A user is asked to type a caption for a photo in a web form's text field. If the caption didn't end with a punctuation mark (. ! ?), a period should automatically be added. A common error is to end with a comma, which should be replaced by a period. Another common error is to end with two periods, which should be changed to one period (however, ending with three periods (or more) indicates elipses so should be kept as is). The corrected caption is output. If the input is "I like pie", the output is "I like pie." If the input is "I like pie!", the output remains "I like pie!" If the input is "Coming soon…", the output remains "Coming soon…"

Answer:

count = 0

while True:

   people = int(input("Enter the number of people arrived/departed: "))

   count += people

   if count == 100:

       print("The bar is full")

       break

   elif count < 100:

       print("There are " + str(count) + " in the bar currently")

   else:

       print(str(people) + " people cannot enter right now")

       print("The maximum capacity is 100!")

       count -= people

       print("There are " + str(count) + " in the bar currently")

Explanation:

*The code is in Python.

Set the count as 0

Create an indefinite while loop.

Inside the loop:

Ask the user to enter the number of people arrived/departed

Add the people to the count (cumulative sum)

Check the count. If the count is 100, stop the loop. If the count is smaller than 100, print the current number of people. Otherwise, state that they cannot enter right now. The capacity is 100 at most. Subtract the people from the count and print the current number of people.

Answer: data

Explanation:

Answer: A. Record Macro dialog box.

Explanation:

Answer: a

Explanation:

Answer:

Naphtha is used to dilute heavy crude oil to reduce its viscosity and enable/facilitate transport; undiluted heavy crude cannot normally be transported by pipeline, and may also be difficult to pump onto oil tankers. Other common dilutants include natural-gas condensate, and light crude.

Answer:

Naphtha is used for laundry soaps and clearing fluids

High Hopes^^

Barry-

Answer:

Its D

Explanation:

On edg

Answer: don’t show on title slide

Explanation:

Answer: all answers for test are

Slide Master View

Layout and Theme

PowerPoint Template

A.

C.

Slide Master Thumbnail, Insert Tab, Header &Footer, Slide tab in the dialog box.

D.

C.

D.

Explanation:

The first thing Harry should do is select the Slide Master View, Next, he should use the command groups to edit the Layout and Theme. Finally, he should save the file as a new PowerPoint Template.

It is a presentation-based programme that employs graphics, movies, etc. to enhance the interactivity and appeal of a presentation.

A saved Powerpoint presentation has the ".ppt" file extension. PPT is another name for a PowerPoint presentation that includes slides and other elements.

This right-sided brain activity is perfectly suited to the principal function of PowerPoint presentations.

For his PowerPoint presentation, Harry wants each slide to have a consistent appearance.

Harry must first choose the Slide Master View before using the command groups to change the Layout and Theme. The file should then be saved as a fresh PowerPoint Template.

Thus, this way, Harry can create a uniform look.

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Answer:

wireless technology that lets you identify and track objects  (radio frequency identification)

medical uses of RFID  (patient identification)

a low-power radio wave used for short distances  (bluetooth)

computing device used with Bluetooth hands-free microphone in car

Explanation:

sorry if late :/

Answer:

Explanation:

edg 2021

Answer:

The answer to this question is given below in the explanation section

Explanation:

The correct answer is RAM.

RAM is used for storing programs and data currently being processed by the CPU.  So, the data in the RAM, can be easily accessible and processed by the CPU more fastly.

While Mass memory and neo volatile memory is not correct options. because these types of memory can stores a large amount of data but CPU fetch data from these memories into RAM. and, RAM can only be used by the CPU when performing operations.

Answer:

D. if else inside a for loop

Explanation:

Answer:

C. double-clike the table

Explanation:

Edg

Answer:

c

Explanation:

Answer:

the motherboard

Explanation:

Answer:

If your discussing colleges and degrees, you cant take courses your not autorized to take.

So if you have one major and wish to change to another then you need to discuss with a student advisor or counseler so they can make the changes. They will also discuss which classes are necessary for your program of choosing, making sure all your requirements are completed.

Explanation:

Answer: Directors

Explanation:  directors create motion pictures, television shows, live theater, commercials, and other performing arts productions. directors work under a lot of pressure, and many are under stress to finish their work on time.  Work hours for producers and directors can be long and irregular.

Answer:

Preheat the oven, mix the ingredients, put into oven.

Answer:

Preheat oven, mix the ingredients, put into oven

Explanation:

basically its B

:)

Answer:

The answer to this question is given below in the explanation section. the correct option is C.

Explanation:

This is Java code statement:

System.out.print("Computing\nisInfun");

The output of this code statement is

Computing

isInfun

However, it is noted that the C option is not written correctly, but it is guessed that it will match to option C.

This Java code statement first prints "Computing" and then on the next line it will print "isInfun" because after the word "Computing" there is a line terminator i.e. \n. when \n will appear, the compiler prints the remaining text in the statement on the next line.

Answer: c

Explanation:

c

Answer:

It's C

Explanation:

On edg

Answer:

C is correct

Explanation:

I got it on edg

Cats are better than dogs

The average function in Microsoft Excel calculates the mean of the cells.

The required formula is: =AVERAGE(E4:E11)

The syntax of the average function is: =AVERAGE(cells-range)

From the question, the cell range is: cell E4 to cell E11

This means that, the average formula would be:

=AVERAGE(E4:E11)

Hence, the formula to enter in cell E13 is:

=AVERAGE(E4:E11)

Read more about Excel formulas at:

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Answer:

Follows are the solution to this question:

Explanation:

In point a:

N = Size of window = 4

Sequence Number Set = 1,024

Case No. 1:

Presume the receiver is k, and all k-1 packets were known. A window for the sender would be within the range of [k, k+N-1] Numbers in order

Case No. 2:

If the sender's window occurs within the set of sequence numbers [k-N, k-1]. The sender's window would be in the context of the sequence numbers [k-N, k-1]. Consequently, its potential sets of sequence numbers within the transmitter window are in the range [k-N: k] at time t.

In point b:

In the area for an acknowledgment (ACK) would be [k-N, k-1], in which the sender sent less ACK to all k-N packets than the n-N-1 ACK. Therefore, in all communications, both possible values of the ACK field currently vary between k-N-1 and k-1.

Answer:

Explanation:

Recursive:

C++ program to find factorial of given number  

#include <iostream>  

using namespace std;  

unsigned int factorial(unsigned int n)  

{  

   if (n == 0)  

       return 1;  

   return n * factorial(n - 1);  

}  

// Driver code  

int main()  

{  

   int num = 5;  

   cout << "Factorial of "

        << num << " is " << factorial(num) << endl;  

   return 0;

Iterative:

// C++ program for factorial of a number  

#include <iostream>  

using namespace std;  

unsigned int factorial(unsigned int n)  

{  

   int res = 1, i;  

   for (i = 2; i <= n; i++)  

       res *= i;  

   return res;  

}  

// Driver code  

int main()  

{  

   int num = 5;  

   cout << "Factorial of "

        << num << " is "

        << factorial(num) << endl;  

   return 0;  

}

Answer:

c

Explanation:

Answer:

If you still can't figure it out look this up

nvcc cafe problem

Explanation:

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

#include <cstring>  //to manipulate C-strings

#include <string>  //to manipulate strings

using namespace std;  //to access objects cin cout

//function prototypes

void upper(char *);  to convert to upper case

void lower(char *);  //to convert to lower case

void reverse(char *);  //to convert to reverse case

int main() {  //start of main method

   char input[101];  //creates a char type array to hold input string

   cout << "Enter a string: ";  //prompts user to enter a string

   cin.getline(input, 101);  //reads input string from user

   upper(input);  //calls upper() method to convert the string to upper case

   lower(input);  //calls lower() method to convert the string to lower case

   reverse(input); } //calls reverse() method to convert the string to reverse case

void upper(char *cString){  //method that takes a pointer to a C-string as it's only argument and converts that string to upper case

   cout << "String in upper case: ";  //displays string in upper case

   for(int i = 0; i < strlen(cString); i++){  //iterates through the input string cString until the length of the cString is reached

       if(islower(cString[i]))  //checks if the character at i-th index of cString is in lower case

           cout << (char) toupper(cString[i]);  //converts each i-th character of cString to upper case at each iteration

       else  //if no character of cString is in lower case

           cout << cString[i];    }  //displays the cString as it is

   cout << endl;}  //prints a new line

void lower(char *cString){  //method that takes a pointer to a C-string as it's only argument and converts that string to lower case

   cout << "String in lower case: "; //displays string in lower case

   for(int i = 0; i < strlen(cString); i++){  //iterates through each character using for loop  first character to last

       if(isupper(cString[i]))  //checks if the character at i-th index of cString is in upper case

           cout << (char) tolower(cString[i]);  //converts each i-th character of cString to lower case at each iteration

       else  //if no character of cString is in upper case

           cout << cString[i];    }  //displays the cString as it is

           cout << endl; }  //prints a new line

void reverse(char *cString){  //method that takes a pointer to a C-string as it's only argument and converts that string to reverse case (upper to lower and vice versa)

   cout << "String in reverse case: ";  //displays string in reverse case

   for(int i = 0; i < strlen(cString); i++){  //iterates through each character using for loop  first character to last

       if(isupper(cString[i]))  //checks if the character at i-th index of cString is in upper case

           cout << (char) tolower(cString[i]);  //converts character at i-th position of cString to lower

       else  //if the character is in lower case

           cout << (char) toupper(cString[i]);    }  //converts character at i-th position of cString to upper

   cout << endl;}  //prints a new line

Explanation:

I will explain the program with an example.

Lets suppose user enters "hi" as input. So

Now first upper() method is called by passing this C-string to it.

It has a for loop that checks at each iteration, if a character of C-string is in lower using islower method which returns true if the character is in lower case. Since both the characters 'h' and 'i' are in lower in case so they are converted to upper case at each iteration using toupper() method. So the output of this part is:

String in upper case: HI

Now next lower() method is called by passing this C-string to it.

It has a for loop that checks at each iteration, if a character of C-string is in upper using isupper method which returns true if the character is in upper case. Since both the characters 'h' and 'i' are in lower in case so the string remains as it is. So the output of this part is:

String in lower case: hi

Now next reverse() method is called by passing this C-string to it.

It has a for loop that checks at each iteration, if a character of C-string is in upper using isupper method which returns true if the character is in upper case. Since both the characters 'h' and 'i' are in lower so else part: cout << (char) toupper(cString[i]); executes which converts these characters to upper case (reverse case). So the output of this part is:

String in reverse case: HI

The screenshot of program output with a different example is attached.

Answer:

-is positioned relative to the browser window

Hope this helps!

Answer: When you set the position property for a block element to fixed, the element  remains in an exact position on the screen even if the page is scrolled down.

Answer:

Its A, B, C, and F

Explanation:

On edg

Rename existing ribbon tabs, Rearrange ribbon commands, Add commands to existing groups and Add a new contextual tab to the ribbon.

A PowerPoint presentation is a type of visual aid that creates a slideshow of information that can be presented to an audience using Microsoft PowerPoint software.

It is typically made up of a series of slides that include text, images, charts, graphs, and other multimedia elements to convey information to the audience.

Kim can complete the following tasks by using the Customize Ribbon dialog box:

Thus, Kim cannot use the Customize Ribbon dialog box to add new PowerPoint commands or a new main tab to the ribbon.

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Answer:

Format Shape pane

Text Options

Shrink text on overflow

Explanation:

Answer:

Format Shape pane

Text Options

Shrink text on overflow

Explanation:

100%

Answer:

#include <iostream>

#include <vector>

using namespace std;

/* Define your function here */

vector<int> GetUserValues(vector<int>& userValues, int numValues) {

  int tmp = 0;

  vector<int> newVec;

  for(int i = 0; i < numValues; i++) {

     cin >> tmp;

     newVec.push_back(tmp);

  }

  return newVec;

}

void OutputIntsLessThanOrEqualToThreshold(vector<int> userValues, int upperThreshold) {

  for (int i = 0; i < userValues.size(); ++i) {

     if(userValues.at(i) < upperThreshold) {

          cout << userValues.at(i) << " ";

     }

  }

  cout << endl;

}

int main() {

  vector<int> userValues;

  int upperThreshold;

  int numValues;

  cin >> numValues;

  userValues = GetUserValues(userValues, numValues);

  cin >> upperThreshold;

  OutputIntsLessThanOrEqualToThreshold(userValues, upperThreshold);

  return 0;

}

Explanation:

Perhaps their is a better way to code this, but I couldn't figure out what to do with the pointer in the first function.