87 electrons are found in an ion with Z = 89. Write its symbol.

Answers

Answer 1

The symbol of the ion is U 2+

U represents the element uranium, and

the superscript 2+ indicates that charge

What is atomic number (Z)?

The atomic number (Z) of an element represents the number of protons found in the nucleus of an atom. In a neutral atom, the number of electrons is equal to the number of protons. However, in an ion, the number of electrons can differ from the number of protons.

To find the symbol for an ion with 87 electrons and a Z of 89, we need to determine the charge on the ion. The charge on an ion is equal to the difference between the number of protons and the number of electrons. In this case, we have:

charge = Z - number of electrons

charge = 89 - 87

charge = +2

Therefore, the ion has a charge of +2. The symbol for this ion can be written as follows:

U 2+

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Related Questions

(a) A compound X contains carbon, 66.7% and hydrogen 11.1% the rest being oxygen. Determine the empirical formula of X. (b) The vapor density of X is 36; determine the molecular formula of X.

Answers

Answer:

The molecular formula of X = C4 h8 O

Science, Use Dimensional Analysis to solve all of the following:​

Answers

0.21 moles of S[tex]O_{2[/tex] can be produced by reacting 8 grams of C[tex]S_{2[/tex]

What is Moles?

Mole is a unit of measurement used in chemistry to express the amount of a substance. It is defined as the amount of a substance that contains the same number of entities (such as atoms, molecules, or ions) as there are atoms in 12 grams of carbon-12. This number is known as Avogadro's number

To calculate the number of moles of S[tex]O_{2[/tex] produced, we need to use the balanced chemical equation to determine the mole ratio between C[tex]S_{2[/tex]and S[tex]O_{2[/tex].

The balanced chemical equation is:

C[tex]S_{2[/tex] + 3[tex]O_{2[/tex]→ C[tex]O_{2[/tex] + 2S[tex]O_{2[/tex]

The molar mass of C[tex]S_{2[/tex] is 76.14 g/mol.

First, we need to calculate the number of moles of C[tex]S_{2[/tex] present in 8 grams:

moles of C[tex]S_{2[/tex] = mass / molar mass

moles of C[tex]S_{2[/tex] = 8 g / 76.14 g/mol

moles of C[tex]S_{2[/tex] = 0.105 moles

From the balanced equation, we see that the mole ratio between C[tex]S_{2[/tex]and S[tex]O_{2[/tex] is 1:2. This means that for every 1 mole of C[tex]S_{2[/tex] that reacts, 2 moles of S[tex]O_{2[/tex] are produced.

Therefore, the number of moles of S[tex]O_{2[/tex] produced can be calculated as:

moles of S[tex]O_{2[/tex] = moles of C[tex]S_{2[/tex] × 2

moles of S[tex]O_{2[/tex] = 0.105 moles × 2

moles of S[tex]O_{2[/tex] = 0.21 moles

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which two of the following compounds would you mix to make a buffer of ph 7.45: h3po4 (fm 97.99), nah2po4 (fm 119.98), na2hpo4 (fm 141.96), na3po4 (fm 163.94)? if you wanted to prepare 1.00 l of buffer with a total phosphate concentration of 0.0500 m, how many grams of each of the two selected compounds would you mix together? (h3po4: pka1

Answers

we need to mix 3.68 g of Na2HPO4 and 2.89 g of NaH2PO4 to prepare 1.00 L of a buffer with a total phosphate concentration of 0.0500 M and a pH of 7.45.

pH = pKa + log([base]/[acid])

Substituting the values:

7.45 = 7.20 + log([Na2HPO4]/[NaH2PO4])

0.25 = log([Na2HPO4]/[NaH2PO4])

Antilog(0.25) = [Na2HPO4]/[NaH2PO4]

1.78 = [Na2HPO4]/[NaH2PO4]

Let x be the amount of Na2HPO4 in moles and y be the amount of NaH2PO4 in moles.

Then:

x + y = 0.0500 (total moles of phosphate)

141.96x + 119.98y = (0.0500)(141.96 + 119.98) (total mass of phosphate)

Solving these equations simultaneously, we get:

x = 0.0259 mol

y = 0.0241 mol

Mass of Na2HPO4 = 0.0259 mol × 141.96 g/mol = 3.68 g

Mass of NaH2PO4 = 0.0241 mol × 119.98 g/mol = 2.89 g

Concentration in chemistry refers to the amount of a substance dissolved in a given volume of a solvent. It is a fundamental concept in chemistry and is used to describe the strength of a solution. The concentration of a solution is usually expressed in terms of the amount of solute present per unit volume of the solution. There are several ways to express concentration, including molarity, molality, mole fraction, and percent by mass or volume.

Molarity is the most commonly used unit of concentration and is defined as the number of moles of solute per liter of solution.  The concentration of a solution plays an important role in determining its properties and behavior. For example, a highly concentrated solution of salt will have a higher boiling point and lower freezing point than a dilute solution. Concentration also affects the rate of chemical reactions, as higher concentrations of reactants typically result in faster reaction rates.

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A Sample of helium occupies a volume of 160 cm³ at 100 KPa and 25°C. what Volume will it occupy if the pressure is adjusted to 80 KPa and the temperature remains unchanged?. -273 ​

Answers

Boyle's Law-

[tex]\:\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{ P_1 \: V_1=P_2 \: V_2}\\[/tex]

(Pressure is inversely proportional to the volume)

Where-

[tex]\sf V_1[/tex] = Initial volume[tex]\sf V_2[/tex] = Final volume[tex]\sf P_1[/tex] = Initial pressure[tex]\sf P_2[/tex] = Final pressure

As per question, we are given that -

[tex]\sf V_1[/tex] = 160 cm³[tex]\sf P_1[/tex] = 100KPa[tex]\sf P_2[/tex] = 80KPa

Now that we have all the required values and we are asked to find out volume which will be occupied if the pressure is adjusted to 80 KPa and the temperature remains unchanged. For that we can put the values and solve for the final volume of helium-

[tex]\:\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{ P_1 \: V_1=P_2 \: V_2}[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf 100 \times 160 = 80 \times V_2\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf V_2 = \dfrac{100 \times 160}{80}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf V_2 =100\times \cancel{\dfrac{ 160}{80}}\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf V_2 = 100 \times 2\\[/tex]

[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{V_2 = 200 \:cm^3 }\\[/tex]

Therefore, 200 cm³ will be occupied if the pressure is adjusted to 80 KPa and the temperature remains unchanged.

an alpha particle (6.70×10-27 kg) moving at a speed of 1.52×107 m/s (34000000 miles per hour).
whats the m?

Answers

According to the given statement the alpha particle's wavelength is 6.48×10⁻¹⁵ meters.

What is alpha particle made of?

The positively charged alpha particles (α) are created when the nucleus of an atom's two protons as well as two neutrons join forces. Alpha particles are created by the radioactivity of the most dangerous radioactive elements, including uranium, radium, and polonium.

The de Broglie wavelength equation may be used to determine the alpha particle's wavelength:

λ = h / p

where p is the particle's momentum, h is its Planck constant (6.626 * 10⁻³⁴ J s), and is its wavelength.

The mass (m) and velocity (v) of an alpha particle may be used to compute its momentum:

p = m * v

Inputting the values provided yields:

p = (6.70×10⁻²⁷ kg) * (1.52×10⁷ m/s) = 1.02×10⁻¹⁹ kg m/s

Now we can determine the wavelength using this value:

λ = h / p = 6.626 x 10⁻³⁴ J s / 1.02×10⁻¹⁹ kg m/s

λ = 6.48 x 10⁻¹⁵ m

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The complete question is -

Calculate the wavelength of -

An alpha particle (6.70×10⁻²⁷ kg) moving at a speed of 1.52×10⁷ m/s (34000000 miles per hour). What is the m ?

structure and function of starch?

Answers

Starch is made up of long chains of sugar molecules that are connected together. Starch's primary role is to help plants store energy. In an animal's diet, starch is a source of sugar. Amylase, an enzyme contained in saliva and the pancreas that breaks down starch for energy, is used by animals to break down starch

What is the molarity (M) of a bleach solution containing 9.50 grams of bleach (NaOCI) in 2,000 ml of solution?​

Answers

The molarity of the bleach solution is 0.0635 M.

How to calculate the molarity (M) of a solution ?

First we need to know the number of moles of solute (in this case, NaOCI) and the volume of the solution in liters.

First, we need to convert the mass of NaOCI to moles using its molar mass:

molar mass of NaOCI = 23.0 g/mol (for Na) + 16.0 g/mol (for O) + 35.5 g/mol (for Cl) + 1.0 g/mol (for I) = 74.5 g/mol

moles of NaOCI = mass / molar mass = 9.50 g / 74.5 g/mol = 0.127 moles

Next, we need to convert the volume of the solution to liters:

volume = 2,000 ml = 2,000 / 1,000 L = 2.0 L

Now we can calculate the molarity of the solution:

Molarity (M) = moles of solute / volume of solution in liters

M = 0.127 moles / 2.0 L = 0.0635 M

Therefore, the molarity of the bleach solution is 0.0635 M.

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Without checking and reporting their boiling points, rank the boiling points of H2O, MgCl2, HBr, and HF H2S from the lowest to highest based on your knowledge of intermolecular forces, hydrogen bond, and ionic bond. Explain how you make your predictions without checking a reference.

Answers

As HF is hydrogen bonded, it has a highest boiling point of 19 oC or less, when it becomes liquid. The boiling points of the remaining hydrogen halides, which are gaseous, are determined by the van der Waal forces.

H2O or HF, which has the higher boiling point?

Hydrogen fluoride (H 2 F) has a lower boiling point than water (H 2 O) ( ). H2O has a boiling point of 100 °C while only having a boiling point of 5 °C. Despite the fact that water and hydrogen fluoride have stronger hydrogen bonds than each other, water only forms two hydrogen bonds per molecule whereas hydrogen fluoride only forms one.

Which has the highest boiling point between H2O and HCL?

Furthermore, water creates hydrogen bonds between nearby molecules. The extremely electronegative oxygen on the other molecule interacts with hydrogen. This is a strong type of interaction that takes more energy than dipole-dipole interactions. As a result, water boils at a greater temperature than HCL.

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Sulfur dioxide gas decomposes into solid sulfur (S8) and oxygen gas. How many grams of solid sulfur would be produced from 25.0g of sulfur dioxide?

Answers

Sulfur dioxide decomposition's balanced chemical equation is 2 SO2(g) 2 S(s) + 3 O2 (g). 200.00 g of solid sulphur would result from 25.0 g of sulphur dioxide.

How much aluminium will react with 25 grammes of oxygen gas?

In order to compute the mass of oxygen that will react or the mass of 02 that will react with aluminium, multiply the molar mass of oxygen molecules, 0.69 mol two, by 32 g per mole. Hence, the answer is that 25 g of aluminium and 22.22 g of cobalt will react.

First, we must determine how many moles of sulphur dioxide are contained in 25.0 g:

Number of moles of SO2 = mass / molar mass

Number of moles of SO2 = 25.0 g / 64.06 g/mol (molar mass of SO2)

Number of moles of SO2 = 0.3904 mol

The number of moles of sulphur produced can then be calculated using the mole ratio between sulphur dioxide and sulphur:

Number of moles of S = 2 x number of moles of SO2

Number of moles of S = 2 x 0.3904 mol

Number of moles of S = 0.7808 mol

Lastly, we may convert the amount of moles to grammes using the molar mass of sulphur:

Mass of S = number of moles x molar mass

Mass of S = 0.7808 mol x 256.53 g/mol (molar mass of S8)

Mass of S = 200.00 g (rounded to two decimal places)

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She measured the mass of the metal to be 352.3 grams. Then she dropped the metal into a measuring cup and found that it displaced 18.0 mL of water

Answers

The metal has a density of 19.3g/mL.

A material's density is determined by how much mass there is in a given volume of that material. We must divide the metal's mass by its volume to determine its density. Density of gold is 19.3 g/mL.Since the volume of the metal is equal to the volume of water it displaced, we can calculate the density of the metal by dividing the mass of the metal (352.3 grams) by the volume of water it displaced (18.0 mL).

Density = [tex]\frac{Mass}{Volume}[/tex]

Density = [tex]\frac{352.3 g}{18.0 mL}[/tex]

Density = 19.3 g/mL

Therefore, the density of the metal is 19.3 g/mL.

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complete question:

She measured the mass of the metal to be 352.3 grams. Then she dropped the metal into a measuring cup and found that it displaced 18.0 mL of water

calculate the density  of metal

densities of some common substances for comparison

Density of water = 1.00 g/mL

Density of air = 1.225 g/mL

Density of iron = 7.86 g/mL

Density of aluminum = 2.7 g/mL

Density of gold = 19.3 g/mL

how does chemical fertilizer decrease the oxygen level in water?​

Answers

Answer: As the fertilizers enter the water systems, they cause an explosion of growth by algae and aquatic plants. When the organisms die they are decomposed by microbes that quickly deplete the oxygen in water, killing animals such as fish and shellfish.

Explanation: Excess fertilizers lead to "eutrophication".

ASAPPPP!!!PLEASE!!!!
Explain what you know about the Oxygen atom based on the following element
symbol? (Be sure to include information about protons, neutrons, electrons, mass
number).
17
8
0

Answers

Answer:

H20 oxygen 17 8 0 gyjhf I'd

How many moles of nickel (Ni) is 3.88 x 1023 atoms of nickel?

O.679 moles Ni
O .644 moles Ni
O.638 moles Ni
O.762 moles Ni

Answers

Answer:

Explanation:

We can use to convert the given number of atoms of nickel to moles.

1 mole of any element contains 6.022 x 10^23 atoms of the element

So, the number of moles of nickel can be calculated as:

moles of Ni = (number of atoms

moles of Ni = 3.88 x 10^23 / 6.022 x 10^23

moles of Ni = 0.644

Therefore, the answer is option B: 0.644 moles Ni.

what are potential sources of error in rate of reaction lab with hcl and calcium carbonate?

Answers

Answer:

human error , random error .

given a gas is 3 L and 3 mol, what is the number of moles of the gas when volume changes to 15 L?

Answers

The ideal gas law can be used to solve this issue:

PV = nRT

where R is the universal gas constant, n is the number of moles, P is the gas's pressure, V is its volume, and T is its temperature.

The following expression can be used to link the starting and final volumes and moles under the assumption that the gas's pressure and temperature don't change:

V1 / n1 = V2 / n2

where V1 and n1 represent the volume and number of moles at the beginning, and V2 and n2 represent the volume and number of moles at the end.

Inputting the specified values results in:

15 L/n2 = 3 L / 3 mol

When we simplify and account for n2, we obtain:

n2 = 3 mol (15 L / 3 L)

n2 = 15

As a result, 15 mol of the gas are present when the volume is changed to 15 L.

How do you calculate the amount of gas in a volume in moles?

Using the equation V = nV m, where V is the volume in liters, n is the amount of gas in moles, and V m is the molar gas volume in liters per mole, is another technique to determine the solution. We may substitute the volume and molar gas volume from the question into this equation.

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On a spring morning (20C) you fill your tires to a pressure of 2.25 atmospheres. As you ride along, the tire heats up to 45C from the friction on the road. What is the pressure in your tires now?

Answers

Assuming the volume of the tire remains constant, we can use the ideal gas law to determine the pressure of the tire at the higher temperature:

P1/T1 = P2/T2

where P1 is the initial pressure, T1 is the initial temperature, P2 is the final pressure (what we're trying to find), and T2 is the final temperature.

Converting the temperatures to Kelvin (as the ideal gas law requires temperatures in Kelvin), we have:

P1/T1 = P2/T2

P1 = 2.25 atm

T1 = 20 + 273.15 = 293.15 K

T2 = 45 + 273.15 = 318.15 K

Solving for P2, we get:

P2 = P1(T2/T1)

P2 = 2.25 atm (318.15 K / 293.15 K)

P2 = 2.44 atm (rounded to two significant figures)

Therefore, the pressure in your tires at 45°C would be approximately 2.44 atm.

Determine the magnitude of the partial charges in HBr given that the bond length is 1.41 angstroms
and the dipole moment is 0.82 debye.

Answers

HBr has a dipole moment of 7.95debye and an interatomic spacing of 1.94 x 10-om.

Is HBr's dipole moment D?

HBr (a polar covalent molecule) has a dipole moment () of 0.851D (debye) and a percentage ionic character of 12.6%.

The size of the charge multiplied by the distance between the centres of the positive and negative charges yields a dipole moment. The Greek character " is used to represent it. It is measured in Debye units ('D'). 1 D = 3.33564 10-30 C.m, where C signifies Coulomb and m a metre.

It's 1018 statcoulomb-centimeters. Traditionally, the debye moment was defined as the dipole moment produced by two charges of opposing sign but equal magnitude of 1010 statcoulomb.

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Below is the titration curve of a 50.0 mL of 0.1 M triprotic acid H3A with 0.1 M NaOH(aq). The initial pH and the equivalence points are indicated in the curve.
Calculate pKa1, pKa2, and pKa3 for the triprotic acid H3A.

Answers

In the titration curve, the initial pH of the triprotic acid H3A is given as approximately 1.8. This corresponds to the pH at which only H3A is present in solution.

The first equivalence point, where half of the H3A has been neutralized, occurs at approximately pH 4.3. This corresponds to the point where H2A^- is formed; therefore, Ka1 can be calculated as follows:

Ka1 = [H2A^-][H3O^+]/[H3A] = 10^(-pH1)

where pH1 is the pH at the first equivalence point.

Substituting the given values, we get:

Ka1 = [H2A^-][H3O^+]/[H3A] = 10^(-4.3)

At the second equivalence point, where H2A^- has been completely neutralized and HA^2- is formed, the pH is approximately 8.5. Thus, Ka2 can be calculated as follows:

Ka2 = [HA^2-][H3O^+]/[H2A^-] = 10^(-pH2)

where pH2 is the pH at the second equivalence point.

Substituting the given values, we get:

Ka2 = [HA^2-][H3O^+]/[H2A^-] = 10^(-8.5)

Lastly, at the third equivalence point, where HA^2- has been completely neutralized and A^3- is formed, the pH is approximately 12.3. Therefore, Ka3 can be calculated as follows:

Ka3 = [A^3-][H3O^+]/[HA^2-] = 10^(-pH3)

where pH3 is the pH at the third equivalence point.

Substituting the given values, we get:

Ka3 = [A^3-][H3O^+]/[HA^2-] = 10^(-12.3)

Thus, the values of pKa1, pKa2, and pKa3 for the triprotic acid H3A are:

pKa1 = -log(Ka1) = -log(10^(-4.3)) = 4.3
pKa2 = -log(Ka2) = -log(10^(-8.5)) = 8.5
pKa3 = -log(Ka3) = -log(10^(-12.3)) = 12.3


A sample of 0.49 g of carbon dioxide was obtained by heating 1.22 g of calcium carbonate. What is the percent yield for this reaction

Answers

The percent yield for the reaction of a sample of 0.49 g of carbon dioxide was obtained by heating 1.22 g of calcium carbonate is 92.4%

Given the mass of carbon dioxide ([tex]CO2[/tex]) = 0.49g

The mass of calcium carbonate ([tex]CaCO3[/tex]) = 1.22g

The reaction is as follows:

[tex]CaCO3(s) -- > CaO(s)+CO2(s)[/tex]

As we see 1 mole of CaCO3 is required to produce 1 mole of [tex]CO2[/tex]

The molar mass of calcium carbonate, = 100.09 g/mol.

The molar mass of given carbon dioxide = 44g

mass of [tex]CaCO3[/tex] used = number of moles x molar mass = 1 * 100 = 100g

Mass of [tex]CO2[/tex] produced = 1 * 44 = 44g

Here for 100g of [tex]CaCO3[/tex] 44g of [tex]CO2[/tex] is produced.

Then for 1.22g of [tex]CaCO3[/tex] = 44 * 1.22/100 = 0.53g of [tex]CO2[/tex] is produced.

But the actual yield of carbon dioxide is 0.49 g

The percent yield is calculated by dividing the actual yield by the theoretical yield and multiplying by 100.

percent yield = 0.49/0.53 * 100 = 92.4%

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Peroxyacyl nitrates contain two relatively weak bonds that can be broken by low-energy photons. The weakest is the N−O
bond in the nitrate functional group of the molecule with a standard bond-dissociation energy of 201 kJ mol−1
. What is the longest wavelength of a photon, in nanometres, that has enough energy to cause the photodissociation of the weakest bond. Assume all energy of the photon is efficiently used for the photodissociation.

Answers

The longest wavelength of a photon that has enough energy to cause the photodissociation of the weakest bond in a peroxyacyl nitrate molecule is approximately 590 nm.

Given the weakest bond in Peroxyacyl nitrate is N-O bond.

The standard bond-dissociation energy of N-O = 201 kJ mol−1

Let the wavelength = l

We know that E = h c / λ, where E is the energy in joules, h is Planck's constant, c is the speed of light, and λ is the wavelength of photons

[tex]E = (6.626 * 10^{-34}) * (3 * 10^8) / \lambda[/tex]

λ =  [tex](6.626 * 10^{-34}) * (3 * 10^8)/201 kJ mol^{-1}[/tex]

λ = 590nm

In order for photodissociation to occur, the photon must have enough energy to break the N−O bond in the nitrate functional group of the molecule. All of the energy of the photon is efficiently used for the photodissociation.

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PLS CHEM HELP
2 NH3 + 3 CuO g 3 Cu + N2 + 3 H2O

In the above equation how many grams of N2 can be made when 197 grams of CuO are consumed?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element

Molar Mass

Hydrogen

1

Nitrogen

14

Copper

63.5

Oxygen

16

Answers

The mass of the nitrogen gas that is found to be produced from the reaction equation is 22.4 g.

What is a balanced reaction?

A balanced chemical equation is a representation of a chemical reaction using the formulas of the reactants and products, and the coefficients that represent the number of each species involved in the reaction.

The correct equation of the reaction is;

2 NH3 + 3 CuO → 3 Cu + N2 + 3 H2O

Number of moles of CuO consumed = 197g/80 g/mol

= 2.4 moles

Given that;

3 moles of CUO is consumed to give 1 moles of N2

2.4 moles of CUO will give 2.4 * 1/3

= 0.8 moles

Mass of N2 = 0.8 * 28 g/mol

= 22.4 g

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in terms of the henderson-hasselbalch equation, show how it can be solved to find ka of an acid when the concentrations of the conjugate acid and bases are equal.

Answers

The pH of the solution is equal to the pKa of the acid when the concentrations of the conjugate acid and base are equal.

The Henderson-Hasselbalch equation is given by:

pH = pKa + log([A-]/[HA])

Where:

pH = the pH of the solution

pKa = the acid dissociation constant of the acid

[A-] = the concentration of the conjugate base

[HA] = the concentration of the acid

When the concentrations of the conjugate acid and base are equal, [A-] = [HA], and the Henderson-Hasselbalch equation can be simplified to:

pH = pKa + log(1)

log(1) = 0, so:

pH = pKa

Therefore, when the concentrations of the conjugate acid and base are equal, the pH of the solution is equal to the pKa of the acid. This can be used to determine the acid dissociation constant (Ka) of the acid by measuring the pH of the solution when the concentrations of the conjugate acid and base are equal.

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Calculate the mass of butane needed to produce 67.5 g of carbon dioxide.
Express your answer to three bignificant figures and include the appropriate units.

Answers

The mass of butane needed to produce 67.5 g of carbon dioxide is 22.27 g.

Steps

The balanced chemical equation for the combustion of butane (C4H10) is:

2 C4H10 + 13 O2 → 8 CO2 + 10 H2O

This equation shows that 2 moles of butane react with 13 moles of oxygen to produce 8 moles of carbon dioxide. The molar mass of butane is 58.12 g/mol, and the molar mass of carbon dioxide is 44.01 g/mol.

To calculate the mass of butane needed to produce 67.5 g of carbon dioxide, we can use the following steps:

Calculate the number of moles of carbon dioxide produced:

67.5 g CO2 x (1 mol CO2 / 44.01 g CO2) = 1.534 mol CO2

Use the mole ratio from the balanced chemical equation to find the number of moles of butane needed:

1.534 mol CO2 x (2 mol C4H10 / 8 mol CO2) = 0.3835 mol C4H10

Calculate the mass of butane needed:

0.3835 mol C4H10 x 58.12 g/mol = 22.27 g C4H10

Therefore, the mass of butane needed to produce 67.5 g of carbon dioxide is 22.27 g.

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7. Calculate the half-life of an isotope if its activity falls from 1600 counts per second to 400 counts per second after 60 days.​

Answers

(Physics question btw)

1600 to 400 counts denotes 2 half lives. (1600/2 = 800, 800/2 = 400)

So if 2 half lives has taken 60 days then 1 half life will be half of 60

= 30 days

Provide a condensed structure for the following compound.

(I just need help with #6, sorry for the bad picture!)

Answers

The condensed structural formula of the compound is;

(CH3)3CCH2CH(CH2CH3)CH2CH2CH(CH3)(CH2CH3)

The functional groups in norethynodrel are;  ketone, alcohol and alkyne

What is condensed structure of an organic compound?

The condensed structure of an organic compound is a simplified representation of the molecular structure of the compound that uses brackets and symbols to indicate the arrangement of atoms in the molecule.

In a condensed structure, the individual atoms are not explicitly shown, and the bonds between them are indicated by lines.

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Convert 350mi/hr to m/sec

Answers

Answer: To convert 350 miles per hour to meters per second, we need to use the following conversion factors:

1 mile = 1609.344 meters

1 hour = 3600 seconds

Therefore, we can write:

350 miles per hour = 350 miles / 1 hour × 1609.344 meters / 1 mile × 1 hour / 3600 seconds

Simplifying the expression, we get:

350 miles per hour = 155.65104 meters per second (rounded to six decimal places)

Therefore, 350 miles per hour is equivalent to 155.65104 meters per second (approximately).

Explanation:

Objects found at the bottom of the ocean are often covered in coral is this a physical or chemical change por favor necesito ayuda contestar pls

Answers

The growth of coral on objects found at the bottom of the ocean is a physical change, not a chemical change.

chemical change por favor necesito ayuda contestar ?

This is because the coral is simply attaching itself to the surface of the object through a physical process, rather than changing the chemical composition of the object itself. The coral is able to attach itself to the surface due to physical forces such as adhesion, cohesion, and surface tension.

However, it is worth noting that over time, the growth of coral on an object can lead to chemical changes in the object as the coral secretes calcium carbonate, which can gradually alter the object's composition.

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How many moles of sodium hydroxide are needed to completely neutralize 25.0 moles of sulfuric acid?

Answers

Answer:

50.0moles

Explanation:

The balanced equation of the reaction is:

2NaOH + H2SO4____ Na2SO4 +2H2O

2moles of NaOH reacted with 1mole of H2SO4

x moles of NaOH will react with 25moles of H2SO4

2moles______1mole

xmoles______25

x=25×2

x=50moles of NaOH

What is the Molarity of a 0.5 Liter solution that contains 3.84 moles of NaCI?


SHOW WORK PLEASE​

Answers

The molarity of a 0.5 liter solution that contains 3.84 moles of NaCl would be 7.68 M.

What is molarity?

Molarity is simply the ratio of the number of moles of solutes per liter volume of a solution.

In other words, molarity is a measure of the concentration of a solute in a solution. It is commonly denoted by the symbol "M" and expressed in units of mol/L.

Molarity = mole/volume

Where the volume is in liters.

In this case:

Number of moles = 3.84 molesVolume = 0.5 liter

Molarity of the NaCl solution = 3.84/0.5

                                                = 7.68 M

Thus, the molarity of a 0.5 Liter solution that contains 3.84 moles of NaCI is 7.68 M.

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scientific report on esterificatin​

Answers

Esterification is a chemical reaction between an alcohol and a carboxylic acid that results in the formation of an ester and a molecule of water.

Write a scientific report on esterification

Esterification  is an important class of organic reactions and is widely used in the synthesis of flavors, fragrances, and plastics. In this report, we will explore the fundamental principles and practical applications of esterification.

The experimental procedure involves the reaction between methanol and acetic acid to form methyl acetate and water. The reaction was carried out in a round-bottom flask equipped with a condenser and a thermometer. The reactants were mixed in stoichiometric amounts, and a small amount of sulfuric acid was added as a catalyst. The flask was heated using a hot plate and maintained at a constant temperature of 60°C.

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