The statement about the chances of occurrence of nonmoving violations more on a weekend than on a weekday in past ten years is cannot be answered using only the information in the database. So, option(b) is provide the right answer.
Database: The database is a large collection of data and it is used to store and retrieve the accordingly. It has an organization of a certain amount of data that needs and it contains. We have a database of all traffic tickets that were issued over the past ten years in a city. The informations including are
the tickets are divided into two categories. 1) moving violations2) nonmoving violations
the month and year in which the ticket was issued the category of the ticket.We have to recongise the statement which is not answering by the above informations in database. First statement is can be answerable, because we have data of year in which tickets are issued. Similarly, statements third and fourth related to data of tickets issued in month and year in past ten years. So, both are answerable statements. Therefore, the second statement
is cannot be answerable here.
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Complete question:
a city maintains a database of all traffic tickets that were issued over the past ten years. the tickets are divided into the following two categories. moving violations nonmoving violations the data recorded for each ticket include only the following information. the month and year in which the ticket was issued the category of the ticket which of the following questions cannot be answered using only the information in the database? responses
a) have the total number of traffic tickets per year increased each year over the past ten years?
b) in the past ten years, were nonmoving violations more likely to occur on a weekend than on a weekday?
c) in the past ten years, were there any months when moving violations occurred more often than nonmoving violations?
d) in how many of the past ten years were there more than one million moving violations?
topic 3 providing lines are parallel
21
21. in the figure, provided line n and line m are parallel the values of x and y are
x = 7
y = 24
How to find x and y21. When line m and line n are parallel then using corresponding angle theorem we have that:
7y - 23 + 8x - 21 = 180
7y - 8x = 180 + 23 - 21
7x - 8x = 182
Also
8x - 21 + 23x - 16 = 180
8x + 23x = 180 + 21 + 16
31x = 217
x = 217 / 31
x = 7
using vertical angle theorem we have:
7y - 23 = 23x - 16
plugging in the value of x
7y - 23 = 23 * 7 - 16
7y - 23 = 145
7y = 145 + 23
7y = 168
y = 24
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Algebra please help
Your school newspaper has an editor-in-chief and an assistant editor-in-chief. The newspaper staff
has 5 students. How many different ways can students be chosen for these positions?
There are 20 different ways the students can be chosen for the positions of editor-in-chief and assistant editor-in-chief.
There are 5 students in the newspaper staff, and two positions to fill i.e. editor-in-chief and assistant editor-in-chief. We need to find the number of different ways the students can be chosen for these positions.
To solve this problem, we can use the formula for permutation
We know the formula for Permutation is
[tex]P(n,r)=\frac{n!}{(n-r)!}[/tex]
Here, n=5 and r=2
So, P(5,2) = 5!/(5-2)!
= 5!/3!
= 120/6
= 20
Therefore, there are 20 different ways the students can be chosen for the positions of editor-in-chief and assistant editor-in-chief.
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Jenny is planning an extended trip to russia.the table below shows a list of cities which she would like to visit during her stay, along with the amount of money she anticipates needing to spend on travel, lodging, and similar expenses in each city. all costs are given in russian rubles (rub). city cost (rub) izhevsk 4,721 novosibirsk 4,870 nizhny novgorod 6,920 moscow 5,485 chelyabinsk 5,217 saint petersburg 5,960 tolyatti 5,598 yaroslavl 4,901 even though jenny wants to go to each of these cities, her budget is only rub 33,000, so she recognizes that she must change her itinerary and choose not to visit some cities. which of the following pairs of cities will not put jenny back under budget if she drops them? a. moscow and chelyabinsk b. izhevsk and nizhny novgorod c. novosibirsk and saint petersburg d. yaroslavl and tolyatti
The pairs of cities that will not put Jenny back under budget if she drops them are:
a. Moscow and Chelyabinsk
b. Izhevsk and Nizhny Novgorod
To determine which pair of cities Jenny can drop without going over budget, we need to find the total cost of each pair and see if it exceeds her budget of rub 33,000.
a. Moscow and Chelyabinsk:
Total cost = 5,485 + 5,217 = 10,702 rubles
This pair of cities is over budget, so Jenny cannot drop any other cities if she wants to visit both Moscow and Chelyabinsk.
b. Izhevsk and Nizhny Novgorod:
Total cost = 4,721 + 6,920 = 11,641 rubles
This pair of cities is over budget, so Jenny cannot drop any other cities if she wants to visit both Izhevsk and Nizhny Novgorod.
c. Novosibirsk and Saint Petersburg:
Total cost = 4,870 + 5,960 = 10,830 rubles
This pair of cities is under budget, so Jenny can drop this pair without going over budget.
d. Yaroslavl and Tolyatti:
Total cost = 4,901 + 5,598 = 10,499 rubles
This pair of cities is under budget, so Jenny can drop this pair without going over budget.
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In ΔPQR, the measure of ∠R=90°, the measure of ∠P=26°, and PQ = 8. 5 feet. Find the length of QR to the nearest tenth of a foot
In ΔPQR, the length of QR is approximately 4.1 feet to the nearest tenth of a foot.
In ΔPQR, given that ∠R=90°, ∠P=26°, and PQ=8.5 feet, you want to find the length of QR to the nearest tenth of a foot.
Step 1: Since ∠R is a right angle (90°), we can use trigonometric ratios to find QR. First, let's find ∠Q. We know that the sum of angles in a triangle is 180°, so ∠Q = 180° - (∠P + ∠R) = 180° - (26° + 90°) = 64°.
Step 2: Now that we have all the angles, we can use the sine formula to find QR. We'll use the sine of ∠P (26°) and the given side PQ (8.5 feet) as our reference. The sine formula is:
QR = (PQ * sin(∠P)) / sin(∠Q)
Step 3: Plug in the known values:
QR = (8.5 * sin(26°)) / sin(64°)
Step 4: Calculate the sine values and the division:
QR = (8.5 * 0.4384) / 0.8988 ≈ 4.1326
Step 5: Round the answer to the nearest tenth of a foot:
QR ≈ 4.1 feet
In ΔPQR, the length of QR is approximately 4.1 feet to the nearest tenth of a foot.
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Boris's backyard has cement and grass. Find the area of the part with cement.
(Sides meet at right angles. )
4 m
1 m
2 m
grass
5 m
3 m
cement
5 m
The constant of proportionality between the number of yards Jackson can mow and the number of hours is 3/4.
To find the area of the part with cement, we need to find the area of the entire rectangle and then subtract the area of the part with grass.
The area of the rectangle is: length x width = 5 m x 4 m = 20 m²
The area of the part with grass is: length x width = 3 m x 2 m = 6 m²
So the area of the part with cement is:
20 m² - 6 m² = 14 m²
Therefore, the area of the part with cement is 14 square meters.
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Garden plots in the Portland Community Garden are rectangles
limited to 45 square meters. Christopher and his friends want a plot
that has a width of 7.5 meters. What length will give a plot that has
the maximum area allowed?
The length should be less than or equal to 6 meters in order to have a plot with the maximum area allowed (45 square meters) when the width is 7.5 meters.
To find the length that will give a plot with the maximum area allowed, we can use the formula for the area of a rectangle:
Area = Length × Width
The width is given as 7.5 meters, and the area should not exceed 45 square meters.
Let's denote the length as L.
We want to maximize the area, so we need to find the value of L that satisfies the condition Area ≤ 45 and gives the largest possible area.
Substituting the given values into the area formula, we have:
Area = L × 7.5
Since the area should not exceed 45 square meters, we can write the inequality:
L × 7.5 ≤ 45
To find the maximum value of L, we can divide both sides of the inequality by 7.5:
L ≤ 45 / 7.5
Simplifying the right side:
L ≤ 6
Therefore, the length should be less than or equal to 6 meters in order to have a plot with the maximum area allowed (45 square meters) when the width is 7.5 meters.
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PLEASE HELP WILL MARK BRANLIEST!!!
The customer can choose from 21 different gifts if they want to order only 1 item, 138 different gifts if they want to order 2 items of different kinds, and 280 different gifts if they want to order 3 items of different kinds.
To find the different number of gifts, we use the fundamental counting principle, which states that the total number of ways to choose a sequence of items is equal to the product of the number of choices available for each item.
⇒ If a customer wants to order only 1 item, they can choose from:
10 varieties of "greeting-cards"
4 types of "fruit-baskets"
7 flower arrangements
So, total number of different gifts that can be created is: 10 + 4 + 7 = 21.
⇒ If a customer wants to order 2 items of different kinds, they can choose from:
10 varieties of greeting-cards and 4 types of fruit baskets :
(10 × 4 = 40 choices)
10 varieties of greeting cards and 7 flower arrangements :
(10 × 7 = 70 choices)
4 types of fruit-baskets and 7 flower arrangements :
(4 × 7 = 28 choices)
So, number of different gifts that can be created is: 40 + 70 + 28 = 138.
⇒ If a customer wants to order 3 items of different kinds, they can choose from:
10 varieties of greeting cards, 4 types of fruit baskets, and 7 flower arrangements (10 × 4 × 7 = 280 choices),
So, the total number of different gifts that can be created is : 280.
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You babysat your neighbor's children and they paid you $45 for 6 hours. Fill in the t-table for hours (x) and money (y)
you got $45 for 6hours.
one hour=$7.5
two hours=$15
three hours=$7.5*3
calculation=$45/6
Determine all of the values of that satisfy the condition cos =0 where 0 ≤ 0 <360°
All the value of of that satisfy the condition cos θ = - 1/2 ,
where 0 ≤ θ <360° are,
⇒ 120°, 240°
Given that;
Expression is,
cos θ = - 1/2
where 0 ≤ θ <360°
Since, cos θ = - 1/2
Hence, It belong in second and third quadrant.
So, cos θ = - 1/2
cos θ = 120°
cos θ = 240°
Thus, All the value of of that satisfy the condition cos θ = - 1/2 ,
where 0 ≤ θ <360° are,
⇒ 120°, 240°
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A survey of 61 randomly selected homeowners finds that they spend a mean of $62 per month on home maintenance. construct a 98% confidence interval for the mean amount of money spent per month on home maintenance by all homeowners. assume that the population standard deviation is $13 per month. round to the nearest cent.
The 98% confidence interval for the mean amount of money spent per month on home maintenance by all homeowners is $58.06 to $65.94.
To construct a confidence interval for the mean amount of money spent per month on home maintenance by all homeowners, we can use the formula:
CI = [tex]\bar{X}[/tex] ± Zα/2 * (σ/√n)
where [tex]\bar{X}[/tex] is the sample mean, Zα/2 is the critical value from the standard normal distribution corresponding to the desired confidence level, σ is the population standard deviation, and n is the sample size.
In this case, we have:
[tex]\bar{X}[/tex] = $62 (the sample mean)
α = 0.02 (since we want a 98% confidence interval, which means α/2 = 0.01)
Zα/2 = 2.33 (from the standard normal distribution table)
σ = $13 (the population standard deviation)
n = 61 (the sample size)
Substituting these values into the formula, we get:
CI = $62 ± 2.33 * ($13/√61)
Simplifying this expression, we get:
CI = $62 ± $3.94
Therefore, the 98% confidence interval for the mean amount of money spent per month on home maintenance by all homeowners is $58.06 to $65.94.
This means that we can be 98% confident that the true population mean falls within this range. In other words, if we were to repeat the survey many times and construct confidence intervals in the same way, about 98% of the intervals would contain the true population mean.
It's important to note that this assumes that the sample is representative of the population, and that the population standard deviation is known. If these assumptions are not met, then the confidence interval may not be accurate.
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What is the quotient of the expression (5.04×1012)÷(6.3×109) written in scientific notation?
The quotient of the expression (5.04×10^12)÷(6.3×10^9) written in scientific notation is 8 × 10^2.
To divide two numbers written in scientific notation, we can divide their coefficients (the decimal parts) and subtract their exponents. So, we have:
(5.04 × 10^12) ÷ (6.3 × 10^9) = (5.04 ÷ 6.3) × 10^(12-9) = 0.8 × 10^3
Since 0.8 is less than 1, we can write this number in scientific notation by moving the decimal point one place to the right and subtracting 1 from the exponent:
0.8 × 10^3 = 8 × 10^2
Therefore, the quotient of the expression (5.04×10^12)÷(6.3×10^9) written in scientific notation is 8 × 10^2.
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Austin use a mold to make cone-shaped cupcakes. The diameter of the mold is 3 inches, and the height of the mold is 2 inches. If one cubic inch is about 0. 55 ounces, how many ounces will 10 cupcakes weigh? Use 3. 14 for pi. Round to the nearest tenth of an ounce
The 10 cupcakes will weigh approximately 25.9 ounces when one cubic inch is about 0. 55 ounces, the diameter of the mold is 3 inches and the height of the mold is 2 inches.
Given data:
Diameter of the mold = 3 inches
Radius = 3/2 = 1.5 inches
Height of the mold = 2 inches.
One cubic inch = 0.55 ounces
π = 3. 14
We need to find how many ounces will 10 cupcakes weigh. to find that we need to find the volume of a cone and the weight of one cupcake. we can find the volume of a cone given by the formula,
[tex]V = (1/3)πr^2h[/tex]
Where:
r = radius
h = height
By Substituting the r and h values into the formula we get:
[tex]V = (1/3)πr^2h[/tex]
[tex]= (1/3) π ((1.5)^2) × (2)[/tex]
[tex]= (1/3) π×(2.25)×(2)[/tex]
= 1.5π
When one cubic inch of the cone is about 0.55 ounces, the weight of one cupcake is approximately
= 1.5π × 0.55
= 0.825π ounces.
The weight of 10 cupcakes is determined by multiplying by the weight of one cupcake, it is given as:
= 10 × 0.825π
= 8.25π ounces
= 8.25 × 3.14
= 25.9 ounces.
Therefore, the 10 cupcakes will weigh approximately 25.9 ounces.
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Mai  Drew does design shown below each rectangle in the design have the same area each rectangle is a what fraction of the area of the complete design 
Answer:
1/3
Step-by-step explanation:
There are 3 rectangles, so 1 rectangle is 1 out of 3 rectangles. So the fraction would be 1/3.
Each rectangle is 1/3 fraction of the complete design.
What are Fractions?Fractions are type of numbers which are written in the form p/q, which implies that p parts in a whole of q.
Here p, called the numerator and q, called the denominator, are real numbers.
Given is a design drawn by Mai.
The design consists of three rectangles.
Also, given that each of the rectangle has the same area.
This means that if we find one of the rectangle's area, multiply it by 3 and we will get the whole area.
Or in other words, if we find the whole area, then divide it by 3 to get each of the rectangle's area.
So the required fraction is 1/3.
Hence the fraction is 1/3.
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Can I have help with this question, Please?
"Write an equation for the ellipse."
Center: (1, -3)
The equation of the ellipse with center (1, -3), and a semi major axis of 4, and a semi minor axis of 3 is; (x - 1)²/4² + (y + 3)²/3²
What is the standard form of the equation of an ellipse?The standard form equation of an ellipse can be presented as follows;
(x - h)²/a² + (y - k)²/b² = 1
Where;
(h, k) = The coordinates of the center of the ellipse.
The length of the semi major axis = a
Length of the semi minor axis = b
The center of the specified ellipse is; (h, k) = (1, -3)
The semi major axis = 4
The length of the semi minor axis = 3
The equation of the ellipse is therefore;
(x - 1)²/4² + (y - (-3))²/3² = 1
(x - 1)²/4² + (y + 3)²/3² = 1
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PLEASE HELPPPP!!!!
The base of a right octagonal prism has eight sides equal in length. One side of the base measures 2. 3 cm, and the area of the base is 25. 76 cm². The surface area of the prism is 223. 56 cm².
Whats the height of the prism?
The height of the right octagonal prism is approximately 10.75 cm.
The given information states that the base of the prism is a regular octagon with each side measuring 2.3 cm, and the area of the base is 25.76 cm². Additionally, the surface area of the prism is 223.56 cm².
First, let's calculate the area of the eight lateral faces. We can do this by subtracting the base's area from the total surface area:
223.56 cm² (total surface area) - 25.76 cm² (base area) = 197.8 cm² (lateral area)
Now, we know that the lateral area is the sum of the areas of all eight rectangular faces. Each rectangle has a base of 2.3 cm (the same as the sides of the octagonal base) and a height equal to the height of the prism (h). Since there are eight faces, the combined area of these rectangles is 8 x 2.3 x h:
8 x 2.3 x h = 197.8 cm²
18.4 x h = 197.8 cm²
To find the height of the prism (h), we can divide both sides of the equation by 18.4:
h = 197.8 cm² / 18.4
h ≈ 10.75 cm
So, the height of the right octagonal prism is approximately 10.75 cm.
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a specific combination lock has 3 numbers chosen out of 40 possible numbers (0-39). assuming that all lock combinations are possible (including repeated numbers) find the number of possible lock combinations.
The total number of possible lock combination using the 40 possible numbers for making lock of 3 numbers is equal to 64,000.
Possible number used for lock combination are 40.
Range is 0 - 39.
Total number chosen for lock combination is equal to 3.
Since there are 40 possible numbers to choose from for each of the three positions on the combination lock.
The total number of possible combinations is equal to ,
40 x 40 x 40
= 40^3
= 64,000
Therefore, there are 64,000 possible lock combinations when choosing 3 numbers out of 40 possible numbers, assuming repeated numbers are allowed.
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17. Determine whether the two figures are similar. If so, give the similarity ratio of *
the smaller figure to the larger figure. The figures are not drawn to scale.
6 ft
8 ft
6 ft
Yes; 3:5
Yes; 2:3
OYes; 2:5
10 ft
12 ft
10 ft
No they are not similar
The answer is "No they are not similar". The correct option is D.
To determine if the two cuboids are similar, we need to check if their corresponding sides are proportional.
If we compare the corresponding sides of the first cuboid and the second cuboid, we get:
6/10 = 0.6
8/12 = 0.666...
6/10 = 0.6
Since these ratios are not equal, the corresponding sides are not proportional, and therefore the two cuboids are not similar.
Therefore, the answer is "No they are not similar".
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Prepare the operating activities section of the statement of cash flows for peach computer using the indirect method. (list cash outflows and any decrease in cash as negative amounts.)
Cash outflows and decreases in cash are reported as negative amounts in the operating activities section of the statement of cash flows for Peach Computer using the indirect method.
How to prepare the operating activities section of the statement of cash flows for Peach Computer using the indirect method?The operating activities section of the statement of cash flows for Peach Computer using the indirect method would include the following cash inflows and outflows:
Cash inflows:
Sales revenue from the sale of computersCash received from customers for computer repairs and servicesInterest received on loans or investmentsCash outflows:
Payments to suppliers for inventory purchasesPayments to employees for salaries and wagesPayments for operating expenses such as rent, utilities, and advertisingPayments of income taxesPayments of interest on loansPayments to creditors for accounts payableAny decrease in cash would be represented as negative amounts in this section.
It's important to note that the specific amounts and details would vary based on Peach Computer's individual financial transactions and operations. The operating activities section provides a summary of the cash inflows and outflows directly related to the company's core business operations during the specified period.
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Triangle XYZ has coordinates X(-2,2), Y(-3,-4). And Z(1,-2). The triangle is reflected across the x-axis. What are the coordinates of triangle X'Y'Z'?
The coordinates of triangle X'Y'Z' is X'(-2,-2), Y'(-3,4), Z'(1,2).
What are the coordinates of the triangle?
The triangle's vertices have the coordinates (x1,y1), (x2,y2), and (x3,y3). The line that connects the first two is split in the ratio l:k, and the line that runs from the division point to the opposing angular point is divided in the ratio m:k+l.
Here, we have
Given: Triangle XYZ has coordinates X(-2,2), Y(-3,-4). And Z(1,-2).
The triangle is reflected across the x-axis and we have to find the coordinates of triangle X'Y'Z'.
X(-2,2), Y(-3,-4) and Z(1,-2).
While reflecting any points across the x-axis with coordinates as (x, y) becomes, (x, -y). i.e. sign of y-coordinate changes.
The rule is (x, y) → (x, -y)
After applying the rule, we get
X(-2,2) ⇒ X'(-2,-2)
Y(-3,-4) ⇒ Y'(-3,4)
Z(1,-2) ⇒ Z'(1,2)
Hence, the coordinates of triangle X'Y'Z' is X'(-2,-2), Y'(-3,4), Z'(1,2).
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On a baseball diamond, home plate and second base lie on the perpendicular bisector of the line segment that joins first and third base. First base is 90 feet from home plate. How far is it from third base to home plate? Sketch a baseball diamond on a separate sheet of paper, labeling home plate as point A
, first base as B
, second base as C
, and third base as D. Label the intersection of AC⎯⎯⎯⎯⎯
and BD⎯⎯⎯⎯⎯
as E. Using the Perpendicular Bisector Theorem, determine how far it is from third base to home plate. Describe your conclusion in the context of the situation
Using the Perpendicular Bisector Theorem, the distance from third base to home plate is 90 feet. This means that all the bases are equidistant from home plate, which is a fundamental property of a baseball diamond.
To find the distance from third base to home plate, we need to use the Perpendicular Bisector Theorem, which states that if a point lies on the perpendicular bisector of a segment, then it is equidistant from the endpoints of the segment.
First, we draw a baseball diamond with points A, B, C, and D labeled as described in the problem.
Next, we draw the line segment that joins first base (B) and third base (D), and we construct the perpendicular bisector of this segment by drawing a line through the midpoint of BD and perpendicular to BD. Let's label the point where the perpendicular bisector intersects the line that connects home plate (A) and second base (C) as E.
Since E lies on the perpendicular bisector of BD, it is equidistant from B and D. We know that first base (B) is 90 feet from home plate (A), so the distance from home plate to E must also be 90 feet. Therefore, the distance from third base (D) to home plate (A) is also 90 feet.
In conclusion, using the Perpendicular Bisector Theorem, we determined that the distance from third base to home plate is 90 feet.
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ALGEBRA
Farha Gadhia has applied for a $100,000 mortgage loan
at an annual interest rate of 6%. The loan is for a period of 30 years
and will be paid in equal monthly payments that include interest.
Use the monthly payment formula to find the payment.
12. A normal distribution has a mean of 34 and a standard deviation of 7. Find the range of
values that represent the middle 95% of the data.
F. 27
G. 20 X 48
H. 13
J. 6
The range of values that represent the middle 95% of the data is from 20.18 to 47.82 or (20.18, 47.82).
What is Hypothesis test?A measurable speculation test is a strategy for factual deduction used to conclude whether the information within reach adequately support a specific speculation. We can make probabilistic statements about the parameters of the population thanks to hypothesis testing.
According to question:The middle 95% of a normal distribution is located within 1.96 standard deviations from the mean in both directions.
Therefore, the lower limit is:
34 - 1.96(7) = 20.18
And the upper limit is:
34 + 1.96(7) = 47.82
So the range of values that represent the middle 95% of the data is from 20.18 to 47.82 or (20.18, 47.82).
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A store sells cashews for $6. 00 per pound and peanuts for $3. 00 per pound. The manager decides to mix 20
pounds of peanuts with some cashews and sell the mixture for $4. 00 per pound. How many pounds of cashews
should be mixed with the peanuts so that the mixture will produce the same revenue as would selling the nuts
separately?
The amount of cashews needed to be mixed with the peanuts so that the mixture will produce the same revenue as selling the nuts separately is 10 pounds.
To solve this problem, we need to use the equation:
$3(20) + 6x = 4(20 + x)$
where x is the number of pounds of cashews needed.
First, we simplify the equation by multiplying:
$60 + 6x = 80 + 4x$
Then we isolate x by subtracting 4x from both sides and subtracting 60 from both sides:
$2x = 20$
Finally, we solve for x by dividing both sides by 2:
$x = 10$
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if you roll two fair six-sided dice, what is the probability that the sum is 4 44 or higher?
The probability of rolling two fair six-sided dice and getting a sum of 4 or higher is 11/12
To calculate the probability of rolling two fair six-sided dice and getting a sum of 4 or higher, we first need to calculate the total number of possible outcomes.
The number of possible outcomes when rolling two dice is 6 × 6 = 36, since each die has 6 possible outcomes.
Now, let's find the number of outcomes that result in a sum of 4 or higher. We can do this by listing all the possible outcomes:
Sum of 4: (1, 3), (2, 2), (3, 1) = 3 outcomes
Sum of 5: (1, 4), (2, 3), (3, 2), (4, 1) = 4 outcomes
Sum of 6: (1, 5), (2, 4), (3, 3), (4, 2), (5, 1) = 5 outcomes
Sum of 7: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1) = 6 outcomes
Sum of 8: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) = 5 outcomes
Sum of 9: (3, 6), (4, 5), (5, 4), (6, 3) = 4 outcomes
Sum of 10: (4, 6), (5, 5), (6, 4) = 3 outcomes
Sum of 11: (5, 6), (6, 5) = 2 outcomes
Sum of 12: (6, 6) = 1 outcome
Therefore, the number of outcomes that result in a sum of 4 or higher is 3 + 4 + 5 + 6 + 5 + 4 + 3 + 2 + 1 = 33.
Therefore, the probability of rolling two fair six-sided dice and getting a sum of 4 or higher is 33/36 = 11/12.
To find the probability of getting a sum of 44 or higher, we need to subtract the probability of getting a sum of 43 or lower from 1:
Sum of 2: (1, 1) = 1 outcome
Sum of 3: (1, 2), (2, 1) = 2 outcomes
Sum of 4: (1, 3), (2, 2), (3, 1) = 3 outcomes
Sum of 5: (1, 4), (2, 3), (3, 2), (4, 1) = 4 outcomes
Sum of 6: (1, 5), (2, 4), (3, 3), (4, 2), (5, 1) = 5 outcomes
Sum of 7: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1) = 6 outcomes
Sum of 8: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) = 5 outcomes
Sum of 9: (3, 6), (4, 5), (5, 4), (6, 3) = 4 outcomes
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The triangle above has the following measures.
a=9cm
b=9√3cm
Use the 30-60-90 Thangle Theorem to find the
length of the hypotenuse Include correct units
Show all your work
Answer:
Step-by-step explanation:
The length of the hypotenuse is approximately 4.95 cm.
We have,
Since triangle ABC is a 45-45-90 triangle, we know that the measure of angle B is also 45 degrees.
Therefore, we can use the 45-45-90 Triangle Theorem, which states that in a 45-45-90 triangle,
the length of the hypotenuse is √2 times the length of either leg.
In this case,
We know that leg a = 3.5 cm, so we can find the length of the hypotenuse c using the formula:
c = a√2
Substituting the value of a, we get:
c = 3.5√2 ≈ 4.95 cm
Therefore,
The length of the hypotenuse is approximately 4.95 cm.
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complete question:
The triangle above has the following measures. mzC = 45° a = 3.5 cm Use the 45-45-90 Triangle Theorem to find the length of the hypotenuse. Include correct units. Show all your work.
PLEASE HELP!!!!!!! Two lines, E and F, are represented by the equations given below. Line E: 5x + 5y = 40 Line F: x + y = 8 Which statement is true about the solution to the set of equations? (4 points) Question 2 options: 1) It is (40, 8). 2) It is (8, 40). 3) There is no solution. 4) There are infinitely many solutions.
Answer: (4)
Step-by-step explanation:
Two lines E and F are same.
5x + 5y = 40
x + y = 8
Deviding both hands of E by 5,
we get F's equation.
So every single point on the line x+y=8
represents the solution of the given system.
A group of students collected old newspapers for a recycling project. The data shows the mass, in kilograms, of old newspapers collected by each student.
23, 35, 87, 64, 101, 90, 45, 76, 105, 60, 55
98, 122, 49, 15, 57, 75, 120, 56, 88, 45, 100.
What percent of students collected between 49 kilograms and 98 kilograms of newspapers? Explain how you got to your solution
To find the percentage of students who collected between 49 and 98 kilograms of newspapers, we need to first count the number of students whose collection falls within this range. We can do this by sorting the data and counting the number of values that fall within this range.
Sorting the data, we get:
15, 23, 35, 45, 45, 49, 55, 56, 57, 60, 64, 75, 76, 87, 88, 90, 98, 100, 101, 105, 120, 122
We can see that there are 17 students whose collection falls within the range of 49 to 98 kilograms.
To find the percentage of students, we can divide the number of students whose collection falls within this range by the total number of students and then multiply by 100. The total number of students is the sum of the number of values in the two sets, which is 22 + 22 = 44.
Therefore, the percentage of students who collected between 49 and 98 kilograms of newspapers is:
17/44 * 100% ≈ 38.6%
So approximately 38.6% of the students collected between 49 and 98 kilograms of newspapers.
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If f(9) = 9, f'(9) = 4, limit x→9√(f(x))-3/√(x)-3 =
A. 1
B. 1/4
C. 1/2
D. -1/2
The answer is A. 1. We can use L'Hopital's rule to evaluate the limit:
limit x→9√(f(x))-3/√(x)-3 = limit x→9 (f(x)-9)/(x-9) / (√(f(x))-3)/(√(x)-3)
Now, we know that f(9) = 9 and f'(9) = 4, so we can use the definition of the derivative to write:
f(x) - f(9) = f'(9)(x-9) + o(x-9)
where o(x-9) represents a term that goes to 0 faster than x-9 as x approaches 9. Plugging this into the numerator, we get:
f(x) - 9 = 4(x-9) + o(x-9)
Plugging this into the denominator, we get:
√(f(x)) - 3 = √(4(x-9) + o(x-9)) = 2√(x-9) + o(1)
√(x) - 3 = √(x-9) + o(1)
Therefore, the limit becomes:
limit x→9 (4(x-9) + o(x-9))/(√(x-9) + o(1)) / (2√(x-9) + o(1))/(√(x-9) + o(1))
Simplifying this expression, we get:
limit x→9 2(4(x-9) + o(x-9))/(√(x-9) + o(1))^2
limit x→9 8 + 2o(1)/(x-9)
As x approaches 9, the o(1) term goes to 0, so the limit becomes:
8 + 2*0/0 = 8
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A man spent 500 dollars on a shopping trip to Erewhon. If the milk costed 132 dollars and the chicken costed 220, how much did the fish cost?
Answer:148
Step-by-step explanation:
Assuming he only bought milk, fish and chicken.
220+132=352
500-352=148
Write the repeating decimal as a geometric series. 0,216
the repeating decimal 0.216 can be written as the geometric series: 0.216 = 216/990.
To write the repeating decimal 0.216 as a geometric series, we first need to express it in the form of a sum of a geometric series.
The decimal 0.216 repeats every three digits, so we can break it down as follows:
0.216 = 0.2 + 0.01 + 0.006 + 0.0002 + 0.00001 + 0.000006 + ...
Now, we can write this as a sum of a geometric series with the first term (a) and the common ratio (r):
a = 0.2
r = 0.01 (because each term is 1/100 of the previous term)
Thus, the geometric series for the repeating decimal 0.216 is:
0.216 = 0.2 + 0.2(0.01) + 0.2(0.01)^2 + 0.2(0.01)^3 + ...
The formula for the sum of an infinite geometric series is S = a / (1 - r), where S is the sum, a is the first term, and r is the common ratio.
Using the values for a and r, we can find the sum of the series:
S = 0.2 / (1 - 0.01) = 0.2 / 0.99 = 216/990.
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