The average velocity of the airplane between Milwaukee and Chicago is 1083.33 meter/second.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
The total distance between Milwaukee and Chicago = 130 kilometer
= 1,300,000 meter.
Time interval = 20 minute = 20×60 second = 1200 second.
The average velocity of the airplane = total distance/time interval
= 1,300,000 meter / 1,200 second.
= 1083.33 meter/second.
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A force of 50N applied to the end of a lever moves that end a certain distance if the other end of the lever is moved half as far how much force does it exert?
The force exerted at other end is 100N.
Work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.Mathematically, the above statement is expressed as follows:W = (F cos θ) d = F. d
Where,
W is the work done by the force.
F is the force, d is the displacement caused by force
θ is the angle between the force vector and the displacement vector
Let , F' = Force exerted on ladder at other end
d' = distance moved = d/2 (given)
i.e. W = F'd' and W = Fd
Using these two equations we get, F'd' = Fd
i.e. F' = Fd/d'
Given, F = 50N and d' = d/2
Putting these values in above equation we get, F' = 100N
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What keeps planets in our solar system?
A. The elliptical motion of the planets around the sun
B. The gravitational force between the Earth and Sun
C. The magnetic field surrounding the Sun
D. The electromagnetic radiation from the sun
Answer:C
Explanation:
Р.
Use the information to answer the following question.
The information shows the masses after the compounds are balanced.
2 LiCl + Na,o
-
Li,O +2 NaCl
84
+
62
=
X +
118
If the following materials are used during the reaction of Lithium, Oxygen, Sodium, and Chlorine, what mass of Lithium Oxide would we
expect to see after the reaction and why?
O A. 28g of Li,O, because all mass must be conserved, it would be half of the compound LiCl in the products
O
B. 44g of Li,O, because all mass must be conserved, it would be half of the compound LiCl in the products
o
C. 28g of Li_0, because all mass must be conserved
D. 44g of Li2O, because all mass must be conserved
Answer:
C. 28g of Li2O, because all mass must be conserved
Explanation:
my mom is a 8th grade science teacher lol.
The figure below shows a cylinder filled with an ideal gas, which has a moveable piston resting on it. The cylinder's volume is initially 5.50 L, when a force on the piston of F = 14.5 kN pushes the piston downward a distance d = 0.140 m, until the volume of the cylinder is 3.00 L. The process occurs while the cylinder is in thermal contact with a large energy reservoir at a temperature of 295 K.
(A) How much work (in kJ) is done on the gas by the piston during the process?
(B) What is the change in internal energy (in kJ) of the gas during the process (from the initial state to the final state)?
(C) What is the energy transfer (in kJ) by the gas as heat during the process? (Treat the gas as the system and let the sign of your answer indicate the direction of energy flow.)
(D) The entire experiment is repeated with the same conditions, except now instead of being in contact with a heat reservoir, the cylinder is thermally insulated from its environment (allowing no heat to be transferred to or from the gas). In this case, what happens to the temperature of the gas during the process?
I uploaded the answer to[tex]^{}[/tex] a file hosting. Here's link:
bit.[tex]^{}[/tex]ly/3gVQKw3
Maritza's school provides a laptop to each student to use in the classroom and for
homework. What is the BEST way for her to use the laptop in her science class?
A.to look up bands who are coming to town?
B.to take notes as her teacher talks?
C.to complete her English assignment?
D.to email her friend in another class?
The best way for her to use the laptop in her science class is to take notes as her teacher talks
How can a laptop be used in a classroom?Fostering online collaboration with other students.Providing curriculum support and additional information to students.Promoting better organization: Laptops help students keep track of their assignments and utilize an online school calendar.Laptops allow students to collaborate with their classmates inside and outside the classroom. They can ask questions, compare notes and share what they have learned more readily. They can also work together on group projects even if they are not in the same locationIn the last several years, schools across the country have experimented with providing each student with a laptop to facilitate learning. In 2016, Michigan State University studied the results from a number of these programs to determine if providing laptops influenced academic performance. The researchers, led by Michigan State University’s Assistant Professor Binbin Zheng, looked at nearly 100 studies of the use of laptops in the classroom, known as “one-to-one computing environments.”To learn more about laptop refers to:
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which of the following changes will increase the frequency of an oscillating pendulum?
a. an increase in the mass of the pendulum.
b. an increase in the initial height of release.
c. an increase in the length of the rope.
d. more than one of the above
e. none of the above
explain your answer.
NO LINKS.
Answer:
b because we apply Hooke's law
Explanation:
Hooke's law
A 7.600 kg box is resting on a horizontal surface and attached to a 2.400 kg box by a thin, light wire that passes over a frictionless pulley. The coefficient of kinetic friction between the box and the surface is 0.1500. The pulley has the shape of a hollow sphere of mass 1.200 kg and diameter 0.2800 m. The system is released from rest and allowed to move. The hanging box falls 0.6100 m before it hits the ground. What is the speed of the hanging block just before it hits the ground
Answer:
v = 1.98 m / s
Explanation:
Let's analyze this exercise a bit, initially the hanging box is at a height h, which is why it has gravitational power energy, as the system is removing the kinetic energy is zero and just when the box reaches the floor its potential energy has dropped to zero and the three bodies have kinetic energy, also between the box and the horizontal surface there is friction, so there is work. Let's use the relationship between work and energy
starting point. Before starting the movement
Em₀ = U = m g h
final point. Just before the block hit the floor
Em_f = K = ½ M v² + ½ I w² + ½ m v²
the speed of the two blocks must be the same to maintain the tension of the rope
The work of the friction force
the friction force opposes the movement so its work is negative
W = - fr x
the law of equilibrium is the largest block
N-W = 0
N = W = Mg
we substitute
W = - μ M g x
the relationship between the work of the non-conservative force (friction) and the energy is
W = Em_f - Em₀
- μ Mg x = ½ M v² + ½ I w² + ½ m v² - mg h
the moment of inertia of a hollow sphere is
I = ⅔ m_s r²
angular and linear velocity are related
v = w r
w = v / r
the distance the horizontal block travels must be the same as the distance the vertical block travels
x = h
let's substitute
- μ M g h = ½ (M + m) v² + ½ (⅔ m_s r²) (v/r) ² - m g h
(- μ M + m) g h = ½ (M + m + ⅔ m_s) v²
v² = [tex]\frac{2(\mu \ M + m ) \ g h }{ M +m + \frac{2}{3} m_s}[/tex]
let's calculate
v² = 2 (-0.15 7.6 +2.4) 9.8 0.61 / (7.6 + 2.4 + 2/3 1.2)
v = [tex]\sqrt{\frac{42.32}{ 10.8} }[/tex]
v = 1.98 m / s
A jug containing water at 26° C while another contains water at 82°C,if a patient wish to bath with water 40°C , the ratio of the mass of hot water to that of cold water is_
Answer:2:7
Explanation:
Quantity of heat energy before mixing= Quantity of heat energy after mixing
M1. S1.T1+ M2.S2.T2= M.S3.T3
Let, .
M1 = mass of cold water
M2 = mass of hot water
S1=S2=S3=S
M=M1+M2
T1=28,T2=82,T3= 40
M1.28 + M2.82= (M1+M2)40
M1.28 + M2.82= M1 40+M2.40
M2.82 -M2.40= M2.40–M1.28
M2.42= M1. 12
M2/M1= 12/42= 2/7
Or
M2: M1= 2:7
please answer fast it doesn't have to be long please :)
Juan drives his car around a curve at a speed of 17.0 m/s. Assume the curve can be approximated by an arc of a circle of radius 122.0 m. If a force of 7380 N is required to maintain the car’s circular motion, what is the car’s mass?
The mass of the car moving with a velocity of 17 m/s is 3115.4 kg.
What is mass?Mass is the quantity of matter a body contains. The S.I unit of mass is kilogram
To calculate the mass of the car, we use the formula below
Formula:
m = Fr/v²...................... Equation 1Where:
m = Mass of the carF = Forcer = Radiusv = VelocityFrom the question,
Given:
F = 7380 Nr = 122 mv = 17 m/sSubstitite these values into equation 1
m = (7380×122)/17²m = 3115.4 kgHence, the mass of the car is 3115.4 kg.
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what are you made of
Answer:
Body stuff
Explanation:
:) <3
The function of the ossicles in the middle ear is to transmit the vibrations of the tympanic membrane caused by sound waves propagated in air to the fluid-filled cochlea. In doing so, the ossicles change the nature of the vibrations. The ear tries to conserve the energy in the wave I,
where v is the wave speed, cramster-equation-2010731130406341613664 is the density of the medium, cramster-equation-2010731131286341613668 is the frequency of the wave and A is the amplitude of the wave.
Calculate the magnitude of the change in A that occurs. The density of air and water is 1.3x10–3g/cm3 and 1.0g/cm3, respectively, and the velocity of sound is 331 m/s in air and 1410 m/s in water. The frequency of the wave remains constant as the wave propagates. (Hint: Begin with to find .)
The frequency of the wave which remains constant as the wave propagates and the magnitude of change in amplitude is 57.2.
What is Density?
Density can be defined as how much matter is contained within a particular volume of a substance. A dense object is the one which weighs more than a less dense object which is the same size. An object which is less dense than that of water will float on it, whereas an object with greater density will sink. The density equation is: D = M / V.
density: dair = 1.3 x 10⁻³ g/cm³, dwater = 1.0 g/cm³,
velocity: vair = 331 m/s, vwater = 1410 m/s
v×d×A² = constant
vair×dair×Aair² = vwater×dwater×Awater²
so,
Aair/Awater = sqrt[(vwater/vair)×(dwater/dair)] = 57.2
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You are assigned the design of a pressurized water tank for a future colony on Mars, where the acceleration due to gravity is 3.71 m/s^2. The pressure at the surface of the water will be 100 kPa, and the depth of the water will be 14.5 m . The pressure of the air outside the tank, which is elevated above the ground, will be 89.0 kPa . The tank's flat bottom has an area of 1.65 m^2, and the density of water is 1000 kg/m^3.
Required:
Find the net downward force on the tank's flat bottom, of area 2.15 m^2, exerted by the water and air inside the tank and the air outside the tank.
Write words with a similar meaning to the given words for old, stubble and room help me?pls
Answer:
Old = senior. geriatric. senescent. unyoung. over-the-hill.
Stubble= bristles
whiskersdesigner stubblehairfacial hairbeardfive o'clock shadowFeedbackWhich ideas did you include in your answer? Check all that apply.
Scientists use relative and absolute dating to determine age of rocks.
Scientists can organize the rocks layers based on their age on the geologic time scale.
The type of rocks and the fossils in the rock layers tell scientists about Earth’s history.
By contrasting a fossil with related rocks and fossils of known ages, relative dating can estimate the fossil's age.
By utilising radiometric dating to track the isotope decay inside the fossil or, more frequently, the rocks it is linked with, absolute dating may pinpoint an object's exact age.
What are the benefits of using relative and absolute dating of rocks?It is possible to identify whether one artefact, fossil, or stratigraphic layer is older than another using relative dating, which does not provide particular dates.
Absolute dating techniques offer more precise dates and times of origin, such as a range in age in years.
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Photo used to help with the question is below!! Please answer! Will mark BRAINLIEST!
⬇⬇⬇⬇⬇⬇⬇
-----------------------------------------------------------------------------------------------------------
Chose the correct answer:
-reflection
-refraction
-absorption
-none of the above
You can see things outside of a beam of light because of? I NEED HELP ASAP
Answer:
Reflected light bounces off of materials that for whatever reason cannot absorb the light. The reflected light is always whatever color it was originally. We do not see things from light that is reflected. We see things from the light that they EMIT.
The rectangular coordinates of a point are (5.00, y) and the polar coordinates of
this point are (r, 67.4°).
a. What is the value of the polar coordinate r in this case?
b. In what quadrant are both the sine and tangent negative?
Answer:
Explanation:
Polar coordinates formula
Summary. To convert from Polar Coordinates (r,θ) to Cartesian Coordinates (x,y) : x = r × cos( θ ) y = r × sin( θ )
What does a step-down transformer change in an alternating current?
Answer: A step-down transformer changes the magnitude of the voltage in an alternating current (AC) electrical signal. It reduces the voltage of the AC signal by using a winding ratio between the primary (input) and secondary (output) coils that is less than 1:1.
Explanation: For example, if the winding ratio of a step-down transformer is 1:0.5, the output voltage of the secondary coil will be half the magnitude of the input voltage of the primary coil. In this case, the transformer would change the AC voltage from a higher value to a lower value.
The transformer does not change the frequency of the AC signal, which is determined by the source of the electrical power. The transformer also does not change the waveform of the AC signal, which is typically a sinusoidal wave.
8:11
GCSE Science - Physics
22 of 25
14 67%
A cat accelerates from rest to 10 m/s
when it sees a dog. This takes 2
the cat?
seconds What is the acceleration of the cat ?
the acceleration of the cat is 5m/s square
1. As air in Earth's atmosphere is heated by
the Sun, the warmer air expands and
becomes less dense than the cooler air. As a
result, the warmer air rises and the cooler
air sinks. What is the cycle of warm air
rising and cool air sinking called?
tidal current
surface current
deep current
convection current
The correct answer is D) convection current.
Convection currents are the cycle of warm air rising and cool air sinking that occurs in Earth's atmosphere (as well as in other fluids) as a result of temperature differences. When a fluid (such as air) is heated, it expands and becomes less dense, causing it to rise. When the warmer fluid cools, it contracts and becomes denser, causing it to sink. This cycle of rising and sinking creates a circular flow known as a convection current.
A 30kg metal ball is dropped from a height of 12.5 m.
a. Find the final velocity when the ball hits the ground.
b. Find the time it takes for the ball to hit the ground.
From conservation of linear momentum, the final velocity is 15.7 m/s and the time taken is 1.6 s
What is Velocity ?Velocity can be defined as a distance travel in a specific direction per time taken. It is a vector quantity.
Given that 30kg metal ball is dropped from a height of 12.5 m.
a. Find the final velocity when the ball hits the ground.
The maximum K.E of the ball at it final velocity will be equal to its maximum P.E at height 12.5 m. That is,
K.E = P.E
1/2mv² = mgh
Where
m = 30 Kgg = 9.8 m/s²h = 12.5 mv = ?Substitute all the parameters
1/2 × 30 × v² = 30 × 9.8 × 12.5
v² = 245
v = √245
v = 15.65 m/s
b. The time it takes for the ball to hit the ground can be found through
h = ut + 1/2gt²
but u = 0
h = 1/2gt²
Substitute all the necessary parameters
12.5 = 1/2 × 9.8 × t²
12.5 = 4.9t²
t² = 12.5/4.9
t² = 2.55
t = √2.55
t = 1.6 s
Therefore, the final velocity when the ball hits the ground is 15.65 m/s and the time it takes for the ball to hit the ground is 1.6 s
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A student conducts an experiment to test how the temperature affects the amount of salt that can dissolve in water. In the experiment, she uses 150 milliliters of water in each trial and stirs for five minutes each time.
The independent variable that we have in the experiment is the temperature. Option B
What is an experiment?We know that if we are talking about an experiment, what we have to look at is that we must consider the interplay of the variables that is taking place in the process. As we change one of the variables in the experiment, there would be a change in another variable in the experiment also.
Now, the variable that we usually beging to alter is the one that we call the independent variable. As we change the value of this particular variable, there would be a change in the independent variable.
We have been told that; a student conducts an experiment to test how the temperature affects the amount of salt that can dissolve in water.
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Which statement correctly characterizes the relationship between water vapor and air
Answer:
A
Explanation:
may i be marked brainliest?
Statement A correctly characterizes the relationship between water vapor and air. Colder air can hold more water vapor.
What is dew point temperature?
Under constant air pressure and water content, the dew point is the temperature at which air must be chilled to become saturated with water vapor.
When temperatures fall below the dew point, moisture capacity decreases and airborne water vapor condenses to create liquid water known as dew.
As the temperature of the air increases the vapor become more and dry. So that older air can hold more water vapor.
Hence,statement A correctly characterizes the relationship between water vapor and air.
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i understand how something about the pod could have affected its velocity change.
yes or not yet.
EXPLAIN your answer choice.
A stronger force can cause a greater change in an object's velocity. The correct option is yes
What caused the pod to change direction?The force exerted by the thrusters caused the pod to change direction. The thrusters on the ACM pod exerted the same strength force as thrusters on other pods on other missions. If the same strength force is exerted on two objects but the objects have different masses the object with less mass will have a greater change in velocity.
Therefore pod would have had to have a lighter mass meaning a smaller amount of force would have had to be exerted onto the pod making it move in the opposite direction.
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Determine the speed of the 50-kg cylinder after it has descended a distance of 2 m, starting from rest. Gear A has a mass of 10 kg and a radius of gyration of 125 mm about its center of mass. Gear B and drum C have a combined mass of 30 kg and a radius of gyration about their center of mass of 150 mm
This question is incomplete, the missing image is uploaded along this answer below.
Answer:
the speed of the 50-kg cylinder after it has descended is 3.67 m/s
Explanation:
Given the data in the question and the image below;
relation between velocity of cylinder and velocity of the drum is;
V[tex]_D[/tex] = ω[tex]_c[/tex] × r[tex]_c[/tex] ----- let this be equ 1
where V[tex]_D[/tex] is velocity of cylinder, ω[tex]_c[/tex] is the angular velocity of drum C and r[tex]_c[/tex] is the radius of drum C
Now, Angular velocity of gear B is;
ω[tex]_B[/tex] = ω[tex]_C[/tex]
ω[tex]_B[/tex] = V[tex]_D[/tex] / r[tex]_c[/tex] -------- let this equ 2
so;
V[tex]_D[/tex] / 0.1 m = 10V[tex]_D[/tex]
Next, we determine the angular velocity of gear A;
from the diagram;
ω[tex]_A[/tex]( 0.15 m ) = ω[tex]_B[/tex]( 0.2 m )
from equation 2; ω[tex]_B[/tex] = V[tex]_D[/tex] / r[tex]_c[/tex]
so
ω[tex]_A[/tex]( 0.15 m ) = (V[tex]_D[/tex] / r[tex]_c[/tex] ) 0.2 m
substitutive in value of radius r[tex]_c[/tex] (0.1 m)
ω[tex]_A[/tex]( 0.15 m ) = (V[tex]_D[/tex] / 0.1 m ) 0.2 m
ω[tex]_A[/tex]( 0.15 ) = 0.2V[tex]_D[/tex] / 0.1
ω[tex]_A[/tex] = 2V[tex]_D[/tex] / 0.15
ω[tex]_A[/tex] = 13.333V[tex]_D[/tex] ----- let this be equation 3
To get the speed of the cylinder, we use energy conversation;
assuming that the final position is;
T₁ + ∑[tex]U_{1-2[/tex] = T₂
0 + m[tex]_D[/tex]gh = [tex]\frac{1}{2}[/tex]m[tex]_D[/tex]V²[tex]_D[/tex] + [tex]\frac{1}{2}I_A[/tex]ω²[tex]_A[/tex] + [tex]\frac{1}{2}I_B[/tex]ω²[tex]_B[/tex]
so
m[tex]_D[/tex]gh = [tex]\frac{1}{2}[/tex]m[tex]_D[/tex]V²[tex]_D[/tex] + [tex]\frac{1}{2}[/tex](m[tex]_A[/tex]k[tex]_A[/tex]²)(13.333V[tex]_D[/tex])² + [tex]\frac{1}{2}[/tex](m[tex]_B[/tex]k[tex]_B[/tex]²)(10V[tex]_D[/tex])²
we given that; m[tex]_D[/tex] = 50 kg, h = 2 m, m[tex]_A[/tex] = 10 kg, k[tex]_A[/tex] 125 mm = 0.125 m, m[tex]_B[/tex] = 30 kg, k[tex]_B[/tex] = 150 mm = 0.15 m.
we know that; g = 9.81 m/s²
so we substitute
50 × 9.81 × 2 = ( [tex]\frac{1}{2}[/tex] × 50 × V[tex]_D[/tex]²) + [tex]\frac{1}{2}[/tex]( 10 × (0.125)² )(13.333V[tex]_D[/tex])² + [tex]\frac{1}{2}[/tex]( 30 × (0.15)²)(10V[tex]_D[/tex])²
981 = 25V[tex]_D[/tex]² + 13.888V[tex]_D[/tex]² + 33.75V[tex]_D[/tex]²
981 = 72.638V[tex]_D[/tex]²
V[tex]_D[/tex]² = 981 / 72.638
V[tex]_D[/tex]² = 13.5053
V[tex]_D[/tex] = √13.5053
V[tex]_D[/tex] = 3.674955 ≈ 3.67 m/s
Therefore, the speed of the 50-kg cylinder after it has descended is 3.67 m/s
In transverse waves, the movement of the particles is _________
O in a circle
O left to right
O diagonal
O up and down
Answer:
the correct answer is up and down
Your friend Christy has always been good at making schedules-she plans her days out to the minute and
loves helping others be more productive in this way too. Which career in astronomy might she be suited for?
Ground Control
CAPCOM
Flight Controller
Flight Director
She might be best suited for a profession as an astronomy flight controller. The target speed for every one of the 4 motors is determined by the flight controller using the information acquired by the sensors.
Why study astronomy?The goal of astronomy is to explain whatever we see within the universe, including the planets and comets inside our own solar system, far-off galaxies, and echoes of something like the Big Bang.
Is math required for astronomy?Math is constantly used by astronomers. When using a telescope to see celestial objects, one application of it is this. The camera that is mounted on the telescope essentially captures a series of numbers, which could represent the amount of light that various celestial objects emit.
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A resistor with a resistance of 2 MΩ is connected in series with a 5 µF capacitor and a battery with emf 10 V. The capacitor has originally a charge of 5 µC and then discharged. At what time will the charge be equal to 1µC?
A. 16 sec
B. 1.6 sec
C. 3.2 sec
D. 8 sec
Sarah and Devon are involved in an egg catching contest. They stand a fixed distance apart and toss a raw egg back and forth to each other. The goal is to catch the egg without it breaking. Which of the following would be the best strategy for Devon to employ as he attempts to catch the egg tossed by Sarah? Devon should…
A
Decrease the time it takes to stop the egg once it hits his hand.
B
Increase the time it takes to stop the egg once it hits his hand.
C
Tell Sarah to toss the egg at a very small angle to decrease the time the egg is in the air.
D
Tell Sarah to toss the egg at a rather large angle to increase the time the egg is in the air.
E
Use only one hand to catch the egg so that less mass is involved in stopping the egg.
Answer:
The correct answer is - B. Increase the time it takes to stop the egg once it hits his hand.
Explanation:
In order to catch the egg the force and time makes an impulse to the egg to change its momentum and bring it to rest. In order to change the momentum, one needs to decrease the force exerted onto the egg and increase the time it takes to make it rest.
Less force can be given to the egg by increasing the time to bring it to rest stop the egg once it hits his hand. Other than this it should be caught to the sides.
A student attempts to spin a rubber stopper(m=0.5kg) in a horizontal circle with a radius of 0.75m.If the stopper completes 2.5 revolutions every second,determine the following; a)The centripetal acceleration. b)The centripetal force.
Explanation:
a) ac = r(omega)^2
where omega = 2.5 rev/s
r = 0.75 m
We need to convert rev/s first into rad/s:
2.5 rev/s × (2pi rad/rev) = 5pi rad/s = omega
Therefore, the centripetal acceleration ac is
ac = (0.75 m)×(5pi rad/s)^2
= 185 m/s^2
b) Fc = mac
= (0.5 kg)(185 m/s^2)
= 92.5 N