A block slides down an incline. As it moves from point A to point B, which are 5.0 m apart, an external force F acts on the block, with magnitude 2.0 N and directed down along the incline. The magnitude of the kinetic frictional force acting on the block is 10 N. If the kinetic energy of the block increases by 35 J from A to B, what is the change of the gravitational potential energy as the block moves from A to B?

The length of weighted rod under the surface when the rod floated in brine density is 7.2cm

Given the length of weighted rod under water(L1) = 6cm

The density of water (d1) = [tex]1000kg.m^3[/tex]

The density of brine (d2) = [tex]1200kg.m^3[/tex]

Let the length of rod floated in brine under surface = L2

We know that the density of a material will increase as its length increases. This is because the mass of the material increases with length, while the volume of the material remains constant.

length under water/length under surface = density of water/density of brine

L1/L2 = d1/d2

Then [tex]6 * 10^{-2}/L2 = 1000kg.m^3/1200kg.m^3[/tex]

L2 = 7.2cm

Hence, the length of rod under surface in brine = 7.2cm

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The minimum radius hump you can use for the semi-circular hump is 11.25 m.

The minimum radius loop you can use for the vertical loop is 16.7 m.

For the rollercoaster ride, use the following equations for the centripetal acceleration:

At the top of the hump:

a = v² / r

At the bottom of the loop:

a = (v² + g × h) / r

where v is the velocity of the rollercoaster, r is the radius of the curve, g is the acceleration due to gravity, and h is the height of the curve.

To satisfy the safety regulations:

a_top ← 1.85g

a_bottom ← 5.45g

Rearrange the equations to solve for the minimum radius required for each curve:

For the hump:

a_top = v² / r

r_top = v² / a_top

r_top = (12.5 m/s)² / (1.85 × 9.8 m/s²)

r_top = 11.25 m

Therefore, the minimum radius for the hump is 11.25 m.

For the loop:

a_bottom = (v² + g × h) / r

r_bottom = (v² + g × h) / a_bottom

r_bottom = (12.5 m/s)² + 9.8 m/s² × 37.1 m / (5.45 × 9.8 m/s²)

r_bottom = 16.7 m

Therefore, the minimum radius for the loop is 16.7 m.

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Answer:

I mean 25 kg of course.

Explanation:

If you filled the bucket it is 25 liters. The density of water is about 1 kg/liter so about 1 kg

Please, for the sake of clarity on the solution to the question on calculating the potential V(r) of the metal sphere, let's go ahead with the step by step explanation as shown below.

To calculate the potential V(r) at a distance r from the center of the spheres, we need to consider two cases:

In this case, the point is inside the inner sphere and the potential is simply the potential due to the inner sphere, which can be calculated using the formula:

V_inner(r) = k * q / ra

where k is the Coulomb constant (k = 1/4πε0) and ε0 is the electric constant.

In this case, the point is between the two spheres and the potential is the sum of the potentials due to the inner and outer spheres. The potential due to the outer sphere can be calculated using the same formula as above:

V_outer(r) = - k * q / rb

Note that the negative sign indicates that the potential due to the outer sphere is negative since it has a negative charge.

Therefore, the total potential at this point is:

V(r) = V_inner(r) + V_outer(r)

= k * q / ra - k * q / rb

In this case, the point is outside both spheres and the potential is simply due to the outer sphere, which is:

V_outer(r) = - k * q / r

So the total potential at this point is:

V(r) = V_outer(r)

= - k * q / r

Therefore, the potential V(r) as a function of the distance r from the center of the spheres is:

V(r) = { k * q / ra - k * q / rb if ra < r < rb

{ - k * q / r if r > rb

where k is the Coulomb constant, q is the charge on the inner sphere, ra is the radius of the inner sphere, and rb is the radius of the outer spherical shell. Note that we have taken the potential to be zero when the distance r from the center of the spheres is infinite.

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The force applied by pressing down on the left side is referred to as the input force. The force that the rope or pulley applies to the box when it is hoisted is known as the output force.

The pulley system employs the tension force applied to one side of the rope to redirect the force in a different direction.

A pulley is a straightforward device that consists of a rope or cable looped around a wheel that has been grooved, as seen below. By pulling on the rope's one end, you operate a pulley. Your pull's force is the input force. The output force pulls up on the object you want to move at the other end of the rope.

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F = K ( | q1 × q2 | ) / r² is the formula you need

convert the value of the charge to the SI system by multiplying with 10^-6

so the task probably gives you coulombs constant but im gonna assume it's K= 9 × 10⁹ Nm²/C² because thats the common way to use it

so we have

F = 9 × 10⁹ ( 7 × 10^-6 × 2 × 10^-6)/ 0.02²

F = 315 N

so i guess the answer is B because your task must give you K=9. something × 10⁹

hope this helps, sorry if i dont make sense

Answer B is correct because the net electrostatic force on q2 is 314.65 N to the left.

In light of the fact that both the charge q1 and the other charge q2 are equal to zero. According to the equation, one charge is positive and the other is negative. Both charges are of similar size. This indicates that the two supplied charges on the system will add up to a total charge of zero.

[tex]F = k * |q1| * |q2| / r^2[/tex]

[tex]F = 9 x 10^9 * 7 x 10^-6 * 2 x 10^-6 / (0.02)^2[/tex]

[tex]F ≈ 314.65 N to the left[/tex]

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Answer:

B. potential mechanical energy to kinetic mechanical energy

Explanation:

The energy of a child on a swing transforms from potential energy to kinetic energy as they swing from the highest point to the lowest point.

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The measure of the amount of water vapor in the atmosphere is called humidity.

Humidity refers to the amount of water vapor present in the air, and it can be expressed in a variety of ways, such as absolute humidity (the actual amount of water vapor per unit volume of air), relative humidity (the amount of water vapor present as a percentage of the maximum amount the air can hold at a given temperature), or specific humidity (the mass of water vapor per unit mass of air). Humidity plays an important role in weather and climate, as it can affect temperature, cloud formation, precipitation, and other atmospheric phenomena.

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Answer:

the beta particle has the same mass and charge as electron.it differs from the electron in its origin

Answer:

0.14442 N

Explanation:

To find the magnitude and direction of the force needed to cause equilibrium in the system, we can use vector addition.

First, we need to convert the forces given in polar coordinates (direction and magnitude) to Cartesian coordinates (x and y components):

Force A: (60 grams) cos(60°) = 30 grams in the x direction, (60 grams) sin(60°) = 51.96 grams in the y direction.

Force B: (100 grams) cos(142°) = -36.07 grams in the x direction, (100 grams) sin(142°) = 94.78 grams in the y direction.

Force C: (130 grams) cos(255°) = -109.57 grams in the x direction, (130 grams) sin(255°) = -62.79 grams in the y direction.

Next, we can add up the x and y components of the three forces to find the net force acting on the system:

Net force in x direction = 30 grams - 36.07 grams - 109.57 grams = -115.64 grams

Net force in y direction = 51.96 grams + 94.78 grams - 62.79 grams = 83.95 grams

Since the system is in equilibrium, the net force in both the x and y directions must be zero. Therefore, we can set up the following equations:

-115.64 grams + F_Dx = 0

83.95 grams + F_Dy = 0

Solving for F_Dx and F_Dy, we get:

F_Dx = 115.64 grams

F_Dy = -83.95 grams

The magnitude of Force D can be found using the Pythagorean theorem:

|F_D| = sqrt(F_Dx^2 + F_Dy^2) = sqrt((115.64 grams)^2 + (-83.95 grams)^2) = 144.42 grams

To convert this to Newtons, we can divide by the conversion factor of 1000 grams per Newton:

|F_D| = 144.42 grams / (1000 grams per Newton) = 0.14442 Newtons

Finally, the direction of Force D can be found using the inverse tangent function:

theta = atan(F_Dy / F_Dx) = atan(-83.95 grams / 115.64 grams) = -37.21 degrees

Therefore, Force D needs to be 144.42 grams (0.14442 Newtons) in magnitude and 37.21 degrees in direction to cause equilibrium in the system.

The total surface area of S that is the boundary of solid between Z=0 and Z=X²​ is given as :

∬S dS = ∫0^2π ∫0^1 tanθ √(1 + cos²θ) dr dθ + ∫0^1 ∫0^2π √(z) / cosθ dθ dz

Applying the surface integral formula:

∬S dS

where S = surface of the solid,

dS = surface area element.

We  can use the cylindrical coordinates  to parameterize the surface S (r, θ, z).

The surface S consists of two parts:

For the top surface,

z = X² = r²cos²θ, so r = sinθ/cosθ = tanθ.

The surface element is given by dS = r dθ dr = tanθ dr dθ.

For the curved surface,

z = X² = r²cos²θ, so r = √(z/cos²θ).

The surface element is  dS = r dθ dz = √(z) / cosθ dθ dz.

In conclusion, the total surface area of S is:

∬S dS = ∫0^2π ∫0^1 tanθ √(1 + cos²θ) dr dθ + ∫0^1 ∫0^2π √(z) / cosθ dθ dz

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Answer: Both static and kinetic coefficients of friction depend on the pair of surfaces in contact. Their values are determined experimentally. For a given pair of surfaces, the coefficient of static friction is larger than the kinetic friction. The coefficient of friction depends on the materials used.

Explanation:

the coefficient of static friction is larger than the kinetic friction.

Answer:

The coefficient of kinetic friction and the coefficient of static friction are both affected by the area of contact between two surfaces in contact. The following is a detailed explanation of how the values of these coefficients are affected by the area of contact.

The coefficient of kinetic friction is defined as the ratio of the force required to maintain a constant velocity between two surfaces in contact to the normal force pressing them together. It is a measure of the resistance to motion between two surfaces in contact. The coefficient of kinetic friction is affected by several factors, including the nature of the surfaces in contact, their roughness, and their temperature. However, the area of contact between two surfaces also plays a crucial role in determining the coefficient of kinetic friction.

The larger the area of contact between two surfaces, the greater the frictional force acting between them. This is because a larger area of contact means that there are more points of interaction between the two surfaces, which leads to a greater number of intermolecular forces acting between them. As a result, it becomes more difficult to maintain a constant velocity between two surfaces with a larger area of contact, and hence, the coefficient of kinetic friction increases.

On the other hand, the coefficient of static friction is defined as the ratio of the maximum force required to initiate motion between two surfaces in contact to the normal force pressing them together. It is a measure of the resistance to motion when an object is at rest on a surface. Like the coefficient of kinetic friction, it is also affected by several factors including surface roughness and temperature. However, unlike the coefficient of kinetic friction, it is not affected significantly by changes in area of contact.

This is because when an object is at rest on a surface, it does not matter how much area it covers on that surface. The maximum force required to initiate motion remains constant regardless of whether an object has a small or large area in contact with another surface. Therefore, changes in area of contact do not significantly affect the coefficient of static friction.

The pelvis in humans serves a functional purpose by supporting the upper body and attaching it to the lower body. Other vestigial structures in humans include ear muscles, tail bone, and hair raising.

As humans evolved, the pelvis became increasingly important in supporting the weight of the upper body and allowing for efficient movement of the legs. In fact, the shape of the pelvis is one of the key factors that distinguishes humans from other primates, as it evolved to accommodate the unique demands of bipedalism. However, not all structures in the human body are as essential as the pelvis. Some, like the ear muscles and tail bone, have lost their original function over time. The ear muscles, for example, were once used to orient the ears towards sounds, but are no longer functional in most humans. Similarly, the tail bone, or coccyx, is a vestige of the tail that our primate ancestors once had, but which no longer serves any purpose in humans. Other vestigial structures in humans include the appendix, which may have once been used to digest a more plant-based diet, and the ability to raise our hair, which was likely used to intimidate predators but now only causes goosebumps.

Despite their lack of function, these vestigial structures continue to exist in humans due to their evolutionary history. And while they may not be essential to our survival, they serve as a reminder of our evolutionary past and the many adaptations that have made us the unique species we are today.

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Kohlberg's three levels of moral development are pre-conventional, conventional, and post-conventional.

Pre-conventional level > Conventional level > Post-conventional level

The pre-conventional level is focused on self-interest and avoiding punishment, while the post-conventional level is based on abstract principles and individual conscience.

It is possible for someone to move backwards in Kohlberg's levels of moral development, especially if they experience a traumatic event or significant life changes that challenge their moral beliefs. However, it is also possible for someone to move forward in their moral development with the right support and experiences.

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The cyclist will be moving with a velocity of 6.12m/s when she reaches the end of the patch which is 290cm long.

Given the speed of cyclist initially (u) = 5m/s

The length of rough horizontal patch of the road (s) = 290cm = 2.9m

The coefficient of kinetic friction of road with her tyres (μ) = 0.220

The frictional force acting on the cyclist f = μN = ma where a is the acceleration acting on the cyclist.

Then f = 0.220 * N

0.220 * m * g = m * a

a = 2.156m/s^2

From Newtons laws of motion we know that :

[tex]v^2 - u^2 = 2as[/tex] where v is the final velocity such that:

[tex]v^2 - (5)^2 = 2 * 2.156 * 2.9[/tex]

[tex]v^2 = 12.5048 + 25 = 37.5048[/tex]

[tex]v = \sqrt{37.5048} = 6.12m/s[/tex]

Hence the final velocity of the cyclist is 6.12m/s

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We can use Coulomb's Law to calculate the force exerted on the charge -q at the center of the hexagon by each of the five +q charges. The force exerted by a single charge is given by:

F = k * (q1*q2)/r^2

where,

k = Coulomb's constant

q1 and q2= charges of the two particles

r = distance between charges

Since all the +q charges are equidistant from the -q charge at the center of the hexagon, the magnitude of the force exerted by each charge is the same.

Let's call this force F1.

Angle between any two adjacent charges in the hexagon =60 degrees, so the force vector between each pair of charges is directed along a line connecting them and points towards the -q charge at the center.

Since there are five charges, the total force on the -q charge is the vector sum of the forces exerted by each charge. We can find the magnitude of this resultant force using the law of cosines:

F^2 = (5F1)^2 + (5F1)^2 - 2*(5F1)(5*F1)*cos(120)

Simplifying this equation gives:

F = sqrt(75)*F1

Distance between the center of the hexagon and each of the five charges= l,

and the charges are all +q, so we have:

F1 = k*q^2/l^2

Substituting this into the previous equation gives:

F = sqrt(75)kq^2/l^2

Therefore, the magnitude of the resultant force on the -q charge at the center of the hexagon is:

|F| = sqrt(75)kq^2/l^2

where k is Coulomb's constant, q is the charge of each particle, and l is the side length of the regular hexagon.

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Answer:

the magnitude of the electric field at a point inside the sphere, 0.110 m below the surface, is 7.31 × 10^5 N/C.

Explanation:

To find the magnitude of the electric field at a point inside the sphere, we can use Gauss's law, which states that the electric flux through any closed surface is proportional to the charge enclosed by that surface. We will assume that the metal sphere is a conductor and has a uniform charge density.

First, we need to find the charge enclosed by a spherical surface with radius 0.110 m, centered at the center of the metal sphere. Since the sphere has a uniform charge density, we can find the charge enclosed by this surface as:

Qenc = (4/3)πr^3ρ = (4/3)π(0.110)^3σ,

where ρ is the charge density of the metal and σ is the surface charge density, which is equal to the net charge divided by the surface area of the sphere:

σ = Qnet / (4πr^2) = 0.270 nC / (4π(0.440)^2) = 4.994 × 10^-5 C/m^2.

Therefore, the charge enclosed by the spherical surface is:

Qenc = (4/3)π(0.110)^3(4.994 × 10^-5) = 1.472 × 10^-8 C.

The electric flux through this surface is proportional to the charge enclosed, so we can use Gauss's law to find the electric field at the point inside the sphere:

ΦE = E(4πr^2) = kQenc,

where k is Coulomb's constant.

Solving for E, we get:

E = kQenc / (4πr^2) = (9 × 10^9 N·m^2/C^2)(1.472 × 10^-8 C) / (4π(0.110)^2 m^2) = 7.31 × 10^5 N/C.

Therefore, the magnitude of the electric field at a point inside the sphere, 0.110 m below the surface, is 7.31 × 10^5 N/C

The value of C₂ is approximately 9.53 microfarads.

Using the conservation of charge, we can say that the total charge on the two capacitors before and after they are connected is the same.

The initial charge on the first capacitor, Q₁, can be calculated as:

Q₁ = C₁ * V

where V is the voltage of the battery (125 V).

When the two capacitors are connected in series, they have the same charge, so the charge on each capacitor is Q = Q₁ = C₁ * V.

The final voltage on each capacitor can be calculated using the formula for capacitors in series:

1/Ceq = 1/C1 + 1/C2

where Ceq is the equivalent capacitance of the two capacitors.

The final voltage on each capacitor is given as 15 V, so we can write:

Q = Ceq * Vf

where Vf is the final voltage on each capacitor (15 V).

Substituting Q = C₁ * V into the above equation and solving for C₂, we get:

C₂ = (C₁ * Vf) / (V - Vf)

Substituting the given values, we get:

C₂ = (7.7 × 10^-6 F × 15 V) / (125 V - 15 V) ≈ 9.53 × 10^-6 F

Therefore, the value of C₂ is approximately 9.53 microfarads.

What is capacitor?

A capacitor is an electrical component that stores electric charge and energy in an electric field between two conductive plates. It consists of two parallel conductive plates separated by an insulating material called a dielectric. When a voltage is applied to the capacitor, it charges up by accumulating electric charges on the two plates, with one plate becoming positively charged and the other negatively charged.

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The graph of the resistors and the colors of the resistors are presented as follows;

Q1. a) Line A represents R₁, B represents R₃, and C represents R₂

b) The line of the equivalent  will be lower than C

c) Brown, green, black and gold

The resistance of a resistor is; R = V/I

V = The voltage across the resistor, and I is the current through the resistor.

Q1. R₁ = 3.13 kΩ, R₂ = 0.52 kΩ, and R₃ = 1.59 kΩ

a) The potential difference, or voltage V = I·R, where;

I = The current

R = The value of the resistor

The slope is therefore, directly proportional to the resistance of the resistor. Therefore, the resistor that the line A in Figure 1 (b) in the question represents is the highest value resistor, which is R₁ = 3.13 kΩ

The resistor that the line B represents is R₃ = 1.59 kΩ

The resistor that the line C represents is R₂ = 0.52 kΩ

b) The value of Requiv can be found as follows;

1/Requiv = 1/R₁ + 1/R₂ + 1/R₃

Therefore;

1/Requiv = 1/3.13 + 1/0.52 + 1/1.59

Therefore; Requiv ≈ 0.348 Ω

Therefore, the line in Figure 1 (b) representing Requiv will be lower than the line C

c) The obtain the four colors of resistor R₃, we need to calculate its value in ohms. Using the values R₃ = 1.36 kΩ and R₃ = 1.61 kΩ, the average value of R₃ can be calculated as follows;

(R₃₁ + R₃₂)/2 = (1.36 + 1.61)/2 = 1.485

The average value of R₃ is therefore, 1.485 kΩ

The colors of R₃ are therefore; brown, green, black, and gold, where, the first two bands represent the significant digits of the resistance value, the third band represent the multiplier, and the fourth band represent the tolerance value.

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Answer:2.5 N of force was required by marco

Explanation: Given

                       work done=48J

                        displacement =19m

                         W=force*displacement

                         force=W/d

                         force=2.5 N

Here the work done is given and the force due to which displacement is also given ,From the formulea work done= force* displacment. We have calculated the answer.

soo helpful

Explanation:

this is so helpful thank you so much

The time interval between the student clapping his hands and hearing the first echo is 0.2 seconds. The time interval between the student clapping his hands and hearing the third echo is 0.6 seconds.

The question is based on echoes and involves the calculation of time taken to hear an echo. To calculate this, we can consider the echo reaching the student as a journey of sound, first going towards the building, and then reflecting back. Therefore, the total distance covered by the sound is twice the distance between the student and the building.

So, if the distance is 33m, the total distance covered is 66m. As the speed of sound is given as 330m/s, the time taken for the first echo = Distance / Speed = 66m / 330m/s = 0.2 seconds.

To hear the third echo, the same journey must be repeated three times. So, the time for the third echo would be 3 * 0.2s = 0.6 seconds.

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Answer:

4618.9N

Explanation:

We need to start of by calculating the Gravitational Force (acceleration) of the Earth (IF it was the same size as the moon) which is showed as follows:

[tex]g = \frac{GM}{r^2}[/tex] where g is the gravitational acceleration, G is the gravitational constant (6.673 × [tex]10^{-11}[/tex] Nm^2kg^-2), M is the mass of the planet, r is the radius of the planet.

Substituting the values as given in the question,

[tex]g = \frac{6.673 * 10^{-11} * 4 * 10^{24}}{(1.7*1000 * 1000)^2}\\\\= \frac{26.69200 * 10^{13}}{2890000000000}\\\\\\= 92.3598615917 N/kg[/tex]

Hence, the gravitational force is 92.4N/kg (or m/s^2).

Considering this,

50 * 92.4 = 4618.89N ≈ 4618.9N

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The density of water being approximately 1000 kg/m³ and acceleration due to gravity being approximately 9.8 m/s², the depth is calculated to be approximately 10.2 meters, while assuming Atmospheric pressure at sea level.

The pressure at any point in a fluid (like water) is given by:

pressure = density x gravity x depth

where density is the density of the fluid, gravity is the acceleration due to gravity, and depth is the depth of the point below the surface.

At sea level, the atmospheric pressure is 10⁵ N/m². This means that the pressure at any point below sea level in water will be higher than 10⁵ N/m².

To find the depth at which the pressure is equal to 10⁵ N/m², we can rearrange the above equation as:

depth = pressure / (density x gravity)

The density of water is approximately 1000 kg/m³, and the acceleration due to gravity is approximately 9.8 m/s². Substituting these values and the given pressure of 10⁵ N/m², we get:

depth = 10⁵ N/m² / (1000 kg/m³ x 9.8 m/s²)

depth = 10.2 meters

Therefore, the depth at which the pressure is equal to atmospheric pressure at sea level (10⁵ N/m²) in water is approximately 10.2 meters.

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Name: Bubble Blitz

Goals and Playthrough: Bubble Blitz is a fast-paced game in which players race against time to pop as many bubbles as possible. The game's objective is to pop as many bubbles as possible to score as many points as possible.

Scoring: One point is awarded for popping each bubble. The player with the highest score wins the game at the end.

Required equipment: A large open area and either a bubble machine or a container filled with soapy water are required for Bubble Blitz.

The number of team members: You can play Bubble Blitz by yourself or in teams of two or more.

Abilities required: To pop the bubbles as they appear in Bubble Blitz, players must have strong hand-eye coordination and quick reflexes.

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The mechanic will have to apply a force of 73.575 N to lift the vehicle using the hydraulic Jack.

To calculate the force the mechanic will have to apply, we first need to determine the pressure exerted by the weight of the vehicle on the surface area.

Pressure is defined as force per unit area, so we can use the formula:

Pressure = Force / Area

The weight of the vehicle is 1500kg, which is equivalent to a force of:

Force = mass x gravity

where;

Force = 1500 kg x 9.81 m/s²

Force = 14,715 N

The pressure exerted by the weight of the vehicle on the surface area of 10m² is:

Pressure = Force / Area

Pressure = 14,715 N / 10 m²

Pressure = 1471.5 Pa

Now we can calculate the force the mechanic will have to apply to the surface area of 0.05m² using the same formula:

Pressure = Force / Area

We know the pressure and the area, so we can rearrange the formula to solve for the force:

Force = Pressure x Area

Force = 1471.5 Pa x 0.05 m²

Force = 73.575 N

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The balloon has a 4.51 m³ volume. The balloon will undergo an initial acceleration of 0.551 m/s².

Buoyant force = Helium density x V x g

(Mass of balloon plus Mass of Load) x g = Weight of Displaced Air

V is equal to (balloon mass plus load mass) / helium density.

V is equal to (1.5 kg + 750 N / 9.81 m/s²) / 0.1785 kg/m3 = 4.51 m³.

Net force is equal to (helium density x 2V x g) - (balloon Plus load) x g.

Net force = 112.79 N a = F / m = (750 N + 900 N + 1.5 kg x 9.81 m/s²) = 0.551 m/s²

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