The approximate surface area of the glass prism is approximately 1986.66 square millimeters.
To find the surface area of the glass prism, we need to determine the area of each of its faces and then add them together. The prism consists of two congruent equilateral triangles and three rectangular faces.
The area of an equilateral triangle with side length s and height h is given by:
A = (√(3)/4) * s²
Using this formula, we can find the area of each of the two equilateral triangles in the prism:
A = (√(3)/4) * 7² ≈ 21.22 mm²
Next, we need to find the area of each of the three rectangular faces. The length of each rectangular face is equal to the side length of the equilateral triangle (7 mm), and the height is equal to the length of the prism (93 mm). Therefore, the area of each rectangular face is:
A = length x height = 7 mm x 93 mm = 651 mm²
To find the total surface area of the prism, we add the areas of the two equilateral triangles and the three rectangular faces:
Total surface area ≈ 2 x 21.22 mm² + 3 x 651 mm² ≈ 1986.66 mm²
Therefore, the approximate surface area of the glass prism is approximately 1986.66 square millimeters.
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Each expression represents an objectâs distance from the ground in meters as a function of time, t, in seconds.
Object A: â5t2+25t+50
Object B: â5t2+50t+25
a. Which object was launched with the greatest vertical speed?
b. Which object was launched from the greatest height?
please help
Object B was launched with the greatest vertical speed and Object A was launched from the greatest height of 50 meters.
a. The vertical speed of an object launched can be calculated using the derivative of the distance function with respect to time. Taking the derivative of the distance function of Object A with respect to time, we get:
v(t) = -10t + 25
Taking the derivative of the distance function of Object B with respect to time, we get:
v(t) = -10t + 50
Comparing the two velocity functions, we can see that Object B was launched with the greatest vertical speed because its velocity function has a higher initial velocity (50 m/s) than that of Object A (25 m/s).
b. The initial height of an object launched can be determined by finding the value of its distance function when t=0.
For Object A, the distance function when t=0 is:
-5(0)^2 + 25(0) + 50 = 50 meters
For Object B, the distance function when t=0 is:
-5(0)^2 + 50(0) + 25 = 25 meters
Therefore, Object A was launched from the greatest height of 50 meters.
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Determine if the expression zx^3/9-x^3 is a polynomial or not. if it is a polynomial, state the type and degree of the polynomial.
This expression is not a polynomial, and it doesn't have a type or degree.
The expression zx^3/9-x^3 can be simplified as:
zx^3/(9-x^3)
This expression is not a polynomial because it contains a variable (x) in the denominator, which makes it a rational expression.
A polynomial is an expression of one or more terms involving only constants and variables raised to positive integer powers, with no variables in the denominators.
Therefore, this expression is not a polynomial, and it doesn't have a type or degree.
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Rectangle abcd was dilated to create rectangle a’b’c’d’. the area of rectangle abcd is 16in^2 and the area of the rectangle a’b’c’d’ is 64in^2. which scale factor was used to dilate the rectangle?
help asap please!!!!!
If the area of rectangle abcd is 16in² and the area of the rectangle a’b’c’d’ is 64in², the scale factor used to dilate the rectangle was 2.
When a rectangle is dilated, its dimensions are multiplied by a common factor known as the scale factor. The scale factor is the ratio of the corresponding sides of the original rectangle and the dilated rectangle.
Let the scale factor be represented by k. The area of the original rectangle is 16 in², so we can write:
length x width = 16
Let L and W represent the length and width of the original rectangle, respectively. Therefore, we have:
LW = 16
After dilation, the area of the new rectangle is 64 in². The length and width of the new rectangle are kL and kW, respectively. Therefore, we can write:
(kL)(kW) = 64
Simplifying the above equation, we get:
k²LW = 64
Substituting the value of LW from the first equation, we get:
k²(16) = 64
Solving for k, we get:
k = √4 = 2
This means that the length and width of the new rectangle are twice the length and width of the original rectangle.
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Mike is shopping for new clothes. He has a coupon for 20% off of his total purchase. His purchase price before the discount is $68. Let T represent the total cost after the discount. Which equation can be written to model this scenario? Select ALL that apply. 68 – 0. 2(68) = T
A 68 – 0. 2 = T
B 68 – 20 = T
C 0. 2(68) = T
D 0. 8(68) = T
68 – 0. 2 = T and 0. 2(68) = T equation can be written to model this scenario. The correct options are A and C.
The equation 68 – 0.2(68) = T is correct since it represents the total cost after the 20% discount is applied.
The equation 68 – 0.2 = T is not correct since it does not correctly calculate the total cost after the discount.
The equation 68 – 20 = T is not correct since it subtracts the discount amount from the original price, which would give the discounted price before the discount, not the total cost after the discount.
The equation 0.8(68) = T is not correct since it calculates the discounted price, not the total cost after the discount.
Therefore the correct options are a and c.
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2. 7.G.1.2 Can a quadrilateral be drawn that meets the conditions described below? Select Yes or No by placing a check or X in the appropriate box. Conditions Two pairs of parallel sides and at least two right angles One pair of parallel sides and no right angles One pair of parallel sides and three right angles No parallel sides and four right angles Yes No
The complete conditions are
Two pairs of parallel sides and at least two right angles : YesOne pair of parallel sides and no right angles :YesOthers are NoChecking if a quadrilateral can be drawn from the conditionsBy definition a quadrilateral is a shape that has four sides and four angles
Next, we test the conditions
Two pairs of parallel sides and at least two right angles
This is true because quadrilaterals like rectangles and squares have two pair of parallel sides and right angles
One pair of parallel sides and no right angles
This is also true because quadrilaterals like trapezoid have one pair of parallel sides and may or may not have right angle
One pair of parallel sides and three right angles
This is false because a quadrilateral cannot be drawn with this condition
No parallel sides and four right angles
This is false because a quadrilateral cannot be drawn with this condition
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Find the perimeter of the polygon with the vertices G(2, 4), H(2,-3), J(-2,-3), and K(-2, 4).
The perimeter is ___ units.
Check the picture below.
consider the following 8 numbers, where one labelled x is unknown. 26 , 7 , 17 , x , 21 , 6 , 34 , 27 given that the range of the numbers is 63, work out 2 values of x .
The two possible values of x are -29 and 69.
To find two possible values for x, we need to use the fact that the range of
the numbers is 63.
The range is defined as the difference between the largest and smallest
numbers in the set.
First, we can find the largest and smallest numbers in the set:
Smallest number = 6
Largest number = 34
Next, we can set up two equations to represent the range of the numbers,
using the two possible scenarios for x:
Scenario 1:
If x is the smallest number in the set, then the range is equal to [tex]34 - x.[/tex]
Scenario 2: If x is the largest number in the set, then the range is equal to
[tex]x - 6[/tex].
We can then set up two equations and solve for x in each scenario:
Scenario 1:
[tex]34 - x = 63x = 34 - 63x = -29[/tex]
Scenario 2:
[tex]x - 6 = 63x = 63 + 6x = 69[/tex]
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Find the distance in between the point P( - 4, 2, 1) and the point Q(-1,2,0).
The distance between the points P(-4, 2, 1) and Q(-1, 2, 0) is [tex]\sqrt{(10)}[/tex] units.
The distance formula is derived from the Pythagorean theorem, which states that in a right triangle, the sum of the squares of the lengths of the legs (the sides that form the right angle) is equal to the square of the length of the hypotenuse (the side opposite the right angle).
In three-dimensional space, we have to use a variation of the Pythagorean theorem that involves finding the distance between the two points in each of the three dimensions (x, y, and z) and then adding up the squares of those distances, before taking the square root of the sum.
To find the distance between two points P(x1, y1, z1) and Q(x2, y2, z2) in three-dimensional space, we use the distance formula:
d = [tex]\sqrt{((x_2 - x_1)^2 + (y_2 - y_1)^2 + (z_2 - z_1)^2)}[/tex]
Using the given points P(-4, 2, 1) and Q(-1, 2, 0), we have:
d = [tex]\sqrt{((-1 - (-4))^2 + (2 - 2)^2 + (0 - 1)^2)}[/tex]
= [tex]\sqrt{(3^2 + 0^2 + (-1)^2)}[/tex]
= [tex]\sqrt{(10)}[/tex]
Therefore, the distance between the points P(-4, 2, 1) and Q(-1, 2, 0) is sqrt(10) units.
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(2) 44% of the students in Prof. Young's class are Liberal Arts major, 64% major in Business Administration, and 39% major in both. Compute the probability that a student selected at random in Prof. Young's class major in Liberal Arts or Business Administration.
The probability that a student selected at random from the class majors in Liberal Arts or Business Administration is 0.69 or 69%.
Let us say that the event that a student is a Liberal Arts major is 'LA' and the event that a student is a Business Administration major is 'BA'.
Now according to the question, we know that 44% of students are Liberal Arts majors, 64% of students are Business Administration majors,
and 39% of students are majoring in both.
With this information, we can say that:
P(LA) = 44% = 0.44
P(BA) = 64% = 0.64
• P(LAN BA) = 39% = 0.39
Now in order to find the probability that a student
is selected at random majors in either Liberal Arts
or Business Administration, we need to compute the value of P(LA U BA), which is the probability of either of the event happening.
The formula for the probability of the union of two events can be used to find the union that is: PILA U BA) = P(LA)+P(BA)-PILAN BA)
Now by substituting the values in the above equation, we get:
P(LA U BA) = 0.44 + 0.64 -0.39
P(LA U BA) = 0.69
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Cecilia found a house she likes. She needs to borrow $95,000 to buy the house. What annual income does Cecilia need to afford to borrow the money?
Required annual income does Cecilia need to afford to borrow the money is $221,395.
To determine the annual income that Cecilia needs to afford borrowing $95,000 for the house she likes, we need to consider her debt-to-income ratio (DTI).
Normally, lenders require a DTI ratio of 43% or lower which means that the total amount of debt Cecilia has (including the mortgage payment) should not exceed 43% of her gross income.
Let a DTI ratio of 43%, Cecilia's annual income should be at least $221,395 to afford borrowing $95,000 for the house.
We can calculate it by multiplying the amount of the loan by 100 and dividing by the DTI ratio: $95,000 x 100 / 43 = $221,395
Hence, required annual income does Cecilia need to afford to borrow the money is $221,395.
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Solve the system of linear equations by elimination
4x+6y=48
3x + 7y=51
To solve the system of linear equations by elimination, we need to eliminate one of the variables by multiplying one or both equations by a constant so that the coefficients of one of the variables are equal in both equations. Then, we can subtract one equation from the other to eliminate that variable and solve for the remaining variable.
In this case, we can eliminate y by multiplying the first equation by -7 and the second equation by 6, so that the coefficients of y are equal in both equations:
-28x - 42y = -336
18x + 42y = 306
Adding these two equations together, we get:
-10x = -30
Dividing both sides by -10, we get:
x = 3
Now that we have solved for x, we can substitute this value into one of the original equations to solve for y. Using the first equation, we get:
4x + 6y = 48
4(3) + 6y = 48
12 + 6y = 48
Subtracting 12 from both sides, we get:
6y = 36
Dividing both sides by 6, we get:
y = 6
Therefore, the solution to the system of linear equations is x = 3 and y = 6.
Find the surface area of this cone please help
The calculated value of the surface area of the cone is 36π
From the question, we have the following parameters that can be used in our computation:
Radius, r = 4 meters
Slant height, l = 5 meters
using the above as a guide, we have the following:
SA = πr(r + l)
Substitute the known values in the above equation, so, we have the following representation
SA = π * 4 * (4 + 5)
Evaluate
SA = 36π
Hence, the surface area of the cone is 36π
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hem t
Q4.
Mr Jones has two sizes of square paving stones.
He uses them to make a path.
3.72m
large
1.55m
small
ASKED
The path measures 1.55 metres by 3.72 metres.
Calculate the width of a small paving stone.
The width of a small paving stone is 0.62 m or 62 cm
Length of path = 4 sides of a large paving stone = 3.72 m
Width of large paving stone: 3.72 m ÷ 4 = 0.93 m
Width of small paving stone: 1.55 m − 0.93 m = 0.62 m
or: Length of path = 6 sides of a small paving stone = 3.72 m
Width of small paving stone: 3.72 m ÷ 6 = 0.62 m
or: Let the width of the small paving stone be x and the width
of the large paving stone be y.
Then in cm: x + y = 155 cm,
and 2x + 3y = 372 cm
We can see from the diagram that y = 372 cm – 2 × (x + y)
so y = 372 cm − 2 × 155 cm = 372 cm – 310 cm = 62 cm
Therefore, the width of a small paving stone is 0.62 m or 62 cm.
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Steve bought 10 gallons of gas at the gas station with the highest price. how much more than cole did he pay for gas?
please help, thank you.
Steve paid $10 more than Cole for gas, regardless of the actual prices of gas at the two gas stations.
To answer this question, we need to know the prices of gas at both gas stations. Let's assume that Cole bought 10 gallons of gas at the gas station with the lowest price, and that the price difference between the two gas stations is $x per gallon.
If we denote the price per gallon of gas at the gas station where Cole bought gas as "c", then the total amount Cole paid for gas is:
10c
If we denote the price per gallon of gas at the gas station where Steve bought gas as "s", then the total amount Steve paid for gas is:
10s
The difference between the two amounts is:
10s - 10c
But we know that Steve bought gas at the gas station with the highest price, so we can assume that s = c + x.
Substituting this expression for s into the equation above, we get:
10s - 10c = 10(c + x) - 10c = 10x
So Steve paid $10 more than Cole for gas, regardless of the actual prices of gas at the two gas stations.
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Brenton invested an average of $250 per month since age 39 in various securities for his retirement savings. His investments averaged a 6% annual rate of return unitl he retired at age 66. Given the same monthly investment and rate of return, how much more would Brenton have in his retirement savings had he started investing at age 25? Assume monthly compounding.
44,520. 00
79,500. 00
292,795. 72
330,027. 55
Brenton would have $330,027.55 more in his retirement savings had he started investing at age 25 instead of age 39, assuming monthly compounding and a 6% annual rate of return.
Brenton would have in his retirement savings if he started investing at age 25 instead of age 39, we need to calculate the future value of his investments in both scenarios and find the difference.
We'll use the formula for the future value of a series of equal payments (annuity) compounded monthly:
[tex]FV = P * (((1 + r)^nt - 1) / r)[/tex]
Where FV is the future value, P is the monthly payment ($250), r is the monthly interest rate (0.06 / 12), n is the number of times compounded per year (12), and t is the number of years.
Scenario 1 (investing since age 39):
t = 66 - 39 = 27 years
[tex]FV1 = 250 * (((1 + 0.06/12)^(12*27) - 1) / (0.06/12))[/tex]
FV1 ≈ $292,795.72
Scenario 2 (investing since age 25):
t = 66 - 25 = 41 years
[tex]FV2 = 250 * (((1 + 0.06/12)^(12*41) - 1) / (0.06/12))[/tex]
FV2 ≈ $622,823.27
Now, find the difference between the two scenarios:
Difference = FV2 - FV1
Difference ≈ $622,823.27 - $292,795.72
Difference ≈ $330,027.55
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Use the box method to distribute and simplify (-2x-6)(-4x - 1). Drag and
drop the terms to the correct locations of the table.
(-2x-6) (-4x-1)
Answer:69x-44
Step-by-step explanation:
69-44=67
Sonia has a hat collection. The ratio of white hats to
blue hats in her hat collection is 10:9. Which ratio is
equivalent to 10:97
The equivalent ratio is 10:107.78
To solve this problem, we need to find a ratio that is equivalent to 10:9 but has a denominator of 97.
First, we can set up a proportion:
10/9 = x/97
To solve for x, we can cross-multiply:
10 * 97 = 9 * x
970 = 9x
To find the value of x, you divided both sides of the equation by 9, resulting in:
x = 107.78 (rounded to two decimal places)
So the equivalent ratio is 10:107.78, but since we can't have a fractional hat, we can round up to 108. Therefore, the answer is 10:108.
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You are told that you can expect to see 6 characters during your times there! You really want to fill out your autograph book which holds 48 signatures.
The percentage of your book that can be filled during your reservation at Goofy's kitchen would be 12. 5%
How to find the percentage ?If there are 6 characters and each one signs your book once, then the total number of signatures you would be able to get are 6 signatures in total.
The calculation to determine the percentage of your book occupied involves dividing the number of signatures by its overall capacity and then multiplying that value by 100.
The percentage that would be covered is:
= 6 signatures / 48 total capacity x 100
= 12.5 %
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Find the moment of inertia about the x-axis of the
first-quadrant area bounded by the curve find lx (round to 1
Decimal place)
y^2=4x−2, the x-axis, and x=7
Im abit confused about this one
To find the moment of inertia about the x-axis of the given area, we can use the formula:
Ix = ∫y^2 dA
Where Ix is the moment of inertia about the x-axis and dA is an infinitesimal area element.
First, we need to find the limits of integration. The curve y^2 = 4x - 2 intersects the x-axis at (1/2, 0). Also, the area is bounded by the x-axis and the line x = 7. Therefore, the limits of integration for x are from 1/2 to 7.
Now, we can express the infinitesimal area element as dA = y dx. Also, we can solve the given equation for x in terms of y as x = (y^2 + 2)/4. Therefore, we can write:
Ix = ∫y^2 (y dx)
Ix = ∫[(y^3)/4 + (y/2)] dx, with limits from 1/2 to 7
Ix = [(y^3)/16 + (y^2)/4] evaluated at x = 7 and x = 1/2
Ix = [(49y^3)/16 + (49y^2)/4] - [(y^3)/16 + (y^2)/4]
Ix = (48y^3)/16 + (48y^2)/4
Ix = 3y^3 + 12y^2
To find the moment of inertia about the x-axis, we need to substitute y with x and take the integral from 1/2 to 0 (since the area is in the first quadrant):
Ix = ∫3x^3 + 12x^2 dx, with limits from 1/2 to 0
Ix = [x^4/4 + 4x^3] evaluated at x = 1/2 and x = 0
Ix = (1/64) + 0 - (0 + 0)
Ix = 1/64
Therefore, the moment of inertia about the x-axis of the first-quadrant area bounded by the curve y^2=4x−2, the x-axis, and x=7 is 0.0156 (rounded to 1 decimal place).
To find the moment of inertia (I_x) about the x-axis of the first-quadrant area bounded by the curve y^2 = 4x - 2, the x-axis, and x = 7, we need to use the following formula:
I_x = ∫(y^2 * dA)
Here, dA represents the differential area element. Since the curve is defined in terms of y^2, let's express y in terms of x:
y = ±√(4x - 2)
As we are considering the first quadrant, we will take the positive root:
y = √(4x - 2)
Now, let's find the differential area element, dA:
dA = y*dx
Substitute the expression for y into dA:
dA = √(4x - 2)*dx
Now, substitute dA into the formula for I_x and integrate with respect to x:
I_x = ∫(y^2 * dA) = ∫((4x - 2) * √(4x - 2)*dx)
Integrate this expression with limits of integration from x = 0 (where the curve intersects the x-axis) to x = 7:
I_x ≈ 203.33
Therefore, the moment of inertia about the x-axis for the given region is approximately 203.3 (rounded to 1 decimal place).
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A company had a profit of $4,758 in January and a profit of -$3,642 in February. The company's profits for the months of March through May
were the same in each of these months. By the end of May, the company's total profits for the year were -$1,275.
What were the company's profits each month from March through May? Enter the answer in the box.
The company's profits for March through May were each -$797.
What was the company's profits for March through May?Let's start by adding the profits for January and February:
Profit for January + Profit for February = $4,758 + (-$3,642) = $1,116
We know that the company's profits for March through May were the same in each of these months, so let's call this common profit "X". Therefore, the total profit for these three months would be:
3 * X = 3X
Adding up the profits for all five months gives us the total profit for the year:
$1,116 + 3X = -$1,275
Subtracting $1,116 from both sides gives us:
3X = -$2,391
Dividing both sides by 3 gives us:
X = -$797
Therefore, the company's profits for March through May were each -$797.
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Town officials want to estimate the number of households that own a dog. Answer the following.
There are 300 households in the town.
Estimate how many households that own a dog
__ households
The estimated number of households that own a dog in the town is 120 households.
To estimate the number of households that own a dog in the town with 300 households, you will need to follow these steps:
1. Collect a random sample of households from the town. The sample size should be large enough to be representative of the entire population.
2. Determine the proportion of sampled households that own a dog.
3. Multiply the proportion of dog-owning households in the sample by the total number of households in the town (300).
For example, let's say you collected data from 50 households and found that 20 of them owned a dog. The proportion of dog-owning households would be 20/50 = 0.4 (40%).
To estimate the total number of households that own a dog in the town, multiply 0.4 by 300:
0.4 * 300 = 120 households
So, the estimated number of households that own a dog in the town is 120 households.
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What is the distance between (-9, -6)(−9,−6)left parenthesis, minus, 9, comma, minus, 6, right parenthesis and (-2, -2)(−2,−2)left parenthesis, minus, 2, comma, minus, 2, right parenthesis
Answer: The answer to your question is the square root of 65
he figure below is a net for a rectangular prism. Side a = 62 centimeters, side b = 21 centimeters, and side c = 16 centimeters. What is the surface area of this figure?
The surface area of the rectangular prism is 4960 cm².
The rectangular prism can be divided into six rectangular faces, with opposite faces having the same area. To find the surface area, we need to calculate the area of each face and add them up.
The net shows three rectangles with dimensions of 62 cm x 21 cm, 62 cm x 16 cm, and 21 cm x 16 cm.
Therefore, the surface area of the rectangular prism is:
Area of the first rectangle = 62 cm x 21 cm = 1302 cm²
Area of the second rectangle = 62 cm x 16 cm = 992 cm²
Area of the third rectangle = 21 cm x 16 cm = 336 cm²
Total surface area = 2(Area of first rectangle) + 2(Area of second rectangle) + 2(Area of third rectangle)
= 2(1302) + 2(992) + 2(336)
= 2604 + 1984 + 672
= 4960 cm²
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8-70. Assume Figure A and Figure B, at right, are similar. Homework Help
a. If the ratio of similarity is (3)/(4), then what is the ratio of the perimeters of Figures A and B ?
b. If the perimeter of Figure A is p and the linear scale factor is r, what is the perimeter of Figure B?
c. If the area of Figure A is a and the linear scale factor is r, what is the area of Figure B?
a. The ratio of the perimeters of Figures A and B will also be (3)÷(4).
b. This is because the corresponding sides of Figure B are (3÷4) is smaller than those of Figure A, and the perimeter is the sum of all the sides.
c. The area of Figure B will be (9÷16)a.
What is perimeter ?Perimeter refers to the total length of the boundary or the outer edge of a two-dimensional closed shape. It is the sum of the lengths of all sides of the shape.
a. Since the ratio of similarity is (3)÷(4), this means that the corresponding sides of Figure A and Figure B are in the ratio of (3)÷(4). Therefore, the ratio of the perimeters of Figures A and B will also be (3)÷(4).
b. If the perimeter of Figure A is p and the linear scale factor is r, then the perimeter of Figure B will be (3÷4)p. This is because the corresponding sides of Figure B are (3÷4) is smaller than those of Figure A, and the perimeter is the sum of all the sides.
c. If the area of Figure A is a and the linear scale factor is r, then the area of Figure B will be (3÷4) square times smaller than that of Figure A. This is because the area of a similar figure proportional to the square of the linear scale factor.
Therefore, the area of Figure B will be (9÷16)a.
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A person is working in the purchasing department of an appliance retailer. This month he is stocking up on washers and dryers. His
supervisor informs him that his budget this month is $12,000. He knows that the average wholesale cost of a washer over the past
year has been $250, while the average wholesale cost of a dryer has been $200. Complete parts a through h
a) What is the maximum number of washers the person can purchase within the budget?
To calculate the maximum number of washers the person can purchase within the budget, we divide the budget by the cost per washer:
$12,000 ÷ $250 = 48 washers
b) What is the maximum number of dryers the person can purchase within the budget?
To calculate the maximum number of dryers the person can purchase within the budget, we divide the budget by the cost per dryer:
$12,000 ÷ $200 = 60 dryers
c) If the person wants to purchase an equal number of washers and dryers, how many of each can he purchase?
To purchase an equal number of washers and dryers, we need to find the common factor of both 48 and 60:
48 = 2 x 2 x 2 x 2 x 3
60 = 2 x 2 x 3 x 5
The common factor is 2 x 2 x 3 = 12. So, the person can purchase 12 washers and 12 dryers within the budget.
d) If the person purchases the maximum number of washers and dryers, what is the total cost of the purchase?
To calculate the total cost of the purchase, we multiply the maximum number of washers and dryers by their respective cost:
48 washers x $250 = $12,000
60 dryers x $200 = $12,000
The total cost of the purchase is $24,000.
e) If the person purchases an equal number of washers and dryers, what is the total cost of the purchase?
To calculate the total cost of the purchase, we multiply the number of washers and dryers by their respective cost:
12 washers x $250 = $3,000
12 dryers x $200 = $2,400
The total cost of the purchase is $5,400.
f) If the person wants to spend the entire budget on washers, how many washers can he purchase?
To spend the entire budget on washers, we divide the budget by the cost per washer:
$12,000 ÷ $250 = 48 washers
g) If the person wants to spend the entire budget on dryers, how many dryers can he purchase?
To spend the entire budget on dryers, we divide the budget by the cost per dryer:
$12,000 ÷ $200 = 60 dryers
h) If the person wants to spend the entire budget and purchase an equal number of washers and dryers, how many can he purchase?
To spend the entire budget and purchase an equal number of washers and dryers, we need to divide the budget by the sum of the cost per washer and cost per dryer, then find the common factor:
($12,000 ÷ ($250 + $200)) ÷ 2 = 18
The common factor of 18 is 2 x 3 = 6. So, the person can purchase 6 washers and 6 dryers within the budget.
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Put the quadratic
y=2x^2-4x+2
into the quadratic formula
enter the number that belongs in the green box.
The quadratic formula for solving quadratic equations of the form ax^2 + bx + c = 0 is:
x = (-b ± sqrt(b^2 - 4ac)) / 2a
To put the quadratic equation y = 2x^2 - 4x + 2 into this formula, we need to identify the values of a, b, and c.
In this case, we have a = 2, b = -4, and c = 2. Substituting these values into the quadratic formula, we get:
x = (-(-4) ± sqrt((-4)^2 - 4(2)(2))) / (2 * 2)
x = (4 ± sqrt(16 - 16)) / 4
x = (4 ± 0) / 4
Simplifying this expression, we get:
x = 1 or x = 1/2
Therefore, the solutions to the quadratic equation y = 2x^2 - 4x + 2 are x = 1 and x = 1/2.
To explain this solution in more detail, we first need to understand the quadratic formula and how it can be used to solve quadratic equations. The quadratic formula is a formula that provides the solutions to any quadratic equation of the form ax^2 + bx + c = 0, where a, b, and c are constants.
In this case, we were given a specific quadratic equation, y = 2x^2 - 4x + 2, and we needed to find its solutions. To do this, we identified the values of a, b, and c and substituted them into the quadratic formula. We then simplified the expression to obtain the solutions, which were x = 1 and x = 1/2.
It is important to be able to use the quadratic formula to solve quadratic equations because many real-world problems can be modeled using quadratic equations. By being able to solve these equations, we can find important information such as the roots, or solutions, of the equation, which can help us make predictions and solve problems.
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Select all the expressions that are equivalent to –25 (fraction 2 over 5)
(15 – 20d).
The equivalent expressions are,
A. [tex]-30 + 40d - 10c[/tex],
B. [tex]-6 + 8d - 2c[/tex]
D. [tex]6 - 8d + 2c[/tex].
What are expressions?An expression is a sentence with at least two numbers or variables having mathematical operation. Math operations can be addition, subtraction, multiplication, division.
For example, [tex]2x+3[/tex]
The given expression.
[tex]\implies -25(15 - 20d + 5c)[/tex]
[tex]\implies -125(3 - 4d + c)[/tex]
So, the given expression can be converted into
[tex]k(3 - 4d + c)[/tex]
The equivalent expressions are:
A. [tex]-30 + 40d - 10c[/tex],
B. [tex]-6 + 8d - 2c[/tex]
D. [tex]6 - 8d + 2c[/tex].
A. [tex]-30 + 40d - 10c[/tex]
[tex]\implies -30 + 40d - 10c[/tex]
[tex]\implies -10(3 - 4d + c)[/tex]
B. [tex]-6 + 8d - 2c[/tex]
[tex]\implies -6 + 8d - 2c[/tex]
[tex]\implies -2(3 - 4d + c)[/tex]
D. [tex]6 - 8d + 2c[/tex]
[tex]\implies6 - 8d + 2c[/tex]
[tex]\implies2(3 - 4d + c)[/tex]
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Use the given terms to generate a recursive rule. Sequence:13,15,23,55,183
To generate a recursive rule for the sequence 13, 15, 23, 55, 183, we need to identify the pattern in the sequence.
Looking at the differences between each term, we can see that:
15 - 13 = 2
23 - 15 = 8
55 - 23 = 32
183 - 55 = 128
So the differences are increasing by a factor of 4 each time.
Using this pattern, we can create a recursive rule:
a(1) = 13
a(n) = a(n-1) + 4^(n-2)
So for example,
a(2) = a(1) + 4^(2-2) = 13 + 1 = 14
a(3) = a(2) + 4^(3-2) = 14 + 4 = 18
a(4) = a(3) + 4^(4-2) = 18 + 16 = 34
a(5) = a(4) + 4^(5-2) = 34 + 64 = 98
a(6) = a(5) + 4^(6-2) = 98 + 256 = 354
And so on.
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The second part of the new coaster is a parabola.
Ray needs help creating the second part of the coaster. Create a unique parabola in the pattern f(x) = (x − a)(x − b). Describe the direction of the parabola and determine the y-intercept and zeros.
The unique equation of the given parabola in the form of f(x) = (x - a)(x - b) is given by, f(x) = x(x + 6).
The y intercept of the parabola is at (0,0).
Zeros of the parabola are at x = 0, -6.
Given the model equation for the parabola is f(x) = (x - a)(x - b)
It is the standard equation of a parabola with zeros x = a, b.
Here from the graph we can see that at x = -6, 0 the value of y reaches 0 that is the parabola has zeros at x = 0, -6.
So, a = 0 and b = -6
So, f(x) = (x - 0)(x - (-6))
f(x) = x(x + 6)
From the graph we can also see that the parabola is downward negative Y axis.
At y intercepts x = 0
So, the equation becomes in that case,
f(x) = 0.
So (0, 0) is the only y intercept of the parabola.
Hence, the equation of the unique parabola is, f(x) = x(x + 6) and Y intercept is at (0, 0) and zeros are at x = 0, -6.
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The question is incomplete. The complete question will be -
"The second part of the new coaster is a parabola.
Ray needs help creating the second part of the coaster. Create a unique parabola in the pattern f(x) = (x − a)(x − b). Describe the direction of the parabola and determine the y-intercept and zeros."
1. If tan theta < 0 and sec theta > 0, which quadrant(s) could the terminal side of theta lie?
2. If csc theta > 0, which quadrant(s) could the terminal side of theta lie?
3. If sin theta < 0 and cot theta < 0, which quadrant(s) could the terminal side of theta lie?
I need help really quick, thank you to whoever can help! :)
If tan theta < 0 and sec theta > 0, the terminal side of theta could lie in either the second quadrant or the fourth quadrant.
If csc theta > 0, the terminal side of theta could lie in either the first quadrant or the second quadrant.
If sin theta < 0 and cot theta < 0, the terminal side of theta could lie in either the third quadrant or the fourth quadrant.
1. If tan theta < 0 and sec theta > 0, the terminal side of theta could lie in either the second quadrant or the fourth quadrant. This is because tan theta is negative in the second and fourth quadrants, and sec theta is positive in the first and fourth quadrants.
2. If csc theta > 0, the terminal side of theta could lie in either the first quadrant or the second quadrant. This is because csc theta is positive in the first and second quadrants.
3. If sin theta < 0 and cot theta < 0, the terminal side of theta could lie in either the third quadrant or the fourth quadrant. This is because sin theta is negative in the third and fourth quadrants, and cot theta is negative in the second and third quadrants.
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