∠A and \angle B∠B are vertical angles. If m\angle A=(3x+3)^{\circ}∠A=(3x+3) ∘ and m\angle B=(4x-8)^{\circ}∠B=(4x−8) ∘ , then find the value of x.

The answer to this question is 115 but how please leave an explanation

Step-by-step explanation:

This particular mineral was found in Finland. A mineral is a naturally occurring crystalline solid that cannot be physically broken down into smaller components. Deposits of minerals form when a medium that contains and transports mineral-making ore releases and deposits the ore.

Solve It for an arithmetic sequence

So

Hence

a_40:-

Answer:

[tex]f(40)=-144[/tex]

Step-by-step explanation:

Given:

This is a recursive arithmetic sequence since each term is defined using the previous term.

To find the nth term, convert the recursive formula to an explicit formula.

Explicit form of an arithmetic sequence: [tex]a_n=a+(n-1)d[/tex]

where:

We have been given the first term: [tex]a=12[/tex]

To get any term from its previous term we subtract 4, so the common different (d) is -4.

Therefore, the formula for the nth term is:

[tex]\implies a_n=12+(n-1)(-4)[/tex]

[tex]\implies f(n)=16-4n[/tex]

To find [tex]f(40)[/tex] simply substitute n = 40 into the explicit formula:

[tex]\implies f(40)=16-4(40)=-144[/tex]

Answer:

The distance betweem the two points is about 14

Step-by-step explanation:

The distance formula is [tex]d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex]

According to the problem: [tex]x_{2}=8[/tex], [tex]x_{1} =1[/tex], [tex]y_{2} =-5[/tex], and [tex]y_{1} =7[/tex]

Substitute these numbers into the problem to get [tex]d=\sqrt{(8-1)^{2}+(-5-7)^{2}}[/tex]

[tex](8-1)^2=(7)^2=49[/tex]

[tex](-5-7)^2=(-12)^2=144[/tex]

[tex]\sqrt{49+144}=\sqrt{193} =13.8923349894[/tex]

You can round this number to approximately 14.

Answer:

[tex] \longrightarrow \sf \purple{ \boxed{ \bold{ \: 12x² + 12x – 18}}}[/tex]

Step-by-step explanation:

Simplify

10x² + 3x – 6 + 2x² + 9x – 12

Steps

1Ox² + 3x- 6 - 2x² + 9x - 12

Step 1:- Group like terms:

= 10x² + 2x²+ 3x + 9x - 6 - 12

Step 2:- Subtract the numbers: – 6–12 = -18

= 10x² + 2x² + 3x + 9x – 18

Step 3:- Add similar elements: 10x² + 2x² – 12x²

= 12x² + 3x + 9x – 18

Step 4:- Add similar elements: 3x + 9x – 12x

= 12x² + 12x – 18

[tex]\angle F+ \angle E = 180^{\circ}\\\\ \implies \angle F + 164^{\circ} = 180^\circ\\\\\implies \angle F = 180^\circ - 164^\circ\\\\\implies \angle F= 16^\circ[/tex]

The slope of the line is -2.5 and the y-intercept is 2. This shows that the Quantity B is greater that A

The intercept is the point where the line intersects

Determine the slope of the graph using the coordinate points (0, 2) and (0.8, 0)
Slope = -2/0.8
Slope = -2.5

The slope of the line is -2.5 and the y-intercept is 2

This shows that the Quantity B is greater than A

Learn more on equation of a line here:https://brainly.com/question/13763238

The equation that models the path of the football released from the given position is h(t) = -10 + 25.37t - 16.1t².

The initial velocity of the ball is determined by applying third kinematic equation as shown below;

Vf² = V₀² - 2gh

0 = V₀² - 2gh

V₀² = 2gh

V₀ = √(2gh)

V₀ = √(2 x 32.17 x 10)

V₀ = 25.37 ft/s

The equation of the ball's motion can be modelled as follows;

h = V₀t - ¹/₂gt²

10 = 25.37t - ¹/₂(32.17)t²

10 = 25.37t - 16.1t²

h(t) = -10 + 25.37t - 16.1t²

Thus, the equation that models the path of the football at any given position is h(t) = -10 + 25.37t - 16.1t².

Learn more about equation of motion here: https://brainly.com/question/25951773

Answer:

Factoring out Greatest Common Factor (GCF)

[tex]6xy+12x^2y^2-4x^3y^3[/tex]

Factor out greatest common term [tex]2xy[/tex]:

[tex]\implies 2xy(3+6xy-2x^2y^2)[/tex]

Factoring by Grouping

[tex]20x^2+11x-3[/tex]

[tex]\implies a=20, b=11, c=-3[/tex]

[tex]\implies ac=20 \cdot -3=-60[/tex]

Find 2 two numbers that multiply to ac (-60) and sum to b (11)

Factors of 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

Therefore, the two numbers are 15 and -4

Rewrite b as the sum of these 2 numbers:

[tex]\implies 20x^2+15x-4x-3[/tex]

Factorize the first two terms and the last two terms separately:

[tex]\implies 5x(4x+3)-1(4x+3)[/tex]

Factor out the common term (4x + 3):

[tex]\implies (5x-1)(4x+3)[/tex]

Factoring by Grouping

[tex]3x^2+3xa-2x-2a[/tex]

Factorize the first two terms and the last two terms separately:

[tex]\implies 3x(x+a)-2(x+a)[/tex]

Factor out the common term (x + a):

[tex]\implies (3x-2)(x+a)[/tex]

Answer:

9.22

I really hope it helps

let me know am i right to be shure

Answer:

[tex]9.22[/tex]

Step-by-step explanation:

You would need to use the distance formula to find the approximate distance between points A and B.

[tex]distance=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^2}[/tex]

[tex]\sqrt{((-2)-4)^{2} +((-4)-3)^2}[/tex]

[tex]\sqrt{(-6)^{2} +(-7)^2}\\[/tex]

[tex]\sqrt{36 +49}[/tex]

[tex]\sqrt{85}[/tex]

[tex]\sqrt{85}=9.219544457=9.22[/tex]

Therefore, the approximate distance between points A and B is 9.22.

Zeros are (-5,0) and (1,0)

Hence

Yes this is the parabola given

So

As for any real x the function will give a real value [square present] the domain is set of real numbers ≤-2

vertex is maximum

Highest value of y is 9

Hence.

Or in interval notation

Answer:

The range of the function is all real numbers less than or equal to 9.

Step-by-step explanation:

Given:

Domain: input values (x-values)

Range: output values (y-values)

The domain of the function is not restricted, so the domain is all real numbers.

The leading coefficient of the function is negative, therefore the parabola opens downwards.  This means that the vertex is the maximum point.

Therefore, the range will be f(x) ≤ 9 → all real numbers less than or equal to 9.

Answer:

Multiply the moduli and add the arguments.Step-by-step explanation:First write out the two terms being multiplied: z1z2= [r1(cos(theta 1) + isin(theta 1))][r2(cos(theta 2)+ isin(theta 2))] z1z2= r1r2 (cos(theta 1) + isin(theta 1))(cos(theta 2)+ isin(theta 2)) z1z2= r1r2(cos(theta 1)cos(theta 2))+(icos(theta 1)sin(theta 2))+(icos(theta 2)sin(theta 1))+(i^2 sin(theta 1)sin(theta 2)) Next group and rewrite the like term with the sums and differences. Your answer is the multiplication of the moduli and the addition of the arguments: z1z2= r1r2[cos(theta 1 + theta 2) + i sin (theta 1 and theta 2)].

The product complex number is [tex]z_1z_2[/tex]= [tex]r_1r_2[/tex][cos (θ1+θ2) + i sin (θ1+θ2)].

A real number and an imaginary number are effectively combined to create a complex number. The complex number is written as a+ib, where a and ib are real and imaginary numbers, respectively.

We have,

z1=r1 (cos θ1 +i sin θ1)

z2=r2 (cos θ2 +i sin θ2)

where r-radius/radii

and, m-modulus/moduli

Now, the product is

[tex]z_1z_2[/tex] = r1 (cos θ1 +i sin θ1) x r2 (cos θ2 +i sin θ2)

[tex]z_1z_2[/tex] = r1 r2(cos θ1 . cos θ2 +i cos θ1 sin θ2 + i sin θ1 cos θ2 + i² sin θ1 sin θ2)

[tex]z_1z_2[/tex] = r1 r2(cos θ1 . cos θ2 +i cos θ1 sin θ2 + i sin θ1 cos θ2 - sin θ1 sin θ2)

We know,

cos (a + b)= cos a cos b - sin a sin b

sin (a+b) = sin a cos b + cos a sin b

Thus, [tex]z_1z_2[/tex] = [tex]r_1r_2[/tex][cos (θ1+θ2) + i sin (θ1+θ2)].

Learn more about complex number here:

brainly.com/question/1462345

#SPJ2

Step-by-step explanation:

7x² + 9x² - x²

when you wrote the expression you used the "multiplication ×" and not "x".

anyway, when you have terms of the same variable of the same exponent, then the combination variable and exponent become an item. and the same items can simply be added in an expression.

this is similar to

7 apples + 9 apples - 1 apple

what would you do there ?

see ?

and the same we are doing now for the given expression : we are adding the terms up :

7x² + 9x² - x² = (7 + 9 - 1)x² = 15x²

and in the middle I gave you even the reason why we can do that.

please, let me know, if this is still unclear.

Answer:

73.6 (or actually 74 - you can't have 0.6 times)

Step-by-step explanation:

here, you're effectively just multiplying fractions.

it is 23/100 that were drawn but 320 is 3.2 X 100 so all you have to do is multiply 23 by 3.2 which is 73.6

Answer:

The answer is a linear graph

Step-by-step explanation:

Answer:

choice f

Step-by-step explanation:

take ∆ abc

ab^2 = ac^2 + ab^2

400 = 225 + ab^2

ab =√ 175

∆aDB

bd = 20-x

ad^2 = 175 -(20-x)^2

∆acd

225 = x^2 + 175 - 400+ 40x - x^2

225 = -225 + 40x

450 = 40x

x = 45/4

Answer:

1/81

Step-by-step explanation:

First lets simplfy the equation :

(3^2)^-2

(remember that you can mutiply the exponent outside the paranthesis by the exponent inside so -2*2=-4)

3^-4

Now lets evaluate this further!

3^-4

(negative exponets mean that you have to raise the number but as the denominator of a fraction)

1/3^4

Now we can solve it fully

1/3^4

1/81

Answer: 256,1

Step-by-step explanation:

[tex]\sqrt{x} - \sqrt{y} =15\\\sqrt{y} = 49-3\sqrt{x} \\\\\sqrt{x} -(49-3\sqrt{x} ) =15 \\so, x=256\\substitute \{x}\ :\\\\\sqrt{y} = 49-3\sqrt{256} =y=1[/tex]

so, 256=x

and, y=1

Hope this Helped!

Answer:

1, 4 or -1, -4

Step-by-step explanation:

Let the two numbers be x and such that x > y.

According to the first condition:

[tex]x^2 -y^2= 15[/tex]

[tex]\implies x^2 =y^2+15[/tex]......(1)

According to the second condition:

[tex]3x^2 +y^2= 49[/tex]

[tex]\implies 3(y^2+15) +y^2= 49[/tex]

(From equation 1)

[tex]\implies 3y^2+45 +y^2= 49[/tex]

[tex]\implies 4y^2 =49-45[/tex]

[tex]\implies 4y^2 =4[/tex]

[tex]\implies y^2 =\frac{4}{4}[/tex]

[tex]\implies y^2 =1[/tex]

[tex]\implies y =\pm 1[/tex]

When y = 1

[tex]\implies x^2 =(1)^2+15=1+15=16[/tex]

[tex]\implies x =\pm 4[/tex]

When y = -1

[tex]\implies x^2 =(-1)^2+15=1+15=16[/tex]

[tex]\implies x =\pm 4[/tex]

Thus, the required numbers are either 1, 4 or -1, -4

Answer:

  (a)  <-3, 14>

Step-by-step explanation:

Addition and subtraction of vectors and matrices is done on a term-by-term basis.

__

The difference is ...

  r - s

  = <4, 9> -<7, -5>

  = <4 -7, 9 -(-5)>

  = <-3, 14> . . . . . . . matches the first choice

6x + 3 = 2

its the answer

easy peasy

Answer:

3 + 6(x) =  2

Step-by-step explanation:

Given statement:

3 more than the product of a number and six is equal to 2​

Converting the statement into an equation:

{3} {more} than {the product of a number and six} is {equal to} {2​}

↓      ↓                                          ↓                                      ↓           ↓

3      +                                        6 × x                                   =           2

⇒ Equation formed: 3 + (6 × x) =  2

⇒ Equation formed: 3 + 6(x) =  2

Answer:

First box, second from the left,

Second box, first on the left.

Third box, third from the left.

Fourth box, Last on the right.

Step-by-step explanation:

Welcome.

Hey there!

7t - 3 = -59

ADD 3 to BOTH SIDES

7t - 3 + 3 = -59 + 3

CANCEL out: -3 + 3 because it give you 0

KEEP: -59 + 3 because it help solve for the t-value

NEW EQUATION: 7t = -59 + 3

SIMPLIFY IT!

7t = -56

DIVIDE 7 to BOTH SIDES

7t/7 = -56/7

CANCEL out: 7/7 because it give you 1

KEEP: -56/7 because it help solve for the t-value

NEW EQUATION: t = -56/7

SIMPLIFY IT!
t = -8

Therefore, your answer is: t = -8

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

because a= 1,1 then 1+1 = 2

Answer:

4x + 15 = 6x - 3

Step-by-step explanation:

Four times an unknown number is 4x, add 15 like it says, then it says three less so it would be - 3 and then it says than six times the [unknown] number, which remains being x

hope this helps!

Note the rules

So

Option A -->Negative

Option B-->Positive

Option C –»Negative

Option D —»Positive

Positive product:

[tex]\left(-\dfrac 23 \right) \left(- \dfrac 23 \right)~ \text{and}~ \left(\dfrac 23 \right) \left(\dfrac 23 \right)[/tex]

Negative product:

[tex]\left(-\dfrac 23 \right) \left(\dfrac 23 \right)~ \text{and}~ \left(\dfrac 23 \right) \left(-\dfrac 23 \right)[/tex]

Answer:

1 hour and 51 minutes

Step-by-step explanation:

Find the difference between the time.

Answer:

B. (solved using the quadratic formula)

Answer:

angle 2 and angle 4

Answer:

6!/3!=6x5x4x3x2/3x2=6x5x4=120

Step-by-step explanation:

There are L, O, O, P, H, O, L, E; 8 letters in LOOPHOLE. However, three letters repeat: OOO. That means we cannot count them as different and use ! for them.

L,P,H,L,E,O are the letters not double counted. There are SIX letters, so 6!, however, you still have to divide since there are the Os you have to consider.

You have to divide by 3! as they repeat 3 times.

Thus, 6!/3!

"There is a subset of permutations that takes into account that there are double objects or repetitions in a permutation problem. In general, repetitions are taken care of by dividing the permutation by the factorial of the number of objects that are identical" -www. ck12. org > probability > lesson > permutation