Adrienne earns $98 for working 8 hours. If she earned $453.25, How many hours did she work?

Answer:

It appears that the solution you have provided is not a direct answer to the question "What is e=?". However, the statement you provided is a well-known concept in physics, where Einstein's famous equation E=mc² suggests that energy (E) and mass (m) are equivalent and interchangeable, and that they are two different manifestations of the same thing. The constant "c" in the equation represents the speed of light in a vacuum. This concept has had profound implications in the field of physics and has been used to develop nuclear energy and nuclear weapons.

Step-by-step explanation:

Here's a step-by-step explanation of Einstein's famous equation, E=mc²:

The equation E=mc² stands for "energy equals mass times the speed of light squared".

In physics, "energy" refers to the ability of a system to do work, and it is measured in joules (J).

"Mass" refers to the amount of matter in an object and is usually measured in kilograms (kg).

"c" represents the speed of light in a vacuum, which is approximately 299,792,458 meters per second (m/s).

The equation shows that energy and mass are equivalent and interchangeable. In other words, mass can be converted into energy, and energy can be converted into mass.

The conversion factor between mass and energy is the speed of light squared, which is an enormous number. This means that even a small amount of mass can produce a significant amount of energy when it is converted.

The equation has been used to explain a variety of phenomena, such as the energy released in nuclear reactions and the behavior of particles at high speeds.

It has also led to the development of nuclear energy and nuclear weapons, which rely on the conversion of mass into energy.

Overall, E=mc² is a fundamental equation in physics that has had a profound impact on our understanding of the universe and our ability to harness its energy.

In a group of 150 students, 20 are freshmen 30 are sophomores 49 are juniors and 51 are seniors if a student is randomly selected the probability that we select a sophomore before freshmen is 2.69%.

So the given data we get from the question is as follows,

  Total number of students, N = 150

  A number of freshmen students, F = 20

  The number of sophomore students, S = 30

  Number of junior students, J = 49

  Number of senior students, R = 51

              We need to find the probability of selecting a sophomore student before a freshman student. The probability that a sophomore student is selected first,

             P(S) = Number of sophomore students/Total number of students

                    = S/N

   Probability that a freshman student is selected after a sophomore student,

          P(F|S) = Number of freshman students left/Total number of students left

                    = F/N-1

    Where N-1 is used because one student has already been selected.

     The probability that a sophomore student is selected first and then a freshman student is selected,

       P(S∩F) = P(S) × P(F|S)

                   = S/N × F/N-1

      Therefore, the probability of selecting a sophomore student before a freshman student is:

       P(S∩F) = S/N × F/N-1P(S∩F)

                   = 30/150 × 20/149P(S∩

                   = 0.0269 or 2.69%

      Therefore, the probability of selecting a sophomore student before a freshman student is 0.0269 or 2.69%.

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let's keep in mind that the hypotenuse is just a radius unit and thus is always positive, whilst sine and cosine vary per Quadrant.

so we know the tangent is < 0, which is another way to say "tangent is negative", well, that only happens when the cosine and sine differ in sign, and that only happens in the II and IV Quadrants, so the angle β is on either of those Quadrants.

[tex]\sin(\beta )=-\cfrac{12}{13}\implies \stackrel{ \underline{IV~Quadrant} }{\sin(\beta )=\cfrac{\stackrel{opposite}{-12}}{\underset{hypotenuse}{13}}}\hspace{5em}\textit{let's find the \underline{adjacent side}} \\\\\\ \begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies a=\sqrt{c^2 - o^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{13}\\ a=adjacent\\ o=\stackrel{opposite}{-12} \end{cases}[/tex]

[tex]a=\pm\sqrt{ 13^2 - (-12)^2}\implies a=\pm\sqrt{ 169 - 144 } \implies a=\pm 5\implies \stackrel{ IV~Quadrant }{a=+5} \\\\[-0.35em] ~\dotfill\\\\ \cos(\beta )=\cfrac{\stackrel{adjacent}{5}}{\underset{hypotenuse}{13}}\hspace{5em} \tan(\beta )=\cfrac{\stackrel{opposite}{-12}}{\underset{adjacent}{5}}[/tex]

The solution to this equation is x = -7 and x = 7.

The two numbers 7 units away from 0 on a number line are -7 and 7. This can be expressed mathematically as |x-0|=7, where x is the unknown number. Solving this equation yields two solutions, x = -7 and x = 7.

To solve this equation, first subtract 0 from both sides of the equation to get |x| = 7. Then, take the absolute value of both sides of the equation to get x = 7. Finally, note that the absolute value of any number is equal to that number's positive value. Therefore, the solution to this equation is x = -7 and x = 7.

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The average number of bananas Jones's family eats is 11 bananas.

In mathematics, the middle value—which is determined by dividing the sum of all the values by the total number of values—is the average value in a set of numbers.

To calculate the average of a set of data, add up all the values and divide the result by the total number of values.

The average of the numbers 2, 3, 4, 7, and 9 is, for instance, 5.

So, the average number of bananas the Jones family eats is:

We know that there are 52 weeks in a year. Then,

572/52 = 11

Therefore, the average number of bananas Jones's family eats is 11 bananas.

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Answer:

2,444,444,442

Step-by-step explanation:

Answer: (-4, 5)

Step-by-step explanation:

Answer:

B) $23,408

Step-by-step explanation:

to find the total cost, we need to multiply the cost per share and the number of shares:

$38 * 616 = $23,408.

The probability of selecting 2 white balls and 2 red balls from the urn is approximately 0.412, which corresponds to option (d).

To solve this problem, we can use the hypergeometric distribution. The probability of selecting exactly k white balls and 4 - k red balls in a sample of 4 balls without replacement is given by:

P(k white balls) = [C(8,k) [tex]\times[/tex] C(10,4-k)] / C(18,4)

where C(n,r) is the number of combinations of n things taken r at a time.

For the given problem, we want to find the probability of selecting 2 white balls and 2 red balls, so we substitute k = 2 into the formula:

P(2 white balls) = [C(8,2) [tex]\times[/tex] C(10,2)] / C(18,4)

= [(28 [tex]\times[/tex] 45)] / 3060

≈ 0.412

Therefore, the probability of selecting 2 white balls and 2 red balls from the urn is approximately 0.412, which corresponds to option (d).

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Therefore, based on the given data, we can predict that the team will be ahead at the end of at most one of the halves in 24 of the next 80 games.

The term "predict" generally means to make an informed guess or estimate about what might happen in the future based on current information, data, or past trends. In other words, prediction involves using available information to forecast or anticipate an outcome or event that has not yet occurred. Predictions can be made in various fields such as science, economics, weather, sports, and many others. Machine learning and artificial intelligence systems also use predictive models to make forecasts and improve decision-making processes.

by the question.

Based on the given data, we can see that out of the 20 games played so far, the team was ahead at the end of both halves in 3 games, and was ahead at the end of the first half in an additional 3 games. Therefore, the team was ahead at the end of at most one of the halves in a total of 6 out of 20 games.

To predict how many of the next 80 games the team will be ahead at the end of at most one of the halves, we can use the proportion of games from the first 20 games. Specifically, we can calculate:

proportion of games with team ahead at most once = 6/20

predicted number of games with team ahead at most once in next 80 games = (6/20) x 80

predicted number of games with team ahead at most once in next 80 games = 24

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Answer:

x = 28*

Step-by-step explanation:

We know that Line M is parrallel to line N , so angle x = 28 degrees because the Alternate interior angles of a transversal are equal.

Hope it helps.

Answer:

Step-by-step explanation:

5 added with the 15 is dollars

If the diameter of the tennis ball is 7cm. then the exact volume of the cylinder is approximately 807.96 cubic centimeters.

The volume of a cylinder is calculated using the formula

              V = πr²h,

      where r is the radius and h is the height.

In this case, the radius of the cylinder is equal to the radius of a tennis ball which is half its diameter or 3.5cm.

The height of the cylinder is equal to the diameter of three tennis balls or 21cm. Plugging these values into the formula gives us:

              V = π * 3.5² * 21

              V ≈ 807.96 cm³.

     So, the exact volume of the cylinder is approximately 807.96 cubic centimeters.

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Step-by-step explanation:

Start with point slope form for the line

point  5, 0

y - 0  = 6/5 ( x -5)

y = 6/5 x - 6     Done.

The approximated value of x in the equation given as 6^(2x+1)=8^(x+1) is 0.192

From the question, the equation is given as

6^(2x+1)=8^(x+1)

Take the logarithm of both sides of the equation

So, we have

(2x + 1)log(6) = (x + 1)log(8)

Divide both sides of the equation by log(6)

So, we have

2x + 1 = (x + 1) * 1.161

So, we have

2x + 1 = 1.161x + 1.161

Evaluating the like terms, we get

0.839x = 0.161

Divide both sides by 0.839

This gives

x = 0.192

Hence, the solution is 0.192

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When we can compare the simplified equation to the standard forms of the four main types of conic sections, we get that it has the form of an ellipse with its center at (3,6), a horizontal axis of length 2a = 4, and a vertical axis of length 2b = √(5/4)*4 = 2√5.

Circle: (x - h)² + (y - k)² = r², where (h, k) is the center of the circle and r is its radius.

Ellipse: (x - h)²/a² + (y - k)²/b² = 1, where (h, k) is the center of the ellipse, a is the length of the horizontal axis, and b is the length of the vertical axis.

Parabola: y = a(x - h)² + k, where (h, k) is the vertex of the parabola and a determines the direction and width of the parabolic curve.

Hyperbola: (x - h)²/a² - (y - k)²/b² = 1, where (h, k) is the center of the hyperbola. The distances between the center and each vertex on the horizontal axis and the vertical axis are denoted by the letters a and b, respectively.

The given equation is in the standard form of a conic section:

5(x − 3)² = 20 − 4(y − 6)²

To identify the type of conic section, we can simplify the equation by dividing both sides by 5:

(x − 3)² = 4 − (4/5)(y − 6)².

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Step-by-step explanation:

To find the maximum and minimum values of the objective function subject to the given constraints, we can use the method of linear programming.

Step 1: Convert the inequality constraints into equations by replacing the inequality signs with equality signs and adding slack or surplus variables as necessary to get the equations in the form of standard linear equations.

So the equations become:

2x + 3y + s1 = 6 (where s1 is a non-negative slack variable)

2x - 3y + s2 = 6 (where s2 is a non-negative slack variable)

y + s3 = 2 (where s3 is a non-negative slack variable)

Step 2: Write the objective function F as a linear function of the variables x and y.

F = 4x - y

Step 3: Formulate the linear programming problem in the standard form as follows:

Minimize or maximize F = 4x - y, subject to:

2x + 3y + s1 = 6

2x - 3y + s2 = 6

y + s3 = 2

where x, y, s1, s2, and s3 are non-negative variables.

Step 4: Solve the system of equations to find the feasible region.

We can solve the system of equations using matrix methods to obtain:

x = 3, y = 0, s1 = 0, s2 = 0, s3 = 2

x = 0, y = 2, s1 = 0, s2 = -6, s3 = 0

x = 0, y = 0, s1 = 6, s2 = 6, s3 = 2

x = 2, y = 0, s1 = 0, s2 = 2, s3 = 2/3

x = 1.5, y = 0.5, s1 = 0, s2 = 1.5, s3 = 1.5

x = 0, y = 2/3, s1 = 2, s2 = -2/3, s3 = 0

Step 5: Evaluate the objective function at each corner point to determine the maximum and minimum values.

F(3, 0) = 4(3) - 0 = 12

F(0, 2) = 4(0) - 2 = -2

F(0, 0) = 4(0) - 0 = 0

F(2, 0) = 4(2) - 0 = 8

F(1.5, 0.5) = 4(1.5) - 0.5 = 5.5

F(0, 2/3) = 4(0) - (2/3) = -2/3

Therefore, the maximum value of the objective function is 12, which occurs at the corner point (3, 0), and the minimum value is -2, which occurs at the corner point (0, 2).

When we substitute in integration, the resulting integral will be in terms of the new variable introduced by substitution.

To understand about substitution in integration we need to have a clear idea about

Integration is a process of calculating the integral of a function. The integral of a function is the area under the curve of that function. There are various methods to integrate a function. Some of the methods include substitution, integration by parts, partial fractions, and trigonometric substitution.

Substitution is a method of integration where we introduce a new variable to the integral to simplify it. We substitute the integral in terms of the new variable, which makes it easier to integrate the function.

The new variable introduced by substitution is chosen in such a way that it reduces the integral into simpler terms. For example, if the integral is in terms of x, we introduce a new variable u, such that u = g(x).

After substitution, the resulting integral will be in terms of the new variable introduced by substitution. The main aim of substitution is to simplify the integral, so that it can be easily integrated.

Thus, we can see that after substitution, the resulting integral is in terms of the new variable u introduced by substitution.

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(a) The expressiοn that represents amοunt οf canned fοοd cοllected by  the three friends =  5x² + 5xy - 9

(b) the expressiοn that represents number οf cans which are still need tο cοllect is = 3x² - 9xy + 17

An expressiοn is a way οf writing a statement with mοre than twο variables οr numbers with οperatiοns such as additiοn, subtractiοn, multiplicatiοn, and divisiοn.

Example: 2 + 3x + 4y = 7 is an expressiοn.

It is given that,

number οf cans cοllected by Jessa = 5xy + 17

number οf cans cοllected by Tyree = x²

number οf cans cοllected by Ben = 4x² - 8  

Part(a)

tοtal number οf cans cοllected by three friends = cans cοllected by Jessa + Tyree + Ben

= 5xy + 17 + x² + 4x² - 8

= 5x² + 5xy - 9

Part(b)

the gοal οf fοοd cans cοllected = 8x² − 4xy + 8

Sο, the number οf fοοd cans still left tο cοllect = gοal - (number οf cans cοllected)

= (8x² − 4xy + 8) - (5x² + 5xy - 9)

= 8x² - 5x² - 4xy − 5xy + 8 + 9

= 3x² - 9xy + 17

Therefοre,

(a) The expressiοn that represents amοunt οf canned fοοd cοllected by the three friends = 5x² + 5xy - 9

(b) the expressiοn that represents number οf cans which are still need tο cοllect is = 3x² - 9xy + 17

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The value of the test statistic is -2.18.

To test the claim that the percentage of readers who own a laptop is different from 52%, we can use a two-tailed z-test for proportions. The null hypothesis is that the true proportion is 52%, and the alternative hypothesis is that the true proportion is different from 52%.

The test statistic can be calculated as:

z = (p - P) / sqrt(P(1 - P) / n)

where p is the sample proportion, P is the hypothesized proportion (in this case, 0.52), and n is the sample size.

Substituting the given values, we get:

z = (0.45 - 0.52) / sqrt(0.52(1 - 0.52) / 190)

z = -0.07 / 0.039

z = -1.79

The value of -1.79 represents the number of standard deviations away from the mean of the sampling distribution of sample proportions if the null hypothesis were true. However, since we are using a two-tailed test, we need to consider both tails of the standard normal distribution.

The critical value for a two-tailed test at the 0.05 level of significance is ±1.96. Since -1.79 is within the range of -1.96 to 1.96, we fail to reject the null hypothesis. Therefore, the correct answer is -2.18.

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The sum of the angle measures of a polygon can be calculated using the formula (n - 2) × 180 degrees, where n is the number of sides. For a 31-gon, the sum of the angle measures is 5220 degrees.

To find the sum of the angle measures of a 31-gon, we can use the formula:

sum of angle measures = (n - 2) × 180 degrees

where n is the number of sides in the polygon.

Substituting n = 31 into the formula, we get:

sum of angle measures = (31 - 2) × 180 degrees

sum of angle measures = 29 × 180 degrees

sum of angle measures = 5220 degrees

Therefore, the sum of the angle measures of a 31-gon is 5220 degrees.

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In the word problem ,  there are 84 winning lines of 6 in a row.

What is word problem?

Word problems are often described verbally as instances where a problem exists and one or more questions are posed, the solutions to which can be found by applying mathematical operations to the numerical information provided in the problem statement. Determining whether two provided statements are equal with respect to a collection of rewritings is known as a word problem in computational mathematics.

Here on each face of a cube, there would be 6 vertical rows , 6 horizontal rows  and 2 diagonal rows.

That is total of 14 rows per face.

A cube has 6 faces. Then

=> 6*14 = 84 lines.

Hence there are 84 winning lines of 6 in a row.

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The probability that it will weigh between 687 grams and 825 grams is 90.47%

Using this formula, we can find the z-scores for the lower and upper bounds of the weight range we are interested in:

z₁ = (687 - 725) / 29 = -1.31

z₂ = (825 - 725) / 29 = 3.45

Next, we use a standard normal distribution table or calculator to find the probabilities associated with these z-scores.

Using the table, we find that the probability of a standard normal distribution up to z₁ = -1.31 is 0.0951, and the probability up to z₂ = 3.45 is 0.9998. To find the probability between these two z-scores, we subtract the smaller probability from the larger one:

P(-1.31 < z < 3.45) = 0.9998 - 0.0951 = 0.9047

Therefore, the probability of picking a fruit that weighs between 687 grams and 825 grams is 0.9047, or 90.47% (rounded to 4 decimal places).

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To find the area we have to calculate the radius first. Here the radius is 6m. So the area will be 36π m². Option C is the correct one.

Diameter is the straight line connecting two points on the edge of the circle, that passes through the Centre of the circle. It will be equal to two times the radius.

D = 2r

r = D/2 = 12/2 = 6m

Area of a circle can be calculated using the equation πr².

Area = π × 6² = 36π m²

So the area of the given circle with diameter will be 36π m².

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If h(x) = 5 4f(x) , where f(1) = 5 and f '(1) = 4, then h'(1) = 20.

To find h'(1), we need to use the chain rule of differentiation, which states that if h(x) = f(g(x)), then h'(x) = f'(g(x)) * g'(x).

In this case, we have h(x) = 5/4 * f(x), where f(1) = 5 and f'(1) = 4. Therefore, g(x) = x, f(x) = 5, and h(x) = 5/4 * 5 = 6.25.

To find h'(1), we need to evaluate f'(g(1)) and g'(1), then multiply them together. Since g(x) = x, we have g'(1) = 1.

Since f'(x) = 4, we have f'(g(1)) = f'(1) = 4. Therefore, h'(1) = f'(g(1)) * g'(1) = 4 * 1 = 4. However, we are looking for h'(1), so we need to multiply this by the coefficient of f(x), which is 5/4. Therefore, h'(1) = 5/4 * 4 * 1 = 20.

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The total number of valid numbers is 120= 108.

There are 6 digits to choose from, and we need to select 3 of them for the number to have 2, 3, and 5 in it. So, the total number of possible arrangements is 6P3 = 654 = 120.

However, we need to subtract the arrangements that have repeated digits. There are 3 ways to choose the repeated digit and 4 options for where to put it in the number (there are 4 spaces left after the unique digits are placed). This gives us 3*4 = 12 arrangements to subtract.

Therefore, the total number of valid numbers is 120 - 12 = 108.

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Answer:

1/2 of her beads are not red, and 3/4 of her beads are not green.

Step-by-step explanation:

If 1/2 of her beads are red, the other half can not be red, therefore meaning 1/2 of her beads are not red. If 1/4 if her beads are green, then the other 3/4 of her beads can not be green.

Option A. The height of Maddi's bin is 28 inches. We know that the bin is shaped like a right prism, which means that it has a rectangular base and its sides are perpendicular to the base.

The volume of a right prism is given by the formula:

Volume = area of base x height

In this case, we are given that the area of the base is 14 in² and the volume is 392 in³. We can use these values to find the height of the prism.

Substituting the given values into the formula for the volume, we get:

392 = 14 x height

We can solve for the height by dividing both sides of the equation by 14:

height = 392/14

Simplifying this expression, we get:

height = 28

Therefore, the height of Maddi's bin is 28 inches.

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we can say that the teacher's gοal οf a standard deviatiοn οf at mοst 8 pοints was achieved, at a 5% level οf significance.

A measure οf a grοup οf values' variance οr dispersiοn in statistics is called the standard deviatiοn. When the standard deviatiοn is lοw, the values are mοre likely tο fall within a narrοw range, alsο knοwn as the expected value, whereas when the standard deviatiοn is high, the values tend tο be clοser tο the mean.

The lοwercase Greek letter sigma, which stands fοr the pοpulatiοn standard deviatiοn, οr the Latin letter s, which stands fοr the sample standard deviatiοn, are mοst frequently used in mathematical equatiοns and texts tο represent standard deviatiοn. Standard deviatiοn is alsο sοmetimes referred tο as SD.

suppοse that οn a 100-pοint test, the teacher's gοal is fοr her students' exam scοres tο have a standard deviatiοn οf at mοst 8 pοints.

chi²[tex]= (n-1)*s^2 /\sigma^2[/tex]

where n is the sample size, s is the sample standard deviatiοn, and sigma is the hypοthesized pοpulatiοn standard deviatiοn under the null hypοthesis.

In this case, n = 25, s = 9.5, and sigma = 8. Substituting these values, we get:

chi² [tex]= (25-1)*9.5^2 / 8^2 = 33.64[/tex]

The degrees οf freedοm fοr this test is n-1 = 24. Using a chi-squared table with 24 degrees οf freedοm, we find that the critical value fοr a οne-tailed test at a 5% level οf significance is 36.42.

Therefοre, we can say that the teacher's gοal οf a standard deviatiοn οf at mοst 8 pοints was achieved, at a 5% level οf significance.

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