Using the z-distribution, the 95% confidence interval to describe the total percentage of registered voters who intend to vote for Steven Collins is:
D. (48.9%, 55.1%)
What is a confidence interval of proportions?A confidence interval of proportions is given by:
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which:
[tex]\pi[/tex] is the sample proportion.z is the critical value.n is the sample size.In this problem, we have a 95% confidence level, hence[tex]\alpha = 0.95[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.95}{2} = 0.975[/tex], so the critical value is z = 1.96.
The other parameters are given as follows:
[tex]\pi = 0.52, n = 1000[/tex]
Hence the bounds of the interval are given by:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.52 - 1.96\sqrt{\frac{0.52(0.48)}{1000}} = 0.489[/tex]
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.52 + 1.96\sqrt{\frac{0.52(0.48)}{1000}} = 0.551[/tex]
As a percentage, option D is correct.
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Need answers in 2 minutes ASAP
Step-by-step explanation:
f(10)=10
f(-2)=-2
f(a)=a
f(a+b)=a+b
g(10)=5×10-12=3
g(-2)=5×(-2)-12=-10-12=-22
g(a)=5×a-12=5a-12
g(a+b)=5×(a+b)-12=5a+5b-12
h(10)=(10)^2 +4(10)-7=100+40-7=133
h(-2)=(-2)^2 +4(-2)-7=4-8-7=-11
h(a)=a^2 +4a -7
h(a+b)=(a+b)^2 +4a+4b-7=a^2+2ab+b^2+4b-7
y=3x+2y is it a function how do you do it
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Answer:
yes
Step-by-step explanation:
Solve for y. You can do this by subtracting 3x+y from both sides of the equation.
y -(3x+y) = 3x +2y -(3x +y)
-3x = y
Or ...
y = -3x
Each value of x maps to a single value of y, so this relation is a function.
_____
This equation is a first-degree polynomial in x. Any polynomial relation y=p(x) is a function, so this is a function.
The area of a circle is 78.5 cm^2. What is the diameter of the circle?
-5 cm
-10 cm
-12.5 cm
-39.25 cm
Answer:
10cm
Step-by-step explanation:
78,5=pi.r^2
Answer5:
Step-by-step explanation:
Anyone’s knows how do this and the answer?
Answer:
12 -16. 19
4. 8. 22
3. -9. -4
Step-by-step explanation:
13-1 = 12
-10-6= -16
12 - -7 = 12+7=19
6-2 = 4
Keep subtracting
19. When the members of a high school club are
arranged in rows of 2, 3, or 4, there is one
person always left over. But when the club
members are arranged in rows of 5, no one is
left over. What is the least number of people
who could be in the club?
À 15 people
C 45 people
B 25 people D 85 people
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Answer:
B. 25 people
Step-by-step explanation:
The remainders tell you the number will be 1 more than some multiple of the least common multiple (LCM) of 2, 3, and 4. The LCM is 3·4 = 12, so we want some multiple (n) of that such that 12n+1 is a multiple of 5. We know this is the case for n=2.
The least number of people who could be in the club is 2·12+1 = 25.
7. What's the perimeter of a rectangle with length 12 m and width 5 m?
A. 60 m
B. 49 m
C. 34 m
D. 17 m
Answer:
Option(c) 34m
Step-by-step explanation:
Perimeter of a rectangle = 2(length + breadth)
length = 12m
breadth/width = 5m
Perimeter = 2(12 + 5)
= 2(17)
= 34m
Answer:
34
you just add, 12+5+12+5 to get 34
Problem 2
Find the area of each shaded region. Show or explain your reasoning.
A
2 cm
B
2 cm
2cm
6 cm
5 cm
3 cm
6 cm
8 cm
C С
D
15 cm
8 cm
8 cm
15 cm
9 cm
6 cm
10 cm
Step-by-step explanation:
A
this is the combination of a 4×6 rectangle and a 2×2 square. nothing is excluded.
so, the area is
(6-2)×6 + 2×2 = 4×6 + 4 = 24 + 4 = 28 cm²
B
this is the area of the large 8×5 rectangle minus the area of the small 2×3 rectangle.
so the area is
8×5 - 3×2 = 40 - 6 = 34 cm²
C
Basically the same thing as for B. large rectangle minus smaller rectangle.
so, the area is
15×10 - 9×6 = 150 - 54 = 96 cm²
D
the area of a triangle is
baseline × height / 2
or baseline here is 2×8, and the height is 5
so we get the area
2×8 × 5 / 2 = 8×5 = 40 cm²
QUESTION 1 11 How does the term quartile relate to how data values are grouped when using a five- number summory?
The Earth scientist most likely to study volcanoes is a (n)
A. Meteorologist
B. Geologist
C. Oceanographer
D. Astronomer
The answer is B Geologist
Answer:
geologist
Step-by-step explanation:
they work with the earths surface and natural land that changes
Identify which of the twelve basic functions listed below fit the description given.
y = x, y = x2, y = x3, y = , y = , y = ex, y = , y = ln x, y = sin x, y = cos x, y = int (x), y = 1/1+e-x
The two functions with infinitely many zeros
Try this option:
only periodical functions have many zeros, that is why y=sinx and y=cosx are the correct answer.
The functions y = x and y = x³ have infinitely many zeros. These functions pass through the origin and have a unique property that allows them to intersect the x-axis an infinite number of times.
The two functions with infinitely many zeros from the given list of twelve basic functions are y = x and y = x³
The function y = x has infinitely many zeros because any value of x that equals zero will result in y also being zero.
In other words, for every x value of 0, the corresponding y value is also 0.
This makes the function pass through the origin (0, 0) and have an infinite number of zeros.
2. The function y = x³ also has infinitely many zeros because the cube of any real number is zero if and only if the number itself is zero.
This means that for every x value of 0, the corresponding y value is also 0. Hence, the function y = x³ passes through the origin (0, 0) and has an infinite number of zeros.
In summary, the functions y = x and y = x³ have infinitely many zeros. These functions pass through the origin and have a unique property that allows them to intersect the x-axis an infinite number of times.
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Solve for x
ax+bx=10
Answer:
[tex]ax + bx = 10 \\ \\ x(a + b) = 10 \\ \\ x = \frac{10}{a + b} [/tex]
I hope I helped you^_^
A triangle has a perimeter of 75 inches. Find the length of three sides
if one side is 15 inches larger than the smallest side, and the third
side is twice the smallest
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Answer:
15 in, 30 in, 30 in
Step-by-step explanation:
Let x represent the length of the smallest side. Then the other two sides are (x+15) and (2x). The perimeter is the sum of the side lengths:
x +(x +15) +2x = 75
4x = 60
x = 15 . . . . . . . . . . . shortest side
(x+15) = 30 . . . . . . second side
(2x) = 30 . . . . . . . third side
The shortest side is 15 inches, the second side is 30 inches, and the third side is 30 inches.
[tex]\lim_{n \to \0}(x/(tan(x))^(cot(x)^2 )[/tex]
It looks like the limit you want to compute is
[tex]\displaystyle L = \lim_{x\to0}\left(\frac x{\tan(x)}\right)^{\cot^2(x)}[/tex]
Rewrite the limand with an exponential and logarithm:
[tex]\left(\dfrac{x}{\tan(x)}\right)^{\cot^2(x)} = \exp\left(\cot^2(x) \ln\left(\dfrac{x}{\tan(x)}\right)\right) = \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]
Now, since the exponential function is continuous at 0, we can write
[tex]\displaystyle L = \lim_{x\to0} \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right) = \exp\left(\lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]
Let M denote the remaining limit.
We have [tex]\dfrac x{\tan(x)}\to1[/tex] as [tex]x\to0[/tex], so [tex]\ln\left(\dfrac x{\tan(x)}\right)\to0[/tex] and [tex]\tan^2(x)\to0[/tex]. Apply L'Hopital's rule:
[tex]\displaystyle M = \lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)} \\\\ M = \lim_{x\to0}\dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)}[/tex]
Simplify and rewrite this in terms of sin and cos :
[tex]\displaystyle M = \lim_{x\to0} \dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)} \\\\ M= \lim_{x\to0}\dfrac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)}[/tex]
As [tex]x\to0[/tex], we get another 0/0 indeterminate form. Apply L'Hopital's rule again:
[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)} \\\\ M = \lim_{x\to0} \frac{\cos^4(x) - 3\sin^2(x)\cos^2(x) - \cos^2(x) + 2x\cos(x)\sin(x)}{2\sin^2(x)+4x\sin(x)\cos(x)}[/tex]
Recall the double angle identity for sin:
sin(2x) = 2 sin(x) cos(x)
Also, in the numerator we have
cos⁴(x) - cos²(x) = cos²(x) (cos²(x) - 1) = - cos²(x) sin²(x) = -1/4 sin²(2x)
So we can simplify M as
[tex]\displaystyle M = \lim_{x\to0} \frac{x\sin(2x) - \sin^2(2x)}{2\sin^2(x)+2x\sin(2x)}[/tex]
This again yields 0/0. Apply L'Hopital's rule again:
[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(2x)+2x\cos(2x)-4\sin(2x)\cos(2x)}{2\sin(2x)+4x\cos(2x)+4\sin(x)\cos(x)} \\\\ M = \lim_{x\to0} \frac{\sin(2x) + 2x\cos(2x) - 2\sin(4x)}{4\sin(2x)+4x\cos(2x)}[/tex]
Once again, this gives 0/0. Apply L'Hopital's rule one last time:
[tex]\displaystyle M = \lim_{x\to0}\frac{2\cos(2x)+2\cos(2x)-4x\sin(2x)-8\cos(4x)}{8\cos(2x)+4\cos(2x)-8x\sin(2x)} \\\\ M = \lim_{x\to0} \frac{4\cos(2x)-4x\sin(2x)-8\cos(4x)}{12\cos(2x)-8x\sin(2x)}[/tex]
Now as [tex]x\to0[/tex], the terms containing x and sin(nx) all go to 0, and we're left with
[tex]M = \dfrac{4-8}{12} = -\dfrac13[/tex]
Then the original limit is
[tex]L = \exp(M) = e^{-1/3} = \boxed{\dfrac1{\sqrt[3]{e}}}[/tex]
The sum of twice a number and three
Answer:
i dont get what youre asking
Step-by-step explanation:
Answer:
2n + 3
Step-by-step explanation:
n = number
Sum of twice a number (2n) and (3)
-> 2n + 3
find the value of a and b in (a,2)=(2,b)
Answer:
a=2 and b=2...............
3/6, 1/12, 3/6, 3/60 determine the lcd by division of prime number
Answer:
LCD = 60
BRAINLIEST, PLEASE!
Step-by-step explanation:
All of the denominator numbers are multiples of 60, and since 60 is also equal to the largest denominator number, it's the LCD.
Write a two-step equation and solve.
Four more than six times a number is 22
Five less than eleven times a number is 50
Seven less than nine times a number is -16
Step-by-step explanation:
1) let number=a
six times a number=6a
Condition:
6a+4=22
2) eleven times a number=11a
Condition:
11a-5=50
3) 9 times a number=9a
Condition:
9a-7=-16
Note:if you need to ask any question please let me know.
Which graph could represent a car that begins by increasing its speed, then travels at a constant speed, and then decreases its speed, as time increases?
A graph with time (minutes) on the horizontal axis and speed (miles per minute) on the vertical axis. Both axes are unnumbered. The speed begins at 0, goes up at first, is steady for a while, and then goes down over time.
A graph with time (minutes) on the horizontal axis and speed (miles per minute) on the vertical axis. Both axes are unnumbered. The speed begins in the middle of the vertical axis, goes down at first, is steady for a while, and then goes up over time.
A graph with time (minutes) on the horizontal axis and speed (miles per minute) on the vertical axis. Both axes are unnumbered. The speed begins at 0, goes up at first, goes down for a while, and then is steady over time.
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Answer:
A
Step-by-step explanation:
If you read your own question, you find that it answers itself.
The problem statement tells you that speed ...
... increasing its speed, constant speed, then decreases
And it tells you the graphs show ...
(a) begins at 0, goes up, is steady for a while, and then goes down
(b) begins in the middle, goes down, is steady, and then goes up
(c) begins at 0, goes up, goes down, and then is steady
___
The first graph has the increasing, steady, decreasing pattern you're looking for.
4 adults consumed food costing $60 for 3days. For the same food cost ,what would be the cost of food consumed by 7 adults for 5days?
Answer:
$175
Step-by-step explanation:
$60÷3÷4 =5
$5 is the cost of one adult's food for one day.
$5×7×5
=$175
$175 is the cost of food consumed by 7 adults for 5 days.
On solving equation 3*1/5b+5=50, the value of b will be?
Answer:
Step-by-step explanation:
14 1⁄16
Name the two input device
Answer:
keyboard and mouse are two examples of input device
Answer:
keyboard and mouse
Step-by-step explanation:
If you like my answer than please mark me brainliest
Consider the points below. P(â1, 4, 1), Q(0, 6, 2), R(4, 3, â1)
a. Find a nonzero vector orthogonal to the plane through the points P, Q, and R.
b. Find the area of the triangle PQR.
Answer:
B. Find the area of the triangle PQR.
After writing a $400 check to pay a bill, a student had a balance of $550 in his account. How much did he have in the account before he wrote the check?
a) Let x= his balance before writing the check. Write the equation you would use to solve this problem.
Answer:
x=950
Step-by-step explanation:
550+400=x
3cm and 7cm
please help me find the area and the perimeter of the above figures using the formular
Its must be a rectangle
Length=3cmBreadth=7cmPerimeter:-
[tex]\\ \sf\longmapsto 2(L+B)[/tex]
[tex]\\ \sf\longmapsto 2(3+7)[/tex]
[tex]\\ \sf\longmapsto 2(10)[/tex]
[tex]\\ \sf\longmapsto 20cm[/tex]
Area:-
[tex]\\ \sf\longmapsto Length\times Breadth[/tex]
[tex]\\ \sf\longmapsto 3(7)[/tex]
[tex]\\ \sf\longmapsto 21cm^2[/tex]
Answer:
Length=3cm
breadth=7cm
Area(A)=?
we know that,
Area of rectangle (A)=l*b
=3cm*7cm
= 21cm^2
Now,
Perimeter (P)= 2(l+b)
=2(3cm+7cm)
=2*10cm
=20cm Ans.
derivative : y=[(1+x^2)arctgx-x]/2
Answer:
s,-8*2-`±_'682-¥´owhsi
log base 4 (x+3)²- log base 4 y² = 0
Answer:
x = - |y| - 3
Step-by-step explanation:
divide write your answer in simplest form 2/3 divided by 1/4
Answer:
8/3 or 2.6667
Step-by-step explanation:
when you divide fractions you use a technique called KCF
K = keep
C = change
F = flip
You write the equation [tex]\frac{2}{3}[/tex] ÷ [tex]\frac{1}{4}[/tex]
you keep [tex]\frac{2}{3}[/tex]
you change the symbol, so from ÷ you change it to x
and flip the last fraction, so you would have [tex]\frac{4}{1}[/tex]
then you solve it
[tex]\frac{2}{3}[/tex] x [tex]\frac{4}{1}[/tex] = [tex]\frac{8}{3}[/tex]
The result of 2/3 divided by 1/4 in simplest form is 8/3 .
Division: It is one of the four basic mathematical operation, the other three being addition, subtraction, multiplication.
Given, division of [tex]\frac{2}{3}[/tex] by [tex]\frac{1}{4}[/tex].
Division of fractional terms:
[tex]=\dfrac{\frac{a}{b}}{\frac{c}{d}}\\= (a)\times(d)/(b)\times(c)[/tex]
Apply, division process of fractional terms.
[tex]=\dfrac{\frac{2}{4}}{\frac{1}{3}}\\ = (2)\times(4)/(1)\times(3)[/tex]
[tex]= \frac{8}{3}[/tex]
Know more about division,
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Solve the below:
4x+3y=7 3x-2y=9
Find the midpoint of the segment with the given endpoints. (-7,-4) and (3,7)?
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Answer:
(-2, 1.5)
Step-by-step explanation:
The coordinates of the midpoint are the average of the end point coordinates:
((-7, -4) +(3, 7))/2 = (-7+3, -4+7)/2 = (-4, 3)/2 = (-2, 1.5)
The coordinates of the midpoint are (-2, 1.5).
Select the correct answer.
Based on these segment lengths, which group of segments cannot form a triangle?
OA 12,7,8
OB. 8, 7, 13
OC. 1,2,3
OD. 80,140, 70
Reset
Next
2021 EdimentumAll rights
Answer:
C
Step-by-step explanation:
If you add up the length of two sides, the sum must be greater than the third side of the triangle.
If you add 1 and 2, it equals 3
But that means it will be equal to the length of the third side, 3
It will be impossible to make a triangle with those lengths of sides no matter how the sides or angles are set.
It's sort of difficult to explain this without any visual
You can look up "triangle inequality" to find out more about this