[tex] - 15 + 8x = x + 3 \\ 8x - x = 3 + 15 \\ 7x = 18 \\ \\ x = \frac{18}{7} \\ \\ x = 2.571[/tex]
We put the unknown on one side, and the other end is empty of the unknown , When it turns to the other side, its sign changes.
As for the number with the unknown, it becomes the denominator with the number without the unknown.
I hope I helped you^_^
Find the formula for the geometric sequence 4, -8, 16, -32
Answer:
bn=4*(-2)^(n-1) where n is a number of searched term
Step-by-step explanation:
b1=4 b2=-8
q=b2/b1=-8/4=-2
bn=b1*q^(n-1)
bn=4*(-2)^(n-1) where n is a number of searched term
even numbers are closed under addition? true or false
Even numbers are closed under addition.
Answer: True
Answer:
Even numbers are closed under addition.
Answer: True
Step-by-step explanation:
A perpendicular bisector runs through the middle of a line segment and splits into
Answer:
B two congruent pieces
Step-by-step explanation:
Perpendicular means at a 90 degree angle
bisector means it divides in it half, into two equal pieces
suppose Point G represents a duck flying over a Lake, point H and J represent two ducks swimming on the lake. Which is a true statement?
Answer:
Choice D. There is exactly one plane that contains the three ducks: [tex]\sf G[/tex], [tex]\sf H[/tex], and [tex]\sf J[/tex].
Step-by-step explanation:
The three points [tex]\sf G[/tex], [tex]\sf H[/tex], and [tex]\sf J[/tex] are distinct since each of the three points represents a different duck.
There's only one line through two distinct points in a 2D cartesian plane.
Likewise, given two distinct points ([tex]\sf G[/tex] and [tex]\sf J[/tex]) in a 3D space, there would be only one line two the two points.
Assume that plane [tex]\sf L[/tex] represents the plane that contains the surface of the lake.
A line is in a plane if and only if all points on that line are in the said plane.
Point [tex]\sf G[/tex] is on the line that contains [tex]\sf G\![/tex] and [tex]\sf H[/tex]. However, since point [tex]\!\sf G[/tex] denotes the flying duck, this point would not be in [tex]\sf L[/tex] (the plane that contains the surface of the lake.)
Hence, the line that contains [tex]\sf G\![/tex] and [tex]\sf H\![/tex] would not be in plane [tex]\sf L\![/tex].
Given three distinct points in a 3D space, there would be exactly one plane that contains the three points.
Hence, three points in a 3D space would not be non-coplanar.
In this question, point [tex]\sf G[/tex], [tex]\sf H[/tex], and [tex]\sf J[/tex] are all distinct. Hence, there would be exactly one plane that contains these three points.
After a grueling year of work, you (Padcha) decide you need absolute peace and quiet for about a month (February). You visit San Pedro de Atacama in the Atacama dessert of Chile, one of the most pristine and beautiful spots on earth. Every morning you have an espresso with a Swiss veterinarian, Dieter, that has retired there and maintains a small hotel and cafe. After week 2 of peace and quiet you become restless for a more meaningful existence.
In a conversation Dieter you learn that he also raises Llama's, Alpacas, and Vicuñas (all members of the Camel Family) for their wool. The conversation follow--
Dieter: "Padcha, I have this problem related to the nutrition of my animals. I know the nutritional content of the feeds I have available (see the Daily Nutritional Requirements for Animals table). I also know the cost of a kilogram of each feed (see table). I would love to have a way of selecting a mix of Corn, Tankage, and Alfalfa that minimizes my daily cost of providing good nutrition for my animals."
Padcha: "Dieter, I think I might be able to help. In LP optimization, there is a problem that is called the nutrition problem. Of course, it is not only about nutrition, it's also about allocating available resources, in an optimal way (minimal cost), to satisfy requirements. You can image, that there are a lot of problems like that in business. A typical constraint, say for carbohydrates, would read-- the number of kilos of Corn times 90, plus the number of kilos of Tankage times 20, plus the number of kilos of Alfalfa times 40 must equal a minimum 200 units of carbohydrates. The constraint shows how we use the resources/decision variables (kilos of Corn, etc.) to satisfy nutritional needs.
Daily Nutritional Requirements for Animals
Kg. Corn KG. Tankage Kg. Alfalfa Min. Daily Reqs.
Carbohydrates 90 20 40 200
Protein 30 80 60 180
Vitamins 10 20 60 150
$Cost of feed/Kg. 35 30 25
a) What is the LP for the nutrition problem?
b) Solve the problem using Solver. What is the value of the optimal solution? What is the number of kilos of Corn, Tankage, and Alfalfa? (Place the Answer Report below)
c) What if the requirements were raised by 1 unit for carbohydrates (from 200 to 201). Without re-solving the problem, what is the new optimal solution value and the units of carbohydrates? (Provide the logic for your answer.)
d) What is the allowable range of values for the coefficient of the Tankage in the objective function, for which a change of the optimal decision variables will not occur?
Answer:YA IM THAT KIND OF GUY I NEED POINTS
Step-by-step explanation:
YA IM THAT KIND OF GUY I NEED POINTS
tìm diện tích hình thang
Answer:
Diện tích hình thang bằng trung bình cộng của 2 đáy nhân với chiều cao của nó. Trong đó: + S: Diện tích. + a,b: Lần lượt là độ dài 2 đáy.
Step-by-step explanation:
uhhh hope that helps:3
Maram is a real estate agent. She earns 6,5% commission on each sale she
makes. Last month she sold one house for $250,000 and another for $310,000.
What did Maram earn in commissions for the month? *
The commission earned by Maram for the given month is $36,400
The given parameter:
percentage of the commission earned by Maram = 6.5%first house sold for the month = $250,000 second house sold for the month = $310,000The commission earned by Maram for the given month is calculated as follows;
[tex]amount \ earned = initial \ amount \times percentage\\\\amount \ earned =0.065(\$250,000) + 0.065(\$310,000) \\\\amount \ earned =\$ 36,400[/tex]
Thus, the commission earned by Maram for the given month is $36,400
Learn more here: https://brainly.com/question/15363170
Which of the following is equivalent to?
Answer:
Answer is 1/6
Step-by-step explanation:
[tex] {36}^{ - \frac{1}{2} } \\ = \frac{1}{ {36}^{ \frac{1}{2} } } \\ \\ = \frac{1}{ \sqrt{36} } \\ \\ = \frac{1}{6} [/tex]
* Suppose that hat f (3)= 1 2 , and hat f (x)>0 , and hat f (x)<0 Is it possible that hat f (2)=
Answer:
I would say true
Step-by-step explanation:
f'(x)>0 is an increasing function
f''(x)<0 is concave down
2<3, 1/3<1/2
24x0.17 help plsssss!
Answer:
4.25
Step-by-step explanation:
brainliest to correct answer
Answer:
14
Step-by-step explanation:
Answer:
14
Step-by-step explanation:
Is f(x)=x^4-x^2 even or odd
In a shipment of 600 parts, 30 are found to be defective. How many defective parts should be expected in a shipment of 1000?
50
200
40
150
if a and b are zeros of the polynomial f(x) = 5x^2+4x-9 then evaluate the following :a^3-b^3.
Answer:
Results will be out: 854/ 125 (Please note that the result is a decimal number)
Step-by-step explanation:
If you need me to explain the steps clearly, please let me know.
I'm not sure but hope it helps.
Identify the terms and coefficients in each expression.
X square 2 - 9y square 2 + 3k
[tex]\\ \rm\longmapsto x^2-9y^2+3k[/tex]
Terms[tex]\\ \rm\longmapsto x^2,-9y^2,3k[/tex]
Coefficients
[tex]\\ \rm\longmapsto x^2=1[/tex]
[tex]\\ \rm\longmapsto -9y^2=-9[/tex]
[tex]\\ \rm\longmapsto 3k=3[/tex]
A committee of 4 boys is selected from 10 boys?
a. How many different committees can be selected?
b. How many of these contain on particular boy x?
c. How many of these contain two particular boys x and y?
d. How many do not contain x?
Answer:
I don't know about this thing
Which number is the largest?
Answer:
54.895
Step-by-step explanation:
hopes it's help you
express
[tex](4 - x) {}^{ \frac{1}{2} } [/tex]
in ascending power of x up to term x²
Answer:
Step-by-step explanation:
Remember:
[tex]\boxed{(1+y)^{\frac{1}{2} }= 1+\dfrac{y}{2} -\dfrac{y^2}{2*4} +\dfrac{1*3*y^3}{2*4*6} +K\ with -1 < y \leq 1 }\\\\\\Let\ say\ 4-x=1+y\ or\ y=3-x\\\\\\(4-x)^{\frac{1}{2} }=1+\dfrac{3-x}{2} -\dfrac{(3-x)^2}{2*4} +K\ with\ 2\leq x <4\\\\=\dfrac{29}{8} -\dfrac{5x}{4} +\dfrac{x^2}{8} +K\\[/tex]
Length of path for the above example
Answer:
D. 25.5 m
Step-by-step explanation:
5.5m+5.5m=11m
4.5m-1m= 3.5m
3.5m+3.5m=7m
The middle vertical path is 3.5m
the middle horizontal path is 5.5m-1.5m=4m
The sum of all is 25.5m
What is the area of BCD?
A. 36 square units
B. 32 square units
C. 16 square units
D. 72 square units
Answer:
in this figure B: 32 square units
order pair for x-3y=6
Answer:
X=6+3y
y=x-6/3
Step-by-step explanation:
1)x-3y+3y=6+3y
x=6+3y
2)3y+6=x
3y=x-6
y=x-6/3
I need the answer, please help!!!
Step-by-step explanation:
0.5 goes first
0.44 goes second
2/5 goes third
3/8 goes fourth
once second I'm ggettin the question
Answer:
0.51
Step-by-step explanation:
-32÷(-61)
in this case the subtraction have to cancel themselves
so it'll remain
32÷61
=0.508
approximately ~=0.51
Simplify the given expression. Assume x = 0
-2
20r-3
10x-1
2
4
Answer:
x⁴/4
Step-by-step explanation:
(20x‐³/10x‐1)‐²
= > 20/10 = 2
so = (2x-³/x-¹)-²
= (2/x²)-²....................(a/b)-²=(b/a)²
= (x²/2)²
= x⁴/2
_ 1. If U = {1,2,3,4,5) and A= {2,4} then A' should be?
a. {2,4,5)
b. {2,4}
c. {1,2,3,4,5)
d. {1,3,5)
If U={1,2,3,4,5) and A={2,4) then A' should be
Ans» d.{1,3,5}
Mr. Thompson's sixth grade class is competing
Three tiles of thickness 20 mm, 17 mm and 8 mm are piled on the top of each other. What is the total thickness of pile in cm?
Answer:
4.5 cmStep-by-step explanation:
Givens: 20 mm, 17 mm and 8 mmOperations: Addition and DivisionSolutions: 20 + 17 + 8 = 45 mm45 mm ÷ 10 = 4.5 cmAnswer: 4.5 cm[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]
Please someone help me.
Answer:
I will help
Step-by-step explanation:
Jaxson did the following problem incorrectly. Choose the option that correctly identifies what Jaxson did
wrong.
Jaxson's work:
8 3/5 + 7 1/8 = 15 4/13
Answer:
4/13 very identifies what Jaxson did wrong.
Step-by-step explanation:
The addition of the whole number part of the fraction was well done that is (8+7)
What Jaxson did wrong in his work was the addition of the fractions (⅗+⅛). They have different denominators and thus can't be added straightforwardly. the denominator has to be a common value.
3) What type of correlation would temperature
and ice cubes have?