A 5.0 g mouse races around a 65-cm-diameter horizontal tack. What is the minimum coefficient of static friction between the track and the mouse’s feet that allows the mouse to run at 1.4 m/s without slipping?

Answers

Answer 1

Answer:0.62

Explanation:

mv*2/rg
(1.4)*2*2/65*10*-2 *9.8

=0.615

Answer 2

This impossible, since the coefficient of static friction cannot be greater than 1.0 and therefore, the mouse cannot run at 1.4 m/s without slipping on this track.

What is static friction?

The Force that keeps any object at the rest is called as static friction.

As, Fc = mv² / r

m is the mass of the mouse, v is its velocity, and r is the radius of the track (not the diameter).  r = 0.5 * 65 cm = 32.5 cm = 0.325 m.

Fc = (5.0 g) x (1.4 m/s)²  / 0.325 m

= 31.96 g m/s²

= 0.313 N

Ff = μs * N

Here, μs is coefficient of static friction and N is normal force acting on mouse.

N = mg

= (5.0 g) x (9.81 m/s² )

= 0.049 N

μs = Ff / N

= (0.313 N) / (0.049 N)

= 6.39

This is impossible, since the coefficient of static friction cannot be greater than 1.0 Therefore, the mouse cannot run at 1.4 m/s without slipping on this track.

To know more about static friction, refer

https://brainly.com/question/13680415

#SPJ1


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Answers

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