2. What would the volume of air inside a 40. 0 L tire under 218 kPa of pressure occupy if it all escaped into a balloon at 101. 3 kPa?

An H2 molecule only has three unique isotope combinations.

The 3H (or hydrogen-3) isotope is more commonly referred to as tritium than the 2H (or hydrogen-2) isotope. Sometimes, deuterium and tritium are represented by the letters D and T rather than 2H and 3H. Although though this application is widespread, according to the IUPAC, it is not preferred.

Each hydrogen atom in a hydrogen molecule (H2) can either be the 1H isotope (also known as protium) or the 2H isotope (also called deuterium). As a result, each hydrogen atom has two potential isotopes, for a total of 2 2 = 4 possible isotope combinations in an H2 molecule. These four potential pairings are as follows:

Both hydrogen atoms are 1H (H-H)

Both hydrogen atoms are 2H (D-D)

The first hydrogen atom is 1H and the second hydrogen atom is 2H (H-D)

The first hydrogen atom is 2H and the second hydrogen atom is 1H (D-H)

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1. Chlorine is a halogen and has a charge of -1. The chemical formula for chloride ion is Cl⁻.

2. Sodium is an alkali metal and has a charge of +1. The chemical formula for sodium ion is Na⁺.

3. Ammonium ion is a polyatomic ion with a charge of +1. The chemical formula for ammonium ion is NH₄⁺.

4. Beryllium is an alkaline earth metal and has a charge of +2. The chemical formula for beryllium ion is Be²⁺.

5. Nitrite ion is a polyatomic ion with a charge of -1. The chemical formula for nitrite ion is NO₂⁻.

6. Calcium is an alkaline earth metal and has a charge of +2. The chemical formula for calcium ion is Ca²⁺.

7. Oxygen is a nonmetal and typically has a charge of -2. The chemical formula for oxide ion is O²⁻.

8. Bromate ion is a polyatomic ion with a charge of -1. The chemical formula for bromate ion is BrO₃⁻.

9. Phosphate ion is a polyatomic ion with a charge of -3. The chemical formula for phosphate ion is PO₄³⁻.

10. Sulfur is a nonmetal and can have a charge of -2, -1, 0, +2, +4, or +6 depending on the compound. For example, the chemical formula for sulfide ion (S²⁻) is formed when sulfur gains two electrons and has a charge of -2.

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Answer:

IT IS IRON.

Explanation:

This ion has 24 electrons, so it has experienced a loss of 2 electrons. So, charge on ion is 2+. Also, the element with 26 protons (26 atomic number) is iron (Fe).

Answer: it’s all weak like me :(

Explanation:

The concentration of hydrogen ions (H+) and hydroxide ions in a solution determines its pH. (OH-). Svante Arrhenius, a Swedish scientist, proposed the Arrhenius model of acids and bases in 1884.

The pH that an acid will create in solution will decrease the stronger the acid is. The negative logarithm of the concentration of hydronium ions is used to determine pH.

The Arrhenius theory states that an acid is a chemical that releases an H+ ion when dissolved in water. It raises the amount of H+ ions present in the solution. A chemical that ionises the OH- ion is the base.

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To determine the final temperature of the water, we need to use the principle of conservation of energy. The heat lost by the hotter water will be gained by the cooler water until they reach thermal equilibrium.

We can use the following equation to calculate the final  temperature :

m1c1ΔT1 + m2c2ΔT2 = 0

where m1 and m2 are the masses of the two samples of water, c1 and c2 are their specific heats, and ΔT1 and ΔT2 are the temperature changes.

In this case, m1 = m2 = 100.0 g and c1 = c2 = 4.184 J/g°C (the specific heat of water). ΔT1 = 84.7°C - T (where Tis the final temperature) and ΔT2 = T - 79.6°C.

Substituting these values into the equation, we get:

100.0 g x 4.184 J/g°C x (84.7°C - T) + 100.0 g x 4.184 J/g°C x (T - 79.6°C) = 0

Solving for T, we get:

T = (100.0 g x 4.184 J/g°C x 84.7°C + 100.0 g x 4.184 J/g°C x 79.6°C) / (100.0 g x 4.184 J/g°C x 2)

T = 82.15°C

Therefore, the final temperature of the water is 82.15°C.

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The electrons that are used in the light reactions of photosynthesis are provided by water (H2O), so the correct answer is (c) H2O.

During the light reactions, light energy is absorbed by the photosystems in the thylakoid membranes of chloroplasts, and this energy is used to split water molecules into oxygen gas (O2), protons (H+), and electrons (e-). The electrons are then used to power the electron transport chain, ultimately leading to the generation of ATP and NADPH, which are used in the Calvin cycle to fix carbon dioxide (CO2) into organic molecules.

The light reactions are located in the thylakoid membrane of the chloroplast, which is also where the pigments (chlorophyll a and b) are located. When a photon of light hits a chlorophyll molecule, it excites the electron to a higher energy level, kicking off a series of reactions that eventually leads to the production of ATP and NADPH. The energy from these molecules is then used to drive the reactions of the Calvin cycle, which produce glucose, sucrose, and other sugars. So, light is the source of energy for photosynthesis to occur. Hence, light provides the electrons that are used in the light reactions. Option C.

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The ranking of the given carboxylic acids in order of increasing acid strength is as follows: B < A < D < C.

The reason for this trend is that electron-withdrawing fluorine atoms in the carboxylic acids increase the acidity of molecule by withdrawing electron density from the carboxyl group, which makes it easier to release a proton. The more electron-withdrawing the substituents, more acidic the carboxylic acid. In this case, compound C has the strongest electron-withdrawing group (CF3), which makes it most acidic of the four. Compound D has a weaker electron-withdrawing group (CHF2), making it less acidic than C but more acidic than B. Therefore, the acid strength of the given carboxylic acids can be ranked as: C > D > A > B.

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The solution's pH is 2.82 and In a 0.62 M solution, propanoic acid ionisation is 0.24%.

The Ka value for propanoic acid (HC₃H₅O₂) is 1.3 × 10⁻⁵. To calculate the pH and percent ionization of a 0.62M solution of propanoic acid, we can use the following equations:

Ka = [H⁺][C₃H₅O₂⁻]/[HC₃H₅O₂]

percent ionization = [H⁺]/[HC₃H₅O₂] x 100

(a) pH Calculation:

We can assume that the initial concentration of propanoic acid, [HC₃H₅O₂] , is equal to the given concentration of 0.62 M.

Let x be the concentration of [H⁺] and [C₃H₅O₂⁻] that forms upon dissociation of the propanoic acid. Since the propanoic acid is a weak acid, we can assume that the concentration of [H⁺] that forms is much smaller than the initial concentration of [HC₃H₅O₂]. Therefore, we can assume that the concentration of [HC₃H₅O₂] after dissociation is approximately equal to the initial concentration.

Using the Ka expression, we can set up the following equation:

1.3 × 10⁻⁵ = x² / (0.62 - x)

Solving for x using the quadratic formula, we get:

x = 0.0015 M

Therefore, the pH of the solution is:

pH = -log[H+] = -log(0.0015) = 2.82

(b) Percent Ionization Calculation:

The percent ionization can be calculated using the equation:

percent ionization = [H⁺]/[HC₃H₅O₂] x 100

From the previous calculation, we know that [H⁺] = 0.0015 M and [HC₃H₅O₂] = 0.62 M.

percent ionization = (0.0015/0.62) x 100 = 0.24%

Therefore, the percent ionization of propanoic acid in a 0.62 M solution is 0.24%.

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In a neutralization reaction, the acid reacts with the base and produces salt and water. The point where the acid and base are present in stoichiometric proportions is known as the equivalence point. To find the molarity of H2SO4, we first need to consider the balanced chemical equation for the reaction between H2SO4 and KOH:

H2SO4 + 2KOH → K2SO4 + 2H2O

From this equation, we can see that 1 mole of H2SO4 reacts with 2 moles of KOH. Now, we can use the information given to calculate the moles of KOH:

moles of KOH = molarity × volume
moles of KOH = 0.540 M × 58.5 mL × (1 L / 1000 mL) = 0.03159 moles

Since 1 mole of H2SO4 reacts with 2 moles of KOH, we can find the moles of H2SO4:

moles of H2SO4 = 0.03159 moles KOH × (1 mole H2SO4 / 2 moles KOH) = 0.015795 moles

Now, we can find the molarity of H2SO4:

molarity of H2SO4 = moles of H2SO4 / volume of H2SO4
molarity of H2SO4 = 0.015795 moles / (25.00 mL × 1 L / 1000 mL) = 0.6318 M

So, the molarity of H2SO4 is approximately 0.632 M (option b).

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Overall, the order of decreasing C-C bond length is dependent on the hybridization of the carbon atoms involved, with sp hybridization resulting in the shortest bond length and sp3 hybridization resulting in the longest bond length.

The length of carbon-carbon bonds depends on the hybridization of the carbon atoms involved. In general, the greater the s-character of the hybridized orbitals, the shorter the bond length.

Therefore, the order of decreasing carbon-carbon bond length for the given compounds can be predicted based on the hybridization of the carbon atoms involved in each compound.

a. H₂CCH₂ < H₃CCH₃ < HCCH

In this series, all carbons are sp3 hybridized in H₃CCH₃, and thus the C-C bond length is the longest. In H₂CCH₂, the carbon atoms are sp2 hybridized, which results in a shorter C-C bond length. In HCCH, the carbon atoms are sp hybridized, which results in the shortest C-C bond length. Therefore, the order of decreasing C-C bond length is:

H₃CCH₃ > H₂CCH₂ > HCCH

b. H₃CCH₃ < H₂CCH₂ < HCCH

This order is the opposite of the previous one. However, the reason behind it is the same, as the sp3 hybridization of H3CCH3 carbon atoms results in the longest C-C bond length, while the sp hybridization of HCCH carbon atoms results in the shortest bond length.

c. HCCH < H₂CCH₂ < H₃CCH₃

This order is the same as the first one. Again, the sp hybridization of HCCH carbon atoms results in the shortest C-C bond length, while the sp3 hybridization of H3CCH3 carbon atoms results in the longest bond length. Therefore, the order of decreasing C-C bond length is:

HCCH > H₂CCH₂ > H₃CCH₃

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Answer:

COOH is the carboxylic acid.

A compound that increases the number of hydroxide ions (OH-) when dissolved in water is called a base.

Bases are substances that have a pH greater than 7 and can neutralize acids to form salts and water. They are characterized by their ability to turn red litmus paper blue, which is a common test used to identify the presence of bases. Examples of common bases include sodium hydroxide (NaOH), potassium hydroxide (KOH), and calcium hydroxide (Ca(OH)2). When a base is dissolved in water, it dissociates to form hydroxide ions and the corresponding cation. Bases play a vital role in many chemical reactions, as in  production of soap,  neutralization of acidic waste streams, and the regulation of pH in biological systems.

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The pH of the buffer solution that is 0.050 M in benzoic acid (HC7H5O2) and 0.150 M in sodium benzoate (NaC7H5O2) is calculated as 4.68.

pH refers to the concentration of hydrogen ions in any solution and this is the indicator of a solution's acidity or alkalinity

Buffer solution is one that resists changes in pH when small amounts of acid or base are added.

HC7H5O2(aq) + H2O(l) ⇌ H3O+(aq) + C7H5O2-(aq)

Ka = [H3O+][C7H5O2-]/[HC7H5O2]

[HC7H5O2] = 0.050 M

[C7H5O2-] = 0.150 M

H3O+(aq) + C7H5O2-(aq) → HC7H5O2(aq) + H2O(l)

pH = pKa + log([C7H5O2-]/[HC7H5O2])

pKa is negative logarithm of the acid dissociation constant (pKa = -log(Ka)).

pH = -log(6.5×10^-5) + log(0.150/0.050)

= 4.20 + 0.477

pH = 4.68

Therefore, pH of the buffer solution is 4.68.

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As just a result, the unknown chemical has a specific heat of about 0.952 J/(g°C). temperature with one gramme of a substance with one Celsius degree.

The quantity of thermal energy needed to increase a substance's temperature by 1°C per unit mass is known as its specific heat capacity (or 1K). joule per kilogramme per kelvin is the SI unit (Jkg-1K-1).

The following equation can be used to determine specific heat, abbreviated Cp: Cp=Qm T C p = Q m T, where m is the material's mass, Q is the heat energy supplied to the substance, while T is the substance's change in temperature.c ≈ -1292.05 J / [(46.4 g) (97.63°C − 46.20°C)]

= -1292.05 J / [(46.4 g) (51.43°C)] = 0.952 J/(g°C)

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If the acid structure induces (H+) release or accept e- or if it is present in higher concentration it affects the pH by reducing it.

Acid and base are two terms that are often encountered in chemistry. The acid-base theory is a theory that explains the chemistry behind these substances. This theory explains how acids and bases react with each other to form a neutral solution, among other things. It also explains the concept of pH.

The pH of a solution is a measure of how acidic or basic it is. The pH of a solution is determined by the concentration of hydrogen ions (H+) in the solution. The higher the concentration of hydrogen ions, the lower the pH, and the more acidic the solution. Conversely, the lower the concentration of hydrogen ions, the higher the pH, and the more basic the solution.

The pH of a solution can be influenced by several factors. These factors include the structure of the acid or base, the initial concentration of the acid or base, and the conditions under which the reaction takes place.

For example, if the structure of the acid is such that it can easily donate hydrogen ions, the acid will be a strong acid. Strong acids have a low pH because they have a high concentration of hydrogen ions. On the other hand, if the structure of the acid is such that it can't donate hydrogen ions easily, the acid will be a weak acid.

Weak acids have a higher pH than strong acids because they have a lower concentration of hydrogen ions. Similarly, the concentration of the acid or base will also affect the pH. If the concentration of the acid or base is high, the pH will be low. Conversely, if the concentration of the acid or base is low, the pH will be high. This is because the concentration of hydrogen ions in the solution is directly proportional to the concentration of the acid or base.

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Chemoautotrophs use inorganic chemicals as an energy source and carbon dioxide as a carbon source.

Chemoautotrophs are autotrophs that obtain their energy from chemical compounds rather than from sunlight. They generate their own food by using energy from inorganic substances like sulfur, ammonia, or ferrous iron in a process called chemosynthesis.

They are mainly found in harsh environments such as volcanic vents or deep-sea vents, where photosynthesis is not possible because there is no sunlight to drive the reaction.

Energy sources are substances or processes that provide energy for a given system. Chemical, thermal, and electromagnetic energy sources are the most common forms of energy sources.

Carbon is an element that is essential to all life forms. Carbon is a building block of most organic molecules, including carbohydrates, lipids, proteins, and nucleic acids, which are the essential components of life.

A carbon source is an essential element for the growth of living organisms. It is a nutrient that is necessary for the synthesis of organic molecules that make up living organisms, such as carbohydrates, lipids, proteins, and nucleic acids.

Chemoautotrophs use inorganic compounds such as ammonia, sulfur, or ferrous iron as an energy source to produce organic molecules from carbon dioxide and water. As a result, chemoautotrophs are the primary producers of food in ecosystems where photosynthesis is not feasible, and their existence is critical to the survival of other living organisms.

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The ranking of the given compounds in order of the increasing boiling point is as follows: ethane < propane < butane < pentane < hexane < heptane.

The reason for this trend is that boiling point increases with the number of carbon atoms in a compound. As the carbon chain becomes longer, the molecules become more polarizable, allowing them to have stronger intermolecular forces of attraction, which requires more energy to overcome and hence, a higher the boiling point. Therefore, heptane, which has the longest carbon chain, has the highest boiling point, while ethane, which has the shortest carbon chain, has the lowest boiling point.

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--The complete question is, Rank the following compounds in order of increasing boiling point.

heptane

ethane

butane

pentane

propane

hexane --

Answer: Francium

Explanation: This is because the atomic radius increases from top to bottom in a group, and decreases from left to right across a period. Thus, helium is the smallest element, and francium is the largest.

Since mixing doesn't change the solution's volume, the volume difference is equivalent to zero.

To calculate the difference in volume between the total volume of water and ethanol mixed to prepare the solution and the actual volume of the solution, we first need to calculate the mass of ethanol in the solution. From the given information, we know that the molarity of ethanol in the solution is 9.811 M, and the volume of ethanol is 796.0 mL. Using the formula M = n/V, where M is the molarity, n is the number of moles, and V is the volume in liters, we can calculate the number of moles of ethanol in the solution.

n(ethanol) = M x V = 9.811 mol/L x 0.7960 L = 7.811 mol

Next, we can calculate the mass of ethanol in the solution using the density of ethanol at this temperature, which is 0.7893 g/mL.

mass(ethanol) = volume(ethanol) x density(ethanol) = 796.0 mL x 0.7893 g/mL = 628.5 g

Using the molar mass of ethanol (46.07 g/mol), we can calculate the number of moles of ethanol from the mass of ethanol in the solution.

n(ethanol) = mass(ethanol) / molar mass(ethanol) = 628.5 g / 46.07 g/mol = 13.646 mol

Finally, we can calculate the volume of water in the solution by subtracting the volume of ethanol from the total volume of the solution.

volume(water) = total volume - volume(ethanol) = 796.0 mL + 652.0 mL - 796.0 mL = 652.0 mL

Therefore, the difference in volume between the total volume of water and ethanol that were mixed to prepare the solution and the actual volume of the solution is:

Difference in volume = total volume - actual volume = (796.0 mL + 652.0

mL) - (796.0 mL + 652.0 mL + change in volume due to mixing) = change in volume due to mixing

Since the volume of the solution is conserved during mixing, the difference in volume is equal to zero.

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The concentration of the solution is 0.205 M. Concentration refers to the quantity of solute present in a given volume of a solution. It is the quantity of solute (in grams or moles) divided by the volume of the solution (in liters). The unit of concentration is usually expressed in molarity (M), which is the number of moles of solute per liter of solution. For this particular question, we are given a concentrated hydrochloric acid solution that is to be diluted.

We can use the formula for concentration to calculate the final concentration of the diluted solution.C1V1 = C2V2where C1 = initial concentration of the solutionV1 = initial volume of the solution C2 = final concentration of the solutionV2 = final volume of the solution We can plug in the given values:C1 = 6.00 M (since it is a concentrated hydrochloric acid solution)V1 = 2.69 mL (since this is the initial volume that we are diluting)C2 = unknownV2 = 175 mL (since this is the total volume of the diluted solution)

Before we can solve for C2, we need to convert the initial volume to liters and the final volume to liters:V1 = 2.69 mL = 0.00269 LV2 = 175 mL = 0.175 LNow we can solve for C2:C1V1 = C2V26.00 M x 0.00269 L = C2 x 0.175 LC2 = 0.205 M Therefore, the concentration of the solution is 0.205 M.

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Excessive breakdown of fatty acid may lead to an increase in ketone body formation. The correct option is c.

The Ketone bodies will be produced in the liver cells by the breakdown of the fatty acids. These are released in to the blood after the glycogen stores in the liver have depleted. The Glycogen will stores that will be typically are depleted with the first 24 hours of the fasting.

Ketones are present in the blood and when the glucose level will be lower in the blood. Liver shifts the metabolization process from the carbohydrates to the fatty acids where there is the lack of the glucose. The correct option is c.

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The correct option is pH > 7. For the titration of a frail corrosive with a solid base, the pH bend is at first acidic and has a fundamental comparability point (pH > 7).

The motivation behind a solid corrosive solid base titration is to decide the grouping of the acidic arrangement by titrating it with an essential arrangement of known focus, or the other way around until neutralization happens. As both the corrosive and base areas of strength are (upsides of Ka and Kb), the two of them will completely separate, and that implies every one of the particles of corrosive or base will totally different particles.

At the comparability point, equivalent measures of H+ and Gracious particles will join to frame H2O, bringing about a pH of 7.0 (neutral). The pH at the identicalness point for this titration will continuously be 7.0, note that this is valid just for titrations of a solid corrosive with a solid base.

Likewise, the anion (negative particle) made from the separation of the corrosive joins with the cation (positive particle) made from the separation of the base to make a salt. In this way, the response between a solid corrosive and a solid base will bring about water and salt.

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Yes, if the concentration of the substrate is equal to the km, it can be a steady state condition.

In this situation, the rate of the reaction remains constant over time, and the concentration of the enzyme-substrate complex is at a maximum. The steady state is defined as the state in which the rate of formation of the enzyme-substrate complex is equal to the rate of breakdown of the enzyme-substrate complex. This implies that the concentration of the enzyme-substrate complex is not changing over time. Suppose the concentration of the substrate is equal to the Km of the enzyme. In that case, the rate of the reaction is half its maximum rate, and the enzyme-substrate complex's concentration is at its maximum. At this point, the formation of the enzyme-substrate complex equals its breakdown rate, and the reaction remains constant over time. Thus, this is a steady-state condition.

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The final concentration of the solution after the dilution is: 0.425 M.

Dilution is a process that occurs when a solution is weakened by adding more solvent to it.

The formula for dilution is: (C1V1) = (C2V2),
where, C1 is the initial concentration of the solution,
V1 is the initial volume of the solution,
C2 is the final concentration of the solution, and
V2 is the final volume of the solution.

The values of V1 and V2 are often equal for simple dilutions.

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The electron transport chain (ETC) is a series of membrane-bound proteins that transfer electrons from electron donors (such as NADH and FADH₂) to electron acceptors (such as oxygen) through a series of redox reactions.

The ETC plays a critical role in aerobic respiration and is responsible for generating a proton gradient across the mitochondrial inner membrane, which is used to generate ATP through the process of oxidative phosphorylation.

Therefore, the event that takes place in the electron transport chain is the harnessing of energy from redox reactions to generate a proton gradient. This occurs as electrons are passed along the ETC and are used to pump protons (H⁺) from the matrix into the intermembrane space. This creates a proton gradient that is used by ATP synthase to generate ATP from ADP and Pi.

The other events mentioned, such as the breakdown of an acetyl group to carbon dioxide and the breakdown of glucose into six carbon dioxide molecules, occur earlier in cellular respiration during glycolysis and the citric acid cycle. Substrate-level phosphorylation, on the other hand, occurs during glycolysis and the citric acid cycle and involves the direct transfer of a phosphate group from a substrate molecule to ADP to generate ATP.

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2. ΔH < 0 contributes to spontaneity, related to the spontaneity of a reaction.

Enthalpy (ΔH) is a measure of the energy of a system and can be used to predict whether a reaction is spontaneous or not. If the enthalpy of a reaction is negative (ΔH < 0), then the reaction is spontaneous. This is because the system is releasing energy, meaning that the reaction is more likely to proceed on its own without any external input. Therefore, a reaction with a negative enthalpy (ΔH < 0) is more likely to be spontaneous than a reaction with a positive enthalpy (ΔH > 0).

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Answer:

Summary – Electrolyte vs Electrolysis

Therefore, the key difference between electrolyte and electrolysis is that electrolyte is a substance that can produce ions, whereas electrolysis is a process in which an electric current is used to drive a chemical reaction.

Explanation: brainliest please

By dividing the amount of half-lives by the time it took for two half-lives to pass (3.04 hours), we can determine the half-life of silver-112. (2). This gives us a silver-112 half-life of 1.52 hours.

The half-life of a radioactive isotope is defined as the amount of time it takes for half of the initial amount of the isotope to decay. To determine the half-life of silver-112, we can use the information given in the problem.

We know that 28.0% of a sample of silver-112 decays in 1.52 hours. Let's assume that we started with a sample of 100 silver-112 atoms. This means that 28.0 of these atoms would decay in 1.52 hours, leaving us with 72.0 atoms remaining.

After another half-life, we would expect half of the remaining atoms to decay. In other words, we would expect 36.0 atoms to decay, leaving us with 36.0 atoms remaining. Since we started with 100 atoms and now have 36.0 remaining, this means that two half-lives have passed.

Therefore, we can calculate the half-life of silver-112 by dividing the time it took for two half-lives to pass (3.04 hours) by the number of half-lives (2). This gives us a half-life of 1.52 hours for silver-112.

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When a proton is removed from the -OH group, the remaining oxygen ion can act as a nucleophile and attack the adjacent carbon atom, forming a cyclic ether. The rate at which this reaction occurs depends on the stability of the intermediate carbocation that is formed during the reaction.

In general, the stability of a carbocation depends on the number of alkyl groups attached to the positively charged carbon atom. More alkyl groups increase the stability of the carbocation, making the reaction more favorable and rapid.

Thus, in the pair of compounds, the one with more alkyl groups attached to the carbon atom adjacent to the -OH group would form a cyclic ether more rapidly. For example, in the pair of compounds 2-methyl-1-butanol and 1-butanol, 2-methyl-1-butanol would form a cyclic ether more rapidly as the intermediate carbocation formed during the reaction is more stable due to the presence of an additional methyl group.

Similarly, in the pair of compounds 2-methyl-2-butanol and 2-butanol, 2-methyl-2-butanol would form a cyclic ether more rapidly due to the presence of two methyl groups attached to the adjacent carbon atom, which increases the stability of the intermediate carbocation formed during the reaction.

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