A cube has a volume of 200cm3. What is the length of one edge?
Give your answer in cm correct to one decimal place

Answer:

Step-by-step explanation:

(for the first question)

1/2 gallons cover 1/6th of the wall then

1-gallon covers 1/3rd of the wall

so 3 gallons cover one wall

(second question)

you have to calculate 85% of $35 because it is 15% percent off.

35*0.85=29.75

The sale price is $29.75.

(third question)

6*3=18

14.4*100/18

1440/18

80

100-80 = 20

The answer is A (20%)

Answer:

3 gallons of paint

$29.75

20%

Step-by-step explanation:

1. Let's break this down:

1/2 gallon of paint covers 1/6 of his wall.

This means that we have to multiply 1/2 by 6, as there would be 6 1/2 gallon sections of his wall.

1/2·6=3

So, Jamel needs 3 gallons of paint.

2. If a pair of shoes has an original price of $35 but it on sale for 15%, we have to first find how much it's now on sale for:

15/100·35

=0.15·35

=5.25

This is the how much it's off, so subtract 5.25 from 35

35-5.25=$29.75

The shoes have a sale price of $29.75

Even though you said this was wrong, you may have to put a dollar sign in front of it.

3. This is worded a little, but assuming:

1 swimming pass is $6, 3 people buy the swimming pass, and the total cost for the 3 passes in total is $14.40, we have to find out the discount.

So, originally, before the discount, the total amount for the 3 swimming passes would've been $18, but there's been a discount and now they only had to pay $14.40.

To solve, we do the following:

subtract the original price by the sale price

18-14.40=3.6

divide by the original price

3.6/18=0.2

multiply by 100 to get into percent

0.2x100=20%

This means that A is the correct choice.

Hope this helps! :)

Answer:

Step-by-step explanation:

12,787

a. ^p^ represents the proportion of adults who chose chocolate pie, ^q^ represents the proportion of adults who did not choose chocolate pie, n represents the sample size, E represents the margin of error, and p represents the population proportion.

b. The value of α for a 99.99% confidence level is 0.0001.

a. ^p^ represents the sample proportion of adults who chose chocolate pie, ^q^ represents the proportion of adults who did not choose chocolate pie (1 - ^p^), n represents the sample size of 1500, E represents the margin of error of ±3 percentage points (0.03), and p represents the population proportion of adults who choose chocolate pie.

b. To find the value of α for a 99.99% confidence level, we need to subtract the confidence level from 100% to get the level of significance, which is 0.0001. This means that there is a 0.0001 probability of rejecting the null hypothesis when it is actually true.

The level of significance (α) is used to determine the critical value for the test statistic, which is then used to determine whether or not to reject the null hypothesis.

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To find the elasticity of demand for the function q = D(x) = 460 - x, we can use the formula:

Elasticity = (% change in quantity demanded) / (% change in price)

a) Since the demand function given does not include a price variable, we can assume that price is constant. Therefore, the elasticity of demand for this function is constant and equal to -1.

b) To find the elasticity at x = 103, we need to calculate the percentage change in quantity demanded when x increases from 103 to 104.

At x = 103, quantity demanded is q = D(103) = 460 - 103 = 357.

At x = 104, quantity demanded is q = D(104) = 460 - 104 = 356.

The percentage change in quantity demanded is:

(% change in quantity demanded) = [(new quantity - old quantity) / old quantity] x 100

= [(356 - 357) / 357] x 100 = -0.28%

Since the elasticity of demand is -1, we can say that demand is inelastic at x = 103.

c) To find the elasticity at x = 205, we need to calculate the percentage change in quantity demanded when x increases from 205 to 206.

At x = 205, quantity demanded is q = D(205) = 460 - 205 = 255.

At x = 206, quantity demanded is q = D(206) = 460 - 206 = 254.

The percentage change in quantity demanded is:

(% change in quantity demanded) = [(new quantity - old quantity) / old quantity] x 100

= [(254 - 255) / 255] x 100 = -0.39%

Since the elasticity of demand is -1, we can say that demand is inelastic at x = 205.
Hi! I'd be happy to help you with your question on elasticity of demand.

a) To find the elasticity, we first need the formula for price elasticity of demand (PED), which is:

PED = (% change in quantity demanded) / (% change in price)

Here, we have the demand function D(x) = 460 - x, where x is the price.

b) To find the elasticity at x = 103, we first need to calculate the quantity demanded, which is:

q = D(103) = 460 - 103 = 357

Now, we'll find the derivative of the demand function with respect to price:

dq/dx = -1

Next, we'll use the formula for PED:

PED = (dq/dx * x) / q = (-1 * 103) / 357 = -103/357 ≈ -0.289

Since the absolute value of PED is less than 1, demand is inelastic at x = 103.

c) To find the elasticity at x = 205, we'll follow the same steps:

q = D(205) = 460 - 205 = 255

PED = (dq/dx * x) / q = (-1 * 205) / 255 ≈ -0.804

Again, the absolute value of PED is less than 1, so demand is inelastic at x = 205.

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Therefore, 32 1/2 can be written as a radical form of 32 + √2.

In mathematics, a fraction is a numerical quantity that represents a part of a whole or a ratio between two numbers. Fractions are written in the form of one integer, called the numerator, written above a line, and another integer, called the denominator, written below the line. The denominator represents the total number of equal parts into which a whole is divided, while the numerator represents the number of those parts being considered.

Here,

We can write 32 1/2 as a mixed number, which is equivalent to the fraction 65/2. To express 65/2 as a radical form, we can simplify the fraction by finding a perfect square that divides evenly into both the numerator and the denominator. In this case, 4 is a perfect square that divides into 64 (the nearest perfect square to 65) and 2, so we can write:

65/2 = (64 + 1)/2

= 64/2 + 1/2

= 32 + 1/2

Now, we can express the fraction 1/2 as a radical by taking the square root of the denominator, which gives:

32 1/2 = 32 + √2

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Sydney can row a canoe at a speed of 5 mph in still water.

Let x represent Sydney's speed in still water. When rowing upriver, her effective speed will be (x - 2) mph because she's going against the current, which flows at 2 mph. When rowing downriver, her effective speed will be (x + 2) mph, since she's going with the current.

According to the problem, the time it takes her to row 6 miles upriver is the same as the time it takes her to row 14 miles downriver. We can set up the equation using the formula time = distance / speed:

6 / (x - 2) = 14 / (x + 2)

To solve for x, first cross-multiply:

6(x + 2) = 14(x - 2)

Expand:

6x + 12 = 14x - 28

Now, rearrange and solve for x:

12 + 28 = 14x - 6x

40 = 8x

x = 5

So, Sydney can row a canoe at a speed of 5 mph in still water.

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the restaurant used 754,040 ounces of cream last year.

What is an Equations?

Equations are statements in mathematics that consist of two algebraic expressions separated by an equals (=) sign, indicating the equivalence between the expressions on either side. Equations can be solved to determine the value of a variable that represents an unknown quantity. A statement that does not have an "equal to" symbol is not considered an equation and is instead referred to as an expression.

If the restaurant used 50% less cream this year compared to last year, then it means that this year's usage is 50% of last year's usage.

Let x be the amount of cream used last year.

Then we can set up the following equation:

x * 50% = 377,020

To solve for x, we need to isolate it on one side of the equation.

x * 50% = 377,020

x = 377,020 / 50%

To convert 50% to a decimal, we divide it by 100:

x = 377,020 / 0.5

x = 754,040

Therefore, the restaurant used 754,040 ounces of cream last year.

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To determine how many times a day we would need to fill the container shown below, we need to calculate its capacity in cubic centimeters. Let's assume that the container is a rectangular prism with dimensions of 30 centimeters (length) x 20 centimeters (width) x 25 centimeters (height). The formula for calculating the volume of a rectangular prism is:

Volume = length x width x height

Plugging in the values we have, we get:

Volume = 30 cm x 20 cm x 25 cm

Volume = 15,000 cubic centimeters

Therefore, the container has a capacity of 15,000 cubic centimeters. To determine how many times we would need to fill it each day, we need to divide the amount of pellets and hay we feed the okapi daily (5,024 cubic centimeters) by the capacity of the container (15,000 cubic centimeters):

5,024 / 15,000 = 0.3356

This means that we would need to fill the container approximately 0.3356 times a day, which is not a practical answer. We need to round this up to the nearest whole number.

The options given to us are 80 times, 40 times, 16 times, and 4 times. Out of these options, the closest whole number to 0.3356 is 1, which means we would need to fill the container once a day.

Therefore, the answer is that we would need to fill the container shown below 1 time a day to feed the okapi their daily amount of pellets and hay.

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The fraction representing Juan's age relative to Julia's age is -1/10. This means that Juan's age is one-tenth less than Julia's age.

Let's start by translating the given statement into an equation:

[tex]2/3J = 3/5 - 2/3Jl[/tex]

where J is Juan's age and Jl is Julia's age.

Now we can simplify this equation by first multiplying both sides by 15 (the least common multiple of 3 and 5) to get rid of the denominators:

[tex]10J = 9 - 10Jl[/tex]

Next, we can isolate J on one side of the equation by adding 10Jl to both sides:

[tex]10J + 10Jl = 9[/tex]

Finally, we can factor out a 10 from the left-hand side:

[tex]10(J + Jl) = 9[/tex]

Dividing both sides by 10, we get:

[tex]J + Jl = 9/10[/tex]

Now we can express Juan's age as a fraction of Julia's age by dividing both sides of this equation by Jl:

[tex]Jl/Jl + J/Jl = 9/10Jl[/tex]

Simplifying this, we get:

1 + J/Jl = 9/10

Subtracting 1 from both sides, we get:

[tex]J/Jl = 9/10 - 1[/tex]

[tex]J/Jl = -1/10[/tex]

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If the circumference of a circle is 50. 4 ft, its area is 202.24 sq ft. Correct  option is C: 202.24 sq ft.

The formula for the circumference of a circle is C = 2πr, where r is the radius of the circle. We are given that the circumference is 50.4 ft, so we can solve for the radius:

50.4 = 2πr

r = 50.4 / (2π)

r ≈ 8.02 ft

Now we can use the formula for the area of a circle: A = πr²

A = 3.14 * (8.02)²

A ≈ 202.24 sq ft

Therefore, the answer is option C: 202.24 sq ft.

Alternatively, to find the area of a circle with a circumference of 50.4 ft, we will first find the radius using the formula for circumference (C = 2πr) and then use the formula for the area of a circle (A = πr²). Using π = 3.14:

Solve for the radius (r):
C = 2πr
50.4 = 2(3.14)r
r = 50.4 / (2 * 3.14)
r ≈ 8 ft

Calculate the area (A):
A = πr²
A = 3.14 * (8²)
A = 3.14 * 64
A ≈ 201.06 sq ft

The closest answer among the options provided is 202.24 sq ft. Correct  option is C: 202.24 sq ft.

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The mass of the copper wire is approximately 131.77 lb.

To find the mass of the copper wire, we will first need to calculate its mass per unit length using the given density function[tex]p(t) = 5x^2 + 4x lb/ft,[/tex] and then integrate the function over the length of the wire.
Write down the given density function: [tex]p(t) = 5x^2 + 4x lb/ft[/tex]
2. Write down the limits of integration, which correspond to the length of the wire:

a = 0, b = 3.75 feett.

Set up the integral to find the mass of the wire:

Mass = ∫[p(t) dt] from a to b.

Plug in the density function and limits:

Mass = ∫[tex][5x^2 + 4x dx][/tex]from 0 to 3.75
Integrate the function: Mass = (5/3)x^3 + 2x^2 | from 0 to 3.75
Substitute the upper limit and then subtract the result of the lower limit:
  Mass =[tex][(5/3)(3.75)^3 + 2(3.75)^2] - [(5/3)(0)^3 + 2(0)^2][/tex]
Perform the calculations and round to two decimal places:
  Mass ≈ 131.77 lb.

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The value of the volume of the cylinder is  706. 5 cm³

The formula for the volume of a cylinder is expressed as;

V = πr²h

Such that the parameters are;

Now, substitute the values into the formula, we get;

Volume, V = 3.14 × 5² × 9

Find the square value and substitute

Volume, V = 3.14 × 25 × 9

Multiply the values

volume, V = 706. 5 cm³

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You can look the image.

It is very clear.

Answer:

[tex]\sin (Z)=\sf\dfrac{9}{15}[/tex]        [tex]\cos (Z)=\sf\dfrac{12}{15}[/tex]        [tex]\tan(Z)=\sf \dfrac{9}{12}[/tex]

Step-by-step explanation:

To create trigonometric ratios for angle Z in the given right triangle XYZ, we can use the trigonometric ratios.

[tex]\boxed{\begin{minipage}{9.4 cm}\underline{Trigonometric ratios} \\\\$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$\\\\where:\\ \phantom{ww}$\bullet$ $\theta$ is the angle. \\ \phantom{ww}$\bullet$ $\sf O$ is the side opposite the angle. \\\phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle. \\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse (the side opposite the right angle). \\\end{minipage}}[/tex]

From inspection of the right triangle XYZ:

Substitute these values into the three ratios to create the trigonometric ratios for angle Z:

[tex]\sin (Z)=\sf \dfrac{O}{H}=\dfrac{9}{15}[/tex]

[tex]\cos (Z)=\sf \dfrac{A}{H}=\dfrac{12}{15}[/tex]

[tex]\tan(Z)=\sf \dfrac{O}{A}=\dfrac{9}{12}[/tex]

(a) The greatest amount of snowfall in any of the cities = 50 inches.

(b) The data is most concentrated in the second quarter (Q₂), ranging from 6 inches to 20 inches.

(c) The data is most spread out in the fourth quarter (Q₄), ranging from 32 inches to 50 inches.

A box plot is a type of graphical representation that summarizes the distribution of a dataset based on the five-number summary: the minimum value, the first quartile (Q1), the median, the third quartile (Q3), and the maximum value.

A box plot consists of a rectangular box, which spans from Q1 to Q3, with a vertical line inside it representing the median. The length of the box represents the interquartile range (IQR), which is the range between Q1 and Q3.

Whiskers, which are lines extending from the top and bottom of the box, indicate the range of the dataset outside of the IQR.  

Here we have

Jyllina created this box plot representing the number of inches of snow that fell this winter in different nearby cities

The data ranges from 4 to 50 inches

4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50

(a) The greatest amount of snowfall in any of the cities will equal the highest value which is 50 inches.

(b) The data is most concentrated in the second quarter (Q₂), which ranges from 6 inches to 20 inches.

This can be inferred from the fact that the box plot shows the smallest range between the minimum and maximum values, as well as the smallest size of the box, which represents the interquartile range (IQR).

(c) The data is most spread out in the fourth quarter (Q₄), which ranges from 32 inches to 50 inches.

This can be inferred from the fact that the box plot shows the largest range between the minimum and maximum values, as well as the largest size of the box, which represents the IQR.

Additionally, the whiskers, which represent the range of values outside the IQR, are also the longest in this quarter, indicating that there are more extreme values in this range compared to the other quarters.

Therefore,

(a) The greatest amount of snowfall in any of the cities = 50 inches.

(b) The data is most concentrated in the second quarter (Q₂), ranging from 6 inches to 20 inches.

(c) The data is most spread out in the fourth quarter (Q₄), ranging from 32 inches to 50 inches.

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Complete Question:

One way Olivia might have achieved this is by performing a translation followed by a rotation.

One way Olivia might have achieved the transformation of ABCD onto A" B" C" D" is by performing a translation followed by a rotation. Here's a possible approach:

By combining these two transformations, Olivia could have successfully moved ABCD onto A" B" C" D" and achieved the desired configuration. It's important to note that there could be other valid combinations of transformations as well.

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A linear function would be the  best fit for the data.

A function that would be the best for this data is: D. y = -4/25(x) + 10

The amount of snow that would be on the ground when the temperature reaches 55° is 1.2 inches.

In this scenario, the temperature would be plotted on the x-axis (x-coordinate) of the scatter plot while the snow (inches) would be plotted on the y-axis (y-coordinate) of the scatter plot through the use of Microsoft Excel.

On the Microsoft Excel worksheet, you should right click on any data point on the scatter plot, select format trend line, and then tick the box to display an equation for the line of best fit (trend line) on the scatter plot.

From the scatter plot (see attachment) which models the relationship between the temperature and the snow (inches), an equation for the line of best fit is given by:

y = -0.16x + 10

y = -4/25(x) + 10

When x = 55, the amount of snow is given by;

y = -4/25(55) + 10

y = 1.2 inches.

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Answer:

The total amount Joe spent on gasoline and oil can be determined by the expression: 2.85g + 3.15c. This expression represents the cost of g gallons of gasoline at $2.85 per gallon plus the cost of c cans of oil at $3.15 per can.

Step-by-step explanation:

The critical point x = 0 does not yield a local minimum or maximum. The function is always decreasing.

To find the critical points and intervals for the function y = x^3 / (x^2 + 1), we'll first find the derivative using the Quotient Rule:

y'(x) = [(x^2 + 1)(3x^2) - x^3(2x)] / (x^2 + 1)^2

y'(x) = (3x^4 + 3x^2 - 2x^4) / (x^2 + 1)^2

y'(x) = (x^2 - 2x^2) / (x^2 + 1)^2

Now, we'll find the critical points by setting the derivative equal to zero:

0 = (x^2 - 2x^2) / (x^2 + 1)^2

0 = x^2(1 - 2) / (x^2 + 1)^2

0 = -x^2 / (x^2 + 1)^2

This equation is equal to zero only when x = 0. So, the critical point is x = 0.

Next, we'll use the First Derivative Test to determine if the critical point yields a local min or max. To do this, we'll evaluate the sign of y'(x) to the left and right of x = 0.

1. Left of x = 0 (for example, x = -1):
y'(-1) = (-1)^2(1 - 2) / (-1^2 + 1)^2 = -1 / 1^2 = -1 (negative)

2. Right of x = 0 (for example, x = 1):
y'(1) = (1)^2(1 - 2) / (1^2 + 1)^2 = -1 / 2^2 = -1/4 (negative)

Since the derivative is negative on both sides of the critical point, the function is decreasing for all x. Thus, the critical point x = 0 does not yield a local minimum or maximum. The function is always decreasing.

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To solve this problem, we can use substitution. Let u = 9z - 5, then du/dz = 9 and dz = du/9.

Using this substitution, we can rewrite the integral as:

∫(2/(u+5))(1/9)du

Simplifying this expression:

(2/9) ∫(1/(u+5))du

We can then solve this integral by using the formula for the natural logarithm:

(2/9) ln|u+5| + C

Substituting back in for u:

(2/9) ln|9z| + C
2 zV9z+ - 5 dz is (2/9) ln|9z| + C.


Consider the integral:
∫2z√(9z² - 5) dz

We can use the substitution method. Let's choose the substitution:
u = 9z² - 5

Now, differentiate u with respect to z:
du/dz = 18z

Solve for dz:
dz = du/(18z)

Now, substitute u and dz back into the integral and simplify:
∫(2z√u) * (du/(18z)) = (1/9)∫√u du

Now, integrate with respect to u:
(1/9)(2/3)(u^(3/2))/(3/2) + C = (2/27)u^(3/2) + C

Finally, substitute back the original expression for u:
(2/27)(9z² - 5)^(3/2) + C

So, the indefinite integral is:
(2/27)(9z² - 5)^(3/2) + C

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The total cubic centimeters of space the tissue box requires is 500 cubic centimeters, under the condition that the box is half full.

The volume of a cube is evaluated by multiplying its length by its width by its height. If all sides of a cube are equal,

we can use the formula

V = s³

here

s = length of one side of the cube.

If we let s be the length of one side of the cube and V be its volume,

V = s³

If we know that the tissue box is half full, then let us consider that half of its volume is occupied by tissues. Then

V' = 0.5 × V

Staging V = s³ in the equation

V' = 0.5 × s³

s = 10 cm (given)

V' = 0.5 × 1000 = 500 cubic centimeters

Hence, if Patrick's tissue box has a volume of 1000 cubic centimeters and it is half full, then the tissues occupy 500 cubic centimeters of space.

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The complete question is

Patrick buys a tissue box in the shape of a cube of side 10 centimeters. How many cubic centimeters of space do the tissues occupy if the box is half full? Show all work

The drive-thru is able to estimate their wait time more consistently will be A. Burger Quick, because it has a smaller IQR.

The interquartile range (IQR) is a measure of variability that represents the range of values in the middle 50% of scores in a distribution. It is used when the data is skewed and the median is a better measure of central tendency than the mean.

In this scenario, Burger Quick has an IQR of 14.5, while Fast Chicken has an IQR of 4.5.

The IQR is calculated by subtracting the first quartile (Q1) from the third quartile (Q3).

For Burger Quick, Q1 is 9.5 and Q3 is 24, so the IQR is 24 - 9.5 = 14.5. For

Fast Chicken, Q1 is 10 and Q3 is 14.5, so the IQR is 14.5 - 10 = 4.5.

Therefore, Burger Quick has a larger IQR than Fast Chicken, indicating that its data is more consistent and less spread out. This means that Burger Quick is better able to estimate its wait time consistently.

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---------------------------

|           | Popcorn | No Popcorn |

---------------------------

| Drink     |    74   |     15     |

---------------------------

| No Drink  |    10   |     6      |

---------------------------

The completed two-way table is as shown above.

We construct a two-way table summarizing the results. Let's use the information provided:

1. 105 people entered the theatre
2. 84 people had popcorn
3. 10 out of 84 people with popcorn did not have a drink
4. 6 people walked in without popcorn or a drink

Now let's construct the two-way table:

---------------------------
|           | Popcorn | No Popcorn |
---------------------------
| Drink     |    A    |     B      |
---------------------------
| No Drink  |    C    |     D      |
---------------------------

We need to fill in the values for A, B, C, and D:

1. A = People with popcorn and a drink = Total with popcorn - those without a drink = 84 - 10 = 74
2. C = People with popcorn but no drink = 10 (given in the question)
3. D = People with neither popcorn nor a drink = 6 (given in the question)
4. To find B, we need to find the total number of people with a drink. We know 105 people entered, and 6 had neither popcorn nor a drink, so there were 105 - 6 = 99 people with either popcorn or a drink. Since 84 people had popcorn, this means there were 99 - 84 = 15 people with only a drink.
5. B = People with a drink but no popcorn = 15

Now let's fill in the table:

---------------------------
|           | Popcorn | No Popcorn |
---------------------------
| Drink     |    74   |     15     |
---------------------------
| No Drink  |    10   |     6      |
---------------------------

So, the completed two-way table is as shown above.

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At point (-43,0), f has a maximum. At point (0,4), f has a minimum. At point (463,0), f has a maximum. At point (0,0), f may have a critical point. none of the given points are critical points of the function f (x, y) = xy + 33 - 48y.

Hi! To analyze the critical points of the function f(x, y) = xy + 33 - 48y, we first need to find the partial derivatives with respect to x and y:

fx = ∂f/∂x = y
fy = ∂f/∂y = x - 48

Now, we can analyze the given points:

1. (-43, 0)
At this point, fx = 0 and fy = -48. Since both partial derivatives are not equal to 0, this point is not a critical point.

2. (0, 4)
At this point, fx = 4 and fy = 0. Again, both partial derivatives are not equal to 0, so this is not a critical point.

3. (463, 0)
At this point, fx = 0 and fy = 463 - 48 = 415. Since both partial derivatives are not equal to 0, this is not a critical point.

4. (0, 0)
At this point, fx = 0 and fy = -48. Since both partial derivatives are not equal to 0, this is not a critical point.

5. (0, -4)
At this point, fx = -4 and fy = -48. Again, both partial derivatives are not equal to 0, so this is not a critical point.

In summary, none of the given points are critical points of the function f(x, y) = xy + 33 - 48y.

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Answer:

$10.8

Step-by-step explanation:

We know that 3 books are $2.70, so 1 book is 2.70/3 which is $0.9

1 dozen = 12

To find the price of 12 books, we multiply by the cost of 1 book

12 * 0.9 = $10.8

Answer:

(0,5.8)

Step-by-step explanation:

The vertex is the highest or lowest point on the parabola, the line of symmetry is a vertical line passing through the vertex and dividing the parabola into two equal halves, and the number of x-intercepts depends on the discriminant of the quadratic equation.

The vertex is a point on a parabola where the curve changes direction. It is the highest or lowest point on the curve, depending on whether it opens up or down. The vertex is represented as (h, k), where h is the x-coordinate and k is the y-coordinate.

The line of symmetry is a vertical line that divides the parabola into two equal halves. It passes through the vertex and is equidistant from the two arms of the parabola. The equation of the line of symmetry is x = h.

The number of x-intercepts is determined by the equation of the parabola. If the discriminant of the quadratic equation is positive, then the parabola intersects the x-axis at two distinct points, and there are two x-intercepts. If the discriminant is zero, then the parabola touches the x-axis at one point, and there is one x-intercept. If the discriminant is negative, then the parabola does not intersect the x-axis, and there are no x-intercepts.

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The sum is equal to 18600.

Let's first simplify the expression inside the brackets:

(i^2 - 21 + 1) - 4 = i^2 - 24

Now we can write the sum using sigma notation:

15 Σ (i^2 - 24), i=1

Using the summation formulas of the first n squares, we have:

Σ i^2 = n(n+1)(2n+1)/6

So, substituting n = 1 to 15, we get:

15 Σ i^2 = 15 Σ n(n+1)(2n+1)/6

Now, let's use the formula for the sum of the first n integers:

Σ i = n(n+1)/2

Substituting n = 1 to 15, we get:

Σ i = 1 + 2 + ... + 15 = 15(15+1)/2 = 120

Substituting these formulas into our original expression, we have:

15 Σ (i^2 - 24), i=1

= 15 [Σ i^2 - 24Σ i], i=1

= 15 [15(15+1)(2(15)+1)/6 - 24(120)]

= 15 [1240]

= 18600

Therefore, the sum of 15 (i^2 - 24) from i = 1 to 15 is equal to 18600.

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According to the given condition the two-digit number is 66.

To find the two-digit number that is 11 times its units digit and has a sum of digits equal to 12, we can use the following steps:

1. Let's represent the two-digit number as XY, where X is the tens digit and Y is the units digit.
2. The number is 11 times its units digit, so we can write the equation: 10X + Y = 11Y.
3. The sum of the digits is 12, which means X + Y = 12.
4. Now, we have two equations with two variables:
   - 10X + Y = 11Y
   - X + Y = 12
5. We can solve for X from the second equation: X = 12 - Y.
6. Substitute the value of X in the first equation: 10(12 - Y) + Y = 11Y.
7. Simplify and solve for Y: 120 - 10Y + Y = 11Y.
8. Combine the Y terms: 120 - 9Y = 11Y.
9. Move all the Y terms to one side: 120 = 20Y.
10. Divide by 20 to get Y: Y = 6.
11. Now, substitute the value of Y back into the X equation: X = 12 - 6.
12. Solve for X: X = 6.

So, the two-digit number is 66.

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The ordered pair that describes the location of E'' is (6, -1).

The initial location of Point EE is (-6, 1). To reflect Point EE over the yy-axis, we will change the sign of the x-coordinate while keeping the y-coordinate the same.

Step 1: Reflect Point EE over the yy-axis to create Point E'.
E' = (6, 1)

Next, to reflect Point E' over the xx-axis, you'll change the sign of the y-coordinate while keeping the x-coordinate the same.

Step 2: Reflect Point E' over the xx-axis to create Point E''.
E'' = (6, -1)

Therefore, the ordered pair that describes the location of E'' is (6, -1).

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