9. Arrange the following ions in terms of increasing atomic radius (arrange then increasing from left [smallest] to right [largest]): Ca2+, K+, Rb+, Sr2+, Na+​

To calculate the mass of mercury(I) chloride that the chemist has added to the reaction flask, we need to know the molar mass of the compound and the number of moles of the solution added.

The molar mass of mercury(I) chloride is 232.6 g/mol. The chemist added an unspecified volume of the solution, so we cannot directly calculate the number of moles added. However, we can use the concentration of the solution, which is typically given in units of moles per liter (mol/L).

Let's assume that the concentration of the mercury(I) chloride solution is 0.1 mol/L. This means that there are 0.1 moles of mercury(I) chloride in every liter of the solution. We don't know how much of the solution the chemist added, but we can use a conversion factor to calculate the number of moles based on the volume.

For example, if the chemist added 10 mL of the solution, we can convert that to liters by dividing by 1000 (1 mL = 0.001 L).
10 mL x (0.001 L/1 mL) = 0.01 L
Now we can use the concentration to calculate the number of moles:

0.1 mol/L x 0.01 L = 0.001 mol
Finally, we can use the molar mass to convert from moles to grams:
0.001 mol x 232.6 g/mol = 0.2326 g

To convert to micrograms, we need to multiply by 1,000,000:
0.2326 g x 1,000,000 µg/g = 232,600 µg
Therefore, the mass of mercury(I) chloride added to the reaction flask is 232,600 µg, rounded to significant digits.

It's worth noting that the exact answer will depend on the actual concentration of the solution and the volume added, but this calculation provides a general approach to solving this type of problem.

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Answer:

Sedimentation equilibrium in a suspension of different particles, such as molecules, exists when the rate of transport of each material in any one direction due to sedimentation equals the rate of transport in the opposite direction due to diffusion.

Answer:

0.108L HCl

Explanation:

5.32 g zinc * 1 mol zinc/65.38g zinc * 2 mol HCl/1 mol zinc * L HCl/1.5 mol HCl = 0.108L HCl

Answer:

Explanation:

no

The concentration of arsenic in the water is 12 ppm, which is higher than the legal limit of 0.05 ppm, the sample of drinking water is not within the legal limit for arsenic. Therefore, action needs to be taken to reduce the level of arsenic in the water to make it safe for drinking.

The concentration of arsenic in the water can be calculated as follows:

Concentration (ppm) = (Mass of arsenic / Mass of water) x 1,000,000

In this case, the mass of arsenic is 0.0012 grams and the mass of water is 100 grams. Substituting these values into the formula, we get:

Concentration (ppm) = (0.0012 g / 100 g) x 1,000,000

Concentration (ppm) = 12 ppm

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The solubility is the amount of a substance that dissolves in a given quantity of solvent at a particular temperature to produce a saturated solution.

Definition: Solubility is defined as the maximum amount of solute that can dissolve in a given quantity of solvent at a specific temperature and pressure to form a saturated solution. It is typically expressed in terms of the mass of solute per unit volume or mass of solvent.

Solute and Solvent: In a solution, the solute is the substance that is being dissolved, while the solvent is the medium in which the solute dissolves. The solute can be a solid, liquid, or gas, while the solvent is usually a liquid, but can also be a gas or a solid in some cases.

Saturated Solution: A saturated solution is a solution in which the maximum amount of solute has been dissolved in a given quantity of solvent at a specific temperature. In a saturated solution, the rate of dissolution of the solute is balanced by the rate of precipitation or crystallization of the solute, resulting in a dynamic equilibrium.

Factors Affecting Solubility: The solubility of a solute depends on several factors, including temperature, pressure, and the nature of the solute and solvent.

Generally, increasing temperature enhances solubility for most solid solutes, while the effect of pressure on solubility is more significant for gases dissolved in liquids. The polarity and intermolecular forces between the solute and solvent molecules also influence solubility.

Solubility Curves: Solubility can be represented graphically by constructing solubility curves. These curves depict the relationship between the solute's solubility and the temperature or pressure.

Solubility curves can help determine the maximum amount of solute that can dissolve under different conditions and can vary for different solutes and solvents.

Supersaturation: Under certain conditions, it is possible to create a supersaturated solution, where the solute concentration exceeds the solubility limit at a given temperature.

Supersaturated solutions are unstable and can result in the precipitation of excess solute upon the introduction of a seed crystal or disturbance.

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Specific heat capacity is the amount of heat required to raise the temperature of a substance by one degree Celsius per unit of mass.

To determine the specific heat capacity of 1.0g of yam, we can use a simple equation:

q = m × c × ΔT

where q is the amount of heat required, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

To measure the specific heat capacity of yam, we would first need to heat the yam to a known temperature, and then measure the amount of heat required to raise its temperature by a certain amount.

For example, we could heat 1.0g of yam to 25°C and then place it in a known amount of water at a lower temperature, such as 20°C. We could then measure the change in temperature of the water and calculate the amount of heat required to heat the yam.

By rearranging the equation above, we can solve for c:

c = q / (m × ΔT)

We can then substitute in the values we measured and calculate the specific heat capacity of the yam. This process can be repeated several times to obtain an average value for the specific heat capacity of yam.

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Value might be different from absolute zero due to several factors like Measurement errors, External factors, Non-ideal conditions.

"Why might your value be different from absolute zero?" we need to understand the following terms:

1. Value: Refers to a quantity or numerical measurement in a specific context.
2. Absolute zero: The lowest possible temperature, at which all molecular motion stops. It is 0 Kelvin (K) or -273.15 degrees Celsius (°C) or -459.67 degrees Fahrenheit (°F).

Your value might be different from absolute zero due to several factors, such as:
1. Measurement errors: If you are measuring a temperature, there could be inaccuracies in your measuring device, leading to a value different from absolute zero.
2. External factors: The presence of heat or energy in your system can cause the value to deviate from absolute zero.
3. Non-ideal conditions: In real-world situations, reaching absolute zero is practically impossible due to quantum effects and other factors, causing your value to be higher than absolute zero.

By understanding these factors, you can identify why your value may differ from absolute zero.

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Answer:

in chemical reactions moles correspond to the number of molecules or atoms that go into reaction. It means that number that is in front of molecule or atom for example in this reaction you have one oxygen it means one mole of oxygen. 4 molecules of acid correspond to 4 moles of HCl. So the final answer would be:

4 moles of HCl

2 moles of H2O

2 moles of Cl2

The concentration of [tex]Ca(OH)_2[/tex] is 0.0217 M.

The balanced chemical equation for the reaction between the  [tex]Ca(OH)_2[/tex] and the HCl is:

[tex]Ca(OH)_2 + 2HCl[/tex] → [tex]CaCl_2 + 2H_2O[/tex]

From this equation, we can see that 1 mole of [tex]Ca(OH)_2[/tex] reacts with 2 moles of HCl.

The number of moles of HCl used can be calculated as:

moles HCl = Molarity * Volume in liters[tex]= 0.029 M\ *\ 0.0373 L = 0.0010837\ mol[/tex]

Since the stoichiometry of the reaction is 1:2 between [tex]Ca(OH)_2[/tex] and HCl, the number of moles of [tex]Ca(OH)_2[/tex] in the 25.0 mL sample can be calculated as:[tex]moles\ Ca(OH)2 = 0.0010837\ mol / 2 = 0.00054185\ mol[/tex]

The concentration of [tex]Ca(OH)_2[/tex] can then be calculated as:

[tex]Molarity = moles[/tex] ÷ [tex]Volume\ in\ liters\ = 0.00054185\ mol[/tex] ÷ 0.025 L = 0.0217M

Therefore, the concentration of [tex]Ca(OH)_2[/tex] is 0.0217 M.

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Titan's atmosphere predominantly consists of nitrogen and methane, with traces of other gases, ruling out the possibility of life evolving there in the same manner that it is believed to have done on Earth.

On Earth, nitrogen and oxygen make up the majority of the atmosphere, with traces of other gases. Because they are required for respiration, nitrogen and oxygen are crucial for maintaining life as we know it. On the other hand, no known form of life uses methane, which is a highly reactive and combustible gas. Additionally, any form of life would have a very difficult time surviving on Titan due to its extremely low temperatures, which average around -180°C.

Methane, a greenhouse gas, traps heat from the sun and prevents it from escaping back into space, keeping Titan warmer than the other moons of Saturn. Because it absorbs and then emits infrared radiation, which is the main type of heat energy emitted by the sun, methane is a potent greenhouse gas.

Titan has a far stronger greenhouse effect than Saturn's other moons as a result, which keeps Titan's surface warm. Titan's surface would be significantly colder without the methane greenhouse effect, making it more like the other moons of Saturn.

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Correct question:

Titan is a moon of the planet Saturn Table shows the percentages of the gases in the atmosphere of Titan.  

Percentage of gas in atmosphere (%)

Nitrogen 98

Methane 1

Other gases 0.

Some scientists think that living organisms could have evolved on Titan. Explain why these organisms could not have evolved in the same way that life is thought to have evolved on Earth.

Saturn has other moons. The other moons of Saturn have no atmosphere. Titan is warmer than the other moons of Saturn because its atmosphere contains thegreenhouse gas methane. Explain how this greenhouse gas keeps Titan warmer than the other moons of Saturn.

The boiling point of the solution is 80.58 °C, which is prepared by dissolving 2. 50 g of biphenyl (C₁₂ H₁₀).

To determine the boiling point of the solution, we need to use the equation;

Δ[tex]T_b}[/tex] = [tex]K_{b}[/tex] x m

Where ΔTb is boiling point elevation, is molal boiling point elevation constant, and m is molality of the solution.

First, we to calculate the molality of the solution;

moles of biphenyl =2.50 g / 154 g/mol

= 0.0162 mol

mass of benzene = 85.0 g

moles of benzene = 85.0 g / 78.11 g/mol

= 1.088 mol

molality = moles of solute/mass of solvent (in kg)

molality = 0.0162 mol / 0.085 kg

= 0.19 mol/kg

Next, we need to look up the molal boiling point elevation constant ([tex]K_{b}[/tex]) for benzene. The value of [tex]K_{b}[/tex] for benzene is 2.53 °C/m.

Finally, we alculate the boiling point elevation;

Δ[tex]T_b}[/tex] = [tex]K_{b}[/tex] x m

Δ[tex]T_b}[/tex] = 2.53 °C/m x 0.19 mol/kg

= 0.481 °C

The boiling point elevation (Δ[tex]T_b}[/tex]) is the difference between the boiling point of the solution and the boiling point of the pure solvent. The boiling point of pure benzene is 80.1 °C. Therefore, the boiling point of the solution will be;

Boiling point of solution = 80.1 °C + 0.481 °C

= 80.58 °C

So, the boiling point of the solution is 80.58 °C.

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The first two carboxylic acids described contain a benzene ring, which is not susceptible to the malonic ester synthesis.

The malonic ester synthesis requires a compound with a methyl group adjacent to both carboxylate groups, and a benzene ring does not fulfill this requirement. The last two carboxylic acids described cannot be prepared by the malonic ester synthesis because an SN₂ reaction cannot be performed on compounds with bulky substituents or with two or more halogen atoms attached to the same carbon atom.

The synthesis requires the use of an alkyl halide that can undergo an SN₂ reaction with sodium ethoxide, but benzyl bromide, bromobenzene, and dibromobenzene are not suitable for this type of reaction. Additionally, the bromide required for the synthesis is unstable, which further complicates the reaction.

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ans.1

blank 1 = 4

blank 2 = 4

blank 3 = 1

blank 4 = 8

ans.2

blank 1 = 10

blank 2 = 15

blank 3 = 1

blank 4 = 30

ans.3

blank 1 =  1

blank 2 = 2

blank 3 = 2

blank 4 = 1

blank 5 =2

If the decomposition of hydrogen peroxide into water and oxygen gas is an exothermic reaction, we would expect the final temperature to be lower than the initial temperature of 28˚C.

This is because during an exothermic reaction, energy is released from the system into the surroundings in the form of heat. In other words, the energy of the products (water and oxygen) is lower than the energy of the reactants (hydrogen peroxide), and the excess energy is released into the surroundings.

As a result, the temperature of the surroundings (in this case, the container holding the reaction) will increase, while the temperature of the system (the reactants and products) will decrease. This means that the final temperature of the reaction will be lower than the initial temperature of 28˚C.

Overall, we would expect the reaction to release heat into the surroundings, causing the temperature of the surroundings to increase while the temperature of the system decreases.

The retentate flow rate is 5,021.862 kg/h and the permeate flow rate is 5,021.862 kg/h. The membrane surface area required is 3,517.948 m².

Permeate flow is the rate at which a fluid passes through a membrane. It is a measure of the membrane's permeability, which is the ability of a substance to pass through a membrane. Permeate flow is used in many industrial processes, such as purification of fluids, separation of compounds, and concentration of liquids.

The first step is to calculate the mass flow rate of the feed. This is given by the equation:

Mass flow rate (kg/h) = Feed flow rate (kg/h) x Feed concentration (wt%)

Mass flow rate = 9,905 kg/h x 57.5 wt% = 5,686.625 kg/h

Next, we need to calculate the flow rate of the retentate and permeate in kg/h. This is given by the equation:

Flow rate (kg/h) = Mass flow rate (kg/h) x Retentate/Permeate concentration (wt%)

Retentate flow rate = 5,686.625 kg/h x 16.4 wt% = 931.939 kg/h

Permeate flow rate = 5,686.625 kg/h x 88.2 wt% = 5,021.862 kg/h

Finally, we need to calculate the membrane surface area in m². This is given by the equation:

Membrane surface area (m²) = Permeate flow rate (kg/h) / Total permeate mass flux (kg/m²-h)

Membrane surface area = 5,021.862 kg/h / 1.43 kg/m²-h = 3,517.948 m².

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To prepare a hydroponic solution with 35 mg/L of phosphorus in a 500 mL volume, you will need to dilute the concentrated calcium dihydrogen phosphate solution.

Firstly, calculate the volume of the concentrated solution required to make the desired concentration. You can apply the formula here:

C1V1 = C2V2

Where C1 is the concentration of the concentrated solution (200 mg/L), V1 is the volume of concentrated solution required, C2 is the desired concentration (35 mg/L), and V2 is the final volume of the solution (500 mL).

Substituting these values, we get:

(200 mg/L) V1 = (35 mg/L) (500 mL)

V1 = (35 mg/L) (500 mL) / (200 mg/L)

V1 = 87.5 mL

So, you need 87.5 mL of the concentrated solution to make 500 mL of the final solution with a phosphorus concentration of 35 mg/L.

To prepare the final solution, measure 87.5 mL of the concentrated solution and add it to a measuring cylinder. Add distilled water to make the remaining 500 mL, and then. Mix the solution well to ensure that the calcium dihydrogen phosphate is evenly distributed.

This will give you a hydroponic solution with a phosphorus concentration of 35 mg/L, which falls within the common range of elemental phosphorus required for growing lettuce.

What is hydroponic solution?

A Hydroponic solution, also known as hydroponic nutrient solution, is a specially formulated liquid mixture of nutrients that is used to grow plants hydroponically. Hydroponics is a method of growing plants in a soil-free medium, where the roots of the plants are suspended in a nutrient-rich solution.

The molar concentration of the solution formed when 0.55 mol of Ca(OH)₂ are dissolved in 2.20 liters of HOH is 0.25 mol/L.

To find molar concentration of a solution use the formula:

Molar concentration = moles of solute / volume of solution in liters

The moles of solute are 0.55 mol of Ca(OH)₂ and the volume of the solution is 2.20 liters of H₂O.

So, the molar concentration of the Ca(OH)₂ solution is:

Molar concentration = 0.55 mol / 2.20 L

Molar concentration ≈ 0.25 mol/L

Therefore, the molar concentration of the Ca(OH)₂ solution is 0.25 mol/L.

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The explanations aq and g are the ones that accurately explain the chemical equation. The appropriate choices are thus C. (so), solid

D. (l), liters

Symbols serve the following four purposes: Motivating others to take action via emotion; socially uniting groups by fostering a sense of common identity and values Clarification and revelation - show insight and clarity into the divine. Communication - conveying emotional components of an event.

The product and reactant symbols have been used to represent the chemical equation. The moles of an element that underwent a reaction are contained in the chemical equation. Prior to the compound, the moles were written as the coefficient.

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The amount heat needed to evaporate 500 g of ice that starts at 0 °C is 1504800 J

First, we shall determine the heat needed to melt the ice. Details below:

H₁ = m × ΔHf

H₁ = 500 × 334

H₁ = 167000 J

Next, we shall determine the heat required to change the water from 0 °C to 100°C. Details below:

H₂ = MCΔT

H₂ = 500 × 4.186 × 100

H₂ = 209300 J

Next, we shall determine the heat required to vaporize the water. Details below:

H₃ = m × ΔHv

H₃ = 500 × 2257

H₃ = 1128500 J

Finally, we shall determine the heat required to evaporate the ice. Details below:

Q = H₁ + H₂ + H₃

Q = 167000 + 209300 + 1128500

Total heat required = 1504800 J

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The difference in pressure between ideal and non-ideal conditions for CO₂ is 23.42 atm.

To find the difference in pressure between ideal and non-ideal conditions for CO₂, we need to use the van der Waals equation:

(P + a(n/V)²)(V - nb) = nRT

where P is the pressure, n is the number of moles, V is the volume, T is the temperature, R is the gas constant, a is a constant related to the attractive forces between molecules, and b is a constant related to the volume of the molecules.

First, we need to calculate the volume of the CO₂ molecules using the given values of n and V:

V/n = V/2.0 mol = 7.30 L/2.0 mol = 3.65 L/mol

Next, we can plug in the given values of a, b, n, V, and T into the van der Waals equation:

(P + a(n/V)²)(V - nb) = nRT

(4.50 atm + 3.59 L²･atm/mol²(2.0 mol/3.65 L)²)(7.30 L - 0.0427 L/mol × 2.0 mol) = 2.0 mol × 0.0821 L･atm/mol･K × 200.0 K

Simplifying the equation, we get:

(4.50 + 3.59(2.0/3.65)²)(7.30 - 0.0427 × 2.0) = 32.19

Therefore, the non-ideal pressure is:

Pnon-ideal = 32.19 atm

To find the ideal pressure, we can use the ideal gas law:

PV = nRT

Pideal = nRT/V = 2.0 mol × 0.0821 L･atm/mol･K × 200.0 K/7.30 L

Pideal = 8.77 atm

Finally, we can calculate the difference in pressure between ideal and non-ideal conditions:

ΔP = Pnon-ideal - Pideal = 32.19 atm - 8.77 atm = 23.42 atm

Therefore, the difference in pressure between ideal and non-ideal conditions for CO₂ is 23.42 atm.

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The percent by mass of hydrogen in CH3COOH is 6.7%. (C)

To calculate the percent by mass of hydrogen in a compound, you need to determine the mass of hydrogen present in relation to the total mass of the compound.

The molecular formula of acetic acid (CH3COOH) indicates that it contains two hydrogen atoms. To calculate the percent by mass of hydrogen, we need to consider the molar mass of hydrogen and the molar mass of acetic acid.

The molar mass of hydrogen (H) is approximately 1.00784 grams per mole, and the molar mass of acetic acid (CH3COOH) can be calculated as follows:

Molar mass of CH3COOH = (molar mass of carbon × 2) + (molar mass of hydrogen × 4) + molar mass of oxygen

= (12.01 g/mol × 2) + (1.00784 g/mol × 4) + 16.00 g/mol

= 24.02 g/mol + 4.03136 g/mol + 16.00 g/mol

= 44.05 g/mol

Now, to calculate the percent by mass of hydrogen, we can use the following formula:

Percent by mass of hydrogen = (mass of hydrogen / total mass of acetic acid) × 100

Since there are two hydrogen atoms in one molecule of acetic acid, the mass of hydrogen is (2 × 1.00784 g/mol) = 2.01568 g/mol.

Plugging the values into the formula, we get:

Percent by mass of hydrogen = (2.01568 g/mol / 44.05 g/mol) × 100= 6.7%

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a. The anode is where oxidation occurs, so the half reaction taking place at the anode is: O₂(g) + 4 H⁺(aq) + 4 e⁻→ 2 H₂O(l)

b. The cathode is where reduction occurs, so the half reaction taking place at the cathode is: 2 H⁺(aq) + 2 e⁻+ 2 H₂S(g) → 2 S(s) + 2 H₂O(l)

c. To calculate the standard cell potential, Eocell, we need to add the reduction potential of the cathode and the oxidation potential of the anode. The reduction potential of the cathode half reaction is +0.15 V, and the oxidation potential of the anode half reaction is -1.23 V. Therefore, Eocell = +0.15 V + (-1.23 V) = -1.08 V.

d. To produce the voltage of -1.08 V, the reaction must be spontaneous, which means that the Gibbs free energy change, ΔG, must be negative.

The relationship between ΔG, Eocell, and the equilibrium constant, K, is: ΔG = -nFEocell = -RTlnK, where n is the number of electrons transferred, F is Faraday's constant, R is the gas constant, and T is the temperature.

Solving for K, we get: K = e^(-ΔG/RT) = e^(-nFEocell/RT).

Substituting the values, we get: K = e^(-(-2)(96485 C/mol)(-1.08 V)/(8.314 J/mol-K)(298 K)) = 4.5 x 10¹⁸. Since the reaction is in acid, the partial pressure of H⁺ is 1 atm.

Using the equilibrium constant expression for the reaction, K = [S]²/[H₂S]², we can solve for the partial pressure of H₂S: P(H₂S) = [S]/√K. Substituting the values, we get: P(H₂S) = (1 atm)/√(4.5 x 10¹⁸) = 6.7 x 10⁻¹⁰atm.

Therefore, the partial pressure of H₂S must be 6.7 x 10⁻¹⁰ atm, and the partial pressure of O₂ must be 1 atm, to produce the voltage in part c.

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The mass of 6.9 moles of nitrous acid (HNO₂) is 324.3 grams.

To calculate the mass of 6.9 moles of nitrous acid (HNO₂), follow these steps:

1. Determine the molar mass of HNO₂.
2. Multiply the molar mass by the given moles (6.9 moles) to find the mass.

Step 1: Determine the molar mass of HNO₂.
HNO₂ consists of 1 hydrogen atom, 1 nitrogen atom, and 2 oxygen atoms.
- The atomic mass of hydrogen (H) is 1 g/mol.
- The atomic mass of nitrogen (N) is 14 g/mol.
- The atomic mass of oxygen (O) is 16 g/mol.

Molar mass of HNO₂ = (1 x 1) + (1 x 14) + (2 x 16) = 1 + 14 + 32 = 47 g/mol.

Step 2: Multiply the molar mass by the given moles (6.9 moles).
Mass of HNO₂ = 6.9 moles × 47 g/mol = 324.3 g.

So, the mass of 6.9 moles of nitrous acid (HNO₂) is 324.3 grams.

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Ketone 1 undergoes different reactions depending on the base used.

When treated with potassium tert-butoxide at room temperature, it produces ketone 2 via an intramolecular aldol reaction.

On the other hand, when treated with LDA at low temperatures, it undergoes a kinetic enolate formation followed by intramolecular cyclization to give an intermediate, which upon heating, eliminates lithium and produces ketone 3. The reaction conditions favor each product due to the different reactivity of the bases.

Potassium tert-butoxide is a strong base and promotes a fast aldol reaction at room temperature, while LDA is a weaker base that requires low temperatures to form the kinetically favored enolate intermediate, which upon heating, undergoes lithium elimination to give ketone 3.

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There are approximately 0.00614 moles of gas in the sample.

To find the number of moles of gas in the sample, we will use the Ideal Gas Law formula: PV = nRT.

Given:
Volume (V) = 155 mL = 0.155 L (converted to liters)
Temperature (T) = 316 K
Pressure (P) = 0.989 atm
Gas constant (R) = 0.0821 L atm / K mol

We need to find the number of moles (n).

Rearranging the formula for n: n = PV / RT


1. Convert the volume to liters: 155 mL = 0.155 L
2. Plug in the given values into the formula: n = (0.989 atm) x (0.155 L) / (0.0821 L atm / K mol) x (316 K)
3. Simplify the equation and solve for n: n ≈ 0.00614 mol

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The substance that will cool the fastest when equal masses are heated to the same temperature is the one with the lowest specific heat.

This is because a substance with a lower specific heat requires less energy to raise its temperature by a certain amount, and therefore it will release heat more quickly when it cools down.

Out of the given substances, substance A has the lowest specific heat of 0.90 J/g-°C, so it will cool the fastest when equal masses are heated to the same temperature.

Substance B has a specific heat of 1.70 J/g-°C, substance C has a specific heat of 2.70 J/g-°C, and substance D has the highest specific heat of 4.18 J/g-°C.

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Ca +Br2 ---> CaBr2

2HNO3 + BaCl2 --->Ba(NO3)2 +2HCl

C7H16 + 11O2 → 7CO2 + 8H2O

Cl2 + 2KI --->2KCl + I2

No reaction

2Na3PO4 + 3Mg(NO3)2 → Mg3(PO4)2 + 6NaNO3

2Al + 3ZnCl2 → 3Zn + 2AlCl3

Li(OH) (ag) + HCI (aq) —>LiCl + H2O

2Na + 2H2O → 2NaOH + H2

The burning splint would make a "pop" sound.

A balanced equation is a chemical equation that has an equal number of atoms of each element on both the reactant and product sides.

In other words, a balanced equation follows the law of conservation of mass, which states that the total mass of the reactants must equal the total mass of the products in a chemical reaction.

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The  statements correctly describe protecting groups are :

"A reactive functional group converted to another functional group and it will not interfere desired reaction."

"The Protecting group easily removed (deprotection) to the regenerate original functional group."

The protecting group are the molecular formula that will be introduced  the specific functional group and which is present in the poly-functional molecule and the protecting group block the reactivity under the some reaction conditions and which is needed to make the modifications in molecule.

The protecting group readily and the protecting group is selectively introduced to functional group in poly-functional molecule. Protecting group is capable of the selectively removed in under some of the mild conditions when protection is no more longer required.

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