The equation that best represents the linear relationship between the total amount Mrs. Jacobs will be charged and the number of children attending the skating party is y = mx + b.
In this case, y represents the total amount in dollars that Mrs. Jacobs will be charged, x represents the number of children attending the party, m represents the slope of the line, and b represents the y-intercept.
To find the equation, we need to determine the slope and y-intercept from the table given. From the table, we can see that for every additional child attending the party, the total amount charged increases by $10. This means that the slope (m) of the line is 10.
To find the y-intercept (b), we can look at the table and see that when there are zero children attending the party, the total amount charged is $50. This means that the y-intercept is 50.
Putting it all together, the equation that best represents the linear relationship is y = 10x + 50.
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David’s net worth is 45,765. 78 and his assets have a value of 62,784,24 if his assets increase by 2,784. 89 and his liabilities decrease y 3,742. 36 what is his net worth
David's net worth: 86,329.95
To calculate David's new net worth, we need to add the increase in assets and subtract the decrease in liabilities from his current net worth.
New assets value = 62,784.24 + 2,784.89 = 65,569.13
New liabilities value = David's current net worth - his current assets value
New liabilities value = 45,765.78 - 62,784.24 = -17,018.46
Since his liabilities have decreased by 3,742.36, we need to subtract this value from the new liabilities value:
New liabilities value = -17,018.46 - 3,742.36 = -20,760.82
Now we can calculate his new net worth by subtracting his new liabilities value from his new assets value:
New net worth = 65,569.13 - (-20,760.82) = 86,329.95
Therefore, David's new net worth is 86,329.95.
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4) Write the rule for the reflection shown below.
The rule for the reflection shown above is (x, y) → (x, -y).
What is a reflection over the x-axis?In Mathematics and Geometry, a reflection over or across the x-axis is represented by this transformation rule (x, y) → (x, -y).
This ultimately implies that, a reflection over or across the x-axis would maintain the same x-coordinate while the sign of the y-coordinate changes from positive to negative or negative to positive.
Conversely, a reflection over or across the y-axis would maintain the same y-coordinate while the sign of the x-coordinate changes from positive to negative or negative to positive.
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Larijah is creating a circular board game with a spinner with four regions that players use to determine what happens on their turns. she wants to meet these requirements: - exactly a quarter of the circle should contain the ""lose a turn"" region. - ""move one space"" should be three times the angle as ""move two spaces"". - ""move two spaces"" should be twice the angle as ""trade places with any opponent"". what is the measure of the ""trade places with any opponent"" region?
The measure of the trade places with any opponent region is 30°
Let the measure of the trade places with any opponent = x
Move two space is twice the angle as trade places with any opponent
Move two space = 2x
Move one space is three times the angle as moving two spaces
Move one space = 3(2x)
Move one space = 6x
Lose your turn is a quarter
Lose your turn = 90°
The sum of a complete angle = 360°
90 + x + 2x + 6x = 360°
9x = 360 - 90
9x = 270
x = 30
The measure of the trade places with any opponent region is 30°
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A large apartment complex has 1,500 units, which are filling up at a rate of 10% per month. If the
apartment complex starts with 15 occupied units, what logistic function represents the number of
units occupied over time?
ON(t)
1500
1+114e-0. 101
ON(t)
800
1+114e-0. 101
N(t)
800
1+99e-0. 100
N(t)
1500
1+99e-0. 101
The logistic function that represents the number of units occupied over time is given by:
[tex]N(t) = (K / (1 + A * e^(-r*t))),[/tex]
where N(t) is the number of units occupied at time t, K is the carrying capacity (maximum number of units that can be occupied),
A is the initial amount of units occupied, r is the growth rate, and e is the base of the natural logarithm.
In this case, the carrying capacity K is 1500 units, and the initial amount of occupied units A is 15 units. The growth rate r can be calculated as follows:
[tex]r = ln((10%)/(100% - 10%)) = ln(0.1/0.9) ≈ -0.101[/tex]
Substituting the given values into the logistic function, we get:
[tex]N(t) = (1500 / (1 + 15 * e^(-0.101*t)))[/tex]
Simplifying further, we get:
[tex]N(t) = (100 / (1 + e^(-0.101*t))) + 15[/tex]
Therefore, the logistic function that represents the number of units occupied over time is:
[tex]N(t) = (100 / (1 + e^(-0.101*t))) + 15[/tex], where t is measured in months.
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What is your net pay after FICA has been taken out if you make $47,000?
Remember that FICA is 7.65%
Answer:
3595.5
Step-by-step explanation:
I used the foil method to expand this but I don’t know what to do after that… a little help?
The expansion of (1+root 2)(3-root 2) is 1 +2√2.
What is distributive property?
The distributive Property states that it is necessary to multiply each of the two numbers by the factor before performing the addition operation when a factor is multiplied by the sum or addition of two terms.
Apply the distributive property
1(3-√2) + √2(3-√2)
Apply distributive property
1.4+ 1(-√2) +√2 (3-√2)
Apply the distributive property
1.3 + 1(-√2) + √2. 3+√2 (-√2)
3+1(−√2)+√2⋅3+ √2(-√2)
Multiply − √2 by 1
3−√2+ √2⋅3+√2(−√2)
Move 3 to the left of √2.3−√2+3⋅√2+√2(−√2)
Multiply √2(−√2)
3−√2+3√2−√2²
Rewrite
√2² as 2.
3−√2+3√2− 1⋅2
Multiply − 1 by 2.
3−√2+3√2−2
Subtract 2 from 3.
1−√2+3√2
Add −√2 and 3√2.
1+2√2
Exact Form:
1 +2√2
Decimal Form:
3.82842712
Therefore, the expansion of (1+root 2)(3-root 2) is 1 +2√2.
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Find the distance between
the points (4, -3) and (-2, 1)
on the coordinate plane.
Ay
O
X
Answer:no image
Step-by-step explanation:
Consider the variable coefficient linear second order non-homogeneous ODE
x^2y^n - 2xy' + (x^2 +2)y =. 3x^3, for x > 0
Write down the associated homogeneous equation.
x²y' - 2xy' + (x² + 2)y = 0 is the associated homogeneous equation with non-homogeneous ODE x²yⁿ - 2xy' + (x² +2)y = 3x³.
It should be noted that the equation is same as the variable coefficient linear second order non-homogeneous ODE but just the right side zero.
The complementary solutions or homogeneous solutions to this homogeneous equation serve as the foundation for the space of all solutions to the non-homogeneous equation.
By assuming that y has the form y(x) = xr and substituting this into the homogeneous equation to create a characteristic equation, we can determine the complementary solutions. We may find the values of r that correspond to solutions of the type y(x) = xr by looking at the characteristic equation's roots.
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Once Farid spends 15 minutes on a single level in his favorite video game, he loses a life. He has already spent 10 minutes on the level he's playing now.
Let x represent how many more minutes Farid can play on that level without losing a life. Which inequality describes the problem?
A. 10 + x > 15
B. 10 + x < 15
Solve the inequality. Then, complete the sentence to describe the solution.
Farid can play less than _______ more minutes on that level without losing a life
The correct inequality to describe the problem is A. 10 + x > 15, which means that the total time Farid spends on the level (10 + x) must be greater than 15 minutes in order for him to lose a life.
To solve the inequality, we can start by isolating x on one side of the inequality:
10 + x > 15
Subtracting 10 from both sides, we get:
x > 5
This means that Farid can play for up to 5 more minutes on the level without losing a life, since spending a total of 10 + 5 = 15 minutes on the level would cause him to lose a life.
Therefore, the solution to the inequality is "Farid can play less than 5 more minutes on that level without losing a life."
Overall, the correct option is A. 10 + x > 15.
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For Items 6-10, the height of an object, in centimeters, is modeled by the function y = 42sin (π/10 (x-h)+ 55. Determine whether each statement is always, sometimes, or never true.
6. The period of the function is 20.
7. The maximum height of the object is 55 centimeters
8. The minimum height of the object occurs when x=0
9. The graph of the function has the midline y= 55
10. The amplitude of the function is 84.
Answer:
It's fascinating to observe how the volume of different shapes can vary based on their measurements. For instance, a cylinder with a height of 6 centimeters and radius r1 has a volume of 302 cubic centimeters. Do you require further assistance?
As for the new set of instructions, please consider the following statements:
6. Sometimes true. The period of the function is determined by the formula T= 2π/b, where b is the coefficient of x in the argument of the sine function. In this case, b = π/5, so T= 10.
7. Always true. The maximum height of the object is equal to the amplitude of the function plus the vertical shift, which is 55 centimeters.
8. Sometimes true. The minimum height of the function occurs when the sine function has a value of -1, which happens at x= h-5. So, if h= 0, then x= -5, which means the statement is sometimes true depending on the value of h.
9. Always true. The midline of the function is determined by the vertical shift, which is 55 in this case.
10. Always true. The amplitude of the function is given by A= |b|, where b is the coefficient of x in the argument of the sine function. In this case, A= 42π/5, which simplifies to 84.
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Jerome wants to buy grass seed to cover his whole lawn, except for the pool. the pool is 4 5/6 m by 2 1/3 m. find the area the grass seed needs to cover.
Jerome will need approximately 138.72 square meters of grass seed to cover his lawn.
To find the area that the grass seed needs to cover, we first need to find the area of the entire lawn. Let's assume that the lawn is rectangular in shape.
Jerome hasn't given us the dimensions of the lawn, so let's say that it measures 10 meters by 15 meters. Therefore, the area of the entire lawn would be:
10 meters x 15 meters = 150 square meters
Now we need to subtract the area of the pool from the area of the entire lawn.
The pool measures 4 5/6 meters by 2 1/3 meters, which we can convert to improper fractions:
4 5/6 = (4 x 6 + 5) / 6 = 29 / 6
2 1/3 = (2 x 3 + 1) / 3 = 7 / 3
So the area of the pool would be:
29/6 meters x 7/3 meters = 203/18 square meters
To find the area that the grass seed needs to cover, we subtract the area of the pool from the area of the entire lawn:
150 square meters - 203/18 square meters
To subtract these two values, we need to get a common denominator:
150 square meters = (150 x 18) / 18 = 2700/18 square meters
203/18 square meters = 203/18 square meters
So the area that the grass seed needs to cover would be:
2700/18 square meters - 203/18 square meters = 2497/18 square meters
We can simplify this fraction by dividing the numerator and denominator by their greatest common factor, which is 1:
2497/18 square meters ≈ 138.72 square meters
Therefore, Jerome will need approximately 138.72 square meters of grass seed to cover his lawn, excluding the area around the pool.
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A theater is selling tickets to a ''preview night'' of their new musical. The tickets cost $12 per adult and $7. 50 per child. Due to limit on seating, they can sell no more than 150 tickets. However, they would like to make at least $675 from ticket sales
it's not possible to sell at least $675 worth of tickets while also staying within the seating limit of 150 tickets. The theater may need to consider raising ticket prices or finding a larger venue to accommodate more audience members.
Let's denote the number of adult tickets sold as "A" and the number of child tickets sold as "C". Then we can set up the following system of equations to represent the given information:
A + C ≤ 150 (limit on seating)
12A + 7.5C ≥ 675 (minimum revenue required)
We want to find the possible values of A and C that satisfy these equations.
One way to solve this system is to graph the inequalities and find the region of overlap. However, since there are only two variables, we can also use substitution or elimination to solve for one variable in terms of the other.
Let's solve for A in terms of C using the first equation:
A ≤ 150 - C
Substitute this expression for A in the second equation:
12(150 - C) + 7.5C ≥ 675
Expand and simplify:
1800 - 12C + 7.5C ≥ 675
-4.5C ≥ -1125
C ≤ 250
So the number of child tickets sold must be less than or equal to 250.
Now we can substitute this inequality into the first equation to find the maximum number of adult tickets sold:
A + 250 ≤ 150
A ≤ -100
This doesn't make sense, since we can't sell negative tickets. Therefore, there is no solution that satisfies the given conditions.
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Find the value of k. Give your answer in degrees ().
k
84°
Not drawn accurately
Step-by-step explanation:
I had to add some assumed portions to your posted picture. See image.
The yellow boxed angle is 84 degrees (upper LEFT) due to alternate interior angles of parallel lines transected by another line.
then, since the triangle is isosceles ....the other (lower LEFT) angle is 84 degrees also....
that means that k= 12 degrees for the triangle interior angles to sum to 180 degrees .
answer please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
9/7
explain:
(36-27) 7
9/7
54/g - 8 when g = 6 and h=3
The value of the simplified expression is -15.
What is the simplification of the expression?
The simplification of the expression is determined by substituting the appropriate values of the variables into the equation.
The given expression; = 54/g - 8h
The value of g = 6 and the value of h = 3,
The value of the expression is calculated as follows;
= 54/g - 8h
= 54/6 - 8(3)
= 9 - 24
= - 15
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The complete question is below:
54/g - 8h, when g = 6 and h=3
What is the volume of the composite figure if both the height and the diameter of the cylinder are 2. 5 feet? Give the exact answer and approximate to two decimal places.
Thank you!
19.29 cubic feet is the volume of the composite figure if both the height and the diameter of the cylinder are 2. 5 feet
Without knowing the specific shape of the composite figure, it is impossible to give an exact answer. However, we can provide a general formula for the volume of a cylinder with height h and diameter d, and assume that the composite figure consists of a cylinder and some other shape.
The volume of a cylinder is given by the formula V = πr^2h, where r is the radius of the cylinder. The diameter of the cylinder is given as 2.5 feet, which means the radius is 1.25 feet.
If the height of the cylinder is also 2.5 feet, then the volume of the cylinder is:
V_cylinder = π(1.25)^2(2.5) = 6.15π cubic feet (exact)
To approximate to two decimal places, we can use the approximation π ≈ 3.14:
V_cylinder ≈ 6.15(3.14) = 19.29 cubic feet (approximate to two decimal places)
However, since we do not know the specific shape of the composite figure, we cannot give an exact answer for its volume.
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Michelle has four credit cards with the balances and interest rates listed below. She wants to pay off her credit
cards one at a time, based on the interest rate. In which order should Michelle pay off her credit cards?
>>>>>a. 3,2,1,4<<<<
b. 1,2,3,4
c. 2,4,3,1
d. 4,1,3,2
Answer:
a) 3, 2, 1, 4
Step-by-step explanation:
If you have multiple credit cards with different APRs, it is best to pay off the card with the highest APR first. This is because you will save the most money in interest by paying off the highest-rate debt first.
Therefore, as Michelle has four credit cards, each with different APRs, she should pay them off in order of the highest to lowest interest rate.
Since the highest APR is 23%, credit card #3 should be paid off first.
The next highest APR is 19%, so credit card #2 should be paid off second.
Credit card #1 should be paid off next as it has an APR of 17%.
Finally, credit card #4 should be paid off last, as it has the lowest APR of 15%.
So the order in which Michelle should pay off her credit cards is:
3, 2, 1, 4A supplier to a car manufacturer produces a certain valve and seal used in their cars. The sizes of these seals and
valves are closely monitored to ensure the parts actually work. Here are summary statistics on the diameters for
these valves and seals (in millimeters).
Mean
Standard deviation
Valve
Hv = 50
OV = 0. 3
Seal
Ils = 51
Os = 0. 4
Both distributions are approximately normal. A seal properly fits a valve if the seal's diameter is larger than the
valve's diameter, but the difference can't be more than 2 mm. Suppose we choose a valve and seal at random
and calculate the difference between their diameters. We can assume that their diameters are independent.
The probability that a seal properly fits a valve is approximately 0.9332 or 93.32%.
How to find the difference between their diameters?To determine the probability that a seal properly fits a valve, we need to calculate the probability that the difference in diameter between the seal and valve is less than or equal to 2 mm.
Let X be the diameter of the valve and Y be the diameter of the seal. Then, the difference in diameter between the seal and valve can be expressed as Z = Y - X. We want to find P(Z ≤ 2).
We know that X ~ N(50, 0.3²) and Y ~ N(51, 0.4²), and since Z = Y - X, we have:
Z ~ N(51 - 50, √(0.3² + 0.4²)²) = N(1, 0.5²)
To find P(Z ≤ 2), we standardize Z by subtracting the mean and dividing by the standard deviation:
(Z - 1)/0.5 ~ N(0, 1)
P(Z ≤ 2) = P((Z - 1)/0.5 ≤ (2 - 1)/0.5) = P(Z ≤ 1.5)
Using a standard normal table or calculator, we find that P(Z ≤ 1.5) ≈ 0.9332.
Therefore, the probability that a seal properly fits a valve is approximately 0.9332 or 93.32%.
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Can you help me with this question step by step.
Answer:
32
Step-by-step explanation:
There are 28 full shaded squares
There are 8 half squares
2 half squares make up 1 full square
So 28 + 4 = 32
Area is 32 units
(a) Find a counterexample which shows that WAT is not true if we replace the closed interval [a,b] with the open interval (a,b).(b) What happens if we replace [a,b] with the closed set [a,\infty). Does the theorem hold?
(a) WAT is not true for the open interval (0,1) with function f(x) = 1/x.
(b) WAT holds for the closed set [a,∞) with any continuous function f(x).
(a) The Weierstrass Approximation Theorem (WAT) is not true if we replace the closed interval [a,b] with the open interval (a,b). A counterexample is the function f(x) = 1/x on the open interval (0,1). This function is continuous on (0,1) but it is not uniformly continuous, so it cannot be uniformly approximated by a polynomial.
(b) The Weierstrass Approximation Theorem holds if we replace [a,b] with the closed set [a,∞). That is, if f(x) is a continuous function on [a,∞), then for any ε > 0, there exists a polynomial p(x) such that |f(x) - p(x)| < ε for all x in [a,∞). The proof is similar to the proof of the original theorem using the Bernstein polynomials.
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Write a recursive rule for the sequence [tex]a_{n}[/tex] = 17 - 4n
The recursive sequence are: 17, 13, 9, 5, 1.
The recursive rule for the sequence [tex]a_{n}[/tex] = 17 - 4n is
[tex]a_{1[/tex] = 17
[tex]a_{n}[/tex] = [tex]a_{n-1}[/tex] - 4 for n ≥ 2
Using this rule, we can find the first few terms of the sequence
[tex]a_{1[/tex] = 17
[tex]a_{2}[/tex] = [tex]a_{1[/tex] - 4 = 17 - 4 = 13
[tex]a_{3}[/tex] = [tex]a_{2}[/tex] - 4 = 13 - 4 = 9
[tex]a_{4}[/tex] = [tex]a_{3}[/tex] - 4 = 9 - 4 = 5
[tex]a_{5}[/tex] = [tex]a_{4}[/tex] - 4 = 5 - 4 = 1
and so on.
Therefore, the recursive sequence are: 17, 13, 9, 5, 1.
The question is incorrect and correct question is '' Write a recursive sequence that represents the sequence defined by the following explicit formula [tex]a_{n}[/tex] = 17 - 4n and find [tex]a_{1[/tex] and [tex]a_{n}[/tex] ''.
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What is the probability that a student took AP Chemistry, given they did not get into their first-choice college? Enter
your answer as a decimal to the ten thousandths place.
Student
0.25
0.10
0.35
0.30
Chemistry
000
Physics
Env Sci
Biology
0.45
1st choice
Not 1st
0.55
0.55 1st choice
0.45
0.20
0.80
0.30
0.70
Not 1st
1st choice
Not 1st
1st choice
Not 1st
P(Chem and 1st choice) = (0 25)(0.45) = 0.1125
P(Chem and Not 1st) = (0.25)(0.55) = 0.1375
P(Phys and 1st choice) = (0.35)(0.55) = 0.1925
P(Phys and Not 1st) = (0.35)(0.45) = 0.1575
P(ES and 1st Choice) = (0.30)(0.20) = 0.0600
P(ES and Not 1st) = (0.30)(0.80) = 0.2400
P(Bio and 1st choice) = (0.10)(0.30) = 0.0300
P(Bio and Not 1st) = (0.10)(0.70) = 0.0700
The probability that a student took AP Chemistry given they did not get into their first-choice college is 0.0566.
What is the probability?The probability that a student took AP Chemistry given they did not get into their first-choice college is calculated using the formula below:
P(Chem | Not 1st) = P(Not 1st | Chem) * P(Chem) / P(Not 1st)P(Not 1st | Chem) =0.1375
P(Chem) = 0.25
P(Not 1st) = P(Chem and Not 1st) + P(Phys and Not 1st) + P(ES and Not 1st) + P(Bio and Not 1st)
P(Not 1st)= 0.1375 + 0.1575 + 0.2400 + 0.0700
P(Not 1st)= 0.6050
Substituting the values in the formula above:
P(Chem | Not 1st) = 0.1375 * 0.25 / 0.6050
P(Chem | Not 1st) = 0.0566
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Find the area of this irregular shape hint area of a triangle a = bh÷2
Answer:
The area of the irregular shape is 62 feetExplanation :
We are given with two shapes triangle and a rectangle.
From the above diagram
We can see that Breadth of the rectangle is 5 ft and length of 10 ft.
As we know that area of Rectangle is length × Breadth
Area(rectangle) = l × b
Area (rectangle) = 10 × 5
Area (rectangle) = 50 ft².
Now,
Area (triangle) = bh ÷ 2where
b is base (10 - 6 = 4 ft)h = Height (11 - 5 =6 ft)Area (triangle) = 4 × 6 ÷ 2
Area (triangle) = 24 ÷ 2
Area (triangle) = 12 ft².
Total area = Area of rectangle + Area of triangle
Total area = 50 + 12
Total area = 62 feet
Therefore, The area of the irregular shape is 62 feet.
Find the area of the composite figure.Round Your Answer To The Nearest Hundreth if needed
Answer:
[tex]A = 68.75 \text{ square inches}[/tex]
Step-by-step explanation:
First, we need to identify the trapezoid's dimensions:
base 1 = 16
base 2 = 11.5
height = 5
Then, we can plug these values into the trapezoid area formula:
[tex]A = \dfrac{b_1+b_2}{2} \cdot h[/tex]
[tex]A = \dfrac{16 + 11.5}{2} \cdot 5[/tex]
[tex]A = \dfrac{27.5}{2} \cdot 5[/tex]
[tex]A = \dfrac{137.5}{2}[/tex]
[tex]\boxed{A = 68.75 \text{ square inches}}[/tex]
so if i went to park at 4:30 and it took me 24 minutes , when did i leave home
I must have left home at 4:54 PM in order to arrive at the park at 4:30 PM after 24 minutes of travel time.
When was the time I left home?Given the parameters in the question: if i went to park at 4:30 and it took me 24 minutes
Arrival time = 4 : 30PM
Travel time = 24 minutes
I can determine when i left home by simply subtracting the travel time from the time I arrived.
Hence,
Add the travel time to the time you arrived at the park.
4:30 PM (arrival time) + 24 minutes (travel time) = 4:54 PM
Therefore, I must have left home at 4:54 PM.
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A homeowner borrows $65,000 to remodel their home. The loan is financed at a 2.3% interest rate, compounded quarterly. How much will the homeowner owe after 8 years? Group of answer choices $78,090 $65,023 $78,117 $67,300
A homeowner borrows $65,000 to remodel their home. The loan is financed at a 2.3% interest rate, compounded quarterly.
So we have to find 2.3% of 65,000 which is 1495
Now we have to multiply 1,495 by 8 because it is 8 years which is 11960. Now we add 11,960 to 65,000 and our answer is
Answer : 76960
(Choice 1)
Use the pythagorean Theorem to find the length of a right triangles hypotenuse. The longer sides are 9 cm and 12 cm long
The length of the hypotenuse of the right triangle is 15 cm.
The Pythagorean Theorem states that in a right triangle, the sum of the squares of the two shorter sides is equal to the square of the hypotenuse. Using this formula, we can calculate the length of the hypotenuse of a right triangle.
Given that the longer sides of the right triangle are 9 cm and 12 cm long, we can assume that one of these sides is the shorter side and the other is the longer side. Let's assume that the shorter side is 9 cm long and the longer side is 12 cm long.
Using the Pythagorean Theorem, we can calculate the length of the hypotenuse as follows:
Hypotenuse² = Shorter side² + Longer side²
Hypotenuse² = 9² + 12²
Hypotenuse² = 81 + 144
Hypotenuse² = 225
Taking the square root of both sides, we get:
Hypotenuse = √225
Hypotenuse = 15
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I have 90 kg of beef and need to add 1. 4 oz of filler to each pound. How many ounces of filler will I add
The ounces of filler will the factory need in order to make meatballs out of this shipment of beef is 56.7 oz of filler.
A number of distinct units of mass, weight, or volume are derived from the uncia, an ancient Roman unit of measurement, including the ounce, which remains almost unmodified. The avoirdupois ounce, also known as the US customary and British imperial ounce, is equal to one-sixteenth of an avoirdupois pound.
One factory obtained 90 kg of beef from overseas.
They want to add 1.4oz of filler for each pound of beef.
Given is:
0.45 kg = 1 pound
So, 90 kg = 90 x 0.45 = 40.5 pounds
The company want to add 1.4 oz of filler for each pound of beef.
So for 1 pound we have 1.4 oz of filler
So, for 40.5 pounds they will need = x oz of filler.
x = 1.4 x 40.5 = 56.7
Therefore, the company needs 56.7 oz of filler.
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Complete question;
Factories often add filler when making meatballs sold by the bag. One factory obtained 90kg of beef from overseas. They want to add 1.4oz of filler for each pound of beef. How many ounces of filler will the factory need in order to make meatballs out of this shipment of beef?
A circle is drawn with a center point of q. janelle wishes to construct a tangent to the circle that passes through point b. she starts by connecting points q and b to form line segment bq.
what is the best next step when constructing a tangent to the circle?
a
strike an arc on bq with a center of b that has a length the same as the radius of circle q.
b
draw a line straight down from point q to the bottom of the circle.
c
extend bq through the other side of the circle.
d
find the midpoint of bq.
The best step when constructing a tangent to the circle is to strike an arc on bq with a center of b that has a length the same as the radius of circle q. The correct answer is option a.
When constructing a tangent to a circle with a center point of Q that passes through point B, and having already connected points Q and B to form line segment BQ, the best next step is to: A) Strike an arc on BQ with a center of B that has a length the same as the radius of circle Q.
This will help you find the point where the tangent line intersects the circle, allowing you to complete the tangent construction. The tangent line will be perpendicular to the radius at the point of tangency.
Therefore option a is correct.
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What is the probability of selecting a 2 and then
a number divisible by 4 ?
a.
5/66
b.
1/20
C.
1/24
D.
1/22
Answer: C. 1/24 and that's is your answer to your question