Solution :
a). Applying the energy balance,
[tex]$\Delta E_{sys}=E_{in}-E_{out}$[/tex]
[tex]$0=\Delta U$[/tex]
[tex]$0=(\Delta U)_{iron} + (\Delta U)_{water}$[/tex]
[tex]$0=[mc(T_f-T_i)_{iron}] + [mc(T_f-T_i)_{water}]$[/tex]
[tex]$0 = 27 \times 0.45 \times (T_f - 375) + 130 \times 4.18 \times (T_f-26)$[/tex]
[tex]$t_f=33.63^\circ C$[/tex]
b). The entropy change of iron.
[tex]$\Delta s_{iron} = mc \ln\left(\frac{T_f}{T_i} \right)$[/tex]
[tex]$ = 27 \times 0.45\ \ln\left(\frac{33.63 + 273}{375 + 273} \right)$[/tex]
= -9.09 kJ-K
Entropy change of water :
[tex]$\Delta s_{water} = mc \ \ln\left(\frac{T_f}{T_i} \right)$[/tex]
[tex]$ = 130 \times 4.18\ \ln\left(\frac{33.63 + 273}{26 + 273} \right)$[/tex]
= 10.76 kJ-K
So, the total entropy change during the process is :
[tex]$\Delta s_{tot} = \Delta s_{iron} + \Delta s_{water} $[/tex]
= -9.09 + 10.76
= 1.67 kJ-K
c). Exergy of the combined system at initial state,
[tex]$X=(U-U_{0}) - T_0(S-S_0)+P_0(V-V_0)$[/tex]
[tex]$X=mc (T-T_0) - T_0 \ mc \ \ln \left(\frac{T}{T_0} \right)+0$[/tex]
[tex]$X=mc\left((T-T_0)-T_0 \ ln \left(\frac{T}{T_0} \right)\right)$[/tex]
[tex]$X_{iron, i} = 27 \times 0.45\left(((375+273)-(12+273))-(12+273) \ln \frac{375+273}{12+273}\right)$[/tex]
[tex]$X_{iron, i} =63.94 \ kJ$[/tex]
[tex]$X_{water, i} = 130 \times 4.18\left(((26+273)-(12+273))-(12+273) \ln \frac{26+273}{12+273}\right)$[/tex]
[tex]$X_{water, i} =-13.22 \ kJ$[/tex]
Therefore, energy of the combined system at the initial state is
[tex]$X_{initial}=X_{iron,i} +X_{water, i}$[/tex]
= 63.94 -13.22
= 50.72 kJ
Similarly, Exergy of the combined system at initial state,
[tex]$X=(U_f-U_{0}) - T_0(S_f-S_0)+P_0(V_f-V_0)$[/tex]
[tex]$X=mc\left((T_f-T_0)-T_0 \ ln \left(\frac{T_f}{T_0} \right)\right)$[/tex]
[tex]$X_{iron, f} = 27 \times 0.45\left(((33.63+273)-(12+273))-(12+273) \ln \frac{33.63+273}{12+273}\right)$[/tex]
[tex]$X_{iron, f} = 216.39 \ kJ$[/tex]
[tex]$X_{water, f} = 130 \times 4.18\left(((33.63+273)-(12+273))-(12+273) \ln \frac{33.63+273}{12+273}\right)$[/tex]
[tex]$X_{water, f} =-9677.95\ kJ$[/tex]
Thus, energy or the combined system at the final state is :
[tex]$X_{final}=X_{iron,f} +X_{water, f$[/tex]
= 216.39 - 9677.95
= -9461.56 kJ
d). The wasted work
[tex]$X_{in} - X_{out}-X_{destroyed} = \Delta X_{sys}$[/tex]
[tex]$0-X_{destroyed} = $[/tex]
[tex]$X_{destroyed} = X_{initial} - X_{final}$[/tex]
= 50.72 + 9461.56
= 9512.22 kJ
You have three solutions of nickel complex ions, one is blue, one is violet, and one is green. Match the complex ion with the correct solution color.
A. [Ni(en)3]2+
B. [Ni(H2O)6]2+
C. [Ni(NH3)5]2+
Answer:
Explanation:
A. [Ni(en)₃]²⁺ --------- Violet
B. [Ni(H₂O)₆]⁺² -------Green
C. [Ni(NH₃)₅]⁺² ---------Blue .
please no links and round two decimal places
Answer:
https://vm.tiktok.com/ZMet3FuC2/
Which of the living things in the pond system uses the energy from sunlight
to make its own food?
A:water lily
B:insect
C:frog
D:small fish
A. water lily
It is a plant. Plants are autotrophs. They make their own food.
Answer:
i am not sure with the answer.
but i think it will be water lily Or insects
A gas occupies 12.5 ft at - 173 °C. At what Celsius temperature will its volume be 16.0
it? Assume that pressure remains constant
Answer:
T₂ = 128.19 K
Explanation:
Given that,
The initial volume, V₁ = 12.5 ft³
Initial temperature, T₁ = -173 °C = 100.15 K
Final volume, V₂ = 16 ft³
We need to find the new temperature. The relation between temperature and volume is given by :
[tex]V\propto T\\\\\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}[/tex]
Put all the values,
[tex]T_2=\dfrac{T_1V_2}{V_1}\\\\T_2=\dfrac{100.15\times 16}{12.5}\\\\T_2=128.19\ K[/tex]
So, the new temperature is 128.19 K.
20. A compound's empirical formula is C,H,O. If the molecular mass of the compound is
162.2g, what is the molecular formula?
NO LINKS PLEASE THIRD TIME IM POSTING THIS ITS DUE IN 8min
Answer:
Just use a text book.. So that you get the concept
A chemist morning commute is 40.2 kilometers. Given an average speed pf 60.5 mph, how many minutes will it take him to arrive at work?
A chemist morning commute is 40.2 kilometers. Given an average speed pf 60.5 mph, 0.66 minutes will it take him to arrive at work.
What is average speed ?The overall distance the object covers in a given amount of time is its average speed. A scalar value represents the average speed. It has no direction and is indicated by the magnitude.
If you know how far something has travelled and how long it took to get there, you can calculate its average speed. Speed is calculated as follows: speed = distance * time.
Distance = speed × time
40.2 = 60.5 × time
time = 40.2 / 60.5
= 0.66 minutes
Thus, A chemist morning commute is 40.2 kilometers. Given an average speed pf 60.5 mph, 0.66 minutes will it take him to arrive at work.
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PLEASE HELP! 80 POINTS
Create a VESPR drawing for
NH3
CH20
N3
SO2CI2
BrF5
Answer:
hope it helps you
How many grams of KCl, are soluble in 100 g of water at 60 ºC?
a)15g
b)35g
c)45g
d)90g
45 g
the solubility of KCl in water at 60 degree c is 45.5g per 100g of water
What mass of ocean water in grams contains 50.8 g of NaCl?
Answer:
1451.42 g
Explanation:
Let assume that the mass of ocean water comprises 3.5%
NaCl = 3.5%
[tex]3.5 = \dfrac{50.8}{mass \ of \ ocean \ water } \times 100[/tex]
[tex]mass \ of \ ocean \ water = \dfrac{50.8}{3.5 } \times 100[/tex]
mass of the ocean water = 1451.42 g
Matthew added a sample of sodium chloride to water and
found the poH to be 2,55. What is the pH of the salt solution?
pH
Answer:
11.45
Explanation:
The ph is just 14-pOH so
14-2.55=ph=11.45
What is the best way to avoid bacterial contaminantion?
Answer:
Wash hands and surfaces often. Harmful bacteria can spread throughout the kitchen and get onto cutting boards, utensils, and counter tops. To prevent this: Wash hands with soap and hot water before and after handling food, and after using the bathroom, changing diapers; or handling pets.
At 25.0° C, a 10.00 L vessel is filled with 5.25 moles of Gas A and 7.75 moles of Gas B. What is the total pressure in atm?
Answer:
23.12 atm
Explanation:
First, add together the moles of the two samples:
5.25 moles + 4.20 moles = 9.45 moles
273 + 25 = 298 K for the temperature
volume is 10.0 L
Since we have moles now, we have to rearrange our ideal law equation to solve for pressure:
[tex]P = \frac{nRT}{V}[/tex]
[tex]\frac{(9.45 moles) X (0.08206) X (298 K)}{10.0 L}[/tex]
9.45 X .08206 X 298 all divided by 10.0 = 23.09202 atm (or 23.12)
In "The Philosophy of the Manufacturers" by Andrew Ure, the author compares a factory worker to a handmade
worker. The author leads the reader to the idea that the factory worker is better off. Choose evidence (a quote
from the text) to support this idea.
a. Certainly no muscular fatigue to sustain, while it procures for him good, unfailing wages, besides a
healthy workshop gratis.
b. The lot of mankind, have been too little dwelt upon; while, on the other har, it has been accused of
lending itself to the rich capitalists as an instrument for harassing the poor.
c. The principle of the factory system then is, to substitute mechanical science for hand skill, and the
partition of a process into its essential constituents.
"Certainly no muscular fatigue to sustain, while it procures for him good, unfailing wages, besides a healthy workshop gratis."
What idea does the quote supports?The concept that factory workers have it better than handcrafted workers is supported by this textual quotation since it implies that factory work is less physically taxing and offers better pay and working conditions.The author is suggesting that factory worker is in better position than hand worker.This is beneficial for the worker, as it means they can work for longer periods of time without experiencing the same level of exhaustion.Finally, the quote states that a factory provides a "healthy workshop gratis" which means that the factory provides a healthy and clean working environment for the worker without any additional costs. This is beneficial for the worker, as it means they can work in a safe and healthy environment, which is not always the case for hand workers.To know more about healthy workshop conditions quote, check out :
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Pls help with question a and b.
a) 1 - Trigonal planar 2 - Trigonal planar
b) 1- Linear 2 - Tetrahedral 3 - Tetrahedral
c) 1 - Trigonal planar 2 - Tetrahedral
What are the shapes?We have to know that the shapes at the various carbon atoms and other atoms would depend on the number of the electron pairs and the hybridization of the atom.
We must have to note that the shape of the atom can be found on the basis of the valence shell electron pair repulsion theory which deals with the arrangement of that electrons around the outermost shell of the central atom.
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Hello!
please help me!
The nerve gas phosgene decomposes according to COC12(g) - CO(g) + Cl2(g), K = 0.32 at 1000 K. If
the initial concentration of phosgene is 0.015 M. what are the equilibrium concentrations of all gases?
Answer:
[tex][CO]=[Cl_2]=0.01436M[/tex]
[tex][COCl_2]=0.00064M[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction at equilibrium, we can set up the equilibrium expression as follows:
[tex]K=\frac{[CO][Cl_2]}{[COCl_2]}[/tex]
Which can be written in terms of x, according to the ICE table:
[tex]0.32=\frac{x^2}{0.015M-x}[/tex]
Thus, we solve for x to obtain that it has a value of 0.01436 M and therefore, the concentrations at equilibrium turn out to be:
[tex][CO]=[Cl_2]=0.01436M[/tex]
[tex][COCl_2]=0.015M-0.01436M=0.00064M[/tex]
Regards!
What is the molarity of a solution composed
of 4.27 g of potassium iodide (KI) dissolved in
enough water to make 0.304 L of solution?
Answer in units of M.
Answer:
0.0845 M
Explanation:
First we convert 4.27 grams of potassium iodide into moles, using its molar mass:
Molar Mass of KI = 166 g/mol4.27 g ÷ 166 g/mol = 0.0257 molNow we calculate the molarity of the solution, using the number of moles and the given volume:
Molarity = moles / litersMolarity = 0.0257 mol / 0.304 L = 0.0845 MWhat contributes to water's properties?
Polar molecule
Shape of the molecule
All of the other options are correct
Oxygen is more electronegative than hydrogen
why is carbon IV oxide and water removed before liquefication of air?
Answer:
Because when they unfreeze and are cooled they would block pipes of the air liquefaction plant and make the air colder, hope this helps!!
Find the molarity of a solution in which 0.99 mol of NaCl are dissolved in 2.5 L of solution.
Answer:
0.369M
Explanation:
[tex]\boxed{Molarity = mole \div volume}[/tex]
☆ Volume has to be in litres
Molarity of solution
= 0.99 ÷2.5
= 0.369 M
__PbSO4 → __ PbSO3 +__O2
Balance the equation and indicate the type of reaction
CHEMISTRY - DOES ANYONE KNOW HOW TO DO THIS QUESTION???
Cathode: 2 Ag+ (aq) + 2 e- → 2 Ag (s). Anode: 2 H+ (aq) → H2 (g) + 2 e-.
What is cathode ?
A cathode is an electrode in an electrical circuit from which electrons flow out. It is usually made of metal and is negatively charged. Cathodes are commonly used in electronic devices such as batteries, lamps, and vacuum tubes. In a battery,
the cathode is the terminal which provides a negative charge and is usually connected to the negative terminal of the battery. In a vacuum tube, the cathode is the source of electrons which flow through the tube to the anode, which is the positive terminal.
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What is the molarity of a solution containing 2 moles of sodium hydroxide (NaOH) dissolved in 4.0 L of solution?
Answer:
0.5M
Explanation:
Molarity = Mols/ Liters
so 2/4
0.5 M
Q)A certain mass of gas occupies a volume 2.5 L at 90atm. What pressure would the gas exert if it were placed in a 10 L container at the same temperatur?
Answer:
23 atm
Explanation:
Step 1: Given data
Initial volume (V₁): 2.5 LInitial pressure (P₁): 90 atmFinal volume (V₂): 10 LFinal pressure (P₂): ?Step 2: Calculate the final pressure of the gas
If we assume constant temperature and ideal behavior, we can calculate the final pressure of the gas using Boyle's law.
P₁ × V₁ = P₂ × V₂
P₂ = P₁ × V₁ / V₂
P₂ = 90 atm × 2.5 L / 10 L = 23 atm
As expected, since the volume increased, the pressure decreased.
If the temperature of 85.0 g of copper changes from 28.0°C to 99.0°C, how much
heat was absorbed? The specific heat capacity of copper is 0.385 J/K:g. Write your
answer to 3 sig figs.
Answer:
2320 J
Explanation:
We'll begin by calculating the change in temperature of the copper. This can be obtained as follow:
Initial temperature (T₁) = 28.0 °C
Final temperature (T₂) = 99.0 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 99 – 28
ΔT = 71 °C
Finally, we shall determine the heat absorbed by the copper. This can be obtained as follow:
Mass of copper (M) = 85 g
Change in temperature (ΔT) = 71 °C
Specific heat capacity (C) = 0.385 J/K.g
Heat (Q) absorbed =?
Q = MCΔT
Q = 85 × 0.385 × 71
Q = 2320 J
Thus, the heat absorbed is 2320 J
The ionization energies of Calcium are (in KJ/mol): 1st: 589.8 2nd: 1145.4 3rd: 4912.4
Explain why there is such a large jump from 2nd to 3rd ionization energy.
pleaseeee i need help, my brain is just not getting it
Answer:
See whole explanation to understand
Explanation:
the reason why there is such a large jump from 2nd to 3rd ionization energy for calcium is because to remove the third electron, a larger amount of energy is required, since the shell is closer to the nucleus, and higher attraction exists between them. This is why the second ionization energy is 1125.4 and then the third IE is 4912.4 which is a very big difference. It's all about the elections and energy!!
Atoms of different element can not have same atomic number because only same type of atoms combine to form element. Atoms belonging to different element can have different atomic number. Therefore, higher attraction between shell and nucleus, there is such a large jump from 2nd to 3rd ionization energy.
What is element?Element generally consist of atoms or we can atoms combine to form element. Atoms of an element is always same, means all the properties of all atoms of one type of element is same. Two or more than two atoms with different physical or chemical properties can not combine together to form an element.
The reason why there is such a large jump from 2nd to 3rd ionization energy for calcium is because to remove the third electron, a larger amount of energy is needed, since the shell is closer to the nucleus, and higher attraction exists between them.
Therefore, higher attraction between shell and nucleus, there is such a large jump from 2nd to 3rd ionization energy.
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Students performed an investigation on how aluminum cans taken to a recyle center were able to be reused. They found out an aluminum can undergoes which type of change?
a physical change because the can is heated
a chemical change because new metal is formed
a physical change because the material remains the same
a chemical change because an old can is changed into a new can
Answer:
The correct answer is - a physical change because the material remains the same.
Explanation:
A chemical change is the change that results in the formation of the new element or the substance whereas the physical change remains the same material or substance even after the change.
The physical change can be a change in density, size, shape, or volume, and other properties. In the recycling of the aluminum can the material remain the same only shape or size of the aluminum change order to reuse.
Answer:
its D i promise
Explanation:
a gas occupies a volume of 95 mL when the pressure is 400 mmHg .what volume does the gas occupy at 1200 mmhg if the temperature
Answer:31.7ml
Explanation:
g h g jg jh gj h g jhg u iga ff f. f. f f f
why is heat or thermal energy considered a form of kinetic energy
If hydrogen diffuses at the rate of 10 cm³ per second from a given apparatus under given conditions of temperature and pressure, calculate under same conditions: a) the volume of oxygen (O₂) which diffuses in 20 seconds
Answer:
Volume of O₂ = 200cm³
Explanation:
Rate of diffusion of gas is directly and inversely proportional to the volume and time taken for the gas to diffuse completely.
Volume
R = -----------
time
let R₁ represent the rate at which the given volume of hydrogen gases diffuses and R₂ represent the rate at which the the volume of the oxygen gas diffused.
V₁, V₂, T₁ and T₂ follows the same process
If the two gases diffuses at the same rate, then;-
R₁ = R₂
V₁ V₂
---------- = ------------
T₁ T₂
V₂
10 = ----------------
20
V₂ = 20•10
V₂ = 200cm³
Therefore, the volume of oxygen that could diffuse in 20 seconds is 200cm³