The concentration of glycine in the given solution is 0.066 M.
Concentration is defined as the amount of solute per unit volume of the solution.
Thus, the formula for calculating the concentration (C) of a solution is:
C = n/V
Where C is the concentration, n is the number of moles of solute, and V is the volume of the solution.
The formula for calculating the number of moles of a solute is given as:
m = n x M
Where m is the mass of the solute, n is the number of moles of solute, and M is the molar mass of the solute.
Using the formula given above, we can calculate the concentration of glycine in the given solution:
C = m/M x V
We know that the mass of glycine is 15.0 g and its molar mass is M(C₂H₅NO₂) = 75.07 g/mol
Substituting the given values, we get:
C = 15.0/75.07 × 0.330L= 0.066 M
Therefore, the concentration of a solution containing 15.0 g of glycine, C₂H₅NO₂, in a total solution volume of 0.330 l is 0.066 M.
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does any solid cu(oh)2 form when 0.075 g koh is dissolved in 1.0 l of 1.0 x 10 -3 m cu(no3)2? ksp of cu(oh)2
Yes, a solid Cu(OH)2 will form when 0.075 g KOH is dissolved in 1.0 L of 1.0 x 10^-3 M Cu(NO3)2. 0.107 g of solid Cu(OH)2 will form.
First, we need to determine the amount of Cu2+ ions present in the solution:
1.0 x 10^-3 M Cu(NO3)2 means that there are 1.0 x 10^-3 moles of Cu2+ ions per liter of solution.
Next, we can use stoichiometry to determine the amount of OH- ions that will react with the Cu2+ ions to form Cu(OH)2. The balanced chemical equation for this reaction is:
Cu2+ (aq) + 2OH- (aq) → Cu(OH)2 (s)
For every 1 mole of Cu2+ ions, we need 2 moles of OH- ions. Therefore, the total amount of OH- ions needed to react with all of the Cu2+ ions in the solution is:
2 x 1.0 x 10^-3 mol = 2.0 x 10^-3 mol
Now we can use the Ksp of Cu(OH)2 to calculate the concentration of Cu2+ and OH- ions in the solution. The Ksp expression for Cu(OH)2 is:
Ksp = [Cu2+][OH-]^2
Since we know the Ksp value for Cu(OH)2, we can solve for either [Cu2+] or [OH-]. Let's solve for [OH-]:
Ksp = [Cu2+][OH-]^2
4.8 x 10^-20 = (1.0 x 10^-3 M)[OH-]^2
[OH-]^2 = 4.8 x 10^-17
[OH-] = 2.2 x 10^-9 M
Therefore, the concentration of OH- ions in the solution is 2.2 x 10^-9 M. Since we need 2 moles of OH- ions for every mole of Cu2+ ions, we know that the concentration of Cu2+ ions is half of the concentration of OH- ions:
[Cu2+] = 1.1 x 10^-9 M
Finally, we can use the molar mass of Cu(OH)2 to determine the mass of solid that will form:
Molar mass of Cu(OH)2 = 97.56 g/mol
1 mole of Cu(OH)2 is formed for every mole of Cu2+ ions, so the mass of Cu(OH)2 that will form is:
0.0011 mol x 97.56 g/mol = 0.107 g
Therefore, 0.107 g of solid Cu(OH)2 will form when 0.075 g KOH is dissolved in 1.0 L of 1.0 x 10^-3 M Cu(NO3)2.
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all of the following are characteristics of nitrous oxide except: weak anesthetic. strong analgesic. strong amnesia. respiratory depression.
The correct answer for the given question is option B strong analgesic.
What is nitrous oxide ?
Nitrous oxide, also known as laughing gas, is a colorless, slightly sweet-smelling gas with the chemical formula N2O. It is a naturally occurring compound that can be synthesized for various uses, including medical and dental procedures, as well as for use as a propellant in whipped cream dispensers and racing cars.
Nitrous oxide is a weak anesthetic, meaning it does not provide complete loss of consciousness but can help reduce anxiety and pain during medical procedures. It is commonly used in combination with other anesthetics, such as oxygen or intravenous sedatives, to achieve a deeper level of anesthesia.
Nitrous oxide is a weak anesthetic and does not provide strong analgesia, but it does have some analgesic properties. It also has strong amnesic effects, meaning that patients may not remember the procedure after it is completed. However, it generally does not cause respiratory depression unless used in very high concentrations.
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at a fixed temperature and number of moles of nitrogen gas, its volume and pressure are 148 ml and 743 torr, respectively. what is the final pressure in torr, if the final volume is 214 ml?
The final pressure of nitrogen gas, at a fixed temperature and number of moles, with a final volume of 214 ml is 552 torr.
The pressure and volume of an ideal gas are inversely proportional to each other, meaning if one increases, the other decreases. This can be expressed by the equation PV=nRT, where n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Since n and T remain constant, the equation can be rearranged to solve for pressure as P=nRT/V. Using the given values, P= (1)(0.08206)(273.15)/(214 ml) = 552 torr.
Thus, the final pressure of nitrogen gas at a fixed temperature and number of moles, with a final volume of 214 ml is 552 torr.
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147 grams of argon to liters
Answer:
Explanation:
3.6797837188344116 mol
Help please i need help on this
Answer:This chemical reaction is a double replacement reaction.
Explanation:
Answer:
A-Double replacement
Explanation:
Hope this helps
suppose your unknown is sodium acetate. when a solution of calcium chloride is added to your unknown what will happen?
When a solution of calcium chloride is added to (the unknown) sodium acetate, sodium chloride (NaCl) and calcium acetate (Ca(C₂H₃O₂)₂) will be formed.
This is a precipitation reaction, and the product will be a solid.
Here is the balanced chemical equation for this reaction:
CaCl₂ + 2NaC₂H₃O₂ → Ca(C₂H₃O₂)₂ ( calcium acetate) + 2NaCl (sodium chloride)
Calcium chloride and sodium acetate will react to produce calcium acetate and sodium chloride in the presence of water. CaCl₂ and NaC₂H₃O₂ are the formulas for calcium chloride and sodium acetate, respectively.
The formula for calcium acetate is Ca(C₂H₃O₂)₂, and the formula for sodium chloride is NaCl.
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how many different alkenes result when 3-bromo-3-methylheptane is treated with a strong base? select answer from the options below 6 3 5 2 4
The number of alkenes formed depends on the position of the bromine and the methyl group on the carbon chain.
What are alkenes?An alkene is described as a hydrocarbon containing a carbon–carbon double bond and often used as synonym of olefin, that is, any hydrocarbon containing one or more double bonds.
When 3-bromo-3-methylheptane is treated with a strong base, an elimination reaction occurs, resulting in the formation of alkenes.
The elimination reaction happens by removing a proton from a beta-carbon (i.e., a carbon adjacent to the carbon bearing the bromine atom) and the bromine atom to form an alkene.
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an oxide of rhenium crystallizes with rhenium atoms at each of the corners and oxygen atoms in the middle of each edge of the cell. what is the formula of the oxide?
An oxide of rhenium crystallizes with rhenium atoms at each of the corners and oxygen atoms in the middle of each edge of the cell. The formula of the oxide is ReO2.
An oxide is a chemical compound of at least one oxygen atom and one other element. One of the most common oxides is carbon dioxide, which is made up of one carbon atom and two oxygen atoms. Oxides are found in many other minerals and rocks, as well as in the atmosphere and they may be divided into acidic oxides and basic oxides on the basis of their chemical behavior. Formula of the oxide the rhenium atoms are present at each of the corners, whereas the oxygen atoms are located in the middle of each edge of the cell, as a result, the oxide formula will be ReO2.
When the structure of the oxide is observed, it is observed that the oxide is made up of tetrahedra in which the oxygen atoms are positioned at the vertices and the rhenium atoms are positioned at the centre of each face. In this, the atoms are arranged in the form of a cubic unit cell, with the oxygen atoms situated at each corner and the rhenium atoms located at the center of each edge. As a result, the oxide formula will be ReO2.
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the half-life of zn-71 is 2.4 minutes. if one had 200 grams at the beginning, how quickly would it be decaying after 6.8 minutes has elapsed?
The decay rate is -364.2 grams per minute, which means that Zn-71 is decaying at a rate of 364.2 grams per minute.
Half-life is a term used to describe the amount of time it takes for half of a radioactive material to decay.
The half-life of Zn-71 is 2.4 minutes, which means that after 2.4 minutes, half of the Zn-71 atoms will have decayed, and after another 2.4 minutes, half of the remaining atoms will have decayed, and so on.
The problem wants to know how quickly the Zn-71 is decaying after 6.8 minutes have passed. We need to figure out how much Zn-71 is left after 6.8 minutes have passed.
We can use the formula N(t) = N0(1/2)t/T
where N(t) is the amount of the radioactive material at time t, N0 is the initial amount of the radioactive material, t is the time elapsed, and T is the half-life of the radioactive material.
We can find out how much Zn-71 is left after 6.8 minutes. N(6.8) = 200(1/2)6.8/2.4N(6.8) = 200(1/2)2.83N(6.8) = 36.42 grams. This means that after 6.8 minutes, only 36.42 grams of Zn-71 is left.
Use the formula for radioactive decay rate: R = -dN/dt, where R is the decay rate, dN is the change in the amount of radioactive material, and dt is the change in time.
We can approximate this using a small time interval, such as 0.1 minute, and use the formula: R ≈ ΔN/Δt.R ≈ (N(6.9) - N(6.8))/0.1R ≈ (0 - 36.42)/0.1R ≈ -364.2
Zn-71 is decaying at a rate of 364.2 grams per minute.
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for a second order reaction with an initial concentration of reactant of 64 m, what concentration of the reactant is left after three half lives?
After three half-lives, the concentration of the reactant will be 1/8 of its initial concentration. This means that the remaining concentration of the reactant after three half-lives will be 8 m.
A second order reaction is one that has a rate proportional to the product of the concentration of two reactants or the square of the concentration of one reactant. In this case, the rate of the reaction is given by the equation:
r = k[A]²
The half-life of a reaction is the amount of time it takes for the concentration of the reactant to decrease by half. The half-life of a second-order reaction is given by the equation:
t½ = 1 / (k[A]₀)
Where k is the rate constant, [A]₀ is the initial concentration of the reactant, and t½ is the half-life of the reaction. After one half-life, the concentration of the reactant will be [A] = [A]₀ / 2
After two half-lives, the concentration of the reactant will be [A] = [A]₀ / 4
After three half-lives, the concentration of the reactant will be [A] = [A]₀ / 8
Given that the initial concentration of the reactant is 64 M, the concentration of the reactant after three half-lives is:
[A] = [A]₀ / 8[A] = 64 / 8[A] = 8 M
Therefore, the concentration of the reactant that is left after three half-lives is 8 M.
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observing the formation of a silver mirror on the surface of a test tube when using tollen's reagent indicates the presence of:
Observing the formation of a silver mirror on the surface of a test tube when using Tollens' reagent indicates the presence of a reducing sugar.
Tollens' reagent is an aqueous solution of silver nitrate, sodium hydroxide, and ammonia used to test for the presence of aldehydes. The test is known as the Tollens' test, and it is based on the fact that aldehydes can be oxidized to carboxylic acids by silver ions.
In the presence of Tollens' reagent, the silver ions are reduced to metallic silver, which forms a silver mirror on the surface of the test tube when they are exposed to a reducing sugar.
Observing the formation of a silver mirror on the surface of a test tube when using Tollens' reagent indicates the presence of reducing sugar.
Reducing sugars are monosaccharides and disaccharides that can donate electrons to other molecules, resulting in their reduction.
Tollens' reagent is an oxidizing agent, and reducing sugars are oxidized by it to carboxylic acids.
As a result, the silver ions in Tollens' reagent are reduced to metallic silver, which forms a silver mirror on the surface of the test tube.
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given silver oxalate ( ag2c2o4= 5.40x10^-12) and silver phosphate (ag3po4 Ksp=8.89x10^-17) which substance has a greater concentration of the ag+ion
The concentration of Ag+ ions in silver phosphate must be less than the concentration of Ag+ ions in silver oxalate.Therefore, we can conclude that silver oxalate has a greater concentration of Ag+ ions than silver phosphate.
What is molar solubility?Molar solubility is the maximum amount of a solute that can dissolve in a solvent to form a saturated solutions at a specific temperature and pressure.
To compare concentration of Ag+ ions in silver oxalate and silver phosphate,we calculate the molar solubility of each compound.
For silver oxalate, the solubility product constant (Ksp) is given as 5.40x10⁻¹².
The balanced equation for the dissociation of silver oxalate is:
Ag₂C₂O₄s) ⇌ 2 Ag+(aq) + C₂O₄₂-(aq)
The Ksp expression for silver oxalate is:
Ksp = [Ag+]² [C₂O₄₂₋]
Since the stoichiometric coefficient of Ag+ is 2, we can assume that the molar solubility of silver oxalate is equal to x mol/L. Then, the molar concentration of Ag+ ions is also x mol/L.
Using the Ksp expression for silver oxalate, we can solve for x:
Ksp = [Ag+]² [C₂O₄₂-]
5.40x10⁻¹² = (x)² (2x)
5.40x10⁻¹² = 2x³
x = (5.40x10⁻¹²/₂)¹/₃
x = 4.38x10⁻⁴ mol/L
Therefore, the molar solubility of silver oxalate is 4.38x10⁻⁴ mol/L, and the concentration of Ag+ ions is also 4.38x10⁻⁴ mol/L.
For silver phosphate, the Ksp is given as 8.89x10⁻¹⁷
The balanced equation for the dissociation of silver phosphate is:
Ag₃PO₄(s) ⇌ 3 Ag+(aq) + PO₄₃-(aq)
The Ksp expression for silver phosphate is:
Ksp = [Ag+]³ [PO₄₃-]
Using the Ksp expression for silver phosphate, we can solve for x:
Ksp = [Ag+]³[PO₄₃-]
8.89x10⁻¹⁷ = (3x)³[PO₄₃-]
8.89x10⁻¹⁷ = 27x³ [PO⁴³-]
[PO⁴³-] = 8.89x10⁻¹⁷/27x³
Since we don't know the value of x yet, we can't directly solve for [PO₄₃-]. However, we know that the molar solubility of silver phosphate must be less than the molar solubility of silver oxalate, since the Ksp value for silver phosphate is smaller.
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a solution is made using 130.0 ml of acetonitrile (density 0.7766 g/ml) and 250.0 ml of water (density 1.000 g/ml). what is the molality acetonitrile in water?
The molality of acetonitrile in water is 9.84 mol/kg.
Molality is an expression of the amount of solute dissolved in a solvent, which is measured in moles per kilogram. Molality is calculated by dividing the moles of the solute by the mass of the solvent, in kilograms.
In this case, the moles of the solute (acetonitrile) can be calculated by multiplying the volume (130.0 mL) with the density (0.7766 g/mL) and dividing it by its molar mass (41.05 g/mol).
moles of acetonitrile = (130.0 mL)(0.7766 g/mL) / (41.05 g/mol) = 2.459 mol
The mass of the solvent (water) can be calculated by multiplying its volume (250.0 mL) with its density (1.000 g/mL).
mass of water = (250.0 mL) (1.000 g/mL) = 250 g
Thus, the molality of acetonitrile in water is:
molality = (2.459 mol) / (250 g)(1 kg/1000 g) = 9.84 mol/kg.
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if you choose to measure the freezing point of a solution of your compound, what would be the objective of the experiment?
The objective of measuring the freezing point of a solution of your compound is: to determine its purity or concentration.
When a compound is dissolved in a solvent, the freezing point of the resulting solution is lower than that of the pure solvent. This is because the solute molecules lower the freezing point of the solvent by interfering with the formation of the crystal lattice. The extent of the depression of the freezing point depends on the concentration of the solute and its nature.
To measure the freezing point of a solution of your compound, the solution is cooled until it begins to solidify. The temperature at which this occurs is recorded as the freezing point of the solution. By comparing the freezing point of the solution with the freezing point of the pure solvent, the concentration or purity of the solute can be calculated using the freezing point depression equation:
ΔTf = Kf · m,
where ΔTf is the freezing point depression, Kf is the freezing point depression constant, and m is the molality of the solute in the solution.
The freezing point depression constant is a property of the solvent and is typically provided in reference tables. Once the molality of the solute is determined, the molar mass or weight percent of the solute can be calculated, allowing for the determination of the purity or concentration of the compound.
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what is the percentage of the renantiomer in a sample of limonene that has a specific rotation ot -38, given that the specific rotatic of (s)-limonene is - 116?
Answer: The percentage of the (R)-limonene in the sample is 67.24%.
The percentage of the (R)-limonene in a sample of limonene with a specific rotation of -38 can be calculated using the following equation:
Percentage (R)-limonene = (Specific rotation of sample - Specific rotation of (S)-limonene) ÷ (Specific rotation of (S)-limonene) x 100%
In this case, the equation is:
Percentage (R)-limonene = (-38 - (-116)) ÷ (-116) x 100% = 67.24%
Therefore, the percentage of the (R)-limonene in the sample is 67.24%.
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. a scientist begins with 200 grams of a radioactive substance. after 210 minutes, the sample has decayed to 31 grams. to the nearest hundredth of a minute, what is the half-life of this substance?
Answer: The half-life of this radioactive substance is 52.38 minutes.
This is calculated by dividing the time period (210 minutes) by the natural log of the ratio of the initial amount of the substance (200 grams) to the remaining amount (31 grams).
Half-life is the amount of time it takes for a substance to decrease by half. In this case, it took 210 minutes for the sample to decrease from 200 grams to 31 grams, which is a decrease of 169 grams. This means that the half-life is 52.38 minutes, or 3,143.8 seconds.
Half-life is an important concept in physics, particularly in the study of radioactive substances. It is used to predict the decay of a substance over time, as well as the rate of decay of a substance. Knowing the half-life of a substance can help researchers determine how quickly a substance will reach a particular amount, as well as how quickly a substance will decay.
In this example, the scientist was able to determine that it took 52.38 minutes for the sample to decay by half. This allowed the scientist to determine the rate of decay and predict how much of the substance will remain after a given amount of time.
Overall, the half-life of this radioactive substance is 52.38 minutes. This is determined by dividing the time period (210 minutes) by the natural log of the ratio of the initial amount of the substance (200 grams) to the remaining amount (31 grams). Half-life is an important concept in physics that can be used to predict the rate of decay of a substance over time.
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tetracycline is an antibiotic containing multiple functional groups. which functional groups are present in this molecule? (select all that apply).
Answer: Tetracycline is an antibiotic containing multiple functional groups, including an amine group, an alcohol group, a carboxylic acid group, and a ketone group.
Tetracycline is an antibiotic containing multiple functional groups. The functional groups present in this molecule are an amine group, an alcohol group, a carboxylic acid group, and a ketone group.
The amine group is composed of nitrogen and hydrogen atoms, and is often found in organic compounds. It is also known as an amino group.
The alcohol group is composed of an oxygen and hydrogen atom bonded to a hydrocarbon group, usually a single bond. It is also known as a hydroxyl group.
The carboxylic acid group is composed of a carbonyl and hydroxyl groups, and is often found in organic compounds. It is also known as an carboxyl group.
The ketone group is composed of two oxygen atoms and two carbon atoms, and is often found in organic compounds. It is also known as a keto group.
In conclusion, tetracycline is an antibiotic containing multiple functional groups, including an amine group, an alcohol group, a carboxylic acid group, and a ketone group.
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if the actual yield for a reaction was 5.6 g, and the percent yield was 84.3%, what was the theoretical yield?
The theoretical yield was 6.64 g
To calculate the theoretical yield of a reaction, we need to use the percent yield formula and rearrange it to solve for the theoretical yield. The percent yield is defined as:
percent yield = (actual yield / theoretical yield) x 100%
Rearranging this equation, we can solve for the theoretical yield:
theoretical yield = actual yield / (percent yield/100%)
Plugging in the given values, we get:
theoretical yield = 5.6 g / (84.3%/100%)
theoretical yield = 6.64 g
Therefore, the theoretical yield of the reaction was 6.64 g.
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true or false, cross interactions between components of a mixture are represented by the ideal mixture model.
The statement "Cross interactions between components of a mixture are represented by the ideal mixture model." is False.
The ideal mixture model represents interactions between components of a mixture as zero. According to the ideal mixture model, the energy of a mixture of gases is determined entirely by the kinetic energy of the individual molecules in the mixture.
A binary solution is a mixture of two pure components. An ideal solution is one in which the behavior of each component is ideal, implying that the intermolecular forces between the different molecules are identical, as are the intermolecular forces between the like molecules. In this case, the interactions between the molecules in the solution would be identical to the interactions between the molecules in the pure liquids.
The model that represents cross interactions between components of a mixture is the non-ideal mixture model. Non-ideal mixtures are mixtures in which the intermolecular forces between the components vary from one component to the next.
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if a chemical is spilled onto the face, wait until you have washed the chemicals off before removing your glasses. group of answer choices true false
Never use a spatula to empty a bottle with solid chemicals. You will contaminate the chemical if you do this. Pour solid into your straight in place of it.
If you spill a chemical on oneself, what should you do?If this solid substance or a liquid containing it comes in touch with your skin, immediately wash it with soap and water to remove any contamination. After cleaning, seek medical assistance if the irritation continues.
What should you do if you just splattered a chemical on someone's face?The area should be immediately thoroughly flushed with water for at least 15 minutes. Try to prevent cross-contamination if flushing your eyes is not necessary.
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in which case is the stronger acid not listed first? 1. h2so4 > h2so3 2. h2o > h2s 3. h2so3 > h2so2 4. hno3 > hno
In case 4, HNO3 is not listed first, but rather HNO2. HNO3 is the stronger acid because it has a higher Ka value, meaning that it is more likely to donate a proton to form the conjugate base.
The other three cases all list the stronger acid first, meaning that it is more likely to donate a proton.
To explain further, we must first understand what Ka is and what it represents. Ka is an equilibrium constant, and it measures the strength of an acid. It is equal to the ratio of the product of the concentrations of the ions and the reactant, and the reactant concentration. A higher Ka value indicates that the acid is more likely to donate a proton, making it a stronger acid.
In case 4, HNO3 has a higher Ka value than HNO2, making it the stronger acid. However, it is listed second in the list, rather than first. This is because the list is in descending order of acid strength, so HNO2 is listed first because it is the weaker acid.
In conclusion, in case 4, HNO3 is the stronger acid, but it is not listed first. This is because the list is in descending order of acid strength, so the weaker acid is listed first.
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a solution is prepared by dissolving 99.7 g of nai in enough water to form 895 ml of solution. calculate the mass % of the solution if the density of the solution is 1.06 g/ml.
The mass % of the solution if the density of the solution is 1.06 g/ml is 10.51%
The mass of NaI = 99.7 g
Volume of the solution = 895 ml
Density of the solution = 1.06 g/ml
To calculate the mass % of the solution, we have to calculate the mass of the solution first.
Step-by-step explanation:
The formula for density is given by:
Density = Mass/Volume
Or,
Mass = Density × Volume
Now, we will calculate the mass of the solution.
Mass = Density × Volume
= 1.06 × 895= 948.7 g
Now, we will calculate the mass % of the solution.
Mass % = (Mass of solute/Total mass of solution) × 100
Mass of solute = 99.7 g
Total mass of solution = 948.7 g
Mass % = (99.7/948.7) × 100
= 10.51%
Therefore, the mass % of the solution is 10.51%.
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what is the original pressure of the gas ?
The original pressure of gas is 4 atm for given volume of 30 liters . This is taken out by boyle law.
What is boyle law ?Boyle's law is an experimental gas law that specifies the relationship between pressure and volume of a confined gas. It is also known as the Boyle-Mariotte law or Mariotte's law (particularly in France). Boyle's law states that the absolute pressure exerted by a given mass of an ideal gas is inversely proportional to the volume it occupies within a closed system if the temperature and amount of gas remain constant.According to Boyle's Law, while the temperature of a given mass of confined gas remains constant, the product of its pressure and volume remains constant as well. When comparing the same substance under two sets of conditions
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a sample of oxygen occupies 560 ml when the pressure is 800 mm hg. at constant temperature, what volume does the gas occupy when the pressure decreases to 700 mm hg?
Answer: When the pressure decreases to 700 mm Hg, the volume of oxygen gas is 640 mL.
A sample of oxygen occupies 560 ml when the pressure is 800 mm Hg. At a constant temperature, the volume of the gas when the pressure decreases to 700 mm Hg can be calculated as follows:
PV = k, where P is pressure, V is volume, and k is a constant at a constant temperature.
Thus, we can write the following equation:
P1V1 = P2V2 where P1 is the initial pressure (800 mm Hg), V1 is the initial volume (560 mL), P2 is the final pressure (700 mm Hg), and V2 is the final volume (which we want to determine).
We can rearrange the equation to solve for V2:V2
= (P1V1) / P2V2
= (800 mm Hg × 560 mL) / 700 mm HgV2
= 640 mL
Therefore, when the pressure decreases to 700 mm Hg, the volume of oxygen gas is 640 mL.
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how many moles of iron metal are produced when 3.2 mol iron (iii) oxide and 2.3 mol carbon monoxide react? fe2o3 3co -------> 2fe 3co2 step by step
Answer : When 3.2 moles of iron (III) oxide and 2.3 moles of carbon monoxide react, 2 moles of iron metal are produced.
2 moles of iron metal are produced when 3.2 moles of iron (III) oxide (Fe2O3) and 2.3 moles of carbon monoxide (CO) react. The balanced chemical equation for this reaction is: Fe2O3 + 3CO --> 2Fe + 3CO2.
This reaction is a combustion reaction, meaning it involves the oxidation of iron (III) oxide by the carbon monoxide. Oxygen from the iron oxide is released as carbon dioxide (CO2) and the iron is left in the reduced form, or elemental iron (Fe).
To calculate the moles of iron metal produced, the mole ratio of Fe2O3 to Fe must be determined. From the balanced equation, it can be seen that for every 1 mole of Fe2O3, 2 moles of Fe are produced. Therefore, to calculate the number of moles of Fe, multiply the number of moles of Fe2O3 by 2. In this case, that would be 3.2 moles of Fe2O3 x 2 = 6.4 moles of Fe.
Finally, to get the number of moles of Fe metal produced, subtract the number of moles of Fe2O3 from the number of moles of Fe. In this case, 6.4 moles of Fe - 3.2 moles of Fe2O3 = 2 moles of Fe metal.
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a solution is 0.30 m in nh3. what concentration of nh4cl would be required to achieve a buffer solution with a final ph of 9.0? recall the hh equation can be written using ph and pka or poh and pkb.
2.69 M of NH4Cl must be added to the solution to create a buffer with a final pH of 9.
A buffer solution is a solution that resists changes in pH when small quantities of an acid or base are added to it. A buffer solution is a solution that can resist changes in pH when acid or base is added to it.
The Henderson-Hasselbalch equation, which relates the pH of a buffer solution to the dissociation equilibrium constant of the weak acid, may be used to determine the pH of a buffer solution. Pka and pH can be used to derive the Henderson-Hasselbalch equation, which is as follows: pH = pKa + log([A-]/[HA]). Here, [A-] is the concentration of conjugate base, and [HA] is the concentration of weak acid. A buffer solution is created by combining a weak acid with its corresponding conjugate base, or a weak base with its corresponding conjugate acid.
When a buffer solution is formed from a weak acid and its conjugate base, it is referred to as an acidic buffer. A buffer solution made up of a weak base and its corresponding conjugate acid is known as a basic buffer. The final pH of a buffer solution is determined by the ratio of the weak acid or base to the conjugate base or acid, as determined by the Henderson-Hasselbalch equation.
pH can be calculated using the following equation: pH = pKa + log([A-]/[HA]). The NH3-NH4+ buffer is commonly used in laboratories. It is made up of ammonia (NH3) and ammonium (NH4+) in a specific ratio. NH3 is a weak base with a Kb value of 1.8 × 10−5, while NH4+ is its conjugate acid, and its Ka value is 5.6 × 10−10.In this problem, we must determine the concentration of NH4Cl required to create a buffer solution with a final pH of 9. Using the Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA]). Since the solution is 0.30 M in NH3, we know that the [A-] is 0.30 M. We must now figure out what the [HA] is to calculate the concentration of NH4Cl necessary. pH can be rearranged in the following manner: pH = pKa + log([A-]/[HA])pH - pKa = log([A-]/[HA])10^(pH - pKa) = [A-]/[HA]. We can find pKa using the Kb value of NH3: Kw = Ka × Kb = 1 × 10^-14 = 5.6 × 10^-10 × 1.8 × 10^-5Ka = 5.6 × 10^-10 / 1.8 × 10^-5 = 3.11 × 10^-6pKa = -log(Ka) = 5.51. Now, we can calculate [HA] using the following equation: [A-]/[HA] = 10^(pH - pKa) = 10^(9 - 5.51) = 0.0301. Thus, the ratio of [A-]/[HA] is 0.30/0.0301 = 9.97.
This implies that we must add NH4Cl to the solution in order to create an ammonium/ammonia buffer with a ratio of 9.97:1. To achieve this ratio, we must add NH4Cl in such a way that the [NH4+] is 9.97 times higher than the [NH3]. Assuming that the volume of the solution is 1 L, the [NH3] is 0.30 M, and the desired ratio is 9.97:1, we can compute the [NH4+] that will be necessary:[NH4+] = [NH3] × ratio = 0.30 M × 9.97 = 2.99 M. We can now calculate the amount of NH4Cl that must be added to the solution using the following equation:2.99 M - 0.30 M = 2.69 M. Therefore, 2.69 M of NH4Cl must be added to the solution to create a buffer with a final pH of 9.
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calculate the mass of so2 produced when 185 grams of oxygen reacts using this equation: 2cu2s 3o2 ----> 2cu2o 2so2 step by step
To calculate the mass of SO2 produced when 185 grams of oxygen reacts, we need to use the following equation: 2Cu2S + 3O2 ---> 2Cu2O + 2SO2.
Step 1: Calculate the molar mass of oxygen.
The molar mass of oxygen is 32.00 g/mol.
Step 2: Calculate the number of moles of oxygen.
To calculate the number of moles of oxygen, we need to divide the given mass of oxygen (185 g) by the molar mass of oxygen (32.00 g/mol).
Therefore, the number of moles of oxygen is 5.78 moles (185 g/32.00 g/mol = 5.78 moles).
Step 3: Calculate the molar ratio between oxygen and SO2.
The equation shows that for every 3 moles of oxygen, 2 moles of SO2 are produced. Therefore, the molar ratio between oxygen and SO2 is 3:2.
Step 4: Calculate the number of moles of SO2.
Since the number of moles of oxygen is 5.78 moles and the molar ratio between oxygen and SO2 is 3:2, the number of moles of SO2 is 3.85 moles (5.78 moles x 2/3).
Step 5: Calculate the molar mass of SO2.
The molar mass of SO2 is 64.07 g/mol.
Step 6: Calculate the mass of SO2 produced.
To calculate the mass of SO2 produced, we need to multiply the number of moles of SO2 (3.85 moles) by the molar mass of SO2 (64.07 g/mol).
Therefore, the mass of SO2 produced is 247.5 g (3.85 moles x 64.07 g/mol = 247.5 g).
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How many liters in 9.87 moles of 0^3
The volume (in liters) in which 9.87 moles of ozone, O₃ can occupy is 221.09 liters
How do i determine the volume?From the question given above, the following data were obtained:
Number of mole of ozone, O₃ = 9.87 molesVolume of ozone, O₃ =?The volume of 9.87 moles of ozone, O₃ can be obtained as illustrated below:
From the ideal gas theory, we understood that:
1 mole of ozone, O₃ = 22.4 Liters
Therefore,
9.87 moles of ozone, O₃ = (9.87 moles × 22.4 Liters) / 1 mole
9.87 moles of ozone, O₃ = 221.09 liters
Thus, we can conclude that the volume is 221.09 liters
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A tree bears 73 individual pieces of fruit each year. Suppose you own an orchard tht contains 120 of these trees.
a. How much fruit will the orchard produce each year?
b. The upkeep and care of the orchard costs you $850 a year. At what prices will you have to sell each piece of fruit just to break even?
The orchard will produce 8760 individual pieces of fruit each year.
What is break even ?
Break even refers to the point at which the total cost of producing a product or providing a service is equal to the total revenue generated from selling that product or service. At the break-even point, there is no profit or loss, and the business is said to be "breaking even."
In other words, the break-even point is the level of sales at which the business is earning enough revenue to cover all its costs, including fixed costs (e.g., rent, salaries) and variable costs (e.g., cost of goods sold, marketing expenses). Beyond this point, any additional sales or revenue will generate a profit for the business.
a. To calculate how much fruit the orchard will produce each year, we need to multiply the number of trees by the number of fruits each tree bears:
Total number of fruit = 120 trees × 73 fruit/tree
Total number of fruit = 8760
Therefore, the orchard will produce 8760 individual pieces of fruit each year.
b. To calculate the price at which you need to sell each piece of fruit to break even, we need to divide the total cost of upkeep and care by the total number of fruit produced, and then add this to the cost of producing each piece of fruit. This will give us the minimum price at which we need to sell each piece of fruit to cover our costs:
Cost per fruit = (Upkeep cost + Cost of producing each fruit) / Total number of fruit
Since the upkeep and care of the orchard costs $850 per year, and the orchard produces 8760 individual pieces of fruit each year, the cost of upkeep and care per fruit is:
Cost of upkeep and care per fruit = $850 / 8760
Cost of upkeep and care per fruit = $0.097
Therefore, the minimum price at which we need to sell each piece of fruit to cover our costs is:
Minimum price per fruit = Cost per fruit + Cost of upkeep and care per fruit
Minimum price per fruit = Cost of producing each fruit + $0.097
Without information about the cost of producing each piece of fruit, we cannot calculate the minimum price required to break even.
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Balance the following chemical equation. PC2H6+O2⟶CO2+H2O
The balanced chemical equation is,
[tex]2 C_{2} H_{6}[/tex] + [tex]7 O_{2}[/tex] ---> 4[tex]CO_{2}[/tex] + 6[tex]H_{2} O[/tex]
Chemical equations are defined as the symbolic representations of chemical reactions in which the reactants and the products are expressed in terms of their respective chemical formulae. Through chemical reaction reactants are converted to products. Balanced chemical equation is the symbolic representation of a chemical reaction having the symbols and chemical formulas. A chemical equation involves the reactant entities which are given on the left-hand side and have the product entities are given on the right-hand side with a plus sign between the entities in both the reactants and the products. There is an arrow that points towards the products to show the direction of the chemical reaction.
The Balanced chemical equations are defined as the chemical equation which have the same number and type of each atom on both sides of the equation. The coefficients in this equation must be the simplest whole number ratio. The mass as well as the changes are equal in the balanced chemical equation.
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The correct question is,
Balance the following chemical equation.
[tex]C_{2} H_{6}[/tex] + [tex]O_{2}[/tex] ------> [tex]CO_{2}[/tex] + [tex]H_{2} O[/tex]