A ball with a mass of 15kg sits at rest on
top of a tall 5m table. What is the
gravitational potential energy of the ball?
a

Explanation:

Sooooo, first,

Constant Speed means that the body isn't accelerating.

a= 0

Let the force that causes it to move up the incline be P and Q be the force that causes the body to move down the incline. Let Fr be the frictional force.

The force that pulls the body downwards is given by,

F = mgsin40°

F= 18.898N

P -(F+Fr) = ma, but, a= 0

P = F + Fr

Fr = 26-18.898

= 7.102N

If the block must move down the incline, Q and Fr will act in the same direction.

Q + Fr = F

Q = 11.796N

Answer:

Brakes unevenly adjusted: Brakes pulling in one direction or the other can lead to a skid. Tires with worn tread: Tread is necessary for traction in wet weather

Explanation:

Answer: exhaust pipe

Explanation: It doesn't really control anything so I'm assuming this is the answer

The magnitude of the net force that is acting on particle q₃ is equal to 6.2 Newton.

Given the following data:

Charge = [tex]-2.35 \times 10^{-6}[/tex] C.

Distance = 0.100 m.

Scientific data:

Coulomb's constant = [tex]8.988\times 10^9 \;Nm^2/C^2[/tex]

In this scenario, the magnitude of the net force that is acting on particle q₃ is given by:

F₃ = F₁₃ + F₂₃

Mathematically, the electrostatic force between two (2) charges is given by this formula:

[tex]F = k\frac{q_1q_2}{r^2}[/tex]

Where:

Note: d₁₃ = 2d₂₃ = 2(0.100) = 0.200 meter.

For electrostatic force (F₁₃);

[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.200^2}\\\\F_{13} = \frac{0.0496}{0.04}[/tex]

F₁₃ = 1.24 Newton.

For electrostatic force (F₂₃);

[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.100^2}\\\\F_{13} = \frac{0.0496}{0.01}[/tex]

F₂₃ = 4.96 Newton.

Therefore, the magnitude of the net force that is acting on particle q₃ is given by:

F₃ = 1.24 + 4.96

F₃ = 6.2 Newton.

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Answer:

6.2

Explanation:

acellus

R² = F1² + F2² + 2 F1.F2 cos α ⇒cosinus

F1 and F2 perpendicular, α = 90°, cos 90° = 0

[tex]\tt R=\sqrt{3^3+4^2}=5[/tex]

Question

4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid

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Answer:

Explanation:4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid

Answer:

Yes, It does mean that there was a Red Giant in the middle of the galaxy.

Explanation:

The star at the middle of the galaxy will forever stay at the middle from the gravity it has on itself and it implodes and turns into a black hole with a mass equal to at least 10 suns

Answer:

A person is doing push-ups against a wall (action force), and the wall exerts an equal and opposite force against the person (reaction force).

Explanation:

Answer:

The formula for work is

W= fd

work= force X distance

so, this is

200 X 5 =1,000

and the unit for work is Joules

so.. 1,000 joules

Explanation:

hope that helps!

The kinetic energy of the merry-go-round after 5.00 s, when a constant force is applied tangentially to it, is determined as 3,069.5 J.

The kinetic energy of the merry-go-round is determined by applying the principle of conservation of angular momentum as follows;

Iα = rF

where;

I = ¹/₂mr²

I = ¹/₂ x 80 x (1.2)²

I = 57.6 kgm²

α = (rF)/I

α = ( 1.2 x 70) / (57.6)

α = 1.46 rad/s²

a = αR

a = 1.46 x 1.2

a = 1.752 m/s²

The velocity of the merry-go-round after 5 s is calculated as follows;

v = u + at

v = 0 + (1.752x 5)

v = 8.76 m/s

K.E = ¹/₂mv²

K.E = ¹/₂ x 80 x 8.76²

K.E = 3,069.5 J

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[tex]\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} ⟿}[/tex]

(i) 0.4 Ω m^-1

(ii) 0.8 Ω

(iii) 0.5 Ω

Explanation:

Resistance of 5 m length of wire :-

[tex] = > R = \frac{V}{I} = \frac{2}{1} = 2 \: Ω [/tex]

Resistance per unit length of the wire :-

[tex] = > \frac{R}{l} = \frac{2}{5} = 0.4 \: Ω \: {m}^{ - 1} [/tex]

(ii) Resistance of 2m length of the wire~

[tex] = \: 0.4 \: Ω \: {m}^{ - 1} \times 2 \: m = 0.8 \: Ω [/tex]

(iii) When the wire is doubled on itself, its area of cross section becomes twice and the length becomes half. Let a be the initial cross section and ρ be the specific resistance of the material of wire. Then,

[tex]from \ relation \: \: ➪ \: R = ρ \times \frac{1}{a}. \\ \\ we \: have, \\ \\ initial \: resistance \:➪ \: 2 = ρ\times \frac{5}{a}....eqn(i) \\ \\ new \: resistance \: ➪ \: R` = ρ\times \frac{2.5}{2a}....eqn(ii) \\ \\ on \: dividing \: eqn(ii) \: by \: eqn(i)... \\ \\ \frac{R`}{2} = \frac{2.5ρ}{2a} \div \frac{5ρ}{a} = \frac{1}{4} \\ \\ R` = \frac{2}{4} = 0.5 \: Ω[/tex]

Thus, on doubling the wire on itself, its resistance becomes one-fourth.

Answer:

19

Explanation:

Avg. Vel = (28 + 10)/2

= 19

BTW, don't forget your units!

Answer:

10 m/s²

Explanation:

Given

Solving

The correct answer is 10 m/s² .

Answer:

The most logical explanation is A.

Explanation:

because we are explaining why the incandescent bulb uses less energy we can eliminate answers B and D then, because we are talking about energy efficiency which has nothing to do with connecting to another circuit we can go with, A because Ultraviolet light generated by fluorescent light bulbs is nothing compared to the heat of an incandescent light bulb because it was engineered to be so.

Answer:

4 km/min^2

Explanation:

acceleration is the rate of change of speed per time

25 -5 = 20 km/min speed change

20 km/min  / 5 min = 4 km /min^2

The time taken for the capacitor voltage to be 45 % of the battery voltage is 5,750.3 s.

The rate at which the capacitor voltage discharges is given by the following formula;

[tex]V = V_0(1 - e^{-t/RC})[/tex]

Where;

The final voltage = 0.45 x 5 V = 2.25 V

[tex]2.25 = 5(1 - e^{-t/RC})\\\\(1 - e^{-t/RC}) = \frac{2.25}{5} \\\\(1 - e^{-t/RC}) = 0.45\\\\e^{-t/RC} = 1- 0.45\\\\e^{-t/RC} = 0.55\\\\\frac{-t}{RC} = ln(0.55)\\\\\frac{-t}{RC} = -0.597\\\\t = 0.597 (RC)\\\\t = 0.597(3440 \times 2.8)\\\\t = 5,750.3 \ s[/tex]

Thus, the time taken for the capacitor voltage to be 45 % of the battery voltage is 5,750.3 s.

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Based on the latitude and time of the place, the solar angle for the day at 10am and 2pm is 51.6° and 73.0°.

The solar hour angle of a point on the earth’s surface is the angle through which the earth would turn to bring the meridian of the point directly under the sun.

The rotation of the earth on its axis is 15° per hour where before noon is negative and after noon is positive. For example, at 10:00 a.m. local apparent time the hour angle is −30°.

Therefore, based on the latitude and time, the solar angle for the day at 10am and 2pm is 51.6° and 73.0°.

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Answer: Matter is anything that is made of atoms and that has mass (A)

Explanation: All everyday objects that can be touched are ultimately composed of atoms. Even you are made of atoms. Anything that you can touch has moving particles unless the object is at absolute zero, which is not possible.

Hope this helps!

Answer:

True

Explanation:

The eletric potential on the x - axis at x = 0 cm for the given three charges is determined as 9 x 10⁶ V.

The electric potential at a point is the work done in moving a test charge from infinity to a certain point.

V(net) = V1 + V2 + V3

[tex]V = - \frac{kq}{r} \\\\V(net) = V_1 + V_2 + V_3\\\\V_{(net)} = -\frac{9\times 10^9 \times 200\times 10^{-6}}{0.2} + \frac{9\times 10^9 \times 300\times 10^{-6}}{0.3}+ \frac{9\times 10^9 \times 400\times 10^{-6}}{0.4}\\\\V_{(net)} = -9\times 10^6 \ + \ 9\times 10^6 \ + \ 9\times 10^6 \\\\V_{(net)} = 9\times 10^6 \ V[/tex]

Thus, the eletric potential on the x - axis at x = 0 cm for the given three charges is determined as 9 x 10⁶ V.

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#SPJ1

Answer:

b)    pressure increases with depth because of the weight of the fluid  above

P = ρ g H        density * gravity * fluid depth

(Note - force from the fluid below is an example of Newton's Third Law - for every action there is an equal and opposite reaction)

Answer:

Take your TIme maaaaaan

Explanation:

Chillax

Here's a question for you Care to go bowling?

Answer:

By taking it Slow.

Don't go too fast

Answer:

It's true that organisms get energy from food.

Answer:

Explanation:

Organisms ingest large molecules, like carbohydrates, proteins, and fats, and convert them into smaller molecules like carbon dioxide and water. This process is called cellular respiration, a form of catabolism, and makes energy available for the cell to use

Answer:

(It was a remove waste from cells)

Explanation:

the cell produces carbon dioxide and water, which are released as waste.

Answer:

Explanation:

This depends on the height.

Using the formula mgh + 1/2mv^2 = total mechanical energy, we can determine the amount of kinetic and potential energy. I'm assuming your talking about if the marble goes all the down, then all of the energy is converted.

The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is 101,204 Pa.

The difference in pressure between the top and bottom of the wingspan is calculated as follows;

ΔP = P(top) - P(bottom)

A = bh

A = 2.7 m x 0.27 m

A = 0.729 m²

W = mg

W = 9 x 9.8

W = 88.2 N

The pressure at the top surface of condor's wings is due to atmospheric pressure

P(top) = 14.7 Psi = 101,325 Pa

The pressure at the bottom surface is due to weight of andean condor.

P = W/A

P(bottom) = 88.2/0.729

P(bottom) = 120.99 Pa

The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is calculated as;

ΔP = P(top) - P(bottom)

ΔP = 101,325 Pa - 120.99 Pa

ΔP = 101,204 Pa

The complete question is below;

An Andean condor with a wingspan of 270 cm and a mass of 9.00 kg soars along a horizontal path. Model its wings as a rectangle with a width of 27.0 cm.

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Answer:

Explanation:

Multiple choices. 1)when two groups are playing tug of war the forces of the two groups are:- A)same direction B)opposite direction C)different direction but not possible D)A and B

a. 850 N is the minimum force needed to get the machine/player system moving, which means this is the maximum magnitude of static friction between the system and the surface they stand on.

By Newton's second law, at the moment right before the system starts to move,

• net horizontal force

∑ F[h] = F[push] - F[s. friction] = 0

• net vertical force

∑ F[v] = F[normal] - F[weight] = 0

and we have

F[s. friction] = µ[s] F[normal]

It follows that

F[weight] = F[normal] = (850 N) / (0.67) = 1268.66 N

where F[weight] is the combined weight of the player and machine. We're given the machine's weight is 200 N, so the player weighs 1068.66 N and hence has a mass of

(1068.66 N) / g ≈ 110 kg

b. To keep the system moving at a constant speed, the second-law equations from part (a) change only slightly to

∑ F[h] = F[push] - F[k. friction] = 0

∑ F[v] = F[normal] - F[weight] = 0

so that

F[k. friction] = µ[k] F[normal] = 0.56 (1268.66 N) = 710.45 N

and so the minimum force needed to keep the system moving is

F[push] = 710.45 N ≈ 710 N

The answer to your question is: C