9. What is the volume of the triangular prism
below?
5cm
3cm
4cm
3cm

Rachel's beginning balance one year ago was $800.

Compound interest is applicable when there will be a change in the principle amount after the given time period.

For example, if you give anyone $500 at the rate of 10% annually then $500 is your principle amount. After 1 year the interest will be $50 and hence principle amount will become $550 now for the next year the interest will be $550, not $500.

Given that,

The current balance is $836 which is the result of compound interest of 4.5 % annually.

The original amount was a priciple amount P on which interest was applied and the final amount $836 made.

Compound interest formula;

A = P[ 1 + RT/100]^T

Where A is the final amount and T is the time period.

Here,

A = 836 , R = 4.5% and T = 1 year.

So,

836 = P[1 + 4.5/100]^1

P = 836/1.045 = $800

Hence "Rachel's beginning balance one year ago was $800".

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7, 7, 9, 27, 27, are the numbers that we can fill these boxes starting from left.

A prime number is not a composite number, prime numbers are only divisible by the number itself and one.

An example of a prime number is 2 which is only divisible by 2 and 1 it is also the only even prime number.

The only prime number is 7.

The intersection of prime and odd numbers is 7.

The only odd number is 9.

The intersection of odd and cube numbers is 27.

The only cube number is 27.

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yes it is uses in1979 there ie big tsunami

Answer:

the American Embassy in Tehran was overrun and its employees taken captive.

Step-by-step explanation:

All the given equations have 2 real solutions except for equation 4 which has only one real root.

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is  ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

The given quadratic equation

[tex]y = 12x^2 - 9x+ 4[/tex]

where, a = 12, b = -9 and c = 4

x = [tex]-b + \sqrt{b^2 - 4ac} /2a[/tex]

x = [tex]-(-9)+ \sqrt{(-9)^2 - 4(12)(4)} /2(12)[/tex]

x = 1.063 or -0.313

Second Equation

[tex]10x +y = -x^2 +2 \\y = x^{2} +10x - 2[/tex]

where, a = 1, b = 10, c = -2

substitute the values into the equation

x = [tex]-b + \sqrt{b^2 - 4ac} /2a[/tex]

[tex]-10 + \sqrt{10^2 - 4(1)(-2)} /2(1)[/tex]

x = 0.195 or -10.195

Third Equation

[tex]4y - 7 = 5x^2 - x +2 +3y[/tex]

[tex]y = 5x^{2} -x -5[/tex]

where, a = 5, b = -1, c = - 5

x = [tex]-b + \sqrt{b^2 - 4ac} /2a[/tex]

[tex]-(-1) + \sqrt{(-1)^2 - 4(5)(-5)} /2(5)[/tex]

x = 0.905 or -0.55

Fourth Equation

[tex]y = (-x +4)^2 \\y = x^{2} -8x +16[/tex]

where, a = 1, b = -8, c = 16

x = [tex]-b + \sqrt{b^2 - 4ac} /2a[/tex]

x = [tex]-(-8) + \sqrt{(-8)^2 - 4(1)(16)} /2(1)[/tex]

x = 4

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Answer:

y = 12x2 - 9x + 4

✔ no

real solution(s)

4y - 7 = 5x2 - x + 2 + 3y

✔ no

real solution(s)

10x + y = -x2 + 2

✔ two

real solution(s)

y = (-x + 4)2

✔ one

real solution(s)

Step-by-step explanation:

hope this helps:)

Answer:

A on edge 2021

Step-by-step explanation:

I got it correct.

Answer:

y = 3x -2

Step-by-step explanation:

General equation of a line in the slope intercept form is

y = mx + b ,

where m is the slope and b is the y-intercept ( where intercepts the y-axis)

y = 3x + b ,

because is given slope is m = 3

For point (x = -2, y = -8) we have

-8 = 3 (-2) + b

-8 = -6 + b

-8 + 6 = b

-2 = b

The equation of the line that passes through the point (-2,-8) and has a slope of 3 is

y = 3x -2

Answer:

A cube is a rectangular prism where all its sides are the same. The formula to find the surface area of a rectangular prism is A = 2wl + 2lh + 2hw, where w is the width, the l is the length, and the h is the height.

The surface area formula for a cube is 6l²

A cube has the following features:

The area of a face of a cube is:

Area = l²

Where l represents the side length

The surface area formula for a cube is then calculated using:

Surface area = 6 * Area of a face

So, we have:

Surface area = 6 * l²

Surface area = 6l²

Hence, the surface area formula for a cube is 6l²

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Answer:

hey i am doing god how are you and i dont know what i am doing for easter. My favorite holiday is christmas and easter. My favorite subjects in school are math and reading. I love school.

Step-by-step explanation:

All polynomials are continuous, so the limit can be evaluated by direct substitution:

[tex]\displaystyle \lim_{x\to-3} (x^3+3x^2+4x-12) = (-3)^3+3(-3)^2+4(-3)-12 = \boxed{-24}[/tex]

The Limit of (x cubed + 3 x squared + 4 x minus 12) as x approaches negative 3 is -24.

Polynomials are those algebraic expressions that consist of variables, coefficients, and constants. The standard form of polynomials has mathematical operations such as addition, subtraction, and multiplication.

All polynomials are continuous, so the limit can be evaluated by direct substitution:

[tex]\lim_{x \to {-3}} x^3 + 3 x ^2+ 4 x - 12\\\\= (-3)^3 + 3 (-3)^2+ 4 (-3)- 12\\\\= -24[/tex]

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Answer: 36

Step-by-step explanation: Ratio 27:36 is also 3:4

Answer:

36 games

Step-by-step explanation:

since the ratio is 3:4 we must get what the original is.

27/3=9

27+9=36

27:36

The difference between the polynomial is [tex]\rm 9x^3-5x^2-6x+10[/tex].

The subtract means to take away from a group or a number of things.

Lorne subtracted 6x3 – 2x + 3 from –3x3 + 5x2 + 4x – 7.

The difference between the expression is;

[tex]\rm ( 6x^3 - 2x + 3 )- (-3x^3 + 5x^2 + 4x - 7)[/tex]

[tex]\rm 6x^3 - 2x + 3 +3x^3 -5x^2 -4x +7\\\\9x^3-5x^2-6x+10[/tex]

Hence, the difference between the polynomial is [tex]\rm 9x^3-5x^2-6x+10[/tex].

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Answer:

1. Growth

2. Growth

3. Decay

Answer:

24 books

Step-by-step explanation:

Books are valued at $10/3 books.  18 books would have a value of (18books)*($10/3books) = $60, and so on.

X books would have a value of X($10/3)=$80

X = ($80)*(3/$10)

X = 24 books

The total of Melinda's expenses for the week is $93.04 option (c) $91.94 is correct.

It is defined as the money spends on the utility, the amount of money is required to buy something in other words it is the outflow of money from the solely earners income or the money incurred by any organization.

Melinda kept a record of her spending for the week as follows:

The amount she spent money to put gas in the car = $25

The amount to buy a new shirt = $22.38

The amount to play putt-putt golf with some friends = $6.95

The amount to buy groceries = $38.71

To calculate the total expenses for the week, we must add all the expenses:

= $25+$22.38+$6.95+38.71

= $93.04

Thus, the total of Melinda's expenses for the week is $93.04 option (c) $91.94 is correct.

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Answer:

Pretty sure it's "only i"

Step-by-step explanation:

A constant rate of change means that something changes by the same amount during equal intervals.

$30 is the same amount whereas 10% could vary.

Hope this helps.

Generally, you'd see the equation of a circle organized in the following format:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

To determine the equation given the center and the radius:

We're given:

Plug the radius and center into the equation as r and (h,k):

[tex](x-(-1))^2+(y-(-8))^2=99^2\\(x+1)^2+(y+8)^2=9801[/tex]

[tex](x+1)^2+(y+8)^2=9801[/tex]

Heyo!

SaddySokka is here to help!!

Let's do this step-by-step explanation!

[tex]=\frac{5^-^6}{5^3}[/tex]

[tex]=5^-^6^-^3[/tex]

[tex]=5^-^9[/tex]

[tex]=\frac{1}{5^9}[/tex]

Answer:

A. [tex]\frac{1}{5^9}[/tex]

Hopefully, this helps you!!

Have a great day!!

SaddySokka~

Answer:

Yes, I agree with Noah because the first lake has a smaller mean and MAD than the second

Step-by-step explanation:

Answer:

Step-by-step explanation: y axis is 6units up (y=+6)

X axis is 2units to the right. (×=+2)

Answer:

(1,12) ; (2,9) ; (3,6) ; (4,3) ; (5,0)

Step-by-step explanation:

You need to plug the x values into the equation.

Your equation: y=15-3x

Example:

Plug in 1

y=15-3

y=12

Plug in 2:

y=15-3(2)

y=15-6

y=9

Plug in 3:

y=15-3(3)

y=15-9

y=6

Plug in 4:

y=15-3(4)

y=15-12

y=3

Plug in 5:

y= 15-3(5)

y=15-15

y=0

The measure of PQ if the triangle LMN is similar to triangle OPQ is 69.4

Similar triangles are triangles that have equal sides and angles. The ratio of the similar sides is a constant.

According to the triangle given:

PQ/17 = OQ/LM
PQ/17 = 49/12
12PQ = 833
PQ = 69.4

Hence the measure of PQ if the triangle LMN is similar to triangle OPQ is 69.4

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[tex]\text{L.H.S}\\\\=\sin^2 \theta \tan \theta + \cos^2 \theta \cot \theta+2\sin \theta \cos \theta \\\\\\=\sin^2 \theta \cdot \dfrac{\sin \theta}{\cos \theta} + \cos^2 \theta \cdot \dfrac{\cos \theta}{\sin \theta} + 2\sin \theta \cos \theta\\\\\\=\dfrac{\sin^3 \theta}{\cos \theta}+ \dfrac{\cos^3 \theta}{\sin \theta}+ 2\sin \theta \cos \theta\\\\\\=\dfrac{\sin^4 \theta + \cos^4 \theta}{\cos \theta \cdot \sin \theta}+ 2\sin \theta \cos \theta\\\\[/tex]

[tex]=\dfrac{(\sin^2 \theta)^2 + (\cos^2 \theta)^2 }{\cos \theta \sin \theta}+ 2\sin \theta \cos \theta\\\\\\=\dfrac{(\sin^2 \theta + \cos^2 \theta)^2-2\sin^2 \theta \cos^2 \theta}{\cos \theta \sin \theta}+ 2\sin \theta \cos \theta\\\\\\=\dfrac{1-2 \sin^2 \theta \cos^2 \theta}{\cos \theta \sin \theta}+ 2\ sin \theta \cos \theta\\\\\\=\dfrac{1-2\sin^2 \theta \cos^2 \theta+2\sin^2 \theta \cos^2 \theta}{\cos \theta \sin \theta}\\\\=\dfrac 1{\cos \theta \sin \theta}\\\\[/tex]

[tex]=\dfrac{\sin^2 \theta + \cos^2 \theta}{\sin \theta \cos \theta}\\\\\\=\dfrac{\sin^2 \theta}{\cos \theta \sin \theta}+\dfrac{\cos^2 \theta}{\cos \theta \sin \theta}\\\\\\=\dfrac{\sin \theta}{\cos \theta}+\dfrac{\cos \theta}{\sin \theta}\\\\\\=\tan \theta + \cot \theta\\\\=\text{R.H.S}\\\\\text{Proved.}[/tex]

The lower quartile is 43.

[tex]\\ \rm\dashrightarrow x^{\frac{2}{7}}[/tex]

[tex]\\ \rm\dashrightarrow x^{2(1/7)}[/tex]

[tex]\\ \rm\dashrightarrow \sqrt[7]{x^2}[/tex]

And

[tex]\\ \rm\dashrightarrow \sqrt[3]{2y}[/tex]

[tex]\\ \rm\dashrightarrow 2y^{\frac{1}{3}}[/tex]

Answer:

see below

Step-by-step explanation:

Problem-1:

[tex] {x}^{ \frac{2}{7} } [/tex]

remember that,

[tex]\displaystyle {x}^{ \frac{a}{b} } = \sqrt[b]{ {x}^{a} } [/tex]

here,

hence,

[tex] {x}^{ \frac{2}{7} } = \boxed{\sqrt[7]{ {x}^{2} } }[/tex]

Problem-2:

recall that,

[tex] \sqrt[n]{x} = {x}^{ \frac{1}{n} } [/tex]

therefore,

[tex] \sqrt[3]{2y} = (2y {)}^{ \frac{1}{3} } \implies \boxed{{2 }^{ \frac{1}{3} } {y}^{ \frac{1}{3} } }[/tex]

Answer:

B) formation of a precipitate
E) change in color

Step-by-step explanation:

just did the assignment on e.d.g.e

Answer:

B and E is correct

Step-by-step explanation: