An engine manufacturer discovered that .08 of a certain production run was defective what fraction of the run does this represent

Answer:

Step-by-step explanation:

Let's assume Kylie's current age to be x.

According to the problem, Laila is 10 years older than Kylie, so her current age would be (x + 10).

Seventeen years ago, Laila's age would have been (x + 10 - 17) = (x - 7), and Kylie's age would have been (x - 17).

The problem also states that Laila's age 17 years ago was triple Kylie's age 17 years ago, so we can set up the equation:

(x - 7) = 3(x - 17)

Solving for x, we get:

x - 7 = 3x - 51

2x = 44

x = 22

Therefore, Kylie's current age is x = 22, and Laila's current age is (x + 10) = 32.

So, Laila is currently 32 years old and Kylie is currently 22 years old.

Answer:

Laila is currently 32 years old.

Kylie is currently 22 years old.

Step-by-step explanation:

To find the current ages of Laila and Kylie, create and solve a system of linear equations using the given information.

Define the variables:

Given Laila is 10 years older than Kylie:

Given 17 years ago, Laila was triple Kylie's age:

Substitute the first equation into the second equation and solve for K:

⇒ (K + 10) - 17 = 3(K - 17)

⇒ K - 7 = 3K - 51

⇒ K - 7 - K = 3K - 51 - K

⇒ -7 = 2K - 51

⇒ -7 + 51 = 2K - 51 + 51

⇒ 44 = 2K

⇒ 44 ÷ 2 = 2K ÷ 2

⇒ K = 22

Substitute the found value of K into the first equation and solve for L:

⇒ L = K + 10

⇒ L = 22 + 10

⇒ L = 32

Therefore, Laila is currently 32 years old and Kylie is currently 22 years old.

Step-by-step explanation:

why did you mention the definition of every side twice ?

I think we need only one per side right ?

because otherwise we would have to do all 3 multiplications before summing things up.

I sorted the terms for the sum based on their variable.

after all, the perimeter of a triangle is the sum of all 3 sides.

1.3t + 7.9u

2.4t - 4.8v

- 9.8u +6.8v

--------------------------

3.7t - 1.9u + 2v cm

For sin the expression [tex]Qiv sin(A)/(2)[/tex] can be simplified using trigonometric identities.

Trigonometric identities are equations involving trigonometric functions that are true for all values of the variables within their domains. These identities are useful in simplifying trigonometric expressions and solving trigonometric equations. Some common identities include the Pythagorean identity, which relates the trigonometric functions of sine, cosine, and tangent, and the double-angle identities, which express trigonometric functions of twice the angle in terms of functions of the original angle.

First, we can recognize that Qiv is the same as 1/4 of the unit circle or 90 degrees. Therefore, [tex]Qiv sin(A)[/tex] can be simplified to sin(A + 90).

Using the identity [tex]sin(A + B) = sin(A)cos(B) + cos(A)sin(B)[/tex], we can rewrite [tex]sin(A + 90)[/tex] as:

[tex]sin(A)cos(90) + cos(A)sin(90)[/tex]

Since [tex]cos(90) = 0 \\sin(90) = 1[/tex], this:

[tex]sin(A) * 0 + cos(A) * 1[/tex]

Which simplifies to just cos(A).

Therefore, the expression [tex]Qiv sin(A)/(2)[/tex] is equivalent to cos(A)/2.

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It displays a regular pentagon with centre point A. From each point, a line is traced to the centre point A. Triangles ABC are made. One of the regular pentagon's central angles measures 72°. In triangle ABC, one of the congruent base angles has a measure of 54.

In a regular pentagon, each of the five central angles has the same measure, which can be found using the formula:

[tex]Central angle = 360° / Number of sides[/tex]

Since we have a regular pentagon, the number of sides is 5, so:

[tex]Central angle = 360[/tex]°/5

central angle = 72°

Therefore, each central angle in the regular pentagon measures 72°.

Now let's look at triangle ABC. Since the pentagon is regular, all the line segments from the vertices to the centre are of equal length, so triangle ABC is an isosceles triangle with base angles that are congruent. Give one of these basic angles a measure of x.

Since the sum of the interior angles in any triangle is 180°, we can write:

x + x + angle at vertex = 180°

But we know that the angle at the vertex is a central angle of the pentagon, and so it measures 72°. Thus, we can substitute 72° for the angle at the vertex, and we have:

2x + 72° = 180°

Subtracting 72° from both sides, we get:2x = 108°

Dividing by 2, we find:

x = 54°

Therefore, each of the congruent base angles in triangle ABC measures 54°.

The complete question is:-

Use this regular pentagon to answer the questions. A regular pentagon with center point A is shown. Line are drawn from each point to center point A. Triangle A B C is formed. What is the measure of one of the central angles in the regular pentagon? ° What is the measure of one of the congruent base angles in triangle ABC? °

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Answer:

Point A would be located at (-2,8)

Step-by-step explanation:

After a dilation of factor 2 centered at the origin (0,0), Point A' would be located at:

A' = (2 * -1, 2 * 4) = (-2, 8)

The effect of the dilation is to stretch the original point A by a factor of 2 along both the x and y directions. This essentially doubles the distances from the origin to the point A, creating the point A'.

The mean points per game for Porter is 26 points.

To find the mean, we use the formula for the z-score:

z = (x - mu) / sigma

where z is the z-score, x is the observed value, mu is the mean, and sigma is the standard deviation. Rearranging this formula, we get:

mu = x - z * sigma

Plugging in the values given in the problem, we have:

mu = 50 - 4 * 6 = 26

This would be the mean if the z-score is 4.

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The answer of the given question is (a) proofing is below  u = √gl. (b) the greatest value of 0 is 2gr and the value of θ when the tension in the rod is mg and the particle is moving with speed √gl is θ = 30° or θ = 150°.

An equilibrium refers to  state of balance or stability where there is no net change in motion. An object is said to be in equilibrium when net force acting on it is zero, which means that  object is either at rest or moving with  constant velocity.

There is two types of equilibrium that are : static equilibrium and dynamic equilibrium. In static equilibrium, an object is at rest, and  net force acting on it is zero. In dynamic equilibrium, an object is moving at  constant velocity, and net force acting on it is also zero.

a) At point C, the particle P is at its lowest point and is in equilibrium. Therefore, the forces acting on P must be balanced. The weight of P is mg acting vertically downwards, and the tension in the rod is acting along OC at an angle of θ to the vertical. The horizontal component of tension is zero because the rod is light. Therefore, the vertical component of tension must balance the weight of P:

T cosθ = mg

We can also write:

T sinθ = mv²/r

where r is the radius of the circle. At the lowest point C, θ = 90° and cosθ = 0, so we have:

T sin90° = mv²/r

T = mv²/r

Substituting this into the first equation:

mv²/r cosθ = mg

v² = gr cosθ

Since the angle between OP and the vertical is θ, we have:cosθ = cos(90° - θ) = sinθ

Substituting this into the previous equation:

v² = gr sinθ = gl

Therefore, u = √gl.

b) When OP makes an angle θ with the vertical, the tension in the rod is:

T = 2mg cosθ

Using the same approach as in part a), we have:

T sinθ = mv²/r

Substituting for T:

2mg cosθ sinθ = mv²/r

2mg sin2θ = mv²/r

v² = 2gr sin2θ

Since sin2θ is maximum when 2θ = 90° or θ = 45°, the greatest value of v² is:

v² = 2gr

When the tension in the rod is mg, we have:

mg sinθ = mv²/r

sinθ = v²/gr

Substituting for v²:

sinθ = 2sin2θ

2sin2θ - sinθ = 0

sinθ(2sinθ - 1) = 0

Therefore, sinθ = 0 or sinθ = 1/2.

If sinθ = 0, then θ = 0° or θ = 180°, which means the particle is at the top or bottom of the circle and is not moving.

If sinθ = 1/2, then θ = 30° or θ = 150°. Substituting into the expression for v²:

v² = 2gr sin2θ = gl

Therefore, when the tension in the rod is mg, the particle is moving with speed √gl when θ = 30° or θ = 150°.

Thus, the greatest value of 0 is 2gr and the value of θ when the tension in the rod is mg and the particle is moving with speed √gl is θ = 30° or θ = 150°.

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After answering the presented question, we can conclude that this equation depicts Bethany and Colin's combined work rate, where 1/4 represents Bethany's work rate.

In mathematics, an equation is a statement that states the equality of two expressions. An equation consists of two sides separated by an algebraic equation (=). The argument "2x + 3 = 9," for example, states that the sentence "2x Plus 3" equals the value "9." The goal of solving equations is to find the value or values of the variable(s) that will allow the equation to be true. Equations can be simple or complex, linear or nonlinear, and contain one or more parts. In the equation "x² + 2x - 3 = 0," the variable x is raised to the second power. Lines are used in many areas of mathematics, including algebra, calculus, and geometry.

The following equation can be used to calculate the number of hours, x, required for Bethany and Colin to mow the lawn together:

1/4 + 1/3 = 1/x

This equation depicts Bethany and Colin's combined work rate, where 1/4 represents Bethany's work rate (in lawns per hour) and 1/3 represents Colin's work rate (in lawns per hour). When they mow the grass together, the equation makes the total of their individual work rates equal to their combined work rate. Solving for x gives us the number of hours it would take them to finish the job if they worked together.

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Answer:

the area of the sector in grey is 100.48 square feet.

Step-by-step explanation:

Area of a circle = radius × radius × π

(π ≌ 3.14)

So

the area of the circle in the picture = 16 × 16 × π = 803.84

As the angle in the grey sector is 45°, so the proportion of the grey sector in the circle is

45°/360° = 1/8

Hence why

the area of the grey sector is 1/8 of the area of the circle, which is

803.84 × 1/8 = 100.48

Answer:

Step-by-step explanation: Derivatives are used to find the rate of changes of a quantity with respect to the other quantity. By using the application of derivatives we can find the approximate change in one quantity with respect to the change in the other quantity. Assume we have a function y = f(x), which is defined in the interval [a, a+h], then the average rate of change in the function in the given interval is

(f(a + h)-f(a))/h

Now using the definition of derivative, we can write

f

'

(

a

)

=

lim

h

→

0

f

(

a

+

h

)

−

f

(

a

)

h

which is also the instantaneous rate of change of the function f(x) at a.

Now, for a very small value of h, we can write

f'(a) ≈ (f(a+h) − f(a))/h

or

f(a+h) ≈ f(a) + f'(a)h

This means, if we want to find the small change in a function, we just have to find the derivative of the function at the given point, and using the given equation we can calculate the change. Hence the derivative gives the instantaneous rate of change of a function within the given limits and can be used to find the estimated change in the function f(x) for the small change in the other variable(x).

Approximation Value

Derivative of a function can be used to find the linear approximation of a function at a given value. The linear approximation method was given by Newton and he suggested finding the value of the function at the given point and then finding the equation of the tangent line to find the approximately close value to the function. The equation of the function of the tangent is

L(x) = f(a) + f'(a)(x−a)

The tangent will be a very good approximation to the function's graph and will give the closest value of the function. Let us understand this with an example, we can estimate the value of √9.1 using the linear approximation. Here we have the function: f(x) = y = √x. We will find the value of √9 and using linear approximation, we will find the value of √9.1.

We have f(x) = √x, then f'(x) = 1/(2√x)

Putting a = 9 in L(x) = f(a) + f'(a)(x−a), we get,

L(x) = f(9) + f'(9)(9.1−9)

L(x) = 3 + (1/6)0.1

L(x) ≈ 3.0167.

This value is very close to the actual value of √(9.1)

Hence by using derivatives, we can find the linear approximation of function to get the value near to the function.

Answer:

The medians intersect at 4-4 (i think).

Step-by-step explanation:

Every triangle has three medians and they all intersect in the triangles centroid. i believe that the medians intersect at 4-4.

i am not a very trustworthy source so you should probably ignore this awnser.

[tex]\cos(XYZ )=\cfrac{\stackrel{adjacent}{6}}{\underset{hypotenuse}{15}}\implies \cos(XYZ )=\cfrac{2}{5} \\\\\\ XYZ=\cos^{-1}\left( \cfrac{2}{5} \right)\implies XYZ\approx 66.4^o[/tex]

Make sure your calculator is in Degree mode.

The Ratio of the number of pairs of Jeanine to the cost of jeans helps us understand how many pairs of jeans Jeanine can purchase for a given amount of money.

To find the ratio of the number of pairs of Jeanine to the cost of jeans, we need to first determine how many pairs of jeans Jeanine has and how much she paid for them. Let's assume Jeanine has 10 pairs of jeans and she paid $50 for each pair. Therefore, the total cost of Jeanine's jeans is $500.

Now we can calculate the ratio by dividing the number of pairs of jeans by the cost of jeans. So, the ratio of the number of pairs of Jeanine to the cost of jeans is:

10 pairs of jeans / $500 = 1/50

This means that for every $50 Jeanine spends on jeans, she gets one pair. Alternatively, we could also express the ratio as a decimal or percentage. In this case, the ratio as a decimal would be 0.02 or 2%, indicating that Jeanine spends 2% of the cost of one pair of jeans for each pair she owns.

Overall, the ratio of the number of pairs of Jeanine to the cost of jeans helps us understand how many pairs of jeans Jeanine can purchase for a given amount of money.

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Answer: -16/3

Step-by-step explanation:

-8 * 2/3

-8 * 2 = -16

Thus, A = -16/3

Answer:

To evaluate the integral over the region R, we can use the change of variables:

u = 4x

v = 2y

This gives us:

x = u/4

y = v/2

The Jacobian of this transformation is:

| ∂x/∂u ∂x/∂v | = | 1/4 0 |

| ∂y/∂u ∂y/∂v | | 0 1/2 |

So the Jacobian determinant is |J| = (1/4)(1/2) = 1/8.

Using this transformation, the region R is mapped onto the unit circle in the uv-plane, and the equation of the ellipse becomes:

u^2 + v^2/4 = 1/16

The integral becomes:

∫∫R 4x^2 e^(4xy) dA

= 2∫∫S u^2 e^uv/2 (1/8) dA

= (1/4) ∫∫S u^2 e^v/2 dA

where S is the unit circle in the uv-plane.

Now we can use polar coordinates in the uv-plane, with u = r cosθ and v = r sinθ. The integral becomes:

(1/4) ∫∫S r^2 cos^2θ e^(r sinθ/2) r dr dθ

= (1/4) ∫0^2π ∫0^1 r^3 cos^2θ e^(r sinθ/2) dr dθ

The inner integral can be evaluated by integration by parts, letting u = r^2 cos^2θ and dv = e^(r sinθ/2) r dr. This gives:

∫ r^3 cos^2θ e^(r sinθ/2) dr

= r^3 cos^2θ (-2/θ) e^(r sinθ/2) + 2/θ ∫ r^2 cos^2θ e^(r sinθ/2) dr

The integral on the right-hand side can be evaluated by another integration by parts, letting u = r^2 cos^2θ and dv = e^(r sinθ/2) dr, which gives:

∫ r^2 cos^2θ e^(r sinθ/2) dr

= r^2 cos^2θ (-2/θ) e^(r sinθ/2) + 4/θ^2 ∫ r cos^2θ e^(r sinθ/2) dr

We can substitute these results back into the original integral and simplify to get:

∫∫R 4x^2 e^(4xy) dA

= (1/4) ∫0^2π ∫0^1 r^3 cos^2θ e^(r sinθ/2) dr dθ

= (1/2π) ∫0^π ∫0^1 r^3 cos^2θ e^(r sinθ/2) dr dθ

Now we can evaluate the inner integral:

∫0^1 r^3 cos^2θ e^(r sinθ/2) dr = (1/2) ∫0^1 r^2 e^(r sinθ/2) d(r^2)

= (1/2) ∫0^1 u^(1/2) e^(u sinθ/2) du

Letting t = u sin(θ/2) and using the identity sin(θ/2) = 2

To get the given probabilities of the event we can use a spinner with 20 green, 25 blue, 40 yellow, and 15 orange parts.

Probability is a way to gauge how likely or unlikely something is to happen. A number between 0 and 1, where 0 denotes an improbable event and 1 denotes a certain event, is used to convey it. The likelihood of an occurrence may be determined by dividing the positive outcomes by the entire number of possible outcomes. For instance, the likelihood of receiving heads on a fair coin flip is 50% since there is only one positive event (heads) out of two possible possibilities (heads or tails). The general probability calculation formula is:

Number of likely outcomes divided by the total number of possible outcomes is how you calculate an event's probability.

To get the given probabilities of the event we can use a spinner with 20 green, 25 blue, 40 yellow, and 15 orange parts.

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Considering the figure, the length of EF is solved to be 22.0

The length EF of the right triangle is solved using trigonometry as follows

Considering the figure and the giving sides we use the trigonometric tangent by using the formula

tan (angle D) = DE / EF

plugging in the values

tan 36 = 16 / EF

EF = 16 / tan 36

EF = 22.022

EF = 22.0 (to the nearest tenth)

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The production of a 5,350 linear-foot irrigation system for Thompson Orchards, job no. 399, was started and completed in March of the current year.

This means that the irrigation system was manufactured and delivered to the customer within that month. It is important to note that completing the production does not necessarily mean that the job is entirely finished, as there may be additional steps involved such as installation and testing. The completion of this job is a significant milestone for Thompson Orchards as it allows for efficient watering of their crops, which is crucial for their growth and productivity. The irrigation system was likely designed and manufactured to meet specific requirements, taking into consideration factors such as the type of crops grown, soil type, and climate. For the manufacturer, completing this job on time and to the customer's satisfaction is a testament to their expertise and ability to deliver high-quality products. This successful project can lead to repeat business and positive word-of-mouth recommendations. Overall, the completion of the irrigation system for Thompson Orchards is a significant accomplishment for both the manufacturer and the customer.

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The box with the most volume has 20 centimetres of side length and 20 centimetres of height. The box has a volume of: 8000 cubic centimetres.

We need to employ optimization strategies to determine the box with the highest feasible volume, which has a square base and an open top. Call the box's height h and the square base's side length x, respectively.

V = [tex]x^(2h)[/tex] gives the volume of the box.

The box's overall surface area will be 1600 square centimetres since the material used to create it has a surface area of 1600 square centimetres.

The box's surface area is made up of the areas of its four sides and base (x2) (4xh). We thus have:

[tex]x^2[/tex]+ 4xh = 1600

The volume of the box, which is given by V = [tex]x^(2h)[/tex], is what we wish to maximise.

We can determine h in terms of x using the equation above:

h = (1600 - [tex]x^2[/tex]) / (4x) (4x)

This result is obtained by replacing h with this equation in the volume formula:

V = [tex]x^2[/tex](1600 - [tex]x^2[/tex]) / (4x) (4x)

If we simplify this expression, we get:

V = 400x - [tex]0.25x^3[/tex]

Now, in order to determine the crucial places, we can take the derivative of V with respect to x and put it equal to zero:

[tex]dV/dx = 400 - 0.75x^2 = 0[/tex]

As a result of solving this equation for x,

x = 20

The result of replacing h in the equation with x = 20 is:

h = (1600 - 400) / (4 * 20) = 20

As a result, the box with the maximum volume has 20 centimetres of height and 20 centimetres of side length. The box has a volume of:

8000 cubic centimetres are equal to V = 202 * 20.

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For a sample of radioactive material,

a) The half-life of the radioactive material with that it disintegrates to 90% of the original amountb is equals to the 6.58 years.

b) The time is 2.12 years, at which the material disintegrates to 80% of the original amount.

We have, a sample of radioactive material disintegrates to 90% of the original amount after one year. The term half-life is defined as the time it takes for one-half of the atoms of a radioactive material to disintegrate. Let the original/ initial amount of a sample of radioactive material = y₀ and after t year amount of material = y₀/2. After one year, amount of sample of radioactive material = 90% of y₀. Now, radioactive decay equation form is y(t) = y₀( 0.90)ᵗ ,

We have to calculate value of t when y = y₀/2.

=> [tex]\frac{ y_0}{2} = y_0( 0.90)^t[/tex]

=> 1/2 = (0.90)ᵗ

Taking natural logarithm both sides

=> ln( 1/2) = ln ( 0.90)ᵗ

=> ln( 1/2) = t ln ( 0.90)

=> t = ln(1/2)/ln(0.90)

=> t = 6.579 ~ 6.58 years

b) Now, we have to determine value of t when material disintegrates to 80% of the original amount. Let t years be required time here. So, 80% of y₀ = y₀ ( 0.90)ᵗ

=> 0.80y₀ = y₀( 0.90)ᵗ

Taking natural logarithm both sides

=> ln( 0.80 ) = ln( 0.90)ᵗ

=> ln( 1/2) = t ln( 0.90)

=> t = ln(0.80)/ln(0.90)

=> t = 2.117 ~ 2.12years

Hence, required value of time is 2.12 years.

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Answer:

90

Explanation:

Given marks of Bob's five tests are:

[tex]72 + 86 + 92 + 63 + 77[/tex]

To get an average of 80 on six tests we will need to multiply 6 tests to average of 80.

So,

[tex]6 \times 80 = 480[/tex]

Adding the marks of given five tests is

[tex]72 + 86 + 92 + 63 + 77 = 390[/tex]

Now, to get the marks for Bob's next test, which is the sixth test, we should subtract 390 from 480.

So,

480 - 390 = 90

Therefore, Bob needs to score 90 marks on his sixth test to obtain the average of 80 for all the six tests.

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Answer:

C and E

Step-by-step explanation:

Select a statement that describes the height data. Mark all that apply. If A or C is marked, the other won't be marked because the two statements are contradictory. Option D will not be marked.

Group 1

mean = (103 + 112 + 108 + 120 + 114 + 125 + 109 + 121) / 8 = 114

MAD = (11 + 2 + 6 + 6 + 0 + 11 + 5 + 7) / 8 = 48 / 8 = 6

Group 2

mean = (120 + 85 + 138 + 126 + 92 + 133 + 128 + 90) / 8 = 114

MAD = (6 + 29 + 24 + 12 + 22 + 19 + 14 + 24) / 8 = 150 / 8 = 18.75

Mark C because 114 = 114.

Mark E because 18.75 > 3 * 6.

Don't mark D, because the data in Group 2 varies more than Group 1.

Don't mark B, because both groups have 8 children.

Answer:

∠ B = 82°

Step-by-step explanation:

complementary angles sum to 90° , then

x - 19 + 3x + 1 = 90

4x - 18 = 90 ( add 18 to both sides )

4x = 108 ( divide both sides by 4 )

x = 27

Then

∠ B = 3x + 1 = 3(27) + 1 = 81 + 1 = 82°

Answer:

I'm sorry, but the information you provided is not clear enough for me to create the required input/output table and graphs on ANNEXURE A. Could you please provide more context and details on the problem? What are the fixed costs, variable costs, and printer's costs for? Are there any other costs involved in selling the books? How many books are initially available for sale? Without this information, I won't be able to provide an accurate solution to your problem.

Step-by-step explanation:

The correct option that result the data with variability:

C. The shoe size of the various 5 year olds.

D. The number of patients at the doctor's office each day.

The term "variability" refers to the distance between data points within a distribution and their distance from its centre. Measures of variability provide you summary statistics that summarise your data in addition to measurements of central tendency.

Spread, scatter, and dispersion are other terms for variation. It is often assessed using the following:

Thus, the result the data with variability:

C. The shoe size of the various 5 year olds as it will vary for different children.

D. The number of patients at the doctor's office each day is also variable.

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a) 8/13 of the marbles are blue or green, 61/5%

b) Blue and green replacing all the marbles would be 7.7%

c) 6/13 of the marbles are blue, 46/2%

d) (2/13)*(6/13) would be a chance of getting a green marble plus another without replacing, 7.1%

Answer:

(b)

Step-by-step explanation:

25 percent of 84 equals 21

84 divided by 4 equals 21

Answer:

84 divided by 4

Step-by-step explanation:

25% of 84 is just (0.25)(84) which is 21

84 divided by 4 is also 21