A 82.9 kg weight-watcher wishes to climb a mountain to work off the equivalent of a large piece of chocolate cake rated at 670 (food) calories. How high must the person climb? The acceleration due to gravity is 9.8 m/s2 and 1 food calorie is 10^3 calories.

Answer:

3.085 [m].

Explanation:

1) The rule:

m₁*g*l₁=m₂*g*l₂, where m₁ and l₁ - the mass and distance for the small child, m₂ and l₂ - for the big child;

2) according to the condigion l₁+l₂=5, then

3) it is possible to make up the system:

[tex]\left \{ {{l_1+l_2=5} \atop {m_1*l_1=m_2*l_2}} \right. \ = > \ \left \{ {{l_1=5-l_2} \atop {18*(5-l_2)=29*l_2}} \right. \ = > \ \left \{ {{l_1=\frac{145}{47}} \atop {l_2=\frac{90}{47}}} \right.[/tex]

4) finally, l₁=145/47≈3.085 [m].

Answer: If you are adding heat to a sample at a constant rate , you plot the temperature against time.

Explanation:

Answer:

The answer would be 25kg.

Explanation:

Because the force is 50 N and the acceleration is 2 meters per second squared and the Newton's Law Triangle is F = m x a or Force = Mass x Acceleration so we have to solve the equation 50 divided by 2 or 50/2 which results in 25kg.

The velocity of 1kg and 2 kg mass when separation becomes 5m is 1.334 x 10⁻¹¹ m/s and 6.67 x 10⁻¹² m/s respectively.

The gravitational force between the masses is determined as follows;

[tex]F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{(6.67 \times 10^{-11}) (1)(2)}{10^2} \\\\F = 1.334 \times 10^{-12} \ N[/tex]

a = F/m

a₁ = (1.334 x 10⁻¹²) / (1)

a₁ = 1.334 x 10⁻¹² m/s²

a₂ = (1.334 x 10⁻¹²) / (2)

a₂ = 6.67 x 10⁻¹³ m/s²

v = u + 2ad

v₁ = u₁ + 2a₁d

v₁ = 0 + 2( 1.334 x 10⁻¹² )(5)

v₁ = 1.334 x 10⁻¹¹ m/s

v₂ = u₂ + 2a₂d

v₂ = (0) + 2(6.67 x 10⁻¹³)(5)

v₂ = 6.67 x 10⁻¹² m/s

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For a 208-volt, 4-wire, 3-phase wye power system feeds a school building, the average daily voltage is mathematically given as

x=206.23v

Generally, the equation for the mean  is mathematically given as

x=total sum/ number

Therefore

ts=05.25 volts, 203.75 volts, 208 volts, 204.35 volts, 206.7 volts, 207 volts, and 208.55 volts.

ts=1433.6

In conclusion

x=1433.6/7

x=206.23v

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Answer:

See below ~

Explanation:

Total Resistance

Total Current Drawn

Answer:

See below ~

Explanation:

Assume the bodies have the same acceleration

Divide the RHS of equation 2 by equation 1.

Therefore, the body of 6 kg accelerates more by 3 times

Answer:

18.51 J

Explanation:

First, we need to find the Kinetic energy of the disk. Since the disk travels in a straight line, we can use the formula [tex]K=\frac{1}{2}mv^2[/tex]:

[tex]Kdisk=\frac{1}{2} 0.033*33.5^2\\Kdisk=18.51 J[/tex]

Since no other force is present, no friction, sound, or vibration, energy must be conserved. Therefore, the answer for both is 18.51 J.

The type of mental function that is the strongest and most obvious is feeling. That is option A.

Mental function can be defined as those activities that are performed by individuals such as thinking, sensing, or reasoning that involves the cognitive use of the brain.

The four basic cognitive functions include:

The magnitude of each basic cognitive functions depends on the personality of the individual.

An extrovert is an individual that is active, outgoing, and has an expressive pattern of behaviour. Therefore extrovert feeling would be the strongest and most obvious.

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According to Myers-Briggs, a charcteristic that is common to judging is  liking things settled and organized.

The term judging has to do with the quest for order and organization. It is one of the personality traits as outlined by Myers-Briggs.

The characteristic that is common among the people that exhibit the judging personality trait is liking things settled and organized.

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Answer:likes to have things settled and organized

Explanation:

bc I just took the test so ik it’s right

Personality test is aimed at being able to decipher the nature of human personality. The opposite of judging in a personality test is prospecting.

The term personality test is aimed at being able to decipher the nature of human personality through a  Personalities Test.

In this personality test different personality types have their respective opposites. The opposite of judging in a personality test is prospecting.

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Answer:

prospecting

Explanation:

Answer:

с The handle will turn anticlockwise (to the left).

Explanation:

For a velocity selector for ions using perpendicular electric and magnetic fields is mathematically given as

B= 0.225 T

Generally, the equation for the magnetic field is mathematically given as

B = E/v

Therefore

B = 900/4000

B= 0.225 T

In conclusion. the magnetic field is

B= 0.225 T

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For an aluminum disk of radius 8.7 cm and thickness 3.0 mm spinning around,  moment of inertia   is mathematically given as

I=16268.20gcm^2

Generally, the equation for the volume  is mathematically given as

v=\pir^2t

Therefore

v=\pi(8.7)^2*0.32

v=76.09cm^3

In conclusion, The inertia

I=136.83*8.7^2/2

I=16268.20gcm^2

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The current in the series circuit  across a 9.0 V potential difference is determined as 0.333 A.

The current in the series circuit is determined by applying ohms law as shown below;

V = IR

where;

R = 12 Ω  + 15 Ω  = 27 Ω

I = V/R

I = 9/27

I = 0.333 A

Thus, the current in the series circuit  across a 9.0 V potential difference is determined as 0.333 A.

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Answer:

1. A substance that can be separated into two or more substances only by a chemical change is a(n) _____.

solution

element

mixture

compound

2.

Which of the following materials is a substance?

air

gasoline

stainless steel

silver

3.

The first figure in a properly written chemical symbol always is _____.

boldfaced

capitalized

italicized

underlined

4.

Which of the following represents a compound?

H

H-3

H2O

O-16

5. What do chemical symbols and formulas represent, respectively?

elements and compounds

atoms and mixtures

compounds and mixtures

elements and ions

Explanation:

The rocket plane will travel 800 meters before coming to rest.

initial speed= 80 m/s

kinetic friction= 0.6

Net force action on the plane:

  F- kinetic friction = mass * acceleration

 mass*g - 0.6*mass*g=mass*acceleration     (take g=10m/s)

              acceleration=4m/s

calculation of stopping distance:-

   V²=U²-2as

   0+2as=U²

   S=U²/2a

   S=(80*80)2*4

   S=800 meter.

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#SPJ2

Answer:

(b) from left to right (→)

Explanation:

Frictional Force

When the surface of one object comes into touch with the surface of another, friction is the force that resists motion. Friction reduces a machine’s mechanical advantage, or, to put it another way, friction reduces the output-to-input ratio. Frictional force refers to the force generated by two surfaces that contact and slide against each other.

Friction is caused due to the irregularities on the two surfaces in contact. So, when one object moved over the other, these irregularities on the surface get entangled, giving rise to friction.

The more the roughness, the more irregularities and more significant will be the friction.

Friction always acts in the opposite direction to the motion, hence the force of friction will be from left to right.

Answer:

a first-hand or contemporary account of an event or topic.

Explanation:

Answer:

B

Explanation: Carbon is released into the air by dead organisms, animals, and humans.

Answer:

Explanation:

wo possible outcomes have an identical probability, which is not possible. C. The sum of all possible moves is greater than 1, which is not possible. D. The probability of two possible outcomes sums to the probability of another outcome, which is not possible.

For a current loop with a radius 20 cm and current 2 A is in a uniform magnetic field of 0.5 T, largest potential energy difference is mathematically given as

du=0.2512J

Generally, the equation for the initial velocity  is mathematically given as

v0=-iAB

Therefore

-2*\pi(0.2)(0.5))

v0=-0.1256J

for  180

theta=0180=-iABcos180

V180=0.1256J

Therefore

du=v180-v0

0.1258-(-0.1256

du=0.2512J

In conclusion,  potential energy

du=0.2512J

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The actions that would decrease the width of the central bright are decrease in the wavelength of the light and Increase in the width of the slit.

The wavelength of the light is determined using the following formulas;

[tex]\lambda = d(\frac{y}{D} )[/tex]

where;

y = (λD) / (d)

Thus, the actions that would decrease the width of the central bright are decrease in the wavelength of the light and Increase in the width of the slit.

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Charge is neither generated nor destroyed, according to the rule of conservation of charge. Charge is merely transferred from one item to another in the form of electrons.

Answer:

The Principle of Moments states that when a body is balanced, the total clockwise moment about a point equals the total anticlockwise moment about the same point.

Explaining with equation

Moment =force F x perpendicular distance from the pivot d. Moment = Fd.

Hi there!

Recall that the amplitude of an oscillating system occurs at a point of maximum potential energy.

For a spring system, potential energy is given as:
[tex]U = \frac{1}{2}kx^2[/tex]

U = Potential Energy (J)

k = Spring constant (N/m)
x = amplitude (m)

We can rearrange the equation to solve for amplitude more easily.

[tex]U = \frac{1}{2}kx^2\\\\2U = kx^2\\\\x^2 = \frac{2U}{k}\\\\x = \sqrt{\frac{2U}{k}}[/tex]

If we double 'U':
[tex]x' = \sqrt{\frac{2(2U)}{k}} = \sqrt{2}*\sqrt{\frac{2U}{k}}\\\\x' = \sqrt{2} * x[/tex]

Thus, the new amplitude would be √2 times greater, so:
[tex]20 cm \cdot \sqrt{2} = \boxed{28.284 cm}[/tex]

[tex]\bold{\huge{\underline{ Solution }}}[/tex]

Here,

Here, we have

We have to find the time of flight

We know that,

Time of flight

[tex]\sf{ = }{\sf{\dfrac{ 2uSin{\theta}}{g}}}[/tex]

Subsitute the required values,

[tex]\sf{ = }{\sf{\dfrac{ 2{\times}100{\times}Sin30{\degree}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 200{\times}{\frac{1}{2}}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 100}{9.8}}}[/tex]

[tex]\bold{ = 10.20 \: s }[/tex]

Hence, The time of flight is 10.20 sec .

Here, We have

We have to find the maximum height attained by the body

We know that,

Maximum height

[tex]\sf{ = }{\sf{\dfrac{ u^{2}Sin^{2}{\theta}}{2g}}}[/tex]

Subsitute the required values,

[tex]\sf{ = }{\sf{\dfrac{ (100)^{2}{\times}Sin^{2}30{\degree}}{2{\times} 9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 10000{\times}{\frac{1}{2}}{\times}{\frac{1}{2}}}{19.6}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 5000{\times}{\frac{1}{2}}}{19.6}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 2500}{19.6}}}[/tex]

[tex]\sf{ = 127.5 \: m}[/tex]

Hence, The maximum height attained by the body is 127.5 .

Here, we have

We have to find the horizontal range

We know that,

Horizontal range

[tex]\sf{ = }{\sf{\dfrac{ u^{2}Sin2{\theta}}{g}}}[/tex]

Subsitute the required values,

[tex]\sf{ = }{\sf{\dfrac{ (100)^{2}{\times}Sin2{\times}30{\degree}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 10000{\times}Sin{\times}60{\degree}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 10000{\times}{\frac{\sqrt{3}}{2}}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 5000{\times}\sqrt{3}}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 5000{\times}1.732}{9.8}}}[/tex]

[tex]\sf{ = }{\sf{\dfrac{ 8660}{9.8}}}[/tex]

[tex]\sf{ = 883.67 \: or 883.7 m}[/tex]

Hence, The range of the body is 883.67 or 883.7 m.

Answer:

(a) 10.20 s (nearest hundredth)

(b) 127.55 m (nearest hundredth)

(c) 883.70 m (nearest hundredth)

Explanation:

Part (a)

At the end of the projectile's flight, its vertical displacement will be zero.

Resolving vertically, taking up as positive:

[tex]s=0\quad u=100 \sin30^{\circ} \quad v=v, \quad a=-9.8, \quad t=t[/tex]

[tex]\begin{aligned}\textsf{Using }\:s & =ut+\dfrac12at^2:\\ 0 & =100 \sin 30^{\circ}t+\dfrac12(-9.8)t^2\\ 0 & = 50t-4.9t^2\\ 4.9t^2 & = 50t\\ 4.9t & = 50\\ t & = \dfrac{50}{4.9}\\ t & = 10.20\:\sf s\:(nearest\:hundredth)\end{aligned}[/tex]

Part (b)

At the maximum height, vertical velocity will be zero.

Resolving vertically, taking up as positive:

[tex]s=0\quad u=100 \sin30^{\circ} \quad v=0, \quad a=-9.8, \quad t=t[/tex]

[tex]\begin{aligned}\textsf{Using }\:v^2 & = u^2+2as :\\ 0^2 & = (100 \sin 30^{\circ})^2+2(-9.8)s\\ 0 & = 2500-19.6s\\ 19.6s & = 2500\\ s & = \dfrac{2500}{19.6}\\ s & = 127.55\: \sf m\:(nearest\:hundredth) \end{aligned}[/tex]

Part (c)

The horizontal velocity of a projectile is always constant, so u = v.

The horizontal component of acceleration is zero.

Resolving horizontally, taking right as positive (and using the value for t we found in part a):

[tex]s=s\quad u=100 \cos30^{\circ} \quad v=100 \cos30^{\circ} , \quad a=0, \quad t=\dfrac{50}{4.9}[/tex]

[tex]\begin{aligned}\textsf{Using }\:s & =ut+\dfrac12at^2 : \\ s & =(100 \cos 30^{\circ})\left(\dfrac{50}{4.9}\right)+\dfrac12(0)\left(\dfrac{50}{4.9}\right)^2\\ s & =50\sqrt{3}\left(\dfrac{50}{4.9}\right)+0\\ s & =883.70\: \sf m\:(nearest\:hundredth)\end{aligned}[/tex]

(a) The magnitude of force vector B at the given resultant force is 120 N.

(b) The direction of  force vector A is 142.46°

The resultant forces is calculated as follows;

Acosθ + Bcosθ = 0 --- (1)

Asinθ + Bsinθ = 150 ---- (2)

Acosθ + Bcos60 = 0    

-60 + Bsin60 = 0     (Acosθ = x-component of A = Ax)

Bcos60 = 60

B = 60/cos(60)

B = 120 N

Asinθ + Bsinθ = 150

Ay + Bsinθ = 150

Ay + 120sin60 = 150

Ay = 150 - 120sin60

Ay = 46.1 N

[tex]tan \theta = \frac{A_y}{A_x} \\\\\theta = tan^{-1} (\frac{A_y}{A_x})\\\\\theta = tan^{-1} (\frac{46.1}{-60})\\\\\theta = -37.53^0\\\\\theta = -37.53^0 + 180 = 142.46^0[/tex]

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[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Here we go ~

Let's use the given expression :

[tex]\qquad \tt \dashrightarrow \:a = v \dfrac{dv}{ds} [/tex]

[tex]\qquad \tt \dashrightarrow \:v \:dv= a \: {}{ds} [/tex]

Now, integrate both sides

[tex]\qquad \tt \dashrightarrow \: \int_{u}^v (v )\: dv= {\int _{0 }^{s} }{}^{} (a) \: {}{ds} [/tex]

[tex]\qquad \tt \dashrightarrow \: {\bigg[\dfrac{v {}^{2} }{2} \bigg]}_{u }^{v} \: = {\bigg[{a{s}^{} }{} \bigg]}_{0}^{s}[/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{1}{2} {\bigg[{v {}^{2} - {u}^{2} }{} \bigg]}_{}^{} \: = a{\bigg[{{s - 0}^{} }{} \bigg]}_{}^{}[/tex]

[tex]\qquad \tt \dashrightarrow \: v {}^{2} - {u}^{2} =2 as[/tex]

[tex]\qquad \tt \: \therefore v {}^{2} =u {}^{2} + 2as[/tex]

I hope you understood ~