alex, beverly and carl live on the same straight road. alex lives 12 miles from beverly and carl 4 mies from berve,y, how far does alex live from carl?

Answers

Answer 1
Alex to Beverly = 12 miles
Carl to Beverly = 4 miles

So it’s 12 + 4 = 16 miles

Related Questions

Given f(x) and g(x) are polynomials, is the product always a polynomial? Justify your argument.



The product of f(x) and g(x) is , .
select choice(sometimes never always)
a polynomial. By the definition of polynomials the product of polynomials is ,
Select Choice(sometimes never always)
a polynomial because the ,
Select Choice(exponents coefficients variables)
are real numbers and the ,
Select Choice(exponents coefficients variables)
are whole numbers. Real numbers and whole numbers are ,
Select Choice(closed not closed
under addition and subtraction.

Answers

The complete statement about the product of the polynomials is that:

The product of f(x) and g(x) is always a polynomial because the coefficients are real numbers and the exponents are whole numbers. Real numbers and whole numbers are closed under addition

How to complete the statements

From the question, we have the following parameters that can be used in our computation:

Polynomials f(x) and g(x)

When these polynomials are multiplied;

We get another polynomial

This is because, when you multiply two polynomials you get a sum of monomials.

A sum of monomials is always a polynomial

The sum of monomials stated above implies that the whole exponents and the real coefficients are closed under addition

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Using pi 3 what is the answer

Answers

Answer:

12mm

Step-by-step explanation:

circumference (distance around) is equal to πd.

here, if π is 3, we do 3 x the diameter, which is 4. 3 x 4 = 12mm

Find the range of values of x for which
|2x+1|-x-3<0, where x € R.

Answers

By analyzing the inequality and solving, the range of values of x for which the inequality is true is x € (-4/3, 4)

What is domain?

Domain is the input to the function.

What is range?

Range is the output of the function.

First, we'll consider the case where |2x+1|-x-3<0.

|2x+1|-x-3<0

|2x+1|<x+3

Now we need to take the absolute value of 2x+1, we have two cases to consider:

Case 1:

2x + 1 > 0

2x + 1 < x + 3

2x - x < 3 + 1

x < 4

Case 2:

2x + 1 < 0

-2x - 1 < x + 3

-2x - 1 -x - 3 < 0

-3x - 4 < 0

x > -4/3

Now we must find the intersection between the two cases:

x € (-4/3, 4)

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Use the decimals 2.49, 9.19, and 6.7 to write two different addition facts and two different subtraction facts.

Answers

The solution to the equations is

Addition : 2.49 + 6.7 = 9.19  ;  6.7 + 2.49 = 9.19

Subtraction : 9.19 - 6.7 = 2.49  ;  9.19 - 2.49 = 6.7

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Let the three decimals be represented as set x = { 2.49 , 6.7 , 9.19 }

Now , the addition facts are given by equations ,

2.49 + 6.7 = 9.19  be equation (1)

6.7 + 2.49 = 9.19   be equation (2)

And , the subtraction facts are given by the equations ,

9.19 - 6.7 = 2.49  be equation (3)

9.19 - 2.49 = 6.7  be equation (4)

Hence , the equations are solved

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PLS BELP I DONT HAVE MUCH TIME!!!

Answers

Answer:

I'd say A or D but I have a feeling it's A

Evaluate the given integral by changing to polar coordinates. sin(x2 y2) dAR, where R is the region in the first quadrant between the circles with center the origin and radii 3 and 4

Answers

Answer:

The result of the integral is [tex]\frac{\pi}{4}(-\cos{16} + \frac{9})[/tex]

Step-by-step explanation:

Polar coordinates:

In polar coordinates, we have that:

[tex]x^2 + y^2 = r^2[/tex]

And

[tex]\int \int_{dA} f(x,y) da = \int \int f(r) r dr d\theta[/tex]

In this question:

[tex]\int \int_{dA} \sin{(x^2+y^2)} dA = \int \int_{dR} = \sin{r^2}r dr d\theta[/tex]

Region in the first quadrant between the circles with center the origin and radii 3 and 4

First quadrant means that [tex]\theta[/tex] ranges between [tex]0[/tex] and [tex]\frac{\pi}{2}[/tex]

Between these circles means that r ranges between 3 and 4. So

[tex]\int \int_{dR} = \sin{r^2}r dr d\theta = \int_{0}^{\frac{\pi}{2}} \int_{3}^{4} \sin{r^2} r dr d\theta[/tex]

Applying the inner integral:

[tex]\int_{3}^{4} \sin{r^2} r dr[/tex]

Using substitution, with [tex]u = r^2, du = 2rdr, dr = \frac{du}{2r}[/tex], and considering that the integral of the sine is minus cosine, we have:

[tex]-\frac{\cos{r^2}}{2}|_{3}{4} = \frac{1}{2}(-\cos{16} + \frac{9})[/tex]

Applying the outer integral:

[tex] \int_{0}^{\frac{\pi}{2}} \frac{1}{2}(-\cos{16} + \frac{9}) d\theta[/tex]

Has no factors of [tex]\theta[/tex], so the result is the constant multiplied by [tex]\theta[/tex], and then we apply the fundamental theorem.

[tex]\frac{\theta}{2}(-\cos{16} + \frac{9}) = \frac{\pi}{4}(-\cos{16} + \frac{9})[/tex]

The result of the integral is [tex]\frac{\pi}{4}(-\cos{16} + \frac{9})[/tex]

make x the subject of the formula in R = ax-p/q+bx

Answers

R = (ax - p)/(q + bx)

(ax - p) = R(q + bx)

ax - p = Rq + Rbx

ax - Rbx = Rq + p

x(a - Rb) = Rq + p

x = (Rq + p)/(a - Rb)

I need help understanding area with combined shapes

Answers

Answer:

Step-by-step explanation:

You can start by splitting one whole complex shape into multiple shapes. Then find the areas of the shapes and add them together. Check the image I attached.

Which equation justifies why ten to the one third power equals the cube root of ten?

ten to the one third power all raised to the third power equals ten to the one third plus three power equals ten

ten to the one third power all raised to the third power equals ten to the one third times three power equals ten

ten to the one third power all raised to the third power equals ten to the three minus one third power equals ten

ten to the one third power all raised to the third power equals ten to the one third minus three power equals ten

Answers

The equation that justifies  ten to the one third power equals the cube root of ten is ten to the one third power all raised to the third power equals ten to the one third times three power equals ten. Option B

How to justify the power

we are to find [tex]10^{\frac{1}{3} } = \sqrt[3]{10}[/tex]

The justification has to be done with the use of the properties of powers as well as roots.

[tex]a^\frac{m}{n} = \sqrt[n]{a^m}[/tex]

then we would have:

[tex]\sqrt[3]{10} = \sqrt[3]{10^1} =10^\frac{1}{3}[/tex]

then we would have

[tex](10^\frac{1}{3} )^3\\\\= 10^\frac{3}{3}[/tex]

= 10

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please help me with this thank you.​

Answers

A) 4:00 PM
B) 1:55 PM

Lillian is wrapping a gift box that has the size shown below. What is the volume of the box?
Enter your answer in the box.

Cube with height of 9 cm and area of base as 36 square cm.

cubic centimeters

Answers

[tex] \huge \mathrm{Answer࿐ }[/tex]

[tex] \boxed{\mathrm{volume = area \times height}}[/tex]

[tex]36 \times 9[/tex]

[tex]\mathrm{324 \: cm {}^{3} }[/tex]

_____________________________

[tex]\mathrm{ \#TeeNForeveR}[/tex]

Answer:

324

Step-by-step explanation:

if you do 36 times 9 you get 324

Help me please...... I dknt understand math I’m du.mb

Answers

Answer:

281/100

the mixed number would be 2 81/100

Step-by-step explanation:

Times 2.81 by 100

Hope it helps :)

A mixed number is a whole number with a proper fraction together.

With that definition, keep the 2. It is already a whole number.

0.81 is the part you need as a proper fraction. 0.81 can be read as 81 hundredths or 81/100.

So combine the two: 2 81/100 is your answer.

To show that NMQ ≈ QPN by SAS, what must be the value or x?

I need help with this please help me

Answers

Answer:

  x = 3

Step-by-step explanation:

You want to know the value of x, given that NM = 5x-1 and QP = 3x+5 in congruent triangles NMQ and QPN.

CPCTC

Corresponding parts of congruent triangles are congruent, so we have ...

  NM = QP

  5x -1 = 3x +5

  2x = 6 . . . . . . . . . . add 1-3x

  x = 3 . . . . . . . . . . divide by 2

The shaded numbers show a pattern in the multiplication table. Which
expression can find the number that comes next in the pattern?
5
X 0 1 2 3 4
0 0 0 0 0 0
1 0 1 23 4
0
5
0
2.
46
8
10
AWN
O
3
12 15
0
4
Lololo
12 16 20
5
0
5
10 15 20 25
25 + 11
25 x 6
25 X 4
25 + 1

Answers

25+1=26 25x4=100 this is the answer


Someone please help me. I will give you hella points I need this answer to like graduate type

Answers

Answer:

$9 and $7

Step-by-step explanation:

The first equation:

x + 2y = 23

The second equation:

2x + 3y = 39

Convert to slope-intercept form:

x + 2y = 23 ⇒ 2y = -x + 23 ⇒ y = -1/2x + 11.52x + 3y = 39 ⇒ 3y = -2x + 39 ⇒ y = -2/3x + 13

The graph is attached

Intersection point is (9, 7)

Adult tickets cost $9Child tickets cost $7

d= c/n solve for n, I've been trying to solve this by multiplying by n but i want to solve for n so that's wrong thank you guys :D

Answers

Answer:

You started correctly....

Step-by-step explanation:

d = c/n      Multiply both sides by 'n'

dn = c        now divide both sides of the equation by 'd'

n = c/d       Done.

If a copy machine can copy 34 sheets of paper in one minute. How many sheets can it copy in 2 hours?

Answers

Answer:

Step-by-step explanation:

34x60

60 minutes in a hour

34x60=204

204+204= 408

408 copies in 2 hours

Answer:

4080

Step-by-step explanation:

First you would multiply 34 by 120. After you multiply those numbers you should get 4080 as your answer.

A conservative investor has $100,000 to invest. The investor has decided to use three vehicles for generating income: Municipal bonds, a certificate of deposit (CD), and a money market account. After reading a financial newsletter, the investor also has identified several additional restrictions on the investments:
a. No more than 40 percent of investment should be in bonds
b. The proportion allocated to the money market account will be at least double the amount in the CD
c. The annual return will be 8% for bonds, 9% for the CD and 7% for the money market account. Assume that the investor wants to maximize the total annual return
Then, formulate the LP model for this problem, ignoring any transaction costs and the potential for different investment

Answers

Answer: Here, let X,Y,ZX,Y,Z indicate the amount in dollars to be invested

Step-by-step explanation: Here, let X,Y,ZX,Y,Z indicate the amount in dollars to be invested

Can y’all help me on question 13?!

Answers

Answer:

C

Step-by-step explanation:

20 - 13 = 7

Answer:

C)

Step-by-step explanation:

7 + 13 = 20

The answer is C

Consider the set {1, 2, 3, 4}.

a. Make a list of all samples of size 2 that can be drawn from this set of integers.
b. Construct the sampling distribution of sample means for samples of size 2 selected from this set.
c. Provide the distribution both in the form of a table and histogram.

Answers

Answer:

(a)

[tex]List = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),\\(4,1),(4,2),(4,3).(4,4)\}[/tex]

(b) Sampling Distribution (Table)

[tex]\begin{array}{cccccccc}{\bar x} & {1} & {1.5} & {2} & {2.5} & {3} & {3.5} & {4} & {Pr}& {\frac{1}{16}} & {\frac{1}{8}} & {\frac{3}{16}} & {\frac{1}{4}} & {\frac{3}{16}} & {\frac{1}{8}} & {\frac{1}{16}} \ \end{array}[/tex]

(b) Sampling Distribution (Histogram)

See attachment

Step-by-step explanation:

Given

[tex]Set = \{1,2,3,4\}[/tex]

[tex]n =4[/tex]

Solving (a): A list of sample size 2

We have:

[tex]n =4[/tex]

[tex]r = 2[/tex] --- the sample size

First, we calculate the number of list using permutation (orders matter)

[tex]n(List) = n^r[/tex]

So, we have:

[tex]n(List) = 4^2[/tex]

[tex]n(List) = 16[/tex]

And the list is:

[tex]List = \{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),\\(4,1),(4,2),(4,3).(4,4)\}[/tex]

Solving (b): Sample distribution  of sample means of (a)

First, calculate the mean of each set using:

[tex]Mean = \frac{Sum}{2}[/tex]

So, we have:

[tex](1,1) \to \frac{1+1}{2} \to 1[/tex]       [tex](1,2) \to \frac{1+2}{2} \to 1.5[/tex]    [tex](1,3) \to \frac{1+3}{2} \to 2[/tex]    [tex](1,4) \to \frac{1+4}{2} \to 2.5[/tex]

[tex](2,1) \to \frac{2+1}{2} \to 1.5[/tex]    [tex](2,2) \to \frac{2+2}{2} \to 2[/tex]     [tex](2,3) \to \frac{2+3}{2} \to 2.5[/tex]    [tex](2,4) \to \frac{2+4}{2} \to 3[/tex]

[tex](3,1) \to \frac{3+1}{2} \to 2[/tex]       [tex](3,2) \to \frac{3+2}{2} \to 2.5[/tex]    [tex](3,3) \to \frac{3+3}{2} \to 3[/tex]    [tex](3,4) \to \frac{3+4}{2} \to 3.5[/tex]

[tex](4,1) \to \frac{4+1}{2} \to 2.5[/tex]    [tex](4,2) \to \frac{4+2}{2} \to 3[/tex]    [tex](4,3) \to \frac{4+3}{2} \to 3.5[/tex]    [tex](4,4) \to \frac{4+4}{2} \to 4[/tex]

Write out the sample means (sorted)

[tex]\bar x =\{1,1.5,1.5,2,2,2,2.5,2.5,2.5,2.5,3,3,3,3.5,3.5,4\}[/tex]

Construct a frequency table

[tex]\begin{array}{cc}{\bar x} & {f} & {1} & {1} & {1.5} & {2} & {2} & {3} & {2.5} & {4} & {3} & {3} & {3.5} &{2} & {4} & {1} & Total & 16\ \end{array}[/tex]

Construct the sampling distribution where the probability is calculated using: [tex]\frac{f}{Total}[/tex]

So, we have:

[tex]\begin{array}{cccccccc}{\bar x} & {1} & {1.5} & {2} & {2.5} & {3} & {3.5} & {4} & {Pr}& {\frac{1}{16}} & {\frac{1}{8}} & {\frac{3}{16}} & {\frac{1}{4}} & {\frac{3}{16}} & {\frac{1}{8}} & {\frac{1}{16}} \ \end{array}[/tex]

Greenfields is a mail order seed and plant business. The size of orders is uniformly distributed over the interval from $25 to $80. Use the following random numbers to generate the size of 10 orders. .41 .99 .07 .05 .38 .77 .19 .12 .58 .60 What is the value for the first order size generated randomly based on random number 0.41? What is the value for the last order size generated randomly based on random number 0.60? What is the average order size?

Answers

Answer:

a) 47.55

b) 58

c) 47.88

Step-by-step explanation:

Given that the size of the orders is uniformly distributed over the interval

$25 ( a ) to $80 ( b )

a) Determine the value for the first order size generated based on 0.41

parameter for normal distribution is given as ;  a = 25,  b = 80

size/value of order  = a + random number ( b - a )

                                = 25 + 0.41 ( 80 - 25 )

                                =  47.55

b) Value of the last order generated based on random number (0.6)

= a + random number ( b - a )

= 25 + 0.6 ( 80 - 25 )

= 25 + 33 = 58

c) Average order size

= ∑ order 1 + order 2 + ----- + order 10  ) / 10

= (47.55 + ...... + 58 ) / 10

= 478.8 / 10 = 47.88

The mail order seed follows a uniform distribution

(a) The value of the first order size generated by 0.41

The given parameters are:

[tex]a = 25[/tex] -- the lower bound

[tex]b = 80[/tex] -- the upper bound

To calculate the required value, we make use of the following order formula

[tex]Value = a + r(b - a)[/tex]

Where r represents the random number.

So, we have:

[tex]Value= 25 + 0.41 \times ( 80 - 25 )[/tex]

Open bracket

[tex]Value= 25 + 0.41 \times 55[/tex]

Evaluate the product

[tex]Value= 25 + 22.55[/tex]

Add the terms

[tex]Value= 47.55[/tex]

Hence,  the value for the first order size generated randomly based on random number 0.41 is 47.55

(b) The value of the last order size generated by 0.60

In (a), we have:

[tex]Value = a + r(b - a)[/tex]

So, we have:

[tex]Value= 25 + 0.60 \times ( 80 - 25 )[/tex]

Open bracket

[tex]Value= 25 + 0.60 \times 55[/tex]

Evaluate the product

[tex]Value= 25 + 33[/tex]

Add the terms

[tex]Value= 58[/tex]

Hence, the value for the last order size generated randomly based on random number 0.61 is 58

(c) The average order size

To do this, we calculate the order size from 1 to 10, and then calculate the average value of the 10 orders.

Using a calculator, the sum of the 10 orders is:

[tex]\sum x= 478.8[/tex]

The average order size is then calculated as:

[tex]\bar x = \frac{\sum x}{n}[/tex]

This gives

[tex]\sum x= \frac{478.8}{10}[/tex]

[tex]\sum x= 47.88[/tex]

Hence, the average order size is 47.88

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Determine the greatest common factor of the following numbers 8 and 12
NO LINKS PLEASE!!!!​

Answers

I think it would be 4.
8 breaks down to 4(2) and 12 breaks down to 4(3). Let me know if that helps!

Question 5, Please Answer and Explain

Answers

The trigonometric ratios for the angle x in the triangle are given as follows:

tan(x) = f/e.cos(x) = e/d.sin(x) = f/d.

What are the trigonometric ratios?

The three trigonometric ratios are defined as follows:

Sine of angle = length of opposite side divided by the length of the hypotenuse.Cosine of angle = length of adjacent side divided by the length of the hypotenuse.Tangent of angle = length of opposite side divided by the length of the opposite side.

In the right triangle in this problem, we have that d represents the hypotenuse, while the sides relative to angle x are given as follows:

Adjacent side: length of e.Opposite side: length of f.

These sides are used along with the definitions of each ratio to give the three trigonometric ratios of angle x.

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Tara is painting her room she brought paint that takes 3 gallons to cover an area of 75 square feet how many gallons of paint will tara need to paint 375 square feet of her room

Answers

Tara will need gallons of paint

Find each marked side or angle show the step by step​

Answers

Answer:

taking b as reference angle

using cos rule

cos b=b/h

cos b=1.3/2.8

cos b=0.46

cos 62 =0.46

Step-by-step explanation:

therefore the value of b is 62 degree

50 POINTS !!


PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.

Answers

Answer:

8.2

Step-by-step explanation:

(4.5)^2+(6.9)^2=c^2

20.25+47.61=67.86

sqrt of 67.86= 8.2 (rounded already) :)

What is the perimeter of the figure?

Answers

320 ft is the perimeter

Rewrite the radical expression as an expression with a rational exponent.

the seventh root of x to the thrid power

x to the three sevenths power
x to the seven thirds power
x^21
x^4

Answers

Answer:

To rewrite the radical expression "the seventh root of x to the thrid power" as an expression with a rational exponent, we need to use the property that allows us to rewrite a root of a power as a power with a rational exponent. This property states that "the nth root of x to the mth power" is equal to "x to the m/nth power".

Using this property, we can rewrite "the seventh root of x to the thrid power" as "x to the 3/7th power". Therefore, the correct answer is "x to the 3/7th power".

The other answer choices are not equivalent to the original expression. "x to the seven thirds power" is not a valid expression because "thirds" is not a unit of measurement. "x^21" is not equivalent to the original expression because the base and exponent are not related in the same way as in the original expression. "x^4" is not equivalent to the original expression because the base is the same but the exponent is not.

Answer: x to the 3/7th power

Step-by-step explanation:

so you dont have to read a essay to get the answer lol

Zachary purchased a computer for $1,800 on a payment plan. Three months after he purchased the computer, his balance was 1,350. Five months after he purchased the computer , his balance was 1,050. What is an equation that models the balance B after m Months

Answers

Answer: y = -150x + 1800

Step-by-step explanation:

1. Find the linear slope of the line between two points.

(Change in Y)/(Change in X)

2. Write out an equation in point slope form.

(y-y1) = m(x-x1)

y-1800 = -150(x-0)

3. Simplify the equation and turn it into slope-intercept form.

y = -150x + 1800

I need help ASAP...please please someone help

Answers

Answer:

x = 26

Step-by-step explanation:

180=(4x+10)+(x+40)

180 = 4x + x +10 + 40

180 - 50 = 5x

130 = 5x

130 / 5 = x

26 = x

A 130+50.
Hdhdhdbsnna
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