50 POINTS NO LINKS

An object is launched at 39.2 meters per second (m/s) from a 42.3-meter tall platform. The equation for the objects height s at time t seconds after launch is s(t)=-4.9t^2+39.2t+42.3, where s is in meters. Create a table of values and graph the function. Approximately what is the maximum height of the object?

Answer:

263.86cm²

Step-by-step explanation:

75/4 = 18.75

to find width = 18.75×1.5=28.13

to find length = 18.75×0.5=9.38

28.13×9.38=263.86cm²

Consider the numbers as, if we assume our first number to be x and second number being y, then from the given information we will be having the following equations :

[tex]{:\implies \quad \begin{cases}\sf 3x+3y=-12\\ \\ \sf 5x+2y=4\end{cases}}[/tex]

Now, rewrite the second equation as ;

[tex]{:\implies \quad \sf 3(x+y)=-12}[/tex]

Divide both sides by 3 ;

[tex]{:\implies \quad \sf x+y=-4\quad ---(i)}[/tex]

Now, consider the second equation of the above cases

[tex]{:\implies \quad \sf 5x+2y=4\quad ---(ii)}[/tex]

Now, multiply (i) by 2 on both sides :

[tex]{:\implies \quad \sf 2x+2y=-8\quad ---(iii)}[/tex]

Now, subtracting (ii) from (iii) will give us :

[tex]{:\implies \quad \sf 2x+2y-(5x+2y)=-8-4}[/tex]

[tex]{:\implies \quad \sf 2x+2y-5x-2y=-12}[/tex]

[tex]{:\implies \quad \sf -3x=-12}[/tex]

[tex]{:\implies \quad \boxed{\bf{x=4}}}[/tex]

Now, putting x = 4 in (i), will give y + 4 = -4, then solving for y will yield [tex]{\boxed{\bf{y=-8}}}[/tex]

Hence, we can conclude that :

[tex]{\quad \qquad \longrightarrow \begin{cases}\bf x=4\\ \\ \bf y=-8\end{cases}}[/tex]

Answer:

2 hours

Step-by-step explanation:

1/7 + 1/3 = 10/21

21/10= 2.1

Answer:

IT will lie in the quardant 1

because  want you to plot a point for "July 1963 was 63 degrees Fahrenheit" so that's in the positive temp region

so the correct option will be 1 and it is

D

Step-by-step explanation:

hope this helps

Answer:

Its going to be 79 degrees still because it doesnt change.

Step-by-step explanation:

.

Step-by-step explanation:

If 76° gives 7.5 meters, we must find out how many meters it is for 360°.

Find how much for 1°: [tex]\frac{7.5}{76}[/tex]

For 360°: [tex]\frac{7.5}{76} \times 360[/tex] = 35.53 meters

Answer:

50

Step-by-step explanation:

It is on edge

Answer:

it is counting 48 than going down

Step-by-step explanation:1,48

Answer:

convert the mixed fractions into decimals. do this by converting them into improper fractions and dividing the numerator by the denominator

Answer:

  278°

Step-by-step explanation:

You want the measure of arc RSQ given inscribed angle RSQ has a measure of 41°.

An inscribed angle has half the measure of the arc it subtends. This means short arc RQ will have double the measure of angle RSQ:

  arc RQ = 2 × 41° = 82°

The measure of long arc RSQ will complete the 360° circle:

  arc RSQ = 360° -arc RQ

  arc RSQ = 360° -82°

  arc RSQ = 278°

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Answer:

D. 638 in

Step-by-step explanation:

W+X+U+2Y+Z+V+T = 638

Answer:

if not 24.5, it should be 31 yds

Step-by-step explanation:

ok so, I don't know how you want me to solve this but, if you're asking the distance diagonally, then it will be 24.5 yds. If you want the distance in straight lines, it will be 31 yds

lol there wasn't much information, sorry

Answer:

B. Cube and E. hexahedron

Step-by-step explanation:

Icosahedron are made of triangles, cubes are made of squares, tetrahedron are made of triangles, octahedron are made of triangles, hexahedron are made of squares, dodecahedron are made of pentagons.

i hope it helps! Have a great day!

Sandra~

The total number of gallons of diesel Truck B used to travel 132 miles is 11.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

A dairy farmer uses two trucks to deliver milk. The two trucks use different kinds of fuel. Truck A uses gasoline and Truck B uses diesel.

From the given table we can see that

The total number of gallons of diesel Truck B used to travel 12 miles = 1

Number of gallons of diesel Truck B used to travel 1 mile = 1 /12

The total number of gallons of diesel Truck B used to travel 132 miles

= 1 /12 x 132

= 132 / 12

= 11

Thus, The total number of gallons of diesel Truck B used to travel 132 miles is 11.

Learn more about the unitary method;

https://brainly.com/question/23423168

#SPJ1

{1, 3, 5, 7, 9, 11, ... , 47}

To Write The Following in Set-builder notation

[tex] \text{A} = [/tex] {x : x ∈ N;x is an odd number, x ≤ 47}

Answer:

Step-by-step explanation:

We need to multiply each dimension by 3.

The base was 3*15 = 45

and the height = 3*9 = 27.

Answer:

$272

Step-by-step explanation:

9x7x12.5=787.5 120x7=840  38.95x7= 272.65 and she said to round to the nearest dollar so $272 dollars

Answer:

∠ 1 = 155° , ∠ 2 = 25°

Step-by-step explanation:

the 2 angles are adjacent angles and sum to 180° , that is

5x + x - 6 = 180

6x - 6 = 180 ( add 6 to both sides )

6x = 186 ( divide both sides by 6 )

x = 31

then

∠ 1 = 5x = 5(31) = 155°

∠ 2 = x - 6 = 31 - 6 = 25°

Answer:

-940.5

Step-by-step explanation:

Answer:

-940.5

Step-by-step explanation:

use pemdas

1.parenthesis

2.exponets

3.multiply

4.divide

5.add

6.subtract

Answer:

415ml

Step-by-step explanation:

there is 1000 ml in 1litre so the question says half which means 500 ml so if he drank 85ml then

500ml-85ml= 415 ml

Answer:

6 Cups of Flower

Step-by-step explanation:

First form a ratio
Cookies:Flour
60:4
Simplify
15:1
Since we now need to find the amount of cups for 90 cookies we must finds the amount of flower.
90:X
Using our old ratio of 15:1 we must divide 90/15 in order to get a factor to multiply 1 to make 15:1 equivalent to 90:X.
90/15 = 6 | 6 is the factor
15(6):1(6)

90:6

To find the volume of a rectangular prism:

  ⇒ must know the formula

        [tex]Volume = length * width * tall[/tex]

Let's convert all the known lengths into improper fractions if needed

Thus: [tex]Volume = \frac{14}{5} *2*\frac{3}{5} =\frac{84}{25}=3.36yd^3[/tex]

When rounded to the nearest tenth, the volume of the pool is 3.4 [tex]yd^3[/tex]

Hope that helps!

Answer: [tex]y=Ce^(^3^t^{^9}^)[/tex]

Step-by-step explanation:

Beginning with the first differential equation:

[tex]\frac{dy}{dt} =27t^8y[/tex]

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

[tex]\frac{1}{y} \frac{dy}{dt} =27t^8[/tex]

Multiply both sides by 'dt' to get:

[tex]\frac{1}{y}dy =27t^8dt[/tex]

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

[tex]\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt[/tex]

[tex]ln(y)=27(\frac{1}{9} t^9)+C[/tex]

[tex]ln(y)=3t^9+C[/tex]

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

[tex]e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)[/tex]

[tex]y=e^(^3^t^{^9} ^+^C^)[/tex]

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

[tex]y=e^(^3^t^{^9}^)e^C[/tex]

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

[tex]y=Ce^(^3^t^{^9}^)[/tex]

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

[tex]\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))[/tex]

[tex]\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)[/tex]

[tex]\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8[/tex]

Now check if the derivative equals the right side of the original differential equation:

[tex](Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)[/tex]

[tex]Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)[/tex]

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

Answer:

b is equal to 14 or higher

Step-by-step explanation:

[tex]\displaystyle \int (\sin 2x + \cos 2x)~ dx\\\\=\displaystyle \int \sin 2x ~dx + \displaystyle \int \cos 2x ~ dx\\\\=-\dfrac{\cos 2x}2 + \dfrac{\sin 2x}2 +C\\\\=\dfrac{\sin 2x - \cos 2x}2+C[/tex]

According to the given figures of triangle.. The value of x is 2.

Answer:

x = 3

Step-by-step explanation:

assuming the triangle is right.

using Pythagoras' identity

(x + 2)² = x² + 4²

x² + 4x + 4 = x² + 16 ( subtract x² from both sides )

4x + 4 = 16 ( subtract 4 from both sides )

4x = 12 ( divide both sides by 4 )

x = 3

Answer:

34.5 cm²

Step-by-step explanation:

The area of the shaded region is the area of the rectangle minus the area of the right triangle.

The area of the rectangle is simply the length 7 cm multiplied by the width 6 cm.

To find the area of the right triangle, you must first find the base and height of the triangle.

The two lengths can be found this way:

7 cm - 2 cm = 5 cm

6 cm - 3 cm = 3 cm

area of shaded region = LW - bh/2

area of shaded region = 7 cm × 6 cm - 5 cm × 3 cm / 2

area of shaded region = 42 cm² - 7.5 cm²

area of shaded region = 34.5 cm²