The initial sample had 0.010925 mol of Copper(II) oxide, or one mole.
What exactly is kinetic-molecular theory?The kinetic-molecular theory, which describes the states of matter, is based on the presumption that matter is composed of minuscule particles that are constantly in motion. This theory explains the observable properties and behaviours of solids, liquids, and gases. The container's walls and the quickly moving particles' collisions with one another are constant.
Copper(II) oxide + Sulfuric acid → Cupric sulfate + Water
One mole of Copper(II) oxide interacts with one mole of Sulfuric acid, as shown by the equation. The amount of Sulfuric acid that reacted with the Copper(II) oxide in the sample is therefore equal to the amount of Copper(II) oxide in the sample.
We must first determine how many moles of Sulfuric acid interacted with the sample:
moles Sulfuric acid = concentration × volume
moles Sulfuric acid = 0.437 mol/L × 0.025 L
moles Sulfuric acid = 0.010925 mol
Since the acid is in excess, the moles of Sulfuric acid remaining after treatment of the sample is:
moles Sulfuric acid remaining = moles Sulfuric acid added – moles Sulfuric acid reacted
moles Sulfuric acid remaining = 0.437 mol/L × 0.0354 L – 0.010925 mol
moles Sulfuric acid remaining = 0.007571 mol
To determine the number of moles of Copper(II) oxide in the original sample, we can use the following equation:
moles Copper(II) oxide = moles Sulfuric acid reacted = 0.010925 mol
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How many hydrogen molecules (h2) are needed to convert the triacylglycerol shown to saturated fat
The triacylglycerol depicted may be converted to a saturated fat by adding two hydrogen atoms (H2) to each carbon-carbon double bond. Six hydrogen atoms (H2) are required to convert the three carbon-carbon double bonds in triacylglycerol into saturated fat.
This is so that the triacylglycerol may be converted to a saturated fat by using hydrogen molecules (H2) to saturate the double bonds.
Triacylglycerol's physical characteristics, such as its melting point, will similarly be altered by the addition of hydrogen molecules (H2), making it more solid at normal temperature.
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A solution contains 0.0400 M Ca2+ and 0.0990 M Ag+. If solid Na3PO4 is added to this mixture, which of the phosphate species would precipitate out of solution first? Ca3(PO4)2
Ag3PO4
Na3PO4
When the second cation just starts to precipitate, what percentage of the first cation remains in solution?
When the second cation first starts to precipitate, 80.8% of Ca²⁺ will still be in solution.
What is cation?A cation is an ion with a positive charge. It is formed when an atom loses one or more of its electrons, resulting in a net positive charge. Cations are attracted to anions (ions with a negative charge) due to their opposite charges. Cations are found in many different substances, including acids, bases, and salts.
Ca₃(PO₄)₂ will be the first species that separates out of solution when solid Na₃PO₄ is introduced to the mixture. This is due to Ca3(PO4)2 having a substantially lower solubility than Ag₃PO₄ and Na₃PO₄.
The proportion of the first cation (Ca²⁺ ) still in solution when the second cation (Ag⁺) is just beginning to precipitate will depend on the starting concentrations of the two cations. In this instance, the starting concentrations of Ca²⁺ and Ag⁺ are 0.0400 M and 0.0990 M, respectively. Therefore, 80.8% of Ca²⁺ will still be in solution when its second cation first begins to precipitate.
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What is the S-P difference (sec)?
What is the amplitude (mm)?
What isthe distance (km)?
What is the magnitude (M)?
The S-P difference (sec) is the time gap between the arrival of the S-wave and the arrival of the P-wave at a seismic station. The S-P discrepancy is depicted in the figure as 20 seconds.
The amplitude (mm) of a seismic wave is the largest displacement from its resting point. The amplitude of the waves is not depicted in the image and cannot be calculated based on the information provided.
Distance (km): Using the S-P time difference and the known velocity of seismic waves, the distance from the seismic station to the earthquake epicenter may be determined. Seismic wave velocity is determined by the type of wave and the features of the Earth's interior. The velocity of P-waves in the Earth's crust, for example, is around 6 km/s. We may compute the distance to the epicenter using this value and the S-P difference of 20 seconds as follows:
Distance = Speed x Time = 6 km/h x 20 seconds = 120 kilometres
As a result, the distance between the seismic station and the earthquake epicenter is about 120 km.
The magnitude of an earthquake (M) is a measurement of the energy generated by the earthquake based on the amplitude of the seismic waves and the distance to the epicenter. Magnitude is commonly measured on a logarithmic scale, with each whole number reflecting a factor of ten increase in energy release.
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What concentration results from the dilution of 500.0 mL of 4.267 M to a volume of 1.85 L?
To calculate the concentration resulting from the dilution of 500.0 mL of 4.267 M to a volume of 1.85 L, we can use the equation:
M1V1 = M2V2
where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.
Plugging in the given values, we get:
4.267 M)(500.0 mL) = M2(1.85 L)
Simplifying this equation, we get:
M2 = (4.267 M)(500.0 mL) / (1.85 L)
M2 = 1.153 M
Therefore, the concentration resulting from the dilution is 1.153 M.
To calculate the concentration after dilution, you can use the dilution formula: C1V1 = C2V2, where C1 and V1 are the initial concentration and volume, and C2 and V2 are the final concentration and volume.
Given:
C1 = 4.267 M
V1 = 500.0 mL = 0.5 L (converted to liters)
V2 = 1.85 L
Now, find C2:
C2 = (C1 * V1) / V2
C2 = (4.267 M * 0.5 L) / 1.85 L
C2 ≈ 1.153 M
The concentration after dilution is approximately 1.153 M.
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To find the concentration resulting from the dilution, we can use the equation:
M1V1 = M2V2
where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration, and V2 is the final volume.
Plugging in the given values, we get:
(4.267 M)(500.0 mL) = M2(1.85 L)
Simplifying and converting units, we get:
M2 = (4.267 M)(500.0 mL) / (1.85 L)
M2 = 1.16 M
Therefore, the concentration resulting from the dilution is 1.16 M.
To find the concentration after dilution, you can use the dilution formula:
C1V1 = C2V2
where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Given:
C1 = 4.267 M
V1 = 500.0 mL (0.5 L)
V2 = 1.85 L
Rearrange the formula to solve for C2:
C2 = (C1V1) / V2
Now, plug in the given values:
C2 = (4.267 M * 0.5 L) / 1.85 L
C2 ≈ 1.154 M
So, the resulting concentration after dilution is approximately 1.154 M.
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Balloons for a New Years Eve party in Fargo, ND, are filled to a volume of 1.90 L at a temperature of 22.0 c and then hung outside. what is the volume of the balloon once they have cooled to the outside temperature of -34.0 c?
The volume of the balloon once they have cooled to the outside temperature of -34.0 c is 1.53 L.
Charles' law predicts the relationship between the volumes and the temperatures of a sample of an ideal gas at different conditions. For this equation to hold true, the number of molecules and the pressure must remain constant despite changes in the environment.
Determine the volume of the balloon outside, V2. We do this by applying Charles' law, such that we relate the volume, V, and the temperature, T, of a sample of gas as
V₁ /T₁ = V₂/ T₂
at two conditions. We are given the following values for the variables:
• V₁ = 1.90 L
T₁ = 22.0+ 273.15 = 295.15 K
T₂= 34.0+273.15= 239.15 K
We proceed with the solution.
V₁/T₁ = V₂/T₂
V₁ /T₁ × T₂ = V₂
1.90 L/295.15 K x 239.15 K = V₂
1.53 L =V₂
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The complete question is
Balloons for a New Year's Eve party in Fargo, ND, are filled to a volume of 1.90 L at a temperature of 22.0 degrees Celsius and then hung outside where the temperature is -34.0 degrees Celsius. What is the volume of the balloons after they have cooled to the outside temperature? Assume that atmospheric pressure inside and outside the house is the same.
2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)
If 538 mol
of octane combusts, what volume of carbon dioxide is produced at 31.0 ∘C
and 0.995 atm?
The volume of the carbon dioxide is produced at the 31.0 °C and the 0.995 atm is 119,786 L.
The number of moles of octane = 538 mol
The moles of carbon dioxide = 4888 mol
The temperature of the gas = 31.0 °C
The pressure of the gas = 0.995 atm
The volume of the gas = ?
The ideal gas equation is :
P V = n R T
Where,
The p is the pressure = 0.995 atm
The V is the volume = ?
The n is moles of gas = 4888 mol
The R is gas constant = 0.823 atm L / mol K
The T is temperature = 31 + 273 = 304 K
V = n R T / P
V = ( 4888 mol × 0.0823 × 304 ) / 0.995
V = 119,786 L
The volume is 119,786 L.
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Both chairs are the same size and have the same number of molecules. The diagram above shows the chairs before they touch.
How does the temperature of the bottom chair compare with the temperature of the top chair before the chairs touch? What will happen after the chairs have been touching for a while?
Before the chairs touch, the temperature of the bottom chair is lower than the temperature of the top chair, this is because the molecules in the bottom chair are in contact with a cooler surface.
After the chairs have been touching for a while, the heat will begin to transfer from the top chair to the bottom chair through a process called conduction. This will continue until the temperature of the two chairs equalizes, at which point there will be no more net heat transfer between them.
The final temperature of both chairs will be somewhere between the initial temperatures of the two chairs, and will depend on factors such as the thermal conductivity of the material, the size of the chairs, and the duration of the contact.
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A flexible container at an initial volume of 5.12 L
contains 8.51 mol
of gas. More gas is then added to the container until it reaches a final volume of 13.3 L.
Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.
Step-by-step Explanation:
8.51 moles is to 5.12 L as 'x' moles is to (13.3-5.12) L
8.51 moles / 5.12 L = x / ( 13.3-5.12)
x = 13.6 moles
If the average speed of an oxygen molecule is 4.37 ✕ 104 cm/s at 25°C, what is the average speed of a CO2 molecule at the same temperature?
The average speed of a gas molecule is proportional to the square root of its temperature and inversely proportional to the square root of its molar mass. Therefore, we can use the following equation to find the average speed of a CO2 molecule at the same temperature:
v2/v1 = sqrt(M1/M2)
where v1 and v2 are the average speeds of the oxygen and CO2 molecules, respectively, M1 and M2 are the molar masses of oxygen and CO2, respectively.
The molar mass of oxygen (O2) is 32 g/mol, and the molar mass of CO2 is 44 g/mol.
We are given that the average speed of an oxygen molecule is 4.37 × 10^4 cm/s at 25°C. We can convert the temperature to Kelvin by adding 273.15 to get:
T = 25°C + 273.15 = 298.15 K
Now we can solve for v2:
v2 = v1 * sqrt(M1/M2)
v2 = 4.37 × 10^4 cm/s * sqrt(32 g/mol / 44 g/mol)
v2 = 3.67 × 10^4 cm/s
Therefore, the average speed of a CO2 molecule at the same temperature is 3.67 × 10^4 cm/s.
Help!!!!!!!!!!!!!!!!!!!!!!!
All of the equation-related claims are not entirely true. The appropriate chemical formula should be:
Fe(OH)3 + 3NH4Cl = FeCl3 + 3NH4OH
Because the total mass of the reactants and products are equal, as well as the number of each type of atom in each of the reactants and products, mass is conserved in this balanced equation. Depending on the stoichiometric coefficients in the balanced equation, there may or may not be an equal amount of molecules in the reactants and products.
Iron(III) hydroxide (Fe(OH)3) and ammonium chloride (NH4Cl) are the products of the chemical reaction between iron(III) chloride (FeCl3) and ammonium hydroxide (NH4OH).
The coefficients (the numbers in front of the chemical formulae) must be changed to make sure that the number of each type of atom is the same on both sides of the equation in order to ensure that the equation is balanced. The coefficients in this instance are:
Fe(OH)3 + 3NH4Cl = FeCl3 + 3NH4OH
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Will we ever send humans to another planet? Most believe that if we were to travel to another planet, Mars would be the best option. Which of these would be a potential problem associated with travel to another planet?
Question 1 options:
we already know everything about Mars
no astronauts would ever volunteer for this mission
Mars has such a high gravity that it would crush humans and our spacecraft
the extended time for humans to be in space
A potential problem associated with travel to another planet is : the extended time for humans to be in space.
What is the potential problem associated with travel to another planet?It is highly likely that humans will travel to another planet, and Mars is currently considered the most viable option for human exploration. However, there are many potential problems associated with this endeavor, and one of the major issues is the extended time that humans would need to spend in space.
Traveling to Mars would take several months, and once there, astronauts would need to spend significant amount of time on planet before returning to Earth. This means that they would be exposed to high levels of radiation and would need to find ways to survive in harsh and unforgiving environment.
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1. Which is an example of heat being transferred through conduction?
2. 6 C (s) + 3 H2 → C6H12 (l)
ΔH = -903
Therefore, this reaction (loses/gains) heat/energy.
Answer:
9. B
10. Loses
Explanation:
9. Conduction is The procedure by which thermal energy or electricity is directly transported through a substance without the material moving when there is a variance in temperature between adjacent parts. Only choice B shows this process.
10. In exothermic reactions, energy/heat is lost. Exothermic reactions are characterized by a negative delta H, such as the delta H for the reaction show.
add a given instant what is the rate of appearance at this time
The rate of appearance of NOBr at the given time is 9.80 × [tex]10^-^4[/tex] M/s which is the second option as the question asks to determine the rate of appearance of NOBr, which is a product of the given chemical reaction, at the given time when the rate of disappearance of Br₂ is known.
For every 1 mole of Br₂ that disappears, 2 moles of NOBr appear. Thus, we can set up a proportion:
(2 mol NOBr / 1 mol Br₂) = (rate of appearance of NOBr / rate of disappearance of Br₂)
Substituting the given values,
(2 mol NOBr / 1 mol Br₂) = (rate of appearance of NOBr / 4.90 x [tex]10^-^4[/tex] M/s)
Solving for the rate of appearance of NOBr,
rate of appearance of NOBr = (2 mol NOBr / 1 mol Br₂) x (4.90 x [tex]10^-^4[/tex] M/s) = 9.80 × [tex]10^-^4[/tex]M/s
The rate of appearance of NOBr at the given time is 9.80 × [tex]10^-^4[/tex] M/s.
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Question 7 of 10
Which variable is unknown until the experiment is performed?
O A. A responding variable
OB. A mathematical variable
OC. A controlled variable
OD. A manipulated variable
SUBI
The mathematical variable is not a standard term in experimental design and is not typically used to describe variables in scientific experiments.
The variable that is unknown until the experiment is performed is typically the responding variable.
The responding variable is the variable that is observed and measured during the experiment, and its value changes in response to the manipulated variable. In contrast, the manipulated variable is the variable that is intentionally changed by the researcher to observe its effect on the responding variable.
The controlled variable is the variable that is kept constant throughout the experiment to ensure that any changes in the responding variable are due to the manipulated variable and not due to other factors. The mathematical variable is not a standard term in experimental design and is not typically used to describe variables in scientific experiments.
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5. The head of matches contains an oxidizing agent such as potassium chlorate, KCIO3, together with tetraphosphorus trisulfide, P4S3.
glass, and binder. When struck either by an obect or on the side of a box of matches, the phosphorus sulfide compound is easily
ignited, causing the potassium chlorate to decompose into potassium chloride and oxygen. The oxygen in turn causes the
phosphorus sulfide to burn more vigorously.
Determine the oxidation number of chlorine in potassium chlorate.
The oxidation number of the unknown chlorine in the compound is + 5
What is oxidation number?The oxidation number of an element in a compound is determined by a set of rules based on its position in the periodic table, as well as the charges of other atoms in the compound
We know that the oxidation number of the chlorine which we want to obtain would be designated as x and the total of the oxidation numbers of the elements in the compound is zero.
Thus we have that;
1 + x + 3(-2) = 0
1 + x - 6 = 0
-5 + x = 0
x = 5
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A platinum ring is composed of 2.35×1023 atoms. Calculate the mass of the ring in grams.
The mass of the platinum ring is 76.0 grams.
To calculate the mass of the platinum ringWe need to know the molar mass of platinum and the number of platinum atoms in the ring.
The molar mass of platinum (Pt) is 195.08 g/mol.
The number of platinum atoms in the ring is 2.35×10^23.
Now we can use the following formula to calculate the mass of the ring:
mass = (number of atoms) x (atomic mass) / Avogadro's number
where Avogadro's number is 6.022 x 10^23 mol^-1.
Substituting the values:
mass = (2.35×10^23 atoms) x (195.08 g/mol) / (6.022 x 10^23 mol^-1)
mass = 76.0 g
Therefore, the mass of the platinum ring is 76.0 grams.
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( + 0₂ (0₂ 1 Is the molecular mas of carbon is 12 and that of oxygen is 32, Calculate the mass of carbon dioxide formed when 24kg of carbon is burnt completely in oxygen and determine the heat thereby released in MJ if the complete combustion of 1kg of carbon releases 33.8MJ of heat
The mass of carbon dioxide formed when 24 kg of carbon is burnt completely in oxygen is 88 kg, and the heat released is 811.2 MJ.
What is Molar Mass?
Molar mass is the mass of one mole of a substance and is expressed in grams per mole (g/mol). It is calculated by adding up the atomic masses of all the atoms in a molecule or formula unit of a compound. The molar mass is used in stoichiometry calculations to convert between mass and moles of a substance.
The balanced equation for the combustion of carbon is:
C + O₂ → CO₂
From the equation, we can see that one mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide. The molar mass of carbon dioxide is 12 + (2 × 16) = 44 g/mol.
First, let's find the number of moles of carbon in 24 kg:
n(C) = m/M = 24000 g / 12 g/mol = 2000 mol
Therefore, 2000 mol of CO₂ will be produced.
The mass of CO₂ produced can be calculated as:
m(CO₂) = n(CO₂) × M(CO₂) = 2000 mol × 44 g/mol = 88,000 g = 88 kg
Now, let's calculate the heat released during combustion:
Heat released = 33.8 MJ/kg × 24 kg = 811.2 MJ
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What is the net ionic charge of an oxygen ion ?
Can someone help me ?
The problem requires the calculation of the volume of carbon dioxide produced at STP when 587 mol of octane combusts; ,therefore, the volume of CO₂ produced at 36.0 °C and 0.995 atm is approximately 124,700 L.
The ideal gas law is given by:
PV = nRT
P is the pressure in atm, V is the volume in L, n is the number of moles, R is the gas constant (0.0821 L·atm/mol·K), and T is the temperature in K.
587 mol octane × (16 mol CO₂/2 mol octane) = 4696 mol CO2
Next, one can use the ideal gas law to calculate the volume of CO₂ produced at 36.0 °C and 0.995 atm. Then one needs to convert the temperature to kelvin by adding 273.15:
T = 36.0 °C + 273.15 = 309.15 K
Substituting the values into the ideal gas law:
PV = nRT
V = nRT/P
V = (4696 mol)(0.0821 L·atm/mol·K)(309.15 K)/(0.995 atm)
V ≈ 124,700 L
Therefore, the volume of CO2 produced at 36.0 °C and 0.995 atm is approximately 124,700 L.
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If heat is going INTO the system, that means that energy must have come OUT FROM the ____________
If heat is going into a system, it means that energy must have come out from the surroundings.
How is energy/heat transferred?Heat is a form of energy transfer from a hotter object to a cooler one, and the direction of heat flow is always from the hotter object to the cooler one.
Therefore, if heat is entering a system, it must be gaining energy from its surroundings, which are at a lower temperature and therefore have less thermal energy.
Conversely, if heat is leaving a system, it means that energy is being transferred from the system to its surroundings, which are at a higher temperature and therefore have more thermal energy.
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How many grams of zinc chloride would be formed if 77.1 grams of zinc reacts?
Zn + HCl -->ZnCl2 + H2
The amount of zinc chloride that would be formed if 77.1 grams of zinc reacts is approximately 160.77 grams
To determine how many grams of zinc chloride ([tex]ZnCl_2[/tex]) would be formed if 77.1 grams of zinc (Zn) reacts, we'll use stoichiometry.
First, we need the molar masses of the substances involved:
Zn: 65.38 g/mol
[tex]ZnCl_2[/tex] : 136.29 g/mol
Now, we'll convert grams of Zn to moles:
77.1 g Zn × (1 mol Zn / 65.38 g Zn) = 1.179 moles Zn
According to the balanced chemical equation, 1 mole of Zn reacts to form 1 mole of [tex]ZnCl_2[/tex]:
1.179 moles Zn × (1 mol ZnCl₂ / 1 mol Zn) = 1.179 moles ZnCl₂
Finally, convert moles of ZnCl₂ to grams:
1.179 moles ZnCl₂ × (136.29 g ZnCl₂ / 1 mol ZnCl₂) ≈ 160.77 g ZnCl₂
So, approximately 160.77 grams of zinc chloride would be formed if 77.1 grams of zinc reacts.
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If you mix 30 mL of cold water with 70 mL of hot water in a calorimeter, then calculate that the cold water gained 142 J of heat and the hot water lost 181 J of heat, and the temperature change of the cold water (and calorimeter) was an increase in 1.93°C, then what is the heat capacity of the calorimeter in J/°C (only enter the number, not units, and assume that no heat was lost to the environment around the calorimeter, assume the density of water to be 1.00g/mL and specific heat capacity of water to be 4.184 J/g-°C)?
First, we need to calculate the heat gained by the cold water and the heat lost by the hot water:
Qcold = mcΔT = (30 g)(4.184 J/g-°C)(1.93°C) = 242.06 J
Qhot = mcΔT = (70 g)(4.184 J/g-°C)(-1.93°C) = -546.53 J
Since energy is conserved, we can assume that the heat gained by the cold water and calorimeter is equal to the heat lost by the hot water:
Qcold + Qcalorimeter = Qhot
Qcalorimeter = Qhot - Qcold
Qcalorimeter = -546.53 J - 242.06 J = -788.59 J
Therefore, the heat capacity of the calorimeter can be calculated as:
Ccalorimeter = Qcalorimeter / ΔT
Ccalorimeter = (-788.59 J) / (1.93°C)
Ccalorimeter ≈ -408.4 J/°C
Note that the negative sign indicates that the calorimeter loses heat when the system gains heat, which is expected since the calorimeter is absorbing some of the heat from the hot water.
PLEASE HELP!!
351.6g of Chromium-63 is allowed to decay for 128.8 years, how much Chromium-63
is left? (The half life of 63 Cr is 32.2 days.) Please, enter your answer as a one decimal
place number with no units.
A crucial trace mineral is chromium. Trivalent chromium, which is safe for people, and hexavalent chromium, which is toxic, are the two types.
Thus, Foods and dietary supplements both contain trivalent chromium. It might assist maintain normal blood sugar levels by enhancing the body's utilization of mineral.
Chromium is used by people to treat deficiencies. Additionally, it is used to treat bipolar disorder, diabetes, high cholesterol, and a variety of other conditions, but the majority of these uses are not well-supported by science.
Chromium by mouth doesn't help control blood sugar levels in people with prediabetes. Schizophrenia. Taking chromium by mouth doesn't affect weight or mental health in people with schizophrenia.
Thus, A crucial trace mineral is chromium. Trivalent chromium, which is safe for people, and hexavalent chromium, which is toxic, are the two types.
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3. Litharge, Pb0, is an ore that can be roasted (heated) in the presence of carbon monoxide, CO, to produce elemental lead. The
reaction that takes place during this roasting process is represented by the balanced equation below.
PbO(s) + CO(g) → Pb(s) + CO₂(g)
In which compound does carbon have the greater oxidation number
Answer:
Explanation:
In the given reaction, carbon has a greater oxidation number in carbon dioxide (CO₂) than in carbon monoxide (CO). In CO₂, the oxidation number of carbon is +4, while in CO it is +2.
A 192 gram piece of copper was heated to 100.°C in a boiling water bath, then it was dropped into a beaker containing 850. mL of water at 4.00°C. What is the final temperature of the copper and water after they come to thermal equilibrium?
Note: The specific heat of copper is 0.385 J/g °C.
Do not round your answer in the middle of the problem. Round at the very end.
Round your answer to the correct number of sig figs. Your units should be degrees Celsius.
The final temperature of the copper and water after they come to thermal equilibrium is 109.8°C.
What is temperature?Temperature is a measure of the amount of thermal energy present in a substance or object. It is measured in degrees on a scale such as Fahrenheit, Celsius, or Kelvin. Temperature is important in determining the physical and chemical properties of a substance, such as its melting point, boiling point, and specific gravity. Temperature also affects the rate of a chemical reaction and the speed of diffusion.
The change in temperature of the copper can be calculated using the equation
ΔT = (Q/mc), where Q is the heat transferred, m is the mass of the copper, and c is the specific heat of copper.
Q = mcΔT = (192 g)(0.385 J/g °C)(100°C) = 74080 J
The heat transferred from the copper must equal the heat transferred to the water. Therefore,
(74080 J) = (0.85 L)(4.184 J/g°C)(ΔT)
ΔT = (74080 J)/[(0.85 L)(4.184 J/g°C)] = 109.8°C
The final temperature of the copper and water after they come to thermal equilibrium is 109.8°C.
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Balance:
2. K₂O + H₂O → KOH
3.F₂ +NaBr-NaF + Br₂
4.Ba(CIO3) → BaCl2 + O2
*
5.SrBr₂ + (NH4)2CO3 → SrCO3 + NH4Br
6. C8H18 + O₂ → CO₂ + H₂O
What is the reactions to these?
the balanced equation and there reactions are as follow:
K₂O + H₂O → 2KOH
The reaction between potassium oxide and water produces potassium hydroxide (KOH).
F₂ + 2NaBr → 2NaF + Br₂
The reaction between fluorine gas and sodium bromide produces sodium fluoride and bromine.
2Ba(CIO3)₂ → 2BaCl₂ + 3O₂
The decomposition of barium chlorate produces barium chloride and oxygen gas.
SrBr₂ + (NH₄)₂CO₃ → SrCO₃ + 2NH₄Br
The reaction between strontium bromide and ammonium carbonate produces strontium carbonate and ammonium bromide.
C₈H₁₈ + 12O₂ → 8CO₂ + 9H₂O
The combustion of octane with oxygen produces carbon dioxide and water.
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What is the difference between collecting and analysing data
Answer:
Data collection is the act of obtaining information from diverse sources, and data analytics is the process of processing that information to derive practical insights.
Explanation:
NaOH is the limiting reactant, producing
2.0 mol Na3PO4. What mass of
Na3PO4 forms during the reaction?
Na3PO4: 164 g/mol
[?] g Na3PO4
Report your answer to two significant figures.
g Na PO
4
Enter
The mass of Na₃PO₄ formed during the reaction is 328 g.
The balanced chemical equation for the reaction is:
[tex]3NaOH + Na_3PO_4 - > 3Na_2PO_4 + H_2O[/tex]
From the equation, we can see that 3 moles of NaOH produce 1 mole of Na₃PO₄.
Given that 2.0 moles of Na₃PO₄ is produced, we can set up a proportion to find the amount of NaOH required:
3 mol NaOH / 1 mol Na₃PO₄ = x mol NaOH / 2.0 mol Na3PO4
Solving for x, we get:
x = (3 mol NaOH / 1 mol Na₃PO₄) × (2.0 mol Na₃PO₄ / 1) = 6.0 mol NaOH
So, 6.0 moles of NaOH are required to produce 2.0 moles of Na₃PO₄.
To find the mass of Na₃PO₄ produced, we can use its molar mass:
mass = moles × molar mass = 2.0 mol × 164 g/mol = 328 g
Therefore, the mass of Na₃PO₄ formed during the reaction is 328 g.
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Strychnine, a deadly poison, has a molecular mass of 334 g/mol and a percentage composition of 75.45% carbon, 6.59% hydrogen, 8.38% nitrogen, and the balance oxygen. What is the molecular formula of strychnine?
The molecular formula of the strychnine, given that it is composed of 75.45% carbon, 6.59% hydrogen, 8.38% nitrogen, and the balance oxygen is C₂₁H₂₂N₂O₂
How do i determine the molecular formula?First, we shall obtain the empirical formula of compound. Details below:
Carbon (C) = 75.45%Hydrogen (H) = 6.59%Nitrogen (N) = 8.38%Oxygen (O) = 100 - (75.45 + 6.59 + 8.38) = 9.58%Empirical formula =?Divide by their molar mass
C = 75.45 / 12 = 6.2875
H = 6.59 / 1 = 6.59
N = 8.38 / 14 = 0.5986
O = 9.58 / 16 = 0.59875
Divide by the smallest
C = 6.2875 / 0.5986 = 10.5
H = 6.59 / 0.5986 = 11
N = 0.5986 / 0.5986 = 1
O = 0.59875 / 0.5986 = 1
Multiply through by 2 to express in whole number
C = 10.5 × 2 = 21
H = 11 × 2 = 22
N = 1 × 2 = 2
O = 1 × 2 = 2
Thus, we can conclude that the empirical formula is C₂₁H₂₂N₂O₂
Now, we shall determine the molecular formula of strychnine. Details below
Empirical formula = C₂₁H₂₂N₂O₂Molar mass of compound = 334 g/molMolecular formula =?Molecular formula = empirical × n = mass number
[C₂₁H₂₂N₂O₂]n = 140.22
[(12×21) + (1×22) + (14×2) + (16×2)]n = 334
334n = 334
Divide both sides by 334
n = 334 / 334
n = 1
Molecular formula = [C₂₁H₂₂N₂O₂]n
Molecular formula = [C₂₁H₂₂N₂O₂]1
Molecular formula = C₂₁H₂₂N₂O₂
Thus, we can conclude that the molecular formula of strychnine is C₂₁H₂₂N₂O₂
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The Environmental Protection Agency was assigned which task? A. setting standards and governing the cleanliness of water used by Americans B. setting standards and governing the highways and interstates in the United States C. setting standards and governing the use of national parks and monuments in the United States. D. setting standards and governing the civil and commercial air transportation throughout America
Answer:
A. setting standards and governing the cleanliness of water used by Americans
Explanation:
The responsibilities of the Environmental Protection Agency (EPA) is to make sure that:
People in America should have clean air, water, and good quality soil so that land is fertile.Using Scientific information to come up with efforts on a national level and reduce risks to the environment.A fair and effective administration of federal laws centered around the protection of human health and our environment.