Explanation:
Here,
object distance(u)=20cm
image distance(v)=80cm-20cm=60cm
focal length(f)=?
we know ,
(1/f)=(1/v)+(1/u)
1/f = 1/60 + 1/20
1/f = (1+3)/60
60 =4f
f=15cm
If a cannonball is fired horizontally it will not go in a straight line why?
Explanation:
A projectile (Cannon ball) is launched at an angle to the horizontal and rises up to a peak while moving horizontally. When it reaches the peak, the projectile starts to fall.
A 1,500kg boulder falls off a 120m tall cliff on a planet that has a surface gravitational field of magnitude 3. 6 N/kg. Assume that the planet has no atmosphere. How long does it take for the boulder to strike the ground?
Write your answer using two significant figures
Answer:
8.16 seconds, enjoy physics
A 1,500kg boulder falls off a 120m tall cliff on a planet that has a surface gravitational field of magnitude 3. 6 N/kg. Assume that the planet has no atmosphere, it would take 8.16 seconds for the boulder to strike the ground
What are the three equations of motion?There are three equations of motion given by Newton
The first equation is given as follows
v = u + at
the second equation is given as follows
S = ut + 1/2×a×t²
the third equation is given as follows
v² - u² = 2×a×s
Note that these equations are only valid for a uniform acceleration.
where u and v are the initial and final velocity respectively
S is the total distance covered by the object
a is the acceleration of the object
As given in the problem a 1,500kg boulder falls off a 120m tall cliff on a planet that has a surface gravitational field of magnitude 3. 6 N/kg. Assume that the planet has no atmosphere
S = 120m, the initial velocity of the boulder is zero
u = 0
g = 3.6 m/s²
S = ut + 1/2at²
u= 0m/s , a= 3.6 m/s² and t = ? seconds
120 = 0×t + 0.5×3.6×t²
t² = 120 /(3.6×0.5)
t² = 66.667
t = 8.16 seconds
Thus, it would take 8.16 seconds for the boulder to strike the ground
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A wave has a period of n seconds. What is the frequency of this wave?
Answer:
n Hz
Explanation:
I think I'm Sry if it is wrong.
When you travel in an elevator (which moves linearly in space), the ___________ detect when the elevator is accelerating or decelerating.
We can confirm that when you travel in an elevator, the utricle and saccule detect when the elevator is moving.
What are the utricle and saccule?These are small organs located in the inner ear. They serve a very important function in our everyday life. These otolith organs are responsible for the detection of movement and provide us with a sense of spatial orientation. They accomplish this by stimulating very small, hair-like cells with a specialized fluid.
Therefore, we can confirm that when you travel in an elevator, the utricle and saccule detect when the elevator is accelerating or decelerating.
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Pls answer asap!! I need help on this question!
Hubble space telescope, Hubble deep field guide, moon, mercury, Saturn, sun, galaxy messier 101
Answer:
1-Hubble Deep Field Galaxy
2-Galaxy Messier 101
3-Sun
4-Saturn
5-Mercury
6-Moon
7-Hubble Space Telescope
1. Potential energy and a roller coaster. A 1000-kg roller coaster car moves from point A to B then C.
(a) What is the potential energy at B and C
relative to A?
(b) What is the change in potential energy
as it goes from B to C?
(c) What is the potential energy at B and C relative to point C?
(d) What is the change in potential energy as it goes from B to C?
Answer:(a) With our choice for the zero level for potential energy of the car-Earth system when the car is at point B ,
U
B
=0
When the car is at point A, the potential energy of the car-Earth system is given by
U
A
=mgy
where y is the vertical height above zero level. With 135ft=41.1m, this height is found as:
y=(41.1m)sin40.0
0
=26.4m
Thus,
U
A
=(1000kg)(9.80m/s
2
)(26.4m)=2.59∗10
5
J
The change in potential energy of the car-Earth system as the car moves from A to B is
U
B
−U
A
=0−2.59∗10
5
J=−2.59∗10
5
J
(b) With our choice of the zero configuration for the potential energy of the car-Earth system when the car is at point A, we have U
A
=0. The potential energy of the system when the car is at point B is given by U
B
=mgy, where y is the vertical distance of point B below point A. In part (a), we found the magnitude of this distance to be 26.5m. Because this distance is now below the zero reference level, it is a negative number.
Thus,
A 89.1 kg weight-watcher wishes to climb a mountain to work off the equivalent of a large peice of chocolate cake rated at 815 (food) calories. How high must the person climb? The acceleration due to gravity is 9.8m/s^2 and 1 food calorie is 10^3 calories. Answer in units of km
Answer:
3904 Meters
Explanation:
F = ma
work = F * d
89.1 (9.8)* d = 815000/.23906 conversion factor 1 j = .23906 cal
d = 3904 meters
When a star is so dense that its atoms have their electrons smashed in toward the nucleus (resulting in densities about a million times greater than water), the resulting material is called ________.
When a star is so dense that its atoms have their electrons smashed in toward the nucleus (resulting in densities about a million times greater than water), the resulting material is called a Neutron star.
What is Star?Stars are present in the galaxy that have the ability to generate their own light. They are both quite hot and very huge.
They are largely formed of hydrogen, with a trace of helium thrown in for good measure.
The sun is also a star, and its energy and light play an important part in the survival of all kinds of life on Earth.
When a star is so dense that its atoms have their electrons smashed in toward the nucleus (resulting in densities about a million times greater than water), the resulting material is called a Neutron star.
Hence the correct answer is a neutron star.
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When an object in simple harmonic motion is at its maximum displacement, its____________ is also at a maximum.
When an object in simple harmonic motion is at its maximum displacement, its acceleration is also at a maximum.
Reason: The speed is zero when the simple harmonic motion is at its maximum displacement, however, the acceleration is the rate of change of velocity. The velocity reverses the direction at that point therefore its rate of change is maximum at that moment. thus the acceleration is at its maximum at this point
Hope that helps!
Is the equation balanced? Why or why not? 2 Zn + 2 HCl ----------> 2 H2 + 2 ZnCl2 SPS3.bGroup of answer choicesYes because the law of conservation of matter is being followed. The mass of the reactants is equal to the mass of the products.No because the law of conservation of energy is not followed. There are different amounts of energy in the reactants and products.Yes because the law of conservation of energy is followed. There are equal amounts of energy in the reactants and products.No because the law of conservation of mass is not being followed. The hydrogen and chlorine atoms have different numbers of atoms in the reactants and products.
The equation is not balance because the law of conservation of mass is not being followed.
Why the equation is not balanced?The hydrogen and chlorine atoms have different numbers of atoms in the reactants and products which is not balance on both sides i.e. reactant and products.
So we can conclude that the equation is not balance because the law of conservation of mass is not being followed.
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Evaluate cos(30°).
ОА. 1.00
ов. 0.87
ОС. 0.50
ОС
D. 0.58
Answer:
The answer for cos(30°) is 0.87
A massless rod is balanced on a pivot as shown below. If the rod is in static equilibrium, what
magnitude of force (x) must be exerted on the other end of the rod?
A. 7.5 N
B. 13 N
C. 20 N
D. 53 N
E. 80 N
Answer:
torques must balance for equilibrium
counterclockwise = clockwise
1.5 X = 4 * 20
x = 80 N-m / 1.5 m = 53 N
(D) is correct
A car of mass of 1200 kg is driven around a corner of a radius of 45m at 15 ms-1
.
(a) Calculate the acceleration of the car.
(b) Calculate the centripetal force acting on the car.
(c) Explain how the centripetal force is being produced.
Explanation:
w = v/r
= 15/ 45 = 1/3 rads-¹
a = w²r
= 1/9 • 45 = 5 ms-²
F = mv²/r
= 1200• 15• 15/45
= 6000N
The car, when rounding the curve, is pulled towards the center by the friction between it's wheels and the road.
A 73.9 kg weight-watcher wishes to climb a
mountain to work off the equivalent of a large
piece of chocolate cake rated at 991 (food)
Calories.
How high must the person climb? The
acceleration due to gravity is 9.8 m/s2 and 1
food Calorie is 103 calories.
Answer in units of km.
The height to which the weight-watcher must climb to work off the equivalent 991 (food) Calories is 0.59 Km
How to determine the energy.1 food calorie = 103 calories
Therefore,
991 food calories = 991 × 103
991 food calories = 102073 calories
Multiply by 4.2 to express in joule (J)
991 food calories = 102073 × 4.2
991 food calories = 428706.6 J
How to determine the height Energy (E) = 428706.6 JMass (m) = 73.9 kgAcceleration due to gravity (g) = 9.8 m/s²Height (h) =?E = mgh
Divide both side by mg
h = E / mg
h = 428706.6 / (73.9 × 9.8)
h = 591.95 m
Divide by 1000 to express in km
h = 591.95 / 1000
h = 0.59 Km
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is an ocean wave electromagnetic or mechanical
Answer:
mechanical
Explanation:
the energy is carried by water <3 hope this helped
2) What did Rutherford discover in his experiment?
a) nucleus
b) electrons
c) neutrons
(02.06 LC)
Etiquette determines which (5 points)
Answer:
Etiquette determines which behaviors are polite and impolite among players and team. It is a code of polite conduct according to social norms and efficiency. Etiquette as a societal rule is formed to enhance positive human relation when interacting and can reduce conflicts in the society. A person who is aware of the etiquette in a given situation will be more confident, comfortable and competent thus making even those around him or her at ease.
Giving Brainliest to The First Correct Answer
A car, with a mass of 1225 kg, traveling at 75 m/s slows to a stop in 5.3min. What is the size and direction of the force that topped the car? What provided the force?
Answer:
[tex]F_{k} = 9854N[/tex] Opposite to the motion of the car.
Explanation:
Please find the detailed solution below
The measurement of cosmic distances was helped tremendously by the discovery, in the early part of the 20th century, that in Cepheid variable stars, the average luminosity was related to:
In the early 20th century, the average luminosity in Cepheid variable stars was related to: the period of time it takes to vary.
What is a cosmic distance?A cosmic distance can be defined as an accurate and precise measurement of the distance to celestial or astronomical objects such as:
GalaxiesStarsMoonSunIn the early 20th century, a discoery of the average luminosity in Cepheid variable stars was related by astronomers to the period of time it takes to vary and this helped tremendously in the measurement of cosmic distances.
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Yellow light (600 nm) passes
through a diffraction grating. Its first
order (m = 1) maximum occurs at
an angle of 21. 2°. What is the slit
separation d?
[?] x 10-6 m
Hint: Just fill in the number that goes in [?]
Answer:
1.66 x 10^-6 m
Explanation:
A 2.03 kg book is placed on a flat desk. Suppose the coefficient of static friction between the book and the desk is 0.602 and the coefficient of kinetic friction is 0.327 . How much force is needed to begin moving the book
Answer:
11.98 N
Explanation:
Normal force = mg = 2.03 * 9.81
coeff of static friction must be overcome for the book to begin moving
.602 = F / (2.03 * 9.81) = 11.98 N
The Special Olympics started for athletes with which disability?
Answer:
intellectual disabilities
Founded in 1968 by Eunice Kennedy Shriver, Special Olympics provides people with intellectual disabilities continuing opportunities to realize their potential, develop physical fitness, demonstrate courage and experience joy and friendship.
Explanation:
A 1,508 kg car rolling on a horizontal surface has a speed of 20.8 km/hr when it strikes a horizontal coiled spring and is brought to rest in a distance of 6.87 m. What is the spring constant (in N/m) of the spring
Answer:
Approximately [tex]1.79 \times 10^{5}\; {\rm N \cdot m^{-1}}[/tex], assuming friction between the vehicle and the ground is negligible.
Explanation:
Let [tex]m[/tex] denote the mass of the vehicle. Let [tex]v[/tex] denote the initial velocity of the vehicle. Let [tex]k[/tex] denote the spring constant (needs to be found.) Let [tex]x[/tex] denote the maximum displacement of the spring.
Convert velocity of the vehicle to standard units (meters per second):
[tex]\begin{aligned}v &= 20.8\; {\rm km \cdot h^{-1}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \times \frac{1\; {\rm h}}{3600\; {\rm s}} \\ &\approx 1.908\; {\rm m \cdot s^{-1}}\end{aligned}[/tex].
Initial kinetic energy ([tex]{\rm KE}[/tex]) of the vehicle:
[tex]\begin{aligned}\frac{1}{2}\, m \, v^{2}\end{aligned}[/tex].
When the vehicle is brought to a rest, the elastic potential energy ([tex]\text{EPE}[/tex]) stored in the spring would be:
[tex]\displaystyle \frac{1}{2}\, k\, x^{2}[/tex].
By the conservation of energy, if the friction between the vehicle and the ground is negligible, the initial [tex]\text{KE}[/tex] of the vehicle should be equal to the [tex]{\rm EPE}[/tex] of the vehicle. In other words:
[tex]\begin{aligned}\frac{1}{2}\, m \, v^{2} &= \frac{1}{2}\, k\, x^{2}\end{aligned}[/tex].
Rearrange this equation to find an expression for [tex]k[/tex], the spring constant:
[tex]\begin{aligned}k &= \frac{m\, v }{x^{2}}\end{aligned}[/tex].
Substitute in the given values [tex]m = 1508\; {\rm kg}[/tex], [tex]v \approx 1.908\; {\rm m\cdot s^{-1}}[/tex], and [tex]x = 6.87\; {\rm m}[/tex]:
[tex]\begin{aligned}k &= \frac{m\, v }{x^{2}} \\ &\approx \frac{1508\; {\rm kg} \times 1.908\; {\rm m\cdot s^{-1}}}{(6.87\; {\rm m})^{2}} \\ &\approx 1.79 \times 10^{5}\; {\rm kg \cdot m \cdot s^{-2} \cdot m^{-3}}\\ &\approx 1.79 \times 10^{5}\; {\rm N \cdot m^{-1}}\end{aligned}[/tex]
Which describe the image formed by the convex
mirror? Check all that apply.
-real
-virtual
-inverted
-upright
-smaller
-larger
Answer:
virtual, upright, smaller
Explanation:
yes
A cylinder has a base radius of 4m and a height of 6m. What is its volume in cubic m, to the nearest tenths place?
Answer:
मार्क ASL brainlisessjd
Estuaries are the place where rivers flow into the sea, and the freshwater they contain meets and mixes with salty seawater. question 2 options: true false
Answer:
true
Explanation:
i did the test
A ball of mass 0.5 kg starts rolling on the ground with a speed of 5 m/s. When the ball starts moving, the momentum of the ball is:
Answer:
2.5 kg - m/s
Explanation:
Momentum = m * v = .5 * 5 = 2.5 kg-m/s
A variable resistor has a voltage of 12.0 V placed across it. If the resistance is increased 20%, what happens to the current flowing through it
Answer:
Explanation:
Remark
The answer is in the formula
E = I * R
E = the voltageI = the CurrentR = the ResistanceSolution
Let the resistance = R
I = 12/R
If we increase the resistance by 20% then we get
R1 = R + (20/100) * R
R1 = R + 1/5 * R
R1 = 6 R/5
What happens to I when you do this
I = 12/(6/5 R) Effectively you need to treat 6/5 as a reciprocal
I = 12 * 5/6 * R
I = 10 / R
What does this tell you? Since the Resistance has a base value of R, when increased by 20%, the numerator of the fraction is reduced to 10 from 12. In other words the current is now smaller when R goes up.
What happens to the force between charges when: (a) the distance between them is halved?
Answer:
i dont know but ill update you
As velocity____kinetic energy _____ and potential energy _____
Answer:
increases increases decreases
Explanation:
For an object falling from a height