Answer:
"Stop!" Cheryl shouted.
34, 83, 116, 111, 112, 33, 34, 32, 67, 104, 101, 114, 121, 108, 32, 115, 104, 111, 117, 116, 101, 100, 46
Does 2 + 3 = 5?
68, 111, 101, 115, 32, 50, 32, 43, 32, 51, 32, 61, 32, 53, 63
I got these numbers with this python code:
print([ord(c) for c in '"Stop!" Cheryl shouted.'])
print([ord(c) for c in 'Does 2 + 3 = 5?'])
Bruno is a network engineer who is tasked with adding a separate layer of protection to the control plane of a router. He wants messages with a bps (bits per second) rate below the threshold 7000 to be transmitted and the messages with a threshold above 7000 to be dropped. Analyze which of the following commands Bruno should use in pmap configuration mode in this scenario.
A network engineer has the duty of protecting a network from external or internal attacks that wants to compromise the integrity of the network.
What is Control Plane Policing?This refers to one of the ways of protecting the control plane by policing the traffic coming into it.
The use of control plane policing is the feature that Bruno is making use of as he wants messages with a bps (bits per second) rate below the threshold of 7000 to be transmitted and the messages with a threshold above 7000 to be dropped.
Please note that your question is incomplete so I gave you a general overview to help you get a better understanding of the concept.
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Write a short note on Ms - Excel.....
Answer:
Microsoft Excel is a spreadsheet program. It provides a grid interface to organize the various information. You can use Excel to create and format workbooks in order to analyse the data. Specifically, you can use Excel to track data, build models for analysing data, write formulas to perform calculations on that data, pivot the data in various ways, and present data in a variety of professional looking charts. Excel is used widely in financial activity. It has the ability to create new spreadsheets where users can define custom formulas for the calculation. Excel is also used widely for common information organization and tracking like a list of sales leads, project status reports, contact lists, and invoicing. Excel is also useful tool for scientific and statistical analysis with large data sets.
Which image file format consumes the most file
space?
0
GIF
JPEG
PNG
Answer: jpeg becauuse itss correct
explain approaches of AI
Answer:
Main AI Approaches
There are three related concepts that have been frequently used in recent years: AI, machine learning, and deep learning.
Sorry, I cant tell you, you need to know
Answer:
answer a
Explanation:
sorry it’s for the points
Complete the sentence.
A(n) ___ interface is one that supports as many people as possible by considering disabilities, screen sizes, languages, and many other factors.
1. web-safe
2. accessible
3. inclusive
what were the results of Dr.bjork's experiment
Answer:
Studying in different rooms seemed to improve a persons memory
why 4gl is called non procedural language? explain in detail.
Answer:
h The user, not the computer, specifies what is desired in terms of application.
. Find the sum of the squares of the integers from 1 to MySquare, where
MySquare is input by the user. Be sure to check that the user enters a positive
integer.
Answer:
in c
Explanation:
#include <stdio.h>
int sumSquares(int n) {
if(n == 0) return 0; else if (n == 1) return 1; else return (n*n) + sumSquares(n - 1);
}
int main() {
int mySquare;
puts("Enter mySquare : ");
scanf("%d", &mySquare);
if(mySquare < 0) mySquare *= -1;// makes mySquare positive if it was negative
printf("Sum of squares: %d", sumSquares(mySquare));
}
Spam is _____.
a set of rules that you should follow when sending e-mail
a set of rules that you should follow when sending e-mail
an example of an ethical use of email
an example of an ethical use of email
the practice of sending unwanted messages to a large group of people
the practice of sending unwanted messages to a large group of people
a type of attachment
Answer:
any kind of unwanted, unsolicited digital communication that gets sent out in bulk
Paragraph on uses of computer 100 words plss
REFER TO ATTACHMENT・ᴥ・
What is the output of this program? Assume the user enters 3, 6, and 11.
numA = 0
for count in range(3):
answer = input ("Enter a number: ")
fltAnswer = float(answer)
numA = numA + fltAnswer
print (numA)
Answer: 20
That would be the sum of 3, 6 and 11.
Explanation:
numA = 0
This step creates a variable called num A with the value of zero.
for count in range(3):
This step repeats our following 3 lines of code 3 times.
answer = input ("Enter a number: ")
This line of code creates and sets the variable "answer" to the
value of what the user enters.
fltAnswer = float(answer)
This step converts our prevous user input which was a string into a
float. This is were the code screams if you were to enter a character
instead of a number.
numA = numA + fltAnswer
This step adds the user input to the variable numA.
Or more correct:
This step sets the variable numA to its previous value plus the user
input.
print (numA)
This step prints out numA. This line is also outside of the loop and
will only activate once when the loop ends.
Convert 108/10 to binary
Explanation:
The answer would be 1101100
Can anyone help me how to fix this code? The output aren't the same as the datafile. It can't be in a matrix shape in the data file.
#include <iostream>
#include <fstream>
using namespace std;
int main()
{
ofstream myfile("Matrix.dat",ios::app);
int A[100][100], B[100][100], row1, co11, row2, co12, i, j, k;
cout << "Enter no. of rows for matrix A: ";
cin >> row1;
cout << "Enter no. of columns for matrix A: ";
cin >> co11;
cout << "Enter no. columns for matrix B: ";
cin >> row2;
cout << "Enter no. of rows for matrix B: ";
cin >> co12 ;
myfile << row1 <<endl;
myfile << co11 <<endl;
myfile << row2 <<endl;
myfile << co12 <<endl;
myfile << endl;
while (co11!=row2)
{
cout << "Sorry! Column of matric A is not equal to row of matrix B.";
cout << "Please enter rows and columns for matrix A: ";
cin >> row1 >> co11;
cout << "Please enter rows and column for the maxtrix B: ";
cin >> row2 >> co12; }
//read matrices
//Storing elements of matrix A
cout << endl << "Enter elements of matrix A:" << endl;
for(i = 0; i < row1; ++i)
for(j = 0; j < co11; ++j)
{
cout << "Enter element A" << i + 1 << j + 1 << " : ";
cin >> A[i][j];
}
//Storing elements of matrix B
cout << endl << "Enter elements of matrix B:" << endl;
for(i=0; i < row2; ++i)
for(j=0; j < co12; ++j)
{
cout << "Enter element B" << i + 1 << j + 1 << " : ";
cin >> B[i][j];
}
//Displaying output of two matrix
{
cout << " \n Matrix A: \n " << endl;
for(i = 0; i < row1; ++i)
{
for(j = 0; j < co11; ++j)
cout << A[i][j] << " ";
cout << endl;
myfile << A[i][j] << " ";
myfile << endl;
}
cout << "\n Matrix B: \n " <<endl;
for(i = 0; i < row2; ++i)
{
for(j = 0; j < co12; ++j)
cout << B[i][j] << " ";
cout << endl;
myfile << B[i][j] << " ";
myfile << endl;
}
return 0;
}
}
Answer:
#include <iostream>
#include <fstream>
using namespace std;
int main()
{
ofstream myfile("Matrix.dat", ios::app);
int A[100][100], B[100][100], row1, co11, row2, co12, i, j, k;
cout << "Enter no. of rows for matrix A: ";
cin >> row1;
cout << "Enter no. of columns for matrix A: ";
cin >> co11;
cout << "Enter no. columns for matrix B: ";
cin >> row2;
cout << "Enter no. of rows for matrix B: ";
cin >> co12;
myfile << row1 << endl;
myfile << co11 << endl;
myfile << row2 << endl;
myfile << co12 << endl;
myfile << endl;
while (co11 != row2)
{
cout << "Sorry! Column of matric A is not equal to row of matrix B.";
cout << "Please enter rows and columns for matrix A: ";
cin >> row1 >> co11;
cout << "Please enter rows and column for the maxtrix B: ";
cin >> row2 >> co12;
}
//read matrices
//Storing elements of matrix A
cout << endl << "Enter elements of matrix A:" << endl;
for (i = 0; i < row1; ++i)
for (j = 0; j < co11; ++j)
{
cout << "Enter element A" << i + 1 << j + 1 << " : ";
cin >> A[i][j];
}
//Storing elements of matrix B
cout << endl << "Enter elements of matrix B:" << endl;
for (i = 0; i < row2; ++i)
for (j = 0; j < co12; ++j)
{
cout << "Enter element B" << i + 1 << j + 1 << " : ";
cin >> B[i][j];
}
//Displaying output of two matrix
{
cout << " \n Matrix A: \n " << endl;
for (i = 0; i < row1; ++i)
{
for (j = 0; j < co11; ++j)
{
cout << A[i][j] << " ";
myfile << A[i][j] << " ";
}
myfile << endl;
cout << endl;
}
myfile << endl;
cout << "\n Matrix B: \n " << endl;
for (i = 0; i < row2; ++i)
{
for (j = 0; j < co12; ++j)
{
cout << B[i][j] << " ";
myfile << B[i][j] << " ";
}
myfile << endl;
cout << endl;
}
return 0;
}
}
Explanation:
I believe the issue was just a matter of when << endl; was being used.
My results:
2
2
2
2
1 2
3 4
5 6
7 8
I'm not exactly how this is supposed to look, but based on the image, this seems like the target output format.
Please test this code. If it is not what you were looking for, then tell me what's wrong with the output.
The electronic transmission standard for outpatient encounter is
The 837I (Institutional) format is the standard format used by institutional providers to electronically communicate health care claims.
Who was making the high-pitched growling noise that Francisco hears?
The high-pitched growling noise that Francisco hears is due to mating call of male midshipman fish or 5G.
What is the hum about?The Hum is known to be a kind of unexplained happenings that has brought a lot of irritations to people. It is known to be a high-pitched noise that brought a lot of scientific theories.
Studies has shown that the high-pitched growling noise that Francisco hears is as a result of mating call of male midshipman fish or 5G.
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Need help finding the smallest number and ending the program with -1. This is what I got H = int(input("Enter a number or enter -1 to end)"))
smallest = H
counter=0
while(True):
number = int(input("Enter a number: "))
if(number == -1):
break
if(number < H):
smallest = number
print(number, "is the smallest")
Let me know What I'm doing wrong please
Answer: your not doing anything wrong it is all good but you need to add a little more to it
Explanation:
drive.
safely*
How many years was Eric sentenced to prison?
life
22 years
30 years
5 years
Answer:
22
Explanation:
2. Write the pseudocode to print all multiples of 5 between 10 and 25 (including both
10 and 25)
Answer:
Read code below
Explanation:
n = 10
while n is <= 25{
print(n)
n +=5
}
This while loop will print all multiples of 5 between 10 and 25 by starting with 10 as n, printing n, then incrementing n by 5 until n is greater than 25.
Anyone want to try ?
Check Your Work: looping_lists.py
Make sure your looping_lists.py program prints the following items, in this order:
print("Using a for loop to print the colors list elements:")
print("Using a for loop with range(10) to print iterator values and a string:")
for i in range(10):
print(i, “Hello”)
counter = 0
print("Using a while loop to print iterator values and a string:")
while counter < 5:
print(counter, "Loop while the counter is less than 5")
counter = counter + 1
print("The for loop removes and prints list elements in stack order:")
for i in range(len(colors)):
print(colors.pop())
print("The colors list after all elements are removed:\n", colors)
new_colors = ["red", "orange", "yellow", "green", "blue", "purple"]
print("The loop prints and removes elements in the new_colors list in queue order:")
for i in range(len(new_colors)):
print(new_colors.pop(0))
print("The new_colors list after all elements are removed:\n", new_colors)
more_colors = ["violet", "pink", "brown", "teal", "magenta"]
more_colors_deque = deque(more_colors)
print("Elements in the more_colors list:\n", more_colors)
print("Elements in the deque object:\n", more_colors_deque)
print("Using a for loop to print the deque elements as a queue:")
for i in range(len(more_colors_deque)):
print(more_colors_deque.popleft())
print("Printing the deque object after all elements are removed:\n",
more_colors_deque)
How has motherboard evolved over time ?
Answer:
more devices were integrated into the motherboard.
Explanation:
It was a slow trend initially though, as I/O ports and disk controllers
what devices do not allow data stored on them to be modified.
Answer:
Read-only memory (ROM) is a type of non-volatile memory used in computers and other electronic devices. Data stored in ROM cannot be electronically modified after the manufacture of the memory device.
This is your code. >>> A = [21, 'dog', 'red'] >>> B = [35, 'cat', 'blue'] >>> C = [12, 'fish', 'green'] >>> e = [A,B,C] How do you refer to 'green'? e(2, 2) e(2, 2) e(2)(2) e(2)(2) e[2][2] e[2][2] e[2, 2] e[2, 2]
So the final list is
e=[A,B,C]Then
e=[[21,'dog','red'],[35,'Cat','blue'],[12,'fish','green']]green is inside a nested list of index 2
C is at index 2 alsoHence required reference is
e[2][2]The probability of event A occurring is 10/10. The probability of event B occurring is 0/10. What is the entropy of this system? Please show work.
The events A and B are the outcomes of the probabilities in the system
The entropy of the system is 0
How to determine the entropy?The probabilities are given as:
P(A) = 10/10
P(B) = 0/10
The entropy is calculated using:
[tex]H(x) = -\sum \limits^{n}_{i = 1} p_i * \log_2(p_i)[/tex]
So, we have
[tex]H(x) = -10/10 * \log_2(10/10) - 0/10 * \log_2(0/10)[/tex]
Evaluate the products
[tex]H(x) = -\log_2(10/10) - 0[/tex]
Evaluate the sum
[tex]H(x) = -\log_2(10/10)[/tex]
Evaluate the quotient
[tex]H(x) =- \log_2(1)[/tex]
Express 1 as 2^0
[tex]H(x) =- \log_2(2^0)[/tex]
Apply the power rule of logarithm
[tex]H(x) =- 0\log_2(2)[/tex]
Evaluate the product
H(x) =0
Hence, the entropy of the system is 0
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Cryptography is the practice of encryption. Information Security uses cryptography techniques to encrypt and decrypt data. A simple encryption method might take plaintext and mix up the letters using some predetermined pattern and then use that pattern to decrypt the data for reading.
Ciphers are the algorithms used to put the data into its secret pattern and then systematically decrypt it for reading. This script is going to use a famous simple cipher called the Caesar Cipher. It is a substitution cipher where each letter in the text is 'shifted' in a certain number of places. It uses the alphabet as the primary pattern and then based on the shift number, it would shift all the letters and replace the alphabet with our pattern.
For example, if our shift number was 3, then A would be replaced with D, if we performed a right shift. As an example:
Text = "THE CAT IS VISIBLE AT MIDNIGHT" Ciphertext = "WKH FDW LV YLVLEOH DW PLGQLIJKW"
The keys to decrypt this message are the shift number and the direction. The shift value can be any integer from 0 - 25. The above example uses shift = 3 and the shift direction is right or direction = 'r'.
Complete the CipherTest class by adding a constructor to initialize a cipher item. The constructor should initialize the shift to 0, and the direction to 'r' for right shift. If the constructor is called with a shift value, and direction, the constructor should assign each instance attribute with the appropriate parameter value.
Complete the following TODO's: (1) create input for text, shift value, and direction (use lower( )) to keep l and r lower case (2) create a cipher item and use the constructor with the above input values (3) use control structures to call shifttoright() if direction is right and call shifttoleft if direction is left. Make sure you print out the return encrypted message inside the control structures.
We can create the encrypted text by using the ord ( ) function. This function will return an integer that represents the Unicode code point of the character. Character are represented by different values for upp/er and lower case so an 'a' returns the integer 97. By using the unicode value we can add and subtract our shift value represented by an integer.
The given program accepts as input a text string as our message to be encrypted, a shift value, and a direction of 'l' for left and 'r' for right. The program creates a cipher item using the input values. The program outputs the encrypted message based on the shift value and the direction provided.
Ex: If the input is text = "Cryptography is fun!", shift = 4, and direction = l.
The output is:
The output of the text if the shift= 4 and the direction = l would be: Y.N.U.L.P.K.C.N.W.L.D.U E.O B.Q.J
What is Cryptography?This refers to the art of writing and solving codes through the use of ciphertext.
Hence, we can see that the ciphertext we have is that there is a shift of 4 and it moves in the leftward direction thus, using the letters of the English alphabet, we would encode this and the output is: Y.N.U.L.P.K.C.N.W.L.D.U E.O B.Q.J
ABCDEFGHIJKLMNOPQRSTUVWXYZ
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In a statement: Scanner keyboard = new Scanner (System.in);
it reads user input by means of a Scanner, the user types the line of input below, exactly as shown, including that same spacing.
What is the statement keyboard.nextDouble( ); returned ?
Answer "2": 1+2 is 3 and "5.0" squared is 25.0 !
Answer:
A misMatchException is returned.
Explanation: Keyboard.nextDouble(); is expecting a double as an input and the user entered a string first so an error is returned.
In a portfolio, which document contains the names and contact details of persons who know you professionally?
A. résumé
B. reference letter
C. certificate
D. tracking worksheet
E. brochure
Answer: B: Reference letter
Explanation: yes
In this lab, you add a loop and the statements that make up the loop body to a C++ program that is provided. When completed, the program should calculate two totals: the number of left-handed people and the number of right-handed people in your class. Your loop should execute until the user enters the character X instead of L for left-handed or R for right-handed.
The inputs for this program are as follows: R, R, R, L, L, L, R, L, R, R, L, X
Variables have been declared for you, and the input and output statements have been written.
Instructions
Ensure the source code file named LeftOrRight.cpp is open in the code editor.
Write a loop and a loop body that allows you to calculate a total of left-handed and right-handed people in your class.
Execute the program by clicking the Run button and using the data listed above and verify that the output is correct.
// LeftOrRight.cpp - This program calculates the total number of left-handed and right-handed
// students in a class.
// Input: L for left-handed; R for right handed; X to quit.
// Output: Prints the number of left-handed students and the number of right-handed students.
#include
#include
using namespace std;
int main()
{
string leftOrRight = ""; // L or R for one student.
int rightTotal = 0; // Number of right-handed students.
int leftTotal = 0; // Number of left-handed students.
// This is the work done in the housekeeping() function
cout << "Enter an L if you are left-handed, a R if you are right-handed or X to quit: ";
cin >> leftOrRight;
// This is the work done in the detailLoop() function
// Write your loop here.
// This is the work done in the endOfJob() function
// Output number of left or right-handed students.
cout << "Number of left-handed students: " << leftTotal << endl;
cout << "Number of right-handed students: " << rightTotal << endl;
return 0;
}
Answer:
#include <iostream>
#include <string>
// R, R, R, L, L, L, R, L, R, R, L, X ==> 6R 5L X
void getLeftOrRight(std::string &l_or_r, int &total_l, int &total_r) {
// notice how the above line matches: getLeftOrRight(leftOrRight, leftTotal, rightTotal);
// the values provided from the loop are given nicknames for this function getLeftOrRight()
if (l_or_r == "L") { // left-handed
total_l++;
} else if (l_or_r == "R") { // right-handed
total_r++;
} else { // quit
// option must be "X" (quit), so we do nothing!
}
return; // we return nothing, which is why the function is void
}
int main() {
std::string leftOrRight = ""; // L or R for one student.
int rightTotal = 0; // Number of right-handed students.
int leftTotal = 0; // Number of left-handed students.
while (leftOrRight != "X") { // whilst the user hasn't chosen "X" to quit
std::cout << "Pick an option:" << std::endl;
std::cout << "\t[L] left-handed\n\t[R] right-handed\n\t[X] quit\n\t--> ";
std::cin >> leftOrRight; // store the user's option in the variable
getLeftOrRight(leftOrRight, leftTotal, rightTotal); // call a function, and provide it the 3 arguments
}
std::cout << "Number of left-handed students: " << leftTotal << std::endl;
std::cout << "Number of right-handed students: " << rightTotal << std::endl;
return 0;
}
Explanation:
This is my take on the question! I had no idea what was meant by the housekeeping(), detailLoop(), endOfJob() functions provided in their source code.
What my code does should be pretty explanatory via the comments and variable names within it — but feel free to make a comment to ask for more info! I've attached a screenshot of my code because I think it's easier to read when it's syntax highlighted with colors.
In this code, the while loop continues to execute as long as the user enters something other than 'X'.
You need to write a loop that repeatedly takes input from the user and updates the leftTotal and rightTotal variables based on the input until the user enters 'X' to quit.
Here's the completed code:
#include <iostream>
using namespace std;
int main()
{
string leftOrRight = ""; // L or R for one student.
int rightTotal = 0; // Number of right-handed students.
int leftTotal = 0; // Number of left-handed students.
cout << "Enter an L if you are left-handed, a R if you are right-handed or X to quit: ";
cin >> leftOrRight;
// Write your loop here.
while (leftOrRight != "X") {
if (leftOrRight == "L") {
leftTotal++;
} else if (leftOrRight == "R") {
rightTotal++;
}
cout << "Enter an L if you are left-handed, a R if you are right-handed or X to quit: ";
cin >> leftOrRight;
}
cout << "Number of left-handed students: " << leftTotal << endl;
cout << "Number of right-handed students: " << rightTotal << endl;
return 0;
}
In this code, the while loop continues to execute as long as the user enters something other than 'X'.
Inside the loop, the input is checked for either 'L' or 'R', and the appropriate total variable is incremented accordingly.
The loop then prompts the user for input again until the user decides to quit by entering 'X'.
Finally, the code displays the total number of left-handed and right-handed students.
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Submit your 300-word article review on a recent cyber bullying occurrence that lists five key points and offers your suggestions for two
things the article should have covered?
Bullying that takes place through the use of digital technologies is known as cyberbullying. Due to increasing technology, cyberbullying is increasing day by day.
What is cyberbullying?Cyberbullying happens on social media, messaging platforms, gaming platforms, and mobile phones, among other places.
It is a pattern of behavior intended to frighten, anger, or shame those who are being targeted.
Thus, bullying that takes place through the use of digital technologies is known as cyberbullying. Due to increasing technology, cyberbullying is increasing day by day.
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Java Unit 3: Lesson 3 - Coding Activity 3
Answer:
import java.util.Scanner;
public class MultiplicationTablePractice {
public static void main(String[] args) {
var scanner = new Scanner(System.in);
var quit = false;
while (!quit) {
var randomNumber1 = (int) (Math.random() * 12) + 1;
var randomNumber2 = (int) (Math.random() * 12) + 1;
System.out.println(randomNumber1 + " * " + randomNumber2 + " = ?");
var answer = scanner.nextInt();
if (answer == randomNumber1 * randomNumber2) {
System.out.println("Correct!");
} else {
System.out.println("Wrong!");
}
System.out.println("Quit? (y/n)");
var quitInput = scanner.next();
if (quitInput.equals("y") ||
quitInput.equals("Y")) {
quit = true;
}
}
scanner.close();
}
}
Explanation:
First, we create a new scanner object, based on the System.in stream. Then we create a varaible called quit which we set to false which we then use as the condition for the while loop.
Inside the scope of the while loop, we create two random numbers based off of Math.random(). The formula we use is (int) (Math.random() * 12) + 1; With these new variables, we print:
randomNumber1 + " * " + randomNumber2 + " = ? "
After this is printed, we scan the user input as an int. We check the input answer against the actual answer to check if it's correct or not. If it is correct, we print "Correct!" otherwise we print "Wrong!".
Once all of this is handled, we ask the user if they want to quit or not. If the input is "y" or "Y" the while loop terminates, and the scanner closes. Otherwise, the while loop will continue, and restart the process.