The mass in grams of 3.011 x 10²³ atoms of F is 9.5 g.
The mass in grams of 1.50 x 10²³ atoms of Mg is 5.98 g.
The mass in grams of 4.50 x 10¹² atoms of Cl is 2.65 x 10⁻¹⁰ g.
The mass in grams of 8.42 x 10¹⁸ atoms of Br is 1.12 x 10⁻³ g.
The mass in grams of 25 atoms of W is 3.1 x 10⁻²¹ g.
The mass in grams of 1 atom of Au is 3.27 x 10⁻²² g.
What is the mass in grams of 3.011 x 10²³ atoms F?
The mass in grams of 3.011 x 10²³ atoms of F is calculated as follows;
6.023 x 10²³ atoms = 19 g of F
3.011 x 10²³ atoms F = ?
= (3.011 x 10²³ x 19 g)/(6.023 x 10²³)
= 9.5 g
The mass in grams of 1.50 x 10²³ atoms of Mg is calculated as follows;
6.023 x 10²³ atoms = 24g of Mg
1.5 x 10²³ atoms F = ?
= (1.5 x 10²³ x 24 g)/(6.023 x 10²³)
= 5.98 g
The mass in grams of 4.50 x 10¹² atoms of Cl is calculated as follows;
6.023 x 10²³ atoms = 35.5 g of Cl
4.5 x 10²³ atoms Cl = ?
= (4.5 x 10¹² x 35.5 g)/(6.023 x 10²³)
= 2.65 x 10⁻¹⁰ g
The mass in grams of 8.42 x 10¹⁸ atoms of Br is calculated as follows;
6.023 x 10²³ atoms = 80 g of Br
8.42 x 10¹⁸ atoms Br = ?
= (8.42 x 10¹⁸ x 80 g)/(6.023 x 10²³)
= 1.12 x 10⁻³ g
The mass in grams of 25 atoms of W is calculated as follows;
6.023 x 10²³ atoms = 74 g of W
25 atoms W = ?
= (25 x 74 g)/(6.023 x 10²³)
= 3.1 x 10⁻²¹ g
The mass in grams of 1 atom of Au is calculated as follows;
6.023 x 10²³ atoms = 197 g of Au
1 atom of Au = ?
= (1 x 197 g)/(6.023 x 10²³)
= 3.27 x 10⁻²² g
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1. ¿Cuál de los factores se deben emplear para convertir: a. ¿Número de moles de cloro en número de moles de NaCl? b. Moles de sodio a moles de cloro C. Moles de cloro a moles de sodio. 2 Na + CI, - 2 Naci
Ayudaaa
Answer:
Número de moles de cloro en número de moles de NaCl
Explanation:
espero que si sea la correcta
How many mm Hg are there in 2.27 atm?
Answer:
[tex]\huge\boxed{\sf 2.27\ atm = 1,725\ mm\ of\ Hg}[/tex]
Explanation:
We know that:
1 atm = 760 mm of Hg (Standardly)
Multiply both sides by 2.27
2.27 atm = 760 * 2.27 mm of Hg
2.27 atm = 1,725 mm of Hg
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807Element is in group 15. Element Y is in group 17. Both of these elements are
In the compound XY3, there are
shared electron pairs.
Answer:
join id(8606512121) pas(12345)
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Answer:
It's also true
Explanation:
the answer is written in this question
I hope that helps
Identify which of the following equations are balanced and which ones are not balanced
A. CH4 +202 —> CO2 + 2H20
B. 6CO2 + 6H2O—> C6H12O6+602
C. 2Na + H2O —> 2NaOH+ H2
Answer:
A. balancedB. UnblalancedC. UnbalancedExplanation:
On vacation, Aria went scuba diving in the Pacific Ocean for the very first time. She rose toward the surface of the water at a steady speed for 4 minutes. She rose 36 meters in that time. What was her speed? HELP ME ASAP!!!!!!!!!!!!!
Aria speed during scuba diving was 0.15 m/s.
Speed is the ratio of the distance travelled to the time taken. Speed is given by:
Speed = distance / time
Given that the distance travelled was 36 meters and the time was 4 minutes, hence:
Time = 4 minutes × 60 seconds per minute = 240 seconds
Speed = 36 m / 240 s
Speed = 0.15 m/s
Therefore Aria speed during scuba diving was 0.15 m/s.
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Sodium, Na, is a metallic element.
Explain, with the aid of a labelled diagram, what is meant by the term metallic bonding.
Answer:
metallic bonding is the bond form between two or more metal elements or between metal element and the other group elements
what is the formula for tetraaquaoxalatoiron(III)sulphate
Answer:
Fe2(SO4)3(H2O)n
Explanation:
Answer:
sorry I couldn't understand the question
In the preparation of a certain alkyl halide, 10 g of sodium bromide (NaBr), 10 mL distilled water (H20), and 9 mL 3-methyl-1-butanol (C5H120) were mixed in the round-bottomed flask and allowed to cool for 2 -3 minutes. Then while swirling the flask, 10 mL sulfuric acid (H2SO4) was slowly added to the flask and the mixture was refluxed and later distilled. The mass of the pure product obtained was 6.48 g. Sodium hydrogen carbonate (NaHCO3) was used to remove impurities. (Density of 3-methyl-1-butanol is 0.810 g/mL). The percentage yield will be?
Percentage yield shows the amount of reactants converted into products. The percentage yield of the reaction is 51.7%.
The equation of the reaction is sown in the image attached. The reaction is 1:1 as we can see.
Number of moles of NaBr = 10 g/103 g/mol = 0.097 moles
We can obtain the mass of 3-methyl-1-butanol from its density.
Mass = density × volume
Density of 3-methyl-1-butanol = 0.810 g/mL
Volume of 3-methyl-1-butanol = 9 mL
Mass of 3-methyl-1-butanol = 0.810 g/mL × 9 mL
Mass of 3-methyl-1-butanol = 7.29 g
Number of moles of 3-methyl-1-butanol = mass/molar mass = 7.29 g/88 g/mol = 0.083 moles
Since the reaction is 1:1 then the limiting reagent is 3-methyl-1-butanol
Mass of product 1-bromo-3-methylbutane = number of moles × molar mass
Molar mass of 1-bromo-3-methylbutane = 151 g/mol
Mass of product 1-bromo-3-methylbutane = 0.083 moles × 151 g/mol
= 12.53 g
Recall that % yield = actual yield/theoretical yield × 100
Actual yield of product = 6.48 g
Theoretical yield = 12.53 g
% yield = 6.48 g/12.53 g × 100
% yield = 51.7%
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Synthetic reactions in Citric Acid Cycle
★ « Synthetic reactions in Citric Acid Cycle » ★
The overall reaction for the citric acid cycle is as follows: acetyl-CoA + 3 NAD+ + FAD + GDP + P + 2H2O = CoA-SH + 3NADH + FADH2 + 3H+ + GTP + 2CO2. Many molecules in the citric acid cycle serve as key precursors for other molecules needed by cells.hope it is
The green light emitted by a stoplight has a wavelength of 505 nm. What is the frequency of this photon? (c = 3.00 × 10⁸ m/s).
Answer:
5.9405*10^14 Hz
Explanation:
Remember the equation c=v*λ
v=frequency
λ=wavelength
By manipulating the equation, we can get it in terms of frequency:
c/λ=v
Now convert wavelength to meters (1nm=m*10^-9)
5.05*10^-7m (2 decimal places were shifted to make the number between 1-10, hence the -7 exponent)
Use the manipulated equation:
(3.00*10^8)/(5.05*10^-7), which yields:
5.9405*10^14 Hz (or s^-1)
The frequency of the photon will be "[tex]5.9405\times 10^{14} \ Hz[/tex]".
According to the question,
Wavelength,
[tex]\lambda = 505 \ nm[/tex]or,
[tex]= 5.05\times 10^{-7} \ m[/tex]
As we know the equation,
→ [tex]c = v\times \lambda[/tex]
or,
→ [tex]v = \frac{c}{\lambda}[/tex]
By putting the values, we get
[tex]= \frac{3.00\times 10^8}{5.05\times 10^{-7}}[/tex]
[tex]= 5.9405\times 10^{14} \ Hz[/tex]
Thus the above answer is right.
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Please tell me an example of a protein structure that would give positive test with Molisch’s Reagent?
Answer:
positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).
Answer:
glycoproteins
Explanation:
A positive reaction for Molisch's test is given by almost all carbohydrates (exceptions include tetroses & trioses). It can be noted that even some glycoproteins and nucleic acids give positive results for this test (since they tend to undergo hydrolysis when exposed to strong mineral acids and form monosaccharides).
Covert 645g of CuCl2 to mole
Answer:
kombinasi kuda-kuda belakang
Explanation:
maaf kalau salahnya
Increasing the frequency _________________ the wavelength. Group of answer choices decreases increases does not change
Answer:
heightens
Explanation:
In the following reaction, how many liters of oxygen will react with 270 liters of ethene (C2H4) at STP?
C2H4(g) + 3O2(g) 2CO2(g) + 2H2O(g)
The volume of one mole of gas at STP is 22.4 liters.
Substance whose smell changes in acidic or basic solutions
Answer:
Olfactory indicators
Explanation:
The substance whose odour changes in an acidic of basic medium are called olfactory indicators. In an olfactory indicator , smell varies depending on whether it is mixed with an acidic or basic solution.
A student uses a solution of potassium hydroxide to titrate a solution of nitric acid. Which question is the student trying to answer?(1 point)
What is the concentration of nitric acid?
What is the concentration of nitric acid?
How much nitric acid solution is present?
How much nitric acid solution is present?
What is the concentration of potassium hydroxide?
What is the concentration of potassium hydroxide?
How many moles of potassium hydroxide are present?
How many moles of potassium hydroxide are present?
Answer:
A. What is the concentration of nitric acid?
Explanation:
its right
Answer:
A
Explanation:
The flask contains 25 mL of an unknown diprotic acid aqueous solution that reacts in a 1:2 stochiometric ratio with NaOH. Titrate the solution with NaOH to determine the concentration of the acid. Perform a titration by setting the concentration of the NaOH solution and adding it to the acid solution using the different Add Base buttons. The equilvalence point of the titration is passed when the indicator color changes. The unknown sample can be titrated multiple times by pressing the Retitrate button and starting over. Enter the concentration of the unknown acid solution.
To obtain accurate results, follow the following procedure:
switch the indicator to phenolphthalein titrate 1 mL at a time until solution turns pink, make note of volume added retitrate add 1 mL at a time until 1 mL less than the first titration add 0.05 mL at a time until the solution just turns pink
Answer:
The flask contains 25 mL of an unknown diprotic acid aqueous solution that reacts in a 1:2 stochiometric ratio with NaOH. Titrate the solution with NaOH to determine the concentration of the acid. Perform a titration by setting the concentration of the NaOH solution and adding it to the acid solution using the different Add Base buttons. The equilvalence point of the titration is passed when the indicator color changes. The unknown sample can be titrated multiple times by pressing the Retitrate button and starting over. Enter the concentration of the unknown acid solution.
Explanation:
.. How many seconds will it take for a satellite to travel 650 km at a rate of 220 m/s?
Answer: 3750s Happy To Help
Explanation:
Identify the functional groups present in each molecule.
A 19-carbon compound is composed of one five-membered ring and three six-membered rings.
Carbon 3 is double bonded to an oxygen and attached to carbon 2 and carbon 4.
Carbon 17 is attached to an oxygen, which is attached to a hydrogen.
i. hydroxyl group
ii. carboxyl group
iii. carbonyl group
A central carbon is attached to an amine, two hydrogens, and a carbon that is double bonded to an oxygen and single bonded to an oxygen attached to a hydrogen.
i. amino group
ii. carboxyl group
iii. amide group
Answer:
Carbon 3 is double bonded to an oxygen and attached to carbon 2 and carbon 4. :
Answer: Carbonyl group ( Ketone or aldehyde)
Carbon 17 is attached to an oxygen, which is attached to a hydrogen. :
Answer: Carboxyl group (Carboxylic acid)
A central carbon is attached to an amine, two hydrogens, and a carbon that is double bonded to an oxygen and single bonded to an oxygen attached to a hydrogen. :
Answer: Amide group
An amide group contains both amine and carboxyl
[tex].[/tex]
Que son Moléculas neutras
Answer:
Una molecula en que hay igual numero de cargas positivas y negativas y los electrones estan distribuidos de modo que no hay regiones con carga parcial(o sea una molecula no polar). Esto ocurre cuand los atomos tienen mas o menos igual electronegatividad para atraer los electrones.
Explanation:
How many moles are present in a sample of HCI with a mass of with a mass of 3.65g?
Answer:
number of moles = 0.1001 mol
Explanation:
number of moles = mass/molar mass
number of moles = 3.65g / 36.459 g/mol
n = 0.1001 mol
how many grams of hydrogen in 1.85moles
Explain the process of ionization in at least 1 paragraph.
Brainliest goes to best explanation!
Explanation:
Ionization is the process by which ions are formed by gain or loss of an electron from an atom or molecule. If an atom or molecule gains an electron, it becomes negatively charged (an anion), and if it loses an electron, it becomes positively charged (a cation). Energy may be lost or gained in the formation of an ion.
Biểu thức định luật Raoul là?
Answer: Định luật Raoult là một định luật hóa học vật lý, với ý nghĩa trong nhiệt động lực học. Được thành lập bởi nhà hóa học người Pháp François-Marie Raoult vào năm 1887, nó nói rằng áp suất một phần của mỗi thành phần của một hỗn hợp chất lỏng lý tưởng bằng với áp suất hơi của thành phần tinh khiết nhân với phần nốt ruồi của nó trong hỗn hợp. Kết quả là, việc giảm áp suất hơi tương đối của dung dịch pha loãng của chất tan không lây bằng với phần nốt ruồi của chất tan trong dung dịch.
Explanation: hope this helps :)
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Answer:
B
Explanation:
Answer:
B
Explanation:
U can read the second part
Part D
Based on the activity series you created in part C, predict whether there would be a chemical reaction or no
reaction when the listed pairs of substances are combined.
Answer:
magnesium and copper(II) sulfate no reaction
iron and magnesium sulfate reaction
copper and iron(III) nitrate reaction
magnesium and hydrochloric acid reaction
Explanation:
THIS IS MY LAST WUESTION FOR MY TEST I ONLY HAVE 30 MINS LEFT TO ASNWER HELP.
Tiffany decided to make a salad for her lunch. She combined Lettuce, croutons, bacon,
cucumbers, cheese, ham and salad dressing into her bowl. As she was adding each different
ingredient, she tasted each one to make sure that she like it. When she was done, she ate her
salad. She noticed while she was eating the salad, that it had a different flavor than each of the
original ingredients. What type of change occurred?
Homogenous change
A solution change
A chemical change
A physical change
Please help me with this I’ll give you extra credit it’s due in 10 minutes thank youuu!!! :))
Answer:
Okay ask away. . . You haven't asked anything that we would be able to answer
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A 49.8 mL sample of gas in a cylinder is warmed
from 18°C to 83 °C.
what is it’s volume at the final temperature? (Assume constant pressure)
Using Charles law
[tex]\\ \sf\longmapsto V_1T_2=V_2T_1[/tex]
[tex]\\ \sf\longmapsto V_2=V_1T_2\div T_1[/tex]
[tex]\\ \sf\longmapsto V_2=\dfrac{49.8(356)}{291}[/tex]
[tex]\\ \sf\longmapsto V_2=\dfrac{17728.8}{291}[/tex]
[tex]\\ \sf\longmapsto V_2=60.9mL[/tex]