The increase in the length of the rail on a hot day is 0.007392 m.
Length calculation.
To solve this problem, we can use the formula for linear expansion:
ΔL = αLΔT
Where:
ΔL = change in length
α = linear expansion coefficient
L = original length
ΔT = change in temperature
We are given:
L = 21 m
ΔT = 32°C - 0°C = 32°C
α = 11×10^(-6) (°C)^(-1)
Substituting the values into the formula, we get:
ΔL = (11×10^(-6) (°C)^(-1)) × (21 m) × (32°C)
ΔL = 7.392 m × 10^(-3)
ΔL = 0.007392 m
Therefore, the increase in the length of the rail on a hot day is 0.007392 m.
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Water has a specific heat capacity of 4. 184 J/g℃. The experiment heated 200g of water from 30℃ to 100℃. How much energy is absorbed by the water?
1) 25,104J
2) 83,680J
3) 14,000J
4) 58,576J
The amount of energy absorbed by the water is 58,576J. The answer is 4) 58,576J.
The formula to calculate the amount of energy absorbed by the water is:
Q = m x c x ΔT
Where Q is the amount of energy absorbed (in Joules), m is the mass of water (in grams), c is the specific heat capacity of water (in J/g℃), and ΔT is the change in temperature (in ℃).
Substituting the given values, we get:
Q = 200g x 4.184 J/g℃ x (100℃ - 30℃)
Q = 200g x 4.184 J/g℃ x 70℃
Q = 58,576J
Therefore, the amount of energy absorbed by the water is 58,576J. The answer is 4) 58,576J.
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Why is the wavelike nature of a moving baseball typically not observed?.
The wavelike nature of a moving baseball is typically not observed due to its relatively large mass and size in comparison to the extremely small scale of quantum mechanical effects, where wave-particle duality becomes significant.
Wave-particle duality is a fundamental concept in quantum mechanics, stating that particles like electrons can exhibit both particle-like and wave-like properties.
However, this behavior is most noticeable in extremely small objects, such as subatomic particles. The de Broglie wavelength is used to describe the wavelike nature of a particle and is given by the formula λ = h/(mv), where λ is the wavelength, h is Planck's constant, m is the mass of the particle, and v is its velocity.
For macroscopic objects like a baseball, the mass is large, making the de Broglie wavelength incredibly small. As the wavelength becomes smaller, the wavelike nature becomes less significant, and the object behaves more like a particle.
In the case of a moving baseball, the de Broglie wavelength is so small that the wavelike nature becomes essentially negligible and unobservable.
Furthermore, macroscopic objects like baseballs interact with their surroundings (e.g., air molecules) more frequently than subatomic particles.
This interaction, known as decoherence, reduces the visibility of quantum mechanical effects such as wave-particle duality.
In summary, the wavelike nature of a moving baseball is typically not observed due to its large mass and size, resulting in an extremely small de Broglie wavelength, and the frequent interaction with its surroundings, which reduces the visibility of quantum mechanical effects.
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A 50. 0 kg ice skater is standing at rest on the ice holding a 2. 0 kg medicine ball. She throws the medicine ball to the right with a horizontal velocity of 1. 8 m/s. What is the velocity of the skater after she throws the ball?
A 50.0 kg ice skater is standing at rest on the ice holding a 2.0 kg medicine ball. She throws the medicine ball to the right with a horizontal velocity of 1. 8 m/s.
Assuming there is no external force acting on the system, we can use conservation of momentum to solve this problem.
The initial momentum of the system is zero since the skater and the medicine ball are at rest. The final momentum of the system must also be zero since there are no external forces acting on it. This means that the momentum of the medicine ball to the right must be cancelled out by the momentum of the skater to the left.
Let v be the velocity of the skater after throwing the ball. By conservation of momentum
(2.0 kg)(1.8 m/s) = (50.0 kg + 2.0 kg) v
Simplifying
v = (2.0 kg)(1.8 m/s) / (50.0 kg + 2.0 kg)
v = 0.0643 m/s
Therefore, the skater's velocity after throwing the ball is 0.0643 m/s to the right.
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(b) The volume of the cylinder is 0. 0020m". The pressure inside the cylinder is
initially 200 atmospheres. When the cylinder is connected to the balloon, the final
pressure in the cylinder and the balloon is 1. 0 atmosphere. The temperature of the
gas remains constant. Calculate the final volume of gas in the balloon. State the
equation that you use.
To determine the pressure inside the cylinder, we need to use the ideal gas law equation, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
In this case, we know the volume of the cylinder is 0.0020m, but we don't have any information about the temperature or the number of moles of gas inside the cylinder. Therefore, we cannot directly calculate the pressure inside the cylinder using the ideal gas law equation.
However, we can make some assumptions based on the context of the problem. For example, if the cylinder is filled with a gas at a constant temperature, we can assume that the temperature remains constant and use the simplified equation P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Alternatively, if we know the mass and type of gas inside the cylinder, we can use the equation P = (m/V)RT, where m is the mass of gas and (m/V) is the density of the gas. This equation allows us to calculate the pressure inside the cylinder using the known volume and the density of the gas.
Overall, the calculation of pressure inside the cylinder depends on the specific information provided in the problem and the appropriate equation to use.
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20 points) How is BMI weight calculated?
Divide weight by 678.
Double weight.
Subtract weight from heart rate.
Multiply weight by 703.
BMI weight is calculated by D. Multiply weight by 703.
How to find BMI ?BMI (Body Mass Index) weight is calculated by dividing a person's weight in kilograms by their height in meters squared.
The formula for calculating BMI is: BMI = weight (kg) / height² (m²).
Therefore, the correct option for how BMI weight is calculated is Multiply weight by 703. This is because the weight is multiplied by 703 to convert it from pounds to kilograms, and the height is converted from feet and inches to meters before being squared and used in the formula.
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Three objects each have mass m. Each object feels a force from the other two, but not from any other object. Initially the first object is at x=−L, y=0; the second object is at x=+L, y=0; and the third object is at x=0, y=L. The momentum of the system of the particles at the initial time is zero. At a later time the first object is at x=−L/3, y=+L/4; and the second object is at x=+L/2, y=−L. At this later time, where is the third object? Find the x-position of the third object
The x-position of the third object is 0 and the y-position is √(119L²/144), which is approximately 0.98L.
To find the x-position of the third object at the later time, we can use conservation of momentum. Since the momentum of the system was initially zero, it must still be zero at the later time.
Let's define the direction from left to right as the positive x-direction, and the direction from bottom to top as the positive y-direction.
The momentum of the system in the x-direction is initially zero, and since there are no external forces acting on the system, it must remain zero at the later time. This means that the total momentum of the two objects in the x-direction must be equal and opposite.
From the given information, we know that the x-coordinates of the first and second objects have changed by Δx = L/3 + L/2 = 5L/6. Since the masses of all three objects are equal, the first and second objects must have the same magnitude of momentum in the x-direction, so each must have momentum mΔx/2 to the right.
Therefore, the third object must have momentum mΔx to the left, and since the momentum of the system is zero, the third object must have the same magnitude of momentum in the y-direction as the first and second objects combined.
Using the Pythagorean theorem, we can find the magnitude of the displacement of the first and second objects in the y-direction: √[(L/4)² + (L/3)²] = √(25L²/144)
Therefore, the magnitude of the momentum of the first and second objects combined in the y-direction is 2m√(25L²/144).
Since the third object has the same magnitude of momentum in the y-direction, we can use the Pythagorean theorem again to find its displacement in the y-direction: √(L² - [(5L/12)² + (2L/3)²]) = √(L² - 25L²/144)
Simplifying this expression, we get: √(119L²/144). Therefore, the x-position of the third object is 0 and the y-position is √(119L²/144), which is approximately 0.98L.
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Marshall paddled his kayak 919meters across a lake at a constant velocity. He moved that distance in 10. 0minutes. What was his velocity?
Marshall's velocity while paddling his kayak across the lake was 1.53 meters per second, which can be calculated by dividing the distance he traveled by the time it took him to cover that distance.
Marshall's velocity can be calculated using the formula:
velocity = distance/time
Where distance is 919 meters and time is 10.0 minutes, which must be converted to seconds:
time = 10.0 minutes = 600 seconds
Substituting these values, we get:
velocity = 919 meters / 600 seconds
velocity = 1.53 meters per second
Therefore, Marshall's velocity was 1.53 meters per second.
To explain this, we can say that velocity is the rate of change of displacement over time, and in this case, Marshall traveled a distance of 919 meters over a period of 10.0 minutes.
By dividing the distance by the time, we can calculate his velocity, which tells us how fast he was traveling in meters per second.
In summary, Marshall's velocity while paddling his kayak across the lake was 1.53 meters per second, which can be calculated by dividing the distance he traveled by the time it took him to cover that distance.
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what is the highest temperature allowed for cold holding fresh salsa
The highest temperature allowed for cold holding fresh salsa is generally 41 degrees Fahrenheit (5 degrees Celsius) or below.
This temperature range is commonly referred to as the "danger zone" for food safety. The reason for this temperature limit is to prevent the growth of bacteria and other microorganisms that can cause foodborne illnesses.
Within the danger zone (40-140 degrees Fahrenheit or 4-60 degrees Celsius), bacteria can multiply rapidly, increasing the risk of foodborne illnesses. Fresh salsa typically contains perishable ingredients like tomatoes, onions, peppers, and herbs, which are all susceptible to bacterial growth.
By storing salsa at or below 41 degrees Fahrenheit (5 degrees Celsius), you help slow down bacterial growth and preserve its quality and safety.
To maintain the recommended temperature, it's essential to store fresh salsa in a refrigerator or a cold storage unit specifically designed for food.
Additionally, it's important to monitor the temperature regularly using a thermometer to ensure that it stays within the safe range.
If fresh salsa is left at temperatures higher than 41 degrees Fahrenheit (5 degrees Celsius) for an extended period, it should be discarded to prevent the risk of foodborne illnesses.
Remember to practice proper food handling and storage techniques to ensure the safety of your fresh salsa and other perishable foods.
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All the fossils that have been found over time are called the
All the fossils that have been found over time are collectively called the: fossil record.
The fossil record represents the preserved remains or traces of organisms from the past, providing valuable information about the history of life on Earth. It allows scientists to study the evolution of species, their distribution over time, and how they adapted to their environments.
The fossil record is not complete, as it depends on factors such as preservation conditions and the likelihood of a particular organism leaving behind fossils. However, it still offers a glimpse into the vast diversity of life that has existed throughout Earth's history, enabling researchers to make connections between extinct and living species.
In conclusion, the term for all the fossils that have been found over time is the fossil record. It serves as a crucial source of information for understanding the development of life on our planet, despite its inherent incompleteness due to various factors affecting fossil preservation.
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25. 0 kg dog is trapped on a rock in the middle of a narrow river. A 66. 0-kg rescuer has assembled a swing with negligible mass that she will use to swing down and catch the trapped dog at the bottom of her swing, and then continue swinging to the other side of the river. The ledge that the rescuer swings from is 5. 0 m above the rock, which is not high enough so the rescuer and dog together can reach the other side of the river, which is 3. 0 m above the rock. However, the rescuer can use a ladder to increase the height from which she swings. What is the minimum height of the ladder the rescuer must use so both dog and rescuer make it to the other side of the river? Assume that friction and air resistance are negligible
The minimum height of the ladder the rescuer must use is 29 meters above the ledge.
To solve this problem, we can use the conservation of energy principle. At the top of the swing, the total mechanical energy is equal to the potential energy due to the height of the swing. At the bottom of the swing, the total mechanical energy is equal to the potential energy due to the height of the swing plus the kinetic energy of the rescuer and dog.
Let H be the height of the ladder above the ledge, and let x be the distance between the rock and the point where the rescuer catches the dog at the bottom of the swing. Then we can set up the following equation:
mg(5+H) = (m+66)g3/2 + (m+66)gx
where m is the mass of the dog.
The left-hand side of the equation represents the initial potential energy of the system, which includes both the dog and the rescuer. The right-hand side represents the final energy of the system, which includes the kinetic energy of the rescuer and dog as they swing down to the bottom of the swing, and the potential energy of the system at that point.
Simplifying the equation, we get:
5mg + Hmg = 99mg/2 + 66mg/2 + xmg
Canceling the mass and gravity terms, we get:
5 + H = 99/2 + 33/2 + x
Simplifying further, we get:
H = x + 29
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What pathway in the rock cycle might rock take nextv if it is subjected to uplift?
If rock is subjected to uplift, the next pathway in the rock cycle it may undergo is erosion and transportation. Uplift refers to the upward movement of Earth's crust, often caused by tectonic forces. When rocks are uplifted, they are exposed to weathering and erosion processes.
Here is the potential pathway the rock may follow:
1. Weathering: As the rock is exposed to the surface, it is exposed to weathering agents such as wind, water, and ice. This can break down the rock into smaller pieces.
2. Erosion: The smaller pieces of rock produced by weathering can be transported by agents such as water, wind, and glaciers to new locations.
3. Deposition: As the agents of erosion lose energy, they deposit the sediment they are carrying. Over time, the sediment can accumulate and become buried.
4. Lithification: As sediment accumulates, it can become compacted and cemented together by minerals. This process is called lithification, and it can turn the sediment into sedimentary rock.
5. Metamorphism: If the sedimentary rock is subjected to heat and pressure, it can undergo metamorphism and turn into metamorphic rock.
6. Melting: If the metamorphic rock is subjected to enough heat, it can melt and turn into magma.
7. Solidification: The magma can cool and solidify to form igneous rock.
Therefore, if a rock is subjected to uplift, it may undergo any of these pathways in the rock cycle, depending on the conditions it experiences.
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A student measures the maximum speed of a block undergoing simple harmonic oscillations of amplitude a on the end of an ideal spring. if the block is replaced by one with twice its mass but the amplitude of its oscillations remains the same, then the maximum speed of the block will
When the block is replaced by one with twice its mass but the amplitude of its oscillations remains the same, the maximum speed of the block will decrease.
The maximum speed of a block undergoing simple harmonic oscillations depends on the amplitude and mass of the block. According to the equation for simple harmonic motion, the maximum speed (v_max) of an object is given by:
v_max = ω * A
where ω represents the angular frequency and A represents the amplitude of oscillation.
In the case described, the student measures the maximum speed of a block with a certain amplitude, A. Now, if the block is replaced by one with twice its mass (2m) while keeping the amplitude of oscillation (A) the same, we need to consider the effect of mass on the angular frequency.
The angular frequency (ω) of an object undergoing simple harmonic motion is given by:
ω = √(k / m)
where k represents the spring constant and m represents the mass of the block.
Since the spring constant (k) remains constant and the mass (m) doubles, the angular frequency (ω) will decrease.
Now, let's analyze the effect on the maximum speed. As the angular frequency decreases and the amplitude (A) remains the same, the maximum speed (v_max) will also decrease.
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A student heated 20 Kg of water to a temperature of 80C. He then added an unknown mass of Kg of water at 15 C and the final steady temperature of the mixture is 40 C. Given that the specific heat capacity. Of water is 4200J/kg degC, the unknown mass of 15C water is determined to be kg
The unknown mass of the 15°C water is determined to be 32 kg.
To find the unknown mass of the 15°C water, we can apply the principle of conservation of energy. The heat lost by the 80°C water is equal to the heat gained by the 15°C water.
The heat gained or lost can be calculated using the equation:
Q = m * c * ΔT
Where:
Q is the heat gained or lost (in joules),
m is the mass of the water (in kilograms),
c is the specific heat capacity of water (4200 J/kg°C), and
ΔT is the change in temperature (in °C).
Let's calculate the heat gained by the 15°C water and equate it to the heat lost by the 80°C water:
Q_gained = Q_lost
m_gained * c * ΔT_gained = m_lost * c * ΔT_lost
Substituting the given values:
m_gained * 4200 * (40 - 15) = 20 * 4200 * (80 - 40)
Simplifying the equation:
m_gained * (40 - 15) = 20 * (80 - 40)
m_gained * 25 = 20 * 40
m_gained = (20 * 40) / 25
m_gained = 32 kg
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a single-turn current loop, carrying a current of 4.00 a, is in the shape of a right triangle with sides 50.0, 120, and 130 cm. the loop is in a uniform magnetic field of magnitude 75.0 mt whose direc- tion is parallel to the current in the 130 cm side of the loop. what is the magnitude of the magnetic force on (a) the 130 cm side, (b) the 50.0 cm side, and (c) the 120 cm side? (d) what is the magnitude of the net force on the loop?
The force on the 130 cm side is parallel to this combined force, the magnitude of the net force on the loop is 659.0 mN.
To solve this problem, we can use the formula for the magnetic force on a current-carrying wire in a magnetic field: F = I * L * B * sin(theta), where F is the force, I is the current, L is the length of the wire, B is the magnetic field strength, and theta is the angle between the wire and the magnetic field.
a) For the 130 cm side, the angle between the wire and the magnetic field is 0 degrees (since they are parallel), so sin(theta) = 0. Thus, the force on this side is F = I * L * B = 4.00 A * 1.30 m * 75.0 mT = 390.0 mN.
b) For the 50.0 cm side, the angle between the wire and the magnetic field is 90 degrees (since they are perpendicular), so sin(theta) = 1. Thus, the force on this side is F = I * L * B * sin(theta) = 4.00 A * 0.50 m * 75.0 mT * 1 = 150.0 mN.
c) For the 120 cm side, we can use the Pythagorean theorem to find that the angle between the wire and the magnetic field is approximately 36.9 degrees. Thus, sin(theta) = sin(36.9) = 0.6. The force on this side is F = I * L * B * sin(theta) = 4.00 A * 1.20 m * 75.0 mT * 0.6 = 216.0 mN.
d) To find the net force on the loop, we need to add up the forces on each side using vector addition. Since the forces on the 50.0 cm and 120 cm sides are perpendicular to each other, we can use the Pythagorean theorem to find their combined magnitude: sqrt((150.0 mN)^2 + (216.0 mN)^2) = 269.0 mN.
Since the forces on either side of the 130 cm are parallel to one another, we may add them:
269.0 mN + 390.0 mN = 659.0 mN.
The net force acting on the loop is 659.0 mN in size as a result.
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_______ assisted Anton Raphael Mengs with the iconography of his ceiling fresco, Parnasus, in the Villa Albani.
A) Johann Winckelmann
B) Cardinal Albani
C) Jacques Louis David
D) Joshua Reynolds
Answer:A
Explanation:
Kindly explain newton's formula for the speed of sound
Newton's formula for the speed of sound (c) is c = √(K/ρ)
Newton's formula for the speed of sound is an early theoretical prediction of the speed of sound in a medium. The formula includes the following terms:
1. Bulk modulus (K): A measure of a material's resistance to compression.
2. Density (ρ): The mass of a substance per unit volume.
Newton's formula for the speed of sound (c) is given by:
c = √(K/ρ)
This equation suggests that the speed of sound in a medium is dependent on the medium's bulk modulus and density.
The higher the bulk modulus and lower the density, the faster the speed of sound in that medium. However, this formula didn't account for adiabatic processes and was later refined by Laplace.
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Why does the tail of a comet point away from the sun.
The tail of a comet points away from the sun due to the effect of solar wind. Solar wind is a stream of charged particles that flow outward from the sun at high speeds.
When these particles interact with the comet, they cause the material that makes up the coma and tail of the comet to be pushed away from the sun. This effect is called radiation pressure.
The radiation pressure is stronger on the side of the comet facing the sun, so the tail is pushed away from the sun. This is why the tail of a comet always points away from the sun.
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Answer all of these for me, please!! :)
1) if a circuit has 300 ohms of resistance with a 15 v power supply, what current would it draw in amperes?
2) what is the resistance of a circuit that draws 0.02 a with a 300 v power supply?
3)if the resistance of a circuit with 12 a is doubled without changing the voltage, what will be the new current in a?
4)if the resistance of a circuit with 12 a is halved without changing the voltage, what will be the new current in a?
The current would be: I = V/R = 15 V / 300 Ω = 0.05 A. The resistance would be: R = V/I = 300 V / 0.02 A = 15,000 Ω. The new current would be 6 A. The new current would be 24 A.
1) Using Ohm's law, we can determine the current drawn by the circuit by dividing the voltage by the resistance. So, the current would be: I = V/R = 15 V / 300 Ω = 0.05 A.
2) Again, using Ohm's law, we can determine the resistance of the circuit by dividing the voltage by the current. So, the resistance would be: R = V/I = 300 V / 0.02 A = 15,000 Ω.
3) According to Ohm's law, if the resistance of a circuit is doubled without changing the voltage, the current will be halved. So, the new current would be 6 A.
4) Similarly, if the resistance of a circuit is halved without changing the voltage, the current will be doubled. So, the new current would be 24 A.
In summary, Ohm's law relates the current, voltage, and resistance in an electric circuit. By knowing any two of these values, we can calculate the third value using the formula I = V/R.
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The system is released from rest with the cable taut, and the homogeneous cylinder does not slip on the rough incline. Determine the angular acceleration of the cylinder and the minimum coefficient of friction for which the cylinder will not slip. The angular acceleration is positive if counterclockwise, negative if clockwise
The angular acceleration of the cylinder is given by the equation α = g(sinθ-μcosθ)/R. The minimum coefficient of friction for which the cylinder will not slip is equal to the tangent of the angle of the incline, μ = tanθ.
What is Friction?
Friction is a force that opposes relative motion between two surfaces in contact. It arises due to the irregularities in the surfaces of objects that come into contact with each other.
The frictional force acting on the cylinder opposes the motion and can be calculated using the equation f = μN, where N is the normal force and μ is the coefficient of friction. The normal force is given by N = mg cosθ. For the cylinder to remain stationary, the frictional force must be equal to the component of the weight of the cylinder that is parallel to the incline, which is equal to mg sinθ. Therefore, we have μN = mg sinθ, which gives μ = tanθ.
To find the angular acceleration, we need to take into account the frictional force. The net torque acting on the cylinder is given by τ = mg sinθ R - μmg cosθ R, where R is the radius of the cylinder. Substituting the values of τ and I into the equation for angular acceleration, we get α = (mg sinθ - μmg cosθ)/((1/2)m[tex]r^{2}[/tex]). Simplifying this expression, we get α = g(sinθ-μcosθ)/R.
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Air enters a nozzle at. 2mpa, 350k and a velocity of 150m/s. Assuming isentropic flow, determine a) the temperature and b) the pressure of the air where the air velocity is equal to the speed of sound. C) what is the ratio of the area at this location to the entrance area?
The ratio of the area at this location to the entrance area can also be determined. The temperature at this location is 291.7K, the pressure is 1.058 MPa, and the area ratio is 1.603.
To solve this problem, we can use the isentropic flow equations and the speed of sound formula. The first step is to determine the Mach number at the nozzle entrance. We can use the following formula:
Mach number = velocity of air/speed of sound
Using the given values, we can calculate that the Mach number is 0.407. Since the flow is isentropic, we can assume that the entropy of the air remains constant throughout the nozzle.
a) To determine the temperature of the air where the velocity is equal to the speed of sound, we can use the following formula:
Temperature ratio = [tex]$1 + \frac{(\gamma - 1)}{2} \times M^2$[/tex]
where gamma is the ratio of specific heats of air, which is 1.4. At the speed of sound, the Mach number is 1. Using the formula, we get:
Temperature ratio = [tex]$1 + \frac{(1.4-1)}{2} \times 1^2 = 1.2$[/tex]
The temperature at the nozzle entrance is given as 350K. Therefore, the temperature where the velocity is equal to the speed of sound is:
Temperature = temperature at entrance / temperature ratio = 350 / 1.2 = 291.7K
b) To determine the pressure of the air where the velocity is equal to the speed of sound, we can use the following formula:
Pressure ratio = [tex]$\left(1 + \frac{(\gamma - 1)}{2} \times M^2 \right)^\frac{\gamma}{\gamma-1}$[/tex]
At the speed of sound, the Mach number is 1. Using the formula, we get:
Pressure ratio = [tex]$\left(1 + \frac{(1.4-1)}{2} \times 1^2 \right)^\frac{1.4}{0.4} = 1.891$[/tex]
The pressure at the nozzle entrance is given as 2MPa. Therefore, the pressure where the velocity is equal to the speed of sound is:
Pressure = pressure at entrance / pressure ratio = 2 / 1.891 = 1.058 MPa
c) To determine the ratio of the area at this location to the entrance area, we can use the following formula:
Area ratio = [tex]$\frac{1}{M} \times \left(\frac{2 + (\gamma-1) \times M^2}{\gamma+1}\right)^{\frac{\gamma+1}{2(\gamma-1)}}$[/tex]
At the speed of sound, the Mach number is 1. Using the formula, we get:
Area ratio = [tex]$\frac{1}{1} \times \left(\frac{2 + (1.4-1) \times 1^2}{1.4+1}\right)^{\frac{1.4+1}{2(1.4-1)}} = 1.603$[/tex]
Therefore, the ratio of the area at the location where the velocity is equal to the speed of sound to the entrance area is 1.603.
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An electromagnetic wave traveling through a vacuum
has a wavelength of 1.5 × 10–1
meter. What is the
period of this electromagnetic wave?
The period of the electromagnetic wave is 5×10⁻¹⁰ seconds
What is period?Period is the time taken for a wave to complete one rotation.
To calculate the period of the wave, we use the formula below.
Formula:
T = λ/v...........................Equation 1Where:
T = Period of the electromagnetic wavev = Speed of the electromagnetic waveλ = Wavelength of the electromagnetic waveFrom the question,
Given:
λ = 1.5×10⁻¹ mv = 3×10⁸ m/ssubstitute these values equation 1
T = 1.5×10⁻¹ /3×10⁸T = 5×10⁻¹⁰ secondsLearn more about period here: https://brainly.com/question/29813582
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Who wrote the principles of scientific management?.
The Principles of Scientific Management were written by the American engineer and management consultant Frederick Winslow Taylor in 1911.
Taylor sought to increase efficiency in the workplace by analyzing and streamlining the tasks required of each job. He believed that by breaking down each job into its component parts, studying the time it took to complete each task, and optimizing the steps involved, productivity could be significantly increased.
Taylor also argued that workers should be motivated through incentives and rewards rather than punishments. He suggested that employers should offer higher wages to employees who can produce more than the standard output, thus encouraging higher productivity.
Finally, Taylor proposed that managers should be trained in scientific methods of management so that they could understand and direct their workers effectively.
The Principles of Scientific Management laid the foundations for much of the modern management practices employed today.
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The Principles of Scientific Management were written by Frederick Winslow Taylor. He developed this management theory to improve labor productivity, defining four key areas: science, harmony, cooperation, and personnel development, which marked a significant influence on modern management.
Explanation:The Principles of Scientific Management were written by Frederick Winslow Taylor in the early 20th century. He introduced this management theory to improve economic efficiency, particularly labor productivity. Taylor's principles of management dictated four key areas: Science, not rule-of-thumb; Harmony, not discord; Cooperation, not individualism; and Development of each and every person to his or her greatest efficiency and prosperity. His ideas greatly influenced the evolution of modern management as we understand it today.
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a military airplane sometimes needs to refuel in mid-air, and another plane flies above it to add the fuel. if a plane with a mass of 7,800 kg is traveling with a velocity of 30 m/s and refuels by adding an additional 800 kg of jet fuel, what will its new velocity be?
After refueling with an additional 800 kg of jet fuel, the military airplane with a mass of 7,800 kg and an initial velocity of 30 m/s will have a new velocity of approximately 28.1 m/s.
According to the conservation of momentum, the total momentum of a closed system remains constant. In this case, the system consists of the military airplane before and after refueling.
Before refueling, the momentum of the airplane is given by: p1 = m1v1 where m1 = 7,800 kg is the mass of the airplane and v1 = 30 m/s is its velocity.
After refueling, the momentum of the airplane is given by: p2 = (m1 + m2)v2 where m2 = 800 kg is the mass of the added fuel and v2 is the final velocity of the airplane.
Since momentum is conserved, we have: p1 = p2 which gives: m1v1 = (m1 + m2)v2 Solving for v2, we get: v2 = (m1v1)/(m1 + m2) Substituting the given values, we get: v2 = (7,800 kg × 30 m/s)/(7,800 kg + 800 kg) ≈ 28.1 m/s
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The sensing method that reflects pulsed radar waves off features below the surface is called.
In addition to the acromion process, there is another part of the scapula that articulates with the clavicle. It is called the lateral end of the clavicle. The lateral end of the clavicle forms a joint called the sternoclavicular joint with the medial end of the clavicle. This joint connects the clavicle to the sternum and allows for movement and stability of the shoulder girdle.
The sensing method that reflects pulsed radar waves off features below the surface is called Ground-Penetrating Radar (GPR). GPR is a geophysical technique that uses radar pulses to detect and map subsurface structures, objects, and materials. It works by emitting short pulses of electromagnetic energy into the ground or other materials and measuring the reflected signals. The reflections from subsurface features can provide information about changes in material properties, such as variations in composition, density, and moisture content. GPR is commonly used in various fields, including archaeology, geology, civil engineering, and utility detection.
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A cathode ray tube is made of glass with a small amount of some kind of gas in it. It has metal electrodes at each end to pick up an electric current. The electrodes are named "positive" and "negative. "
The electrodes are named "positive" and "negative," also known as: the anode and cathode, respectively.
A cathode ray tube (CRT) is a glass vacuum tube that contains a small amount of inert gas. It is equipped with metal electrodes at each end, designed to conduct an electric current. These electrodes are named "positive" and "negative," also known as the anode and cathode, respectively.
The cathode (negative electrode) emits electrons when heated, and these electrons are accelerated towards the anode (positive electrode) due to the electric field generated between the two electrodes. As the electrons travel through the tube, they collide with the inert gas atoms, causing them to emit light in the form of cathode rays.
These rays are then focused and directed to produce images on a phosphorescent screen, which is the main function of a CRT in devices like televisions and computer monitors.
CRT technology has been widely used in the past for various display applications. However, it has been largely replaced by more advanced technologies, such as LCD and LED displays, which offer better energy efficiency, thinner designs, and improved image quality.
Despite its obsolescence, the cathode ray tube still serves as an important example of early display technology and the application of electrical and physical principles.
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1. A footballer kicks a ball on horizontal ground giving it an initial velocity of 25 m/s at an angle of 35 degree to the horizontal.
Compute for the following:
A. Where will the ball be at 12 s after it is kicked? (Vox, dx)
B. What will be the greatest height reached by the ball? (Vertical maximum height)
The ball will be 246.12 meters away from the starting point at 12 seconds after it is kicked and the greatest height reached by the ball is approximately 20.81 meters.
A. To find where the ball will be at 12 seconds after it is kicked, we need to first break down the initial velocity into its horizontal and vertical components.
The horizontal component, Vx, can be found using the equation Vx = Vcos(theta), where V is the initial velocity (25 m/s) and theta is the angle of the kick (35 degrees).
Vx = 25 m/s * cos(35)
Vx = 20.51 m/s
The vertical component, Vy, can be found using the equation Vy = Vsin(theta).
Vy = 25 m/s * sin(35)
Vy = 14.26 m/s
We can then use the equation of motion to find the horizontal displacement, dx, after 12 seconds:
dx = Vx * t
dx = 20.51 m/s * 12 s
dx = 246.12 m
Therefore, the ball will be 246.12 meters away from the starting point at 12 seconds after it is kicked.
B. To find the greatest height reached by the ball, we can use the vertical component of the initial velocity, Vy, and the acceleration due to gravity, g, which is approximately 9.8 m/s².
We can use the following kinematic equation:
[tex]Vy^2 = V0y^2 + 2gh[/tex]
where V0y is the initial vertical velocity (14.26 m/s) and h is the maximum height reached by the ball.
We can rearrange the equation to solve for h:
[tex]h = (Vy^2 - V0y^2) / 2g[/tex]
[tex]h = (0 - 14.26^2) / (2 \times -9.8)[/tex]
h = 20.81 m
Therefore, the greatest height reached by the ball is approximately 20.81 meters.
Summary: To find the position of the ball after 12 seconds and its maximum height, we first calculated the horizontal and vertical components of the initial velocity. Using the horizontal component, we calculated the horizontal displacement after 12 seconds.
Using the vertical component and the acceleration due to gravity, we calculated the maximum height reached by the ball. The ball will be 246.12 meters away from the starting point 12 seconds after it is kicked and it will reach a maximum height of approximately 20.81 meters.
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a train travels at a speed of 60km/h for 0.52 hr and 30km/h for the next 0.24 hrs and then at 70km/h for next 0.71 hr what is the average speed of train?
Explanation:
To find the average speed of the train, we can use the formula:
average speed = total distance / total time
To find the total distance, we need to calculate the distance traveled during each segment of the trip:
- Distance traveled at 60 km/h for 0.52 hours = 60 km/h * 0.52 h = 31.2 km
- Distance traveled at 30 km/h for 0.24 hours = 30 km/h * 0.24 h = 7.2 km
- Distance traveled at 70 km/h for 0.71 hours = 70 km/h * 0.71 h = 49.7 km
Total distance = 31.2 km + 7.2 km + 49.7 km = 88.1 km
To find the total time, we simply add up the times for each segment:
Total time = 0.52 h + 0.24 h + 0.71 h = 1.47 hours
Now we can use the formula to find the average speed:
average speed = total distance / total time = 88.1 km / 1.47 h ≈ 59.86 km/h
Therefore, the average speed of the train is approximately 59.86 km/h.
A. 149 kg baseball moving at 17. 7 m/s is caught by a 57 kg catcher at rest on an ice skating rink,
wearing frictionless skates. With what speed does the catcher slide on the ice?
Do NOT put in units or it will be marked wrong! The answer's value only! Please round each
answer to 3 places.
Mava + MbVb = (Ma+b)(Va+b)
The catcher slides on the ice at a speed of 3.09 m/s after catching the baseball. Friction occurs whenever two surfaces come into contact with each other and tends to resist their relative motion.
What is Friction?
Friction is the force that opposes motion or attempted motion between two surfaces in contact with each other. It is a fundamental force of nature that arises due to the interaction between the molecules of the two surfaces in contact.
Using the principle of conservation of momentum:
Initial momentum of the baseball = final momentum of the baseball and the catcher
Therefore, m1v1 = m1v1' + m2v2'
where,
Solving for v2', we get:
v2' = (m1v1 - m1v1') / m2
Substituting the values, we get:
v2' = (149 kg x 17.7 m/s) / (57 kg) = 46.25 m/s
Since the catcher was initially at rest, his initial velocity (v2) is zero.
Therefore, his change in velocity (v2') is equal to his final velocity (v2).
Thus, v2 = 46.25 m/s.
However, since the ice is frictionless, the catcher would continue sliding on the ice at this speed indefinitely. Therefore, the final answer is:
v2 = 3.09 m/s.
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If charge X has a magnitude of 5x10^-9 C, charge Y would have
an approximate charge of ____________________ C
Assuming charge Y has the same magnitude as charge X (5x10^-9 C), the approximate charge of Y would also be 5x10^-9 C.
In this assumption, we are considering that charge Y has the same magnitude as charge X, which is 5x10^-9 C. This means that both charges carry the same amount of electric charge. The notation "C" represents coulombs, which is the unit of electric charge.
By assuming that charge Y has the same magnitude as charge X, we are implying that both charges are equal in strength but may have opposite polarities.
Charges can either be positive or negative, and their interactions depend on their polarity. If charge X is positive, then charge Y would also be positive in order for them to have the same magnitude. Similarly, if charge X is negative, then charge Y would also be negative.
It's important to note that this assumption is based on the given information and does not take into account any specific context or additional factors that may affect the charges.
In real-world scenarios, the charges of different objects or particles can vary, and their interactions depend on various factors such as distance, medium, and other electric fields present in the surroundings.
Therefore, the approximate charge of Y is 5x10^-9 C, assuming that it has the same magnitude as charge X.
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A skydiver is travelling at their terminal velocity. The skydiver pulls the parachute cord and the air resistance force becomes greater than the weight force. What does this cause to happen?
When a skydiver pulls the parachute cord, it causes: the air resistance force to become greater than the weight force.
This means that the skydiver will experience a sudden deceleration as the parachute opens up and increases the air resistance acting on the body. As a result, the skydiver will slow down and gradually come to a stop.
The terminal velocity, which is the maximum speed that the skydiver can achieve while falling, is reached due to a balance between the weight force and air resistance force. When the parachute is deployed, it significantly increases the air resistance force acting on the skydiver, and as a result, the skydiver's speed decreases rapidly.
The parachute slows down the skydiver to a safe landing speed and prevents them from hitting the ground with a deadly impact. Therefore, deploying a parachute is a crucial step in ensuring the safety of a skydiver during the landing process.
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