A car drives to the right. There is a large amount of air resistance, and the car's engine provides the car's forward motion. Which force on the free-body diagram below represents the normal force acting on the car?

A man is pushing a baby stroller. Compared to the magnitude of the force exerted on the stroller by the man, the magnitude of the force exerted on the man by the stroller is the same.

From Newton's third law of motion, the force exerted on the stroller by the man is same as the force exerted on the man by the stroller but is in the opposite direction.

Thus, the magnitude of the force exerted on the stroller by the man and the magnitude of the force exerted on the man by the stroller is same but in opposite direction.

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Answer:

C. -35N/m

Explanation:

Using Hooke's Law, we know that the elastic constant of a spring can be found with this formula:
[tex]F=-kx[/tex]

where:

[tex]F[/tex] is the force ( in Newtons)
[tex]k[/tex] is the constant ( in Newtons per meter)
[tex]x[/tex] is the extension ( in meters)

thus, by rearranging the formula we can get:
[tex]k=-\frac{F}{x}[/tex]

[tex]k = -\frac{10}{0.286}[/tex]

[tex]k=-34.96503N/m[/tex]

Rounding off the answer, we get -35N/m

Answer:

b.

Explanation:

Answer:

b

Explanation:

when moving charged bodies move there is changing magnetic flux linking in the particles and thus magnetic field is created between them

Explanation:

Your wavelength is 0.4

Yout Amplitude is 1

Answer:

The answer is below

Explanation:

The acceleration of a ball rolling down an inclined plane would be greater than that of the acceleration of a ball rolling up if acted upon by a force of equal magnitude. For a ball rolling down an inclined plane, the acceleration due to gravity (gsinθ) acts in the direction of motion of the ball thereby leading to an increase in the acceleration of the ball; while for a balling rolling upwards, the acceleration due to gravity acts in the direction opposite to the motion of the ball thereby leading to a decrease in the acceleration of the ball.

When we wear the backpack, the center of gravity will go to the back and up direction.

A location established in relation to an object or set of objects is the center of mass. It represents the system's average location as weighted by each component's mass. The center of gravity for straightforward stiff objects with homogeneous density is found at the centroid.

Because the center of mass of any body is situated where the majority of the body mass is concentrated, when we wear a backpack, the center of mass shifts toward the up and back.

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B. The springs stretched to double the original displacement, is the the statement that best describe the effect this had on the springs.

The displacement is the shortest distance in geometry and mechanics between the initial and final positions of a point P. From the starting position to the ending position of the point trajectory, it measures the length and direction of the net motion, or total motion, in a straight line. A displacement can be discovered by using the translation that joins the starting point and ending point.

Another way to define a displacement as a relative position is the relationship between a point's final position, or xf, and its starting position, or xi (resulting from motion). The corresponding displacement vector can be defined by the difference between the starting and final positions:

                                            [tex]$ s=x_{\textrm {f}}-x_{\textrm {i}}=\Delta {x}}$[/tex]

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Answer:

14.28 m/s

Explanation:

We use this equation to find ciruclar velocity: v = 2πr/T

Find your given:

r = 5 m

T = 2.2 s

Plug in your given into the equation:

v = 2π(5 m)/2.2 s

v = 14.28 m/s

Answer:

[tex]2.09 m/s^{2}[/tex]

Explanation:

The upward acceleration of an object can be calculated using the formula:

[tex]a = F / m[/tex]

where:

a is the acceleration of the object (in meters per second squared)

F is the force acting on the object (in newtons)

m is the mass of the object (in kilograms)

So in this case, we have:

[tex]a = 11000 N / 5250 kg = 2.09 m/s^2[/tex]

This is the upward acceleration of the helicopter when a force of 11000 N is acting on it.

Answer: -200,000N

(To be more specific, 200,000N in the opposite direction)

Explanation:

By Newton's 3rd law (Action reaction pair)

The crumple zone exerts a force on the wall, the wall will exert an equal but opposite force on the wall.

Same magnitude -> 200,000N

Opposite direction-> Include a negative sign as force is a vector which depends on both magnitude and direction.

Answer:

D, the lithosphere. (CRUST AND UPPER MANTLE)

Explanation:

A tectonic plate (also called lithospheric plate) is a massive, irregularly shaped slab of solid rock, generally composed of both continental and oceanic lithosphere. Plate size can vary greatly, from a few hundred to thousands of kilometers across; the Pacific and Antarctic Plates are among the largest. Plate thickness also varies greatly, ranging from less than 15 km for young oceanic lithosphere to about 200 km or more for ancient continental lithosphere (for example, the interior parts of North and South America).

Information found on:

https://pubs.usgs.gov/gip/dynamic/tectonic.html#:~:text=A%20tectonic%20plate%20(also%20called,both%20continental%20and%20oceanic%20lithosphere.&text=Continental%20crust%20is%20composed%20of,such%20as%20quartz%20and%20feldspar.

Answer:

The answer is C.) 300,000,000 m/s

Explanation:

Light travels at a constant rate of 300,000,000 m/s. this can be determined by dividing the distance (144,000,000,000 meters) by the time (480 seconds). that's pretty fast. in fact, nothing can travel any faster than this. ever.

Light travels at a constant rate of 300,000,000 m/s. This can be determined by dividing the distance (144,000,000,000 meters) by the time (480 seconds). That's pretty fast. In fact, nothing can travel any faster than this. Ever.

First, we need to calculate force of the rocket.

What is Velocity?

Velocity is a vector quantity that describes the rate and direction of a body's motion. It is represented by an arrow pointing in the direction of motion and having a length equal to the rate of motion. Velocity is a fundamental concept in classical mechanics and is defined as the rate of change of position with respect to time.

Calculate the force of the rocket:

F = ma = (15,000 kg)(230 m/s) = 3,450,000 kg m/s2

Calculate the force of the exhaust gases:

F = ma = (1,000 kg)(-1,200 m/s) = -1,200,000 kg m/s2

Calculate the net force on the rocket:

Net Force = F_rocket + F_exhaust = 3,450,000 kg m/s2 + (-1,200,000 kg m/s2) = 2,250,000 kg m/s2

Calculate the acceleration of the rocket:

a = F/m = (2,250,000 kg m/s2)/(15,000 kg) = 150 m/s2

Calculate the change in velocity of the rocket:

Δv = a × t = (150 m/s2)(6.0 s) = 900 m/s.

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According to the given information the spring constant is 74.9 J N/m

joule, unit of work or energy in the International System of Units (SI); it is equal to the work done by a force of one newton acting through one metre. Named in honour of the English physicist James Prescott Joule, it equals 107 ergs, or approximately 0.7377 foot-pounds.

Established in the British countryside by Tom Joule in 1989, Joules is a true premium lifestyle brand with an authentic heritage. Now a truly multi-channel business, Joules designs and sells clothing, footwear, accessories, homeware, gifting and lifestyle product collections for all the family.

= PEs = 16kx² 234)

= 1/2k(25mm)² K

= 74.9 J N/m

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Answer:

The box with a mass of 10 kilograms would have a greater amount of potential energy than the box with a mass of 4 kilograms.

Explanation:

Potential energy can be defined as an energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

[tex] P.E = mgh[/tex]

Where,

P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per seconds square.

h represents the height measured in meters.

Let's assume the height is 5 meters.

Acceleration due to gravity, g = 10 m/s²

For box with mass of 10 kg

[tex] P.E = 10*10*5[/tex]

P.E = 500 Joules.

For box with mass of 4 kg;

[tex] P.E = 4*10*5[/tex]

P.E = 200 Joules.

Hence, the box with a mass of 10 kilograms would have a greater amount of potential energy than the box with a mass of 4 kilograms.

Answer:

1. e

2. f

3. b

4. g

5. a

6. c

7. d

8. j

9. k

10. i

The points of Column A with Column B related to unit measurement, temperature and energy are matched with their appropriate option.

[tex]1-2-3-4-5-6-7-8-9-10\\ e-f-b-g-a-c-d-j-k-l[/tex]

Energy is the capacity of a object to do a work. More the energy object posses, more the work it can do.

The main categories of energy

Let's match the point of Column A with Column B.

Thus, the points of Column A with Column B related to unit measurement, temperature and energy are matched with their appropriate option.

[tex]1-2-3-4-5-6-7-8-9-10\\ e-f-b-g-a-c-d-j-k-l[/tex]

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The sky diver falls vertically downward from an altitude of 6000 ft and opens the parachute after 10 s of free fall.

What is Acceleration?

Acceleration is the rate of change of velocity over time. It is basically a vector quantity, meaning it has both magnitude and direction. Acceleration is caused by a force and is measured in meters per second squared (m/s2).

a) The speed of the skydiver when the parachute opens can be found by using the equation

v=gt,

where g is the acceleration due to gravity and t is the time of free fall.

We can substitute the given values into the equation to find the speed.

v=gt

v=(32ft/s^2)(10s)

v=320ft/s

b) The distance fallen before the parachute opens can be found by using the equation

s=1/2gt^2,

where g is the acceleration due to gravity and t is the time of free fall.

We can substitute the given values into the equation to find the distance.

s=1/2gt^2

s=(1/2)(32ft/s^2)(10s)^2

s=16000ft.

c) The limiting velocity after the parachute opens can be found by using the equation

v_L=√(2mg/ρA)

where m is the mass of the skydiver, g is the acceleration due to gravity, ρ is the density of air, and A is the projected area of the parachute.

We can substitute the given values into the equation to find the limiting velocity.

v_L=√(2(180lb)(32ft/s^2)/(1.225kg/m^3)(6m^2))

v_L=30.68ft/s.

d) The time the sky diver is in the air after the parachute opens can be found by using the equation

t=v/a

where v is the initial velocity, and a is the acceleration due to air resistance.

We can substitute the given values into the equation to find the time.

t=v/a

t=(320ft/s)/(12ft/s^2)

t=26.67s.

So, the sky diver is in the air for 26.67s after the parachute opens.

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Answer:

12 N

Explanation:

Given,

Mass ( m ) = 3 kg

Acceleration ( a ) = 4 m/s^2

To find : Force ( F ) = ?

Formula : -

F = ma

F

= 3 x 4

= 12 N

Therefore, the force acting on the object is 12 N.

Answer: 12 N

Explanation:

A thermal emitter cannot be accurately approximated by hot, thin gas.

Devices known as thermal emitters radiate heat from a heated component. Some of them can be used as broadband infrared light sources for applications in spectroscopy, for instance, when the very low brightness is acceptable. Some of them are special types of incandescent lamps, sometimes in a very compact form. Their emission may be fairly continuous, but not always with high calibration accuracy. Unique designs, such as the globar and the Nernst lamp. These sources occasionally have an infrared filter installed that only allows the transmission of infrared light in a specific spectral range.

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Answer:

The bigger the energy source the more light it makes

Answer:

Energy effects light by heat, and radiation. and the depth of it and how big and other things, radiation can change the appearance slightly and heat also.

for example energy can make light, the light bulb in my opinion is electricity turned off and on Etc.

Energy can be made by light also, and other things that are completely complicated. Just look into generators and how they do that and etc.

Answer:

Pascal's law states that when there is an increase in pressure at any point in a confined fluid, there is an equal increase at every other point in the container. ... Applied to a more complex system below, such as a hydraulic car lift, Pascal's law allows forces to be multiplied.

Explanation:

When you touch a piece of wool against your skin, your skin acquires a negative charge because of the conservation of charge, which caused it to gain a positive charge.

Charge is a material's property that can be transferred into another person's body. The transfer of the charge results in the generation of electricity. The following are some examples of charge's various properties: 1 Electric charge addition 2 Electric charge conservation 3 Electric charge quantization. Equations in chemistry are denoted by the capital letter Q to denote charge, with the elementary charge of an electron (e) serving as a standard unit. The coulomb is the SI-derived unit of charge (C). In electrical engineering, the ampere-hour (Ah) unit of charge is frequently used.Dipole Definition in Chemistry and Physics. by this primary information we can consider that when you rub a piece of wool upon your skin and your skin becomes negatively charged because it gained a positive charge as the result of conservation of charge.

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Answer: Pulses do not have energy, however, waves do.

Hope this helps (^_^)

Answer:

0.22 A

Explanation:

We must first find the impedence of the circuit using the formula;

√R^2 + (XL)^2

XL = 2πfL

XL = 2 * 3.14 *1000* 30 * 10^-3

XL = 188 Ω

√(200)^2 + (188)^2

=√40000 + 35344

=274.5 Ω

Then;

V= IZ

I = V/Z

I= 60 V/274.5 Ω

I= 0.22 A

The 2.00-kilogram object weighs 19.6 newtons on Earth, its weight on the Mars is 2.00 kg.

The mass is known as the amount of matter which is contained in a body.  It is a property which is consistent in a body regardless of the body's current location, gravitational pull and various other factors which exist.

Mass and weight are two separate quantities. Weight is computed as a product of mass and acceleration. Mass has a property to remain constant and it means that whether the object is on any planet, irrespective of that, it will be constant. The mass remains the same that is 2.00 kg.

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Answer:

D(ensity) = M / V = 6.94 g / 13 cm^3 = .534 g / cm^3

Compare to H20 at 1 gm / cm^3

Explanation:

Always write what you know first about the problem

The surface of the piston that has the force applied is a circle

The area of a circle is pi x r^2

Pressure is Force / Area

Write this out

P = F / (pi x r^2)

solve for r

sqrt( F / (P x Pi)) = r

But dont forget that d = 2 x r

The diameter of the piston is equal to 3.38 inches.

The pressure can be defined as the force that is applied per unit area. Force will be applied perpendicular to the surface per unit area. pressure can be measured in the unit of pascal. A Pascal can be defined as the pressure exerted by one force Newton on one square area.

The mathematical expression to calculate pressure is:

Pressure = Force/area

Given, the maximum pressure of the piston, P = 2.5 psi

We know that 1 psi = 703.07 Kg/m²

P = 2.5 × 703.07 = 1757.67 Kg/m²

The force applied, F = 100N = 100/ 9.8 Kg = 10.20 Kg

The area of the piston, A = F/P

A = 10.20/1757.67

A = 0.00580 m²

Area of the piston, A = πr²

0.0058 = 3.14 × r²

r = 0.04297 m

Diameter, d = 2r = 0.0859 m

We know that one meter = 39.37 inch  

The diameter of the piston, d = 0.0859 × 39.37 = 3.384 inch

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Answer:

b. climb a mountain

Answer:

A. rocky orbiting object

Answer:

A rocky orbiting object.

i hope it's helpful

51.6 seconds long does it take a plane, traveling at a constant speed of 130 m/s, to fly once around a circle whose radius is 2650 m.

The time it takes for an object to travel once around a circle of radius r at a constant speed v can be found using the equation:

T = 2 x π x r ÷ v

where T is the time in seconds, pi is approximately 3.14, r is the radius of the circle in meters, and v is the speed of the object in meters per second.

Given a constant speed of 130 m/s and a radius of 2650 m, the time it would take for a plane to fly once around the circle would be:

T = 2 x π x 2650 m / 130 m/s

T = 51.6 sec

So, it would take approximately 51.6 seconds for a plane traveling at a constant speed of 130 m/s to fly once around a circle whose radius is 2650 m.

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