A balloon containing 2. 6 mol hydrogen has a volume of 3. 9 l. More hydrogen is added to the balloon, giving it a volume of 17. 1 l. How many moles of hydrogen were added? show your work

(A) Helium gas would effuse faster than nitrogen gas. (B) The rate of effusion of helium to nitrogen gas is approximately 4:1. (C) It would take helium gas approximately 5.5 seconds to effuse.

Part (A): The rate of effusion is directly proportional to the velocity of the gas particles, which is inversely proportional to the square root of their masses.

Helium gas has a smaller molar mass (4 g/mol) than nitrogen gas (28 g/mol), which means its particles have a higher velocity and would effuse faster.

Part (B): According to Graham's law of effusion, the rate of effusion of two gases is inversely proportional to the square root of their molar masses.

Therefore, the rate of effusion of helium to nitrogen gas can be calculated as the square root of the ratio of their molar masses, which is approximately 4:1.

Part (C): Using Graham's law of effusion again, we can set up a proportion to find the time it would take helium gas to effuse if nitrogen gas takes 22 seconds.

The ratio of the square roots of their molar masses is 1:√7, so the proportion is:

√(4/28) : √(1/√7) = 22 : x

Solving for x, we get approximately 5.5 seconds.

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Answer is D)1.10 grams

From the balanced equation, we know that for every 1 mole of carbonic acid (H2CO3) that is heated, 1 mole of carbon dioxide ([tex]CO_2[/tex]) is produced. The molar mass of [tex]H_2CO_3[/tex] is 62.03 g/mol, while the molar mass of [tex]CO_2[/tex] is 44.01 g/mol.

To find out how much carbon dioxide is formed from 1.55 g of carbonic acid, we first need to convert the mass of  [tex]H_2CO_3[/tex] to moles:

1.55 g  [tex]H_2CO_3[/tex] / 62.03 g/mol  [tex]H_2CO_3[/tex] = 0.025 mol  [tex]H_2CO_3[/tex]

Since the mole ratio of [tex]H_2CO_3[/tex] to [tex]CO_2[/tex] is 1:1, we know that 0.025 moles of [tex]CO_2[/tex] will be produced.

To convert this to grams:

0.025 mol [tex]CO_2[/tex] x 44.01 g/mol [tex]CO_2[/tex] = 1.10 g CO2

Therefore, 1.55 g of carbonic acid will produce 1.10 g of carbon dioxide upon heating.

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The sample of crushed rock containing 4.81 x 10²¹ atoms of gold corresponds to 0.008 moles of gold.

The number of moles of gold in the sample of crushed rock can be calculated by dividing the total number of atoms of gold by Avogadro's number, which represents the number of particles in one mole of a substance.

First, we convert the given value of atoms of gold to moles by dividing by Avogadro's number (6.022 x 10²³ atoms per mole).

Number of moles of gold = 4.81 x 10²¹ atoms / 6.022 x 10²³ atoms/mol

Simplifying the calculation, we get:

Number of moles of gold = 0.00799 moles

Therefore, there are approximately 0.008 moles of gold present in the sample of crushed rock.

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The average rate of reaction for the time interval from 180s to 300s is 0.00083 M/s.

To calculate the average rate of reaction for a given time interval, we need to know the change in the concentration of a reactant or product over that time period. Let's assume that we have that information.

The average rate of reaction from 180s to 300s can be calculated using the following formula:

average rate = (change in concentration)/(change in time)

Let's say that the concentration of a product increased from 0.05 M to 0.15 M over the time interval from 180s to 300s. The change in concentration is:

change in concentration = final concentration - initial concentration

change in concentration = 0.15 M - 0.05 M

change in concentration = 0.10 M

The change in time is:

change in time = final time - initial time

change in time = 300 s - 180 s

change in time = 120 s

Now we can substitute these values into the formula to find the average rate of reaction:

average rate = (change in concentration)/(change in time)

average rate = (0.10 M)/(120 s)

average rate = 0.00083 M/s

Therefore, the average rate of reaction for the time interval from 180s to 300s is 0.00083 M/s.

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The final temperature is 49.2 degrees Celsius.

To find the final temperature, we can use the formula:

Q = mcΔT

where Q represents the amount of heat energy measured in calories (450.5 calories), m represents the mass of the substance in grams (89.6 grams), c represents the specific heat capacity in calories per gram per degree Celsius (0.215 calories/gram degree Celsius), and ΔT represents the change in temperature.

First, we need to find the change in temperature (ΔT):

450.5 calories = (89.6 grams) * (0.215 calories/gram degree Celsius) * ΔT

Now, we can solve for ΔT:

ΔT = 450.5 calories / [(89.6 grams) * (0.215 calories/gram degree Celsius)] ≈ 23.5 degrees Celsius

Since we know the initial temperature (25.7 degrees Celsius), we can find the final temperature:

Final temperature = Initial temperature + ΔT = 25.7 degrees Celsius + 23.5 degrees Celsius ≈ 49.2 degrees Celsius

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The term mole concept is used here to determine the number of atoms in 6.88 moles of AgNO₃. The number of atoms present in 6.88 moles of AgNO₃ is

One mole of a substance is defined as that amount of it which contains as many particles or entities as there are atoms in exactly 12 g of carbon-12. The equation used to calculate the number of moles is given as:

4. Number of atoms = Number of moles of atoms × 6.022 × 10²³

6.88 × 6.022 × 10²³ = 4.14 × 10²⁴

5. Number of moles of atoms = 278 / 110.98 = 2.50

Number of atoms = 2.50 × 6.022 × 10²³ = 1.50 × 10²⁴

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States bordering the Gulf of Mexico have fossilized seashells from millions of years ago that were discovered on the ground far from the shore. This is evidence of previous geological and environmental changes in the area.

These fossils imply that the sea levels were much higher than they are today and that the area was once submerged underwater. The land rose and the sea retreated over time due to the movement of tectonic plates and other geological processes, leaving fossilized relics of marine life on what is now dry land. These fossils help us better comprehend the long-term processes that have changed our planet over millions of years and offer insightful information on the history of the area.

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When sodium hydroxide reacts with a copper nitrate solution, the reaction vessel needs to be kept on ice to slow down the reaction. This describes an exothermic reaction.

An exothermic reaction is a type of reaction which releases heat.

The cooling provided by the ice helps control the reaction rate and prevents it from becoming too vigorous or unmanageable.

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The types of rocks being described in this process are sedimentary and metamorphic. (A)

Dead plant material, which is organic, is compressed into coal, which is a type of sedimentary rock. The coal is then buried within the earth and subjected to heat and pressure from the overlying material, which turns it into anthracite coal, a type of metamorphic rock.

Sedimentary rocks are formed from the accumulation and cementation of sediment, such as dead plant material. Metamorphic rocks are formed from the transformation of existing rocks under intense heat and pressure. In this case, the coal is transformed into anthracite coal through the process of metamorphism.

Igneous rocks are not mentioned in this process, as they are formed from the cooling and solidification of magma or lava, and do not play a role in the formation of coal. Therefore, the correct answer is A: sedimentary and metamorphic.

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Calcium carbonate is dissolved by acidic groundwater, creating limestone caves. It is possible for the rate of chemical reactions to accelerate when the temperature of limestone rock in a cave rises.

This could speed up the decomposition of calcium carbonate, which would speed up the creation of caves. The reverse outcome, though, is also possible because a rise in temperature can also make the water in the cave evaporate, which can cause calcium carbonate to precipitate and give rise to stalactites, stalagmites, and other structures. The balance between dissolution and precipitation reactions, and how these are altered, determine how temperature affects cave development.

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The molarity of an aqueous solution containing 6.7 moles of potassium chloride in 0.63L is 10.6 M.

The quantity of solute molecules per litre of solution is known as a solution's molarity. In this issue, we are given the number of moles of solute (potassium chloride) and the volume of the solution. We can use this information to calculate the molarity of the solution using the following formula:

Volume of solution (V) / moles of solute (n) equals molarity (M).

Substituting the given values, we get:

Molarity (M) = 6.7 moles / 0.63 L = 10.6 M

Therefore, the molarity of the solution is 10.6 M, rounded to the tenths place.

It is important to note that molarity is a measure of concentration and is affected by both the amount of solute and the volume of the solution. Thus, it is important to accurately measure the volume of the solution to calculate the molarity correctly.

Furthermore, it is important to use caution when handling concentrated solutions such as this one, as they can be hazardous. Proper safety equipment and procedures should be followed when working with such solutions.

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There are approximately 3.40 x 10²⁴ molecules in 9.44 moles of AlCl₃.

This is calculated by using Avogadro's number (6.022 x 10²³) and multiplying it by the number of moles given.


To calculate the number of molecules in a given amount of substance, we use Avogadro's number, which is 6.022 x 10²³. This number represents the number of particles (molecules, atoms, ions) in one mole of a substance.

In this case, we are given the number of moles of AlCl₃, which is 9.44. To calculate the number of molecules, we simply multiply the number of moles by Avogadro's number:

9.44 moles AlCl₃ x 6.022 x 10²³ molecules/mole = 3.40 x 10²⁴ molecules AlCl₃

Therefore, there are approximately 3.40 x 10²⁴ molecules in 9.44 moles of AlCl₃.

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1) The solution is saturated. 2) 40 grams of KCl has dissolved in 100 grams.  3) 50 grams of KClO₃ will dissolve. 4) 75 grams of H₂O can dissolve 24.6 grams. 5) To saturate 28.4 grams of CaCl₂ must be added.

Saturated is a term used to describe a state of being filled to capacity, or containing the maximum amount possible. It is most commonly used in reference to liquids, where it indicates that no more of a given substance can be dissolved into the liquid. In chemistry, saturation refers to the point at which a solution has reached its maximum solubility.

1) The solution is saturated because 65 grams of Pb(NO₃)₂ has dissolved in 100 grams of H₂O at 25°C.

2) 40 grams of KCl has dissolved in 100 grams of H₂O at 10°C, so no more will dissolve.

3) 50 grams of KClO₃ will dissolve in 92.5 grams of H₂O at 70°C.

4) 75 grams of H₂O can dissolve 24.6 grams of K₂Cr₂O7 at 90°C.

5) At 25°C, 59 grams of CaCl₂ has dissolved in 100 grams of H₂O. To saturate the solution, an additional 28.4 grams of CaCl₂ must be added.

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The term molarity is an important method which is used to calculate the concentration of a solution. By dissolving the same number of moles of each substance in the same volume of water we can make solutions of same molarity. The correct option is B.

Molarity is defined as the number of moles of the solute present per litre of the solution. It is represented as 'M' and its unit is mol / L. The term molarity is also called the molar concentration.

When same number of moles of substances are dissolved in the same volume of water, then the two solutions have same molarity.

Thus the correct option is B.

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The amount of heat that would be given out is 14.1kJ.

Heat capacity is a physical property that describes the amount of heat required to raise the temperature of a substance by one degree Celsius. We know that the heat capacity of steam is 2J/g/°C.

We can tell that;

H = mcdT

H = heat that is absorbed or evolved

m = mass of the object

c = Heat capacity of the object

dT = temperature change

Then we have that;

H = 150 * 2 * (98 - 145)

H = -14.1kJ This is the heart lost

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The specific heat capacity of glass is 0.84 J/g°C.

To calculate the specific heat capacity of the glass, follow these steps:
1. Determine the energy gained by the water: Q_water = m_water * c_water * ΔT_water
2. Determine the energy lost by the glass: Q_glass = m_glass * c_glass * ΔT_glass
3. Since energy is conserved, Q_water = Q_glass
4. Solve for the specific heat capacity of the glass (c_glass).


m_glass = 45.7 g
m_water = 250.0 g
c_water = 4.18 J/g°C
Initial temperature of water (T1_water) = 22.5°C
Final temperature (T2) = 24.2°C
ΔT_water = T2 - T1_water = 1.7°C
ΔT_glass = T2 - 100°C = -75.8°C

1. Q_water = 250.0 g * 4.18 J/g°C * 1.7°C = 1776.7 J
2. Q_glass = 45.7 g * c_glass * (-75.8°C)
3. 1776.7 J = 45.7 g * c_glass * (-75.8°C)
4. c_glass = 0.84 J/g°C

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The gravitational potential energy of the stone on the moss is 147 joules.

Gravitational potential energy is the energy possessed by an object due to its position in a gravitational field. It is defined as the energy required to move an object of a given mass from infinity to its current position against the force of gravity.

In the case of the stone weighing 1.5 kilograms resting on a rock at a height of 20 meters above the ground, the gravitational potential energy can be calculated using the formula PE = m × g × h, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above the ground.

So, in this case, the gravitational potential energy of the stone at a height of 20 meters can be calculated as:

PE = m × g × h
PE = 1.5 kg × 9.8 N/kg × 20 m
PE = 294 J

When the stone rolls down 10 meters and comes to rest on a patch of moss, its height above the ground decreases to 10 meters. The gravitational potential energy of the stone on the moss can be calculated using the same formula:

PE = m × g × h
PE = 1.5 kg × 9.8 N/kg × 10 m
PE = 147 J

Therefore, the gravitational potential energy of the stone on the moss is 147 joules.

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The pair of elements that have the most similar Lewis structures are F and Ne.

The Lewis structure of an atom shows its valence electrons as dots around the symbol representing the nucleus. Atoms with similar Lewis structures have similar numbers of valence electrons and, therefore, similar chemical properties.

N and S have different numbers of valence electrons (5 and 6, respectively), so their Lewis structures are different.

P and F have different numbers of valence electrons (5 and 7, respectively), and the placement of the dots on their Lewis structures is different.

F and Ne both have 7 valence electrons and would have similar Lewis structures, with one dot representing each valence electron. They are both nonmetals and are found in the same period of the periodic table, which also contributes to their similar chemical properties.

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The specific heat of the glass is 1.58 J/(g°C).

The specific heat of a substance is the amount of energy required to raise the temperature of one unit of mass of the substance by one degree Celsius.

To find the specific heat of the glass, we can use the formula:

Q = mcΔT

where Q is the amount of energy transferred to the glass, m is the mass of the glass, c is the specific heat of the glass, and ΔT is the change in temperature of the glass.

We are given:

m = 385 g

Q = 7032 J

ΔT = 24°C - 12°C = 12°C

Substituting these values into the formula, we get:

7032 J = (385 g) c (12°C)

Solving for c, we get:

c = 7032 J / (385 g * 12°C)

c = 1.58 J/(g°C)

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The Arrhenius equation describes the relationship between the rate constant (k) of a chemical reaction and the temperature (T) at which the reaction occurs. The equation is given as:

k = Ae^(-Ea/RT)

where A is the pre-exponential factor or frequency factor, Ea is the activation energy required for the reaction to occur, R is the gas constant, and e is the base of the natural logarithm.

The Arrhenius equation indicates that as the temperature of a chemical reaction increases, the rate constant also increases exponentially.

The activation energy term (Ea) represents the minimum energy required for reactants to form products, and the pre-exponential factor (A) represents the frequency of successful collisions between reactant molecules.

This equation is commonly used in the study of chemical kinetics, which is the study of the rates of chemical reactions and the factors that affect them.

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A cylinder of Krypton has contains 17 L of Ar at 22. 8 atm and 112 degrees celsisus. There are 0.824 moles of Ar in the cylinder.

The number of moles of Ar in the cylinder can be calculated using the ideal gas law equation: PV = nRT, where P is the pressure in atm, V is the volume in liters, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.

To use this equation, the given temperature of 112 degrees Celsius must be converted to Kelvin by adding 273.15 to get 385.15 K. The pressure of 22.8 atm and volume of 17 L are already in the correct units.

R can be found using the equation R = 0.0821 L atm/(mol K), and plugging in the values for P, V, n, R, and T gives: (22.8 atm)(17 L) = n(0.0821 L atm/(mol K))(385.15 K) n = 0.824 mol

The number of moles of Ar in the cylinder can be found using the ideal gas law equation, which requires the pressure, volume, temperature, and the gas constant. After converting the given temperature to Kelvin, the calculation yields 0.824 moles of Ar.

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The concentration of the solution is 0.748 M.

To find the concentration of the solution, we need to calculate the number of moles of calcium carbonate present in the solution.

First, we need to determine the molecular weight of calcium carbonate ([tex]CaCO3[/tex]).

[tex]CaCO3[/tex] = 1 x Ca + 1 x C + 3 x O

= 40.08 g/mol + 12.01 g/mol + (3 x 16.00 g/mol)

= 100.09 g/mol

Next, we can use the formula:

concentration (in mol/L) = moles of solute / volume of solution (in L)

We have 37.5 grams of calcium carbonate in 500 ml of water. To convert ml to L, we divide by 1000:

volume of solution = 500 ml / 1000 ml/L = 0.5 L

moles of calcium carbonate = mass / molecular weight

= 37.5 g / 100.09 g/mol

= 0.374 moles

Therefore, the concentration of the solution is:

concentration = 0.374 moles / 0.5 L

= 0.748 M

The concentration of the solution is 0.748 M.

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The initial temperature of the water is 25.8 °C. As a result, the lead ball loses heat rapidly when it is placed in the water bath, causing the water temperature to increase significantly.

What is  Temperature?

Temperature is a measure of the average kinetic energy of the particles in a substance. It is a physical quantity that describes how hot or cold an object is. Temperature is usually measured using a thermometer and is commonly expressed in units such as degrees Celsius (°C), Fahrenheit (°F), or Kelvin (K).

The energy gained by the water can also be calculated using the formula:

Q = mcΔT

where Q is the energy gained (in joules), m is the mass of the water (in grams), c is the specific heat capacity of water (in J/g°C), and ΔT is the change in temperature of the water (in °C).

We can calculate Q as follows:

Q = (500.0 g)(4.184 J/g°C)(35°C - T)

where T is the initial temperature of the water.

Since the energy lost by the lead ball is equal to the energy gained by the water, we can set these two equations equal to each other and solve for T:

(20.0 g)(0.13 J/g°C)(705°C - T) = (500.0 g)(4.184 J/g°C)(35°C - T)

Simplifying and solving for T gives:

T = 25.8°C

Therefore, the initial temperature of the water is 25.8 °C.

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Chemical change results in a new substance and it cannot be reversed by physical means.

Chemical changes is said to occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances  and are not reversible except by further chemical reactions.

Examples of chemical change would be:

It is also worthy to note that in a physical change, no new substance is formed and also a  chemical change is always accompanied by one or more new substance.

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Aromatic hydrocarbons are organic compounds that contain one or more benzene rings in their structure. These compounds are characterized by their strong, pleasant odor, which is why they are called aromatic. They are commonly found in petroleum products and are often used as feedstock for the production of chemicals and fuels.

Out of the options given, clothing and polyvinyl chloride do not contain aromatic hydrocarbons. On the other hand, barbecue fuel and pain relievers can contain aromatic hydrocarbons.

Barbecue fuel, also known as charcoal briquettes, is made from compressed charcoal dust mixed with a binding agent. The charcoal is made by heating wood in the absence of oxygen to remove the moisture and other impurities. The resulting charcoal contains a high concentration of aromatic hydrocarbons, which gives it its characteristic smell and helps it burn efficiently.

Pain relievers, such as aspirin and ibuprofen, are also known to contain aromatic hydrocarbons. These compounds are used in the synthesis of these drugs as intermediates, and traces of them can be present in the final product. However, the levels are generally low and not considered harmful to health.

In summary, barbecue fuel and pain relievers can contain aromatic hydrocarbons, while clothing and polyvinyl chloride do not. It is important to note that exposure to high levels of these compounds can be harmful to health, and precautions should be taken to minimize exposure.

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Answer: b

Explanation: because i just took the quiz

On day 4, you would observe a significant growth of white, fuzzy mycelium. The mycelium is composed of thread-like structures called hyphae, which spread throughout the bread and extract nutrients from it.

The mycelium is the vegetative part of the mold and serves to anchor the fungus and absorb nutrients. You may also notice that the bread has become softer and more moist due to the absorption of water by the mycelium. Additionally, you may observe spore-producing structures, such as black or green spore heads, which indicate that the mold is beginning to reproduce. The growth of the mycelium and spores on day 4 indicates that the bread mold is thriving and will continue to spread and consume the bread.

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In a 23.5 mol sample of C₇H₅N₃O₆, there are 6.87 moles of nitrogen atoms and 8.79 moles of oxygen atoms.

In order to determine the number of moles of nitrogen and oxygen atoms in a 23.5 mol sample of C₇H₅N₃O₆, we first need to look at the chemical formula for this compound.

From the formula, we can see that there are 7 nitrogen atoms and 9 oxygen atoms present in each molecule of C₇H₅N₃O₆.

To calculate the number of moles of nitrogen atoms, we multiply the total number of moles by the mole fraction of nitrogen in the compound:

Moles of nitrogen = 23.5 mol x (7 nitrogen atoms / 24 total atoms)
Moles of nitrogen = 6.87 mol

Similarly, to calculate the number of moles of oxygen atoms, we use the mole fraction of oxygen in the compound:

Moles of oxygen = 23.5 mol x (9 oxygen atoms / 24 total atoms)
Moles of oxygen = 8.79 mol

Therefore, there are approximately 6.87 moles of nitrogen atoms and 8.79 moles of oxygen atoms in a 23.5 mol sample of C₇H₅N₃O₆.

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If the final temperature of the wood is 57C, then the initial temperature of the wood would have been 32.00 ºC.

To solve the problem, we can use the formula,

Q = m * c * ΔT , amount of heat absorbed by the wood is Q, its mass is m, specific heat capacity is c, the change in temperature is ΔT.

We know that m = 1500.0 g, c = 1.8 J/gºC, Q = 67,500 J, and the final temperature T₂ = 57ºC. We need to find the initial temperature T₁.

First, we can calculate the change in temperature,

ΔT = T₂ - T₁

ΔT = 57ºC - T₁

Next, we can rearrange the formula to solve for T₁,

T₁ = T₂ - (Q / (m * c))

T₁ = 57ºC - (67,500 J / (1500.0 g * 1.8 J/gºC))

T₁ = 57ºC - 25ºC

T₁ = 32ºC

Therefore, the initial temperature of the wood was 32.00 ºC.

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