4/7x7/8. Can somebody help me with this I’m so confused

9514 1404 393

Answer:

Step-by-step explanation:

Let x, y, z represent the numbers of 20-cent, 35-cent, and 50-cent valentines. Then the given relations can be written as ...

  x = 1 +2y

  z = -2 +y

  0.20x +0.35y +0.50z = 4.20

__

Using the first two equations to substitute for x and y in the third equation, we get ...

  0.20(1 +2y) +0.35y +0.50(-2 +y) = 4.20

  1.25y -0.80 = 4.20 . . . . . simplify

  1.25y = 5.00 . . . . . . . . . . add 0.80

  y = 4 . . . . . . . . . . . . . . . divide by 1.25

  x = 1 +2(4) = 9

  z = -2 +4 = 2

Romeo bought 9 20-cent, 4 35-cent, and 2 50-cent valentines.

Answer:

[tex]x = 9 \\ y = 3 \\ xy = x \times y = 9 \times 3 \\ = 27[/tex]

Step-by-step explanation:

the explanation is in the diagram above

Answer:

Step-by-step explanation:

Let the height above which the ball is released be  H  

This problem can be tackled using geometric progression.

The  nth  term of a Geometric progression is given by the above, where  n  is the term index,  a  is the first term and the sum for such a progression up to the  Nth  term is

Answer:

Ten

Step-by-step explanation:

5000/500 = 10

Answer: 10 times as many 5 hundreds

Step-by-step explanation: five times five hundreds equals 5,000

Answer:

the value of N should be -1

90,000 units of the product has to be sold each year in other to break even.

The old established price = 42 per unit :

The break even unit is the number of units sold such that the net profit = 0

(expenses - income) = 0

The expenses = (Fixed cost + variable cost)

Fixed cost = 540000

Fixed cost = 540000Variable cost per unit = 36

Let the number of units required to break even = x

Expenses = income or revenue

(540000 + 36x) = 42x

540000 + 36x = 42x

540000 = 42x - 36x

540000 = 6x

x = 540000 / 6

x = 90000

Hence, 90,000 units has to be sold at the old established price in other to break even.

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Answer:

21

Step-by-step explanation:

3^2=9

9+12=21

Keep it up

Step-by-step explanation:

let the number

[tex] = x[/tex]

Then:

[tex](3x - 14) = 53 \\ 3x = 53 + 14 \\ 3x = 67 \\ x = 67 \div 3 = 22.33[/tex]

Answer:

[tex]number = x \\ 3x - 14 = - 53 \\ 3x = - 53 + 14 \\ 3x = - 39 \\ x = \frac{ - 39}{3} \\ x = - 13 \\ thank \: you[/tex]

Answer:

d. 0.25q+0.10d

Step-by-step explanation:

Because quarters are equivalent to 0.25 and dimes are 10 cents, option d is correct.

The expression to find the total amount of money in Andrea's jar is: 0.25q + 0.10d.

Thus, option (D) is correct.

A quarter is worth $0.25, and the number of quarters is represented by q.

A dime is worth $0.10, and the number of dimes is represented by d.

To calculate the total amount of money, multiply the value of each coin by the respective quantity and sum them up.

So, the expression to find the total amounts is 0.25q + 0.10d

Here, expression accounts for the value of each coin (0.25 for a quarter and 0.10 for a dime) and multiplies it by the corresponding quantity to obtain the total amount of money in dollars.

Thus, option (D) is correct.

Learn more about Expression here:

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Answer:

c)9

Step-by-step explanation:

f(x)=2x+1

f(1)=2(1)+1

f(1)=2+1

f(1)=3

g(x)=7/4 x+1

g(-4)=7/4 (-4)+1

g(-4)=-7+1

g(-4)=-6

f(1)-g(-4)=3-(-6)

=3+6

=9

Answer:

If two vectors are perpendicular, then their dot-product is equal to zero. The cross-product of two vectors is defined to be A×B = (a2_b3 - a3_b2, a3_b1 - a1_b3, a1_b2 - a2*b1). The cross product of two non-parallel vectors is a vector that is perpendicular to both of them.

Step-by-step explanation:

Answer:

87

Step-by-step explanation:

f(x)=19x+11

Let x = 4

f(4) = 19*4 +11

     =76 +11

     = 87

Answer:

[tex]f(x) = 19x + 11 \\ f(4) = 19 \times 4 + 11 \\ = 76 + 11 \\ = 87 \\ thank \: you[/tex]

Answer:

The answer is 2,157

Step-by-step explanation:

15,099÷7=2,157

Step-by-step explanation:

125cm = 1.25m.

2m : 1.25m = 8:5

Answer:

Srectangle: (3y+1)*25=75y+25(cm^2)

Step-by-step explanation:

Srectangle= w*L

Answer:

Step-by-step explanation:

Apply the natural log to both sides we have

[tex](-(2/3)x -1 ) \ln 2 = (3-2x)\ln 3\\-x(2/3)\ln 2 + 2x\ln 3 = 3\ln 3 -\ln 2\\x\left(\frac{-2}{3}\ln 2 +2\ln 3\right)=\ln (27/2)\\x\left(\ln 9 -\ln \sqrt{8}) =\ln(27/2)\\\\x\ln (9/\sqrt{8})=\ln(27/2)\\\\x= \ln(27/2) / \ln(9/\sqrt{8})[/tex]

Answer:

27

Step-by-step explanation:

Answer:

92170

I hope it's helps you

Answer:

10.89

Step-by-step explanation:

3.3 to the power of two is just saying 3.3 squared. which is just multiplying the number by itself.

so 3.3 times 3.3 = 10.89

Answer:

None of the above.

Step-by-step explanation:

Just subtract the functions

Answer:

a) 0.025£ b)3825£

Step-by-step explanation:

a) 5200-200=5000 - of the value will be lost after reaching the milleage of 200000 miles

200000-5000

1-x

200000=5000/x

x=5000/200000= 5/200=1/40=0.025£- the depreciation cost per mile

b)0.025*55000= 1375- the decreasing of the price

5200-1375=3825£- the book value of the car after it has driven 55000 miles

Answer:

The guitar's volume was amplified, but it was hard to hear the notes since it was so loud.

What word or phrase is a signal word that a context clue might be nearby to help determine the meaning of "amplified"?

Step-by-step explanation:

Answer:

x= –4/5 , x= 2

Step-by-step explanation:

5x²-6x-14=-6

5x² –6x –14 +6=0

5x²–6x –8=0

(5x+4)(x-2)=0

x=–4/5

x=2

Hi! I'm happy to help!

To solve this, we simply have to replace x with the given values.

First, we have -14, let's apply that:

(5·(-14²))-(6·(-14))-14=

Now, let's solve (using the order of operations):

(5·(-14²))-(6·(-14))-14=

(5·196)-(6·(-14))-14=

980-(6·(-14))-14=

980-(-84)-14=

980+84-14=

1064-14=

1050=

1050≠-6

Option 1 is incorrect.

Next, let's substitute 14 for x:

(5·14²)-(6·14)-14=

Now, let's solve:

(5·14²)-(6·14)-14=

(5·196)-(6·14)-14=

980-(6·14)-14=

980-84-14=

896-14=

880=

880≠-6

Option 2 is incorrect.

Now, let's substitute -7 for x:

(5·(-7²))-(6·(-7))-14=

Now, let's solve:

(5·(-7²))-(6·(-7))-14=

(5·49)-(6·(-7))-14=

245-(6·(-7))-14=

245-(-42)-14=

245+42-14=

287-14=

273=

273≠-6

Option 3 is incorrect.

Now, let's substitute 7 for x:

(5·7²)-(6·7)-14=

Now, let's solve:

(5·49)-(6·7)-14=

245-(6·7)-14=

245-42-14=

203-14=

189=

189≠-6

Option 4 is incorrect.

Now, let's substitute -2 for x, and solve:

(5·(-2²))-(6·(-2))-14=

(5·4)-(6·(-2))-14=

20-(6·(-2))-14=

20-(-12)-14=

20+12-14=

32-14=

18=

18≠-6

Option 5 is incorrect.

Now, let's substitute 2 for x and solve:

(5·2²)-(6·2)-14=

(5·4)-(6·2)-14=

20-(6·2)-14=

20-12-14=

8-14=

-6=

-6=-6

Option 6 is correct.

Now, let's substitute -1 for x and solve:

(5·(-1²))-(6·(-1))-14=

(5·1)-(6·(-1))-14=

5-(6·(-1))-14=

5-(-6)-14=

5+6-14=

11-14=

-3=

-3≠-6

Option 7 is incorrect.

Now, let's substitute 1 for x and solve:

(5·1²)-(6·1)-14=

5-(6·1)-14=

5-6-14=

-1-14=

-15=

-15≠-6

Option 8 is incorrect.

Now, let's substitute -4/5 for x and solve:

(5·(-4/5²))-(6·(-4/5))-14=

(5·0.64)-(6·(-4/5))-14=

3.2-(6·(-4/5))-14=

3.2-(-4.8)-14=

3.2+4.8-14=

8-14=

-6=

-6=-6

Option 9 is correct.

Now let's substitute 4/5 for x and solve:

(5·4/5²)-(6·4/5)-14=

(5·0.64)-(6·4/5)-14=

3.2-(6·4/5)-14=

3.2-4.8-14=

-1.6-14

-15.6

-15.6≠-6

Option 10 is incorrect.

To summarize, you should pick option 6, and option 9.

I hope this was helpful, keep learning! :D

Answer:

So, 23, 29, 31, 37, 41, 43 and 47 these are the prime numbers between 20 and 50.

Step-by-step explanation:

plz mark me brainliest

Answer:

So the prime numbers between 20 and 50 are so easy

- 23, 29, 31, 37, 41, 43 and 47

these are the prime numbers between 20 and 50

Step-by-step explanation:

Hope it helps

Answer: 3/20

Concept:

When encountering questions that ask for [how much longer A comparing to B], the basic operation would be the value of A subtracted by the value of B.

Solve:

Given information

Maggie study time = 2/5 hours

Julie study time = 1/4 hours

Given expression deducted from the concept

Maggie (study time) - Julie (study time)

Substitute values into the expression

2/5 - 1/4

Find the denominators' Least Common Multiple (LCM)

First five multiples of 5: 5, 10, 15, 20, 25

First five multiples of 4: 4, 8, 12, 16, 20

Since [20] is the first term that appears in both multiples, it would be the LCM of 4 and 5

Convert the fractions to common denominator

2/5 = (2 × 4) / (5 × 4) = 8 / 20

1/4 = (1 × 5) / (4 × 5) = 5 / 20

Simplify by subtraction

=8/20 - 5/20

=(8 - 5) / 20

=[tex]\boxed{\frac{3}{20} }[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

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