The two experimental procedures for determining rate laws are the method of initial rates and the graphical method.
The two experimental procedures for determining rate laws are the method of initial rates and the graphical method.
Method of Initial Rates: This method involves measuring the initial rates of reaction under different initial concentrations of reactants while keeping all other conditions constant. The rate law can be determined by comparing the initial rates with the initial concentrations of the reactants.
Graphical Method: In this method, the concentration of the reactants is plotted against time. The rate law can be determined by analyzing the slope of the resulting curves.
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4. (Hard) A coal power station generates electricity by first burning coal to heat water into steam, then passing that steam through a turbine to make it spin. The turbine drives a generator which gives out electrical energy A. Read the paragraph above. Identify the energy stores and transfers for the coal power station. B. The coal has a chemical potential energy store of 20,000J. 90% of the energy is transferred into the heat store of the water. Then, 30% of the energy is dissipated in the turbine. Of the remaining energy, 85% is transferred as electricity by the generator. Calculate how much electrical energy is produced by the generator. C. If the power station is provided with 10,000J of energy per second from the coal, calculate the power output of the power station. D. Give three specific improvements that could be made to the power station to make it more efficient
A coal power station generates electricity by first burning coal to heat water into steam, then passing that steam through a turbine to make it spin.
A. Energy stores:
Chemical potential energy in the coal
Thermal energy in the water
Kinetic energy in the steam
Kinetic energy in the turbine
Electrical energy in the generator
Energy transfers:
Chemical potential energy in the coal to thermal energy in the water (by burning the coal)
Thermal energy in the water to kinetic energy in the steam (by boiling the water)
Kinetic energy in the steam to kinetic energy in the turbine (by passing through the turbine)
Kinetic energy in the turbine to electrical energy in the generator (by driving the generator)
B. Energy transferred into heat store of water: 20,000 J x 0.9 = 18,000 J
Energy dissipated in the turbine: 18,000 J x 0.3 = 5,400 J
Remaining energy after turbine: 18,000 J - 5,400 J = 12,600 J
Energy transferred as electrical energy: 12,600 J x 0.85 = 10,710 J
C. Power output = energy input per second = 10,000 J/s
So, the power output of the power station is 10,710 J/s (since 85% of the remaining energy is transferred as electrical energy).
D. Three specific improvements that could be made to the power station to make it more efficient are:
Implementing better combustion techniques to increase the efficiency of burning coal.
Using better insulation materials to minimize heat loss in the power station.
Using more efficient turbines and generators to convert kinetic energy to electrical energy.
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The magnetic field through a circular loop of radius r = 15 cm varies with time, as shown. The direction of the field is perpendicular to the loop. What is the magnitude of the induced emf, ε1, in millivolts, at time t1 = 1.0ms?
B=0I2R(at centre of loop), B = 0 I 2 R(at centre of loop), where R is the loop's radius, gives the magnetic field strength at the loop's centre.
How does the magnetic field change as the loop's radius increases?The magnetic field strength diminishes with increasing radius. Radius of the loop has an inverse relationship with magnetic field intensity.
With its plane normal to an external field of magnitude 5.0102T, a circular coil with a radius of 10 cm and 16 turns that is carrying a current of 0.75 A is at rest. The coil is unrestricted in its ability to rotate around an axis in a plane perpendicular to the field direction.
Hence, the integral around any circle's diameter that is centred on a wire.
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Assuming all objects are moving with the same velocity, which statement describes the object with the smallest inertia?
A bowling ball rolls across a street and into a large soccer field.
A driver continues forward after his car takes a sharp turn.
A helicopter is following a high-speed pursuit across town.
A pebble is thrown in space and continues in a straight line.
A pebble is thrown in space and continues in a straight line. Hence, the correct option is (d). When all objects are moving with same velocity.
Inertia is the resistance of an object to changes in its motion, and it depends on the object's mass. The smaller the mass of an object, the smaller its inertia. In option (d), the pebble has the smallest mass and therefore the smallest inertia among the objects described. The driver in option (b) experiences a force that changes the direction of his motion, so his inertia is greater than that of the pebble. In option (c), the helicopter is actively moving and changing its velocity, so its inertia is greater than that of the pebble. In option (a), the bowling ball has a much larger mass than the other objects and therefore greater inertia.
Therefore, option (d) - A pebble is thrown in space and continues in a straight line - describes the object with the smallest inertia assuming all objects are moving with the same velocity.
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During the photoelectric effect experiment, a photon is emitted with 9.60 x10-20 J of kinetic energy. If the work function of the photosensitive surface is 1.68 eV, which is the frequency of the incident light? (h = 6.626 x 10-34 J·s; 1 eV = 1.60 x 10-19 J)
According to the given statement 5.50 * 10¹⁴Hz is the frequency of the incident light.
What does the term "photoelectric effect" mean?The photoelectric effect, which happens when light strikes a metal, can release electrons out of its surface. As the electrons that are expelled first from metal are known as emitted electrons, this process is also sometimes referred to as photoemission.
The following equation may be used to determine a photon's energy in terms of frequency:
E = hf
The work function must first be changed from electron volts (eV) to joules (J):
1 eV = 1.602 × 10⁻¹⁹ J
Hence, the work function is:
1.68 eV × 1.602 × 10⁻¹⁹ J/eV = 2.69 × 10⁻¹⁹ J
The emitted photon's kinetic energy is:
E = 9.60 × 10⁻²⁰ J
E = E0 + KE
where KE is the kinetic energy of the released electron and E0 is the work function.
Inputting the values, we obtain:
hf = E0 + KE
hf = 2.69 × 10⁻¹⁹ J + 9.60 × 10⁻²⁰J
hf = 3.65 × 10⁻¹⁹ J
When we solve for f, we obtain:
f = E/h = (3.65 × 10⁻¹⁹ J) / (6.626 × 10⁻³⁴ J s)
f = 5.50 × 10¹⁴ Hz
As a result, the incident light has a frequency of 5.50 * 10¹⁴Hz.
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A long, cylindrical solenoid with 100 turns per centimeter has a radius of 1.5 cm. (a) Neglecting end effects, what is the self-inductance per unit length of the solenoid? (b) If the current through the solenoid changes at the rate 5.0 A/s, what is the emf induced per unit length?
The solenoid's induced emf is 0.011 V/m per unit length. Be aware that the negative sign denotes an opposition to the change in current in the direction of the induced emf.
What is the amount of induced emf per unit length if the current through the solenoid changes at a rate of 5.0 A/s?Faraday's law of induction provides the emf induced per unit length in a solenoid as follows:
ε = -N(dΦ/dt)
A solenoid's magnetic flux is determined by:Φ = μ₀n²AI
where I is the solenoid's current (passing through it).
When we adjust for time in both sides of this equation, we obtain:
dI/dt = 0n2A(dd)
When we add this to Faraday's law, we obtain:
= -0n2A(dI/dt)N
Inputting the values provided yields:
= - (4 10 7 T m/A) (100 000 turns/m)² (7.07×10^−4 m²)(5.0 A/s)
ε = - 0.011 V/m
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The weighted rod floats with with 6cm of its length under water density (1000kg m3) .what length is under the surface when the rod floated in brine density (1200kg m3)?
The length of the rod under the surface of the water can be calculated using Archimedes’ principle. The principle states that the buoyant force on an object is equal to the weight of the fluid displaced by the object.
The buoyant force is given by the formula:
Buoyant force = Density of fluid x Volume of fluid displaced x Gravity
Since the rod is floating, the buoyant force is equal to the weight of the rod. We can use this to calculate the volume of fluid displaced by the rod.
Let L be the length of the rod under the surface of the water when it floated in brine density.
The weight of the rod is given by:
Weight of rod = Density of rod x Volume of rod x Gravity
Since the rod is floating, the weight of the rod is equal to the buoyant force.
Buoyant force = Weight of rod = Density of rod x Volume of rod x Gravity
The volume of fluid displaced by the rod is given by:
Volume of fluid displaced = Volume of rod = Length of rod x Cross-sectional area of rod
Since the cross-sectional area of the rod is constant, we can write:
Buoyant force = Density of fluid x Volume of fluid displaced x Gravity Density of rod x Volume of rod x Gravity = Density of fluid x Length of rod x Cross-sectional area of rod x Gravity
Solving for L, we get:
L = (Density of rod / Density of fluid) x Length of rod
Substituting the given values, we get:
L = (1000 / 1200) x 6 cm = 5 cm
Therefore, the length of the rod under the surface of the water when it floated in brine density is 5 cm.
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A refrigerator removes 37.0 kcal of heat from the freezer and releases 82.5 kcal through the condenser on the back. How much work was done by the compressor?
Answer:
work = (37.0 kcal) - (82.5 kcal) = -45.5 kcal
Explanation:
The first law of thermodynamics states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system. In this case, the refrigerator is removing heat from the freezer and releasing it through the condenser on the back. Therefore, the work done by the compressor is:
work = heat removed - heat released
The negative sign indicates that work was done on the refrigerator by an external agent (e.g., an electric motor) to remove heat from the freezer and release it through the condenser.
I got you Bruv :)
Find the heat energy per unit time per unit area (power/area, or 'flux') given off by a body having an emissivity € = 0.500 and temperature of 20.0° C. [Convert to Kelvin temperature.]
Therefore, the heat energy per unit time per unit area, or flux, emitted by the body is approximately 241.7 W/m².
What is the thermal energy equation?The heat transfer equation can be written as Q = m c T, where Q denotes the amount of heat transferred, m denotes mass, c denotes specific heat, and T denotes the temperature differential. Heat transfer is the process by which heat is transferred from a hot object to a cold object.
The Stefan-Boltzmann Law can be used to determine the thermal energy per unit time per unit area, or flux, released by a body:
F = σ * € * T⁴
To convert 20.0°C to Kelvin, we add 273.15 K to get 293.15 K.
Now we can plug in the values:
F = 5.67 x 10⁻⁸ W/m² K⁴ * 0.500 * (293.15 K)⁴
F ≈ 241.7 W/m²
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A railroad car of mass 2.00×104 moving at a speed of 3.00 collides and couples with another railroad car of mass 4.00×104 and moving toward it at 1.20 . What is the speed of the coupled cars after the collision?
The speed of the car after the collision is determined as 0.2 m/s.
What is the speed of the car after the collision?The speed of the car after the collision is calculated by applying the principle of conservation of linear momentum as follows;
m1u1 + m2u2 = v(m1 + m2)
where;
m1 and m2 are the masses of the carsu1 and u2 are the initial velocity of the carsv is the final velocity of the cars after the collision20000(3) - 40000(1.2) = v (20000 + 40000)
12,000 = 60,000v
v = 12,0000 / 60,000
v = 0.2 m/s
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If light passing through a medium with an index of refraction of 1.0 enters a medium with an index or refraction of 1.45, the beam will…
A. refract away from the normal in the new medium
B. refract towards the normal in the new medium
C. reflect and remain in the first medium
D. pass through without refracting
Answer:
correct option is B . toward the normal .
Explanation:
as we know , if the ray will pass from denser to rarer mediu, the ray will bend away from the normal
If light passing through a medium with an index of refraction of 1.0 enters a medium with an index or refraction of 1.45, Then the beam will refract towards the normal in the new medium. The correct answer is B.
What is the refractive index?The refractive index is a measure of how much a material bends or refracts light as it passes through it. It is defined as the ratio of the speed of light in a vacuum to the speed of light in the material:
n = c/v
Where
n = is the refractive index of the material,
c = is the speed of light in a vacuum (approximately 299,792,458 meters per second),
v = is the speed of light in the material.
The refractive index of a material is an important property that determines how much light is bent as it passes through the material. Materials with a higher refractive index bend light more than materials with a lower refractive index.
The refractive index of a material depends on its physical properties, such as its density, chemical composition, and temperature. It also depends on the wavelength of the light passing through the material, as different wavelengths of light can be refracted to different degrees.
Here in the question,
When light passes through a medium with a different index of refraction, it changes its speed and direction, a phenomenon is known as refraction. The angle of refraction depends on the angle of incidence and the indices of refraction of the two media.
The relationship between the angles of incidence and refraction is given by Snell's law:
n₁sinθ₁ = n₂sinθ₂
Where
n₁ and n₂ = are the indices of refraction of the first and second media, respectively,
θ₁ = is the angle of incidence,
θ₂= is the angle of refraction.
In this case, the light is passing from a medium with an index of refraction of 1.0 to a medium with an index of refraction of 1.45. Since the second medium has a higher index of refraction than the first, the light will bend towards the normal when it enters the second medium.
Therefore, the correct answer is B i.e The beam will refract towards the normal in the new medium.
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Block A has a mass of 10 kg and Block B has a mass of 70 Kg.
The Friction coefficient of Block A on the plane is 0.18, and the pulley friction is neglected. The block B is maintained at rest at a position 15 m above the ground. It is then released from rest and falls on the ground.
- Using the Conservation of Energy, what will be the velocity of Block B when it is at half of its path?
Velocity of block B when it is at half of its path is approximately 10.17 m/s.
What is Conservation of Energy?Law of conservation of energy is a fundamental principle in physics that states that energy cannot be created or destroyed, but can only be transformed from one form to another.
Potential energy of block B is : PE = mgh
m is mass of the block, g is acceleration due to gravity, and h is height of the block above the ground.
Initial potential energy of block B is: PEi = mgh = 70 kg × 9.81 m/s² × 15 m = 10290 J
When block B is at half of its path, its height above the ground is: h/2 = 15 m / 2 = 7.5 m
Final potential energy of block B at this height is: PEf = mgh/2 = 70 kg × 9.81 m/s² × 7.5 m = 5143.5 J
Change in potential energy is:
ΔPE = PEf - PEi = 5143.5 J - 10290 J = -5146.5 J
Kinetic energy of block B at half of its path is: KE = -ΔPE = 5146.5 J
Kinetic energy of block B is given by: KE = (1/2)mv²
v = √(2KE/m) = √(2ΔPE/m)
v = √(2 × 5146.5 J / 70 kg) = 10.17 m/s
Therefore, velocity of block B when it is at half of its path is approximately 10.17 m/s.
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Which meteoroid is most likely to reach the Earth’s surface? Explain why this is so, in terms of heat transfer. Use data from the table to support your response.
The meteoroid that is most likely to reach the Earth's surface is the one with the highest mass-to-surface area ratio which is number 2. This is because as a meteoroid enters the Earth's atmosphere, it encounters a great deal of resistance, which generates heat due to friction.
Meteoroids and Heat TransferMeteoroids are small rocky or metallic objects that are present in the solar system. They range in size from tiny particles to large boulders, and they can originate from comets, asteroids, or other celestial bodies. When a meteoroid enters the Earth's atmosphere, it becomes a meteor or a shooting star, and if it survives the descent and reaches the Earth's surface, it is then called a meteorite.
The meteoroid that is most likely to reach the Earth's surface is the one with the highest mass-to-surface area ratio. This is because as a meteoroid enters the Earth's atmosphere, it encounters a great deal of resistance, which generates heat due to friction. This heat is transferred to the meteoroid through conduction, and it can cause the meteoroid to vaporize or break apart. However, a larger meteoroid has more mass to dissipate this heat over, so it is less likely to be completely destroyed.
Additionally, a larger meteoroid has a smaller surface area to mass ratio, which means that there is less surface area to be heated and potentially destroyed by the heat generated during entry into the Earth's atmosphere. Therefore, a larger meteoroid with a higher mass-to-surface area ratio is more likely to survive and reach the Earth's surface.
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Meteoroid 2, with an initial mass of 3.24 kg, is most likely to reach the Earth's surface.
Why is Meteoroid 2 the most likely meteoroid?This is because the surface temperature of the meteoroid in space before entering the atmosphere is relatively high at 92°C, which means it has a greater amount of heat energy than the other meteoroids. When meteoroids enter the Earth's atmosphere, they encounter resistance from the air, which causes them to slow down and heat up due to friction.
The surface temperature of Meteoroid 2 at 150 km above the Earth's surface is 1727°C, which is higher than the other meteoroids. This suggests that Meteoroid 2 has a greater ability to resist the heat transfer from the high temperatures it reaches during entry into the Earth's atmosphere.
According to the table, the initial mass of Meteoroid 2 is the largest, and it also has the highest surface temperature in space. These factors contribute to the meteoroid's ability to resist heat transfer and increase the likelihood of it reaching the Earth's surface.
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Hot air moves into a valley, causing a hot day. Which method of heat transfer is this an example of?
Group of answer choices
Radiation
Kinetic energy
Conduction
Convection
How many nodes are on this standing wave? *
The number of nodes present in this standing wave is 6
How many nodes are on this standing wave?A standing wave is a type of wave that remains in a constant position and does not propagate through a medium. Instead, it oscillates in place between two fixed points, creating a pattern of constructive and destructive interference.
In a standing wave, nodes are the points along the medium that remain stationary, with no displacement or movement of the medium. These nodes occur at locations where the displacement of the medium is always zero, meaning that the amplitude of the wave is zero at those points.
In other words, nodes are the points of minimum energy in the standing wave. They are the points where the crest of the wave meets the trough of the wave, resulting in the cancellation of the wave's amplitude. The distance between two adjacent nodes is half of the wavelength of the standing wave.
In this standing wave, the number of nodes present is 6
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Define the term schema as used by piaget
Answer:A schema, or scheme, is an abstract concept proposed by J. Piaget to refer to our, well, abstract concepts.
Explanation:
2. A pencil case is dropped vertically from a height at rest and hits the ground 0.5 seconds later. a) What vertical velocity did the pencil case hit the ground with? b) What horizontal velocity did the pencil case hit the ground with? 3. A stone is projected vertically upwards with a velocity of 12ms¹. Calculate or find: a) How long it took the stone to reach its maximum height. b) Maximum height reached by the stone. 4. A balloon is climbing vertically upwards with a constant velocity of 4.2ms¹. A sandbag is dropped from the balloon and hits the ground 3.6 seconds later. Calculate or find: a) Velocity of the sandbag as it hits the ground.
An individual dropped the sandbag from a height of 63.504 metres.
How does moment of inertia change with angular momentum?The relationship between angular momentum L and moment of inertia I and angular speed, expressed in radians per second, is shown. Moment of inertia is different from mass in that it depends on both the form and location of the axis of rotation in addition to the amount of stuff present.
vf = vi + at
vf = 0 + (9.8 m/s²)(0.5 s)
vf = 4.9 m/s
vf = vi + at
0 = 12 m/s - (9.8 m/s²)t
t = 1.22 s
Δy = vi t + 1/2 a t²
Δy = (12 m/s)(1.22 s) + 1/2 (9.8 m/s²) (1.22 s)²
Δy = 7.33 m
Δy = vi t + 1/2 a t²
Δy = vi t + 1/2 a t²
0 = (4.2 m/s)(3.6 s) + 1/2 (9.8 m/s²) (3.6 s)² + Δy
Δy = -63.504 m
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A stick is resting on a concrete step with 1/7 of its total length hanging over the edge. A single ladybug lands on the end of the stick hanging over the edge, and the stick begins to tip. A moment later, a second, identical ladybug lands on the other end of the stick, which results in the stick coming momentarily to rest at theta = 67.3 degrees with respect to the horizontal, as shown in the figure. If the mass of each bug is 3.09
times the mass of the stick and the stick is 11.5 cm long, what is the magnitude of the angular acceleration of the stick at the instant shown? Use =9.81 m/s2.
Let the stick be divided into two parts, A and B, by the point where the two ladybugs are sitting. Let the length of part A be x and the length of part B be (1-x). Then, we have:
x + (1-x) = 1
Let the distance of the midpoint from the end of part A be d. Then, we have:
d = x/2 - (1/7)
Let the mass of the stick be M and the mass of each ladybug be m. Then, we have:M = 7m
The gravitational force acting on the system produces a clockwise moment about the end of part A, which is given by:
Mg(x/2 - d) = Mg(x/2 - (x/2 - 1/7)) = Mg/7
Let the distance of the first ladybug from the end of part A be L1 and the distance of the second ladybug from the end of part A be L2. Then, we have:
L1 = x
L2 = 1 - (1-x) = x
The moments produced by the ladybugs are given by:
mgL1sinθ
mgL2sinθ
mgL1sinθ = mgL2sinθ = Mg/7
Substituting the given values and solving for θ, we get:
sinθ = M/14m = 1/14
θ = 3.87 degrees
Mg(x/2 - d)sinθ
2mgL1sinθ
Substituting the given values and solving for x, we get:
x = 0.315
Substituting this value into the equation for the moment of inertia, we get:
I = 1.08e-5.
What is an inertia ?Inertia is the property of an object to resist any change in its state of motion. It is a measure of an object's resistance to changes in its velocity, including changes in direction and speed. Objects with more mass have more inertia, and they require more force to be moved or to stop moving. Inertia is described by Newton's first law of motion, which states that an object at rest will remain at rest, and an object in motion will remain in motion with a constant velocity, unless acted upon by an external force.
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A motor uses a movable pulley to lift a box weighing 100000N to a height of 10m, taking 10 seconds.
a. Calculate the pulling force that the engine has exerted.
b. Calculate the power of the motor.
c. Know the efficiency of the motor is 50%. How much work does it take to lift 100 boxes?
If a motor uses a movable pulley to lift a box weighing 100000N to a height of 10m, taking 10 seconds.
a. The pulling force that the engine has exerted is 50000N.
b. The power of the motor is 50000W or 50kW.
c. The work it take to lift 100 boxes is 200,000,000J.
How to find work exerted?a. The mechanical advantage of a movable pulley is 2, so the pulling force that the engine has exerted is:
Pulling force = weight of the box / mechanical advantage
Pulling force = 100000N / 2
Pulling force = 50000N
b. The power of the motor can be calculated using the formula:
Power = work / time
The work done by the motor is equal to the force applied multiplied by the distance traveled by the box:
Work = force x distance
Work = 50000N x 10m
Work = 500000J
Therefore, the power of the motor is:
Power = work / time
Power = 500000J / 10s
Power = 50000W or 50kW
c. The work done to lift one box is equal to the weight of the box multiplied by the height lifted:
Work per box = weight of the box x height
Work per box = 100000N x 10m
Work per box = 1,000,000J
To lift 100 boxes, the work required is:
Total work = work per box x number of boxes
Total work = 1,000,000J x 100
Total work = 100,000,000J
However, since the efficiency of the motor is 50%, only half of the input energy is converted to useful work. Therefore, the actual work required is:
Actual work = total work / efficiency
Actual work = 100,000,000J / 0.5
Actual work = 200,000,000
Therefore, the motor needs to perform 200,000,000J of work to lift 100 boxes, taking into account its 50% efficiency.
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An incompressible fluid of uniform density flows through an infinitely long pipe. See picture below. In the section shown, the pipe narrows from a diameter of 4 cm to a diameter of x cm, and the fluid is flowing through the narrow region at a speed of 3 m/s. What is the flow speed of the fluid in the wide region of the pipe? a. 16x^2/3 m/s b. 12x^2 m/s c. 3x^2/4 m/s d. 4x^2/3 m/s
e. 3x^2/16 m/s
The flow speed of the fluid in the wider section of the pipe is x^2/3 m/s. The correct option is d.
Since the pipe is infinitely long, the mass flow rate of the fluid is constant throughout the pipe. Therefore, the product of the density, cross-sectional area, and flow speed is also constant throughout the pipe.
Let's assume that the density of the fluid is ρ and the diameter of the narrower section is x cm. Then, the cross-sectional area of the narrower section is πx^2/4. From the given information, the flow speed in the narrower section is 3 m/s.
Using the equation of continuity,
A1V1 = A2V2
π(4/2)^2V1 = πx^2/4 * 3
V1 = (3/16) * (16x^2/3) = x^2/3
Therefore, the flow speed of the fluid in the wider section of the pipe is x^2/3 m/s. Hence, the correct option is (D).
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Help me on this question!
The other ball will go up to a height of 4.3 m after the collision.
What is the height risen by the ball after the collision?To solve this problem, we can use the principle of conservation of energy and momentum.
Let's first find the initial potential energy of the dropped ball:
E_i = mgh = 5 kg x 9.8 m/s² x 12 m = 588 J
When the ball hits the bar, the momentum is conserved:
m1v1 + m2v2 = (m1 + m2)vf
where;
m1 is the mass of the dropped ball (5 kg), v1 is its initial velocity (0), m2 is the mass of the bar (9 kg), v2 is the velocity of the bar after the collision, and vf is the final velocity of the system (the bar and the dropped ball) after the collision.We can simplify this equation by noting that the bar is initially at rest, so v2 = 0:
m1v1 + m2v2 = (m1 + m2)vf
5 kg x 0 m/s + 9 kg x 0 m/s = (5 kg + 9 kg + 5 kg)vf
vf = 0 m/s
This means that the system (the bar and the dropped ball) comes to a momentary stop just after the collision.
Now, let's find the final potential energy of the system:
E_f = (m1 + m2)gh
E_f = (5 kg + 9 kg) x 9.8 m/s² x h
E_f = 137.2 J x h
We can equate the initial and final energies:
E_i = E_f
588 J = 137.2 J x h
h = 4.3 m
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when finding the block by hanging it from a force meter. force is measured to be u.sn what mass is the mass of the object in grams
The mass of the object in grams can be determined by multiplying the force that was measured (u.sn) by the acceleration due to gravity (g). The acceleration due to gravity on Earth is 9.8 m/s².
Define acceleration due to gravity.The acceleration of an object in free fall within a vacuum is known as gravitational acceleration (and thus without experiencing drag). This is the constant acceleration brought on just by the gravitational pull. Gravimetry is the measurement and analysis of these rates. All bodies accelerate at the same rate in vacuum, independent of their masses or compositions.
The combined effects of gravity and the centrifugal force from Earth's rotation cause the Earth's gravity to be as great as it is at a given location on the surface.
What are the factors affecting acceleration due to gravity?The four elements listed below have the biggest impacts on g:
1) the Earth's form.
2) Earth's rotational motion.
3) height above the surface of the Earth.
4) length of time spent underground.
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A spring is holding a door open. What type of energy is in the compressed spring?
Group of answer choices
Chemical energy
Spring potential energy
Kinetic energy
Elastic potential energy
Assuming all objects are moving with the same velocity, which statement describes the object with the largest inertia?
A bowling ball rolls across a street and into a large soccer field.
A driver continues forward after his car takes a sharp turn.
A helicopter is following a high-speed pursuit across town.
A pebble is thrown in space and continues in a straight line.
All objects are moving with the same velocity, A bowling ball rolls across a street and into a large soccer field. Hence, the correct option is (a).
Inertia is the resistance of an object to changes in its motion, and it depends on the object's mass. The greater the mass of an object, the greater its inertia. In option (a), the bowling ball has the largest mass and therefore the greatest inertia among the objects described. The driver in option (b) experiences a force that changes the direction of his motion, so his inertia is not as great as the bowling ball's. In option (c), the helicopter is actively moving and changing its velocity, so its inertia is not as great as the bowling ball's. In option (d), the pebble has a much smaller mass than the other objects and therefore less inertia.
Therefore, option (a) - A bowling ball rolls across a street and into a large soccer field - describes the object with the largest inertia assuming all objects are moving with the same velocity.
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On a distance vs. time graph, the slope of the line equals the object’s? 9._____
Answer: speed
Explanation: On a distance vs. time graph, the slop of the line equals how fast an object is going.
please use strictly python and only euler-cromer method
thank you
Answer:
Driven pendulum = 2.0 f =0.2 q =1.0
in this experiment you need to examine the idea of thermal energy transfer. Using a controlled experiment what might a good question about the variables that affect thermal energy transfer be? Therapist energy transfer depends on many properties, but limit your question to only two
The thermal conductivity of a material and the temperature differential between two objects affect the rate of thermal energy transfer between them would be an excellent question on the factors that influence thermal energy transfer.
What is an example of regulating the passage of thermal energy?The amount of radiant energy that enters a residence in the winter is maximised by large windows that face south. Tiny windows that face north help keep heat in. Triple-paned windows minimise thermal energy loss.
What elements influence the transfer of thermal energy?The surface area, volume, material, and kind of the surface the object is in touch with are all factors that affect how quickly an object transfers energy by heating.
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**NEED ANSWER ASAP**
Identify the constellation, label any of the names stars or asterisms that were covered in class
Answer: I believe this constellation is cygnus, the swan. The brightest star is Deneb at the tail. The bright double star at the head of the swan is Albireo.
Explanation:
find distance of this v-t graph
The distance of the v-t graph as shown in the diagram is 1000 m.
How to find the distance in a v-t graph?
To calculate the distance in a velocity-time graph, we find the total area under the graph
From the graph in the question above,
Distance in the v-t graph = Area of a tripezium = h(a+b)/2A = h(a+b)/2........................ Equation 1Where:
A = Total distance of the v-t graphh = Height of the tripeziuma and b = Both parallel side of the tripeziumFrom the diagram,
h = 50 secondsa = 10 m/sb = 30 m/sSubstitute these values into equation 1
A = 50(10+30)/2A = 50×20A = 1000 mHence, the distance is 1000 m.
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What happens to artificial satellites sent into the Earth’s orbit?
Artificial satellites are launched into Earth's orbit for various purposes, including communication, navigation, weather monitoring, scientific research, and military surveillance.
What exactly happens when artificial satellites are sent into the Earth’s orbit?Artificial satellites sent into Earth's orbit the Earth, typically at an altitude between 200 and 22,000 miles, depending on its intended purpose. Satellites in low Earth orbit (LEO) travel at a speed of about 17,500 miles per hour, completing one orbit in about 90 minutes, while satellites in geostationary orbit (GEO) remain stationary above the equator at an altitude of about 22,236 miles.
Satellites can remain in orbit for many years, but eventually, they can fall out of orbit due to atmospheric drag or collisions with space debris. When a satellite falls out of orbit, it typically burns up in Earth's atmosphere, although larger satellites may leave debris that can pose a risk to other spacecraft.
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When a car is stopped, facing upwards on a hill, which way does friction act?
When a car is stopped, facing upwards on a hill, the friction acts in the opposite direction to the motion that the car would naturally take if it were not stopped.
In this case, the car would roll backwards down the hill due to the force of gravity. The friction between the tires and the road surface acts in the opposite direction to this motion, providing a force that opposes the car's tendency to roll backwards. Therefore, the friction acts in the forward direction, up the hill, to prevent the car from rolling backwards.
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