Answer:
40 to 80
Explanation:
A car's kinetic energy changes with the speed. Cars going slower have less potential energy than cars going faster.
A car approaches you at 50 km/h. A fly inside the car is flying toward the back of the car at 7 km/h. From your point of view by the side of the road, the fly is moving at ______________km/h. Group of answer choices 57
Answer:
43 km/h
Explanation:
If the car is going past you at 50 km/h, then all the objects inside appear to be going 50 km/h. The fly is flying 7km/h in the opposite direction, and would appear to be going 7 km/h slower. Therefore, as 50 - 7 is 43, the fly would appear to be going 43 km/h. Hope this helps :D
The steepest street in the world is Baldwin Street in Dunedin, NZ. It is inclined at an angle of 380 , with the horizontal. A child slides down the street with a constant velocity on a sled with high friction runners. What is the coefficient of friction between the sled runners and the street?
Newton's second law allows to find the result for the friction coefficient of the street is:
The friction coeficinwete is: μ = 0.78
Newton's second law establishes a relationship between the net force, the mass and the acceleration of the body.
∑ F = m a
Where bold indicates vectors, m is to mass and acceleration.
In the attached we see a free body diagram, it is a diagram of the forces without the details of the body, the x-axis is parallel to plane also shown with the positive in the direction of movement, going down the plane and the y-axis perpendicular to the plane.
Let's use trigonometry to break down the weight.
Sin θ = [tex]\frac{W_x}{W}[/tex]
cos θ = [tex]\frac{W_y}{W}[/tex] / W
Wₓ = W sin θ
[tex]W_y[/tex] = W cos θ
We write Newton's second law for each axis.
y-axis
N- [tex]W_y[/tex] = 0
N = mg cos θ
x-axis
Wₓ - fr = ma
Since they indicate that the body goes down at a constant speed, the acceleration is zero.
W sin θ = fr
The friction force is the macroscopic representation of the interactions between the two surfaces and the formula.
fr = μ N
we substitute.
fr = μ mg cos θ
mg sin θ = μ cos θ
μ = tan θ
Let's calculate.
μ = tan 38.0
μ = 0.78
In conclusion using Newton's second law we can find the results for the friction coefficient of the street is:
The frivtion coefficient is: μ = 0.78
Learn more about the coefficient of friction here: brainly.com/question/11808898
what are the advantages of atmospheric pressure?
Answer:
it effects the amount of gas that dissolve in water
. The gas in a piston (defined as the system) warms and absorbs 655 J of heat. The expansion performs 344 J of work on the surroundings. What is the change in internal energy for the system
The change in the internal energy for the system is 311 J
The change in internal energy for the system will be the difference between the heat absorbed and the work expansion from the surroundings.
i.e.
ΔU = Q + W
where;
internal energy = Uheat absorbed = Qworkdone on surroundings = -WΔU = ( 655 J + ( - 344 J) )
ΔU = 311 J
Learn more about change in internal energy for the system here:
https://brainly.com/question/20920764?referrer=searchResults
During cellular respiration, cells absorb what ?and use it to release energy from food
Answer:
Cellular respiration is the process in which cells break down glucose, release the stored energy, and use the energy to make ATP.
Explanation:
who agree?? with this
Explanation:
ME!!!!!!!!!!!!!!!!!!
Answer:
I Fully Agree with this becoz it is only the key...
Do u agree?
The trachea splits into two branches called larynx true or false
pls answer somebodyyyyyyy
Answer:
False
Explanation:
The trachea divides into left and right air tubes called bronchi, which connect to the lungs. Within the lungs, the bronchi branch into smaller bronchi and even smaller tubes called bronchioles.
Hope this helps :)
how many gallons of gasoline are consumed in the us daily?
Jefferson refers to
_____ rights in the Declaration of Independence.
Explain what these rights are:
Answer: natural
Explanation:
Answer:
natural i just copy tha answer in there i just explain it(づ￣ 3￣)づ
Explanation:
The meaning of the term “Pursuit of Happiness.” In the Declaration of Independence, Thomas Jefferson announced that every human being has “certain unalienable rights,” among which are those to “life, liberty, and the pursuit of happiness.” What did he mean by “the pursuit of happiness”?
what is the purpose of delivering medical aid through drones
Look at the diagram shown below. The reading on ammeter 1 is 0.15 A. What will the reading on ammeter 2 be
There's no way to tell, without knowing the resistance of either X-1 or X-2, or the reading on A3.
Question 2
You can make the puck travel in complex ways by placing a set of charges around on the field. So, here’s your game challenge:
Arrange sources charge around to propel the puck from its starting position into the goal. That’s pretty easy for a straight shot; you just put a negative charge behind the goal. But what if there are barriers along the way? This is a real test of your physical understanding, including Newton’s laws of motion and electrostatic forces. Game’s on!
Part A
On the control bar, check the Trace and Field boxes. The game has three Difficulty levels. Start with Difficulty level one and arrange source charges to get the puck into the goal. Once you’ve made a score at any level, increase the Difficulty level. Take a screen capture of two of your most difficult goals and paste them here. At least one of these should be at Difficulty level 2 or 3.
Answer:
A. The electric field lines point outward and the black puck moves backwards. From this I can see that I can't put the red charge in front of the black puck because it will go away from the goal.
B. The electric field lines point inward and the black puck moves forwards and backwards. The conclusion I made from this was the blue charge by itself will not be able to get into the goal.
C.The puck moves faster when the mass increases and moves slower when the mass decreases. The more mass, the more force that is applied to the puck.
D. The relationship between the speed of the black puck and its distance from the blue charge is when the puck is further away from the blue charge, the slower the puck moves away from it.
Explanation:
Brainlest if this helped!
Rope A is tied to block 1, and rope B is attached to both block 1 and block 2 as shown in the diagram. Block 1 has a mass of 4.2 kg and block 2 has a mass of 2.6 kg. You lift both blocks straight up. Calculate the magnitude of tension in each of the ropes when the blocks
Move at constant velocity of 1.5 m/s [up]
Find the magnitude of tension in each rope when the blocks are accelerating at 1.2 m/s^2 [up].
The maximum tension the strings can withstand is 90. N. Knowing this, determine the maximum acceleration of the blocks that would not break the rope.
Hi there!
Part 1:
If the blocks are moving at a constant velocity:
∑F = 0
Begin by summing the forces acting on each block. Let the upward direction be positive.
∑F₁ = Ta - M₁g - Tb
∑F₂ = Tb - M₂g
Sum the forces:
∑F = Ta - M₁g - Tb + Tb - M₂g
∑F = Ta - M₁g - M₂g = 0
Solve for Tension A:
Ta = M₁g + M₂g (Let g = 9.8 m/s²)
Ta = 4.2(9.8) + 2.6(9.8) = 66.64 N
Now, solve for tension B using the summation of ∑F₁:
0 = Tb - M₂g
Tb = (2.6* 9.8) = 25.48 N
Part 2:
We can use the same method, but incorporate the acceleration:
∑F = Ta - M₁g - M₂g
(M₁ + M₂)a = Ta - M₁g - M₂g
(M₁ + M₂)a + M₁g + M₂g = Ta
(4.2 + 2.6)(1.2) + 4.2(9.8) + 2.6(9.8) = 74.8 N
∑F₂ = Tb - M₂g
M₂a + M₂g = Tb = 28.6 N
Part 3:
Since the top string experiences most of the tension, we can use its equation to calculate the maximum acceleration:
∑F = Ta - M₁g - M₂g
(M₁ + M₂)a = Ta - M₁g - M₂g
a = (90 - M₁g - M₂g)/(M₁ + M₂)
a = 3.435 m/s²
what will be the effect on gravitational pull between two objects of medium between them is changed
Answer:
force of gravitational attraction between them also decreases.
Explanation:
force of gravitational attraction between them also decreases.
What mass M will cause this system accelerate e 0.75 m/s²?
Answer:
5.54 [kg].
Explanation:
1) if m₁=6; g=9.81; a=0.75 and m₂ - reqired mass, then
2) it is possible to write: m₁*a=m₁*g-m₂*g, and
3) [tex]m_2=\frac{m_1(g-a)}{g}; \ => \ m_2=\frac{6*(9.81-0.75)}{9.81}=5.54[kg].[/tex]
Asap
A cyclist needs to spin 100 meters with a velocity of 5 m/s. How long will the cyclist take?
Answer:
[tex]v = \frac{d}{t} \rightarrow t= \frac{v}{d} \\ = 100m \div 5m. {s}^{ - 1} = \frac{100}{5} \\ \color{green} \boxed{ t = 20s}[/tex]
A box of mass 20 kg has a base of area 4 m2
. Calculate the pressure exerted by it on the ground. (Use 1
kg-f = 10 N)
[tex]\huge \bf༆ Answer ༄[/tex]
First, find the force exerted by the box.
[tex] \sf \: F = ma [/tex]
The required terms are :
m = mass = 20 kga = Acceleration due to gravity = 10 m/s²Calculate the force : -
[tex] \sf \: F = 20 \times 10 [/tex][tex] \sf \: F = 200 \: N[/tex]_____________________________________
Pressure can be calculated using this formula : -
[tex] \sf \: P = \dfrac {F }{A }[/tex]The stated terms are :
P = pressure F = force = 200 NA = Area = 4 m²Calculate the Pressure now : -
[tex] \sf \: P = \dfrac{200}{4} [/tex][tex] \sf \: P = 50 \: pascals[/tex][tex]꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]
A race car is traveling at a speed of 80. 0 m/s on a circular racetrack of radius 450 m. What is it's centripetal acceleration in m/s2?.
Answer:
14.2m/s^2
Explanation:
The centripetal acceleration of the race car is 14.22 m/s².
What is centripetal acceleration?Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.
In your daily existence, you must have encountered numerous instances of centripetal acceleration. A centripetal acceleration occurs when you drive in a circle, and a centripetal acceleration also occurs when a satellite orbits the earth. Centripetal refers to being in the center.
Given that: Speed of the race car: v = 80.0 meter/second.
Radius of the racetrack: r = 450 meter.
Hence, the centripetal acceleration of the car is = v²/r
= (80.0)²/450 m/s²
= 14.22 m/s².
Learn centripetal acceleration here:
https://brainly.com/question/14465119
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Determine the kinetic energy of a 1500 kg roller coaster car that is moving with a speed of 35.0 m/s.
Answer:
kinetic energy equation is 85,714.2857 kg.
Explanation:
A 60 kg gorilla named Anthony Falcon is standing on his skateboard. This is on planet Erf,
where a = g = -10m/s2
If Anthony Falcon has a weight of 600 N, with what amount of force is their body pushing
down on the skateboard with?
a helicopter cruises at a constant velocity when the total thrust of the engines is 5,000 N. How much air resistance acts on the jet ??
Hi there!
[tex]\large\boxed{F_{A} = -5000N}}[/tex]
For an object to be moving at constant velocity:
∑F = 0 (The sum of the forces acting on the object MUST be 0 N)
We can do a summation of forces for this helicopter in the HORIZONTAL direction:
∑Fₓ = Ft (Force of Thrust) + Fa (Force of air resistance) = 0
Thus, if we substitute in the given value for Ft:
Ft = -Fa
5000N = -Fa
Fa = -5000N
How much force is needed to accelerate a 70 kg rider and the 200kg motorcycle the
rider is on at 4m/s?
Answer: F = (200 kg + 70 kg) * 4 m/s² = 270 kg* 4m/s² = 1080 N
Answer:
F = 1080 N
Explanation:
To measure the current through and the voltage across a resistor in a circuit, you should place the ammeter in _____ with the resistor and the voltmeter in _____ with the resistor.
Answer:
ammeter: seriesvoltmeter: parallelExplanation:
The current is the same through components connected in series. If you want to measure the current in a component, the ammeter must be placed in series.
__
The voltage is the same at the terminals of components connected in parallel. If you want to measure the voltage across a component, the voltmeter must be connected across the component, that is, in parallel with it.
[tex]\huge \mathbb \pink{ANSWER:}[/tex]
To measure the current through and the voltage across a resistor in a circuit, you should place the ammeter in series with the resistor and the voltmeter in parallel with the resistor.
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1 point
What is the potential energy of a 12543 kg tank this on the ground? (only
put the number, no units or commas) *
Answer:
PE=0
Explanation:
If the tank is on the ground, there is 0 height which means the equation of PE=mh will be PE=12543(0)=0, hope this helps!
Select the correct answer.
When rocks containing copper are oxidized, they tend to turn from red to green. Based on this information, what evidence
would best support the theory that oxidation could not have occurred in Earth's early atmosphere?
Rocks from early Earth that contained copper are green in color.
There are no copper-containing rocks from early Earth.
Rocks from early Earth that contained copper are red in color.
All copper minerals were converted to iron minerals.
Answer:
Rocks from early Earth that contained copper are red in color
Explanation:
"Copper, a red mineral, reacts with oxygen to form a green-colored compound. In early years, rocks containing copper were red. This fact shows that there was no oxygen in the early atmosphere to oxidize red copper into the green-colored compound."
Explain the relationship between the frequency, energy, and wavelength of a wave.
Answer:
Explanation:
The energy equation is E=hv
if a car travels 90km/h for 15 minutes it will travel a. bc x 10^d what are the values of a, b, c and d
Hope it helps.
Do comment if you have any query.
Which of the following surfaces would have the lowest amount of friction?
a.Glass
b.Sand
c.Wood
d.Ice
Answer:
d. ice
Explanation:
Answer:
The correct answer is C. Ice, you know, since it's so slippery. lol
pls give brainliest
does the cars mass alone determine whether the egg breaks?
Answer:
Sample answer: The mass of the car and the speed of the car (determined by the height of the hill) determine whether the car will break the egg.
Explain how coral reefs alter the weathering and erosion of shorelines.
Answer: Coral reef structures also buffer shorelines against 97 percent of the energy from waves, storms, and floods, helping to prevent loss of life, property damage, and erosion. When reefs are damaged or destroyed, the absence of this natural barrier can increase the damage to coastal communities from normal wave action and violent storms.