Answer:
Thus, the pollutant concentration in lake will be reduced to 0.2% after 6.931471 days
Explanation:
From the information given:
A(t) = amount of pollutant for time (t)
A 4 billion cubic ft is the same as 4000 million cubic ft:
∴
The Initial amount of pollutant is [tex]A_o = (\dfrac{0.4}{100})\times 4000[/tex]
[tex]A_o = 16 \ million \ cubic \ feet[/tex]
However;
the pollutant rate (input) = 400 × 0 = 0
the pollutant rate (output) = [tex]400( \dfrac{A(t)} {4000})[/tex]
[tex]= 1( \dfrac{A(t)} {10})[/tex]
The net rate = [tex]A'(t) = 0 - 1( \dfrac{A(t)} {10})[/tex]
[tex]\implies A'(t) = - 1( \dfrac{A(t)} {10})[/tex]
[tex]\implies \dfrac{1}{A(t)}A'(t) = -(\dfrac{1}{10})[/tex]
[tex]\implies \int (\dfrac{1}{A(t)}A'(t) ) dt = \int -(\dfrac{1}{10}) dt[/tex]
[tex]\implies In (A(t)) = -(\dfrac{1}{10})t + c[/tex]
[tex]\implies A(t) = e^{-(\dfrac{1}{10})t+c}[/tex]
[tex]\implies A(t) = Ce^{-\dfrac{1}{10}^t}[/tex]
A(0) = 16
[tex]\implies Ce^{ -(1/20)^0} = 16 \\ \\ C = 16[/tex]
[tex]\implies A(t) = 16e^{(-1/10)t}[/tex]
[tex]0.2\% \ pollutant = (\dfrac{0.2}{100})*4000 =8 \ million \ cubic \ feet[/tex]
A(t) = 8
[tex]\implies 16e^{(-1/10)t}= 8 \\ \\ \implies e^{1/10)t} = 2 \\ \\ (\dfrac{1}{10} )^t = In(2) \\ \\ t = 10\ In(2) \\ \\ \mathbf{ t = 6.931471}[/tex]
A block of metal has a mass of 18.361kg and the following dimensions: 22.35 cm x 7.34 cm x 22.05 mm. What is the density of the metal in g/cm^3
Answer:
50.76 g/cm³
Explanation:
We'll begin by converting 18.361 Kg to g. This can be obtained as follow:
1 Kg = 1000 g
Therefore,
18.361 Kg = 18.361 Kg × 1000 g / 1 Kg
18.361 Kg = 18361 g
Next, we shall express the dimension in the same unit of measurement.
Dimension = 22.35 cm x 7.34 cm x 22.05 mm
Thus, we shall convert 22.05 mm to cm. This can be obtained as follow:
10 mm = 1 cm
Therefore,
22.05 mm = 22.05 mm × 1 cm / 10 mm
22.05 mm = 2.205 cm
Thus, the dimension is 22.35 cm x 7.34 cm x 2.205 cm.
Next, we shall determine the volume of the metal. This can be obtained as follow:
Dimension = 22.35 cm x 7.34 cm x 2.205 cm.
Volume = 361.728045 cm³
Finally, we shall determine the density of the metal. This can be obtained as follow:
Mass of metal = 18361 g
Volume of metal = 361.728045 cm³
Density of metal =?
Density = mass / volume
Density of metal = 18361 / 361.728045
Density of metal = 50.76 g/cm³
Which of the following best represents the structure of an amino acid in basic solution (pH = 11)?
Answer:
Explanation:
In basic solution (pH = 11), an amino acid typically exists in its zwitterionic form. This means that the amino acid has both a positive and a negative charge, due to the presence of both a basic amino group (-NH2) and an acidic carboxyl group (-COOH).
The structure of an amino acid in basic solution (pH = 11) can be represented as follows:
The central carbon atom (also known as the alpha carbon) is bonded to a hydrogen atom, an amino group (-NH2), a carboxyl group (-COOH), and a side chain R group.
The amino group is positively charged due to the loss of a proton (H+).
The carboxyl group is negatively charged due to the gain of a proton (H+).
Overall, the amino acid has a net charge of zero, due to the equal and opposite charges of the amino and carboxyl groups. This is known as the zwitterionic form of the amino acid.
Here is a visual representation of the structure of an amino acid in basic solution (pH = 11):
H |
N-C-COOH
|
R
Regenerate response
Which type of lipids/fats increase cholesterol levels in the
blood?
saturated lipids
unsaturated lipids
Answer:
In humans, saturated fat intake increases LDL cholesterol in comparison with all nutrients except trans fats [2•]. Because saturated fat also increases high-density lipoprotein (HDL) cholesterol, the total cholesterol (TC) to HDL cholesterol ratio (a risk marker for CVD) is not altered. I would like Brainleist please!
Explanation:
A GC analysis of a oil containing the unknown diene produced a chromatogram with 3 distinct peaks. From the determination of peak area, you find that the percent compositions represented by the peaks are: peak A is 26.66 percent, peak B is 60 percent, and peak C is 13.33 percent. If the largest peak in the chromatogram corresponds to the diene, how many moles of diene are in the crude oil
Answer:
0.011 moles of diene are in the crude oil
Explanation:
The mass of the oil is 2.5g and the M.W. of the diene is 136g/mol
The largest peak is the peak that has the higher percent concentration: That is the peak B with 60% by mass.
Knowing this we can find the mass of the diene using its percentage and with the mass and the molecular weight we can find its moles:
Mass Diene:
2.5g Oil * (60g Diene / 100g Oil) = 1.5g Diene are in the oil
Moles:
1.5g Diene * (1mol / 136g) =
0.011 moles of diene are in the crude oilHow many moles are in 20.5 grams of Calcium (Ca)? (1pt)
A)762.45 moles
B)1 mole
C)2 moles
D)0.5 moles
Answer:
Number of moles in 20.5 grams of calcium (Ca) = 0.5 moles (Approx.)
Explanation:
Given:
Amount of calcium (Ca) = 20.5 grams
Find:
Number of moles in 20.5 grams of calcium (Ca)
Computation:
Number of moles = Gram weight / Atomic weight of substance
We know that, Atomic weight of calcium (Ca) is 40.078 u
Number of moles in 20.5 grams of calcium (Ca) = Amount of calcium (Ca) / Atomic weight of calcium (Ca)
Number of moles in 20.5 grams of calcium (Ca) = 20.5 / 40.078
Number of moles in 20.5 grams of calcium (Ca) = 0.511
Number of moles in 20.5 grams of calcium (Ca) = 0.5 moles (Approx.)
These are specially built to prevent waste chemicals from moving into the soil. As rainwater or groundwater moves through solid waste, it can dissolve or corrode some items. Plastic liners and compacted clay are used to prevent these solutions from entering the soil and the groundwater.
a
Sewage Treatment Facility
Sanitary landfill
c
Landfill
d
Effluent
Answer:
sanitary landfill is the answer
What are the uses of the metal Magnesium?
Answer:
use of sterile injections for clearanti bodies
Explanation:
Answer:
Hello There!!
Explanation:
They can be used in making products that make it lightweight such as in power tools and luggages.
hope this helps,have a great day!!
~Pinky~
What is the hybridization of all the atoms (other than hydrogen) in each of the following species?
Drag the appropriate items to their respective bins.
The hybridization of C in HCN is sp because, carbon is triple bonded to the nitrogen. Hybridization of N in HCN is also sp. Hybridization of nitrogen in NH₄ is sp³.
What is hybridization?When tow atoms combines to form a molecules, the energy of individual atomic orbitals redistribute to form hybrid orbitals of equivalent energy. The type of hybridization s based on the on the involvement of s, p or d orbitals of the atom.
In HCN, carbon is triple bonded to nitrogen. Here, both s and p orbital contribution is 50%. Hence, both C and N in HCN in sp hybridized.
In NH₄, the nitrogen is sigma bonded to each hydrogen and the hybridization of N is sp³ here since, 3 p orbitals of nitrogen and one s orbital are involved.
In CH₃-, C is sp² hybridized and in CH₃⁺ , C is sp³ hybridized. The C in C(CH₃)₄ is also sp³ hybridized where carbon involves sigma bonds with the methyl groups.
N in NH₃ is sp³ hybridized. Oxygen in water is sp² hybridized. When water abstracts one more proton forming H₃O⁺ , oxygen forms sp³ hybridized orbitals.
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Classify each of the following amines as primary (1°), secondary (2°), or tertiary (3°):
Drag the appropriate items to their respective bins.
Primary (1°) amine
Secondary (2°) amine
Tertiary (3°) amine
Functional group can be interconverted into each their by the means of suitable reagent. Functional group are responsible for the chemical and physical properties of a compound. Therefore in the below given ways compound can bee classified.
What is functional group?A group of atoms forming a component of a molecule that accounts for a particular function or chemical behavior is called a functional group. There are so many functional group in organic chemistry.
first compound-------- secondary (2°)
second compound-------------- secondary (2°)
third compound-------------------- tertiary (3°)
fourth compound ----------------primary (1°)
fifth compound---------------primary (1°)
Therefore in the above given ways compound can bee classified.
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Can someone help me with this pls
Answer:
i think the correct answer is A
A discarded spray paint can contains only a small volume of the propellant gas at a
pressure of 34.5 kPa. The volume of the can is 473 ml. If the can is run over by the
garbage truck and flattened to a volume of 13.16 ml, what is the pressure in kPa
assuming the can doesn't leak?
Answer:
1.24 × 10³ kPa
Explanation:
Step 1: Given data
Initial pressure of the gas (P₁): 34.5 kPaInitial volume of the can (V₁): 473 mLFinal pressure of the gas (P₂): ?Final volume of the can (V₂): 13.16 mLStep 2: Calculate the final pressure of the gas in the can
If we assume that the gas in the can behaves as an ideal gas and that the temperature remains constant, we can calculate the final pressure of the gas using Boyle's law.
P₁ × V₁ = P₂ × V₂
P₂ = P₁ × V₁ / V₂
P₂ = 34.5 kPa × 473 mL / 13.16 mL = 1.24 × 10³ kPa
If you get the question right i will give brainliest (HINT ITS NOT A)
Answer:
Explanation:
its b, i looked it up
3.
Find the kinetic energy of a 20,000-kg truck moving at 110 km/h (leave your answer in standard form
Answer:
9,339,136 J
Explanation:
Convert km/hr to m/s:
(110km/s)(1000m/km)(1hr/60min)(1min/60s) = 30.56m/s
KE = (1/2)mv^2 = (1/2)(20,000kg)(30.56m/s)^2 = 9,339,136 J
2. A small block of a metal with a mass of 223.1 grams when
submerged in a beaker containing water, the water level rises to
150.0 mL as shown in the figure here. If the density of the metal
block is 7.41 g/cm³ at 22°C, then what was the original water level
in the beaker?
Water leve
150 mL
The volume of the metal block can be calculated using the density and mass of the block is 30.0 cm³
What is metal block?A metal block is a solid piece of metal that is typically used for machining and other industrial applications. It is usually made from aluminum, steel, or other metals, and can be machined into a variety of shapes and sizes depending on the application. Metal blocks are also used for casting, forging, and other manufacturing processes. Metal blocks may also be used for decorative purposes, such as sculpture or engraving. They are also used in jewelry making and engraving, as well as in medical and dental applications.
The volume of the metal block can be calculated using the density and mass of the block:
Volume = Mass/Density = 223.1 g/7.41 g/cm³ = 30.0 cm³
Since the metal block was submerged in the water, the volume of the block will be added to the volume of water in the beaker. Therefore, the original water level in the beaker can be calculated using the following equation:
Original Water Level = 150 mL + (30.0 cm³/1000 cm³/mL) = 180.0 mL
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Why is only a small amount of the energy stored in food available to the next organism in a food web or chain?
There are more producers than consumers.
There are fewer top consumers
Primary and secondary consumers compete for their food.
Most energy is used for life or released as heat before the organism is eaten.
Answer:
There is only a small amount of energy stored in food for the next organism because the other organisms have to share their food with other animals which will limit the amount of food if that makes sense. (Basically the primary and secondary consumers competing each other for food)
Explanation:
Answer:
There is only a small amount of energy stored in food for the next organism because the other organisms have to share their food with other animals which will limit the amount of food if that makes sense. (Basically the primary and secondary consumers competing each other for food)
Explanation:
Given: Mg3N2 + 3 K2O → 3 MgO + 2 K3N
If 14 moles of potassium oxide, K2O, reacts, how many grams of potassium nitride, K3N, will be made? Show work
Explanation:
14 moles of potassium oxide, K2O, reacts, how many grams of potassium nitride, K3N, will be made? Show work
starting with calcium chloride describe how one can prepare calcium carbonate
How many atoms of oxygen (o)are present 2naOH+H2SO4 2H2O+Na2SO4
Answer:
10
Explanation:
Which of the following statements is true?
A Protons are positively charged and have a mass of 1 amu.
B Electrons are negatively charged and have a mass of 1 amu
C. The nucleus of an atom is positively charged and never has a mass of 1 amu,
D. Neutrons are negatively charged and have a mass of 1 amu,
Answer: Correct option is (A)
Explanation:
Protons carry a single positive charge that have a mass of one approximately one atomic mass unit.
Answer:
B: its positively charged of 1 or 3 amu
Explanation:
Hope it works!!
What effect does light have on the growth of plants?
Select all that apply.
Light does not have any effect on a plant’s growth.
Light makes a plant’s stem grow shorter.
Light makes a plant’s leaves turn brown.
Light will make a plant’s leaves grow bigger.
Answer:
The answer is the last one only.
Explanation:
Light/sun gives energy and growth which makes the plants leaves/plant grow bigger.
Explanation:
Without the sun, plants wouldn't get the food that's needed to grow, reproduce and survive. plants need sunlight, water and carbon dioxide to live.
Which of the following statements describes
an exothermic reaction but not an endothermic
reaction?
A. Energy is destroyed during the reaction.
B.
Energy is used to form chemical bonds.
C. Energy is used to break chemical bonds.
D. Energy is released as heat during the reaction.
Answer:
Energy is released as heat during the reaction.
Answer:
D. Energy is released as heat during the reaction.
Explanation:
How many moles are in 18.3 grams of Carbon?
Answer:
1.5236414197340638
HELPP! pls
Consider the following reaction: _2_ Al + _6_ HBr → _2_ AlBr3 + _3_ H2
When 3.22 moles of Al reacts with 4.96 moles of HBr, how many moles of H2 are formed?
What is the limiting reactant?
What is the excess reactant?
Answer:
"2.48 mole" of H₂ are formed. A further explanation is provided below.
Explanation:
The given values are:
Mole of Al,
= 3.22 mole
Mole of HBr,
= 4.96 mole
Now,
(a)
The number of mole of H₂ are:
⇒ [tex]\frac{Mole \ of \ H_2}{3} =\frac{Mole \ of HBr}{6}[/tex]
or,
⇒ [tex]Mole \ of \ H_2=\frac{1}{2}\times Mole \ of \ HBr[/tex]
⇒ [tex]=\frac{1}{2}\times 4.96[/tex]
⇒ [tex]=2.48 \ mole[/tex]
(b)
The limiting reactant is:
= [tex]HBr[/tex]
(c)
The excess reactant is:
= [tex]Al[/tex]
A group of electrons is treated as a point charge of -1.12 x 10-18 C. How many electrons make up this point charge? Remember that each electron has a charge of -1.602 x 10-19 C. o 2 o 4 4 07
Answer:
7
Explanation:
Given that the total charge is given by;
C =nq
Where;
n = number of charges
q = quantity of charge
Where the total amount of charge is -1.12 x 10-18 C and the magnitude of each charge is -1.602 x 10-19 C
Then the number of electrons is obtained from;
n = -1.12 x 10-18 C/ -1.602 x 10-19 C
n = 7
Two clear solutions are placed in separate beakers. The first solution has a pH = 4, and the pH of the second solution is unknown.
If the two solutions are mixed and the resulting solution has a pH = 7, describe the second solution.
A) The second solution has a higher pH level than the first solution. It has a
pH that is weaker but still neutralized the first solution. It also has a higher
concentration of hydronium ions compared to the first solution.
B) The pH of the second solution is higher than the pH of the first solution. It
is also acidic and, therefore, has a higher concentration of hydroxide ions
compared to the first solution.
C) The second solution has a basic pH level. It was strong enough to
neutralize the first solution. It also has a higher concentration of hydroxide
ions compared to the first solution.
D) The second solution has and equivalent number of hydroxide and
hydronium ions. It has a pH level that is higher (stronger) than the first
solution.
Answer:
C.
Explanation:
When the pH is 7 there is equal amount of H+ and OH so the solution added must be strong enough to nuetralize the acid. So option A is out B is wrong because adding a acidic solution to an acidic solution wont nuetralize it, D is wrong because if the 2 solution was already equal in both it would essentaly be water. ALthough water would raise the pH it would not nuetralize it to a even 7.
No Constant Variable
A 2.00L sample of gas at STP is heated to 500K and compressed to 200 kPa. What is
the new volume of the gas?
I’ll give you all my points
The new volume of the gas will be 1.85L.
The three gas laws are what?According to Boyle's Law, as pressure lowers, gas volume grows. According to Charles' Law, when the temperature rises, the volume of the gas also rises. Avogadro's Law also states that as the amount of gas increases, so does the volume of the gas.
Given, initial volume of gas V1 = 2L
initial temp T1 = 273K
initial pressure P1 = 101.3 kPa
final temperature, T2 = 500K
Final pressure, P2 = 200 kPa
let final or new volume be V,
now for a constant moles of gas,
by using ideal gas equation,
P1×V1/T1 = P2×V/T2
101.3×2/273 = 200×V/500
202.6/273 = 2V/5
V = 0.742×5/2
V = 1.85 L
The new volume of the gas will be 1.85L.
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In a cycle of copper experiment, a student first reacts a piece of copper metal with nitric acid to produce copper(II) nitrate (Cu(NO3)2) solution. The student then performs various reactions which transform the copper ions into a series of different copper compounds and complexes. Finally, the last reaction reduces the copper ions back to elemental copper metal. Copper atoms are conserved throughout the process. If the initial step of the experiment produces 4.12 mL of 2.41 M Cu(NO3)2, what is the theoretical yield of solid copper (Cu) that can be recovered at the end of the experiment
Answer:
0.631 grams is the theoretical yield of solid copper (Cu) that can be recovered at the end of the experiment
Explanation:
The concentration of the solution is given by :
[tex][C]=\frac{\text{Moles of compound}}{\text{Volume of solution in Liters}}[/tex]
We have:
Concentration of copper (II) nitrate solution = [tex][Cu(NO_3)_2]=2.41 M[/tex]
The volume of solution = 4.12 mL
1 mL= 0.001 L
[tex]4.12 mL= 4.12\times 0.001 L= 0.00412 L[/tex]
Moles of copper (II) nitrate in solution = n
[tex]2.41=\frac{n}{0.00412 L}=0.0099292 mol[/tex]
Moles of copper (II) nitrate in solution = 0.0099292 mol
1 Mole of copper(II) nitrate has 1 mole of copper then 0.0099292 moles of copper(II) nitrate will have :
[tex]1\times 0.0099292 mol= 0.0099292 \text{ mol of Cu}[/tex]
Mass of 0.0099292 moles of copper:
[tex]=0.0099292 mol\times 63.55 g/mol=0.63100 g\approx 0.631 g[/tex]
This mass of copper present in the solution is the theoretical mass of copper present in the given copper(II) nitrate solution.
0.631 grams is the theoretical yield of solid copper (Cu) that can be recovered at the end of the experiment
Average Volume of A Drop. 15 Drops for 1 ML
Note that if the water volume (ML) in a graduated cylinder is 30.0 and the volume of a drop of water is 1.00 and the number of drops is 15, the average drop volume (ML) is 2.0 mL.
What is average drop volume?Average drop volume is a measurement of a droplet's average volume. It is employed in a wide range of applications, including laboratory experimentation, medical research, and medication delivery systems.
It aids in deciding the proper amount of liquid to utilize in a certain condition. It also aids in the creation of novel pharmaceuticals and assuring exact and constant dosing in medical treatments.
You may calculate the average drop volume by dividing the total amount of water (30.0 mL) by the number of drops (15). That is to say:
(30.0 mL divided by 15 drops = 2.0 mL/drop)
Hence where the number of drops is 15mL and the volume of one drop is 1.00mL, the average Volume of a Drop is 2.0mL
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Spilled oil is considered a pollutant. Why is this so? Describe some way of cleaning oil after a spill
Answer: use methods to clean up ocean oil spills
Explanation:
Calculate the osmotic pressure of 5 % glucose solution and the osmotic pressure of 0.2 %, 0.9 % and 10 % sodium chloride solutions on the base of Van’t Hoff’s law (d = 1.1 g/ml for 10 % NaCl).
Based on Van't Hoff's law, the osmotic pressure of 5% glucose solution with 0.2%, 0.9%, and 10% sodium chloride solutions is 0821 liter atm K1mol1).
What is the osmotic pressure Van t Hoff law?Boyle, Van't Hoff The rule of solution: In a delute solution, the osmotic pressure () is directly proportional to the molar concentration (C) or inversely proportional to the volume (V) of the solution at constant temperature. Reason: C but C = Vn.
What does class 12 osmotic pressure formula mean?Pi=iMRT is the formula for osmotic pressure. The osmotic pressure increases with a solution's concentration (M) or temperature (T).
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