A billiard ball of mass 0.28 kg hits a second, identical ball at a speed of 8.6 m/s
and comes to rest as the second ball flies off. The collision takes 250 μs.

What is the average force on the first ball?

What is the average force on the second ball?

Answers

Answer 1

The average force on the first ball = - 272.8 N.

The average force on the second ball is 9,568 N, and it acts in the direction of its motion.

What is the principle of conservation?

the principle of conservation of momentum, which states that the total momentum of a closed system remains constant if no external forces act on it. In this case, the two billiard balls can be considered as a closed system.

Let's define some variables:

m =  (mass of each ball)

v1 =  (initial velocity of the first ball)

v2 =  (final velocity of the second ball)

t = 250 μs = 0.00025 s (duration of the collision)

According to the conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision:

m * v1 = m * v2

Solving for v2, we get:

v2 = v1 * (m/m) = v1

This indicates that the second ball departs in the opposite direction of the first ball but with the same velocity. As a result, the system's total momentum is preserved.

The impulse-momentum theorem states that the impulse (change in momentum) is equal to the average force multiplied by the duration of the collision. We can use this to determine the average force on the first ball:

F1 * t = m * (v2 - v1)

Substituting the values we know, we get:

F1 * 0.00025 = 0.28 * (-8.6)

Solving for F1, we get:

F1 = - 272.8 N

The first ball's force is acting in the opposite direction of its initial velocity when the sign is negative.

To find the typical power on the subsequent ball, we can utilize a similar recipe:

F2 * t = m * (v2 - v1)

Substituting the values we know, we get:

F2 * 0.00025 = 0.28 * (v2 - 0)

Since we know that v2 = 8.6 m/s, we can solve for F2:

F2 = (0.28 * 8.6) / 0.00025

F2 = 9,568 N

Therefore, the average force on the second ball is 9,568 N, and it acts in the direction of its motion.

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Related Questions

31. IP Point charges +4.1 µC and -2.2 μC are placed on the x axis at (11 m, 0) and (-11 m, 0), respectively. (a) Sketch the electric potential on the x axis for this system. (b) Your sketch should show one point on the x axis between the two charges where the potential vanishes. Is this point closer to the +4.1-C charge or closer to the -2.2-µC charge? Explain. (c) Find the point referred to in part (b).​

Answers

Explanation:

let at a distance x from the c

Remember the steps that the American Heart Association recommends for saying no to cigarettes. Which one of these will you use if you are faced with peer pressure to smoke? Which one of these will you use if you are faced with peer pressure to drink or take drugs? Explain the method you will use and why you chose it.

Answers

Answer: just say no and never talk to that person again.

Explanation:

because that is what i would do to prevent drugs and/or nicotine to enter my body.

A student decides to devise a new temperature scale with the freezing and boiling points at 0° X and
70° X. What Celsius temperature would correspond to a temperature of 35° X?
O 50
O 35
O 90
O 70

Answers

Answer:

To convert temperature from the new scale (X) to Celsius, we simply subtract 0 from the value in X and then multiply the resulting number by a factor of 100/70. This gives us the Celsius temperature.

For 35° X, we can use the formula as follows:

C = (35 - 0) * (100/70)

C = 35 * 1.4286

C = 50°C

Therefore, the correct answer is option A, which is 50.

The lightweight wheel on a road bike has a moment of inertia of 0.097 kg⋅m2
. A mechanic, checking the alignment of the wheel, gives it a quick spin; it completes 5 rotations in 2.2 s. To bring the wheel to rest, the mechanic gently applies the disk brakes, which squeeze pads against a metal disk connected to the wheel. The pads touch the disk 7.1 cm from the axle, and the wheel slows down and stops in 1.2 s.

What is the magnitude of the friction force on the disk?

Answers

the magnitude of the friction force on the disk is approximately 1.16 N.

We can use the conservation of energy to find the friction force on the disk. The initial kinetic energy of the wheel is equal to the work done by the friction force on the disk:

K_i = W_friction

The initial kinetic energy of the wheel can be found from its moment of inertia and angular velocity:

K_i = (1/2) I [tex]ω^2[/tex]

where I is the moment of inertia, ω is the angular velocity, and the factor of 1/2 comes from the rotational kinetic energy formula.

The final kinetic energy of the wheel is zero, since it comes to a stop. The work done by the friction force can be found from the distance over which it acts:

W_friction = F_friction d

where F_friction is the friction force and d is the distance over which the pads act on the disk. We can find the distance from the angular displacement of the wheel:

θ = ω t

where θ is the angle through which the wheel rotates, t is the time for the wheel to come to a stop, and the factor of 1/2π converts from rotations to radians. The distance over which the pads act is then:

d = r θ = 0.071 m × (5/2π) ≈ 0.562 m

Now we can put everything together:

K_i = W_friction

(1/2) I [tex]ω^2[/tex] = F_friction d

We can solve for the friction force:

F_friction = (1/2) I [tex]ω^2[/tex] / d

Plugging in the given values:

F_friction = (1/2) ×[tex]0.097 kg⋅m^2[/tex] × [tex](5/2.2π rad/s)^2[/tex] / 0.562 m ≈ 1.16 N

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A green ball and a blue ball have a mass of 10 kg each one. The green ball, traveling at 10 m/s, strikes the blue ball, which is at rest. Assuming that the balls slide on a frictionless surface and all collisions are head-on, find the final speed of the blue ball in each of the following situations:

a. The green ball stops moving after it strikes the blue ball

b. The green ball continues moving after the collision at 4 m/s in the same direction.

Answers

(a) The final velocity of the blue ball is 5 m/s after the collision

(b)  The final velocity of the blue ball is 6 m/s after the collision.

What is the final velocity of the balls?

To solve this problem, we can use the conservation of momentum and the conservation of kinetic energy. The total momentum and total kinetic energy of the system before and after the collision must be the same.

a. When the green ball stops moving after the collision, its final velocity is 0 m/s. Let's call the final velocity of the blue ball v. The conservation of momentum equation is:

m_green x v_green + m_blue x v_blue = (m_green + m_blue)v

Substituting the values, we get:

10 kg x 10 m/s + 10 kg x 0 m/s = 20 kg x v

Simplifying, we get:

v = 5 m/s

b. When the green ball continues moving after the collision at 4 m/s in the same direction, its final velocity is 4 m/s. Let's call the final velocity of the blue ball v.

The conservation of momentum equation is the same as before:

m_green x v_green + m_blue x v_blue = (m_green + m_blue)v

Substituting the values, we get:

10 kg x 10 m/s + 10 kg x 0 m/s = 10 kg x 4 m/s + 10 kg x v

Simplifying, we get:

v = 6 m/s

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4. An ice skater is spinning on the ice at 4.00 rev/s. If the skater’s nose is 0.120 m from the axis of rotation, what is the centripetal acceleration of his nose?

Answers

Answer:

a = 3.02 m/s^2

h

Explanation:

we know that centripetal acceleration (a) is

[tex] \frac{v {}^{2} }{r} = a[/tex]

since v = rω, we can substitute it into the equation, which now gives us the centripetal acceleration in terms of angular velocity and radius (check image).

now we use the values given and find the answer

A horizontal force of 25 N is exerted on a box (mass 10 kg), as shown in the diagram. The box accelerates at 2.0 m.s-2. What is the magnitude of the frictional force acting between the box and the floor?​

Answers

Answer:

the magnitude of the frictional force acting between the box and the floor is 5 N.

Explanation:

A 10,000 kg freight car is rolling along a track at 3.00m.s.Calculate the time needed for a force of 1000N for stop the car

Answers

It takes 0.3 seconds for a force of 1000 N to halt a 10,000 kg goods car moving at 3.00 m/s along a track.

Calculate the time needed for a force of 1000N for stop the car

We must first establish the car's starting kinetic energy in order to calculate the time required to stop the vehicle:

Kinetic Energy (KE) is equal to half of mass times speed, or 10,000 kg times 3.00 m/s.

KE = 45,000 J

Then, we may use the designed with the intent, which asserts that an object's change in kinetic energy equals the jobs performed by an external force: Work equals Force x Distance x Change in KE.

The gain in kinetic energy is equal to the starting kinetic energy because the car is coming to a stop: KE Change = -45,000 J

As a result, the external force's work is: Work equals force times distance, or -45,000 J.

When we solve for distance, we obtain: Work / Force = -45,000 J / 1000 N Distance

Location = -45 m

Because the force is against the direction of the car's motion, you'll see that the range is negative.

Finally, we can calculate the travel time using the kine model for uniformly accelerated motion: Distance is equal to 1/2*acceleration*time2. Time is calculated as sqrt(2 * Distance / Acceleration) as well as sqrt(2 * 45 m / (1000 N / 10,000 kg)).

time equals sqrt(0.09 s2/kg).

time = 0.3 s

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why would the acceleration not change when adding mass to an air cart?

Answers

Answer:

The acceleration of an air cart, which is an object moving on a cushion of air, would not change when adding mass to it because the force of air resistance acting on the cart is negligible compared to the force applied by the air source that propels it. Therefore, the total force acting on the cart remains almost constant, regardless of the cart's mass, and according to Newton's second law of motion, the cart's acceleration would remain the same. This assumes that the air source provides a constant force and that the added mass does not significantly affect the friction between the cart and the surface on which it is moving.

Q37. A major source of heat loss from a house in cold weather is through the windows. Calculate the rate of heat flow through a glass window 2.0m x 1.5m in area and 3.2mm thick, it the temperatures at the inner and outer surfaces are 15.00C and 14.0°C​

Answers

The rate of heat flow through the window is approximately 84.38 W.

To calculate the rate of heat flow through a glass window

The rate of heat flow through the window can be calculated using the formula:

Q = (kA (T1 - T2))/d

Where

Q is the rate of heat flowk is the thermal conductivity of the glassA is the area of the windowT1 is the temperature at the inner surfaceT2 is the temperature at the outer surfaced is the thickness of the glass

We first need to convert the temperatures to Kelvin, since temperature differences must be in Kelvin in this formula:

T1 = 15.0°C + 273.15 = 288.15 K

T2 = 14.0°C + 273.15 = 287.15 K

The thermal conductivity of glass can vary depending on the type of glass, but a typical value is around k = 0.9 W/(m·K) for plate glass.

Substituting the given values into the formula, we get:

Q = (0.9 W/(m·K) x 2.0 m x 1.5 m x (288.15 K - 287.15 K))/0.0032 m

Simplifying this expression, we get:

Q ≈ 84.38 W

Therefore, the rate of heat flow through the window is approximately 84.38 W.

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Need help with this ​

Answers

Explanation:

See image for definitions....look at the units and fill the blanks appropriatly

The following conversion equivalents are given:
1 m 100 cm 1 in = 2.54 cm 1 ft = 12 in
A bin has a volume of 1.5 m3. The volume of the bin, in ft3, is closest to:

Answers

Answer:52.972ft^3

Explanation:

It is unit conversion based and for a volume of a bin from cubic meter to cubic foot as we know 1 meter =3.281 foot.

where volume=1.5m^3

multiply 1.5*(3.281)^3 ft^3

v=52.972 ft^3

A machine has a velocity ratio of 5. ut requires a 50kg weight to overcome 20kg weight. calculate the efficiency of the machine ( take g= 10m/s^2)​

Answers

Answer:

The answer is 8%

Explanation:

We know that the efficiency of the machine is given by,

E=(M.A)*100

=([tex]\frac{20}{50}[/tex])*[tex]\frac{1}{5}[/tex]*100

=8%

A metal weigh 20N in air, 12N in water, and 14N in Kerosene. Cal the the Relative density of (a) Metal (b) kerosene​

Answers

The relative density of kerosene is 0.006, or 6 kg/m³.

A metal block that weighs 60 tonnes in the air and 40 tonnes beneath water, what is its density?

1 Response. Employ the Archimedes' Principle to your advantage: the buoyant force of a fluid is equal to the apparent loss of weight in water and is also equal to the weight of the displaced fluid. Weight of the displaced water equals 60 - 40 N, or the apparent loss in weight of the metal block. Water displacement mass is calculated as 20 / 9.8 = 2.04 kg.

Buoyant force = Weight of the displaced water = 20 N - 12 N = 8 N

Volume of water displaced = Buoyant force / Density of water = 8 N / 9.8 m/s² = 0.8163 kg

Density of metal = Weight of metal in air / Volume of metal = 20 N / (density of air x volume of metal)

Density of metal = 20 N / 0.8163 kg = 24.5 kg/m³

Buoyant force = Weight of the displaced kerosene = 20 N - 14 N = 6 N

Volume of kerosene displaced = Buoyant force / Density of kerosene = 6 N / 9.8 m/s² = 0.6122 kg

Density of kerosene = Mass of kerosene / Volume of kerosene displaced = 14 N / 0.6122 kg = 22.86 kg/m³

Relative density of kerosene = Density of kerosene / Density of water = 22.86 kg/m³ / 1000 kg/m³ = 0.006, or 6 kg/m³.

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QUICK ANSWER Fiber optic cables utilize internal reflection to transmit signals. TRUE OR FALSE

Answers

PLS MRK ME BRAINLIEST

Answer:

True

Explanation:

optical fibre consists of core and cladding. The signal is converted to light using transducers. The light travels across the cable undergoing multiple internal reflections. At the other end the light is converted back to Signal using transducers.

Answer: True

Explanation: Optical fiber uses the optical principle of "total internal reflection" to capture the light transmitted in an optical fiber and confine the light to the core of the fiber.

If I get this wrong im sorry

If astronomers were to find they have made a mistake and our solar system is actually 7.2 (rather than 8.2) kpc from the center of the galaxy, but the orbital velocity of the sun is still 240 km/s, what is the minimum mass of the galaxy?

Answers

Assuming a circular orbit for the Sun, we can use the equation:

v^2 = GM/r

where v is the orbital velocity of the Sun, r is the distance from the center of the galaxy, G is the gravitational constant, and M is the mass of the galaxy.

We can solve for M:

M = v^2 * r / G

Using the given values of v = 240 km/s and r = 7.2 kpc = 7.2 * 3.086e+19 m, and G = 6.6743e-11 N m^2/kg^2, we get:

M = (240000 m/s)^2 * 7.2 * 3.086e+19 m / 6.6743e-11 N m^2/kg^2

M = 1.47e+42 kg

Therefore, the minimum mass of the galaxy, if the distance of the solar system from the center is actually 7.2 kpc, is approximately 1.47 x 10^42 kg.

6. Construct a new physical equations having in terms of G, C and h dimensions of length where G is universal gravitational constant, c is the speed of light and I is planck's Constant.​

Answers

Basic values of mass in the existing program are c1/2 G-12 h1/2 if the speed of light (c), newtonian constant (G), and Planck's parameter (h) are taken as the fundamental units.

What is the G equivalent of the principle of the universal gravitational equation?

According to the Universal Gravitation Equation, G is equal to 6.673 x 10-11 N m2/kg2. Everything because of how a fruit falls from a tree to the reason the moon rotates around the earth may be explained by the Universal Gravitational Law.

What does the formula for the universal law of gravity mean?

This rule states that the distance is proportional to the product of the mass of the two objects. The Universal Law of Force of gravity is summed up by the following gravitational force equation: FG = (G.m1.

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From time to time, people claim to have invented a machine that will run forever without energy input and develop more energy than it uses (perpetual motion). What is wrong with this claim?

Answers

Explanation:

It ignores some basic laws of physics:

  You cannot get more work out of a machine than goes in

    You cannot ignore friction

At the point 0, there are 2 point sources, emitting the same constant sound power,
with intensity in inversely proportional to the square of the distance from the source. At the point A, the sound level intensity is [tex]20dB[/tex]
(a) What is the sound level intensity at A of one source?
(b) What is the number of sources that we have to add at A so that the sound level intensity at the midpoint M of OA is [tex]30dB[/tex]?

Answers

The number of sources that we have to add at A so that the sound level intensity at M is doubled is 2.

(a) Let the distance of point A from one source be x. Then the distance from the other source is (OA - x), where OA is the distance between the two sources. The sound intensity at point A due to one source is proportional to 1/x^2. So, if the sound power of one source is P, then the sound intensity at A due to one source is given by I = P/(4πx^2), where 4πx^2 is the surface area of a sphere with radius x.

The sound level intensity is defined as L = 10log(I/I0), where I0 is a reference intensity (I0 = 10^-12 W/m^2). Since there are two sources, the total sound intensity at A is twice the sound intensity due to one source, i.e., I_total = 2I = 2P/(4πx^2). Therefore, the sound level intensity at A is L = 10log(2P/(4πx^2I0)) = 10log(2P/(4πI0)) - 20log(x).

(b) Let the distance of point M from one source be y. Then the distance from the other source is (OM - y), where OM is the distance between O and M. The sound intensity at M due to one source is proportional to 1/y^2. So, if the sound power of one source is P, then the sound intensity at M due to one source is given by I = P/(4πy^2), where 4πy^2 is the surface area of a sphere with radius y.

The sound level intensity at M due to one source is L_M = 10log(I/I0) = 10log(P/(4πy^2I0)).

Since the sound intensity is inversely proportional to the square of the distance, the sound intensity at A due to one source is four times the sound intensity at M due to one source. Therefore, I_A = 4I = 4P/(4πy^2), and the sound level intensity at A due to one source is L_A = 10log(I_A/I0) = 10log(P/(πy^2I0)).

We want the total sound level intensity at M due to all sources to be L_M = L_A + 10log2, where 10log2 is the sound level intensity increase due to adding a second source. Therefore, we have:

10log(P/(4πy^2I0)) + 10log2 = 10log(P/(πy^2I0))

10log2 = 10log(4/π)

log2 = log(4/π)

2 = 4/π

π = 2

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What is the charge of an electric field 0.40 m away from a
source charge of 3.00 x 10-5C?

Answers

The electric field 0.40 m away from a source charge of 3.00 x 10^-5 C is 1.69 x 10^6 N/C, directed away from the source charge.

How to find the charge

The electric field created by a point charge at a distance r from the charge is given by the equation:

E = kQ/r^2

where

E is the electric field in N/C,

k is Coulomb's constant (9.0 x 10^9 N m^2/C^2),

Q is the source charge in Coulombs, and

r is the distance from the source charge in meters.

Substituting the given values into the equation, we get:

E = (9.0 x 10^9 ) x (3.0 x 10^-5) / (0.40)^2

E = 1.69 x 10^6 N/C

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MS-PS2-1, MS-PS2-2: Newton...
16
Distance (m)
Distance vs. Time
B
120
Time (sec.)
A
B
Which car is faster, A or B? Choose the statement that BEST fits the graph.
Car A is faster than B because A's speed is 120 m/s.
Car B is faster than A because B's speed is 90 m/s.
Car A is faster than B because A's speed is 20 m/s and B is 15 m/s.
D) Car B is faster than A because B's motion is accelerating and A is constant speed.

Answers

The statement that best fits the graph is: D) Car B is faster than A because B's motion is accelerating and A is constant speed.

Which car is faster, A or B?

From the graph, we can see that the distance traveled by both cars increases over time. However, the slope of the distance-time graph for car B is steeper than that of car A. This means that car B covers more distance in the same amount of time as car A, indicating that car B is traveling faster than car A.

Furthermore, we can see that the speed-time graph for car B is a straight line with a positive slope, indicating that its speed is increasing over time. On the other hand, the speed-time graph for car A is a horizontal line, indicating that its speed is constant.

Therefore, we can conclude that car B is faster than car A because car B's motion is accelerating, while car A is moving at a constant speed.

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QUICK ANSWER Rainbows are caused by the refraction of visible wavelengths of light. TRUE OR FALSE

Answers

Answer:

true it is refraction of visible

In an electric circuit, what is one material that the connector can be made of?

Answers

copper alloys se more………

A car slows down from -27.7m/s to -10.9m/s while undergoing a displacement of -105. What was the acceleration? (Unit=m/s^2)

Answers

The acceleration of the car was 6.88 [tex]m/s^2[/tex]. The negative sign indicates that the car was decelerating, or slowing down.

To find the acceleration of the car, we can use the following formula:

acceleration = (final velocity - initial velocity) / time

However, we are not given the time it took for the car to undergo the displacement. To find the time, we can use the following formula:

displacement = (final velocity + initial velocity) / 2 * time

Solving for time, we get:

time = displacement / ((final velocity + initial velocity) / 2)

Plugging in the given values, we get:

time = [tex]-105 / ((-10.9 - 27.7) / 2) = 2.29 s[/tex]

Now that we have the time, we can use the first formula to find the acceleration:

acceleration = [tex](-10.9 - (-27.7)) / 2.29 = 6.88 m/s^2[/tex]

Therefore, the acceleration of the car was [tex]6.88 m/s^2[/tex]. The negative sign indicates that the car was decelerating, or slowing down.

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Find the position of the center of mass of the system of the sun and Jupiter. (Since Jupiter is more massive than the rest of the planets combined, this is essentially the position of the center of mass of the solar system.)

Answers

it's only beyond the surface of the sun! There is a barycenter throughout our entire solar system. All of the planets in the solar system, including the sun, center of mass.

Is the Sun more massive than the solar system as a whole?

The sun is significantly more massive than Earth and has a radius that is likewise much greater. The mass of the sun is more than 333,000 times more than the mass of the Earth and makes up nearly all of the solar system's mass (99.8%).

How much more does the Sun compare to Jupiter?

The Sun is 1000 times more than Jupiter, the solar system's most planet , but Jupiter is still 1000 times less than it.

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Consider a converging lens with focal length 9.56 cm. The distance between an object and
a real image of the object created by the lens is 59.6 cm. Find the distance between the
object and the lens if the lens is closer to the object than it is to the image. Answer in cm

Answers

The object's distance from the lens is 11.4 cm.

Calculation-

The thin lens equation can be used to determine how a converging lens's object distance (p), image distance (q), and focal length (f) relate to one another:

1/p + 1/q = 1/f

where p denotes the distance to the object, q is the distance to the picture, and f is the focal length.

Let's solve for the object distance using the thin lens equation:

1/p + 1/59.6 = 1/9.56

Combining both sides with p59.69.56 results in:

59.69.56 + p9.56 = p*59.6

Adding and subtracting:

570.176 + 9.56p = 59.6p

50.04p = 570.176

p = 11.4 cm

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I need help with this ty

Answers

Answer:

4 & 2

Explanation:

If you plug in experimental values into the formula for kinetic energy, you will see the relationship.

1.

[tex]\frac{1}{2}(2 kg)(2 m/s)^{2} = 4 kg * m^{2} /s^{2} \\\\\frac{1}{2}(8 kg)(2m/s)^{2} = 16 kg * m^{2} /s^{2}\\\\\frac{16}{4} = 4[/tex]

2.

[tex]\frac{1}{2}(6 kg)(2m/s)^{2} = 12 kg * m^{2} /s^{2} \\\\\frac{1}{2}(3 kg)(2 m/s)^{2} = 6 kg * m^{2}/s^{2}\\ \\\frac{12}{6} = 2[/tex]

Cathode ray tubes (CRTs) used in old-style televisions have been replaced by modern LCD and LED screens. Part of the CRT included a set of accelerating plates separated by a distance of about 1.70 cm. If the potential difference across the plates was 24.5 kV, find the magnitude of the electric field (in V/m) in the region between the plates.

Answers

the magnitude of the electric field in the region between the plates is 1.44 × [tex]10^6[/tex]V/m.

The electric field between the plates of the CRT can be calculated using the formula:

E = V/d

where E is the electric field, V is the potential difference across the plates, and d is the distance between the plates.

Substituting the given values, we get:

E = 24.5 kV / 0.017 m

Converting kV to V and simplifying, we get:

E = 24.5 × [tex]10^3[/tex]V / 0.017 m

E = 1.44 × [tex]10^6[/tex] V/m

An electric field is a force field created by a charged object or collection of charged objects that exerts a force on other charged objects within its vicinity. The electric field is a vector quantity and is measured in units of volts per meter (V/m).

The electric field at a point in space is defined as the force per unit charge acting on a positive test charge placed at that point. The direction of the electric field is given by the direction of the force that would be experienced by a positive test charge placed at that point.

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a person that just start driving a car is called​

Answers

Answer:

A person who drives a car for themselves, generally taking themselves back and forth to work or errands, is generally referred to as a driver.

WHAT IS QUANTUM PHYSICS
hi! ​

Answers

Answer:

Quantum physics is the study of matter and energy at the most fundamental level. It aims to uncover the properties and behaviors of the very building blocks of nature.

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7. What is the measure of ZAOB? dr. sanchez conducts a simple random sample of 500 men who became fathers for the first time in the past year. he finds that 23% of them report being unsure of their ability to be good fathers, plus or minus 4%. if dr. sanchez increased his sample size to 1,000, which of the following would happen? group of answer choices the margin of error would become smaller. the true estimate would increase. external validity would become less important. statistical validity would become negatively affected. Part BWhich principles did you use to determine the order of the layers in question 1, part A?The correct sequence for the formation of the features from oldest to newest is layer 4, layer 3, layer 2, layer 5, and layer 1. The following M & M colors are in the bowl: 4 yellow, 6 orange, 3 green, 5 blue, 2 brown. What is the probability of selecting a brown cand consider the table. mother nature tlaloc bob value of sales ($) 2750 7750 20000 dirt ($) 0 2750 0 bricks ($) 0 0 7750 wages ($) 1000 3700 10000 interest payments ($) 1000 600 900 rent ($) 500 300 700 profits ($) 250 400 650 total expenditure ($) 2750 7750 20000 mother nature produces dirt, tlaloc turns the dirt into brick, and bob creates brick houses. the economy is characterized by the table. note all figures are measured in dollars. what is the value added for mother nature? Explore the diagram of the stages in human development. Then complete the flowchart using the terms embryo development, fertilization, and zygote formation. a 1-kg mass is attached to a spring whose constant is 16 n/m and the entire system is then submerge in a liquid that imparts a damping force numerically equal to 10 times the instantaneous velocity. determine the position of the motion if the weight is released 1 m below the equilibrium position with an upward velocity of 12 m/s. The expression 1.01x1.005 gives the amount of money, in thousands of dollars, in Carter's savings account t years after he opens it. one of the main purposes behind the confederate invasion of new mexico was . a) to incite local indians to rise up against the united states b) to enlarge the cotton-growing lands of the confederacy c) to capture mineral mines located in the territory d) to help break the hold of the u.s. naval blockade by blazing a trail to california and its port URGENT NEED HELP WITH 7.6 LESSON PRACTICE QUESTIONS 7 & 8def mystery(a = 2, b = 1, c = 3): return 2 * a + b + 3 * c What is the output for mystery(1)What is the output for mystery()? 30. Health information professionals are trainers, implementation managers, medical record operators. True or false a financial analyst wants to conduct simulation regarding the return of a certain portfolio in 5 years. he needs to generate a random interest rate that is believed to be normally distributed with a mean of 3.8% and a standard deviation of 0.4%. what is the correct excel formula to generate such an interest rate? ryan is a 25% partner in the rocc partnership. at the beginning of the tax year, his basis in the partnership interest was $90,000, including his share of partnership liabilities. during the current year, rocc reported net ordinary income of $100,000. in addition, rocc distributed $10,000 to each of the partners ($40,000 total). at the end of the year, ryan's share of partnership liabilities increased by $10,000. his basis in the partnership interest at the end of the year is: An electrician leans an extension ladder against the outside wall of a house so that it reaches an electric box 27 feet up. The ladder makes an angle of 62^{\circ} with the ground. Find the length of the ladder. Round your answer to the nearest tenth of a foot if necessary. amber observed that she received e-mails containing ads that were often related to the websites she had visited recently or the topics that she had browsed on the internet. the various ads that were sent to her e-mail were related to her previous searches. this is an example of: Help , I need help with this question last week we covered the income statement and this week we covered the cash flow statement. both financial statements are very important to understanding a company. there are some similarities between the two statements, yet there are also many differences. for this week's post, explain those similarities and differences. also, if you had to rely solely on one statement to understand a company, which would you choose and why? Balanced chemicsl equation CuSO4 + Na2SO4 if 2.00 mol of carbon dioxide and 1.5 mol of hydrogen are placed in a5.00 l vessel and equilibrium is established, what will be the concentration of carbonmonoxide?7) can someone give me the answers in order pleaseA car was valued at $44,000 in the year 1992. The value depreciated to $15,000 by the year 2006.A) What was the annual rate of change between 1992 and 2006?r=---------------Round the rate of decrease to 4 decimal places.B) What is the correct answer to part A written in percentage form?r=---------------%C) Assume that the car value continues to drop by the same percentage. What will the value be in the year 2009 ?value = $ -----------------Round to the nearest 50 dollars.