A pile of bricks of mass M is being raised to the tenth floor of a building of height H = 4y above the ground by a crane that is on top of the building. During the first part of the lift, the crane lifts the bricks a vertical distance h1=3y in a time t1=4T. During the second part of the lift, the crane lifts the bricks a vertical distance h2=y in t2=T. Which of the following correctly relates the power P1 generated by the crane during the first part of the lift to the power P2 generated by the crane during the second part of the lift?
A. P2=4P1
B. P2=43P1
C. P2=P1
D. P2=34P1
E. P2=13P1

Answer:

The cell will have no electromotive force in it.

Explanation:

The battery provides the chemical energy that produces the force needed to move electron around the circuit and to generate electrical energy.

Answer:

66n

Explanation:

4376

Answer:

1, 1583.33 V/m

2, 4.72*10^-12 C

3, 39.2*10^-11 C

Explanation:

1

E = V / d

E = 8.55 / 5.4*10^-3

E = 8.55 / 0.0054

E = 1583.33 V/m

2

Capacitance, C = (k * e0 * A) / d, where k = 1

A = area of capacitor, 3.37 cm² = 3.37*10^-4 m²

d = plate separation, 5.4 mm

e0 = Constant, 8.85*10^-12

Applying these, we have

C = (1 * 8.85*10^-12 * 3.37*10^-4) / 5.4*10^-3

C = 29.82*10^-16 / 0.0054

C = 5.52*10^-13 F

Since Q = CV, then

Q = 5.52*10^-13 * 8.55

Q = 4.72*10^-12 C

3

We are given that k = 83, so

Capacitance, C = (k * e0 * A) / d

C = (83 * 8.85*10^-12 * 3.37*10^-4) / 5.4*10^-3

C = 2.475*10^-13 / 0.0054

C = 4.58*10^-11 F

Q = CV

Q = 4.58*10^-11 * 8.55

Q = 39.2*10^-11 C

Answer:

she should ve the one handing out the cookies each day, to make sure each child gets only one cookie a day.

Answer:

A hypothesis is what you think will happen.

A conclusion is the results of an experiment summarized.

Hope this helps.

Answer Yes you answered correctly.

Explanation:

Gases, such as the air or helium inside a balloon, take the shape of the containers they're in. They spread out so that the space is filled up evenly with gas molecules. The gas molecules are not connected.

Answer:

Yea ur right

Explanation:

Answer:

energy

Explanation:

Energy can't be destroyed or created, just transferred.

Answer:

Cheetah cubs are in danger from predators like lions and hyenas which can track their prey by scent and so the mother and her cubs leave an area when their scent is too strong so that they are not hunted and the cubs survive.

Mother Cheetahs also train their cubs to hunt so that they may get food for themselves which will ensure their survival as well thus showing that both of these practices can impact on reproductive success.

Answer:

6.12 m/s

Explanation:

In order to solve this we have two parts of this problem, first we have the time that the pizza dough spent going upwards and after that we have a free fall from there, so we will use the free fall formula after we figured out whats the final height the dough reached after being thrown from Francesco's height which is 6ft3inches or 1.90 meters

We first have to find out how much time the dough spent in the air before reaching 0 as final speed and then started the free falling:

The formula would be:

[tex]Vf=Vo-at\\0=1-(-9.81t)\\1=9.81t\\t=\frac{1}{9.81}\\t=.101[/tex]

The formula to find out final height would be:

[tex]y = \frac{ h + Vy (t-gt^{2})}{2} \\[/tex]

Now we just insert the values we know

[tex]y = h+ \frac{ Vy (t-gt^{2})}{2} \\\\y = 1.90 +\frac{ .101-(-9.81)(.101)^{2})}{2} \\\\y=1.91[/tex]

So from 1.91 meteres the free fal started we have to just calculate the final velocity with the formula for free fall and velocity:

[tex](vf)^{2} =Vo^2 +2ad[/tex]

Since Vo is 0 because we are talking about free falling we just insert the values we know:

[tex](vf)^{2} =Vo^2 +2ad\\(vf)^{2} =2ad\\(vf)^{2} =2(9.81)(1.91)\\vf=\sqrt{37.4742} \\Vf=6.12m/s[/tex]

So the final speed that the dough hit the ground with is 6.12 m/s

Answer:

It burns easily & It produces a lot of energy

Explanation:

Coal burns easily and thus is ideal for use in a power plant.  

• To generate electric power in the United States, the main fuel used is coal.  

• It is used as it is burned easily and thus producing enormous amount of energy.  

• In the power plants, the lignite, bituminous coal, or subbituminous coal is burned.  

• The heat generated by the burning of the coal is used to transform water into high pressure steam that mediates a turbine, which generates electricity.  

• About 23 percent of the electricity in the United States is produced by the burning of coal.  

Thus, the correct answer is that coal burns easily.

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Answer:

29.4m/s

Explanation:

Given.

Time (t) = 3.0s

Required

Determine the final velocity

Since, it's a vertical motion, we make use of the following formula to solve for the final velocity (v).

v = u + gt

Where u = 0, g = 9.8m/s² and t = 3s

v = 0 + 9.8m/s² *3s

v = 0 + 29.4m/s

v = 29.4m/s

Hence, the final velocity is 29.4m/s

Answer:

5 billion years ago...ends 4.9 billion years later

Answer:

That's correct... you can mark them brainliest now. You have to have both slots answered before you can mark them. So, you're welcome :)

Explanation:

Explanation:

(a) Given:

Δy = 0 m

v₀ᵧ = 20.0 m/s sin 53° = 16.0 m/s

aᵧ = -9.8 m/s²

Find: t

Use an equation that doesn't include final velocity, v.

Δy = v₀ᵧ t + ½ aᵧt²

0 m = (16.0 m/s) t + ½ (-9.8 m/s²) t²

0 = 16t − 4.9t²

0 = t (16 − 4.9t)

t = 3.26 s

(b) Given:

v₀ₓ = 20.0 m/s cos 53° = 12.0 m/s

aₓ = 0 m/s²

t = 3.26 s

Find: Δx

Use an equation that doesn't include final velocity, v.

Δx = v₀ₓ t + ½ aₓt²

Δx = (12.0 m/s) (3.26 s) + ½ (0 m/s²) (3.26 s)²

Δx = 39.24 m

(c) Given:

v₀ᵧ = 20.0 m/s sin 53° = 16.0 m/s

vᵧ = 0 m/s

aᵧ = -9.8 m/s²

Find: Δy

Use an equation that doesn't include t.

vᵧ² = v₀ᵧ² + 2aᵧ Δy

(0 m/s)² = (16.0 m/s)² + 2 (-9.8 m/s²) Δy

Δy = 13.02 m

Alternatively, use t/2 = 1.63 seconds, and use an equation that doesn't include the final velocity, v.

Δy = v₀ᵧ t + ½ aᵧt²

Δy = (16.0 m/s) (1.63 s) + ½ (-9.8 m/s²) (1.63 s)²

Δy = 13.02 m

Sounds like the shingle/ball is thrown from the roof horizontally, so that the distance it travels x after time t horizontally is

x = (7.2 m/s) t

The object's height y at time t is

y = 9.4 m - 1/2 gt²

where g = 9.80 m/s² is the magnitude of the acceleration due to gravity, and its vertical velocity is

v = -gt

(a) The object hits the ground when y = 0:

0 = 9.4 m - 1/2 gt²

t² = 2 * (9.4 m) / (9.80 m/s²)

t ≈ 1.92 s

at which time the object's vertical velocity is

v = -g (1.92 s) = -18.8 m/s ≈ -19 m/s

(b) See part (a); it takes the object about 1.9 s to reach the ground.

(c) The object travels a horizontal distance of

x = (7.2 m/s) * (1.92 s) ≈ 13.8 m ≈ 14 m

Answer:

Can't really answer that for now. More context please?

Explanation:

I will answer it in a comment when you give some context.

Answer:

a) [tex]\beta = 1.111\times 10^{-7}[/tex], b) [tex]\beta = 9\times 10^{-7}[/tex], c) [tex]\beta = 3.087\times 10^{-6}[/tex], d) [tex]\beta = 2.5\times 10^{-5}[/tex], e) [tex]\beta = 0.5[/tex], f) [tex]\beta = 0.877[/tex]

Explanation:

From relativist physics we know that [tex]c[/tex] is the symbol for the speed of light, which equal to approximately 300000 kilometers per second. (300000000 meters per second).

a) A car traveling 120 kilometers per hour:

At first we convert the car speed into meters per second:

[tex]v = \left(120\,\frac{km}{h} \right)\times \left(1000\,\frac{m}{km} \right)\times \left(\frac{1}{3600}\,\frac{h}{s} \right)[/tex]

[tex]v = 33.333\,\frac{m}{s}[/tex]

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 33.333\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{33.333\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 1.111\times 10^{-7}[/tex]

b) A commercial jet airliner traveling 270 meters per second:

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 270\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{270\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 9\times 10^{-7}[/tex]

c) A supersonic airplane traveling Mach 2.7:

At first we get the speed of the supersonic airplane from Mach's formula:

[tex]v = Ma\cdot v_{s}[/tex]

Where:

[tex]Ma[/tex] - Mach number, dimensionless.

[tex]v_{s}[/tex] - Speed of sound in air, measured in meters per second.

If we know that [tex]Ma = 2.7[/tex] and [tex]v_{s} = 343\,\frac{m}{s}[/tex], then the speed of the supersonic airplane is:

[tex]v = 2.7\cdot \left(343\,\frac{m}{s} \right)[/tex]

[tex]v = 926.1\,\frac{m}{s}[/tex]

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 926.1\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{926.1\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 3.087\times 10^{-6}[/tex]

d) The space shuttle, travelling 27000 kilometers per hour:

At first we convert the space shuttle speed into meters per second:

[tex]v = \left(27000\,\frac{km}{h} \right)\times \left(1000\,\frac{m}{km} \right)\times \left(\frac{1}{3600}\,\frac{h}{s} \right)[/tex]

[tex]v = 7500\,\frac{m}{s}[/tex]

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 7500\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{7500\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 2.5\times 10^{-5}[/tex]

e) An electron traveling 30 centimeters in 2 nanoseconds:

If we assume that electron travels at constant velocity, then speed is obtained as follows:

[tex]v = \frac{d}{t}[/tex]

Where:

[tex]v[/tex] - Speed, measured in meters per second.

[tex]d[/tex] - Travelled distance, measured in meters.

[tex]t[/tex] - Time, measured in seconds.

If we know that [tex]d = 0.3\,m[/tex] and [tex]t = 2\times 10^{-9}\,s[/tex], then speed of the electron is:

[tex]v = \frac{0.3\,m}{2\times 10^{-9}\,s}[/tex]

[tex]v = 1.50\times 10^{8}\,\frac{m}{s}[/tex]

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 1.5\times 10^{8}\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{1.5\times 10^{8}\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 0.5[/tex]

f) A proton traveling across a nucleus (10⁻¹⁴ meters) in 0.38 × 10⁻²² seconds:

If we assume that proton travels at constant velocity, then speed is obtained as follows:

[tex]v = \frac{d}{t}[/tex]

Where:

[tex]v[/tex] - Speed, measured in meters per second.

[tex]d[/tex] - Travelled distance, measured in meters.

[tex]t[/tex] - Time, measured in seconds.

If we know that [tex]d = 10^{-14}\,m[/tex] and [tex]t = 0.38\times 10^{-22}\,s[/tex], then speed of the electron is:

[tex]v = \frac{10^{-14}\,m}{0.38\times 10^{-22}\,s}[/tex]

[tex]v = 2.632\times 10^{8}\,\frac{m}{s}[/tex]

The ratio [tex]\beta[/tex] is now calculated: ([tex]v = 2.632\times 10^{8}\,\frac{m}{s}[/tex], [tex]c = 3\times 10^{8}\,\frac{m}{s}[/tex])

[tex]\beta = \frac{2.632\times 10^{8}\,\frac{m}{s} }{3\times 10^{8}\,\frac{m}{s} }[/tex]

[tex]\beta = 0.877[/tex]

Answer:

6) False

7) True

8) False

9) False

10) False

11) True

12) True

13) True

14) True

Explanation:

The spacing between two energy levels in an atom shows the energy difference between them. Clearly, B has a greater value of ∆E compared to A. This implies that the wavelength emitted by B is greater than A while B will emit fewer, more energetic photons.

When atoms jump from lower to higher energy levels, photons are absorbed. The kinetic energy of the incident photon determines the frequency, wavelength and colour of light emitted by the atom.

The energy level to which an atom is excited is determined by the kinetic energy of the incident electron. As the voltage increases, the kinetic energy of the electron increases, the further the atom is from the source of free electrons, the greater the required kinetic energy of free electron. When electrons are excited to higher energy levels, they must return to ground state.

Answer:

motion repeating itself is referred to as periodic or oscillatory motion. An object in such motion oscillates about an equilibrium position due to a restoring force or torque. ... This motion is important to study many phenomena including electromagnetic waves, alternating current circuits, and molecules.

Explanation:

Answer:

Moves to and from about it's mean position in a fixed time interval.

Answer:

The maximum height reached by the ball is 16.35 m.

Explanation:

Given;

initial velocity of the ball, u = 17.9 m/s

the final velocity of the ball at the maximum height, v = 0

The maximum height reached by the ball is given by;

v² = u² + 2gh

During upward motion, gravity is negative

v² = u² + 2(-g)h

v² = u² -  2gh

0 = u² -  2gh

2gh = u²

h = u² / 2g

h = (17.9)² / (2 x 9.8)

h = 16.35 m

Ttherefore, the maximum height reached by the ball is 16.35 m.

Answer:

The 10X objective is use for the identification of actual size of histology tissues and 4X magnification is best for observation of most tissues slides

Explanation:

4X magnification is best for observation of most tissues slides because it has an objective lens that have lower power and have great high field overview which make it very easier to locate specimens on the slide. It is use to get the overview of histology slides. It is use to showcase more detailed observations about histology.

The 40X objective is use majorly to identify tissue , to observe the finer details and study tissue organization on the histology slide.

Answer: Temperature

Explanation:

The average kinetic energy of the particles in a gas is proportional to the temperature of the gas. Because the mass of these particles is constant, the particles must move faster as the gas becomes warmer.

"The kinetic energy of an object is the energy that it possesses due to its motion."

"The product of the half of the mass of each gas molecule and the square of RMS speed."

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Answer:

what

Explanation:

what I dont get it??

Answer:

that makes me confused I don't think of pizza the same again LOL

Answer:

a) = 11.29°

b) = 1.93 m/s²

Explanation:

θ = θ(m) sin(w(n).t + Φ)

w(n) = 2π / t

w(n) = 6.284 / 1.3

w(n) = 4.834 rad/s

θ• = θ(m).w(n).cos (w(n).t + Φ)

θ•(m) = θ(m).w(n)

v(m) = L.θ•(m)

v(m) = L.θ(m).w(n)

θ(m) = v(m) / L.w(n)

For a simple pendulum,

w(n) = √(g / l)

l = g / w(n)²

l = 9.8 / 4.834²

l = 9.8 / 23.368

l = 0.42 m

Remember, θ(m) = v(m) / l.w(n)

θ(m) = 0.4 / (0.42 * 4.834)

θ(m) = 0.4 / 2.03

θ(m) = 0.197 rad

Converting to °, we have

0.197 * 360 * 1/2π

0.197 rad = 11.29°

Thus, the amplitude of the motion is 11.29°

a(t) = l.θ(t)

Tangential acceleration occurs when θ(t) is maximum, so

θ(t) = -θ(m).w(n)².sin(w(n)t + Φ)

θ(t max) = θ(m).w(n)²

a(t max) = l.θ(m).w(n)²

a(t max) = 0.42 * 0.197 * 4.834²

a(t max) = 1.93 m/s²

Explanation:

Answer:

Falling from the Sears Tower

• After 5 seconds, the ball falling from the

Sears Tower will have fallen

distance = ½ • 32 ft/s2 • (5 s)2 = 16 • 25

= 400 feet.

• We can turn the formula around to figure

out how long it would take the ball to fall all

the way to the ground (1450 ft)

Ætime = square root of (2 x distance/g)

Explanation:

Answer:

nice cool math and jim jake jr as a baby and just jim jake baby and nice pfp d00d XD

Explanation:

Answer:engineers developed and improved solutions in response to consumer demand for equal access for people with disabilities.

Explanation:

Apex