Although two identical objects may have the same mass and the same weight (meaning that the force of gravity is the same for both), they may not fall to Earth at the same rate. This is because of air resistance. Any object that is falling has friction, or resistance, from the air. The larger the object, the more resistance it has as it falls.

Get two identical pieces of paper. Crumple one up into a ball, but leave the other one a flat sheet. Drop both pieces of paper off a high place at the same time. What happens? Which falls faster? Record your observations and make a conclusion, using the terms “mass,” “weight,” “force,” “resistance,” and “gravity.”

MUST BE AT LEAST 4 sentences and include the terms weight, force, resistance, and gravity.

Answer:

the paper ball falls faster and the unfolded paper falls at a slower rate

Explanation:

this is because gravity is pulling both objects down to the ground and hence they are falling. Both objects have the same mass and weight but the resultant force of the paper ball is smaller than that of the unfolded paper. The unfolded paper has a larger surface area and so a larger force is acted upon it, meaning there is more air resistance. This shows that the paper ball falls faster than the unfolded paper.

The air resistance acting on the crumpled ball will be less and hence it will fall faster.

Air resistance describes the forces that are in opposition to the relative motion of an object as it passes through the air. The larger the object, the more resistance it has as it falls.

Mathematically, we can write it as -

F = [tex]\frac{1}{2} C_{D}[/tex] × ρv²A

Given are two identical pieces of paper such that one is crumpled up into a ball and the other one is left as flat sheet.

Now, as you throw both, the crumpled up ball and the flat sheet, the crumpled up ball will fall faster. The main reason behind this is that the total surface area of the crumpled ball in contact with the air is less than compared to that of the flat sheet. Air resistance on the crumpled ball with surface are in contact [say A(c)] can be written as -

F[1] =  [tex]\frac{1}{2} C_{D}[/tex] × ρv²A(c)

And that on the flat sheet with area of contact with the air [say A(f)] can be written as -

F[2] =   [tex]\frac{1}{2} C_{D}[/tex] × ρv²A(f)

Now as A(f) > A(c), therefore F[2] > F[1]

Therefore, the air resistance acting on the crumpled ball will be less and hence it will fall faster.

To solve more questions on Air resistance, visit the link below-

https://brainly.com/question/19165683

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