A cyclist rides her bike at a rate of 10 kilometers per hour what is this rate in miles per hour? How many miles will the cyclist travel in 3 hours? In your computations, assume that 1 mile is equal to 1.6 kilometers l. Do not round your answers

The expression to represents the perimeter is,

54 = 2 (2k + k)

And, The width of the rectangle is, 9 units.

A rectangle is a two dimension figure with 4 sides, 4 corners and 4 right angles. The opposite sides of the rectangle are equal and parallel to each other.

Given that;

The perimeter of a rectangle is equal to 54 units.

And, The length of the rectangle is 2k units, and the width of the rectangle is k units.

Now, We know that;

Perimeter of rectangle = 2 (Length + Width)

Substitute the given values, we get;

Perimeter of rectangle = 2 (Length + Width)

54 = 2 (2k + k)

54 = 2 × 3k

54 = 6k

54/6 = k

k = 9

Hence, The width of the rectangle is, 9 units.

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Answer:

20 pesos lang

Step-by-step explanation:

kami 5 pesos per ticket kayo 12 dollar

Answer:

-4m-3

Step-by-step explanation:

Step-by-step explanation:

→ -0.25(16m+12)

→ (-0.25×16m)+(-0.25×12)

→ (-4m)+(-3)

→ -4m-3. Answer

(a) 305 (?)

(b) Fields, monroe

(c) Treevale

Answer:

27

Step-by-step explanation:

start with {5*(13-8)+12/6}

simplify to get:

(5*5)+12/6

simplify to get:

25+12/6

simplify to get:

25+2

simplify to get your answer:

27

Answer:

500, 300

Step-by-step explanation:

Assuming the rounding is for nearest 100,

635-124

600-100

500

864-612

900-600

300

answer is the option 0.1

Answer:

0.1

Step-by-step explanation:

By looking at numbers after the decimal point, the largest number comes the soonest. Looking at our options here, 0.1 would be the largest since it is the closest to 1, whereas 0.00005 is the smallest because it is very far from 1.

Answer:

3000000cm³

Step-by-step explanation:

150cm x 100cm x 200cm = 3000000cm³

Answer:

4 units i think

Step-by-step explanation:

i dont know how beacuse 4 is answer

Answer:

sorry I don't remember bye I will try to remember

Answer:

7 3/5 is the correct answer

Answer: A

Step-by-step explanation:

A is not a function because in order to be a function. It has to pass the vertical line test. based on the graph, it doesn't pass the test. You can search up the graph on desmos.

Answer:

Yes.

Step-by-step explanation:

Yes.

Assuming a, b and c are integers (not = 0)

a/b + b/c

= (ac + b^2) / bc   which is a rational number.

Answer:c?

Step-by-step explanation: i think?

Answer:1 mile traveled at the rate of 200 miles in 60 minutes. ... Therefore, it would take 18 seconds to travel 1 mile going at a speed of 200 miles per hour!

Step-by-step explanation:

Answer:

$101.45

Step-by-step explanation:

change 17% to .17 then multiply it by 86.71=14.74 then add that to 86.71 and you get your answer $101.45

Answer:

(b) 729

Step-by-step explanation:

9 × 9 × 9 = 9^3 = 729

Thus, 9 is the cube root of 729

Answer:

The first numbers in the sets are input and the second numbers are outputs.

1. {(1, 1), (2, 3), (3,5)}

2. {(6,2), (5, 3), (4,8)}​

Answer:

x = 68°, y=14

Step-by-step explanation:

∵ m║n

∴ m∠x = 180 - m∠112

m∠x = 68°

∵ ∠x and ∠(5y - 2) are vertically oppose

∴ m∠(5y - 2) = m∠x

m∠(5y - 2) = 68

Make equation

5y - 2 = 68

5y = 68 + 2

5y = 70

y = 70/5

y = 14

Hope this helps

Step-by-step explanation:

• The supplement of the angle with the measure of 112° is :

[tex]\bf x + 112 = 180 \\ \bf x = 180 - 112 \\ \bf \boxed{ \color{#FF0000}x = 68 }[/tex]

This angle of 68° and the angle sign x° are in angular positions.

Internal alternators

The lines m and n are parallel, these angles have the same measure.

The marking of the angle x and the marking of the angle (5y-2)° are opposite to the vertex.

They have the same measure:

[tex]\bf 5y - 2 = 68 \\ \bf 5y = 68 + 2 \\ \bf 5y = 70 \\ \bf y = 70 \div 5 \\ \bf \boxed{ \color{#FF0000}y = 14 }[/tex]

Step-by-step explanation:

5⁴+5³-6(5)²-5(5)-15

= 560

Answer:

D) 6.48 x 10⁻³

Step-by-step explanation:

to get an exponent of -3 means you move the decimal point three spaces to the right

2) 8,300,000

3) 970,000

4) 5.01 x 10⁻²  (picture)         5.01 x 10⁻¹ (question)

5) 0.000499

9514 1404 393

Answer:

 no; the yardage should be more than 0.75 yards

Step-by-step explanation:

A value that is 15% more than 0.75 will be a number that is greater than 0.75. The number 0.1125 is much less than 0.75, so cannot be the correct amount of fabric.

Chloe did not cut the correct amount.

(the correct amount is 0.8625 yards)

_____

Additional comment

Often, all that is needed for answering a multiple choice question properly is ...

  a) an understanding of what the question is asking

  b) comprehension of what the answer must look like.

Here, the directions are saying to cut more than 0.75 yards. The result will be a value that is more than 0.75 (and less than 1).

The value 0.1125 yard is 15% of 0.75 yard. The cut amount should be that much in addition to 0.75 yard: 0.75 +0.1125 = 0.8625 yard.

Step-by-step explanation:

Slope:(II)m= -2

y-1=-2(x+4)

y-1=-2x+8

+1. +1

Answer: y=-2x+9

Answer:

always the same

Step-by-step explanation:

Step-by-step explanation:

Given Question

Complete the following tables and plot the points on the graph paper yo represents the equations given below :-

[tex]\begin{gathered}\boxed{\begin{array}{c|c|c|c} \bf x & \bf 1 & \bf 2& \bf 3\\ \frac{\qquad}{} & \frac{\qquad}{}\frac{\qquad}{} &\frac{\qquad}{} & \frac{\qquad}{} &\\ \sf y = x + 1 & \sf & \sf & \sf \\ \\ \sf (x,y)& \sf & \sf & \sf \\ \end{array}} \\ \end{gathered} \\ [/tex]

and

[tex]\begin{gathered}\boxed{\begin{array}{c|c|c|c} \bf x & \bf 1 & \bf 2& \bf 3\\ \frac{\qquad}{} & \frac{\qquad}{}\frac{\qquad}{} &\frac{\qquad}{} & \frac{\qquad}{} &\\ \sf y = - 3x & \sf & \sf & \sf \\ \\ \sf (x,y)& \sf & \sf & \sf \\ \end{array}} \\ \end{gathered} \\ [/tex]

[tex]\large\underline{\sf{Solution-}}[/tex]

Given that,

[tex]\rm \longmapsto\:y = x + 1[/tex]

On substituting x = 1, we get

[tex]\rm \longmapsto\:y = 1 + 1[/tex]

[tex]\rm \longmapsto\:y = 2[/tex]

On substituting x = 2, we get

[tex]\rm \longmapsto\:y = 2 + 1[/tex]

[tex]\rm \longmapsto\:y = 3[/tex]

On substituting x = 3, we get

[tex]\rm \longmapsto\:y = 3 + 1[/tex]

[tex]\rm \longmapsto\:y = 4[/tex]

Hence,

[tex]\begin{gathered}\boxed{\begin{array}{c|c|c|c} \bf x & \bf 1 & \bf 2& \bf 3\\ \frac{\qquad}{} & \frac{\qquad}{}\frac{\qquad}{} &\frac{\qquad}{} & \frac{\qquad}{} &\\ \sf y = x + 1 & \sf 2 & \sf 3 & \sf 4\\ \\ \sf (x,y)& \sf (1,2) & \sf (2,3) & \sf (3,4)\\ \end{array}} \\ \end{gathered}[/tex]

Now, draw a graph using the points (1 , 2), (2 , 3) & (3 , 4)

---------------------------------------------

Given equation is

[tex]\rm \longmapsto\:y = - 3x[/tex]

On substituting x = 1, we get

[tex]\rm \longmapsto\:y = - 3 \times 1[/tex]

[tex]\rm \longmapsto\:y = - 3[/tex]

On substituting x = 2, we get

[tex]\rm \longmapsto\:y = - 3 \times 2[/tex]

[tex]\rm \longmapsto\:y = - 6[/tex]

On substituting x = 3, we get

[tex]\rm \longmapsto\:y = - 3 \times 3[/tex]

[tex]\rm \longmapsto\:y = - 9[/tex]

Hence,

[tex]\begin{gathered}\boxed{\begin{array}{c|c|c|c} \bf x & \bf 1 & \bf 2& \bf 3\\ \frac{\qquad}{} & \frac{\qquad}{}\frac{\qquad}{} &\frac{\qquad}{} & \frac{\qquad}{} &\\ \sf y = - 3x & \sf - 3 & \sf - 6 & \sf - 9\\ \\ \sf (x,y)& \sf (1, - 3) & \sf (2, - 6) & \sf (3, - 9)\\ \end{array}} \\ \end{gathered}[/tex]

Now, draw a graph using the points (1 , - 3), (2 , - 6) & (3 , - 9)

are you sloving the x? or what are you sloving

We want to find the work done by lifting a book a given distance.

The answer is 200 N*m

We know that the book weighs 100 Newtons and that we lift it a distance of 2 meters.

Remember that the work needed to lift an object of mass M to a height H is:

W = M*g*H

where g is the gravitational acceleration.

Knowing that:

weight = M*g

We can replace the things we know to get the work:

W = 100N*2m = 200 N*m

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