an animal shelter has fixed weekly expenses of 750. each animal in the shelter cost an additional 6 a week. during the winter month, the weekly expenses are at the most 900. write and solve an inequality that represents the number of animal at the shelter for expenses to be at the most 900 a week

Answer:

k=-4

Step-by-step explanation:

k+7=3

take way 7 from both sides

k=-4

Answer: 1. (8b + 5)

2. (22p - 9)

HAVE A GREAT DAY!!!!

Step-by-step explanation:

The resulting graph should have a period of 4, an amplitude of 3, a midline of y=-1, and no reflection over the x-axis.

What are the period and amplitude of a graph?

The period of a function is the smallest distance over which the function repeats itself. In other words, it is the length of one complete cycle of the function. For a sine or cosine function of the form f(x) = a sin(bx) or f(x) = a cos(bx), the period is given by 2π/b.

The most simple sine function considered the parent function, is:

  y = sin(x)

That function has:

Midline, also known as rest or equilibrium position: y = 0

Minimum: - 1

Maximum: 1

Amplitude: the distance between a minimum or a maximum and the midline = 1

period: the interval of repetition of the function = 2π

The more general sine function is:

 y = Asin(Bx + C) + D            

That function has:

Midline: y = D (it is a vertical shift from the parent function)

Minimum: - A + D

Maximum: A + D

Amplitude: A

period: 2π/B

phase shift: C (it is a horizontal shift of from the parent function)

Now, you have to draw the sine function with the given key features:

Period = 4 ⇒ 2π/B = 4 ⇒ B = π/2

Amplitude, A = 3

midline y = - 1 ⇒ D = - 1

y-intercept = (0, -1)

Substitute the know values and use the y-intercept to find C:

y = 3sin(2x/π + C) -1

Substitute (0, -1)

-1 = 3sin(2(0)/π + C) -1

3sin(C) = 0

sin(C) = 0

C = 0

Hence, the function to graph is:

             y = 3sin(2x/π ) -1

To draw that function use this:

Maxima: 3(1) - 1 = 3 - 1 = 2, at x = 1 ± 4n (n = 0, 1, 2, 3, ...)

Minima: 3(-1) - 1 = - 3 - 1 = -4

y-intercept: (0, - 1)

x-intercepts: the solutions to 0 = 3sin(πx/2) = - 1

first point of the midline: (0, -1) it is the same y-intercept

Hence, the resulting graph should have a period of 4, an amplitude of 3, a midline of y=-1, and no reflection over the x-axis.

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1.The equation that represents the proportional relationship is y = 4x + 3.

2. The corresponding equation that represents a proportional relationship is y = (1/5)x.

3. y = 7/2x.

4. when y = 21 is x = 6.

5. y = 8 is x = 3.33.

The slope of a function is the rate of change in the function's output (y-value) relative to the change in its input (x-value).

The equation that represents a proportional relationship is y = mx + b, where m is the slope of the equation.

In this equation, x and y are in direct proportion.

1.The equation that represents the proportional relationship is y = 4x + 3. This equation is in the form of y = mx + b, with m being the coefficient of x, which is 4, and b being the constant, which is 3.

2. The corresponding equation that represents a proportional relationship is y = (1/5)x.

This equation is in the form of y = mx + b, with m being the coefficient of x, which is 1/5, and b being the constant, which is 0.

3. The equation that represents this relationship is y = 7/2x.

This equation is in the form of y = mx + b, with m being the coefficient of x, which is 7/2, and b being the constant, which is 0.

4. The value of x when y = 21 is x = 6.

This is because the equation representing the proportional relationship is y = 7/2x, and

when y = 21, 21 = 7/2x,

so x = 6.

5. The value of x when y = 8 is x = 3.33.

This is because the equation representing the proportional relationship is y = 12/5x, and when y = 8, 8 = 12/5x, so x = 3.33.

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Answer:

y + 13 = - [tex]\frac{2}{3}[/tex] (x + 11)

Step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b ) a point on the line

here m = - [tex]\frac{2}{3}[/tex] and (a, b ) = (- 11, - 13 ) , then

y - (- 13) = - [tex]\frac{2}{3}[/tex] (x - (- 11) ) , that is

y + 13 = - [tex]\frac{2}{3}[/tex] (x + 11)

Step-by-step explanation:

angle c = 180 -19 - 139 = 22 degrees   (  interior angles of a triangle sum to 180 degrees)

Now you can use law of sines to find the missing  side lengths

12 / sin 22  =  DC /sin19

DC = sin 19 * 12 / sin 22  = 10.4 units

12/sin 22 = BC / sin 132

BC =  sin132 * 12 / sin 22 =  23.8 units

No, the process for multiplying polynomials is different from adding and subtracting.

What exactly are polynomials?

Polynomials are algebraic expressions made up of variables and coefficients that are joined using the addition, subtraction, and multiplication operations. The variables in a polynomial can be raised to non-negative integer powers.

For example, the expression 3x² - 2x + 1 is a polynomial, where 3, -2, and 1 are the coefficients, and x², x, and 1 are the variables with their respective powers.

Now,

The process for adding and subtracting polynomials involves combining like terms. To add or subtract two polynomials, we simply combine the coefficients of the same degree terms.

For example, to add the polynomials 2x² + 3x + 4 and 4x² - 2x - 1, we group the like terms and add the coefficients:

(2x² + 4x²) + (3x - 2x) + (4 - 1) = 6x² + x + 3

To subtract the polynomial 4x² - 2x - 1 from the polynomial 2x² + 3x + 4, we change the sign of the second polynomial and then combine the like terms:

(2x² + 3x + 4) - (4x² - 2x - 1) = 2x² + 3x + 4 - 4x² + 2x + 1 = -2x² + 5x + 5

The process for multiplying polynomials is different from adding and subtracting. When we multiply two polynomials, we need to distribute each term of polynomials, and then combine the like terms.

For example, to multiply the polynomials (x + 2) and (x - 3), we use the distributive property:

(x + 2)(x - 3) = x(x - 3) + 2(x - 3) = x² - 3x + 2x - 6 = x² - x - 6

As we can see, the process for multiplying polynomials is different from adding and subtracting, but all three operations involve combining like terms in some way.

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The range of the difference in means' 99% confidence level is from -1.42 to 10.02. The true mean difference between Treatments 1 and 2 falls between these two numbers, we can claim with 99% certainty for t-distribution.

We can use a t-distribution to determine a confidence interval for the difference in means using paired data. Prior to determining the mean difference and standard deviation of the differences, we first compute the difference between the paired observations.

Because we are only interested in the mean difference between Treatments 1 and 2, we compute the differences for each pair and get the following outcomes:

6 -3 8 2 6

The sample mean and sample standard deviation of these differences are then computed. The average of these variations is the sample mean.

(6 - 3 + 8 + 2 + 6)/5 = 3.8

The square root of the sum of squared differences divided by the degrees of freedom yields the sample standard deviation.

[tex]\sqrt{[(6 - 3.8)^2 + (-3 - 3.8)^2 + (8 - 3.8)^2 + (2 - 3.8)^2 + (6 - 3.8)^2]/(5-1)) } = 3.06[/tex]

The 99% confidence interval for the mean difference can then be determined using the t-distribution. Our sample size is tiny (n=5), so we utilise a t-distribution with four degrees of freedom.

The sample mean, which is 3.8, provides the most accurate approximation of the mean difference.

We must determine the crucial value of t for a 99% confidence interval with 4 degrees of freedom in order to determine the margin of error. The crucial value, which we determine using a t-table, is 4.604.

The margin of error is:

[tex]4.604 * (3.06/\sqrt{5}) = 5.22[/tex]

Lastly, by deducting and adding the margin of error from the sample mean, we can determine the confidence interval:

3.8 - 5.22 = -1.42

3.8 + 5.22 = 10.02

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[tex]\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2 \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{26}\\ a=\stackrel{adjacent}{2x}\\ o=\stackrel{opposite}{2x-14} \end{cases} \\\\\\ (26)^2= (2x)^2 + (2x-14)^2\implies 676 = (4x^2)+(4x^2-56x+14^2) \\\\\\ 676=4x^2+4x^2-56x+14^2\implies 676=8x^2-56x+196 \\\\\\ 0=8x^2-56x-480\implies 0=8(x^2-7x-60) \\\\\\ 0=x^2-7x-60\implies 0=(x-12)(x+5)\implies x= \begin{cases} ~~ 12 ~~ \checkmark\\ -5 ~~ \bigotimes \end{cases}[/tex]

now, -5 is a valid value for "x", however in this case we can't use it, because that makes one of our sides negative and all sides must be a positive value.

[tex]\stackrel{ 2(12) }{\text{\LARGE 24}}\hspace{5em}\stackrel{ 2(12)-14 }{\text{\LARGE 10}}\hspace{5em}\text{\LARGE 26}[/tex]

Let's call Michelle's speed "M" and John's speed "J". We know that John's speed is 10 miles per hour faster than Michelle's speed, so we can express this as:

J = M + 10

We also know that Michelle is 50 miles ahead of John, so we can express this as:

Distance = 50 miles

Now we can use the formula:

Distance = Rate x Time

We want to know how long it will take John to catch up to Michelle, so we can call this time "t". We can use the formula for both Michelle and John, and set their distances equal to each other since they will meet at the same point:

M * t + 50 = J * t

Now we can substitute J with M + 10, and simplify:

M * t + 50 = (M + 10) * t

M * t + 50 = M * t + 10t

50 = 10t

t = 5

Therefore, John will catch up to Michelle in 5 hours (answer choice B).

Answer:

Step-by-step explanation:

because 110

Answer:

Answer is option  D

Step-by-step explanation:

Hope this helps:)

Answer:

[tex]a_{n}[/tex] = 7n - 6

Step-by-step explanation:

there is a common difference between consecutive terms , that is

8 - 1 = 15 - 8 = 22 - 15 = 29 - 22 = 7

this indicates the sequence is arithmetic with nth term

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

here a₁ = 1 and d = 7 , then

[tex]a_{n}[/tex] = 1 + 7(n - 1) = 1 + 7n - 7 = 7n - 6

Answer:

7n-6

Step-by-step explanation:

Work out the difference of the sequence:

8-1=7

Now you have the first part of the equation: 7n

n is the number that the integer is on the sequence

In this case:

1 = 1 as 1 is the first number of the sequence

And 2 = 8 as 8 is the 2nd number of the sequence

To find the full equation:

Do 7x1 to get you 7

Now see how far the 1st number is from 7

In this case you would do:

7-1 which gives you 6

Since you subtracted it to find the difference, it would be:

- 6

Therefore your answer would be 7n-6

To check it:

Times 7 by let's say 3 to get you 21

Then subtract 6 to get 15.

This is proven right as the 3rd number of the given sequence is 15.

Hope this helped

The number of girls in the gym must be: g ≥ 16

Let's define the variable "g" to be a representation of the number of girls in the gym.

We know that there are 30 students in total. Therefore, the number of boys in the gym will be:

b = 30 - g

We also know that there are at least 16 girls in the gym. So, we can write the inequality:

g ≥ 16

This inequality means that the number of girls in the gym must be greater than or equal to 16.

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Answer:

The slope of this line is 2.

Step-by-step explanation:

Start at (1, 0). Go up 4 units, then right 2 units. You will end at (3, 4). The slope of this line is 2.

Consequently, the retirement account's income rate is roughly 3.8%. (rounded to one decimal place).

Consider borrowing $1,000 at a 10% interest rate for seven years. Your interest for the first year would be $100. Your interest payment for the following year would be made up of the original sum plus interest, or $1,100. As a result, your income for the following year would be $110 ($1,100 multiplied by 0.10).

The interest rate can be calculated using the continuous compounding formula:

[tex]A=P e^{r t}[/tex]

where:

A = final balance = $9,483.80

P = initial investment = $6,398

r = rate

t = time in years = 16

Substituting the given values, we have:

$9,483.80 = $6,398[tex]e^{r16}[/tex]

Dividing both sides by $6,398, we get:

1.4829 = [tex]e^{r16}[/tex]

Using the simple logarithm of both parts, the following is obtained:

ln(1.4829) = r × 16

Solving for r, we get:

r = ln(1.4829)/16

r ≈ 0.038

Therefore, the interest rate of the retirement account is approximately 3.8% (rounded to one decimal place).

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$26.40

ten percent is 88 divided by 10= 8.8

8.8 multiplied by 3 is 26.40

Answer:

Therefore, the shuffleboard disk will travel a distance of 4.71 meters before coming to a stop, which is less than the length of the court (14.3 meters).

Step-by-step explanation:

We can start by using the work-energy principle, which states that the net work done on an object is equal to its change in kinetic energy. In this case, we can assume that the initial kinetic energy of the disk is entirely converted to work done by friction, which causes the disk to come to a stop. The equation can be written as:

Work done by friction = Change in kinetic energy

The work done by friction can be calculated using the formula:

Work = force x distance

The force of friction can be found using the formula:

Force of friction = coefficient of friction x normal force

The normal force is equal to the weight of the disk, which can be found using the formula:

Weight = mass x gravity

Substituting the values given in the problem, we get:

Weight = mass x gravity = 0.75 kg x 9.81 m/s^2 = 7.3575 N

Force of friction = coefficient of friction x normal force = 0.34 x 7.3575 N = 2.4985 N

Work done by friction = Force of friction x distance

We can solve for the distance by rearranging the equation as:

Distance = Work done by friction / Force of friction

The initial kinetic energy of the disk can be found using the formula:

Kinetic energy = 0.5 x mass x velocity^2

Substituting the values given in the problem, we get:

Kinetic energy = 0.5 x 0.75 kg x (5.6 m/s)^2 = 11.76 J

Using the work-energy principle, we know that the work done by friction is equal to the change in kinetic energy, which is:

Work done by friction = Kinetic energy = 11.76 J

Substituting this value and the force of friction into the distance formula, we get:

Distance = Work done by friction / Force of friction = 11.76 J / 2.4985 N = 4.71 m

Therefore, the shuffleboard disk will travel a distance of 4.71 meters before coming to a stop, which is less than the length of the court (14.3 meters).

Answer:

x=14

Step-by-step explanation:

80+58=138

180-138=42

42÷3=x

14=x

Answer:

x= 14

Step-by-step explanation:

80 + 58 = 138°

A triangle has 180°

180-138= 42°

Put into equation

42=3x

42/3=14

X=14

Polynomials are functions that are constructed from a sum of powers of the independent variable x, multiplied by coefficients. In this case, we have powers of x from 0 to 3, and the coefficients are 3, 5, -11, and 3.

To evaluate the function for a particular value of x, we substitute that value in place of x and perform the necessary arithmetic. For example, to find f(2), we substitute x = 2 in the expression for f(x):

f(2) = 3(2)^3 + 5(2)^2 - 11(2) + 3

= 24 + 20 - 22 + 3

= 25

Therefore, f(2) = 25. We can similarly evaluate the function for other values of x.

From the expression, the form of the d⁵ is provided by the stated assertion.

A group of words joined with the actions +, -, x, or  form an expression, such as 4 x 3 or 5 x 2  3 x y + 17. A statement containing the equals symbol, such as 4 b 2 = 6, says that two formulas are equivalent in value and is known as an equation.

As an illustration, the expression x + y is one where both x and y have words with an addition function in between. There are two kinds of expressions in mathematics: numerical expressions, which only comprise integers, and algebraic expressions, which also include variables.

[tex]d^{(8-3)} = d^5[/tex]

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Enter an expression equivalent to (d^(8))/(d^(3)) in the form, d^(n).

The value of t for a t-distribution with 45 degrees of freedom such that the area to the right of t equals 0.010 is approximately -2.326.

With its bell-shaped structure and heavier tails, the t-distribution, commonly referred to as the Student's t-distribution, is a kind of probability distribution that resembles the normal distribution. When there are insufficient samples or unknown variances, it is used to estimate population parameters. T-distributions have broader tails than normal distributions because they are more likely to contain extreme values.

To find the value of t for a t-distribution with 45 degrees of freedom such that the area to the right of t equals 0.010, we can use a t-table or a calculator. Using a calculator, we can use the inverse t-distribution function. The inverse t-distribution function gives us the value of t for a given probability and degrees of freedom.

Using this function, we have:

t = invT(0.010, 45) ≈ -2.326

Rounding this to three decimal places gives us the answer:

t ≈ -2.326

Therefore, the value of t for a t-distribution with 45 degrees of freedom such that the area to the right of t equals 0.010 is approximately -2.326.

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The derivative of f(x) = 3·x² + 7·x + 6, at x = 4, f'(4) is presented as follows;

f'(4) is the limit as x → 4 of the expression 6·x + 7.

The value of this limit is 31

The equation of the tangent line to the parabola y = 3·x² + 7·x + 6 at the point (4, 82) is y = 31·x - 42

The derivative of a function is a measure of how much the output values of the function changes as the input value is changed. The derivative is the limit of the difference quotient as the change in input approaches zero. The limit is the instantaneous rate of change of the function at a specified input variable value.

The value of f'(4) using the definition of derivative, can be obtained using the following definition;

f'(x) = lim(h → 0)[f(x + h) - f(x)]/h

Plugging in x = 4, and f(x) = 3·x² + 7·x + 6, we get;

f'(4) = lim(h → 0)[f(4 + h) - f(4)]/h

f'(4) = lim(h → 0)[3·(4 + h)² + 7·(4 + h) + 6 - (3·(4)² + 7·(4) + 6)]/h

f'(4) = lim(h → 0)[(3·h + 31)·h]/h

f'(4) = lim(h → 0)[(3·h + 31)]

Therefore;

f'(4) = lim(h → 0)[(3·h + 31)] = 31

f'(4) = 31

Therefore; f'(4) is the limit as x → 4 of the expression 6·x + 7, therefore. The value of this limit is 31

The point-slope form of the equation of a line can be used to find the equation of the parabola as follows;

y - y₁ = m·(x - x₁)

The point (x₁, y₁) and the slope of the line is m

The point on the parabola of the tangent is; (4, 82)

The slope of the tangent line at x = 4, f'(4) = 31

The tangent equation is therefore;

y - 82 = 31·(x - 4)

y =  31·(x - 4) + 82 = 31·x - 42

The equation of the tangent line to the parabola, y = 3·x² + 7·x + 6, at the point (4, 82) is; y = 31·x - 42

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To solve for z, we can subtract 7 from both sides to get -5/z = -6. Finally, we can multiply both sides by -1 to get z = -7. Therefore, the solution to this equation is z = -7.

A logarithm is an equation that expresses the relationship between an exponent and its base. In this equation, we have two logarithms, ln (-5z) and ln [tex](z^2-7z)[/tex], which are both equal to each other. To solve this equation, we can use the properties of logarithms to isolate the variable. First, we can rewrite the equation as ln (-5z) - ln [tex](z^2-7z)[/tex]= 0, which can then be simplified to ln (-5/z+7) = 0. We can then take the inverse of both sides to get -5/z+7 = 1. To solve for z, we can subtract 7 from both sides to get -5/z = -6. Finally, we can multiply both sides by -1 to get z = -7. Therefore, the solution to this equation is z = -7.

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Answer:

Nathan would have to pay 20 dollars if he parked for 6 hours.

2t+8

Step-by-step explanation:

Answer:

there are 41 white marbles in the bag.

Step-by-step explanation:

Let's use the variable w to represent the number of white marbles and y to represent the number of yellow marbles.

From the problem, we know that:

w + y = 49 (since there are 49 marbles in total)

And we also know that:

w = 5y + 1 (since the number of white marbles is 1 more than 5 times the number of yellow marbles)

Now we can use substitution to solve for w:

w + y = 49

(5y + 1) + y = 49 (substitute w = 5y + 1)

6y + 1 = 49 (combine like terms)

6y = 48 (subtract 1 from both sides)

y = 8 (divide both sides by 6)

Now we know there are 8 yellow marbles. We can use this information to find the number of white marbles:

w = 5y + 1

w = 5(8) + 1

w = 41

we can simplify |x+3| to x+3 when x is greater than 5. This is the final answer.The absolute value of a number is the distance of the number from zero on a number line, regardless of whether the number is positive or negative.

For example, the absolute value of -5 is 5, because 5 is the distance of -5 from zero on the number line.

In this problem, we are asked to simplify the expression |x+3| without using the absolute value symbol. We are also given the condition that x is greater than 5.

When x is greater than 5, we know that x+3 is also greater than 5+3=8. This is because x is already greater than 5, and adding 3 to it makes it even larger. So, we can say that x+3 is positive when x is greater than 5.

Now, let's consider what the absolute value of x+3 means in this context. Since x+3 is positive when x is greater than 5, the absolute value of x+3 is just x+3 itself. This is because the absolute value of a positive number is just the number itself.

Therefore, we can simplify |x+3| to x+3 when x is greater than 5. This is the final answer.

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The independent variable and the dependent variable are the number of dollars spent and the number of tickets bought

Given that we have the following statement:

The independent variable is the input value

i.e. the number of dollars spent

Similarly, the dependent variable is the output value

i.e. the number of tickets bought

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Answer:

Volume =

Step-by-step explanation:

Volume = length x width x depth

Volume = (6.5 x 3 x 1.6)m

Volume = 31.2m