Already Know The Vertex but need help on the opens and axis of symmetry

Answer:

Step-by-step explanation:

Without a diagram, I cannot determine the equation of the curve. However, I can provide you with the general steps to find the equation of a quadratic curve given three points on the curve.

Let the three points be (x1, y1), (x2, y2), and (x3, y3). Then the equation of the quadratic curve in the form ax²+bx+c can be found using the following system of equations:

y1 = a(x1)² + b(x1) + c

y2 = a(x2)² + b(x2) + c

y3 = a(x3)² + b(x3) + c

Solving this system of equations simultaneously will give us the values of a, b, and c, which we can use to write the equation of the quadratic curve.

However, since you have only provided three y-values (32, 2.0, and 8.0), without their corresponding x-values or the diagram, it is not possible to determine the equation of the curve.

The evaluated missing length in right triangle by using the Pythagorean theorem is  9 yards under the condition given the triangle is a right triangle.

The Pythagoras theorem projects that in a right triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides,
It is given to us that in a right triangle,
Hypotenuse = 15 yd
Perpendicular = 12 yd

Therefore, applying Pythagoras theorem;
Base² = 15² - 12²

Base² = 225 - 144

Base² = 81

Base = √81

Base = 9 yards

Hence, The missing length present in the right triangle by applying the Pythagorean theorem is,
9 yards

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The complete question is

Determine the missing length in each right triangle using the Pythagorean theorem. Round the answer to the nearest tenth, if necessary

the volume of each souvenir is  43. 85 cm³

The formula for calculating the volume of a cone is represented as;

V = 1/3 πr²h

Given that;

Then,

r = diameter/2 = 4.2 /2 = 2.1 centimeters

Substitute the values, we have

Volume = 1/3  × 3.14 × 2.1² × 9.5

find the square, we have;

Volume = 1/3 × 3.14 × 4. 41 × 9.5

Multiply the values

Volume = 131. 5503/3

divide the values

Volume = 43. 85 cm³

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Answer:

Step-by-step explanation:

We can use the Pythagorean theorem to solve this problem. Let's call the length of the ladder "L". The ladder, the wall of the house, and the ground form a right triangle. The distance between the ladder and the house is the base of the triangle, which is 15 feet. The height of the triangle is the distance from the ground to the spotlight, which is 20 feet. The length of the ladder is the hypotenuse of the triangle.

Using the Pythagorean theorem, we have:

L^2 = 15^2 + 20^2

L^2 = 225 + 400

L^2 = 625

L = sqrt(625)

L = 25

Therefore, a ladder of at least 25 feet is needed for the electrician to reach the place where the light is mounted.

The maximum volume of a cone that can be carved from the foam cylinder is approximately 9.42 cubic inches.

Given data:

diameter = 3 inches

radius = r = 3 ÷ 2 = 1.5 inches

height = 4 inches

We need to find the maximum volume of a cone that can be carved from the foam cylinder. The volume of a cone is given by the formula:

V = [tex]\frac{1}{3}\pi r^2h[/tex]

where:

V = volume

r = radius of the base

h = height

π = 3.14.

Substituting the r, h, and  π values in the formula, we get:

V = [tex]\frac{1}{3}[/tex]π[tex]r^2[/tex]h

V = [tex]\frac{1}{3}[/tex] × π × (1.5)² ×(4)

V =  [tex]\frac{1}{3}[/tex] × π × 2.25 ×(4)

V = 3 π

V = 9.42 cubic inches

Therefore, the maximum volume of a cone is 9.42 cubic inches.

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Answer:

1 time, though your answer would be ongoing. If you the actual answer, it's 1.2

Step-by-step explanation:

Round to the nearest tenth.

Answer:

1.2

Step-by-step explanation:

Five can go into six 1.2 times because (1.2)(5)=6. Of course, if you want to know how many times five can go into 6 as a WHOLE, then the answer would obviously be 1.

Hope this helps a bit :)

Answer:

Step-by-step explanation:

33

Answer:

mmm, well, not much we can do per se, you'd need to use a calculator.

I'd like to point out you'd need a calculator that has regression features, namely something like a TI83 or TI83+ or higher.

That said, you can find online calculators with "quadratic regression" features, which is what this, all you do is enter the value pairs in it, to get the equation.

Step-by-step explanation:

The value of (f-g)(2) is 16, provided that Megan has made no mistakes in the calculation.

The problem asks us to compute the value of (f - g)(2) where f(x) = 3x^2 - 2x + 4 and g(x) = x^2 - 5x + 2.

The notation (f - g)(2) means that we need to subtract g(x) from f(x) and then evaluate the result at x = 2. We can do this as follows:

(f - g)(x) = f(x) - g(x) = (3x^2 - 2x + 4) - (x^2 - 5x + 2) = 2x^2 + 3x + 2

Substituting x = 2, we get:

(f - g)(2) = 2(2)^2 + 3(2) + 2 = 16

Therefore, the value of (f - g)(2) is 16.

It's worth noting that the problem statement mentions "what did she do wrong?" without providing any context or information about what Megan did or didn't do. So, it's not possible to identify any error in Megan's solution based on the given information. However, based on the correct computation above, we can be sure that (f - g)(2) is indeed equal to 16.

In other words, it can be described as,

The error in Megan's solution is not clear from the given statement. However, it seems that she may have made an error while computing (f-g)(2).

To compute (f-g)(2), we need to subtract g(2) from f(2) as follows:

f(2) = 3(2)^2 - 2(2) + 4 = 12

g(2) = (2)^2 - 5(2) + 2 = -4

Therefore, (f-g)(2) = f(2) - g(2) = 12 - (-4) = 16. is the final conclusion.

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C. All rectangles have four sides. All squares are rectangles. Therefore, all squares have four sides.

This is an example of deductive reasoning because it starts with a general statement (all rectangles have four sides) and then applies a specific example (squares are rectangles) to come to a logical conclusion (all squares have four sides).

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We have shown that ⊙O and ⊙P are similar using similarity transformations.

To prove that ⊙O and ⊙P are similar using similarity transformations, we need to show that they have the same shape . Let's consider a dilation transformation with a scale factor of 2, centered at point A, which is the midpoint of the line segment connecting the centers of ⊙O and ⊙P:

1.Draw a line segment connecting the centers of ⊙O and ⊙P, and label the midpoint of this line segment as point A.

2.Draw two radii from the centers of ⊙O and ⊙P to a point B on the circumference of ⊙O, and label the intersection point of AB and ⊙P as point C.

3.Draw a perpendicular line from point A to BC, and label the intersection point as point D.

4.Since AD is the perpendicular bisector of BC, we have BD = DC.

5.By the properties of dilation, the length of any line segment on ⊙O is doubled when it is transformed by a dilation with a scale factor of 2 centered at A.

6.Therefore, the length of BD is doubled to become BE, and the length of DC is doubled to become CF.

7.Since ⊙O is transformed to a circle with center A and radius 10, and ⊙P is transformed to a circle with center A and radius 24, we can see that they have the same shape but different sizes.

Therefore, we have shown that ⊙O and ⊙P are similar using similarity transformations.

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The critical point is c = 2, the function is decreasing on the interval 0 < x < 2, and increasing on the interval x > 2.

To find the critical point of the function y = x^2 - 4x, we first need to find its derivative, which represents the slope of the tangent line at any point on the curve.

The derivative of y with respect to x is:

y' = 2x - 4

Now, we need to find the critical points, which occur where the derivative is zero or undefined. In this case, the derivative is a polynomial, so it is never undefined. To find where it equals zero, we set y' equal to zero:

0 = 2x - 4

Solving for x, we get:

x = 4/2 = 2

So, the critical point is c = 2.

Now, we need to determine if the function is increasing or decreasing on the interval x > 0. To do this, we can analyze the sign of the derivative. If y' > 0, the function is increasing; if y' < 0, the function is decreasing.

For x > 2 (to the right of the critical point), the derivative y' = 2x - 4 is positive (since 2x > 4 when x > 2). Therefore, the function is increasing on the interval x > 2.

For x < 2 (to the left of the critical point), the derivative y' = 2x - 4 is negative (since 2x < 4 when x < 2). Therefore, the function is decreasing on the interval 0 < x < 2.

In summary, the critical point is c = 2, the function is decreasing on the interval 0 < x < 2, and increasing on the interval x > 2.

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Answer:

False.

Inflation occurs in an economy when there is an increase in the overall price level of goods and services over time. It is usually caused by factors such as an increase in the money supply, higher demand for goods and services, or a decrease in the supply of goods and services. Therefore, a reduction in the total amount of money in an economy would generally lead to deflation, which is the opposite of inflation.

The measure of angle A is 20 degrees, the measure of angle B is 65 degrees, and the measure of angle C is 95 degrees.

To find the measure of the angles in triangle ABC, we first need to determine the total ratio of measures.

The total ratio is 4 + 13 + 19 = 36.

Next, we can use the ratios to find the measure of each angle.

Let x be the measure of the smallest angle in triangle ABC.

Then the measures of the angles are:

Angle A = 4x
Angle B = 13x
Angle C = 19x

We know that the sum of the angles in a triangle is 180 degrees, so we can set up the equation:

4x + 13x + 19x = 180

Simplifying, we get:

36x = 180

Dividing both sides by 36, we get:

x = 5

Therefore, the measures of the angles in triangle ABC are:

Angle A = 4x = 4(5) = 20 degrees
Angle B = 13x = 13(5) = 65 degrees
Angle C = 19x = 19(5) = 95 degrees

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Answer:

x = 7 is not a function--it is a vertical line.

The total differential of w is given by dw = (∂w/∂x)dx + (∂w/∂y)dy + (∂w/∂z)dz + (∂w/∂z)(∂z/∂y)dy + (∂w/∂z)(∂z/∂z)dz.

Differentiation is a process of finding the changes in any function with a small change in By differentiation, it can be checked that how much a function changes and it also shows the way of change Differentiation is being used cost, production and other management decisions. It gives the rate of change independent variable with respect to the independent variable.                                                                                                             First, let's get the partial derivatives of w with respect to x, y, and z: ∂w/∂x = 15x^14yz^11, ∂w/∂y = x^15z^11cos(yz), ∂w/∂z = 11x^15y^z^10 + x^15y^11cos(yz). Next, we need to find (∂w/∂z)(∂z/∂y): ∂z/∂y = cos(y)
So, (∂w/∂z)(∂z/∂y) = x^15y^11z^10cos(y). Substituting these values into the formula for the total differential, we get: dw = (15x^14yz^11)dx + (x^15z^11cos(yz))dy + (11x^15y^z^10 + x^15y^11cos(yz))dz + (x^15y^11z^10cos(y))dy
Simplifying, we get: dw = 15x^14yz^11dx + x^15z^11cos(yz)dy + (11x^15y^z^10 + x^15y^11cos(yz) + x^15y^11z^10cos(y))dz.

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The average time patients waited in 2014 was approximately 76 minutes, calculated by dividing the 2015 waiting time by 0.89 as patients waited 11% less time in 2015.

Let's call the average time patients waited in 2014 as per Wenford Hospital records "x" (in minutes). According to the problem statement, patients waited 11% less time in 2015 compared to 2014, so,

0.89x = 68

Solving for x,

x = 68 / 0.89

x ≈ 76.4

Therefore, the average time patients waited in 2014 was approximately 76 minutes (rounded to the nearest minute).

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The theoretical probability of rolling a one or two on a number cube is 2/5 or 0.4.

To find the theoretical probability of rolling a one or two on a number cube, we need to determine the number of outcomes that correspond to rolling a one or two, and divide that by the total number of possible outcomes.

From the table, we can see that Alexandria rolled a one or two a total of 24 times out of 60 rolls. This means that the probability of rolling a one or two is: P(1 or 2) = 24/60

Simplifying the fraction by dividing both the numerator and denominator by the greatest common factor, we get: P(1 or 2) = 4/10

This can be further reduced to: P(1 or 2) = 2/5

Therefore, the theoretical probability of rolling a one or two on a number cube is 2/5 or 0.4.

In summary, the theoretical probability is the expected probability of an event occurring, based on mathematical reasoning. Here, we used the number of favorable outcomes to calculate the probability of rolling a one or two, and expressed the answer as a fraction in simplest form.

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To the nearest tenth of an inch, the length of the shorter leg of each right triangle will be 2.7 inches.

A triangle is a polygon with three sides and three angles. The sum of the three angles in a triangle always adds up to 180 degrees. There are many different types of triangles, including equilateral triangles (where all three sides are equal in length and all three angles are 60 degrees), isosceles triangles (where two sides are equal in length and two angles are equal in measure), and scalene triangles (where no sides are equal in length and no angles are equal in measure).

Let x be the length of the shorter leg of each right triangle. Then, the longer leg will be twice as long, so its length will be 2x. Using the Pythagorean theorem, we can write:

x² + (2x)² = 6²

Simplifying and solving for x, we get:

x² + 4x² = 36

5x² = 36

x² = 7.2

x ≈ 2.7

Therefore, to the nearest tenth of an inch, the length of the shorter leg of each right triangle will be 2.7 inches.

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A simplification of the expression [tex]\frac{x^3y^3 \cdot x^3 }{4x^2}[/tex] is [tex]\frac{x^4y^3 }{4}[/tex].

In Mathematics, an exponent is a mathematical operation that is commonly used in conjunction with an algebraic equation or expression, in order to raise a given quantity to the power of another.

Mathematically, an exponent can be represented or modeled by this mathematical expression;

bⁿ

Where:

By applying the division and multiplication law of exponents for powers of the same base to the given algebraic expression, we have the following:

[tex]\frac{x^3y^3 \cdot x^3 }{4x^2}=\frac{x^{3+3-2}y^3 }{4}\\\\\frac{x^{3+3-2}y^3 }{4}=\frac{x^4y^3 }{4}[/tex]

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Complete Question;

Simplify each of the expressions given.

a) The characteristic equation is r^2 + 11r + 28 = 0.

b) The associated homogeneous equation are y1(x) = c1e^(-4x) and y2(x) = c2e^(-7x).

c) The form of the particular solution is y_p(x) = Ae^(5x) + Bx + C.

d) By solving the system of equations, it gives A = 1/28, B = 1/28, and C = -211/196.

e) The general solution is y(x) = c1e^(-4x) + c2e^(-7x) + (1/28)e^(5x) + (1/28)x - 211/196.

a) The characteristic equation of the associated homogeneous equation is r^2 + 11r + 28 = 0.

b) Factoring the characteristic equation gives (r + 4)(r + 7) = 0, so the solutions to the associated homogeneous equation are y1(x) = c1e^(-4x) and y2(x) = c2e^(-7x).

c) The form of the particular solution is y_p(x) = Ae^(5x) + Bx + C. Taking the first and second derivatives of y_p(x) gives y_p'(x) = 5A + B and y_p''(x) = 0.

d) Substituting y_p(x), y_p'(x), and y_p''(x) into the original nonhomogeneous equation gives:

0 + 11(5A + B) + 28(Ae^(5x) + Bx + C) = e^(5x) + x + 4

Simplifying this equation gives:

(28A)e^(5x) + (28B)x + 11(5A) + 11B + 28C = e^(5x) + x + 4

Comparing coefficients gives the system of equations:

28A = 1

28B = 1

11(5A) + 11B + 28C = 4

Solving this system of equations gives A = 1/28, B = 1/28, and C = -211/196.

e) The general solution to the nonhomogeneous equation is y(x) = y_h(x) + y_p(x), where y_h(x) = c1e^(-4x) + c2e^(-7x) and y_p(x) = (1/28)e^(5x) + (1/28)x - 211/196. Therefore, the general solution is:

y(x) = c1e^(-4x) + c2e^(-7x) + (1/28)e^(5x) + (1/28)x - 211/196.

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Answer:

Step-by-step explanation:

4/625 x 625/9 = 4 x 1 / 5 x 5 x 5 x 1 = 4/625. The cross cancellation did not change the result.

The solution is correct, as both sides of the equation are equal.

To find out how much money Rachel had before she went grocery shopping, we can create an equation using a variable.

Let x represent the amount of money Rachel had before grocery shopping.

The equation for the situation would be: x - $68 = $23

Now, let's solve for x:
Step 1: Add $68 to both sides of the equation:
x = $23 + $68

Step 2: Calculate the sum:
x = $91

So, Rachel had $91 before she went grocery shopping.

To prove the solution is correct, we can plug the value of x back into the equation:
$91 - $68 = $23
$23 = $23

Hence, both are equal.

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To find the values of f(a), f(a-1), and f(a+1) when f(x) = x^2 + 4x + 6, So, the values are:  f(a) = a^2 + 4a + 6, f(a-1) = a^2 + 6a + 3, f(a+1) = a^2 + 6a + 11.

we simply substitute the given values of a into the function.
1. f(a) = a^2 + 4a + 6
2. f(a-1) = (a-1)^2 + 4(a-1) + 6 = a^2 + 2a + 1 + 4a - 4 + 6 = a^2 + 6a + 3
3. f(a+1) = (a+1)^2 + 4(a+1) + 6 = a^2 + 2a + 1 + 4a + 4 + 6 = a^2 + 6a + 11
So, the values are:
1. f(a) = a^2 + 4a + 6
2. f(a-1) = a^2 + 6a + 3
3. f(a+1) = a^2 + 6a + 11

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The surface area of the solids are listed below:

Case 1: A = 366 mm²

Case 2: A = 448 cm²

Case 3: A = 748 m²

Case 4: A = 221.5 in²

Case 5: A = 692 in²

Case 6: A = 276 ft²

In this question we need to determine the surface area of six solids, that is, the sum of areas of all faces in each solid. The solids can include areas of rectangles and triangles, whose formulas are:

Rectangle

A = b · h

Triangle

A = 0.5 · b · h

Where:

Case 1

A = 2 · (13 mm) · (3 mm) + 2 · (13 mm) · (9 mm) + 2 · (9 mm) · (3 mm)

A = 78 mm² + 234 mm² + 54 mm²

A = 366 mm²

Case 2

A = 2 · (20 cm) · (6 cm) + 2 · (4 cm) · (6 cm) + 2 · (20 cm) · (4 cm)

A = 240 cm² + 48 cm² + 160 cm²

A = 448 cm²

Case 3

A = 2 · (5 m) · (14 m) + 2 · (16 m) · (14 m) + 2 · (5 m) · (16 m)

A = 748 m²

Case 4

A = 2 · (2 in) · (6.5 in) + 2 · (11.5 in) · (6.5 in) + 2 · (11.5 in) · (2 in)

A = 221.5 in²

Case 5

A = 2 · 0.5 · (12 in) · (7 in) + (11 in) · (19 in) + (9 in) · (19 in) + (12 in) · (19 in)

A = 692 in²

Case 6

A = 2 · 0.5 · (8 ft) · (3 ft) + 2 · (5 ft) · (14 ft) + (8 ft) · (14 ft)

A = 276 ft²

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Answer: Goofy Ahh

Step-by-step explanation:

That question is so Goofy Ahh

Weeee

The points are graphed on a coordinate plane and attached

A coordinate plane, also known as a Cartesian plane, is a two-dimensional plane with two perpendicular lines that intersect at a point called the origin.

The horizontal line is called the x-axis and the vertical line is called the y-axis. The axes divide the plane into four quadrants.

Each point on the plane can be uniquely identified by a pair of coordinates (x, y), where x is the horizontal distance from the origin along the x-axis and y is the vertical distance from the origin along the y-axis.

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The equivalent expression is $\boxed{4^{15} \cdot 5^{10}}$.

We can simplify the expression inside the parentheses first, using the rule that says when you raise a power to another power, you multiply the exponents:

$\left(\dfrac{4^{3}}{5^{-2}}\right)^{5} = \left(4^{3} \cdot 5^{2}\right)^{5}$

Now, we can use the rule that says when you raise a product to a power, you raise each factor to the power:

$\left(4^{3} \cdot 5^{2}\right)^{5} = 4^{3 \cdot 5} \cdot 5^{2 \cdot 5}$

Simplifying further:

$4^{3 \cdot 5} \cdot 5^{2 \cdot 5} = 4^{15} \cdot 5^{10}$

we can substitute this expression back into the original expression:

$\left(\dfrac{4^{3}}{5^{-2}}\right)^{5} = \left(4^{3} \cdot 5^{2}\right)^{5}$

To simplify this expression further, we can use the rule that says when you raise a product to a power, you raise each factor to the power:

$\left(4^{3} \cdot 5^{2}\right)^{5} = 4^{3 \cdot 5} \cdot 5^{2 \cdot 5}$

Simplifying the exponents, we get:

$4^{3 \cdot 5} \cdot 5^{2 \cdot 5} = 4^{15} \cdot 5^{10}$

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The unit vector in the direction of steepest ascent at P is <-4/sqrt(17), -1/sqrt(17)>,  and the unit vector in the direction of steepest descent at P is <4/sqrt(17), 1/sqrt(17)>.  A vector that points in a direction of no change at P is ⟨-1,1⟩.

To find the direction of steepest ascent/descent at P(-1,1) for f(x,y) = 4x^4 - 4x^2y + y^2 + 9, we need to find the gradient vector evaluated at P and then normalize it to get a unit vector. The gradient vector is given by

grad f(x,y) = <∂f/∂x, ∂f/∂y> = <16x^3 - 8xy, -4x^2 + 2y>

So, at P(-1,1), the gradient vector is

grad f(-1,1) = <16(-1)^3 - 8(-1)(1), -4(-1)^2 + 2(1)> = <-8,-2>

To find the unit vector that gives the direction of steepest ascent, we normalize the gradient vector

||grad f(-1,1)|| = sqrt[(-8)^2 + (-2)^2] = sqrt(68)

So, the unit vector in the direction of steepest ascent at P is

u = (1/sqrt(68))<-8,-2> = <-4/sqrt(17), -1/sqrt(17)>

To find the unit vector that gives the direction of steepest descent, we take the negative of the gradient vector and normalize it

||-grad f(-1,1)|| = ||<8,2>|| = sqrt[8^2 + 2^2] = sqrt(68)

So, the unit vector in the direction of steepest descent at P is

v = (1/sqrt(68))<8,2> = <4/sqrt(17), 1/sqrt(17)>

To find a vector that points in a direction of no change in the function at P, we need to find a vector orthogonal to the gradient vector at P. One such vector is

n = <2,-8>

To see why this works, note that the dot product of the gradient vector and n is

<16x^3 - 8xy, -4x^2 + 2y> . <2,-8> = 32x^3 - 16xy - 4x^2y + 2y^2

Evaluating this at P(-1,1), we get

32(-1)^3 - 16(-1)(1) - 4(-1)^2(1) + 2(1)^2 = 0

So, the vector n is orthogonal to the gradient vector at P and points in a direction of no change in the function.

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