A reading work shop started at 8.30am and ended at 1pm. how long wasthe workshop .give your answer in h and min​

Answer:

problem 8= 769.3

problem 16=A

problem 11= independent-x , dependent-y

problem 12= independent- s , dependent- v

problem 17= C

The standard form of the expression (4 × 10) + (3 × 1/100) + (5 × 1/1000) is 40.035

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

We have expression:

= (4 × 10) + (3 × 1/100) + (5 × 1/1000)

= 40 + 0.03 + 0.005

= 40.035

Thus, the standard form of the expression (4 × 10) + (3 × 1/100) + (5 × 1/1000) is 40.035

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Answer:

The question has some missing details such as ; Use cylindrical shells to find the volume of the remaining solid if the remaining solid is 8cm high. I have however solved it using the value of 8cm, you can use the same approach to solve for the volume irrespective of the value of the height you are given.

Step-by-step explanation:

The detailed step by step analysis and appropriate Integration by susbtitution in order to get the volume of the remaining solid is as shown in the attached file.

Answer:

126

Step-by-step explanation:

[tex]V = A * h = \frac{1}{4} * \pi * d^{2} * h = A * h = \frac{1}{4} * 3.14 * 36 * 5 = 141.3\\ \\V_{empty} = A * h = \frac{1}{4} * \pi * d^{2} * h = \frac{1}{4} * \pi * 4 * 5 = 15.7[/tex]

[tex]V_{full} = V - V_{empty} = 141.3 - 15.7 = 125.6 \approx 126[/tex]

Answer:

0

Step-by-step explanation:

5^2-4(5)-5=2(5)-10

0=0

Answer:

(3)   {5,7}

Step-by-step explanation

135 people voted for it on gauth math

Answer:

The zeros are -2 and 8, because the factors of g are (x+2) and (x-8).

Step-by-step explanation:

Answer:

Joaquin Phoenix Has the Fastest Joker Makeup at Just 15 Minutes.

Answer:

Range :24

Mode: No mode

Median:13

Mean:46.5 OR 13.30

Answer:

This is unsolvable without the graph. show me the graph and i can solve it

Step-by-step explanation:

Answer:

y = 0

Step-by-step explanation:

Plug 10 in for x, and solve for y.

10 + 5y = 10

5y = 0

y = 0

Step-by-step explanation:

green = surface area

volume = 9/5 × 2/3

= 18/15

= 6/5 = 1.2 or 1 1/5

Answer:

2(60)+2b=360

120+2b=360

2b=360-120

2b/2=240/2

b=120

[tex]\huge\fcolorbox{blue}{aqua}{Answer:}[/tex]

═════════════════════

1.[tex]- 5x - y = 8[/tex]

[tex]-5x-y=8[/tex]

[tex]-5x=8+y [/tex]

[tex]-5x=y+8 [/tex]

[tex]\frac{-5x}{-5}=\frac{y+8}{-5} [/tex]

[tex]x=\frac{y+8}{-5} [/tex]

[tex]x=\frac{-y-8}{5} [/tex]

[tex]-5x-y=8[/tex]

[tex]-y=8+5x [/tex]

[tex]-y=5x+8 [/tex]

[tex]\frac{-y}{-1}=\frac{5x+8}{-1} [/tex]

[tex]y=\frac{5x+8}{-1} [/tex]

[tex]y=-5x-8 [/tex]

────────────────────

2.[tex]-4x-y=2 [/tex]

[tex]-4x-y=2 [/tex]

[tex]-4x=2+y [/tex]

[tex]-4x=y+2 [/tex]

[tex]\frac{-4x}{-4}=\frac{y+2}{-4} [/tex]

[tex]x=\frac{y+2}{-4} [/tex]

[tex]x=-\frac{y}{4}-\frac{1}{2} [/tex]

[tex]-4x-y=2[/tex]

[tex]-y=2+4x [/tex]

[tex]-y=4x+2 [/tex]

[tex]\frac{-y}{-1}=\frac{4x+2}{-1} [/tex]

[tex]y=\frac{4x+2}{-1} [/tex]

[tex]y=-4x-2 [/tex]

════════════════════

Explanation:

#Carry on learning

Step-by-step explanation:

take it again, it's so blur

Answer:

275.63 mm^2

Step-by-step explanation:

The measurements of the pyramids are

Edge length: 10
Egde width: 8.66 (because 10x8.66/2 = 43.3)
Height: 9

To find the surface area, use this formula, and you will get 275.63:

Answer:

c. $750

Step-by-step explanation:

the perimeter is 80m

80÷8=10

10*75=750

Answer:

291.

Step-by-step explanation:

(x - 147) / 12 = 12

x - 147 = 144

x = 144 + 147

x = 291.

i believe it is called a parameter

Answer:

11

Step-by-step explanation:

x = 4

2x

= 2 * 4

= 8

y = 3

2x + y

= 8 + 3

= 11

Answer:

the answer is 90 degrees

Answer:

Step-by-step explanation:

Original coordinates of F

It is reflected across the y-axis.

Transformation of coordinates across y-axis

Therefore, on reflection, the coordinates of F' will be :

Answer:

Yes

Step-by-step explanation:

put point (3,28) in the above equation

28=19+3(3)

28=28

[tex]\LARGE{\text{please\:refer\:to\:the\:"explanation"\:section\:of\:this\:ans}}[/tex]

An easy way to check whether or not a point lies on a line is to plug in the x-coordinate in lieu of x and the y - coordinate in lieu of y As follows :

x - coordinate : 3

y=19+3(3)

y - coordinate : 28

28 = 19 + 9

28 = 28 [tex]\Large\checkmark[/tex]

LHS = RHS

[tex]\footnotesize{\text{hope\:helpful}}[/tex]

Answer:

it’s 8 and 2 and 4 and 0

Step-by-step explanation:

this is because when you multiply 2x the x is an 8 so 2 times 8 is 16 then minus 2 is 14 which is greater than -4 same for my other answer

Answer:

Step-by-step explanation:

Here are the steps to solve this equation:

Given:

First step: 2(y+6)-4y

Use the distributive property.

Distributive property:

2(y+6)

2*y=2y

2*6=12

2y+12

Isolate the term of y from one side of the equations.

2y+12=4y

Subtract by 12 from both sides.

2y+12-12=4y-12

Solve.

2y=4y-12

Then, you subtract by 4y from both sides.

2y-4y=4y-12-4y

Solve.

2y-4y=-2y

-2y=-12

Divide by -2 from both sides.

[tex]\sf{\dfrac{-2y}{-2}=\dfrac{-12}{-2}}[/tex]

Solve.

Divide the numbers from left to right.

Solutions:

-12/-2=6

[tex]\Longrightarrow: \boxed{\sf{y=6}}[/tex]

I hope this helps. Let me know if you have any questions.

Answer:

[tex]\textsf{a)}\quad y=8x^2+2x-3[/tex]

[tex]\textsf{b)}\quad y=x^2-2x-4[/tex]

Step-by-step explanation:

Given information:

[tex]x^2+bx+c=0[/tex]

[tex]x_1+x_2=-b[/tex]

[tex]x_1x_2=c[/tex]

Part (a)

[tex]\textsf{If}\quad x_1=\dfrac12\quad\textsf{and}\quad x_2=-\dfrac34[/tex]

[tex]\begin{aligned}\implies -b & =\dfrac12+\left(-\dfrac34\right)\\ & = \dfrac24-\dfrac34\\ & =-\dfrac14\end{aligned}[/tex]

[tex]\begin{aligned}\implies c & =\dfrac12 \cdot \left(-\dfrac34\right)\\ & = \dfrac{1 (-3)}{2 \cdot 4}\\ & =-\dfrac38\end{aligned}[/tex]

Substituting the found values of b and c into [tex]x^2+bx+c=0[/tex]

[tex]\implies x^2+\dfrac14x-\dfrac38=0[/tex]

Multiply both sides by 8 so that coefficients are integers:

[tex]\implies 8x^2+2x-3=0[/tex]

Therefore, the final quadratic equation is:

[tex]y=8x^2+2x-3[/tex]

----------------------------------------------------------------------------------------------

Part (b)

[tex]\textsf{If}\quad x_1=1+\sqrt{5}\quad\textsf{and}\quad x_2=1-\sqrt{5}[/tex]

[tex]\begin{aligned}\implies -b & =(1+\sqrt{5})+(1-\sqrt{5})\\ & = 1+1+\sqrt{5}-\sqrt{5}\\ & =2\end{aligned}[/tex]

[tex]\begin{aligned}\implies c & =(1+\sqrt{5})(1-\sqrt{5})\\ & = 1-\sqrt{5}+\sqrt{5}-5\\ & =-4\end{aligned}[/tex]

Substituting the found values of b and c into [tex]x^2+bx+c=0[/tex]

[tex]\implies x^2-2x-4=0[/tex]

Therefore, the final quadratic equation is:

[tex]y=x^2-2x-4[/tex]

Answer:

E) None of the above

Step-by-step explanation:

Given [tex]f(x)=\sqrt{x}[/tex] and [tex]g(x)=x+2[/tex], then [tex]f(g(x))=\sqrt{x+2}[/tex]. This shifts the graph of the parent function [tex]f(x)=\sqrt{x}[/tex] 2 units to the left. Thus, the domain of the function is [tex][-2,\infty)[/tex], making none of the above true.

The domain of f(g(x)) is all real numbers x such that x ≥ -2.

Hence, Option e is correct.

A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

Now, To find the domain of f(g(x)), we need to first determine the domain of g(x).

Since, g(x) is a polynomial function,

And, we know that it is defined for all real numbers.

Therefore, the domain of g(x) is (-∞, ∞).

Next, we need to find the domain of f(g(x)), which means we need to determine which values of x make g(x) a valid input for f(x).

Since, f(x) is defined only for non-negative real numbers, we need to ensure that g(x) is a non-negative real number.

Therefore, we set the inequality g(x) ≥ 0 and solve for x:

x + 2 ≥ 0

x ≥ -2

So, The domain of f(g(x)) is all real numbers x such that x ≥ -2.

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[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve ~

[tex]\qquad \tt \dashrightarrow \:6 < 4x + 8 < 14[/tex]

[tex]\qquad \tt \dashrightarrow \:6 - 8 < 4x + 8 - 8 < 14 - 8[/tex]

[tex]\qquad \tt \dashrightarrow \: - 2 < 4x < 6[/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{ - 2}{4} < \dfrac{4x}{4} < \dfrac{6}{4} [/tex]

[tex]\qquad \tt \dashrightarrow \: \dfrac{ - 1}{2} < {x}{} < \dfrac{3}{2} [/tex]

hope it helps ~