A wagon wheel is a ring (hoop) of mass 77.1 kg and radius of 0.630 m. If it has 182 J of rotational KE, what is its angular velocity?

Answer:

Hey I would say Dust

hope this helped

Answer:

The answer is A/Dust

Explanation:

Explanation:

Starburst galaxies have the highest rates of star formation.

Central dominant galaxies are the ones which are largest individual galaxies in the universe.

The collective activity of many supernova events in a relatively small volume of a galaxy can create galactic wind.

The energy for all active galactic nuclei is thought to come from in-fall of matter into supermassive black holes.

Radio galaxies are often characterized by sources of immense energy located hundreds of thousands of light-years away on either side of their centers.

Answer:

position 3

Explanation:

in position 3 PE is least as height is least

so KE is most as energy is always conserved

The average speed of the car is 24 m/s. The average speed of the car is therefore below 25.0 m/s.

The description of rapidity. a change in the location of an object in either direction or speed. How fast something is going is determined by the distance travelled and the time required to cover that distance. Speed is a scalar quantity since it just has an arrow-like direction and no magnitude.

The entire movement of an item, independent of direction, is called distance. Distance may be characterized as the quantity of ground covered, regardless of the starting or finishing points of an item.

distance (d) = 9 miles = 14.4841 km

d = 14484.1 m

1 miles = 1609.34 m

t₁= 14484.1/ 20

 = 724.2 sec

t₂= 14484.1/ 30= 482.8 sec

total time ( t) = t+t

t= 724.2+ 482.8 = 1207 sec

Vavg = 2d/t= 2*14484.1/1207

Vavg = 24m/s

24< 25

lessthan 25m/s

car average speed (Vavg) = 24 m/s.

Therefore, the car average speed is 24 m/s.

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Answer:

RT = 341.62 Ohms

Explanation:

Given the following data;

R1 = 420 Ohms

R2 = 320 Ohms

R3 = 160 Ohms

To find the equivalent resistance;

From the circuit, we can see that R1 and R2 are connected in parallel;

Mathematically, the total equivalent resistance of resistors connected in parallel is given by the formula;

[tex] RT = \frac {R1*R2}{R1 + R2} [/tex]

Substituting into the formula, we have;

[tex] RT1 = \frac {420*320}{420 + 320} [/tex]

[tex] RT1 = \frac {134400}{740} [/tex]

RT1 = 181.62 Ohms

Next, we resolve the resistors to form a series circuit.

RT = RT1 + R3

RT = 160 + 181.62

RT = 341.62 Ohms

Answer:

hlfzuprsuo4sljfxuptdpi5ekcg

Answer:

You can not find out an answer with this information

Explanation:

Provide some sort of graph

The identical formula for the two angles is Asin(b),Asin(b).

The general word for interference effects involving edges or apertures is diffraction. In waves with longer wavelengths than those of light, diffraction is more common. Diffraction, for instance, is what causes sound to swell when it goes through a doorway or bend around corners. Diffraction causes water waves along a rocky coast to widen as they pass through the rocks. Usually, Fresnel and Fraunhofer diffraction regimes are distinguished.

Fresnel diffraction is the regime in which the diffracted waves are observed relatively close to the site of the diffraction (in comparison to the size of the item causing the diffraction). Working with Fresnel diffraction is typically very challenging. The Fraunhofer diffraction regime is the more manageable of the two.

angle 1 = asin(λb),

angle 2 = asin(−λb)

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The balloon will be drawn to the wall once it has been rubbed sufficiently to build up a sufficient negative charge. Even though the wall should generally be neutrally charged, its charges can change, causing a positively charged region to pull the negatively charged balloon toward it.

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The amount of effort force applied by Diana if this was an ideal machine is 250 N.

The load is typically divided by the number of ropes to determine the effort. The mass must be divided by the quantity of ropes.

Hours per person, days, weeks, or something else could be your unit of work. (If you are using a scrum-based project approach, you may have chosen to assess effort in relative terms, using points (story points), in which case you can omit any information in the Effort fields.)

For instance, when using a shovel, you keep one end steady to serve as the fulcrum and use the other hand to pull up on a load of dirt. The dirt being scooped up is the resistance force, and the second hand is the effort force.

Given:

Load force = 1000 N

Load distance = 5.00 m

Effort distance = 20.0 m

For ideal machine,

Effort force × Effort distance = Load force × Load distance

[tex]Effort force= \frac{1000*5.00}{20.0}[/tex]

Effort force = 250N

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Statement D. They have sufficient gravity to make themselves round accurately describes a similarity between all planets in terms of this movement and the presence of mass to form such a celestial body.

All planets need to have gravity in order to orbit around major celestial bodies, i.e., stars such as in the case of the earth planet or Mars, they orbit around the Sun which is the star of the solar system. The presence of the attractive force of gravity allows planets to move in a cycle across their stars.

Therefore, with this data, we can see that all planets have gravity and orbit around major celestial bodies and thus they can be considered to share the particularity to have a well defined orbit due to the presence of mass.

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Two physics concepts that interact with one another to keep a satellite in orbit are the gravitational force and the centrifugal force.

The apparent outward force that a rotating mass experiences is known as centrifugal force. Imagine a ball being whirled around on a string or the outward motion you experience when driving around a curve. Since the system is not rotating in an inertial frame, there is no outward acceleration. The ball or your body just continues to go in the same direction that they did at first. However, they seem to be accelerating away in the rotating reference frame of the string or the car. The direction of centrifugal force is always outward and away from the axis because the Earth revolves around a fixed axis. Thus, in the equator and at the poles of the Earth, it is the opposite of the direction of gravity.It is zero at the poles of the Earth.

One of the four fundamental forces of the universe is gravity. A centripetal force is necessary in nonlinear motions like the planetary motion. In the study of disciplines like astronomy, physics, space exploration, cosmology, and many others, both of these forces are crucial.

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Answer:

Seafloor spreading is a geologic process in which tectonic plates—large slabs of Earth's lithosphere—split apart from each other. ... As tectonic plates slowly move away from each other, heat from the mantle's convection currents makes the crust more plastic and less dense

Explanation:

hope it helps stay safe

Answer:

Magma comes out of the rift valley.

Magma cools to rock and hardens.

Rock is pushed away as new rock is formed at MOR.

Oceanic crust and continental crust meet at the trench.

Oceanic crust bends down under the continental crust.

Gravity pulls rock towards mantle.

Rock melts to mantle.

Explanation:

Hope it helps!

Please mark as Brainiest!!

Answer:

In the medium where the angle of incedence is 10°

Explanation:

This is because angle of incedence is directly proportional to refractive index of a medium.

Since refractive index is inversely proprtional to speed of light in medium, it will be the case.

The ball requires a total of zero work to go to the right at 24 m/s.

Take into account the ball's kinetic energy.

Vi = -24 ms-1 for the initial velocity

Final velocity: vf = +24ms⁻¹

K = 12mvf²- 12mvi² = 12m(vf² - vi²) = 12m(242 - 242) = 0,

meaning that the ball does not undergo any effort.

As an alternative, think about the effort made to stop the ball.

W1 = ½m(0 – 24²) = 0.5 × 0.06 × –576 = –17.28J

Work required to accelerate the ball from rest to +24 milliseconds per second was W2 = 12m(242 - 0) = 0.5 0.06 576 = +17.28 J.

Therefore, the sum of the work is W = W1 + W2 = -17.28 + 17.28 = 0 J.

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Answer:

cell wall hope this will help

Answer:

The geological features that is not created by the movement of the Earth's plates is Canyons.

The piece of sausage need to make 55 pizza is 21 × 55 = 1155.

The typical baking time for a pizza is 8 to 15 minutes, and larger, thicker pizzas bake more slowly than thin-crust, petite pizzas with few toppings. Just a friendly reminder: never lose sight of the pizza.

The "2 pizza rule" is a formula for determining how many people to invite to a gathering. Every meeting had to be small enough for two large pizzas to feed everyone, according to the rule.

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The amount of energy stored in a battery is measured in watt-hours (Wh), kilowatt-hours (kWh), or ampere-hours (Ah) (Ahr).

Potential energy is stored energy that is affected by the relative position of various components of a system. When a spring is squeezed or extended, its potential energy increases. A steel ball has higher potential energy when lifted above ground than when it falls to Earth.

Because every item moved from its resting posture has stored energy, it is referred to as potential energy because it has the ability to accomplish work when released.

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Answer:

6m/s

Explanation:

formula used; S= d/t

the "7th Street"doesn't matter it's just apart of the scenario. The only thing that matters is the distance and time which we have. the speed in seconds is 6. I had the same question on my phsyics quiz lol.

Hence, the ladder top to touch ground the ladder base should pull back a distance of ( 6 - 3 ) = 3 meters on ground As the rate of sliding of base of ladder is 0.5 meter per second , it takes a time of [  3/ (0.5) ] = 6 seconds.

What is Distance? Distance is the total movement of an object without any regard to direction. We can define distance as to how much ground an object has covered despite its starting or ending point.

Distance measures length. For example, the distance of a road is how long the road is. In the metric system of measurement, the most common units of distance are millimeters, centimeters, meters, and kilometers.

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Answer:

To solve this problem, you can use the principle of transverse static equilibrium. This states that the sum of the forces acting on an object must be equal to zero for the object to be in equilibrium. In this case, the forces acting on the rod are the tension in the strings, the weight of the rod, and the weight of the masses hung on the rod.

First, you can find the weight of the rod by multiplying its mass by the acceleration due to gravity:

Wrod = mrod * g

= 0.7 kg * 9.8 m/s^2

= 6.86 N

Next, you can find the weight of the 4.0-kg mass by multiplying its mass by the acceleration due to gravity:

W1 = m1 * g

= 4.0 kg * 9.8 m/s^2

= 39.2 N

You can find the weight of the 2.0-kg mass in the same way:

W2 = m2 * g

= 2.0 kg * 9.8 m/s^2

= 19.6 N

To find the tension in the strings, you can use the principle of transverse static equilibrium. The forces acting on the rod are the tension in the strings, the weight of the rod, and the weight of the masses hung on the rod. You can represent these forces as vectors acting at the points where the strings are attached to the rod. The vectors representing the tension in the strings will be equal in magnitude but opposite in direction. The vectors representing the weight of the rod and the masses will act vertically downward.

[asy]

unitsize(2cm);

pair P1, P2, P3, P4;

P1 = (0,0);

P2 = (1,0);

P3 = (0.8,0);

P4 = (0.2,0);

draw((-1,0)--(2,0));

draw((0,-1)--(0,1));

draw(P1--P3,red,Arrow(6));

draw(P2--P4,red,Arrow(6));

draw(P3--P4,red,Arrow(6));

draw((P1)--(P1+(0,-0.7)));

draw((P2)--(P2+(0,-4)));

draw((P2)--(P2+(0,-2)));

label("$T_1$", (P1 + P3)/2, red);

label("$T_2$", (P2 + P4)/2, red);

label("$W_{rod}$", (P3 + P4)/2, red);

label("$W_1$", (P2 + P4 + (0,-4))/2, red);

label("$W_2$", (P2 + P4 + (0,-2))/2, red);

label("$12$ cm", (0,0.2), red);

label("$20$ cm", (0.4,-0.4), red);

label("$25$ cm", (0.75,-0.4), red);

[/asy]

The sum of the forces in the x-direction must be equal to zero, so you can set up the following equation:

T1 - T2 = 0

The sum of the forces in the y-direction must also be equal to zero, so you can

If friction is neglected, at any given instant both objects will have the same c) Height.

Friction is the resistance to motion that results from two objects rubbing against one another. Two objects rubbing against one another causes friction. Motion is opposed by friction, which works against the motion.

When an object slides over another object, friction slows it down. As a result, energy is used. However, the energy does not fade away. Kinetic energy, also referred to as moving energy, is transformed into heat energy. We rub our hands together when it's cold because of this. Rub them together, and friction and heat will result.

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(a) The charge carrier density doubles,(b) The current density doubles, (c) The electron drift velocity doubles, (d) The average time interval between collision halved.

I = nq[tex]v_{d}[/tex]A

where n is the charge/volume

I is the current.

q is the charge per carrier

[tex]v_{d}[/tex] is the drift velocity of the charge carriers

A is the cross-sectional area of current flow

Here,

a) The charge carrier density (n) doubles if I doubles.

b) The charge carrier density (J = I/A is the current density).  If I doubles, J doubles.

c)  The electron drift velocity ([tex]v_{d}[/tex]) doubles if I doubles.

d)  The average time interval between collisions depends inversely on [tex]v_{d}[/tex].  If I doubles, [tex]v_{d}[/tex] doubles, so the average time between collisions is halved.

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The acceleration of the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.

Acceleration is the rate of change of velocity. At any point on a trajectory, the magnitude of the acceleration is given by the rate of change of velocity in both magnitude and direction. Acceleration of the body that we can consider is the increasing value of the velocity of any object at a constant rate and that of wee can calculate. Hence by the primary information that we have we can formerly consider that the acceleration which is acting on the particle at t=0 is zero because the particle is in rest position and did not moving at any of the instance or travelling at an uniform speed through out the whole journey or yet did not start from the source point.

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The frequency of the cart's motion for a distance of 10.0 meters is 0.075 Hz (Hertz), which means the cart completes 0.0775 round trips per second.

1) Period (T):

The period (T) is the time taken for one complete round trip. The cart travels from one end to the other and back in one round trip.

T =  (distance/speed)

T = (10.0 / 0.75 )

T = 13.33 seconds

So, the period of the cart's motion for a distance of 10.0 meters is approximately 13.33 seconds.

2) Frequency (f):

The frequency (f) is the number of complete round trips per unit time. It is the reciprocal of the period.

f = 1 / T

f = 1 / 13.33

f =  0.075 Hz

So, the frequency of the cart's motion for a distance of 10.0 meters is approximately 0.075 Hz (Hertz), which means the cart completes approximately 0.0775 round trips per second.

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Answer:

Exposure occurs when a person comes into contact with hazard

According to the given information the velocity is .0148 m/s2 and the kinetic energy is 3.78 J.

The movement that an item or particle experiences with regard to time is expressed vectorially as velocity. One metre per second (m/s) is the accepted unit of flow speed (also known as speed).

The metric speed unit is the meter per minute (m/s). A different way to express velocity magnitude is in centimeters per second (cm/s).

vilocity = 5/(5.8×5.8)

            = 0.148

kinetic energy = 1/2mv^2

                        = 1/2 × (0343 × 0.148×0.148)

                        = 3.78 J

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The velocity of the hammer of mass 1.9 kg is 11.07 m/s.

Velocity is the rate of change of displacement.

To calculate the velocity of the hammer, we use the formula below.

Formula:

Where:

Substitute these values into equation 1

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The probability that a particular nucleus of Element A will decay between 5 and 10 hours is 0.7, and the probability that a particular nucleus of Element A will decay between 5 and 20 hours is 0.9.

What is nucleus?

Nucleus is a fundamental subatomic particle which is present in the atoms of all chemical elements. It is composed of protons and neutrons and is the heaviest and most densely packed constituent of atoms. It is the core of an atom, and it is the positive charge that attracts the electrons, which are negatively charged particles. The nucleus is surrounded by a cloud of electrons which determine the properties of the atom and its chemical behavior. The size of the nucleus is typically around one hundred-thousandth of the diameter of the atom. It is held together by strong nuclear forces and has a diameter of around 10-15 femtometers.

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The probability that a particular nucleus of Element A will decay between 5 and 10 hours is 1/2 and the probability that a particular nucleus of Element A will decay between 5 and 20 hours is 7/8.

The total number of identical nuclei present in the nucleus affects how likely it is that the nucleus will disintegrate per second in a radioactive sample. Each nucleus breaks down on its own, regardless of any external factors. Consequently, the likelihood of nuclei disintegrating is the same.

The expression for the disintegration equation is given by

N(t) = N₀[tex]e^{-\lambda t}[/tex]            .... (1)

The half-life of the particle for 5 hours is given by

N(5) = N₀/2

Substitute in equation (1) to get

N₀[tex]e^{-\lambda t}[/tex] = N₀/2

[tex]e^{-\lambda t}[/tex] = 1/2

λ = ln2/5

The half-life of a particle for 10 hours is given by

N(10) = N₀/4

N₀[tex]e^{-\lambda t}[/tex] = N₀/4

[tex]e^{-\lambda t}[/tex] = 1/2

λ = ln4/10

The probability of disintegration is given by:

P = N(5) - N(10)/N(5)

Substitute the values, to get

P = (N₀/2 - N₀/4)/(N₀/2)

= (N₀(2-1)/4)/ N₀(1/2)

= 1/2

The probability of element decay between 5 to 10 hours is 1/2.

Now, the half-life of a particle for 20 hours is given by

N(20) = N₀/16

N₀[tex]e^{-\lambda t}[/tex] = N₀/16

[tex]e^{-\lambda t}[/tex] = 1/16

λ = ln16/20

The probability of disintegration is given by:

P = N(5) - N(1\20)/N(5)

Substitute the values, to get

P = (N₀/2 - N₀/16)/(N₀/2)

= (N₀(8-1)/16)/ N₀(1/2)

= 7/8

The probability of element decay between 5 to 20 hours is 7/8.

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