Answer:
It's 2–
Explanation:
Usually, in ionic bonds, these elements will receive 2 electrons, so its ion will carry a 2– charge
The ionic charge its ion will carry will be 2-
An element is required to have 8 electrons in its outermost shell to assume it's full octet configuration.
The statement above of course excludes Hydrogen and helium which have only 1 and 2 electrons respectively.
An element with 6 Valence electrons would require 2 electrons to assume the full octet configuration.
As such, it is liable to accept 2 electrons from an electropositive element or group of elements to complete it's octet.
Therefore, accepting 2 electrons adds 2 negative charges and consequently, the ionic form of the element carries a 2- ionic charge
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how do i solve this?
Answer:
hmmm i dont know....
Explanation:
i just wanted free point. TANKS YOU SIR!!
A 0.0250kg golf ball is placed on a spring that is compressed 0.0500m. How high will the ball get when the spring is released if the spring constant is 200.N/m?
20.4m
2.04m
1.02m
40.8m
Answer:
1.02m
Explanation:
Apply Principle of conversation of energy,
mgh = 1/2 Ke²
s dispersion dispersion
, refraction
Answer:
If you want definition, here it is:
Dispersion is defined to be the spreading of white light into its full spectrum of wavelengths. Refraction is responsible for dispersion in rainbows and many other situations. The angle of refraction depends on the index of refraction, as we saw in The Law of Refraction.
The density of gold is 19.3 g cm³. What is the mass of a bar of gold in Kg that measures 6 cm x 4 cmx to 2 cm ?
solve
Answer: 0.9264 kg
Explanation: [I'll use "cc" for cubic centimeter, instead of cm^3.
The volume is 6cm*4cm*2cm = 48 cm^3 (cc).
Density of Au is 19.3 g/cc
Mass of gold = (48 cc)*(9.3 g/cc) = 926.4 grams Au
1 kg = 1,000 g
(926.4 grams Au)*(1 kg/1,000 g) = 0.9264 kg, 0.93 kg to 2 sig figs
At gold's current price of $57,500/kg, this bar is worth $53,268. Keep it hidden from your lab partner (and instructor).
define null point
define null point
Answer:
In physics a null is a point in a field where the field quantity is zero as the result of two or more opposing quantities completely cancelling each other
how to convert m/s to miles/seconds
Answer:
Divide by 1609
Explanation:
So to convert from m/s to m/s divide by 1609
How do particles differ after a physical change
Answer:
In physical changes, no new materials are formed and the particles do not change apart from gaining or losing energy. ... Particles stay the same unless there is a chemical change whether the matter is solid, liquid or gas. Only their arrangement, energy and movement change.
Explanation:
A bracelet's mass is 80 g, and its volume is 10 cm3. What is its density?
Answer:
Density is 8 g/cm³
Explanation:
[tex]density = \frac{mass}{volume} \\ [/tex]
mass » 80 g
volume » 10 cm³
[tex]density = \frac{80 \: g}{10 \: {cm}^{3} } \\ \\ = 8 \: {gcm}^{ - 3} [/tex]
Answer:
mass=80
volume=10
density=mass/volume
which is 80/10
so the density is equals to 10.
10. Numerical problems:
b. A stone is thrown vertically upwards with an initial velocity of 20 m/sec.find the maximum height it reaches and the time taken by it to reach the height. (g = 10 m/s2).
c. A car is moving at a rate of 72 km/hr. How far does the car move when it stops after 4 seconds?
d. A bus starts from rest. If the acceleration is 2 m/s2, find
1. the distance travelled.
2. the velocity after 2 seconds.
e. A stone is thrown vertically upward with the velocity of 25 m/s. How longo it take to reach the maximum height? Also calculate the height.
with process please
Answer:
a)20 m,2s
Explanation:
Given
Initial velocity=20 m /sec
g=10 m/s square
v =0m/s
h =?
t =?
now,
v = U +gt
=v=20 +10t
Or,10t=20
Or,t=20
10
therfore ,2 s.
Again,
h=ut -1 gt square
2
Or, h=20×2-1×10(2)square (multiply and cut )2×5 =10
; 2
Or,40-5×4
therefore , 20m
People used to believe that if a penny was dropped ff Tom the Empire State Building, how fast would it be moving just before impact on ground? From release of your hand it takes 45 seconds falling at 9.8 m/s^2 due to gravity l.
Answer:
99
Explanation:
For which length of wire are the readings of resistance the most precise
What is pascal law? Define it
Answer:
Pascal's law states that the pressure exerted anywhere in a confined incompressible liquid is transmitted equally in all directions irrespective of the area on which it acts and it always acts at right angles to the surface of containing vessel.
have a great day sister
Electrons could be swiped off of the
outermost shell of the electron
True
False
can sound waves propagate in vacuum if yes why if no why not??
Answer:
please mark me brainliest
Explanation:
No, sound waves cannot travel in a vacuum. This is because sound waves are mechanical waves that need a medium (such as air and water) to travel. Sound in physics is defined as a vibration that propagates as an audible wave of pressure, through a medium such as a gas, liquid or solid.
35/h expressed in meter per second
Answer:
9.722
Explanation:
35*1000÷1×60*60
35000÷3600
9.722
An object of mass 2kg is thrown vertically downwards with an initial kinetic energy of 100J. What is the distance fallen by the object at the instant when its kinetic energy has doubled
The distance fallen by the object at the instant when its kinetic energy has doubled is 5.097m
The kinetic energy of an object is the energy possessed by the body by virtue of its motion.
The gravitational potential energy (energy due to the virtue of its position) of a body is being converted to Kinetic energy once an object falls.
Using the law of conservation of energy according to the equation:
Kinectic Energy = Potential Energy
Since PE = mgh
KE = PE = mgh
Given the following parameters
KE = 100J
m = 2kg
g = 9.81m/s²
Required
Height h
Substitute the required values into the formula
100 = 2(9.81)h
h = 100/19.62
h = 5.097m
Hence the distance fallen by the object at the instant when its kinetic energy has doubled is 5.097m
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electrons are tiny particles with very small negative charges when two electrons are place near each other the electric force pushes them apart what does this tell you about the mass of an electron
Answer:
Explanation:
like charges repel each other if one group of electrons has more mass it will push the other smaller mass of electrons away
if you are planning to go for hiking on the mountain,what type of shoes will you wear
Answer:
you will have to wear hiking shoes or sports shoes
what happens when you try to walk on the smooth well polished floor wearing brand new shoes
4) Gabo bought three chicken dinners for $6.95 each and one hamburger meal for $5.75. He and three friends decide to divide the cost of the meals equally. How much money does Gabo receive in total from his three friends?
(A) $6.35 (B) $6.65 (C) $19.65 (D) $19.95 (E) $26.60
Answer: the answer is d $19.95
Explanation:
chicken dinner: 6.95 x 3 = 20.85
burger: 5.75
20.85 + 5.75 = 26.6
26.6 divided by 4 (bc theres 4 ppl and the bill needs to be split equally)
26.6/4= 6.65
and since 3 friends are paying him back u gotta do 6.65 x 3 = 19.95
The quantity of matter inside the body is?
Answer:
mass is the quantity of matter inside the body
Answer:
The mass of a body is the quality of matter it contains
a block occupies 0.2587 ft. what is the volume in mm?
Answer:
70
Explanation:
Who exerts more pressure? a) A girl of 50 kg, wearing heels with an area of 1 cm2. b) An elephant of 4000 kg with foot area of 250 cm2.
Answer:
The girl exerts more pressure.
Explanation:
Pressure can be defined as the force exerted normally or perpendicularly per unit area.
i.e P = F/A
Girls
Area of the heel = 1cm² = 10^(-4) m²
Force = mg = 50 × 10 = 500N
Pressure =
[tex] \frac{500}{10 ^{ - 4} } [/tex]
[tex] = 5 \times {10}^{6}[/tex]
Elephant
Area = 250cm² = 2.5 x 10^(-2)b m²
Force = mg = 40000N
Pressure =
[tex] \frac{40000}{2.5 \times {10}^{ - 2} } [/tex]
[tex] = 1.6 \times {10}^{6} [/tex]
Runner A is initially 8.4 km west of a flagpole and is running with a constant velocity of 4.8 km/h due east. Runner B is initially 6.0 km east of the flagpole and is running with a constant velocity of 8.4 km/h due west. What will be the distance of the two runners from the flagpole when their paths cross?
Thanks for your help :)
Answer:
Distance = 2m
Explanation:
Runner A : 1,75
Runner B : 0.71 ( divided speed over velocity for both & B)
Distance = 1,75 + 0,71 = 2,46 m
Is it right?
A motorcycle is moving with the velocity of 72km/h. If the velocity reaches 40m/s after 0.5m calculate the acceleration
Answer:
72km/hr
= 72× 1000m/1×60×60 sec
= 72000m/ 3600sec
=20m/s
0.5 m
= 0.5×60 sec
= 30 sec
Now,
acceleration = v-u/t
= 40m/s-20m/s divided by 30 sec
= 20m/s divided by 30 sec
= 0.6m/s2
Explanation:
hope this helps you
11 An unstretched spring is 12,0 cm long. A load of 5.0N stretches it to 15.0cm. How long will it be under a load
of 15N? (Assume that the spring obeys Hooke's law.)
Answer: Approximately 22 cm
=========================================================
Explanation:
The unstretched spring is 12.0 cm long. When adding a load of 5.0 N, it stretches to 15.0 cm. This is a displacement of 15.0 - 12.0 = 3.0 cm, which is the amount the spring is stretched.
Convert this displacement to meters (so that it fits with the meters unit buried in Newtons).
3.0 cm = (3.0)/100 = 0.03 m
Apply Hooke's Law to find the spring constant k
F = -kx
5.0 = -k*(0.03)
k = -(5.0)/(0.03)
k = -166.667 approximately
Now we must find the displacement x when F = 15 newtons
F = -kx
-kx = F
x = F/(-k)
x = -F/k
x = -15/(-166.667)
x = 0.089 approximately
x = 0.1
The displacement to one decimal place is about 0.1 meters, which converts to 100*0.1 = 10 cm
So the spring will be stretched to about 12cm+10cm = 22 cm
0.0084x91 ...................
Answer:
0.0084×91=0.7644
Explanation:
hope this helps
please mark this answer as brainlist
Based on the ionic notation shown here, what has happened to this ion. ***List all that apply!!!*** Fe2+ *
Atom has become an anion.
Atom has become a cation.
Atom has lost 2 electrons.
Atom has gained 2 electrons.
Answer:
atom has become cation
atom has lost 2 electrons
Explanation:
when atom loses electron they become positively charged and cation are positive ion
a hot metal block is placed into 50g of water in an insulated container the water increases in temperature from 20c to 32c the specific heat capacity of water is 4200j/kgk calculate the quantity of heat energy supplied to the water from the metal
Answer:…..
Explanation:
The quantity of heat energy supplied to the water from the metal is 2520 J.
What is meant by specific heat capacity ?The quantity of heat energy needed to increase the temperature of one kilogram of a substance by one degree Celsius is known as the substance's specific heat capacity.
Here,
Mass of the water in the container, m = 50 g = 0.05 kg
Initial temperature of the water, T₁ = 20°C = 293 K
Final temperature of the water, T₂ = 32°C = 305°C
Specific heat capacity of water, C = 4200 J/kgK
The expression for the quantity of heat energy supplied to the water from the metal is given by,
Q = mcΔT
Q = mC(T₂ - T₁)
Applying the values of m, C, T₁ and T₂
Q = 0.05 x 4200 (305 - 293)
Q = 210 x 12
Q = 2520 J
Hence,
The quantity of heat energy supplied to the water from the metal is 2520 J.
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Plzz help me fast
(There is both physics and chemistry question )
1) Write the molecular formula of the following by crisscross method :
1. Potassium sulphate
2. Sodium chloride
3. Ammonium chloride
4. Silver oxide
2) Prove that F=ma pl
Potassium Sulphate :-
[tex]\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf K}\put(0,0){\bf 1}\put(4,3){\sf SO_4}\put(4,0){\bf -2}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}[/tex]
[tex]\boxed{\sf K_2SO_4}[/tex]
Sodium chloride:-
[tex]\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf Na}\put(0,0){\bf 1}\put(4,3){\sf Cl}\put(4,0){\bf -1}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}[/tex]
[tex]\boxed{\sf NaCl}[/tex]
Ammonium Chloride
[tex]\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf NH_4}\put(0,0){\bf 1}\put(4,3){\sf Cl}\put(4,0){\bf -1}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}[/tex]
[tex]\boxed{\sf NH_4Cl}[/tex]
Silver Oxide
[tex]\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf Ag}\put(0,0){\bf 1}\put(4,3){\sf O}\put(4,0){\bf -2}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}[/tex]
[tex]\boxed{\sf Ag_2O}[/tex]