a 30kg mass is placed on a 15cm spring and compressed to 12cm how much work is required to compress spring from 12cm to 10 cm

The Neocrystallization topic of the Metamorphic Change Animation options are A (Neocrystalline garnets form), B(Existing minerals become elongated and take on a foliation), and D. (Existing minerals undergo plastic deformation. E. Neocrystalline garnets are compressed.)

Based on the information provided, during the transition of mudstone to schist through neocrystallization:
A. Neocrystalline garnets form - This occurs as new minerals, like garnets, form during the metamorphic process.
B. Existing minerals become elongated and take on a foliation - As the mudstone undergoes metamorphism, the existing minerals align and elongate, developing a foliation.
D. Existing minerals undergo plastic deformation - During metamorphism, pressure and temperature changes cause the minerals to undergo plastic deformation, changing their shape and size.
Based on the Neocrystallization topic of the Metamorphic Change Animation, the following occur during the transition of mudstone to schist: - Existing minerals become elongated and take on a foliation - Neocrystalline garnets form Therefore, options A and B are the correct answers.
So, the correct options are A, B, and D.

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Approximately [tex]1.31 \times 10^{20}[/tex] electrons are transferred in a strong lightning bolt carrying an electric charge of 21 C.

The electric charge of one electron is equal to [tex]-1.602 \times 10^{-19}[/tex] Coulombs (C). Therefore, we can calculate the number of electrons transferred by dividing the total charge transferred by the charge of a single electron:

Number of electrons = Total charge transferred / Charge of a single electron

Number of electrons = [tex]\frac{21 C }{-1.602 \times 10^{-19} C}[/tex]

The number of electrons ≈ [tex]1.31 \times 10^{20} electrons[/tex]

Hence the number of electrons transferred during the lightning bolt is [tex]1.31 \times 10^{20}[/tex].

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Not all comet nuclei become active, comets have highly elliptical orbits, and can be obscured by other celestial bodies.

Despite the fact that stargazers gauge that there might be a trillion comet cores circling past Pluto, we don't see more comets in that frame of mind because of different elements. To begin with, not all comet cores become dynamic and form into comets. Second, numerous comets have profoundly circular circles that benefit them from the inward planetary group, where they are not apparent from Earth. Third, comets can be darkened by other heavenly bodies, like planets or stars. At last, numerous comets have extremely lengthy orbital periods, requiring hundreds or even millennia to finish a solitary circle, and hence may not be apparent during a human lifetime. Furthermore, the brilliant comets that are noticeable from Earth are frequently generally uncommon and happen inconsistently, making them much more extraordinary and energizing to see when they do show up.

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The problem involved calculating the speed of an airplane using the change in wavelength of radio waves it emits. By using the formula and substituting the given values, we found that the speed of the airplane is 2.5 x 10^5 m/s.

The given information can be summarized as:

The wavelength of the radio wave emitted by the airplane = λ_emitted = 1.2 m

The wavelength of the radio wave received at the airport = λ_received = λ_emitted + 1.1 x 10^-6 m

The speed of the radio wave = v_wave = 3.0 x 10^8 m/s

We can use the formula given in the problem to find the speed of the airplane:

change of wavelength = speed of airplane x wavelength / speed of radio wave

Substituting the given values, we get:

λ_received - λ_emitted = speed of airplane x λ_emitted / v_wave

Simplifying and solving for the speed of the airplane, we get:

speed of airplane = (λ_received - λ_emitted) x v_wave / λ_emitted

Plugging in the values, we get:

speed of airplane = (1.2 + 1.1 x 10^-6 - 1.2) x 3.0 x 10^8 / 1.2

speed of airplane = 2.5 x 10^5 m/s

Therefore, the speed of the airplane is 2.5 x 10^5 m/s.

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The apparent weight of a person with a mass of 78 kg in an elevator accelerating upward at 1.80 m/s2 is 91.2 kg.

This is calculated using the equation: apparent weight = mass x acceleration due to gravity + acceleration of elevator, which equals 78 kg x 9.81 m/s2 + 1.80 m/s2 = 91.2 kg.

Steps:

Therefore, the apparent weight of the person is 767.78 N + 140.4 N = 908.18 N.

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The given statement a constructor which has thrown an exception will also return a reference to its constructed object is false  because when an exception is thrown during the construction of an object, the constructor does not complete its initialization process.

As a result, the constructed object may be in an invalid or partially constructed state, which can lead to unexpected behavior if the object is used later in the program. A constructor cannot return a value, not even a reference to its constructed object. Instead, the constructor initializes the object's data members and sets up the object's state. If a constructor throws an exception, the object is not fully constructed and is therefore not valid. The exception can be caught and handled by the caller of the constructor.

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Answer: The magnitude of the acceleration of the laundry cart is 20.32 m/s2.

The magnitude of the acceleration of the laundry cart can be calculated using the equation F = ma, where F is the force applied, m is the mass of the object and a is the acceleration.

We can rearrange the equation to solve for acceleration: a = F/m.

Plugging in the values we know, the acceleration of the laundry cart is:

a = 63N / 3.1kg = 20.32 m/s2

Therefore, the magnitude of the acceleration of the laundry cart is 20.32 m/s2.



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The magnitude of the impulse delivered to the bullet by the block during this time is 0.90 Ns.

The mass of the bullet is given as 0.010 kg and its initial speed as 100 m/s. After travelling 0.10 m, the bullet comes to rest in a wooden block. The time taken for the bullet to stop is 0.02 seconds. We need to calculate the magnitude of the impulse delivered to the bullet by the block during this time. We can use the formula for impulse, which is Impulse = Force × Time. Impulse is defined as the change in momentum. Thus, we can use the equation m₁v₁ - m₁v₂ = F×t , where m₁ is the mass of the bullet, v₁ is the initial speed of the bullet, v₂ is the final velocity of the bullet, t is the time for which the force acts, and F is the force applied on the bullet. In this case, we know the mass and initial speed of the bullet. We need to find the final velocity of the bullet to calculate the force. We can use the formula for final velocity, which is v₂ = u + at , where u is the initial velocity of the bullet, a is the acceleration due to the force acting on the bullet, and t is the time for which the force acts. Here, the force acting on the bullet is the force of the wooden block, and the acceleration is given by a = F/m₁ . Thus, we have v₂ = u + F/m₁ × t . The distance travelled by the bullet is given as 0.10 m. We can use the formula for distance travelled, which is s = ut + ½at² . Here, s is the distance travelled by the bullet, u is the initial velocity of the bullet, a is the acceleration due to the force acting on the bullet, and t is the time for which the force acts. We have u = 100 m/s, s = 0.10 m, and t = 0.02 s. We can use this equation to calculate the acceleration of the bullet. Solving for a, we get a = (2s - ut) / t² = (2 × 0.10 - 100 × 0.02) / (0.02)² = -450 m/s². Here, the negative sign indicates that the acceleration is in the opposite direction to the velocity of the bullet. Substituting this value of a in the equation for v₂, we get v₂ = 100 - 450 × 0.02 / 0.010 = 10 m/s. Thus, the change in velocity of the bullet is Δv = v₂ - v₁ = 10 - 100 = -90 m/s. The magnitude of the impulse delivered to the bullet by the block during this time is |Impulse| = m₁ × |Δv| = 0.010 × 90 = 0.90 Ns. Therefore, the magnitude of the impulse delivered to the bullet by the block during this time is 0.90 Ns.

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The trailer pulls on the vehicle with an average force of A=B=C.

Newton's second law of acceleration is expressed as follows: F = ma

In this case, the mass is m, and the acceleration is a.

Assume that g=9.8 m/s2 represents the acceleration caused by gravity.

The acceleration of the object will be zero if it is travelling at a constant speed.

Because of the constant velocity, the van's net force on the trailer is therefore zero.

As a result, the van applies the same amount of force to each trailer. Thus, FA FB = FC.

As a result, each trailer pulls on the van with the same amount of force in the opposite direction. FA' = FB' = Fc', therefore.

As a result, A=B=C represents the rank of the force the trailer exerts on the van.

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The strobe light's flashes occur at a 70 Hz frequency.

The frequency of a sound pressure wave, also known as pitch, is the quantity of times every second that it repeats. A bullfrog cry is far downward communication than a whistle, while a cricket is much downward communication than a drum beat.

T is the amount of time between flashes in seconds, and f is the frequency expressed in Hertz (Hz).We obtain the following value by inserting the given value: f = 1 / (1/70) f = 70 Hz.

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The boat will bob up and down on ocean waves that have a wavelength of 36.0 m and a propagation speed of 4.80 m/s once every 7.50 seconds.

To solve the given question, we must use the formula:

n= v/f

Where: v is the velocity of the wave (in m/s)f is the frequency of the wave (in Hz)n is the number of cycles per second

Therefore, the frequency of the wave (in Hz) can be calculated by using the formula:

f= v/λ

where: v is the velocity of the wave (in m/s)λ is the wavelength of the wave (in m)

The frequency of the wave is 0.1333 Hz (approx).

Now, the number of cycles per second (n) is: n = v/λ

We can solve for n by dividing the velocity of the wave by the wavelength of the wave.

Therefore,

n= v/λ= (4.80 m/s) / (36.0 m)= 0.1333 Hz

So, the boat bob up and down 0.1333 times a minute on ocean waves that have a wavelength of 36.0 m and a propagation speed of 4.80 m/s.

1 Hz = 60 seconds,

0.1333 Hz = 7.50 seconds.

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A 7.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between the block and the surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.390 m along the surface before stopping the initial velocity of the bullet was 958 m/s.

First, let's calculate the momentum of the bullet before the collision. Momentum is defined as mass times velocity, so we need to find the velocity of the bullet. We can use the fact that the bullet remains embedded in the block to determine the final velocity of the bullet-block system. The momentum of the system is equal to the mass of the system times its velocity.
Let's call the initial velocity of the bullet "v". The mass of the system is the mass of the bullet plus the mass of the block, which is 7.00 g + 1.20 kg = 1.207 kg. After the collision, the block and bullet move together at a final velocity of "vf". We can use the fact that the block slides 0.390 m along the surface before stopping to determine vf. The work done by friction is equal to the force of friction times the distance over which it acts. This work is equal to the change in kinetic energy of the system, which we know is equal to the initial kinetic energy of the bullet. We can write:
frictional force x distance = 1/2 x m x v^2
The frictional force is equal to the coefficient of kinetic friction times the normal force, which is equal to the weight of the block. We can write:
0.20 x 1.20 x 9.81 x 0.390 = 1/2 x 1.207 x vf^2
Solving for vf, we get:
vf = 2.62 m/s
Now we can use the conservation of momentum to find the initial velocity of the bullet:
m_bullet x v = (m_bullet + m_block) x vf
7.00 g x v = 1.207 kg x 2.62 m/s
v = 958 m/s
So the initial velocity of the bullet was 958 m/s.

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One of the advantages of digital imaging is increased speed for viewing images.

Digital imaging is a technology that enables doctors to take X-rays, MRIs, CT scans, and other medical images, and store them digitally.

Digital imaging provides many advantages over traditional film-based imaging, such as increased speed for viewing images.

Digital imaging is a medical technology that allows physicians to take, store, and view medical images in digital form. Digital imaging includes modalities such as X-rays, computed tomography (CT), magnetic resonance imaging (MRI), and ultrasound.

Digital imaging provides several benefits, such as increased speed, improved diagnostic accuracy, lower radiation exposure, and reduced chemical usage. It also enables doctors to view images in real-time, making it easier to detect and diagnose medical conditions.

Additionally, digital images can be easily shared between medical professionals, allowing for better communication and collaboration.

The advantages of digital imaging include increased speed for viewing images. Instead of waiting for film-based images to be developed, doctors can view digital images instantly. This can be particularly important in emergency situations, where time is critical.

Digital imaging also allows doctors to manipulate images, zooming in or out as needed, to get a clearer view of the affected area or to identify specific features or abnormalities.

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The terminal speed of the skydiver as he falls feet first would be  54.9 m/s.

To find the terminal velocity of the skydiver, we need to balance the forces acting on him. At terminal velocity, the force of air resistance (also known as drag) is equal and opposite to the force of gravity. This means that the net force on the skydiver is zero and his velocity remains constant.

The force of air resistance is given by:

F_drag = (1/2) * rho * v^2 * C_d * A

where:

rho is the density of air (about 1.2 kg/m^3 at sea level)

v is the velocity of the skydiver

C_d is the drag coefficient (0.6 in this case)

A is the cross-sectional area of the skydiver

The force of gravity on the skydiver is given by:

F_gravity = m * g

where:

m is the mass of the skydiver (75 kg in this case)

g is the acceleration due to gravity (9.81 m/s^2)

At terminal velocity, F_drag = F_gravity, so we can set the two equations equal to each other:

(1/2) * rho * v^2 * C_d * A = m * g

Solving for v, we get:

v = sqrt((2 * m * g) / (rho * C_d * A))

Substituting in the values given, we get:

v = sqrt((2 * 75 kg * 9.81 m/s^2) / (1.2 kg/m^3 * 0.6 * 1.5 m^2))

v = 54.9 m/s

Therefore, the terminal speed of the skydiver is about 54.9 m/s when falling feet first with a drag coefficient of 0.6.

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The direction the automobile should move to generate the maximum motional emf in the antenna, with the top of the antenna positive relative to the bottom towards the east.

A magnetic field is an area surrounding a magnet or an electric current, characterized by the presence of a force that can attract or repel other magnetic materials. The concept of magnetic fields is significant in a variety of contexts, including electromagnetism, particle physics, and ferromagnetism.

According to Faraday's Law of Electromagnetic Induction, the emf generated in a conducting wire moving in a magnetic field is proportional to the strength of the magnetic field and the velocity of the conductor.

The magnitude of the emf is given by ε = Blv sinθ, where

- ε is the magnitude of the induced emf,

- B is the magnetic field strength,

- l is the length of the wire in the magnetic field,

- v is the speed of the conductor relative to the magnetic field, and

- θ is the angle between the velocity vector and the magnetic field vector.

Due to the given conditions in the question, we can use the above formula for calculating the maximum emf. To generate the maximum motional emf in the antenna, the automobile should move in a direction perpendicular to both the antenna and the Earth's magnetic field. The angle between the velocity vector and the magnetic field vector should be 90°.

1: Identify the direction of the magnetic field. In this case, the magnetic field is directed toward the north and downward at an angle of 65.0° below the horizontal.

2: Determine the direction perpendicular to both the antenna and the magnetic field. This can be done by using the right-hand rule. Point your right thumb in the direction of the magnetic field (north and downward at 65.0° below the horizontal) and your right index finger in the direction of the antenna (vertical). Your right middle finger will then point in the direction of the motion required to generate the maximum emf (perpendicular to both the magnetic field and the antenna).

The direction the automobile should move to generate the maximum motional emf in the antenna, with the top of the antenna positive relative to the bottom, is to the east.

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The total entropy change during this process is, -16.4 J/°C.

To determine the total entropy change during this process, we need to consider both the entropy change of the iron block and the entropy change of the water in the tank. We can assume that the entire process is adiabatic (i.e., no heat transfer occurs between the system and the surroundings), so the total entropy change of the system is zero.

The entropy change of the iron block can be calculated as,

ΔS_iron = m × Cp_iron × ln(T_f / T_i)

where m is the mass of the iron block, Cp_iron is the specific heat capacity of iron, T_f is the final temperature of the iron block, and T_i is the initial temperature of the iron block.

Assuming that the final temperature of the iron block is the same as the temperature of the water in the tank (i.e., 18°C), we can calculate the entropy change of the iron block as,

ΔS_iron = 25 kg × 0.45 J/g°C × ln(18°C / 350°C)

≈ -16.4 J/°C

The entropy change of the water in the tank can be calculated as,

ΔS_water = m × Cp_water × ln(T_f / T_i)

where m is the mass of the water in the tank, Cp_water is the specific heat capacity of water, T_f is the final temperature of the water, and T_i is the initial temperature of the water.

Assuming that the iron block and the water reach a final temperature of 18°C, we can calculate the entropy change of the water as,

ΔS_water = 100 kg × 4.18 J/g°C × ln(18°C / 18°C)

= 0 J/°C

Therefore, the total entropy change during this process is,

ΔS_total = ΔS_iron + ΔS_water

≈ -16.4 J/°C + 0 J/°C

≈ -16.4 J/°C

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To determine the temperature increase if a specific amount of heat energy is transferred to the gas at a constant volume, we will use the equation:

Q = nCvΔT,

where Q is the amount of heat energy transferred, n is the number of moles of gas, Cv is the heat capacity at a constant volume, and ΔT is the temperature change.

The expression to determine the temperature change is:

ΔT = Q / (nCv)

where ΔT is the change in temperature, Q is the amount of heat energy transferred, n is the number of moles of gas, Cv is the specific heat capacity at constant volume.

For this case, the formula to calculate the change in temperature if a certain amount of heat energy is transferred to the gas at constant volume is given by:

ΔT = Q / (nCv)

Where; ΔT = temperature change, n = number of moles of gas, Cv = specific heat capacity at constant volume, Q = amount of heat energy transferred.


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The quantity that describes the ability of a force to rotate an object is torque. It differs from a force in that it is a rotational force, not a linear force. Torque depends on the force applied and the distance from the point of application to the pivot point.

Torque is the measure of the ability of a force to cause rotational motion. It is defined as the product of the force and the distance between the point of application of the force and the pivot point or axis of rotation. Unlike a linear force, which produces linear motion, a torque produces rotational motion. The unit of torque is the newton-meter (N·m) in the SI system.

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The change in momentum of the two-object system from immediately before the collision to immediately after the collision is m(v-V) + 2m(V-v).

The change in momentum of the two-object system from immediately before the collision to immediately after the collision can be determined using the following equation:

Change in Momentum = Final Momentum - Initial Momentum.

Therefore, the change in momentum of the two-object system from immediately before the collision to immediately after the collision is given by m(v-V) + 2m(V-v).

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The speed of the water coming out of the nozzle is 19.2 m/s. The result is obtained by using the formula for volumetric flow rate.

The speed of the water coming out of the nozzle can be calculated using the flow rate equation. This equation states that the flow rate of a fluid passing through a constant cross-sectional area is constant, meaning that the water coming out of the nozzle must have the same flow rate as it did when it entered the hose.

Q₁ = Q₂

A₁v₁ = A₂v₂
We have

Determine v₂!

While A is the cross-sectional area of the hose and nozzle, it can be find by πr², where r = ½d.

Using the formula above, we get:

πr₁² × v₁ = πr₂² × v₂

(½(9.6))² × 1.3 = (½(2.5))² × v₂

23.04 × 1.3 = 1.562 × v₂

v₂ = 19.2 m/s

Hence, the speed of the water coming out of the nozzle is 19.2 m/s.

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The speed of sound in air is approximately the same for all wavelengths.

Step by step Explanation :

The evidence that this is true is the following:

The speed of sound in air is approximately the same for all wavelengths. This is proved by the fact that a sound wave is an atmospheric disturbance that propagates as a longitudinal wave through the air, travelling as a pressure wave that causes areas of compression and rarefaction.

The speed of sound in air is constant and is determined by the average kinetic energy of the air molecules. This is why the speed of sound is the same for all wavelengths.

When the temperature of air is held constant, the speed of sound in air is constant. This is the primary reason why the speed of sound in air is practically constant at a given temperature.

The wavelengths of sound range from about 17 meters for the lowest audible frequency (about 20 Hz) to about 17 millimeters for the highest audible frequency (about 20,000 Hz).

The speed of sound in dry air at room temperature is around 343 meters per second, but it may vary depending on a variety of factors, including humidity, temperature, and pressure.

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Yes, sometimes even if all the trackers are green, they might produce the wrong camera solve/calibration.

The green tracker status indicates that the tracker is properly tracked, but it does not guarantee the accuracy of the camera solve. Various factors could lead to an incorrect camera solve.

One of the primary factors is improper tracking. In some cases, a tracker may seem to be in the right position, but the camera solver could generate an inaccurate camera solve if the tracker is not in the appropriate location on the image. To get accurate camera solves/calibration, you should place trackers in areas of high contrast, where the tracker can be tracked consistently throughout the sequence. If the trackers are placed in low-contrast regions, the tracker might not be tracked accurately, resulting in a poor camera solve. Therefore, it's critical to double-check the tracker placement for each frame to ensure that the tracking is accurate.

Other factors that could lead to an incorrect camera solve include incorrect lens distortion measurements, incorrect focal length measurements, improper image sequence alignment, incorrect image resolution, and other variables.

Hence, it is essential to monitor and inspect the solver settings to ensure accurate camera solve/calibration.

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You have learned that in the earth-moon system, the gravitational pull of earth's tidal bulges causes the moon to spiral away from earth. since triton has a retrograde orbit, this affects the neptune-triton system to be unstable, making it difficult for the other moons to maintain stable orbits.

Triton is a large moon of Neptune, about 1,680 miles (2,700 kilometers) in diameter. Its orbit is tilted and is also in the opposite direction of the other moons in the solar system's plane. Triton's orbit is retrograde, which means it is moving in the opposite direction to Neptune's rotation. When an object orbits in the opposite direction to the rotation of the planet it orbits, it is said to have a retrograde orbit. This is because the gravitational attraction between the two objects is weaker when they are moving in opposite directions. Because of this, Triton's retrograde orbit has a destabilizing effect on Neptune's other satellites.

The retrograde orbit of Triton causes the Neptune-Triton system to be unstable, making it difficult for the other moons to maintain stable orbits. The gravitational force of Triton is pulling away at the other moons, causing them to move erratically, some being pushed further away from Neptune and others being pulled closer. In addition to the destabilizing effect, Triton's retrograde orbit has caused it to move closer to Neptune over time, where it is thought that it will eventually break apart, forming a ring around the planet.

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The current that would pass through the body is 0.92 A.

Current is a measure of the rate of flow of electric charge in a circuit and is measured in amperes (A). Ohm's law describes the relationship between voltage, current, and resistance in an electrical circuit.

Using Ohm's Law, the current that would pass through the body can be calculated as:

I = V/R, where V is the voltage and R is the resistance.

In this scenario,

V = 120 V

R = 130,000 ohms

Substituting these values in the formula, we get:

I = 120 V / 130,000 ohms = 0.92 A.

Therefore, approximately 0.92 amperes (or 920 milliamperes) of current would pass through the body.

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Answer: That's a good question

Explanation:

The speed of the cart is 4.0 m/s.

step by step explanation:

Force F is 10-N,

Distance d is 8.0-m, and

Mass m is 20-kg,

A constant 10-N horizontal force is applied to a 20-kg cart at rest on a level floor.

If friction is negligible, then the speed of the cart when it has been pushed 8.0 m can be calculated using the equation v = Fd/m,

where v is the speed of the cart,

F is the applied force,

d is the distance, and

m is the mass of the cart.

so the speed of the cart is v = (10 N × 8.0 m) / 20 kg = 4.0 m/s.

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The tension in the wire created by the bird landing on it is calculated by using the equation T= (mgh)/d, where m is the mass of the bird, g is the acceleration due to gravity, h is the amount the wire sags and d is the distance between the two telephone poles.

In this case, with m = 1.02 kg, g = 9.81 m/s2, h = 0.212 m and d = 49.5 m, the tension in the wire is calculated as T = (1.02 kg x 9.81 m/s2 x 0.212 m)/49.5 m = 4.299 N.

This means that the bird produces a tension of 4.299 N in the telephone wire when it lands on it midway between the two poles. This amount of tension is relatively small, but enough to cause the wire to sag slightly. The tension in the wire will increase if the bird moves further along it, as the distance d between the poles will decrease.

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(a) The final velocity of the person and cart relative to the ground is 0 m/s.

(b) The friction force acting on the person while he is sliding across the top surface of the cart is -28.96 N, acting in the negative direction.

(c) The friction force acts on the person for a time of 1.50 s.

(d) The change in momentum of the person is -103.2 N⋅s, acting in the negative direction.

(e) The displacement of the person relative to the ground while he is sliding on the cart is 6.07 m, acting in the positive direction.

(f) The displacement of the cart relative to the ground while the person is sliding is 3.03 m, acting in the positive direction.

(g) The change in kinetic energy of the person is -128.8 J.

(h) The change in kinetic energy of the cart is -64.4 J.

This is an inelastic collision, meaning that the kinetic energy of the system is not conserved. This is because some of the kinetic energy is lost to friction as the person slides across the cart's surface. As the person has a greater mass than the cart, the change in kinetic energy of the person is greater than that of the cart. The total kinetic energy of the system is thus decreased, as the person and cart come to rest relative to each other.

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The electric field stored between two square plates of 9.3 cm on a side and separated by a 2.5 mm air gap is 1110 N/C. This can be calculated using Coulomb's law and the given information.

Coulomb's law states that the electric field is equal to the charge (Q) divided by the permittivity of free space (ε₀) multiplied by the distance (d) squared:

E=Q/(ε₀*d²).
Plugging in the given information,

E=(13 nC)/(8.85 x 10⁻¹² * 0.0025²) = 1110 N/C.
This answer uses Coulomb's law to calculate the electric field stored between two square plates, given the plates' side lengths, air gap width, and charge magnitude.

Learn more about Coulomb's law at https://brainly.com/question/506926

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