waves left a loudspeaker and the time these sound waves reached a student through the air. If the air is at STP, how far was the student from the speaker? (1) 1.5 × 10-m (91.7 × 102 m (3) 6.6 × 10? m (4) 1.5 × 108 m
The distance that is covered by the sound is 1.66 * 10^2 m.
What is the distance?We know that sound is a mechanical wave. The implication of this is that sound woulod need to have a medium through which the sound can be able to travel. The speed of sound in the various media through which the sound travels is not the same.
We know that the speed of sound in air is 331 m/s and we have to use this in our calculations.
Distance = speed * time
Distance = 331 m/s * 0.5 s
= 1.66 * 10^2 m
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In a comic book, Superman carries a bus (with a bomb on board) up into the air, hovers for a second and then
throws the bus over the horizon while he stays hovering. How does this situation break the law of conservation
of momentum? What should have happened instead? Why?
This situation breaks Newton's Second Law of motion which states that for every action there is an equal and opposite reaction.
It could have been ideal if the force exerted on the bus by superman should also be exerted on superman by the bus because if we use the equation F=m*a, since superman's mass is so much less than the mass of the bus, he should experience a much higher acceleration than the bus does.
What is the second law ?Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body and it states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.
Newton’s second law is one of the most important in all of physics. For a body whose mass m is constant, it can be written in the form F = ma, where F (force) and a (acceleration) are both vector quantities.
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What is the relationship between mass thermal energy transfer kinetic energy and temperature?
The relationship between mass thermal energy transfer kinetic energy and temperature is: When the temperature of an object raises, the average kinetic energy of its particles raises. When the average kinetic energy of its particles raises, the object's thermal energy raises.
The thermal energy in a substance is the whole kinetic energy of all the particles in the substance. If we warm a substance or object, as each particle speeds up, the average speed of the particles (temperature) raises, and accordingly the total speed (kinetic energy) of the particles (thermal energy).
The total of heat transferred is also directly proportional to the mass. To make an equivalent temperature change in a doubled mass, we need to add twice the heat.
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how would you describe the atmosphere to a friend.
-We are discussing the book Paulo's Parachute Mission-
Answer:
its a shield that can protect us from super hot rays and all though ita not that strong atleast we wont get burned to death lol :)