A microscope slide of the letter "p" is placed on the microscope stage so that it is oriented right side up with respect to the student using the microscope. What will the letter resemble when she observes the letter through the microscope?

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Answer 1

On the microscope slide, a specimen will appear upside-down and facing left while it is actually right-side up and facing right.

What is the orientation of a microscope?

The orientation of the specimen image is reversed when viewed via a microscope compared to the orientation of the actual specimen. As a result, when viewed under a microscope, the specimen will appear to be upside-down and backwards.

Coarse Adjustment Knob: To concentrate the specimen, the coarse adjustment knob, which is placed on the microscope's arm, raises and lowers the stage. With just a partial turn of the adjustment knob, the gearing system creates a significant vertical movement of the stage.

Condenser-Objective lens-Body tube-Eyepiece is the proper order for the flow of light in a compound microscope.

Use two hands at all times when moving your microscope. Lift the scope while encircling the arm with one hand.

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Related Questions

You bought a can of apricot jam. The contents marked as: net weight: 500g and volume: 400ml is the statement correct?why? and what is the mass of the jam you bought? calculate the density of jam in g/cm

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The statement is not correct the mass of the jam is 500g and the density of the jam is 0.125gm/cm³

How to calculate the density?The statement is not correct because mass and volume cannot be used together to describe the contents of a can. Mass is a measure of how much matter is in an object and volume is a measure of the amount of space taken up by an object. So, in this case, the can of apricot jam should just be marked with the net weight in grams.The mass of the jam you bought is 500g.To calculate the density of the jam, we need to divide the mass by the volume. The density of the jam is 500g/400ml = 1.25g/ml. To put this in g/cm3, we need to divide the density by 1000, which gives us 1.25g/ml = 0.125g/cm3.

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Stern observed all of the following results EXCEPT _______ in his experiment. A. one of the recombinant phenotypes was associated with an X chromosome of normal length B-the number of car, B. male offspring was roughly equal to the number of car+, B male offspring C. the number of males was roughly equal to the number of females D. offspring with red, round eyes resulted from fertilization of eggs containing recombinant X chromosomes

Answers

The number of males was roughly equal to the number of females: Stern observed all of the following results EXCEPT _______ in his experiment.

What is experiment?

The Stern-Gerlach experiment (also known as the Stern-Gerlach experiment or the Stern-Gerlach magneto-optical experiment) was a landmark experiment in the early 20th century that demonstrated the inherent quantization of atomic-scale systems. It was conducted in 1922 by Otto Stern and Walther Gerlach in Germany.

The experiment showed that when a beam of silver atoms was passed through a non-uniform magnetic field, the beam split into two separate beams travelling in different directions. This showed that the silver atoms had two possible orientations of their magnetic dipole moment, which could only take on two discrete values. This phenomenon is now known as the Stern-Gerlach effect and is a fundamental part of quantum mechanics.

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If an electric heater is rated at 15,000 W, and the voltage used is 240 V, what size breaker in amps would be required

Answers

The current required by the electric heater which has the power of 15,000 W is 62.5 A

The power of the heater = 15,000 W

The voltage used by the heater = 240 V

The current required by the electric heater can be found using the formula,

P = VI

where P is the power of the electric heater

V is the voltage used by the electric heater

I is the current required by the electric heater

Let us rearrange the above equation in order to get the current required by the heater is

I = P/V

Let us substitute the known values in the above equation, we get

I = 15,000 / 240

= 62.5 A

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