The pH of the buffer solution after 0.024 mol of Ba(OH)₂ are added is approximately 4.90.
To solve this problem, we need to use the Henderson-Hasselbalch equation, which relates the pH of a buffer solution to the concentrations of the weak acid and its conjugate base;
pH = pKa + log([base]/[acid])
where pKa will be the dissociation constant of the weak acid, [base] is the concentration of the conjugate base, as well as [acid] is the concentration of the weak acid.
From the given information, we can determine the pKa of the weak acid;
pH = 8.87 = pKa + log([base]/[acid])
pKa = 8.87 - log([base]/[acid])
pKa = 4.83
We can also determine the initial concentrations of the weak acid and its conjugate base.
[base] = 0.49 M
[acid] = 0.45 M
Now, we can use the balanced chemical equation for the reaction of Ba(OH)₂ with BH;
Ba(OH)₂ + 2BH → BaB₂ + 2H₂O
The moles of BH that react with the added Ba(OH)₂ is equal to half the moles of Ba(OH)₂ added, because the stoichiometry of the reaction is 2:1. Therefore, moles of BH consumed = 0.024 mol / 2 = 0.012 mol
The volume of the solution is given as 0.62 L, so the new concentration of BH is;
[acid] = (0.45 M x 0.62 L - 0.012 mol) / 0.62 L
[acid] = 0.441 M
The new concentration of B can be determined from the conservation of mass equation:
[base] + [BaB2] = constant
[base] + 0.012 mol / 0.62 L = constant
[base] = 0.49 M - 0.012 mol / 0.62 L
[base] = 0.470 M
Now, we can use the Henderson-Hasselbalch equation to determine the new pH of the buffer solution
pH = pKa + log([base]/[acid])
pH = 4.83 + log(0.470/0.441)
pH = 4.90
To know more about conjugate base here
https://brainly.com/question/12883745
#SPJ4
Help what's the answer??
Answer: 1.57g and 70.5%
Explanation:
Theoretical Yield
The theoretical yield of a reaction is the absolute maximum amount of product that could be created with the amounts of reactants.
This problem gives us the amount of hydrochloric acid, which is 6.37 grams. The molar mass of HCl is the molar mass of hydrogen plus the molar mass of chlorine, which is 36.46 g/mol.
To find the moles of HCl, we just divide the mass by the molar mass.
6.37/36.46 = 0.175 moles HCl
Since oxygen is in excess, the amount used in the reaction will be dictated by the amount of HCl used in the reaction. It does not need to be taken into consideration when determining the amount of reactant since it is in excess.
To find the theoretical yield of water, we will do stoichiometry.
Balancing the equation
Written out with the chemical symbols, this equation is
HCl + O2 ⇒H2O + Cl
This is not balanced, since there is 1 hydrogen on the left side and 2 on the right, and 2 oxygens on the left and 1 on the right.
To balance this, we can put coefficients in front of some reactants and products to make sure there are equal amounts of everything on each side.
The balanced equation will be 4HCl + O2 ⇒ 2H2O + Cl
Now, there are 4 hydrogens on the left and 4 on the right, as well as 2 oxygens on the left and 2 on the right. It is balanced.
We can see by looking at the coefficients of the balanced equation that every 4 moles of HCl consumed will produce 2 mole of H2O, so the ratio is 1:2.
To do stoichiometry, we will multiply the moles of HCl by the ratio of H2O to HCl, which is just dividing by 2.
The theoretical yield of water is then 0.175 moles HCl * [tex]\frac{1moleH2O}{2moleHCl}[/tex] = 0.1874 moles H2O.
Our theoretical yield is 0.0874 moles H2O. But the question and the actual yield are in grams, so we will convert this to grams. To convert moles to grams, just multiply the moles by the molar mass. The molar mass of water is 18.0 g/mol, so
0.0874*18.0 = 1.57 g
The theoretical yield is 1.57 g H2O
Percent Yield
Percent yield is much easier. Percent yield is
((actual yield)/(theoretical yield))*100
In this case, our actual yield is 1.11 grams and our theoretical yield is 3.15 grams, so
[tex]\frac{1.11}{1.57} =[/tex] 70.5%
70.5% is the percent yield.
the ph of a solution of hexanoic acid is measured to be . calculate the acid dissociation constant of hexanoic acid. be sure your answer has the correct number of significant digits.
The acid dissociation constant of hexanoic acid is 4.93 × 10^-10 mol/L.
When measuring the pH of a solution of hexanoic acid to be 4.96, the acid dissociation constant of hexanoic acid can be calculated. This can be done through the following equation:
Ka = [H3O+][A-] / [HA]whereKa
= acid dissociation constantH3O+
= hydronium ionA-
= conjugate baseHA
= acidThe pH of the solution of hexanoic acid is measured to be 4.96.
Thus, [H3O+] is equal to 10^-4.96 or 7.02 × 10^-5 M.
The initial concentration of the hexanoic acid is equal to the concentration of the undissociated acid or [HA].The acid dissociation constant of hexanoic acid can be calculated by plugging the known values into the equation:
Ka = [7.02 × 10^-5][A-] / [HA]The concentration of the conjugate base, A-, is equal to the concentration of the dissociated acid, which is equal to [H3O+].
Thus,Ka = [7.02 × 10^-5]^2 / [HA]Ka = 4.93 × 10^-10 mol/L
To learn more about : acid
https://brainly.com/question/25148363
#SPJ11
if there is no diethyl ether in the lab, what other solvent can you use as an alternative? select one: methanol ethyl acetate tetrahydrofuran water
While considering a good solvent alternative for diethyl ether, the best one will be ethyl acetate. It can be used for extraction due to its polarity and less toxicity.
Diethyl ether is one of the commonly used solvent in extraction process of non-polar or slightly polar organic compounds. This is because it does not have hydrogen bonding. So here methanol cannot be used as it has extensive hydrogen bonding and non-polar compounds might not dissolve.
Water also cannot be used because of its polar nature. So organic compounds does not dissolve. Tetrahydrofuran can be used as a solvent, but toxicity levels are higher compared to diethyl ether.
So the alternative that can be used is ethyl acetate, which is also widely used solvent in extraction of non-polar compounds. Also it has less toxicity compared to THF.
For more details regarding organic solvents, kindly refer
https://brainly.com/question/28850026
#SPJ4
if the coefficients in the redox reaction are doubled, how will the given quantities be affected for a voltaic cell under nonstandard conditions?
When the coefficients in the redox reaction are doubled, the given quantities will be affected for a voltaic cell under nonstandard conditions in the following ways.
Explanation:
An increase in the coefficients of a balanced redox reaction increases the number of moles of the reacting species. Thus, an increase in the coefficients of a redox reaction would result in an increase in the cell potential.
Furthermore, the reaction quotient Q would become smaller due to an increase in the concentrations of products and a decrease in the concentrations of reactants. This shift toward the products would make the reaction more spontaneous.The increase in coefficients would result in an increase in the molar quantities of each species, resulting in a change in the Q value. The standard EMF of the cell is unaffected since it is based solely on standard conditions. The value of ΔG, which is directly related to the potential difference in a galvanic cell, changes as the value of Q changes.
for more such question on coefficients :
https://brainly.com/question/18667947
#SPJ11
A student dilutes 15.00 mL of 0.275 M NaNO3 stock solution to a volume of 100.0 mL. What is the final molarity?
When a stock solution is diluted, the number of moles of solute (NaNO3 in this case) remains constant. Therefore, we can use the following equation to find the final molarity of the diluted solution:
M1V1 = M2V2
where M1 is the initial molarity (0.275 M), V1 is the initial volume (15.00 mL), M2 is the final molarity (what we want to find), and V2 is the final volume (100.0 mL).
First, we need to convert the initial volume from milliliters to liters:
V1 = 15.00 mL = 0.01500 L
Next, we can substitute the given values into the equation:
(0.275 M) × (0.01500 L) = M2 × (0.1000 L)
Solving for M2, we get:
M2 = (0.275 M × 0.01500 L) ÷ 0.1000 L
M2 = 0.04125 M
Therefore, the final molarity of the NaNO3 solution is 0.04125 M.
which does not describe radon-222? group of answer choices its effects can be reduced by increasing ventilation. it exists in the igneous rock granite all around the world. it binds with hemoglobin in the blood and can lead to death. it seeps into homes through cracks in the foundation or soil. it is a radioactive gas that occurs from the natural decay of uranium
The statement that does not describe radon-222 is It binds with hemoglobin in the blood and can lead to death.
Radon-222 is a radioactive gas that occurs from the natural decay of uranium. It exists in igneous rock granite all around the world and can seep into homes through cracks in the foundation or soil. Its effects can be reduced by increasing ventilation in the affected areas.
This statement is inaccurate because radon does not bind with hemoglobin in the blood. Instead, radon gas decays into radioactive particles that can be inhaled and damage lung tissue, increasing the risk of lung cancer.
Know more about Radon-222 here :
brainly.com/question/30876043
#SPJ11
. consider a buffer solution that contains a mixture of aqueous hcn and kcn. a. write the net ionic equation for the reaction that occurs when a few drops of hcl are added to the solution. b. write the net ionic equation for the reaction that occurs when a few drops of naoh are added to the solution
The ionic equations are as follows:
[tex]H^{+} (aq) + CN^{-} (aq) < -- > HCN(aq)[/tex]
[tex]CN^{-} (aq) + H2O (l) < = > HCN (aq) + OH^{-} (aq)[/tex]
The buffer solution containing a mixture of aqueous HCN and KCN can be represented as:
[tex]HCN(aq) + CN^{-} (aq) + K^{+} (aq) < --- > HCN(aq) + KCN(aq)[/tex]
a. When a few drops of HCl are added to the buffer solution, the H+ ions from the HCl react with the CN- ions in the buffer solution to form HCN. The net ionic equation for the reaction is:
[tex]H^{+} (aq) + CN^{-} (aq) < -- > HCN(aq)[/tex]
b. When a few drops of NaOH are added to the buffer solution, the OH- ions from the NaOH react with the HCN molecules in the buffer solution to form CN- ions. The net ionic equation for the reaction is:
[tex]CN^{-} (aq) + H2O (l) < = > HCN (aq) + OH^{-} (aq)[/tex]
To know more about ionic equations go through:-
https://brainly.com/question/13879496
#SPJ4
write the net ionic equation for the acid-base hydrolysis equilibrium that is established when ammonium nitrate is dissolved in water. (use h3o instead of h .)
The net ionic equation for the acid-base hydrolysis equilibrium that is established when ammonium nitrate is dissolved in water is given below:Answer: NH4+(aq) + H2O(l) ⇌ H3O+(aq) + NH3(aq) + NO3-(aq).
The ionic equation is a chemical equation in which the electrolytes in aqueous solution are represented by their actual ions rather than their complete formulas. It indicates that ions undergo a chemical reaction to produce a new compound.
The net ionic equation displays the actual chemical reaction taking place in an aqueous solution. It is derived by eliminating spectator ions, which do not play any active role in the chemical reaction.The acid-base hydrolysis equilibrium is as follows:NH4+(aq) + H2O(l) ⇌ NH3(aq) + H3O+(aq).
The ammonium ion hydrolyzes to form ammonium ion and hydronium ions. The nitrate ion is a spectator ion that does not participate in the reaction. Therefore, the net ionic equation is given by:NH4+(aq) + H2O(l) ⇌ H3O+(aq) + NH3(aq).
To know more about ionic equation refer to-
brainly.com/question/29299745#
#SPJ11
a student spotted a tlc plate and ran it in 10% ethyl acetate/hexanes. the tlc obtained showed a streak rather than separate spots for the components. what technical mistake might the student have made?
To fix the issue, the student should carefully reapply the sample in a smaller amount, allow it to dry completely, and adjust the solvent system if necessary to achieve proper separation of the components on the TLC plate.
The student might have made the following technical mistake while running the TLC plate:
1. Overloading the sample: When spotting the TLC plate, the student may have applied too much sample, causing the components to streak rather than separate into individual spots. To resolve this, the student should apply a smaller amount of sample and ensure that it is evenly distributed.
2. Insufficient drying: If the student did not allow the spotted sample to dry properly before placing it in the solvent, it can cause the components to streak. To prevent this, the student should ensure the sample is completely dry before running the TLC plate.
3. Inappropriate solvent system: Although the student used a 10% ethyl acetate/hexane mixture, it is possible that this solvent system was not suitable for the specific sample. Adjusting the solvent ratio or trying different solvent systems could help achieve better separation.
to know more about TLC refer here:
https://brainly.com/question/13086570#
#SPJ11
Given the following equation:
2H2O --> 2H2 +O2
What mass of oxygen would form from 5 moles of water?
Question 6 options:
.078
320
.3125
80
I have 0.60 moles of sodium iodide (NaI). How many liters of water would it take to make a 0.19 M solution?
it would take 3.16 litres of water to make a 0.19 M solution of NaI from 0.60 moles of NaI.
To calculate the volume of water needed to make a 0.19 M solution of NaI, we need to use the formula:
Moles of solute = Molarity x Volume (in liters)
We can rearrange this formula to solve for the volume of water:
Volume (in liters) = Moles of solute / Molarity
First, let's calculate the number of moles of NaI in 0.60 moles:
Moles of NaI = 0.60 moles
Now, we can use the formula above to calculate the volume of water needed:
Volume (in litres) = Moles of NaI / Molarity
Volume (in litres) = 0.60 moles / 0.19 M
Volume (in litres) = 3.16 litres
Therefore, it would take 3.16 litres of water to make a 0.19 M solution of NaI from 0.60 moles of NaI.
To know more about moles go through:-
https://brainly.com/question/29367909
#SPJ4
Elemental analysis of a pure compound indicated that the compound contained 324 g of C, 48.5 g of H and 16.0 g of O. What is its empirical formula?
Answer:
To find the empirical formula of a compound, we need to determine the simplest whole number ratio of the atoms present in the compound. We can do this by dividing each element's mass by its molar mass to get the number of moles of each element, and then dividing each number of moles by the smallest number of moles obtained. The molar masses of carbon, hydrogen, and oxygen are 12.01 g/mol, 1.008 g/mol, and 16.00 g/mol, respectively. Number of moles of C = 324 g / 12.01 g/mol = 26.98 mol Number of moles of H = 48.5 g / 1.008 g/mol = 48.11 mol Number of moles of O = 16.0 g / 16.00 g/mol = 1.
Answer:
C27H48O
Explanation:
To determine the empirical formula of the compound, we need to find the simplest whole number ratio of atoms in the compound. We can do this by assuming that we have 100 g of the compound, and finding the number of moles of each element in this amount.
Number of moles of carbon (C): 324 g / 12.01 g/mol = 26.98 mol
Number of moles of hydrogen (H): 48.5 g / 1.01 g/mol = 48.02 mol
Number of moles of oxygen (O): 16.0 g / 16.00 g/mol = 1.00 mol
Next, we divide each of these mole values by the smallest value to get the simplest ratio:
C: 26.98 mol / 1.00 mol = 26.98
H: 48.02 mol / 1.00 mol = 48.02
O: 1.00 mol / 1.00 mol = 1.00
We can see that the simplest ratio of atoms in the compound is approximately C27H48O. However, we need to express this as a whole number ratio, so we divide each subscript by the smallest subscript (which is 1):
Empirical formula: C27H48O
Therefore, the empirical formula of the compound is C27H48O.
b) explain the meaning of the term ld50 (ed50). what is the ld50 concentration of cuso4 for brine shrimp?
The LD50 concentration of CuSO₄ for brine shrimp is reported to be around 2.75 ppm (parts per million), which means that if 50% of the brine shrimp population were exposed to this concentration of CuSO₄, they would die as a result of the exposure
The LD50 and ED50 are both terms commonly used in toxicology to express the effectiveness or toxicity of a substance.
The LD50, which stands for "lethal dose 50," is the amount of a substance required to cause death in 50% of the test population. It is typically expressed in units of milligrams or micrograms of the substance per kilogram of body weight of the test animal.
On the other hand, the ED50 stands for "effective dose 50," which is the amount of a substance required to produce a desired effect in 50% of the test population. It is commonly used in pharmacology to measure the potency of a drug.
In the case of the brine shrimp, the LD50 concentration of CuSO4 (copper sulfate) would be the amount of CuSO4 that would cause the death of 50% of the shrimp population in a given test. It is important to note that the LD50 can vary depending on various factors such as the species being tested, the method of exposure, and the duration of exposure.
learn more about brine shrimp here : brainly.com/question/30637879
#SPJ4
how many liters of 0.100 m hcl would be required to react completely with 5.00 grams of calcium hydroxide?
The balanced chemical equation for the reaction between hydrochloric acid (HCl) and calcium hydroxide (Ca(OH)2) is:
2HCl + Ca(OH)2 → CaCl2 + 2H2O
First, we need to calculate the moles of calcium hydroxide (Ca(OH)2) present in 5.00 grams:
molar mass of Ca(OH)2 = 40.08 + 2(15.99) + 2(1.01) = 74.10 g/mol
moles of Ca(OH)2 = mass / molar mass = 5.00 g / 74.10 g/mol = 0.0674 mol
According to the balanced chemical equation, 2 moles of HCl react with 1 mole of Ca(OH)2. Therefore, the number of moles of HCl required to react completely with 0.0674 mol of Ca(OH)2 is:
moles of HCl = 2 x moles of Ca(OH)2 = 2 x 0.0674 mol = 0.1348 mol
Finally, we can use the molarity (0.100 M) and the number of moles of HCl to calculate the volume of the HCl solution required:
moles = molarity x volume (in liters)
volume (in liters) = moles / molarity = 0.1348 mol / 0.100 mol/L = 1.35 L
Therefore, 1.35 liters of 0.100 M HCl are required to react completely with 5.00 grams of calcium hydroxide.
1.35 liters of 0.100 M [tex]HCl[/tex] would be required to react completely with 5.00 grams of calcium hydroxide.
To determine how many liters of 0.100 M [tex]HCl[/tex]would be required to react completely with 5.00 grams of calcium hydroxide, follow these steps:
1. Write the balanced chemical equation for the reaction:
[tex]2 HCl(aq) + Ca(OH)₂(s) → CaCl₂(aq) + 2 H₂O(l)[/tex]
2. Calculate the moles of calcium hydroxide (Ca(OH)₂):
Molar mass of [tex]Ca(OH)₂ = 40.08 (Ca) + 2 * (16.00 + 1.01) (2 * OH) = 74.10 g/mol[/tex]
Moles of[tex]Ca(OH)₂[/tex] = mass / molar mass =[tex]5.00 g / 74.10 g/mol ≈ 0.0675 mol[/tex]
3. Determine the stoichiometry between[tex]HCl[/tex] and[tex]Ca(OH)₂[/tex] from the balanced equation:
2 moles of [tex]HCl[/tex] react with 1 mole of [tex]Ca(OH)₂[/tex].
4. Calculate the moles of[tex]HCl[/tex] required to react completely with[tex]Ca(OH)₂[/tex]:
Moles of [tex]HCl = 0.0675 mol Ca(OH)₂ * (2 mol HCl / 1 mol Ca(OH)₂) = 0.135 mol HCl[/tex]
5. Determine the volume of 0.100 M[tex]HCl[/tex]needed to provide the required moles of[tex]HCl[/tex]:
Volume = moles of[tex]HCl[/tex] / molarity = 0.135 mol / 0.100 M = 1.35 L
to know more about calcium hydroxide refer here:
https://brainly.com/question/9584549#
#SPJ11
A scientist wants to perform a reaction in a vacuum chamber to control the experiment as much as possible and to prevent other variables from impacting the reaction. The scientist is trying to determine if the reaction is endothermic or exothermic and measure how much energy is absorbed or given off. Is this a valid approach? Why or why not? In three to five sentences, explain your reasoning.
Performing a reaction in a vacuum chamber to control the experiment is a valid approach to prevent external variables from impacting the reaction.
However, it may not be sufficient to determine if the reaction is endothermic or exothermic and measure the amount of energy absorbed or given off. This is because the vacuum chamber only isolates the reaction from the environment, but it does not provide a way to measure the energy changes that occur during the reaction. To measure the energy changes, the scientist should use techniques such as calorimetry, which directly measures the heat absorbed or released by the reaction.
To know more about calorimetry please refer:
https://brainly.com/question/1407669
#SPJ1
5. How many atoms are found in a 15.5 g sample of bismuth (Bi)? See periodic
table for the molar mass of bismuth. Use dimensional analysis, show all work to
receive full credit. (5 pts)
a. 9.33 × 1024 atoms
b.
3.24 × 10³ atoms
1.26 x 1022 atoms
d. 4.46 × 1022 atoms
C.
tech a states that overheated catalysts cannot be restored and must be replaced. tech b states that overheated catalysts can be easily restored by driving the vehicle for an extended time under a moderate load. who is correct?
Tech A is correct who says that overheated catalysts cannot be restored and must be replaced.
In chemistry, a catalyst is any substance that speeds up a reaction without consuming itself. Many crucial biochemical reactions are catalysed by enzymes, which are substances that occur naturally.
The majority of solid catalysts are made of metals, or the oxides, sulphides, and halides of metals, as well as of the semimetallic elements silicon, aluminium, and boron. Solid catalysts are frequently dispersed in materials known as catalyst supports, while gaseous and liquid catalysts are typically used in their pure form or in combination with appropriate carriers or solvents.
Visit here to learn more about the catalyst: https://brainly.com/question/24430084
#SPJ4
Theo watches the Moon every night for four weeks. He notices that
Theo watches the Moon every night for four weeks, he notices that how the Moon's position in the sky changes over time.
What does Theo notice ?Here are some things that Theo might observe or learn about the Moon:
The Moon's phases: By watching the Moon every night for four weeks, Theo would likely observe the changing phases of the Moon as it orbits the Earth. The Moon goes through a complete cycle of phases roughly once a month, which includes the new moon, waxing crescent, first quarter, waxing gibbous, full moon, waning gibbous, third quarter, and waning crescent.
The Moon's position in the sky: Theo might also notice how the Moon's position in the sky changes over time. The Moon rises and sets at different times each night, and its position in the sky also changes depending on its phase and location relative to the horizon.
The Moon's motion: By observing the Moon's position in the sky each night, Theo might notice that the Moon appears to move relative to the stars.
To know more about Moon, refer
https://brainly.com/question/1286359
#SPJ1
if i add 25 ml of ater to 125 ml of a 0.15 m sodium hydroxide solution, what will the molarity of the diluted solution be?
The molarity of the diluted solution is 0.125M.
To find the molarity of the diluted solution after adding 25 ml of water to 125 ml of a 0.15 M sodium hydroxide solution, you can follow these steps:
1. Determine the initial volume (V1) and molarity (M1) of the sodium hydroxide solution: V1 = 125 ml and M1 = 0.15 M.
2. Determine the volume of water added (V2): V2 = 25 ml.
3. Calculate the total volume of the diluted solution (Vt):
Vt = V1 + V2
Vt = 125 ml + 25 ml
Vt = 150 ml.
4. Use the dilution equation M1V1 = M2V2, where M2 is the molarity of the diluted solution.
5. Solve for M2:
M2 = (M1V1) / Vt
M2 = (0.15 M × 125 ml) / 150 ml
M2 = 18.75 / 150
M2 = 0.125 M.
So, the molarity of the diluted solution after adding 25 ml of water to 125 ml of a 0.15 M sodium hydroxide solution will be 0.125 M.
Learn more about molarity here:
brainly.com/question/8732513
#SPJ11
The diagram shows part of a DNA molecule. Using the order of bases in the top strand, write the letters of the bases that belong on the bottom strand.
Answer:
G, A, A, T, C, C, G, A, A, T, G, G, T
Explanation:
Calculate AH for the reaction:
C2H4 (g) + 3O2 (g)--> 2H2O (g) + 2CO2 (g)
The enthalpy change or AH for the reaction is -1560.9 kJ/mol. This negative value indicates that the reaction is exothermic, meaning it releases energy in the form of heat to the surroundings.
To calculate the enthalpy change (ΔH) or AH for the reaction:C2H4 (g) + 3O2 (g) → 2H2O (g) + 2CO2 (g)
We can use the standard enthalpies of formation (∆Hf°) of the products and reactants to determine the overall enthalpy change. The ∆Hf° values can be found in a reference table or online database.
The balanced equation tells us that 1 mole of C2H4 reacts with 3 moles of O2 to form 2 moles of H2O and 2 moles of CO2. So, we can write:
ΔH° = [2∆Hf°(H2O) + 2∆Hf°(CO2)] - [∆Hf°(C2H4) + 3∆Hf°(O2)]
Substituting the ∆Hf° values for each substance, we get:
ΔH° = [2(-241.8 kJ/mol) + 2(-393.5 kJ/mol)] - [(52.3 kJ/mol) + 3(0 kJ/mol)] ΔH° = -1560.9 kJ/mol
Therefore, the enthalpy change or AH for the reaction is -1560.9 kJ/mol. This negative value indicates that the reaction is exothermic, meaning it releases energy in the form of heat to the surroundings.
To know more about enthalpy change, visit:
https://brainly.com/question/29556033
#SPJ1
in the case of anionic polymerization using organometallic initiator, abby was able to get polystyrene with a number average molecular weight of 31,200 g/mole. please estimate the outcome of the new polymer if she double the initial monomer concentration and quadruple the initiator concentration from the original settings with all the other conditions/parameters and conversion being the same?
If Abby doubles the initial monomer concentration and quadruples the initiator concentration from the original settings, the outcome of the new polymer will likely have a higher number average molecular weight.
Abby's outcome of the new polymer will likely have a higher number average molecular weight because increasing the monomer concentration will lead to more monomer units being available for polymerization, while increasing the initiator concentration will lead to more initiation events, resulting in a higher degree of polymerization.
However, the exact molecular weight of the new polymer will depend on the efficiency of the polymerization reaction and any potential side reactions or termination events that may occur. It is possible that increasing the initiator concentration could also lead to more side reactions, such as chain transfer or termination, which could affect the final molecular weight distribution.
Learn more about monomer concentration: https://brainly.com/question/28875367
#SPJ11
which mixture will not result in a neutral solution? select the correct answer below: 1 m naoh and 1 m hcl 1 m nh3 and 1 m hcl 1 m koh and 1 m hbr 1 m naoh and 1 m hi
When a strong acid and a strong base are mixed in equal amounts, they undergo a neutralization reaction, resulting in the formation of water and a salt.
Therefore, the mixture of 1 M NaOH and 1 M HCl will not result in a neutral solution but instead will form sodium chloride and water. On the other hand, the mixture of 1 M NH3 and 1 M HCl, and the mixture of 1 M KOH and 1 M HBr, will also undergo neutralization reactions but will result in the formation of ammonium chloride and potassium bromide, respectively. The mixture of 1 M NaOH and 1 M HI will also not result in a neutral solution but will form sodium iodide and water due to the reaction between the strong base NaOH and the weak acid HI.
Learn more about equal amounts,
https://brainly.com/question/13024617
#SPJ4
of the encircled carbonyl groups in the compound below, how many of these groups could undergo reduction with sodium borohydride?
The part 2 in the attached image will undergo reduction with sodium borohydride.
Sodium borohydride (NaBH₄) is a commonly used reducing agent in organic chemistry. It is primarily used to reduce carbonyl groups (aldehydes and ketones) to their corresponding alcohols. Sodium borohydride can also reduce some other functional groups, such as imines and acid chlorides, but its reactivity towards these groups is much lower compared to carbonyls.
In general, the carbonyl groups in a molecule are the most likely functional groups to undergo reduction with sodium borohydride. Other functional groups such as alkenes, alkynes, aromatic rings, and alcohols are generally unreactive towards sodium borohydride.
Therefore, if your compound contains any carbonyl groups (such as aldehydes or ketones), those groups would be the most likely candidates for reduction with sodium borohydride. Part 2 is a carbonyl group, hence it will react.
To know more about Sodium borohydride, here
brainly.com/question/31321350
#SPJ4
which of the following correctly identifies the dependent and independent variables in this experiment? responses the color of the light is the dependent variable, and the percentage of plants showing phototropism is the independent variable. the color of the light is the dependent variable, and the percentage of plants showing phototropism is the independent variable. the percentage of plants showing phototropism is the dependent variable, and the color of the light is the independent variable. the percentage of plants showing phototropism is the dependent variable, and the color of the light is the independent variable. the direction of the light is the dependent variable, and the percentage of plants showing phototropism is the independent variable. the direction of the light is the dependent variable, and the percentage of plants showing phototropism is the independent variable. the color of the light is the dependent variable, and the direction of the light is the independent variable.
The percentage of plants showing phototropism is the dependent variable, and the color of the light is the independent variable. Therefore, the correct answer is: "the percentage of plants showing phototropism is the dependent variable, and the color of the light is the independent variable."
The dependent variable is the variable that is being measured or observed, and its value depends on the independent variable, which is the variable that is being manipulated or changed in the experiment. In this experiment, the percentage of plants showing phototropism is being measured, which means that it is the dependent variable. The color of the light is being manipulated, which means that it is the independent variable.
For more such question on phototropism
https://brainly.com/question/24567669
#SPJ11
What is the molar mass of an unknown if a 0.45 M solution is created by dissolving 12 grams in 425 mL of water?
To calculate the molar mass of the unknown substance, we need to use the formula:
Molar mass = (mass of solute) / (number of moles of solute)
First, let's calculate the number of moles of solute in the solution:
Number of moles = (concentration) x (volume in liters)
We know that the concentration of the solution is 0.45 M, and the volume of the solution is 425 mL, which is equivalent to 0.425 L. Substituting these values into the formula, we get:
Number of moles = 0.45 M x 0.425 L
Number of moles = 0.19125 moles
Next, we can calculate the mass of the solute (the unknown substance) by using the formula:
mass = number of moles x molar mass
Rearranging the formula, we get:
molar mass = mass / number of moles
We know that the mass of the solute is 12 grams, and we have already calculated the number of moles as 0.19125 moles. Substituting these values into the formula, we get:
molar mass = 12 g / 0.19125 moles
molar mass = 62.8 g/mol
Therefore, the molar mass of the unknown substance is 62.8 g/mol.
How can you differentiate Hydrogen and carbon dioxide gases. (by flame)
The presence of hydrogen would be indicated by a pale blue flame that is nearly invisible in broad daylight, but the presence of carbon dioxide would be indicated by the flame going out.
Why do carbon dioxide and hydrogen gas flames differ from one another?A flame ignited by hydrogen gas emits a barely perceptible pale blue flame under normal lighting conditions. This is due to the flame that hydrogen gas produces mostly emitting light in the ultraviolet spectrum, which is invisible to the human eye.
On the other side, a flame is put out when carbon dioxide gas is added to it. This is because carbon dioxide is a gas that does not support burning and is not flammable.
To learn more about hydrogen and carbon dioxide gas visit:
brainly.com/question/17546490
#SPJ9
At 25 °C, an aqueous solution has an equilibrium concentration of 0.00343M for a generic cation, A+(aq), and 0.00343M for a generic anion, B−(aq). What is the equilibrium constant, sp, of the generic salt AB(s)?
[tex] \:\:\:\:\:\:\star [/tex]For the general solubility equilibrium [tex]\sf \underline{AB \longrightarrow A^+ + B^-} [/tex]the solubility product has the following expression-
[tex] \:\:\:\:\:\:\star\longrightarrow \sf\underline{K_{(sp)} = [A^+] \times [B^-]}\\[/tex]
As per question, we are given that-
Equilibrium concentration for generic cation,[tex]\sf [A^+][/tex]= 0.00343MEquilibrium concentration for generic anion, [tex]\sf [B^-] [/tex]= 0.00343M[tex] \:\:\:\:\:\:\star [/tex] Now that we have all the required values, so we can substitute these values into the Ksp expression and solve for Ksp-
[tex] \:\:\:\:\:\:\star\longrightarrow \sf\underline{K_{(sp)} = [A^+] \times [B^-]}\\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf K_{(sp)} = 0.00343 \:M\times 0.00343\:M\\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf K_{(sp)} = 0.00343 \:molL^{-1}\times 0.00343\:molL^{-1}\\[/tex]
[tex] \:\:\:\:\:\:\longrightarrow \sf \underline{K_{(sp)} = 1.17649\times 10^{-5} \: mol^2L^{-2}}\\[/tex]
Hence, the equilibrium constant(Ksp) of the generic salt AB(s) is [tex]\sf\underline{\boxed{\sf1.17649\times 10^{-5} \: mol^2L^{-2}}}.\\[/tex]calculate the volume of 5.9 x 10^23 molecules of propane gas trapped in a container at a pressure of 253.3 kpa and a temp
To calculate the volume of
[tex]5.9 \times 10^23[/tex]
molecules of propane gas trapped in a container at a pressure of 253.3 kPa and a temperature, we can use the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.
We need to convert the number of molecules to moles. The molar mass of propane is 44.1 g/mol, so the number of moles of propane is
[tex]5.9 \times 10^23[/tex]
molecules /
[tex]6.022 \times 10^23[/tex]
molecules/mol = 0.98 moles.
We need to convert the pressure to atmospheres (atm), which is the unit typically used with the ideal gas law. 253.3 kPa / 101.3 kPa/atm = 2.50 atm.
We also need to convert the temperature to Kelvin by adding 273.15 to the Celsius temperature. Let's assume the temperature is 25°C, so T = 25°C + 273.15 = 298.15 K.
We can plug in the values into the ideal gas law equation and solve for V:
[tex]V = (nRT) / P = (0.98 mol \times 0.0821 L•atm/mol•K \times 298.15 K) / 2.50 atm = 29.6 L[/tex]
The volume of
[tex]5.9 \times 10^23[/tex]
molecules of propane gas trapped in a container at a pressure of 253.3 kPa and a temperature of 25°C is 29.6 L.
The ideal gas law equation is a useful tool to calculate the volume of a gas sample when its pressure, temperature, and amount of substance are known.
It is important to convert the units to the appropriate ones and use the correct value for the gas constant depending on the units used.
Learn more about propane here:
https://brainly.com/question/25008296
#SPJ4
Need help please!! Don’t know any of this.
1. The mass (in grams) of FeBr₃ produced from 65 g of Br₂ is 80.13 g
2. The mole of CO₂ formed from 10 moles of C₅H₁₂ is 50 moles
3. The moles of MnCl₂ prepared from 52.1 grams of MnO₂ is 0.6 mole
1. How do i determine the mass of FeBr₃ produced?The mass of FeBr₃ produced can be obtained as illustrated below:
2Fe + 3Br₂ -> 2FeBr₃
Molar mass of Br₂ = 160 g/molMass of Br₂ from the balanced equation = 3 × 160 = 480 g Molar mass of FeBr₃ = 295.85 g/molMass of FeBr₃ from the balanced equation = 2 × 295.85 = 591.7 gFrom the balanced equation above,
480 g of Br₂ reacted to produce 591.7 g of FeBr₃
Therefore,
65 g of Br₂ will react to produce = (65 × 591.7) / 480 = 80.13 g of FeBr₃
Thus, the mass of FeBr₃ produced is 80.13 g
2. How do i determine the mole of CO₂ formed?The mole of CO₂ formed can be obtained as follow:
C₅H₁₂ + 8O₂ -> 5CO₂ + 6H₂O
From the balanced equation above,
1 mole of C₅H₁₂ reacted to produce 5 moles of CO₂
Therefore,
10 moles of C₅H₁₂ will react to produce = 10 × 5 = 50 moles of CO₂
Thus, the mole of CO₂ formed is 50 moles
3. How do i determine the mole of MnCl₂ prepared?First, we shall obtain the mole of 52.1 g of MnO₂, Details below:
Mass of MnO₂ = 52.1 grams Molar mass of MnO₂ = 86.94 g/mol Mole of MnO₂ =?Mole = mass / molar mass
Mole of MnO₂ = 52.1 / 86.94
Mole of MnO₂ = 0.6 mole
Finally, we shall determine the mole of MnCl₂ prepared can be obtained as follow:
MnO₂ + 4HCl -> MnCl₂ + Cl₂ + 2H₂O
From the balanced equation above,
1 mole of MnO₂ reacted to produce 1 mole of MnCl₂
Therefore,
0.6 mole of MnO₂ will also react to produce 0.6 mole of MnCl₂
Thus, the mole of MnCl₂ prepared is 0.6 mole
Learn more about mass produced:
https://brainly.com/question/9526265
#SPJ1