413.33 The 3 in the hundredths place is _____ times the value of the 3 in the tenths place.

After solving the equation: the nearest cent, the interest earned is $467.

Interest is a mathematical concept used to describe the cost or gain associated with the use of money over a period of time. It is usually expressed as a percentage rate of the principal (the amount borrowed or invested). Interest can be earned or paid, depending on the situation.

Using the formula B=p(1+r)t, John's final balance after 1 year is B = 4069(1+0.12)1 = $4,536.28.
The interest earned in 1 year is the difference between the final balance and the starting amount, which is $4,536.28 - $4,069 = $467.28. To the nearest cent, the interest earned is $467.

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Answer:

The expected value is $2.1

Step-by-step explanation:

If we have an event with some given outcomes:

x₁, x₂, ..., xₙ

Such that each one of these outcomes has the correspondent probability:

p₁, p₂, ..., pₙ

The expected value is:

EV = p₁*x₁ + ... + pₙ*xₙ

In this case we have a table with the events (the payouts) and the probability for each one, so we have:

x₁ = $0

p₁ = 0.5

x₂ = $2

p₂ = 0.2

x₃ = $4

p₃ = 0.15

x₄ = $6

p₄ = 0.1

x₅ = $10

p₅ = 0.05

Now we can just replace these in the expected value equation, so we get:

EV = $0*0.5 + $2*0.2 + $4*0.15 + $6*0.1 + $10*0.05 = $2.1

Answer:

a number that cannot be written as a/b

it's a non-repeating, non-terminating decimal

typically, irrational numbers are square roots of numbers that are not perfect squares; also, π is considered irrational

Step-by-step explanation:

Answer:

12x-6

Step-by-step explanation:

Answer:

The common ratio is 4

Step-by-step explanation:

How?

Multiplying or dividing is how to get the common ratio in a geometric sequence (moving from either left to right or right to left) *in this question to be precise* okay so...

Moving from right to left, and dividing, 96 ÷ 24 is 4; 24 ÷6 is 4 so the common ration is still 4.

(To find the next terms, moving from left to right, and multiplying, multiply the previous term by the common ration, so the next term after 96 is 96 × 4, which is 384, and you continue....)

You are very welcome and good luck :)

The horizontal distance required for the ramp is 143.5 inches

Consider the following figure.

In right triangle ACB, CB is the horizontal distance,

hypotenuse AB = 144 in.

and the vertical distance AC = 12 in.

We need to find the measure of side CB

Let m be the measure of the horizontal distance CB

Using Pythagoras theorem for right triangle ACB,

(AB)² = (AC)² + (CB)²

Substitute given values in above equation.

(144)² = (12)² + (m)²

20736 = 144 + m^2

20736 - 144 = 144 + m^2 - 144

20592 = m^2

m^2 = 20592

m = 143.5 in.

Therefore,  the horizontal distance is 143.5 in.

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Answer:by uvyvyvyi

Step-by-step explanation:

Answer:

28 units

Step-by-step explanation:

Firstly, we can see that the vertical sides are 9 units each.

To get the diagonal sides, we can turn the ends into right triangles, which we can then use with the Pythagorean Theorum.

To make the top side into a triangle, we would draw a horizontal line connecting points (-1, 3) and (3, 3). This creates a right angle which is essential when using the Pythagorean Theorum.

A^2 + B^2 = C^2

We can plug in values for the Pythagorean Theorum because we can see that going across horizontally from point (-1, 3) to (3, 3), there are 4 units in between the two points. This will be our A value. We will do the same but vertically from points (3, 6) to (3, 3). The 3 units between the two points will be our B value. Now, we can plug in our values into the Pythagorean Theorum to find side C, the hypotenuse.

4^2 + 3^2 = C^2

16 + 9 = C^2

25 = C^2

√25 = C

C = 5

Now that we know the diagonal value of the side, we also know the same diagonal value of the bottom side. When you add all four sides together,

9 + 5 + 9 + 5 = 28

you get 28, which is the perimeter of the parallelogram.

Answer:

B. 45

Step-by-step explanation:

If im wrong please let me know

Have a nice day :)

Answer:

The height of the smaller cone is 19.52 cm

Step-by-step explanation:

Given that,

The volume of cone 1, V₁ = 3970 cm³

The volume of cone 2, V₂ = 3100 cm³

The height of the larger cone, h₁ = 25 cm

We need to find the height of the smaller cone. Let it is h₂. For similar cones,

[tex]\dfrac{V_1}{V_2}=\dfrac{h_1}{h_2}[/tex]

Put values,

[tex]h_2=\dfrac{h_1V_2}{V_1}\\\\h_2=\dfrac{25\times 3100}{3970}\\h_2=19.52\ cm[/tex]

So, the height of the smaller cone is 19.52 cm.

Answer:

8

Step-by-step explanation:

5 ( x - 3 ) + 2x = 41

5x - 15 + 2x = 41

5x + 2x - 15 = 41

7x - 15 = 41

7x = 41 + 15

7x = 56

x = 56 / 7

x = 8

Answer:

X=8

Step-by-step explanation:

Combine like terms: 5x + 2x = 7x

-15 + 7x = 41

Solving

-15 + 7x = 41

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '15' to each side of the equation.

-15 + 15 + 7x = 41 + 15

Combine like terms: -15 + 15 = 0

0 + 7x = 41 + 15

7x = 41 + 15

Combine like terms: 41 + 15 = 56

7x = 56

Divide each side by '7'.

x = 8

Answer:

x+-3/4

Step-by-step explanation:

-2/3(2)+x+7/3/4

=-4/3+(4/3+7/12)

x+-3/4

Answer:

(6,2)

Step-by-step explanation:

Combine them

Answer:

Step-by-step explanation:

A system of equations is a set of two or more equations that represent a relationship between two or more variables. A solution of this system is an ordered pair that satisfies each equation in the system. Finding the set of all solutions is called solving the system of equations. Solving a system of equations by graphing is exactly what the name implies – graph both equations, and their point(s) of intersection is the solution. A system of linear equations only have one solution because each equation is a straight line, they will only have one point of intersection (unless, of course, they are the same line).

THE TWO LINES WOULD INTERSECT (6, 2). BECAUSE THE SOLUTION IS THE INTERSECTION..

Answer:

El perímetro de un terreno rectangular mide 48 m . Calcula sus dimensiones si el largo es el doble que el ancho.

Respuesta:

De largo mide 16m

De ancho mide 8m

Explicación paso a paso:

Perímetro = número de lados multiplicado por longitud del lado.

Formula: P = 2(a + b)  o    P = 2b + 2h

Donde: P = Rectángulo del perímetro

           a y b = Longitudes de lados

Asignamos las variables:

Largo = 2x

Ancho = x

Utilizamos la formula:

2(x) + 2(2x) = 48

2x + 4x = 48

6x = 48

x = 48/6

x = 8m  (ancho)

2x

2(8)

16m (largo)

Step-by-step explanation:

When you and your 3 friends decide to split the bill of $36 evenly and you leaving a 12% tip on your part, you pay a total of $13.32.

Therefore the answer is 13.32 dollars.

When you and your 3 friends decide to split the bill evenly, each person is responsible for paying 1/4 of the total bill. The total bill is $36, so each person is responsible for paying

$36 / 4 = $9

You also decided to leave a 12% tip on your part, so you need to calculate 12% of $36. To do this, you can multiply $9 by 0.12

$36 × 0.12 = $4.32  

So, you are responsible for paying $9 + $4.32 = $13.32

So you are responsible for paying $13.32 in total.

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If [tex]$\mathrm{x} \neq 3$[/tex], the expression [tex]$\frac{2 x^3+7 x^2-3 x-25}{x+3}$[/tex] is equivalent to [tex]$2 x^2+x-6-\frac{7}{x+3}$$[/tex].

A mathematical expression is a phrase that includes at least two numbers or variables, at least one arithmetic operation, and the expression itself. Any one of the following mathematical operations can be used.

A mathematical sentence with variables, numbers, or both is known as an expression. Operation can also be a part of an expression, although an equal sign is never present in an operation. A mathematical expression that demonstrates the equality of two expressions is called an equation. There is a sign of equality in equations.

An expression in mathematics is made up of a mixture of variables, numbers, and functions (such as addition, subtraction, multiplication or division etc.) In some ways, phrases and expressions are comparable.

Let the equation be

[tex]$\frac{2 x^3+7 x^2-3 x-25}{x+3}[/tex]

simplifying the equation, we get

[tex]$& \text { Divide } \frac{2 x^3+7 x^2-3 x-25}{x+3}=2 x^2+\frac{x^2-3 x-25}{x+3} \\[/tex]

[tex]$& =2 x^2+\frac{x^2-3 x-25}{x+3}[/tex]

[tex]$& \text { Divide } \frac{x^2-3 x-25}{x+3}=x+\frac{-6 x-25}{x+3} \\[/tex]

[tex]$ =2 x^2+x+\frac{-6 x-25}{x+3}[/tex]

Divide [tex]$\frac{-6 x-25}{x+3}=-6+\frac{-7}{x+3}$[/tex]

[tex]$=2 x^2+x-6+\frac{-7}{x+3}$$[/tex]

Simplifying the equation, we get

[tex]$=2 x^2+x-6-\frac{7}{x+3}$$[/tex]

Therefore, the correct answer is option 1) [tex]$2 x^2+x-6-\frac{7}{x+3}$$[/tex].

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Answer:

$8.

Step-by-step explanation:

right!!

Answer:

a = 1.5

VW = 9 ft

Step-by-step explanation:

Since the tangent lines connect both circles, we know that the line VU and VX are congruent (equal). Thus, we can set them equal to each other and solve for a:

a + 4 = a² + 0.25                            Set equal

a² - a = 3.75                                    Isolate a values

a² - a + 0.25 = 3.75 + 0.25            Complete the square

(a + 0.5)² = 4                                  Factor

a + 0.5 = 2                                     Simplify

a = 1.5

Now we need to calculate VW, but thats easy because its equal to TV, and since we know a, we can just plug it in:

((1.5) + 7.5) ft

9 ft

On solving the provided question, we can say that - the linear equation y = 7x - 17 at x= 0; y = -17 and m = -17

The algebraic equation y=mx+b is known as a linear equation. B is the y-intercept, and m is the slope. The previous sentence, where y and x are variables, is commonly referred to as a "linear equation in two variables." Bivariate linear equations are those that contain two variables in them. The linear equations 2x - 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, x + y = 2, and 3x - y + z = 3 are examples. When an equation has the formula y=mx+b, with m denoting the slope and b the y-intercept, it is referred to as being linear.

y = 7x - 17

at x= 0

y = -17

and m = -17

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[tex]( x - 4 ) + ( 2x - 7 )[/tex]

Combine Like Terms:

[tex](x+2x)+(-4+-7)[/tex]

[tex](3x)+(-11)[/tex]

[tex]\fbox{3x - 11}[/tex]

Answer:3x-11

Step-by-step explanation:

(x-4)+( 2x-7)

x-4+2x-7

3x-11

Answer:

7

Step-by-step explanation:

Since V is equal to 5, I'm guessing the equation is 2V - 3? You substitute V with 5, in the equation and solve! 5 ⋅ 2 - 3, so 5 times 2 is 10, and then you subtract 3 by 10. Then you get the answer 7!

Answer:

Step-by-step explanation:

standard form = combine like therms and degrees drop from left to right

In this there aren’t like therms, so:

6x^3+x^2-9x+5

therms =  each therm is seprated by a plus or a minus

in this case there are 4 therms

degree = look at the monomial with the highest degree

in this case is 3

Name = in this case there are four therms so it is a quadrinomial

Standard form denotes to arranging according to degrees or exponents

Standard form

Number of terms=4

Degree=3

Name Quadrinomial or Biquadratic

Answer:

Step-by-step explanation:

SQR-PRQ-SRP

SP/RP=RP/PQ

QP/QR=RQ/SQ

Answer: The Seed Calculator app is used to calculate the amount of seed required in order to produce a desired crop yield.

Step-by-step explanation:

Answer:

3pq

Step-by-step explanation:

The statement regarding the region of rejection for a 5% significance level would be true is the region of rejection lies between the z-scores -2 and 2.Option B is correct.

A collection of values for the test statistic for which the null hypothesis is rejected constitutes a critical zone, sometimes referred to as the region of rejection. For example, if the observed test statistic is in the critical range, the null hypothesis is rejected and the alternative hypothesis is accepted.

Further the rejection zone is the area in which we have sufficient data to reject the null hypothesis if our test statistic falls within it. The rejection area, for the right-tailed test, for instance, is any value bigger than the critical value, or c 1 .

Therefore, the interval that causes the null hypothesis H 0 to be rejected in a hypothesis test is known as the region of rejection and is measured in the sampling distribution of the statistic under examination.

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