The median weekly earnings of the data set of the workers in the occupations listed for 2010 is calculated as: $971.
How to Find the Median Weekly Earnings?To find the median weekly earnings for the occupations listed in 2010, we need to first arrange the earnings in order from least to greatest:
$501, $900, $971, $977, $1071
The median is the middle value in this ordered list. Since there are an odd number of values, the median is simply the middle value.
Therefore, the median weekly earnings of workers in the occupations listed for 2010 is $971.
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What are the solutions to the system of equations?
y=x^2−5x−6
y=2x−6
(−1, 0) and (−6, 0)
(7, 8) and (0, −6)
(−6, 0) and (0, −1)
(−1, 0) and (0, −6)
Please answer- I will report you if you do not answer and only want the points.
The solutions of the system of equations are (0, -6) and (7, 8)
How to find the solution of the system of equations?
Here we have the system of equations:
y=x^2−5x−6
y=2x−6
To solve this, we need to solve the equation:
x^2 - 5x - 6 = 2x - 6
x^2 - 7x = 0
x*(x - 7) = 0
We can see that the two solutions are:
x = 0
x = 7
Evaluating the line in these values we get:
y = 2*0 - 6 = -6
y = 2*7 - 6 = 8
Then the solutions are (0, -6) and (7, 8)
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B as a % of A is equal to A as a % of (A+B). Find B as a % of A.
Option (b), 62% is correct.
How to solveBy the given condition,
B/A = A/(A + B) ..... (1)
Now to find the percentage of A = B, we consider B = Ax. From (1), we get
Ax/A = A/(A + Ax)
or, x = 1/(1 + x)
or, x² + x - 1 = 0
Using the quadratic formula, we get
x = {- 1 ± √(1 + 4)}/2
= (- 1 ± √5)/2
Since x cannot be negative, we take
x = (- 1 + √5)/2
≈ 0.62
Therefore the required percentage is
= 0.62 × 100%
= 62%
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B as a percentage ofAis equal to Aas a
percentage of(A+B). How much percent
of A is B?
(a) 60%
(b) 62%
(C) 64%
(d) 66%
Three fourths of the girls in the eighth grade have long hair. One half of the girls are wearing dresses today. What is the probability that an eighth grade girl will have long hair and be wearing a dress?
The probability that an eighth-grade girl will have long hair and be wearing a dress is 3/8 or 0.375, which is the same thing expressed as a decimal.
what is probability?
Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain to happen.
To solve the problem, we need to find the intersection of the events "having long hair" and "wearing a dress" and calculate the probability of that intersection.
Let L be the event "having long hair" and D be the event "wearing a dress". Then we know:
P(L) = 3/4, since three-fourths of the girls have long hair.
P(D) = 1/2, since half of the girls are wearing dresses.
To find P(L ∩ D), we need to multiply the probabilities of the two events:
P(L ∩ D) = P(L) × P(D) = (3/4) × (1/2) = 3/8
Therefore, the probability that an eighth grade girl will have long hair and be wearing a dress is 3/8 or 0.375, which is the same thing expressed as a decimal.
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Can you help me with this please
Answer: [tex]\frac{2}{5}[/tex] x [tex]\frac{4}{5}[/tex] = [tex]\frac{8}{25}[/tex]
Step-by-step explanation:
We can do this by counting the boxes for both the Width and the Length.
If we look at the width of these boxes (horizontally) then we see that there are 5 boxes all together, with 2 shaded green.
this means that 2 out of 5 of the boxes are shaded for the width, giving us the fraction: [tex]\frac{2}{5}[/tex]
Then for the Length (vertically) we see that there are also 5 boxes, but this time 4 are shaded. This gives us the fraction: [tex]\frac{4}{5}[/tex].
Then, to fill the equation in, we do: [tex]\frac{2}{5}[/tex] x [tex]\frac{4}{5}[/tex] , which gives us [tex]\frac{8}{25}[/tex]
2 x 4 = 8
5 x 5 = 25
To double check this answer, we can count how many boxes are shaded green.
We see that 8 are shaded green, out of the 25 boxes that are there.
Therefore, giving us a complete answer of: [tex]\frac{2}{5}[/tex] x [tex]\frac{4}{5}[/tex] = [tex]\frac{8}{25}[/tex]
Find z
x+y=z
y-z=x
I will award brainlest
Answer:
To solve for z in terms of x and y using the given equations:
x + y = z ........(1)
y - z = x ........(2)
From equation (2), we get:
y - x = z (by adding z on both sides)
Substituting this value of z in equation (1), we get:
x + y = y - x
2x = 0
x = 0
Substituting x = 0 in equation (2), we get:
y - z = 0
y = z
Therefore, the solution is:
z = y
We cannot determine a specific value of z without knowing the values of x and y.
2. Four friends have stamps, as described below.
• Samir has 60 stamps.
•Lisa has 24 times as many stamps as Samir.
Kwame has 443 stamps.
To the nearest whole number, what is the mean of the
Jake has 159 fewer stamps than Kwame.
number of stamps for these four friends?
Answer:
All of them have a combined of 2,227 Stamps
Mean: 2014
The following table shows students’ test scores on the first two tests in an introductory calculus class.
Calculus Test Scores
First test, x 64
59
45
73
73
76
40
56
68
55
78
83
Second test, y 68
63
55
74
68
75
43
64
61
64
77
84
Step 2 of 2 : If a student scored a 69
on his first test, make a prediction for his score on the second test. Assume the regression equation is appropriate for prediction. Round your answer to two decimal places, if necessary.
if a student scored a 69 on his first test, predict that his score on the second test will be approximately 64.57.
Students’ test scores on the first two tests in an introductory calculus class.
To make a prediction for the student's score on the second test based on their score of 69 on the first test, we need to find the regression equation for the data set.
The regression equation for these data is
y = 0.6443x + 19.943
Where y is the predicted score on the second test and x is the actual score on the first test.
Substituting x = 69 into this equation, we get
y = 0.6443(69) + 19.943 ≈ 64.57
Therefore, if a student scored a 69 on his first test, we predict that his score on the second test will be approximately 64.57.
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 how many kilograms are in 14500 grams
Answer: 14.5 kg
Step-by-step explanation:
Rebecca used 4.25pt of milk in her baking recipe. How many cups of milk did she use?
Answer: 8.25
Step-by-step explanation:
Select the two values of x that are roots of this equation x^2-5x+3=0
The two roots of the quadratic equation x² - 5x + 3 = 0 are (5 + √13) / 2 and (5 - √13) / 2.
To find the roots of the quadratic equation x² - 5x + 3 = 0, we can use the quadratic formula:
x = (-b ± √(b² - 4ac)) / 2a
where a, b, and c are the coefficients of the quadratic equation.
Substituting the values of a, b, and c from the given equation, we have:
x = (-(-5) ± √((-5)² - 4(1)(3))) / 2(1)
x = (5 ± √(25 - 12)) / 2
x = (5 ± √13) / 2
Therefore, the roots of the equation are (5 + √13) / 2 and (5 - √13) / 2.
To verify that these are indeed the roots of the equation, we can substitute each of these values for x in the original equation and check if the equation is satisfied. For example, if we substitute (5 + √13) / 2 for x, we get:
(5 + √13)² - 5(5 + √13) + 3 = 0
Simplifying this equation, we get:
13 - 5√13 + 8 + 13 - 5√13 + 3 = 0
This equation is true, which means that (5 + √13) / 2 is a root of the equation x² - 5x + 3 = 0. Similarly, we can verify that (5 - √13) / 2 is also a root of the equation.
These roots can be found using the quadratic formula, which is a useful tool for solving quadratic equations.
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On January 10, 2022, Cullumber Co. sold merchandise on account to Robertsen Co. for $16,600, n/30. On February 9, Robertsen Co. gave Cullumber Co. a 11% promissory note in settlement of this account.
The preparation of the journal entry to record the sale and the settlement of the account receivable is as follows:
Journal Entry:January 10, 2022:
Debit Accounts Receivable $16,600
Credit Sales Revenue $16,600
(To record the sale of merchandise on account to Robertsen Co, n/30.)
February 9, 2022:
Debit Notes Receivable $16,600
Credit Accounts Receivable $16,600
(To record the receipt of a 11% promissory note in settlement of account receivable.)
What are journal entries?Journal entries refer to the initial records maintained about business transactions.
Journal entries show how the transactions will be posted in the general ledger.
Transaction Analysis:January 10, 2022: Accounts Receivable $16,600 Sales Revenue $16,600
Terms n/30
February 9, 2022: Notes Receivable $16,600 Accounts Receivable $16,600
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Question Completion:Prepare the journal entry to record the sale and the settlement of the account receivable.
What is 1 and 1/4
And 1 and 1/2
The mixed fraction 1 and 1/4 is equal to 5/4 and the mixed fraction 1 and 1/2 is equal to 3/2.
Given first number = 1 and 1/4.
1 and 1/4 is a mixed fraction so, we can write it in the form as [tex]1\frac{1}{4}[/tex] .
To find the value of [tex]1\frac{1}{4}[/tex] we have to multiply 4 with 1 and add the numerator part of the fraction which is 1 and then divide it by 4 which is the denominator. So,
[tex]1\frac{1}{4}[/tex] = ((4x1) + 1 )/4 = 5/4.
Similary, for 1 and 1/2,
[tex]1\frac{1}{2}[/tex] = ((2x1) + 1)/2 = 3/2.
From the above analysis, we can conclude that the value of 1 and 1/4 is 5/4 and the value of 1 and 1/2 is 3/2.
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The model for radioactive decay is y=y0e^-kt. a radioactive substance has a half-life of 170 years. if 40 grams are present today. in how many years will 15 grams be present? While solving this problem, round the value of k to seven decimal places. Round your answer to two decimal places.
It will take about 225.25 years of time for 15 grams to be present.
The half-life of a radioactive substance is the time it takes for half of the substance to decay.
For this substance with a half-life of 170 years, we can use the following formula to find the value of k:
[tex]0.5 = e^(^-^1^7^0^k^)[/tex]
Taking the natural logarithm of both sides, we get:
ln(0.5) = -170k
Solving for k, we get:
k = ln(0.5) / (-170)
= 0.004085
Now, we can use the model [tex]y = y_0e^(^-^k^t^)[/tex] to find the time t required for the substance to decay from 40 grams to 15 grams.
We have:
[tex]15 = 40e^(^-^0^.^0^0^4^0^8^5^t^)[/tex]
Dividing both sides by 40 and taking the natural logarithm of both sides, we get:
ln(15/40) = -0.004085t
Solving for t, we get:
t = ln(15/40) / (-0.004085)
= 225.25 years
Therefore, it will take about 225.25 years for 15 grams to be present.
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Please see the attached
Using the ratios, 1 yd/3 feet, 1 mi/5,280 feet, and 200 yards/1 feet, the number of flags required to mark the racecourse with a flag every 200 yards is 22.
What are the ratios?Ratios are relative sizes of one quantity or value compared to another.
Ratios are depicted as fractional values using decimals, percentages, or fractions, including the standard ratio form (:).
The total distance of the racecourse = 2.5 miles
The common distance between each flag = 200 yards
1 mile = 1,760 yards
2.5 miles = 4,400 yards
1 yard = 3 feel
The number of flags required to cover the distance = 22 (4,400 ÷ 200)
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Car A travels 221.5 km at a given time, while car B travels 1.2 times the distance car A travels at the same time. What is the distance car B travels during that time?
Answer:
Distance that car B travels =1.2× distance that car A travels
=1.2×221.5=265.8 km
Answer:
car B travels a distance of 265.8 km during the same time.
Step-by-step explanation:
Car A travels 221.5 km at a given time.
To find the distance traveled by car B, which is 1.2 times the distance traveled by car A, we can multiply the distance of car A by 1.2:
Distance of Car B = 1.2 * Distance of Car A
Distance of Car B = 1.2 * 221.5 km
Distance of Car B = 265.8 km
Therefore, car B travels a distance of 265.8 km during the same time.
Arthur has decided to start saving for a new computer. His money is currently in a piggy bank at home, modeled by the function s(x) - 85. He was told that he could do the laundry for the house and his allowance would be a(x) = 10(x - 1), where x is measured in weeks. Explain to Arthur how he can create a function that combines the two, and describe any simplification that can be done.
The simplification of the function is r(x)=10x - 95.
We are given that;
s(x) = -85 and a(x) = 10(x - 1)
Now,
To create a function that combines them, you can substitute these expressions into the formula above:
r(x) = s(x) + a(x) r(x) = (-85) + 10(x - 1)
You can simplify this function by distributing the 10 and combining the constants:
r(x) = -85 + 10x - 10 r(x) = 10x - 95
Therefore, the function will be r(x)=10x - 95.
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1 Soo divides a square into sixths. She colors one of the
equal parts red. What fraction of the square is red?
The fraction of the square that is red is 1/6.
Define fractionA fraction is a number that represents a part or parts of a whole. It consists of two numbers separated by a horizontal or diagonal line, with the number above the line (numerator) representing the part and the number below the line (denominator) representing the whole. For example, the fraction 3/4 represents three parts out of a whole that is divided into four equal parts.
A square divided into six equal parts has six equal sixths.
If Soo colors one of these equal parts red, then she has colored one-sixth of the square red.
Therefore, the fraction of the square that is red is 1/6.
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Given u=12i-3j and v=-5i+11j, what is u x v?
Answer:
117
Step-by-step explanation:
You want the cross product of vectors u = (12i -3j) and v = (-5i +11j).
Cross productThe cross product of 2-dimensional vectors is a scalar that is effectively the determinant of the matrix of coefficients.
u×v = (12)(11) -(-3)(-5) = 132 -15
u×v = 117
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I need help pleaseeee
(a) The value of the row operation of -2(row1) + row (2) is [-10 4 -12].
(b) The interchange of row 1 and row 2 is [0 6 -3]
[5 -2 6]
What is the row operation of the matrix?The value of the row operation of -2(row1) + row (2) is calculated as follows;
-2 (row 1) = 2 [5 -2 6]
-2 (row 1) = [-10 4 -12]
The addition of -2(row1) to row (2) is calculated as follows;
[-10 4 -12] + [0 6 -3]
= [-10 10 - 15]
The interchange of row 1 and row 2 is calculated as follows;
R₁ ↔ R₂
= [5 -2 6] = [0 6 -3]
[0 6 -3] [5 -2 6]
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PLEASE HELP!!
A cone has a radius of 3 inches and a slant height of 12 inches.
What is the exact surface area of a similar cone whose radius is 6 inches?
Enter your answer in the box.
Surface area of similar cone =
___in²
Surface area of similar cone is 44π square inches
What does a cone in maths ?
A cone is referred to as a "right cone" when its vertex is higher than the base's centre (i.e., when the angle formed by the vertex, base center, and any base radius is a right angle); otherwise, the word "oblique" is used. A cone is referred to as an elliptic cone when the base is assumed to be an ellipse rather than a circle.
The surface area of a cone is given by:
surface area = πr(r + l)
where r is the radius and l is the slant height.
surface area of original cone = π(3)(3 + 12) = 45π
slant height of similar cone = (6/3)(12) = 24 inches
surface area of similar cone = π(6)(6 + 18) = 144π
ratio of surface areas = surface area of similar cone / surface area of original cone
= (144π) / (45π)
= 3.2
Therefore, The exact surface area of the similar cone is 6 times the surface area of the original cone,
6 × 45π = 144π square inches
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Please help !!!!!
!!!!!
Answer: 10w + 3 + 4.5w = 90
Step-by-step explanation:
a right angle is 90 degrees, so 10w + 3 and 4.5w have to add up to 90 degrees
PLEASE HELP WITH THE IMAGE!! DUE TOMORROW!!!
The calculations of the down payments, monthly income or payments are as follows:
Part 1:
Annual income = $226,000
Federal Tax = $62,582
State Tax = $16,385
Local Tax = $5,537
Healthcare = $4,520
Yearly income = $136,976
Monthly income = $11,414.67.
Part 2:
Down payment = $150,000
The amount to borrow (Mortgage loan) = $600,000
Estimated interest = $810,000
Total installment payments = $1,410,000
Monthly payment = $3,916.67.
Part 3:
Down payment = $2,902.50
Mortgage loan = $16,447.50
Estimated interest = $3,700.69
Interest + Mortgage loan = $20,148.19
Monthly payment = $335.80.
Part 1:
Annual income = $226,000
Federal Tax:
25% of $89,350 = $22,337.50
28% of $97,000 = $27,160.00
33% of $39,650 = $13,084.50
Total federal tax = $62,582
State Tax = 7.25% of $226,000 = $16,385
Local Tax = 2.45% of $226,000 = $5,537
Healthcare = 2% of $226,000 = $4,520
f) Total of Federal, State, Local, and Healthcare = $89,024
Yearly income = $136,976 ($226,000 - $89,024)
Monthly income = $11,414.67 ($136,976 ÷ 12)
Part 2:
a) House price = $750,000
b) Down payment = 20%
= $150,000 ($750,000 x 20%)
c) Mortgage loan = $600,000 ($750,000 - $150,000)
d) Interest rate = 4.5%
Number of mortgage years = 30 years
Mortgage period in months = 360 months (30 x 12)
Estimated interest = $810,000 ($600,000 x 4.5% x 30)
Interest + Mortgage loan = $1,410,000 ($600,000 + $810,000)
Monthly payment = $3,916.67 ($1,410,000 ÷ 360)
Part 3:
Price of car = $19,350
Down payment = 15%
= $2,902.50 ($19,350 x 15%)
Mortgage loan = $16,447.50 ($19,350 - $2,902.50)
Number of years = 5 years
Mortgage period in months = 60 months (5 x 12)
Estimated interest = $3,700.69 ($16,447.50 x 4.5% x 5)
Interest + Mortgage loan = $20,148.19 ($16,447.50 + $3,700.69)
Monthly payment = $335.80 ($20,148.19 ÷ 60)
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lim h -> 0 [f(x_{0} + h) - f(x_{0})] / h
the limit expression gives the value of the derivative of a function at a specific point. where f'(x_0) denotes the derivative of f(x) at x = x_0.
what is derivative ?
The derivative of a function is a measure of how the function changes as its input variable changes. It gives the instantaneous rate of change or slope of the tangent line of the function at a specific point.
In the given question,
The expression you provided represents the limit definition of the derivative of a function f(x) at the point x = x_0. The limit evaluates the instantaneous rate of change or slope of the tangent line of the function f(x) at the point x = x_0.
To evaluate the limit, substitute x = x_0 + h in the expression of the function f(x) and simplify:
[tex]lim h - > 0 [f(x_{0} + h) - f(x_{0})] / h = f'(x_{0})[/tex]
where f'(x_0) denotes the derivative of f(x) at x = x_0.
Therefore, the limit expression gives the value of the derivative of a function at a specific point.
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A box contains 16 transistors, 3 of which are defective. If 3 are selected at random, find the probability of the statements below.
a. All are defective
b. None are defective
a. The probability is.
(Type a fraction. Simplify your answer.)
***
The probability of selecting all defective transistors is 1/560.
To find the probability of the statementsThe probability of selecting all defective transistors can be calculated as:
P(all defective) = (number of ways to select 3 defective transistors) / (total number of ways to select 3 transistors)
The number of ways to select 3 defective transistors is simply the number of combinations of 3 defective transistors out of the total of 3, which is 1. The total number of ways to select 3 transistors out of 16 is:
total number of ways = number of combinations of 3 transistors out of 16
= (16 choose 3)
= 560
Therefore, the probability of selecting all defective transistors is:
P(all defective) = 1 / 560
To simplify the answer, we can write it as a fraction in lowest terms:
P(all defective) = 1 / 560 = 1/ (161514/321) = 1/560
Therefore, the probability of selecting all defective transistors is 1/560.
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1. Find the zeros of the quadratic function by graphing. Round to the nearest tenth if necessary.
f(x) = -2x² + 3x + 1
A 0.8,2.1) is a zero of the quadratic function because it is the peak of the parabola.
B (0,1) is a zero of the quadratic because it is where the parabola crosses the y-axis.
C (-0,3,0) and (1.8,0) are zeros of the quadratic function because it is where the parabola crosses the x-axis.
D (0.8,2.1) and (0,1) are zeros of the quadratic function because it is where the parabola crosses the x-axis.
The correct answer is C: (-0.3,0) and (1.8,0) are zeros of the quadratic function because they are the points where the parabola intersects the x-axis.
The right response is C: (- 0.3,0) and (1.8,0) are zeros of as far as possible since they are the places where the parabola meets the x-turn.
plot the y-get at (0,1),
x = - b/2a
To find the x-heading of the vertex, which is x = 3/4. Substitute this worth into the capacity to find the y-course of the vertex, which is
f(3/4) = 1/8.
Plot the vertex at (3/4, 1/8).
Then, utilize this data to plot the remainder of the parabola. The zeros are the places where the parabola crosses the x-focus, which are close (- 0.3,0) and (1.8,0) obviously following changing in accordance with the closest 10th.
To track down the zeros of the quadratic capacity by illustrating, one ought to at first plot the y-get at (0,1) and a brief time frame later utilize the vertex condition to track down the headings of the vertex. Following plotting the vertex, the remainder of the parabola can be drawn. The zeros of the capacity are the x-gets, which can be found by finding the places where the parabola combines the x-turn. For this current situation, the zeros are close (- 0.3, 0) and (1.8, 0) resulting to adjusting to the closest 10th.
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Suppose a polynomial function of degree 4 with rational coefficients has the given numbers as zeros. Find the other zeros.
-3, √3, 13/3
The other zeros are
(Use a comma to separate answers.)
Answer:
{-3, √3, -√3, 13/3}
Step-by-step explanation:
Since the polynomial has rational coefficients, any irrational zeros must come in conjugate pairs. So, if √3 is a zero, then so is its conjugate, -√3.
We can write the polynomial with these zeros as:
p(x) = a(x + 3)(x - √3)(x + √3)(x - 13/3)
where a is some constant coefficient. Multiplying out the factors, we get:
p(x) = a(x + 3)(x^2 - 3)(x - 13/3)
To find the remaining zeros, we need to solve for x in the expression p(x) = 0. So we set up the equation:
a(x + 3)(x^2 - 3)(x - 13/3) = 0
This equation is true when any of the factors is equal to zero. We already know three of the zeros, so we need to solve for the fourth:
(x + 3)(x^2 - 3)(x - 13/3) = 0
Expanding the quadratic factor, we get:
(x + 3)(x - √3)(x + √3)(x - 13/3) = 0
Canceling out the (x - √3) and (x + √3) factors, we get:
(x + 3)(x - 13/3) = 0
Solving for x, we get:
x = -3 or x = 13/3
Therefore, the other zeros are -3 and 13/3.
The complete set of zeros is {-3, √3, -√3, 13/3}.
Hope it helps^^
The strength of a beam is proportional to the width and the square of the depth. A beam is cut from a cylindrical log of diameter d = 24 cm. The figures show different ways this can be done. Express the strength of the beam as a function of the angle in the figures. (Use k as your proportionality constant.)
The strength of the beam is proportional to the width and the square of the depth, so we can express it as Strength = k * width * depth²
where k is the proportionality constant.
In the given figures, the beam is cut from a cylindrical log of diameter d = 24 cm, which means the maximum width and depth of the beam are limited by this diameter. We can see from the figures that the width and depth of the beam change depending on the angle at which it is cut from the log.
In Figure 1, the width and depth of the beam are equal, so we can express the strength of the beam as:
Strength = k * width * depth² = k * x² * (d/2 - x)²
where x is the width and depth of the beam.
In Figure 2, the width and depth of the beam are not equal, so we need to express them separately. Let w be the width and d be the depth, then we can express the strength of the beam as:
Strength = k * width * depth² = k * w * d² = k * ((d/2)sinθ)² * ((d/2)cosθ)²
where θ is the angle at which the beam is cut from the log.
In Figure 3, the width and depth of the beam also vary with the angle θ. We can express the width and depth as follows:
w = d sinθ
d = (d/2)cosθ
Then we can express the strength of the beam as:
Strength = k * width * depth² = k * (d sinθ) * [(d/2)cosθ]²
Therefore, depending on the angle at which the beam is cut from the log, the strength of the beam can be expressed using different equations, but in all cases, the strength is proportional to the width and the square of the depth, with a proportionality constant k.
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Complete question is:
The strength of a beam is proportional to the width and the square of the depth. A beam is cut from a cylindrical log of diameter d = 24 cm. The figures show different ways this can be done. Express the strength of the beam as a function of the angle in the figures. (Use k as your proportionality constant.)
a) What information is provided by each of the graphs below? b) Explain below which of the two graphs is the best representation of the data. Support your thinking by using numbers from each graph.
The information provided by each of the graphs is Sales from July to December and graph A best represents the data
What information is provided by each of the graphs?From the question, we have the following parameters that can be used in our computation:
The graphs
On the graphs, we have the information to be
Sales from July to December
Which of the two graphs is the best representation of the data.The graph that is the best representation of the data is the A
This is because the scale and origin of the graph are defined
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If 90% of a number is 110, find 9% of that number.
We can set up the equation :
0.9x = 110 ,
where x is the unknown number. To solve for x, we can divide both sides by 0.9 :
x = 110 ÷ 0.9
x = 122.22 (rounded to two decimal places)
So the unknown number is approximately 122.22.
To find 9% of that number, we can multiply 122.22 by 0.09 :
0.09 × 122.22 = 11.00 (rounded to two decimal places)
Therefore, 9% of the number is approximately 11.
Time (minutes) Jumping Jacks
1 50
2 100
3 150
4 200
Considering the jumping jacks: 50, 100, 150, 200, what is the common difference?
50
Now, think of this table as a set of ordered pairs. This means that the first row can be placed in an ordered pair as (1, 50). The second row can be written as (2, 100). Using this, what is the slope of the line that connects the first two points?
50
What is the slope of the line that connects the 3rd and 4th point?
50
What is the slope of the line that connects the 1st and the 4th point?
150
Is the common difference (aka slope aka rate of change) constant?
Yes
Why is it or is it not constant?
It is constant because it is a linear function.
Answer:
Step-by-step explanation:
The common difference between the number of jumping jacks is 50, as you correctly stated. This means that the number of jumping jacks increases by 50 for each additional minute.
The slope of the line that connects any two points on this table represents the rate of change of the number of jumping jacks with respect to time. Since the common difference is constant, the slope of the line that connects any two points on this table will be the same. In this case, the slope is 50.
The slope of the line that connects the first and fourth points is calculated as (200 - 50) / (4 - 1) = 150 / 3 = 50, not 150.
The common difference (aka slope aka rate of change) is constant because the number of jumping jacks increases by the same amount for each additional minute. This means that the relationship between time and the number of jumping jacks is linear.