You roll a die 60 times how many times do you expect to roll a factor of 12
Answer:
Just for fun, the probability of rolling a die 60 times and getting no ones is
(600)(5/6)60=0.0018% .
Step-by-step explanation:
This 10 ones is the value with the highest probability of occurring. It has a probability of (6010)(1/6)10∗(5/6)50≈13.7% .
Two teenagers work summer jobs. The first teenager earns $20 an hour plus $55 in tips for each shift worked. The second teenager earns $25 per hour and receives no tips. Each teenager worked an 8 hour shift. Who earned more money: the first teenager or the second teenager?
Answer:
1 :
20×8=$160
160+55=$215
2:
25×8=$200
the first teenager earns more money after every shift
hope this helps you :D
what is 7.364.51 to 3 decimal places
Answer:
7.265
Step-by-step explanation:
Answer:
7.364
Step-by-step explanation:
Thats my answer.Brainliest
Divide. give the quotient and remainder
2746/6
Answer:
On the image
Step-by-step explanation:
...............
Answer:
457 Remainder 4
Step-by-step explanation:
In this problem you will compare the effects of different compounding periods on the interest an investment earns. Complete the table below using the values indicated. Show the formula you used, with the correct values, in the second column. In the third column, give the result, rounded to the nearest cent.
Principal: $1,000
APR: 4.5%
Time: 10 years
Find the equations for annually, quarterly, monthly and daily
Answer:
see attached
Step-by-step explanation:
You are asked to use the compound interest formula for different values of n, the number of times per year the interest is compounded.
__
The basic formula is ...
A = P(1 +r/n)^(nt)
for the amount in an account in which principal P earns interest at annual rate r compounded n times per year for t years.
The problem statement gives values for P, r, t, so we only need to compute the result for different values of n. With the given values filled in, the formula is ...
A = 1000(1 +0.045/n)^(10n)
Values of n to be used are ...
annually: n = 1quarterly: n = 4monthly: n = 12daily: n = 365The formula you will evaluate uses these values where 'n' is in the formula. Corresponding account balances are ...
annual compounding: $1552.97quarterly compounding: $1564.38monthly compounding: $1566.99daily compounding: 1568.27__
For repetitive evaluation of the same formula, we like a calculator or spreadsheet. Many calculators have the "time value of money" formulas pre-programmed. This is shown in the second attachment, where the value that varies is "C/Y", the number of compoundings per year.
Please help me! No bots or trolls please!
Answer:
part: 17 players = 1/4
whole: 68 players in all
percent: 17 players = 25%
Step-by-step explanation:
We'll use p as a variable for the total players, alright?
So, 25% of p usually gets called back.
This season, 17 is 25% of p OR you might say 17 = 1/4 of p
in other words, p/4 = 17
multiply each side by 4 (to get the variable alone)
p = 17 * 4
p = 68
______________
part/whole = percent/100
SUBSTITUTE!
17/68 = 25%
check!
(simplify) 1/4 = 25% true!
Bella is building two wigwams for a school project on american indian tribes. she first builds two wooden frames, each in the shape of a cone with a base radius of 2 feet and a slant height of 5 feet. if bella wants to cover the frames in fabric, how many square feet of fabric will she need? (use 3.14 for pi and round to the nearest whole number. recall the formulas l a = pi r l and s a = pi r l pi r squared.) square inches
The amount of fabric needed = 2(surface area of the cone-shaped wooden frame) = 88 ft².
What is the surface Area of a Cone?Surface area of a cone = πr² + πrl
Given the following dimensions of the cone-shaped wooden frame:
Slant height (l) = 5 feetRadius (r) = 2 feetAmount of fabric needed = 2(surface area of the cone-shaped wooden frame) = 2(πr² + πrl)
= 2(3.14 × 2² + 3.14 × 2 × 5)
= 87.92
Amount of fabric needed ≈ 88 ft²
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Answer:
88
Step-by-step explanation:
Before he moved, Chet was a student at
this school, If you include Chet's ant farm in
the data, the median is 8. How many ants
does Chet's ant farm have? Explain your
reasoning
The number of ants that Chet's ant farm have based on the median given is 96 ants.
How to calculate the number ants?Your information is incomplete. Therefore, the numbers will be assumed. Let's assume that the numbers of ants in each column is 12.
In this case, when Chet's ant farm in the data, the median is 8. Therefore, the number of ants will be:
= 12 × 8
= 96 ants.
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ASAP can somebody please tell me the steps for both problems, I will also give brainliest (please list all the steps i have to show my work
The answer to #11 is: x = 15
The answer to #12 is: x = 5
The graph shows the amount in Harold's savings
account over a certain number of weeks. Find the rate
of change and record it in the grid
HELPS A GIRL OUT
An oil can is shaped like a cylinder. The radius of the oil can is 3.5 inches and its height is 10 inches. Which measurement is closest to the volume of the oil can in cubic inches? 109.9 in³ 219.8 in³ 384.8 in³ 1099 in³
Answer:
384.8 cubic inches.
Step-by-step explanation:
Help I need the awnser asap
AABC = ADEF
B
C
E
F
Match BC to the corresponding part.
EF FD
ZE
Answer:
Is it not just EF?
Step-by-step explanation:
I mean BC is the bottom of the triangle so the corresponding part is just the other triangles bottom which is EF if it was just angle B it'd be just angle E but it's not it's both B and C so it's E and F
When Sarah divided a number by 5, the quotient was 147 with a remainder. What is one possible dividend? With a complete sentence, explain how you found the dividend.
Answer: possible dividend is 736, 737, 738, 739
Step-by-step explanation: The remainder cannot be divided by 5 so it can be 1, 2, 3 and 4 added to (147 ×5)
please help me out on this question
Answer:
the train won't always go the same distance each minute and for the second one its 4 minutes
Calculate the median of the data set below. {0.3, 1.5, 3.8, 2.6, 1.5, 9.1, 4.2, 3.8, 1.5, 2.9} A. 3.8 B. 3.35 C. 2.75 D. 2.5
Answer:
2.75
Step-by-step explanation:
0.3,1.5,1.5,1.5,2.6,2.9,3.8,3.8,4.2,9.1
(smaller to greater)
middle of this is 2.6 and 2.9
so, 2.6+2.9=5.5
now we divide it by 2
so, 5.5/2=2.75
Which expressions are equivalent to 42-5? Choose all the correct answers. Show your work in arriving at your answers.
Answer:
B, C, E
Step-by-step explanation:
Exponent Rules
[tex]a^b \cdot a^c=a^{b+c}[/tex]
[tex]\dfrac{a^b}{a^c}=a^{b-c}[/tex]
[tex]a^n \cdot b^n=(ab)^n[/tex]
[tex]a^0=1[/tex]
[tex]\dfrac{1}{a^b}=a^{-b}[/tex]
[tex](a^b)^c=a^{bc}[/tex]
[tex]\textsf{A}\quad42^{-3} \cdot 42^8=42^{-3+8}=42^5[/tex]
[tex]\textsf{B}\quad \dfrac{42^{-7}}{42^{-2}}=42^{-7-(-2)}=42^{-5}[/tex]
[tex]\textsf{C}\quad \dfrac{6^{-5}}{7^5}=6^{-5} \cdot 7^{-5}=(6 \cdot 7)^{-5}=42^{-5}[/tex]
[tex]\textsf{D}\quad 42^0 \cdot 42^5=1 \cdot 42^5=42^5[/tex]
[tex]\textsf{E}\quad \left(\dfrac{1}{42^{-5}}\right)^{-1}=(42^5)^{-1}=42^{-5}[/tex]
[tex]\textsf{F}\quad \left(\dfrac{6^{-5}}{7^5}\right)^{-1}=\left(6^{-5} \cdot 7^{-5}\right)^{-1}=\left(\left(6 \cdot 7\right)^{-5}\right)^{-1}=42^{-5(-1)}=42^5[/tex]
Check one by one
#A
[tex]\\ \rm\Rrightarrow 42^{-3}42^8=42^{-3+8}=42^5[/tex]
#B
[tex]\\ \rm\Rrightarrow \dfrac{42^{-7}}{42^{-2}}=42^{-7+2}=42^{-5}\checkmark[/tex]
#C
[tex]\\ \rm\Rrightarrow \dfrac{6^{-5}}{7^5}=6^{-5}7^{-5}=42^{-5}\checkmark[/tex]
#d
[tex]\\ \rm\Rrightarrow 42^0.42^5=42^{0+5}=42^5[/tex]
#e
[tex]\\ \rm\Rrightarrow \left(\dfrac{1}{42^{-5}}\right)^{-1}=42^{-5}\checkmark[/tex]
#f
[tex]\\ \rm\Rrightarrow \left(\dfrac{6^{-5}}{7^5}\right)^{-1}[/tex]
[tex]\\ \rm\Rrightarrow (42^{-5})^{-1}[/tex]
[tex]\\ \rm\Rrightarrow 42^5[/tex]
Tyler applied the change of base formula to a logarithmic expression. The resulting expression is shown below.
StartFraction log one-fourth Over log 12 EndFraction
Which expression could be Tyler’s original expression?
Log Subscript one-fourth Baseline 12
Log Subscript 12 Baseline One-fourth
12 Log one-fourth
One-fourth log 12
Answer:
[tex]log_{12}(\frac{1}{4})[/tex]
Step-by-step explanation:
We start with our equation that the change of base formula was applied to:
[tex]\frac{log\frac{1}{4} }{log12}[/tex]
The change of base formula describes taking the base (b) of the logarithm and setting it as the denominator while taking the remaining number (a) and setting that as the numerator.
If we reverse the formula, we end up with the supplied answer.
[tex]log_{12}(\frac{1}{4})[/tex]
Answer:
Other guy is correct
Step-by-step explanation:
I need help with 19
Answer: 5/26
Step-by-step explanation:Hope this is helpful
Linda bought 2 cans of paint and 1/2 of a pint of special paint additive formulated to reduce mildew. Before painting her house, she divided the additive equally between the 2 cans of paint. How much additive did she put in each can?
What set of numbers are shaded on the
hundred chart?
A only the factors of ten
B only the multiples of 10
C only the factors of 20
D only the multiples of 20
what is the substance of 0.03 in scientific notation
Answer:
3x10 to the power of -2
Step-by-step explanation:
0.03=3x0.01
0.01=10 to the power of -2
Which equation translates the sentence, "Three times the number m plus ten is equal to n"?
A. 3m + 10 = n
B. 3(10) + m = n
C. 3 + 10m = n
D. 3 x 10(m) = n
Show your work step by step
Answer: Given that MP \\NS , RS\\PQ and MR =NQ
MRN is a straight line with sum of angles equal to 180⁰ MQN is also a straight line triangle equal to 180⁰
Angle at R + 3 = Angle at Q +2 = 180⁰
Angle R is alternate to Q and angle 2 is alternate to 3 and both sets are equal
Therefore angle 1 is equal to 4 and this makes their third angles in the triangle equal.
Triangle MQP then becomes a perfect replica of NRS
Step-by-step explanation:
2. For a simple interest rate of 10%, p.a calculate the number of year's needed for an interest of $1149.60 to be earned on an investment of $2874
Answer:
r=10%
I=1149.60
P=2874
t=(I×100)/(p×r)
(1149.60×100)/(2874×10)
114960÷28740
4 years
[tex]r = 10\%[/tex]
[tex]p = 2874[/tex]
[tex]l = 1149.60[/tex]
to find:the numbers of year's needed for the investment.
solution:[tex]t = \frac{l \times 100}{p \times r} [/tex]
[tex]t = \frac{1149.60 \times 100}{2874 \times 10} [/tex]
[tex]t = \frac{114960}{28740} [/tex]
[tex]t = 4[/tex]
therefore, 4 years is needed for the investment.
HELP PLSS
Select all of the expressions that are equivalent to 7c.
A c + 3(c + c)
B 2(c + c) +c
C 3c + 4c + c
D 2c + 4c + c
E c (2c + 2c)
D 2c + 4c + c
Step-by-step explanation:Collect Coefficients of like terms
[tex](2+4+1)\times c[/tex]
__________________________________________________
Calculate the sum or difference
[tex]7c[/tex]
__________________________________________________
Determine true/false
[tex]Determine\ whether\ 7c\ and\ 2c+4c+c\ are equivalent:[/tex]
[tex]True[/tex]
I hope this helps you
:)
The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament.
Find the mean, median, mode, range, and interquartile range of the data. Round your answers to the nearest tenth, if necessary.
The mean is.
The median is.
The modes from least to greatest are , , and.
The range is.
The interquartile range is.
The data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20
What is mean, median and mode of a data set?The mean of the data is the average value of the given data. The mean of the data is the ratio of the sum of all the values of data to the total number of values of data.
The median of the data is the middle value of the data set when it arrange in ascending or descending order.
Mode of a data set is the value, which occurs most times for that data set. The value which has the highest frequency in the given set of data is known as the mode of that data set.
The stem-and-leaf plot shows the number of digs for the top 15 players at a volleyball tournament. The table is attached below.
The data according to the table is,
41,41,43,43,45,50,52,53,54,62,63,63,67,75,97
The mean is-[tex]\mu=\dfrac{41+41+43+43+45+50+52+53+54+62+63+63+67+75+97}{15}\\\mu=\dfrac{849}{15}\\\mu=56.5[/tex]
The median is.
The arranged data according to the table is,
41,41,43,43,45,50,52,53,54,62,63,63,67,75,97
Here, the middle value is 53. Thus, the median is 53.
The modes from least to greatest are , , and.Mode is the data which occur most offen. Here the order of modes from least to greatest is,
41 41 43 43 45 50 52 53 54 62 63 63 67 75 97
The range is.Lowest value in data is 41 and highest is 97. Thus, the range is,
[tex]r=97-41\\r=56[/tex]
The interquartile range is.The third quartile of data is 63 while first quartile is 43. Thus, the interquartile range is.
[tex]IQR=63-23\\IQR=20[/tex]
Thus, the data of players of volleyball tournament, the mean is 56.5, median is 53, range is 56 and interquartile range is 20.
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What is the coefficient of the term x^2 when the expression below is simplified? (5x^2-x-1)-(-3x^2-2x-5)
Answer: 8
Step-by-step explanation:
Given:
(5x^2-x-1)-(-3x^2-2x-5)
Rewrite:
(5x² -x -1) - (-3x² -2x -5)
Distribute the negative:
5x² -x -1 + 3x² +2x +5
Reorder terms:
5x² + 3x² -x +2x -1 +5
Combine like terms:
8x² + x + 4
The coefficient of the x² term is 8,
8x² + x + 4
At Michael's school, 38% of the students have a pet dog and 24% of the students have a pet cat. Michael found that 11% of the students
had both a pet dog and a pet cat.
What is the probability that a randomly chosen student at Michael's school will have a pet dog or a pet cat?
A. 62%
B. 51%
C. 40%
D. 83%
Answer: C. 51%
Step-by-step explanation:
Match each statement in the table with one of the diagrams shown.
a o o
A
B
C
D
Statement
Diagram
All the vertices of the square touch the circle
Only one side of the square is a chord of the circle
All four sides of the square are tangents to the circle
Answer:
A
C
B
Step-by-step explanation:
A) All the corners of the square touch the edge of the circle
B) Only 1 side of the square touches the circle so it forms a chord.
C) The circle is inside the square so the sides of the square form tangents (Perpendicular lines to the radius).
prove that
{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)
First, expand the terms inside the bracket you will get
[tex](( \tan {}^{2} (x) + 2 \tan(x) \sin(x) + \sin {}^{2} (x) - ( \tan {}^{2} (x) - 2 \tan(x) + \sin {}^{2} (x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )[/tex]
[tex]( 4 \tan(x) \sin(x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )[/tex]
[tex]16 \tan {}^{2} (x) \sin {}^{2} (x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )[/tex]
[tex]16 \tan {}^{2} (x) (1 - \cos {}^{2} (x) ) = 16 (\tan(x) + \sin(x) )( \tan(x) - \sin(x) )[/tex]
[tex]16( \tan {}^{2} (x) - \frac{ \sin {}^{2} (x) \cos {}^{2} ( {x}^{} ) }{ \cos {}^{2} (x) } [/tex]
[tex]16( \tan {}^{2} (x) - \sin {}^{2} (x) ) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )[/tex]
[tex]16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )[/tex]